On Fri, 9 May 2008, Michael DiPersio wrote:
I am trying to use winProgressBar, however I find that although
setWinProgressBar updates the value on the screen, getWinProgressBar does
not return this value.
E.g
pb - winProgressBar()
setWinProgressBar(pb, 0.2)
getWinProgressBar(pb)
[1] 0
It
On Fri, May 9, 2008 at 4:04 AM, Federico Calboli
[EMAIL PROTECTED] wrote:
Note that random can be a list:
a one-sided formula of the form ~x1+...+xn, or a pdMat object with a
formula
(i.e. a non-NULL value for formula(object)), or a list of such formulas or
pdMat
objects.
If you can
Hello,
I've a .por file from 1998. I've tried to read it with
library(foreign)
read.spss(mhp_hu.por)
at this point R simply stops working and my whole system is close to unusable
I've found one related thread, but even there no real solution was given
Here is a suggestion
con - textConnection(AnimalA,AnimalB,Score
A1,A2,1
A1,A3,2
A1,A4,3
A2,A3,4
A2,A4,5
A3,A4,6
)
tst - read.csv(con)
close(con)
an - with(tst, sort(unique(c(as.character(AnimalA),
as.character(AnimalB)
M - array(0,
Hi Kate and Fernando,
I'm late into this thread,
but from reading it I get the impression that Fernando really
wants to do *robust* (as opposed to least-squares) non-linear
model fitting. His proposal to set residuals to zero when they
are outside a given bound is a very special case of an
And how are we supposed to help without knowing your version of R, the
version of 'foreign', anything about your system (or you) and without
access to the file?
Please do consult the posting guide and supply enough information that we
have a chance of helping you.
On Sat, 10 May 2008,
Hello R-People!
I am running R 2.7.0 on a Power Book (Tiger). (I am still R and
statistics beginner)
Perhaps this is another stupid question of me, but I was wondering
how I know the needed random (set.seed) numbers, when running
randomForest (library randomForest) on a large dataset.
For learning purposes mainly I attempted to implement hashes/maps/dictionaries
(Python lingua) as S4 classes, see the coding below. I came across some rough S4
edges, but in the end it worked (for one dictionary).
When testing ones sees that the dictionaries D1 and D2 share their environments
Look at the zoo and quantmod packages.
On Sat, May 10, 2008 at 12:51 AM, falcon [EMAIL PROTECTED] wrote:
I am new to R and am trying to solve the following problem:
I have a data file containing tick-by-tick, millisecond level prices for
some stocks. I have another file or two containing
sorry, but it turned out that only the file was bigger than my patience
(next time I will be more careful about the posting guide as well)
thanks for your time!
Viktor
2008/5/10 Prof Brian Ripley [EMAIL PROTECTED]:
And how are we supposed to help without knowing your version of R, the
Fantastic! Thanks very much!
Where can I read more about the double assignment statement at the bottom?
Closest I could get was a double for loop, which takes a long time
Bill.Venables wrote:
Here is a suggestion
con - textConnection(AnimalA,AnimalB,Score
A1,A2,1
A1,A3,2
Hi Hans --
Hans W Borchers [EMAIL PROTECTED] writes:
For learning purposes mainly I attempted to implement hashes/maps/dictionaries
(Python lingua) as S4 classes, see the coding below. I came across some rough
S4
edges, but in the end it worked (for one dictionary).
When testing ones sees
On Sat, 2008-05-10 at 13:21 +0200, Birgit Lemcke wrote:
Hello R-People!
I am running R 2.7.0 on a Power Book (Tiger). (I am still R and
statistics beginner)
Perhaps this is another stupid question of me, but I was wondering
how I know the needed random (set.seed) numbers, when running
On Fri, May 9, 2008 at 7:17 PM, knussear [EMAIL PROTECTED] wrote:
Hi Group
I have a large data set of individual pairwise values (250,000 rows) that I
need to reshape into a pairwise matrix for mantel tests of these values
versus genetic distances.
the data are currently in columns
On May 10, 2008, at 7:30 AM, