On Thu, Mar 06, 2008 at 06:54:41PM -0500, Charilaos Skiadas wrote:
On Mar 6, 2008, at 1:49 PM, Mag. Ferri Leberl wrote:
Dear everybody!
Is there a command in \LaTeX to display the R-Logo or has anybody
made it up?
Thank you in advance.
Isn't it just an image? Hence you would
If you are calling libR.so, it is an option set when you initialize R.
See Rf_initEmbeddedR in 'Writing R Extensions' and the examples in the
tests/Embedded directory in the sources.
BTW, discussion of embedded R is definitely off topic for R-help: use
the R-devel list.
On Thu, 6 Mar 2008,
Whoa! If you want to optimise in R, you need to write an R function to
define your objective. If that function is already written in C, as
appears to be the case, you need to write an interfact to make it
available to R. This is not exactly something novices would take on
lightly.
If you wish
Hi,
I can not comprehend the linear fitting results of polynoms. For
example, given the following data (representing y = x^2):
x - 1:3
y - c(1, 4, 9)
performing a linear fit
f - lm(y ~ poly(x, 2))
gives weird coefficients:
coefficients(f)
(Intercept) poly(x, 2)1 poly(x, 2)2
4.667
poly() computes by default orthogonal polynomials; check the online
help file for poly() for more info. Probably you want to use the 'raw'
argument in this example, i.e.,
x - 1:3
y - c(1, 4, 9)
lm(y ~ poly(x, 2, raw = TRUE))
I hope this helps.
Best,
Dimitris
Dimitris Rizopoulos
It does help if you read the help information for poly.
?poly
x - 1:3
y - c(1, 4, 9)
f - lm(y ~ poly(x, 2, raw = TRUE)) ## note raw = TRUE
coef(f)
(Intercept) poly(x, 2, raw = TRUE)1 poly(x, 2, raw = TRUE)2
0 0 1
You were
Dear,
I need to analyse reaction time.
The general idea might be described as this: There are 8x8 circles. My
program light a circle at one time. The subject then click the lighted
circled as fast as possible. After the correct circle is clicked, then the
next circle will be lighted for the
On 07-Mar-08 08:16:06, Firas Swidan, PhD wrote:
Hi,
I can not comprehend the linear fitting results of polynoms.
For example, given the following data (representing y = x^2):
x - 1:3
y - c(1, 4, 9)
performing a linear fit
f - lm(y ~ poly(x, 2))
gives weird coefficients:
Thanks for the clarifications. It seems the confusion resulted from
making one assumption more than necessary regarding the behavior of
poly().
Best wishes,
Firas.
On Fri, 2008-03-07 at 18:33 +1000, [EMAIL PROTECTED] wrote:
It does help if you read the help information for poly.
?poly
x -
Hi,
I can not comprehend the linear fitting results of polynoms. For
example, given the following data (representing y = x^2):
x - 1:3
y - c(1, 4, 9)
performing a linear fit
f - lm(y ~ poly(x, 2))
gives weird coefficients:
coefficients(f)
(Intercept) poly(x, 2)1 poly(x, 2)2
4.667
Nathanael,
On 7 Mar 2008, at 09:40, nathan3073 wrote:
Dear,
I need to analyse reaction time.
The general idea might be described as this: There are 8x8 circles. My
program light a circle at one time. The subject then click the lighted
circled as fast as possible. After the correct circle
I believe that the procedure you describe at the end (resampling the
cases) is the original interpretation of bagging, and that using weighting
is equivalent when a procedure uses case weights.
If you are getting different results when replicating cases and when using
weights then rpart is not
Hi, yes it's true Mathematica is too expensive (I think one of the most
expensive out there), but yacas has a lng way to go before becoming
mathematica. I agree mathematica is not really for data analysis but I think
it's to help researchers and inventors invent new ideas, understand concepts
Hi,
I'm no expert programmer at all;
I'm running an R script (mariam1_2.R). This scripts calls another
script, which contains an R function, which .Call some C code.
It runs several times without any problem, but sometimes I get the error:
---
*** caught segfault ***
address 0x1c404ec8, cause
Dear All,
I am using xyplot() with many groups like this:
statselect - levels(dat$stat)
xyplot(relmse~T|lambda, groups=stat, data=dat,
panel = panel.superpose,
key=simpleKey(statselect, lines=T))
However, I want lines not scatterplots and if I set
panel.groups=panel.linejoin that
Dear Javier,
From your description, it seems you are not the author of the C
function rrfunc, which is where the problem is probably located (the
segmentation fault is most likely a pointer related problem where the
C code is trying to do something with memory it should not be trying
to do).
Thanks a lot, John, Gavin; Hadley and Greg, for your helpful comments
and suggestions. I finally achieved what I wanted using the suggested
method from Gavin with corrections from Greg.
Out of curiosity (and interest to learn): Hadley, how would you
simplify that code using lattice or ggplot and
Today HTML help stopped working. The menu command Help Html help usually
brings up my default web browser (Opera 9.26), but now R gives the error
Error: file association for 'doc\html\index.html' not available or invalid
If I try the same menu command a second time, R crashes with the message
Dear R Users:
We have splitted up the micEcon package into three packages:
a) Package maxLik provides tools for maximum likelihood estimations
(see http://www.maxLik.org).
b) Package sampleSelection provides tools for estimating Heckman-type sample
selection/generalized tobit models (see
k.m.csillery at sms.ed.ac.uk writes:
I am using xyplot() with many groups like this:
statselect - levels(dat$stat)
xyplot(relmse~T|lambda, groups=stat, data=dat,
panel = panel.superpose,
key=simpleKey(statselect, lines=T))
Add lty=l. And remove the panel=panel.superpose,
Hi,
Was wondering if it is possible to pass function name as a parameter, smth
along this line
param.to.pass-c(1,'max','h')
dd-function(dfd, param=param.to.pass,...){
ttime.int - format(ttime,fmt)
data.frame(
param[3] = tapply(dfd[,param[1]],ttime.int,param[3]),
...)
}
I
1. I have used gdata::read.xls() with much happiness. But every now
and then it breaks. I have not, as yet, been able to construct a
mental model about the class of .xls files for which it works. Does
someone have a simple rule for predicting the circumstances under
which it will work?
On Fri, 7 Mar 2008, Jon Olav Vik wrote:
Today HTML help stopped working. The menu command Help Html help usually
brings up my default web browser (Opera 9.26), but now R gives the error
Error: file association for 'doc\html\index.html' not available or invalid
If I try the same menu command
Duncan Murdoch wrote:
On 06/03/2008 6:45 PM, Thomas Manke wrote:
Hi,
I have a character-valued vector (old_names) and want to translate
its entries whenever possible, using a dictionary (dict=data.frame).
The translation direction is dict$V3 -- dict$V2, but
some values may be undefined
Yes,
tapply(rnorm(100), gl(5,20), max)
On 07/03/2008, Yuri Volchik [EMAIL PROTECTED] wrote:
Hi,
Was wondering if it is possible to pass function name as a parameter, smth
along this line
param.to.pass-c(1,'max','h')
dd-function(dfd, param=param.to.pass,...){
ttime.int -
Dear Ramon,
I'm afraid I'm the author of the C function. Although I'm not a 'real'
programmer I need to do some programming in my research work.
As you say, I've used MAKEFLAGS=CFLAGS=-O1, and valgrind, with the
expression you've said.
The content of the log file contains three blocks of the
Hi
I created a complex layout with using layout() and it looks exactly as
I need it. But I don't want to print in the order in which the
subfigure are numbered, but in a different order.
How can I navigate in the layout so that I can specify the subfigure
in which to plot?
At the moment I am
Hi
I have a raster which I would like to plot in a greyscale instead of
colour. Is this possible, and how?
Thanks
Rainer
--
Rainer M. Krug, Dipl. Phys. (Germany), MSc Conservation Biology (UCT)
Plant Conservation Unit Department of Botany
University of Cape Town
Rondebosch 7701
South Africa
Hello!
I need some help, because I don't know how this error means: Error:
variables ‘Output1’, ‘Output2’, ‘Output3’, ‘Output4’, ‘Output5’ were
specified with different types from the fit
Execution halted
Can you help me?
Thank You
__
Dear Javier,
On Fri, Mar 7, 2008 at 1:09 PM, [EMAIL PROTECTED] wrote:
Dear Ramon,
I'm afraid I'm the author of the C function. Although I'm not a 'real'
Oh, oh... that's too bad. There is not anyone else to blame, then :-).
programmer I need to do some programming in my research work.
On Mar 7, 2008, at 7:18 AM, Rainer M Krug wrote:
Hi
I created a complex layout with using layout() and it looks exactly as
I need it. But I don't want to print in the order in which the
subfigure are numbered, but in a different order.
How can I navigate in the layout so that I can specify
On 07/03/2008, Charilaos Skiadas [EMAIL PROTECTED] wrote:
On Mar 7, 2008, at 7:18 AM, Rainer M Krug wrote:
Hi
I created a complex layout with using layout() and it looks exactly as
I need it. But I don't want to print in the order in which the
subfigure are numbered, but in a
On Mar 7, 2008, at 2:17 AM, Oldrich Kruza wrote:
Hello Soumyadeep,
if you store the data in a tabular file, then I suggest using standard
text-editing tools like cut (say your file is called data.csv, fields
are separated with commas and you want to get rid of the third and
sixth column):
I need some help, because I don't know how this error means: Error:
variables ?Output1?, ?Output2?, ?Output3?, ?Output4?, ?Output5? were
specified with different types from the fit
Execution halted
Can you help me?
No!
Please read the posting guide at
On Mar 7, 2008, at 8:02 AM, Rainer M Krug wrote:
On 07/03/2008, Charilaos Skiadas [EMAIL PROTECTED] wrote:
On Mar 7, 2008, at 7:18 AM, Rainer M Krug wrote:
Hi
I created a complex layout with using layout() and it looks
exactly as
I need it. But I don't want to print in the order in
On Fri, 7 Mar 2008, Prof Brian Ripley wrote:
I believe that the procedure you describe at the end (resampling the cases)
is the original interpretation of bagging, and that using weighting is
equivalent when a procedure uses case weights.
If you are getting different results when
Was wondering if it is possible to pass function name as a parameter
Yes. This isn't exactly what you wanted, but it demonstrates the
principle.
x = rnorm(5)
[1] -0.6510448 0.4591730 1.3225205 1.2314391 -0.0888139
myfun - function(fname, x) eval(parse(text=paste(fname,(x),sep=)))
On 07/03/2008, Charilaos Skiadas [EMAIL PROTECTED] wrote:
On Mar 7, 2008, at 8:02 AM, Rainer M Krug wrote:
On 07/03/2008, Charilaos Skiadas [EMAIL PROTECTED] wrote:
On Mar 7, 2008, at 7:18 AM, Rainer M Krug wrote:
Hi
I created a complex layout with using layout() and it looks
Dear Rers,
I understand that I can include R-code in LaTeX using Sweave. Is there a way
to do it the other way round? Particularly, I need some TeX symbols in the
legend of an R-plot. This can be done in matlab easily, so I am optimistic
with R. Any suggestions for a command or package?
Best,
On Mar 7, 2008, at 8:41 AM, Rainer M Krug wrote:
I'm not sure I understand it, why don't you want to just number the
subfigures in the order in which you will draw them?
