/ I am trying to fit a non linear regression model to time series data.
//
// If I do this:
// reg.logis = nls(myVar~SSlogis(myTime,Asym,xmid,scal))
// I get this error message (translated to English from French):
// Erreur in nls(y ~ 1/(1 + exp((xmid - x)/scal)), data = xy, start =
//
Dear all,
I have problems with the lmer output (see
below)(2.6.2, WindowsXP), it is incomplete (no DFs, no
p-values)and also generating an anova-table doesn´t
work out. What is the fault? Does anybody know?
This example is about plant height within different
treatments (each with 5 replicates)
Dear list,
sorry for asking a more statistical question. I have been reading on
penalyzing estimates of regression and bootstrapping regression,
trying to include both or either in my analysis. But it is not clear
to me (mainly due to my non-statistics background) whether they aim to
do
The R command line (Rterm.exe) under cygwin seems to hang after the computer is
locked (the screensaver got activated).
It is not strictly reproducible, sometimes there is no problem after logging in
again.
There seems to be no reaction of Rterm/cygwin to anything I type, whether it is
a
Hi,
It works for me to import spss datasets via library(foreign) with read.spss or
via library Hmisc by (spss.get).
But no matter which way I do import the data, user-defined missings from Spss
are always lost.
(it makes no difference if there are a single value, a range, or any
combination
Hi,
I read in some tabular data using this:
read.table(file, quote = \, header = TRUE, sep = \t,
stringsAsFactors = FALSE, comment.char = )
One slight problem I have now is that some columns in the data set contain
either or +, which means FALSE or TRUE respectively. The command
Hello,
I'm new to R and have a very basic syntax question for the
functionglm. I am using the function glm() to do a regression on a
data set. I want to run this function in a while loop, so I need to be
able to do two things:
(1) I need to be able to have my list of variables in the regression
Maria,
you might get an answer in this thread, from Douglas Bates
lmer, p-values and all that, dated May 19 2006
HTH
David
Maria Meyen [EMAIL PROTECTED] ha escrito:
Dear all,
I have problems with the lmer output (see
below)(2.6.2, WindowsXP), it is incomplete (no DFs, no
p-values)and
Hi Maria,
the output is not incomplete. See the FAQ here:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-are-p_002dvalues-not-displayed-when-using-lmer_0028_0029_003f
and the lengthy discussions about p-values and lmer (try Google).
Andrew
On Tue, Apr 15, 2008 at 10:51:46AM +0200, Maria
Dear R Helpers,
I am running R 2.6.2 on a Windows XP machine.
I am trying to use regexpr to locate full stops in strings, but, without
success.
Here an example:-
f=a,[EMAIL PROTECTED]: #define an arbitrary test string
regexpr(',',f) #find the occurrences of ',' in f - should be one at location
Define those columns as being character with colClasses and then use
'ifelse' to change it to boolean:
x - c(, , +, , +)
x
[1] + +
y - ifelse(x == , FALSE, TRUE)
y
[1] FALSE FALSE TRUE FALSE TRUE
On Tue, Apr 15, 2008 at 5:10 AM, Johannes Graumann
[EMAIL PROTECTED] wrote:
Hi,
I
Dear Naiara and Andy,
My strategy in cases with unbalanced data is:
tmp - as.vector(table(factors));
num_clases - length(tmp);
min_size - tmp[order(tmp,decreasing=FALSE)[1]];
vector_for_sampsize - rep(min_size,num_clases);
Then:
randomForest(..., y=factors, sampsize=vector_for_sampsize)
I hope
Thanks.
Prof Brian Ripley wrote:
Which messages? R.app and R itself handle this differently for their
messages.
You will find a discussion in the 'R Installation and Administration'
manual. You don't give an address, but I suspect you are in a
Spanish-speaking locale. I believe the
You have already had a reply to a version of this (posted from another
address) at https://stat.ethz.ch/pipermail/r-help/2008-April/159342.html .
'Kind souls' are likely to get exasperated when their help is
unacknowledged.
You need SPSS and Windows to reproduce this, and this is the R forum.
...
On 10 mar, 17:00, Liaw, Andy [EMAIL PROTECTED] wrote:
Are you sure there are 100 sites in your data? Here's an example:
R library(randomForest)randomForest4.5-23
Type rfNews() to see new features/changes/bug fixes.
R f - factor(sample(1:4, nrow(iris), replace=TRUE))
R rf1
In a regular expression, '.' matches any character, which will be the
first one. If you want to match a period, you have to escape it:
f=a,[EMAIL PROTECTED]: #define an arbitrary test string
regexpr('.',f)
[1] 1
attr(,match.length)
[1] 1
regexpr('\\.',f)
[1] 4
attr(,match.length)
[1] 1
On
On Tue, 15 Apr 2008, [Ricardo Rodriguez] Your XEN ICT Team wrote:
Thanks.
Prof Brian Ripley wrote:
Which messages? R.app and R itself handle this differently for their
messages.
You will find a discussion in the 'R Installation and Administration'
manual. You don't give an address, but
On Tue, 15 Apr 2008, jim holtman wrote:
Define those columns as being character with colClasses and then use
'ifelse' to change it to boolean:
x - c(, , +, , +)
x
[1] + +
y - ifelse(x == , FALSE, TRUE)
y
[1] FALSE FALSE TRUE FALSE TRUE
Or define a custom class with an as()
Please, one question
I have a two dimensional data (X,Y) that I want to represent with different
colours,
I want to make a plot with a graduate color scale at right, or below
Can you help me, please?
Thank you very much
[[alternative HTML version deleted]]
summary:
The function 'by' inconsistently strips class from the data to which
it is applied.
quick reason:
tapply strips class when simplify is set to TRUE (the default) due to
the class stripping behaviour of unlist.
quick answer:
This can be fixed by invoking tapply with simplify=FALSE,
Hello
Are you working with parametric (your title) or non-parametric (your
text) data? And what type of data (time series?)? Finally what kind of
non-linearities are you interested in?
Non-linear regression models (threshold autoregression, smooth
transition, ANN) are avalaible in package
Try
On Tue, Apr 15, 2008 at 6:07 AM, maud [EMAIL PROTECTED] wrote:
Hello,
I'm new to R and have a very basic syntax question for the
functionglm. I am using the function glm() to do a regression on a
data set. I want to run this function in a while loop, so I need to be
able to do two
DAVID ARTETA GARCIA wrote:
Dear list,
sorry for asking a more statistical question. I have been reading on
penalyzing estimates of regression and bootstrapping regression,
trying to include both or either in my analysis. But it is not clear
to me (mainly due to my non-statistics
Hi
Could anyone please explain to me the difference between the = and the ==?
I'm quite new to R and I've tried to find out but didn't get any wiser...
Thanks
--
View this message in context:
http://www.nabble.com/%3D-vs.-%3D%3D--tp16700216p16700216.html
Sent from the R help mailing list
I'm sure you'll get a friendlier answer, but... see
?=
?==
Introduction to R
G.
On Tue, Apr 15, 2008 at 05:28:53AM -0700, Linn wrote:
Hi
Could anyone please explain to me the difference between the = and the ==?
I'm quite new to R and I've tried to find out but didn't get any wiser...
Hi.
= means assignment (like a=2, may be used instead of a - 2, although
I prefer to always use -); It is also used to pass values to
arguments in named argument lists, or to set default argument values).
== is the boolean (logical) operator for testing whether two values are equal
e.g. a - 2
Hi,
Given the following,
a - rnorm(5)
b - rnorm(5)
c - rnorm(5)
a.1g.scale - scale(c(a,b,c))[1:5]
b.1g.scale - scale(c(a,b,c))[6:10]
c.1g.scale - scale(c(a,b,c))[11:15]
a.2g.scale - scale(c(a,b))[1:5]
b.2g.scale - scale(c(a,b))[6:10]
c.2g.scale - scale(c)
a.3g.scale - scale(a)
b.3g.scale -
Hi,
I have created a number of custom functions, and hope to reuse them in other
source files. How should I go about doing that ?