Because i thought it would be easier the other way round? Thanks
anyway
Yes, I agree it should not be as hard as it
Hi
Martin Kaffanke [EMAIL PROTECTED] napsal dne 06.03.2008 18:05:03:
Am Donnerstag, den 06.03.2008, 17:47 +0100 schrieb Petr PIKAL:
Hi
[EMAIL PROTECTED] napsal dne 06.03.2008 17:41:06:
Hi there,
When i do
mean(fl[1:20], na.rm=T)
e.g.
sum(!is.na(fl[1:20]))
Mario Maiworm wrote:
Dear Rers,
I understand that I can include R-code in LaTeX using Sweave. Is there a way
to do it the other way round? Particularly, I need some TeX symbols in the
legend of an R-plot. This can be done in matlab easily, so I am optimistic
with R. Any suggestions for a
Carla Rebelo wrote:
Hello!
I need some help, because I don't know how this error means: Error:
variables ‘Output1’, ‘Output2’, ‘Output3’, ‘Output4’, ‘Output5’ were
specified with different types from the fit
Please read the posting guide!
Please tell us at least what produced the error
Rainer M Krug wrote:
Hi
I have a raster which I would like to plot in a greyscale instead of
colour. Is this possible, and how?
Probably, and we may tell you how given you tell us what raster means:
?raster
No documentation for 'raster' in specified packages and libraries:
you could try
Andrew McFadden Andrew.McFadden at maf.govt.nz writes:
Hi all
The code of trying to write relates to selecting properties (given by x
and y co-ordinates) spatially (distance X from infected properties
identified by date) over a certain time period.
i.e. what properties are within 3
Dear Experts,
I am trying to do a time-stratified case-crossover analysis on air
pollution data and number of myocardial infarctions. In order to avoid
model selection bias, I started with a simple simulation.
I'm still not sure if my simulation is right. But the results I get from
the
Dear Mag. Ferri Leberl,
I'm using something like:
--- tex.tex ---
\documentclass{article}
\usepackage{graphicx}
\usepackage{fancyvrb}
\newcommand{\Rlogo}{\protect\includegraphics[height=1.8ex,keepaspectratio]{Rlogo.pdf}}
\newcommand{\myinput}[1]
Dear Experts,
I am trying to do a time-stratified case-crossover analysis on air pollution
data and number of myocardial infarctions. In order to avoid model selection
bias, I started with a simple simulation.
I'm still not sure if my simulation is right. But the results I get from the
Thank you, uwe and jeremy. I was actually looking exactly for that! But
something still doesn't work:
I want to plot a symbol in a legend of a plot, lets say \sigma = 2. 2
should be the value of a variable. So, when I try
mySigma=2;plot(1:10,dnorm(1:10,sd=mySigma),type='l')
Jean,
this is nice, but 1) the logo is a bitmap, it is ugly if you
resize it, 2) you don't need a pdf version for pdflatex, it
handles jpg (and maybe also png as well), so you can
just use the logos at the R developer site.
It would be really nice to have a non-bitmap version, though.
If it
Hi,
Thakns all for your help
I am doing the next in my dataframe tabla, column pend1, because the
Lilliefors (Kolmogorov-Smirnov) test give me a pvalue alfa. (data no
normal distribution). I need do a transformation with box-cox or
other:
bc - boxcox.fit(tabla$pend1)
R send to me:
Error in
Hi, netters,
This is probably a rookie question but I couldn't find the answer after hours
of searching and trying.
Suppose there'a a dataframe M:
x y
10 A
13 B
8 A
11 A
I want to locate the rows where x =10 and y=A. I know how to do it to
vectors by using
which, but how to
On Mar 7, 2008, at 10:50 AM, zhihuali wrote:
Hi, netters,
This is probably a rookie question but I couldn't find the answer
after hours of searching and trying.