Thanks
Stanley
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Ng Stanley wrote:
Hi,
I have created a number of custom functions, and hope to reuse them in other
source files. How should I go about doing that ?
The best way is to create a package to hold them, then just use
library(MyPackage)
to attach them. See Writing R Extensions for
Why should it not be the same? Its the same dataset (up to scaling) you
are testing on. Your effect (mean difference) will be different, but not
your (standardized) t-statistic and df and therefore not your p-value.
You will get the same result for the first if you simply test
t.test(a,b)
hth.
On 15-Apr-08 12:28:53, Linn wrote:
Hi
Could anyone please explain to me the difference between
the = and the ==?
I'm quite new to R and I've tried to find out but didn't
get any wiser...
Thanks
While these are indeed documented in ?= and ?==, as
Gabor Csardi has pointed out, these
Hi all,
In Spanish vowels with accent like á, é, ... doesn't affect to the
alphabetical order of vector of strings. I mean, a or á don't matter for
establishing the alphabetical order.
Nevertheless, while working with R order, here is what I get.
Given a file transport.txt
medio#variable
When discussing statistics in e-mail based discussion groups, or in
newsgroups, it is sometimes useful to include simple, text-based
statistical graphics. Here is an example, a histogram (only useful
with a fixed-width font, obviously).
:.
Thanks for your inputs. colClasses will be learned.
Joh
Prof Brian Ripley wrote:
On Tue, 15 Apr 2008, jim holtman wrote:
Define those columns as being character with colClasses and then use
'ifelse' to change it to boolean:
x - c(, , +, , +)
x
[1] + +
y - ifelse(x == , FALSE,
This is a known Mac OS X bug, nothing to do with R which uses the system
functions (strcoll/wcscoll) for such things.
If you look at the help for sort, it refers you to ?Comparison. Which
says
Comparison of strings in character vectors is lexicographic within
the strings using the
Dear R users,
This is a basic question.
I want to fit a Weibull distribution. fitdistr(data, weibull) works and it
is a maximum likelihood fitting. Is it a good method ? Or is it better to
write a function for the log-likelihood and the gradient and to use a
numerical routine ?
Fitdistr works
I like to find out more about plotmath
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
Emmanuel Birdling wrote:
I like to find out more about plotmath
See the extensive help page
?plotmath
and the article referenced therein
Murrell, P. and Ihaka, R. (2000) An approach to providing
mathematical annotation in plots. _Journal of Computational and
Graphical Statistics_, *9*,
I look for codes sources of R (examples of application) to implement
examples on Monte Carlo, MCMC and Gibbs sampling.
--
Dr. P. NGOM,
Faculté des Sciences et Techniques
Département de Mathématiques et Informatique
Université Cheikh Anta Diop Dakar - Sénégal
See MCMCpack package
On Tue, Apr 15, 2008 at 12:59 PM, [EMAIL PROTECTED] wrote:
I look for codes sources of R (examples of application) to implement
examples on Monte Carlo, MCMC and Gibbs sampling.
--
Dr. P. NGOM,
Faculté des Sciences et Techniques
Département de Mathématiques et
I am looking for an algorithm (written in R (preferably) or C,
but even pseudo-code in a text book maybe fine)
to determine the sign of a permutation.
What is that? Well, a permutation is either even or odd, the
sign is +1 or -1, respectively, see, e.g.,
Hello, all,
First thanks in advance for helping me.
I am now handling a data frame, dimension 11095400 rows and 4 columns. It
seems work perfect in my MAC R (Mac Pro, Intel Chip with 4G RAM) until I was
trying to write this file out using the command:
When I first started using an early port of S, the main way to create
graphs was with the printer graphics device which created plots like
this (back then that was impressive). S-PLUS does still have the
printer graphics device to do things like this, but I don't think that
anyone has ever
On Mon, 2008-04-14 at 17:00 -0400, Sarah Goslee wrote:
On Mon, Apr 14, 2008 at 4:47 PM, Gavin Simpson [EMAIL PROTECTED] wrote:
Note that the default is to produce a bray-curtis dissimilarity matrix
from the input species data. As such, I reproduce this dissimilarity
matrix as arg 1 to
Ok,
thanks a lot, everyone!