Suppose there'a a dataframe M:
x y
10 A
13 B
8 A
11 A
I want to locate the rows where x =10 and y=A. I
Hi Zhihua,
M - data.frame (x=c(10, 13, 8, 11), y=c('A', 'B', 'A', 'A'))
which (M$x = 10 M$y == 'A')
# [1] 1 4
Hope it helps,
Nael
2008/3/7 N. Lapidus [EMAIL PROTECTED]:
Hi Zhihua,
M - data.frame (x=c(10, 13, 8, 11), y=c('A', 'B', 'A', 'A'))
which (M$x = 10 M$y == 'A')
# [1] 1 4
Hope
You might want to read
Ligges, U. (2002): R Help Desk: Automation of Mathematical Annotation
in Plots. R News 2 (3), 32-34.
with an example at the end that meets your requirements:
(please note that I removed those ugly ;
mySigma[1] - 2
mySigma[2] - 3
plot(1:10, dnorm(1:10, sd = mySigma[1]),
Hello,
I am looking for advice on a task I am trying to complete.
I have a 4 column dataframe defining the start and end coordinates of
line edges (from a CGAL alpha shapes function to define concave hulls
from point clusters). I would like to create polygon shapefiles from
these line edges,
Or my personal favorite if the length of mySigma is variable:
mySigma - 2:3
plot(1:10, dnorm(1:10, sd = mySigma[1]), type = 'l')
lines(dnorm(1:10,sd = mySigma[2]),lty = 2)
leg - as.expression(lapply(mySigma, function(x) bquote(sigma == .(x
legend(x = topright, lty = c(1,2),legend = leg)
Hi,
Can anyone explain the following error??
Error in FUN(newX[, i], ...) : missing observations in cov/cor
In addition: Warning message:
In FUN(newX[, i], ...) : NAs introduced by coercion
svm_modelSAheart1 - svm(x_training, y_training) is the command i am
using.my x/y training are working
I would like to thank Brian Ripley and Torsten Hothorn for their quick and
thoughtful responses.
I rerun the example given by Professor Ripley by just starting R and
sourcing the code below and I got slightly different results. Then I ran
it again setting the random seed before the sample
Gabor,
this is nice, but
1) the logo is a bitmap, it is ugly if you resize it
Sure, it's a bitmap, but the naked eye resolution is only
100 $\mu$m so that a vectorized solution is overkilling
in most common situations IMHO. I have to zoom by a factor
1200% to see some pixellization problems
I finally got everything plotted as I had planned. So, thank you again.
Sundars suggestion looks more flexible when it comes to large numbers of
categories (i.e. sigmas). In the plot I will be using, there are 3 sigmas...
I am keen to learn about that bquote and substitute stuff. I will
After some struggling with the data format, non-standard in
BioConductor, I have gotten cor.balance in package CORREP to work. My
desire was to obtain maximum-likelihood p-values from the same data
object using cor.LRtest, but it appears that this function wants
something different, which I
I have a set of data that consists of a number of biological measurements.
The columns are Time that runs from 01/01/2005 to 01/5/2007, Group which has
23 levels and postcode which is nested within group. This is a balanced panel
but the number of postcodes differs within groups, from 15
Jean,
On Fri, Mar 07, 2008 at 06:09:35PM +0100, Jean lobry wrote:
Gabor,
this is nice, but
1) the logo is a bitmap, it is ugly if you resize it
Sure, it's a bitmap, but the naked eye resolution is only
100 $\mu$m so that a vectorized solution is overkilling
in most common situations
Hi
I have been trawling the web, FAQs, and R manuals for help on the following
issue, but have failed and was wondering if anyone has a solution to the
following problem:
After having installed R 2.6.2 for Windows (binary), I tried to install various
packages. Every time I try loading a
Friends,
I changed one line of a package at the source level and then rebuilt it.
When I run R CMD check, I get an error:
installing R.css in C:/polsplineRS.Rcheck
-- Making package polsplineRS
adding build stamp to DESCRIPTION
making DLL ...
making hareall.d from
Dear UseRs,
I'm curious about the derivative of n!.
We know that Gamma(n+1)=n! So when on takes the derivative of
Gamma(n+1) we get Int(ln(x)*exp(-x)*x^n,x=0..Inf).