Yes, I should rather have started thinking a bit more myself,
before going the easy route to R-help
Anyway, the most obvious algorithm,
just putting things into place by swapping elements,
and counting how many times you have to swap, is easy and
quite efficient.
merca duria [EMAIL PROTECTED] wrote:
I have a two dimensional data (X,Y) that I want to represent with different
colours,
I want to make a plot with a graduate color scale at right, or below
Take a look at the levelplot function in the lattice package.
require(lattice)
?levelplot
--
On Fri, Apr 11, 2008 at 11:05 AM, Thiemo Fetzer [EMAIL PROTECTED] wrote:
Hello to the whole group.
I am a newbie to R, but I got my way through and think it is a lot easier to
handle than other software packages (far less clicks necessary).
[snip]
However, my wish is the output to have a
On Mon, 14 Apr 2008, Jarrett Byrnes wrote:
Quick question about the usage of glht. I'm working with a data set
from an experiment where the response is bounded at 0 whose variance
increases with the mean, and is continuous. A Gamma error
distribution with a log link seemed like the logical
On Tue, Apr 8, 2008 at 1:23 PM, Paul Johnson [EMAIL PROTECTED] wrote:
On Tue, Apr 8, 2008 at 4:29 AM, Prof Brian Ripley [EMAIL PROTECTED] wrote:
Looks likes the the laptop is using different fonts with incorrect font
metrics. This could happen because it has a different screen resolution,
Hi Xiaojing,
That's a big table!
You might try 'write' (you'll have to work harder to get your data into
an appropriate format).
You might also try the R-2.7 release candidate, which I think is
available here
http://r.research.att.com/
for the mac. There was a change in R-2.7 that will make
Try to write the data.frame to file in blocks of rows by calling
write.table() multiple times - see argument 'append' for
write.table(). That will probably require less memory.
/Henrik
On Tue, Apr 15, 2008 at 6:12 PM, Xiaojing Wang [EMAIL PROTECTED] wrote:
Hello, all,
First thanks in
Matthew B. mtthw.bt at gmail.com writes:
Dear R users,
This is a basic question.
I want to fit a Weibull distribution. fitdistr(data, weibull) works and it
is a maximum likelihood fitting. Is it a good method ? Or is it better to
write a function for the log-likelihood and the gradient
Martin Maechler wrote:
Ok,
thanks a lot, everyone!
Yes, I should rather have started thinking a bit more myself,
before going the easy route to R-help
Anyway, the most obvious algorithm,
just putting things into place by swapping elements,
and counting how many times you have to swap,
Ben Bolker wrote:
Matthew B. mtthw.bt at gmail.com writes:
Dear R users,
This is a basic question.
I want to fit a Weibull distribution. fitdistr(data, weibull) works and it
is a maximum likelihood fitting. Is it a good method ? Or is it better to
write a function for the
For (possibly) censored data, survreg() in package survival can be used
(just regress on a constant). The parametrization is slightly different
from [dpqr]weibull, but it is easy to do the translation.
On Tue, 15 Apr 2008, Ben Bolker wrote:
Matthew B. mtthw.bt at gmail.com writes:
Dear R
What are you going to do with the table after you write it out? Are
you just going to read it back into R? If so, have you tried using
'save'?
On Tue, Apr 15, 2008 at 12:12 PM, Xiaojing Wang [EMAIL PROTECTED] wrote:
Hello, all,
First thanks in advance for helping me.
I am now handling a
Thank you
I don't know anything about survival regressions. Where should I start ?
(anything to read ?)
Maybe it is better or easier for me to write my own functions.
2008/4/15, Prof Brian Ripley [EMAIL PROTECTED]:
For (possibly) censored data, survreg() in package survival can be used
(just
I would look at Sweave, particularly outputting to LaTeX. Then have a
look at the xtable or Hmisc's latex() functions.
I believe one can write to OpenOffice file formats too which may be an
alternative solution.
Best wishes,
Mark
On 14/04/2008, Ng Stanley [EMAIL PROTECTED] wrote:
Hi,
Is
Dear List,
I have two questions about how to do predictions using lrm, specifically
how to predict the ordinal response for each observation *individually*.
I'm very new to cumulative odds models, so my apologies if my questions are
too basic.
I have a dataset with 4000 observations.
On Tue, 15 Apr 2008, Matthew B. wrote:
Thank you
I don't know anything about survival regressions. Where should I start ?
(anything to read ?)
MASS, same as for fitdistr.
Maybe it is better or easier for me to write my own functions.
2008/4/15, Prof Brian Ripley [EMAIL PROTECTED]:
For
On Sun, Apr 06, 2008 at 07:30:48PM -0500, Dirk Eddelbuettel wrote:
On 6 April 2008 at 23:58, (Ted Harding) wrote:
| Hi Folks,
| A while ago (September 2007) I set up an experimental
| Debian 4.0 Etch installation, and installed R on it,
| along with several packages -- including e1071 and
To reply, in case anyone reads this, the problem was of course in the setup
of the matrix, and there are two possible solutions.
The first, for a model with only a single set of groupings, is to use mcp.
So, even with this contrast matrix
contra-rbind(A v. B = c(-1,1,0,0),
Ok, if I have to make the spss file available, then I hope an attachment is
fine.
I really would appreciate if any 'kind soul' would give me a push into the
right direction to solve this problem.
The spss file contains only two variables and five cases. For one case both
values are defined as
Dear R community,I am creating large graphs with hundreds of
thousands of datapoints. My usual way for output was pdf, but now I am
getting file sizes of 30Mb that do not open well (or at all) in Adobe. Is
there a way to reduce the resolution or get rid of overlaying datapoints?
Any other
Dear Stanley, Alternatively you can also look at textplot from the
gregmisc package.
Cheers, Georg.
Georg Ehret
Johns Hopkins
Baltimore, US
On Tue, Apr 15, 2008 at 4:11 PM, Mark Wardle [EMAIL PROTECTED] wrote:
I would look at Sweave, particularly outputting to LaTeX.
Tricky question, this order issue :-(
Thank you so much for the detailed explanation.
Thus, please, must I conclude that I will have to survive with this
ASCII order while working in Mac OS X 10.5.2 until Mac people fix this bug?
You spoke about es_ES.ISO8859-15 in Mac. Will it do the trick?
It's probably best to choose a different format like PNG or jpeg.
-roger
On Tue, Apr 15, 2008 at 5:22 PM, Georg Ehret [EMAIL PROTECTED] wrote:
Dear R community,I am creating large graphs with hundreds of
thousands of datapoints. My usual way for output was pdf, but now I am
getting
As a followup, what about wrting ANOVA tables and such to files? I keep
getting odd errors converting an ANOVA object to a data frame and such.
Mark Wardle wrote:
I would look at Sweave, particularly outputting to LaTeX. Then have a
look at the xtable or Hmisc's latex() functions.
I
Hello!
I suppose this is more a matrix theory question than a question on R,
but I will give it a try...
I am using La.svd to compute the singular value decomposition (SVD) of
a variance matrix, i.e., a symmetric nonnegative definite square
matrix. Let S be my variance matrix, and S = U D V' be
Thanks all,
[EMAIL PROTECTED] wrote:
From: [Ricardo Rodriguez] Your XEN ICT Team [EMAIL PROTECTED]
Date: 2008/04/14 Mon PM 07:43:23 CDT
To: Henrique Dallazuanna [EMAIL PROTECTED], r-help@r-project.org
Subject: Re: [R] looking for a string
henrique means to use his command directly and
Almost done...
Sys.setlocale(category = LC_ALL, locale = es_ES.ISO8859-15)
The order is now correct, but it renders incorrectly most of the
non-ASCII characters, both in console:
1 √\201guilas de mantenimiento 1.97 NA 1.72
2 √\201ngeles de la CONAGUA 1.77 1.97 1.94
And in quartz():
Yes. SVD of any symmetric (which is, of course, also square) matrix will
always have U = V. Also, SVD is the same as spectral decomposition, and the
columns of U and V are the eigenvectors, but the singular values will be the
absolute value of eigenvalues.