I've tried code like
integrand-function(x) {log(x)*exp(x)*x^n}
integrate(integrand,lower=0,upper=Inf)
It seems that R doesn't
Thanks! That's seemed to partially work, but now when I try to load it
in R I get:
library(polsplineRS)
Error in library.dynam(polspline, pkg, lib) :
shared library 'polspline' not found
Error in library(polsplineRS) : .First.lib failed for 'polsplineRS'
-Original Message-
Hi Max,
The analytic integral \int _0 ^\Inf exp(-t) t^n log(t) might not converge
because the integrand tends to -Inf as t - 0.
So, here is a numerical approach to estimating the derivative of the gamma
function:
library(numDeriv)
fx - function(x, n) exp(-x) * x^n
gf - function(n)
Prof Brian Ripley formulated on Friday :
On Fri, 7 Mar 2008, Max wrote:
Dear UseRs,
I'm curious about the derivative of n!.
We know that Gamma(n+1)=n! So when on takes the derivative of
Gamma(n+1) we get Int(ln(x)*exp(-x)*x^n,x=0..Inf).
I've tried code like
integrand-function(x)
Hi max,
Prof. Ripley is right. Your problem is that you missed a (-) sign in the
exponential. Here is a demonstration showing the agreement between
numerical and analytical results:
gx - function(x, n) exp(-x) * x^n * log(x)
df - function(n) {integrate(gx, lower=0, upper=Inf, n=n)$val}
Hi,
I get the following error when I try to predict the probabilities of a
test sample:
Error in predict.randomForest(fit.EBA.OM.rf.50, x.OM, type = prob) :
New factor levels not present in the training data
I have about 630 predictor variables in the dataset x.OM (25 factor
variables and the
1. This is not reproducible.
Lines was not provided in reproducible form.
Please look at my prior emails and use that
form so that one can copy from your post and
paste it directly into R and observe the error.
2. What do you mean by does not plot? Do you get
an error or does nothing appear? If
bayesm version 2.2-0 is now available on CRAN.
Major changes include:
1. general density estimation using a Dirichlet Process Prior and a
normal base
2. linear instrumental variable models with unknown error distributions
(the Bayesian analogue of IV methods). Achieved via DP priors.
peter
Dear All,
I have a function f(x,y,z)=exp(x^3+y^4+x^2*y+x*z^2+y/z) over D, where is D={
(x,y,z)| 0 zInf, 0yc1*z, 0xc2*/y}. x,y,z are all vectors and c1 and c2
are constants. I tried the adapt package and I get some error. This is the
error message:
Error in function (z, y, x) : argument x is
Also, see the nearZeroVar function in the caret package.
MAx
On Fri, Mar 7, 2008 at 7:41 AM, Charilaos Skiadas [EMAIL PROTECTED] wrote:
On Mar 7, 2008, at 2:17 AM, Oldrich Kruza wrote:
Hello Soumyadeep,
if you store the data in a tabular file, then I suggest using standard
On Fri, 7 Mar 2008, Max wrote:
Prof Brian Ripley formulated on Friday :
On Fri, 7 Mar 2008, Max wrote:
Dear UseRs,
I'm curious about the derivative of n!.
We know that Gamma(n+1)=n! So when on takes the derivative of
Gamma(n+1) we get Int(ln(x)*exp(-x)*x^n,x=0..Inf).
I've tried code
Is there a way to combine two columns within a data frame?
Example data:
id snp AL1 AL2
150030 A B
151030 A A
152030 A B
This is what I would like:
indvsnp AL1AL2
150030 AB
151030 AA
152030 AB
Any
Try:
transform(x, AL1Al2 = paste(AL1, AL2, sep=''))[-c(3:4)]
On 07/03/2008, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Is there a way to combine two columns within a data frame?
Example data:
id snp AL1 AL2
150030 A B
151030 A A
152030
Or perhaps:
myfun - function(fname, ...)match.fun(fname)(...)