Ravi.
But you also might have the additional problem that too many data points
just produce an incoherent solid blob, no matter the format.
Lots of folks have written about this. Check out JCGS and computer graphics
literature for ideas. Also,this is one arena where fancy, dynamic,
interactive software
Thanks Mark!
[EMAIL PROTECTED] wrote:
From: [Ricardo Rodriguez] Your XEN ICT Team [EMAIL PROTECTED]
Date: 2008/04/15 Tue PM 04:48:12 CDT
To: [EMAIL PROTECTED], r-help@r-project.org
Subject: Re: [R] looking for a string
Hi Ricardo: you can use the idea you
found below to apply
Let me correct my reply a bit.
U and V will differ by a factor of (-1) corresponding to negative
eigenvalues (if any) of a general symmetric A. However, for symmetric
positive-definite matrices (e.g. variance-covariance matrix), they will be
identical.
Ravi.
On 15/04/2008 5:22 PM, Georg Ehret wrote:
Dear R community,I am creating large graphs with hundreds of
thousands of datapoints. My usual way for output was pdf, but now I am
getting file sizes of 30Mb that do not open well (or at all) in Adobe. Is
there a way to reduce the resolution
Hi,
I am running an R script from the command line by calling:
R --vanilla test.R
My terminal is part of the Xwin (Xterm) and there is a plot(1:10)
command in the test.R script.
This will not produce a grahic though. When I start R by calling R then
plotting from the R command in the same
Hi Peter-
that worked wonderfully! I am having a hard time adding labels to the
tick marks. I've tried a myriad of things. I just want to label the
ticks 1- 23.
any thoughts?
thanks again for your help!
sheck
Peter Alspach wrote:
Sherri
Is this what you want?
sherri -
x - read.table(LittleGarvin.csv, sep=,, header=TRUE)
y - t(x)
str(y)
chr [1:193, 1:288] oligocha 0 0 0 0 0 ...
- attr(*, dimnames)=List of 2
..$ : chr [1:193] X upwd1201 upwd0502 upwd0702 ...
..$ : NULL
x is a data frame with a whole bunch of numeric vectors I would like for the
rows
jayhegde wrote:
Dear List,
I have two questions about how to do predictions using lrm, specifically
how to predict the ordinal response for each observation *individually*.
I'm very new to cumulative odds models, so my apologies if my questions are
too basic.
I have a dataset
I have a species as rows and sites as columns matrix. I would like to
tranpose this matrix so that I can do an NMDS analysis with the vegan
package. I have used
y - t(x)
and it indeed transposes the matrix, but it changes the whole make up
chr [1:193, 1:288] oligocha 0 0 0 0 0 ...
-
Linn wrote:
Hi
Could anyone please explain to me the difference between the = and the ==?
I'm quite new to R and I've tried to find out but didn't get any wiser...
= is the assignment operator as in
x = 3
x
[1] 3
(but use the - operator instead, see a post by Bill Venables a few
days
RML: *** Data frames are NOT matrices!!! ***
On 16/04/2008, at 10:35 AM, stephen sefick wrote:
x - read.table(LittleGarvin.csv, sep=,, header=TRUE)
y - t(x)
str(y)
chr [1:193, 1:288] oligocha 0 0 0 0 0 ...
- attr(*, dimnames)=List of 2
..$ : chr [1:193] X upwd1201 upwd0502
Hi,
I am building a package which contains some Java class files. I am planning
to create a subdirectory inst/Java/ in the source directory and put Java
files in it, therefore after installing the package, those files will be in
the Java/ subdirectory in where the package is installed. My
Look at the hexbin package (bioconductor I think).
-Original Message-
From: Georg Ehret [EMAIL PROTECTED]
To: r-help [EMAIL PROTECTED]
Sent: 4/15/08 3:23 PM
Subject: [R] heavy graphs
Dear R community,I am creating large graphs with hundreds of
thousands of datapoints. My usual
On 15/04/2008 7:20 PM, Hongshu Chen wrote:
Hi,
I am building a package which contains some Java class files. I am planning
to create a subdirectory inst/Java/ in the source directory and put Java
files in it, therefore after installing the package, those files will be in
the Java/
Hi Ravi,
Thank you for your useful reply. Does the result also hold for
variance-covariance matrices that have one or more zero eigenvalues?
Do you have a reference to suggest?
Thank you again!
Giovanni
Date: Tue, 15 Apr 2008 18:14:11 -0400
From: Ravi Varadhan [EMAIL PROTECTED]
List,
I have looked through several R books and searched the web to find
answers to my questions with no results. I have an ensemble of time
series data (what are essentially Monte Carlo simulations) which I would
like to summarize as a time series of boxplots, by date/time at 6-hr
intervals.
Hi,
How to get assign an vector of words to associative array ?
a[[animal]] - c(dog, cat)
Error in a[[animal]] - c(dog, cat) :
more elements supplied than there are to replace
Thanks
stanley
[[alternative HTML version deleted]]
__
ok
site1 site2 site3 site4
species1 1 2 3 4
species2 30 4 5
species3 5 3 73
spesies4 0 3 67
species1 species2 species3 species4
site1 1
Henrique Dallazuanna from Curitiba writes:
Try
On Tue, Apr 15, 2008 at 6:07 AM, maud [EMAIL PROTECTED] wrote:
[snip]
(1) I need to be able to have my list of variables in the regression
be based from a variable vector instead of hard code.
(2) I need to be able to collect the
On 15/04/2008 8:36 PM, Ng Stanley wrote:
Hi,
How to get assign an vector of words to associative array ?
a[[animal]] - c(dog, cat)
Error in a[[animal]] - c(dog, cat) :
more elements supplied than there are to replace
R uses named lists as associative arrays, but the line above is not
The the use of optim with the L-BFGS-B method for the following simple
function gives erroneous results. Any help appreciated!
Best,
Bob Reilly
# Code:
V=function(p){
p1=p[1];p2=p[2]
y=p1*p2-.4*(p1+p2)
return(-y)}
p=c(.2,.2) # p=c(.8,.8)
max=optim(p,V,method =
dat - read.table(textConnection(
site1 site2 site3 site4
species1 1 2 3 4
species2 30 4 5
species3 5 3 73
spesies4 0 3 67
))
dat
site1 site2
On 15/04/2008 6:59 PM, Bob Reilly wrote:
The the use of optim with the L-BFGS-B method for the following simple
function gives erroneous results. Any help appreciated!
Best,
Bob Reilly
# Code:
V=function(p){
p1=p[1];p2=p[2]
y=p1*p2-.4*(p1+p2)
return(-y)}
p=c(.2,.2) # p=c(.8,.8)
Hi,
I'm trying to do a linear regression style one-way ANOVA using some
data in a data frame, and (perhaps because I am still relatively
unfamiliar with both R and statistics) what I thought I should do was
to make the data frame into a factor. By that I mean that I have a
data frame whose
Hi,
t - list(cat=1)
exists(t)
[1] TRUE
exists(t[[cat]])
Error: unexpected symbol in exists(t[[cat
exists(t[[\cat\]])
[1] FALSE
Thanks
Stanley
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
Thanks that help.
On Wed, Apr 16, 2008 at 8:46 AM, Duncan Murdoch [EMAIL PROTECTED]
wrote:
On 15/04/2008 8:36 PM, Ng Stanley wrote:
Hi,
How to get assign an vector of words to associative array ?
a[[animal]] - c(dog, cat)
Error in a[[animal]] - c(dog, cat) :
more elements
Hi,
We wanted to use R on production systems and business requirements mean
that the software should have technical support.
Is there any company providing support for R?
Regards,
Sankalp
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R-help@r-project.org mailing list
I think you want to look into ?stack. For example:
x-data.frame(a=1:5,b=6:10)
y- stack(x)
Then x$values are the values, and x$ind is the factor.
On Apr 15, 2008, at 9:36 PM, Paul Lynch wrote:
Hi,
I'm trying to do a linear regression style one-way ANOVA using some
data in a data frame,
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