On 07/03/2008, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Was wondering if it is possible to pass function name as a parameter
Yes. This isn't exactly what you wanted, but it demonstrates the
principle.
x = rnorm(5)
[1]
Depending on your purpose you might want to look
at ?interaction or its synonym : (i.e. a colon)
On Fri, Mar 7, 2008 at 4:09 PM, [EMAIL PROTECTED] wrote:
Is there a way to combine two columns within a data frame?
Example data:
id snp AL1 AL2
150030 A B
1510
Dale,
Other than the first SAS contrast, does the following demonstrate what
your asking for?
summary(twoway)
material temp voltage
1:12 50:12 Min. : 20
2:12 65:12 1st Qu.: 70
3:12 80:12 Median :108
Mean :106
3rd
Dear list,
I just made a very simple mistake, but it was hard to spot. And I
think that I should warn other people, because it is probably so
simple to make...
=== R code ===
# Let us create a matrix:
(a - cbind(c(0,1,1), rep(1,3)))
# [,1] [,2]
# [1,]01
# [2,]11
# [3,]
Hello,
I have an irregular time series of the form :
Time Data Time1 Data1
1 b1 e
7 g 4i
NA NA 5 k
NA NA NA NA ...
(the columns have varying length of NAs after a certain point)
Converting this to regular time
and you might want to check ?prop.table
prop.table(a, 2)
[,1] [,2]
[1,] 0.0 0.333
[2,] 0.5 0.333
[3,] 0.5 0.333
or even ?sweep (which will be useful for more complex situations)
sweep(a, 2, colSums(a), /)
[,1] [,2]
[1,] 0.0 0.333
[2,] 0.5 0.333
Hi all:
I have always used SPSS to estimate weekly
covariance based on a linear regression model
but have to hard code the model Std. Error and the
Mean-Square and then execute
one week a the time. I was wondering if someone
could give me an idea on how to estimate
weekly(WK) covariance
R is working exactly as documented. If you look at how the matrix is
stored (column-wise) and then what you are dividing by, you will see
that it is doing what you asked (when recycling values):
as.vector(a)
[1] 0 1 1 1 1 1
as.vector(a)/c(2,3)
[1] 0.000 0.333 0.500 0.333
Dear all,
Thank you very much for all your valuable suggestions!
Best wishes,
Alexey Shipunov
__
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Works fine for me on the same setup. Try this and compare (especially
the size of the downloaded file):
url - http://cran.uk.r-project.org/bin/windows/contrib/2.6/ada_2.0-1.zip;;
download.file(url, basename(url), mode=wb) # Note wb!!!
trying URL
As the error message says: the transformation requires positive data
Your data has a minimum value at zero. That means it is merely
non-negative.
Positive means all the values must be greater than zero. Strictly.
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On
The error message is pretty clear, really. To spell it out a bit more,
what you have done is as follows.
Your training set has factor variables in it. Suppose one of them is
f. In the training set it has 5 levels, say.
Your test set also has a factor f, as it must, but it appears that in
the
Have you considered using 'corCAR1' with 'lme' in the 'nlme'
package?
Hope this helps.
Spencer Graves
p.s. If you are not familiar with this, I highly recommend Pinheiro,
J.C., and Bates, D.M. (2000) Mixed-Effects Models in S and S-PLUS
(Springer). The
Thank you very much. I'll jump in to the data and verify the
consistency between the training and testing variables and their
levels.
On Fri, Mar 7, 2008 at 5:14 PM, [EMAIL PROTECTED] wrote:
The error message is pretty clear, really. To spell it out a bit more,
what you have done is as
I have a table like the following. I want to fit Cm to Vm like this:
Cm ~
Cl+Q1*b1*38.67*exp(-b1*(Vm-Vp1)*0.03867)/(1+exp(-b1*(Vm-Vp1)*0.03867))^2+Q2*b2*38.67*exp(-b2*(Vm-Vp2)*0.03867)/(1+exp(-b2*(Vm-Vp2)*0.03867))^2
I use nls, with start=list(Q1=2e-3, b1=1, Vp1=-25, Q2=3e-3, b2=1,
Vp2=200). But
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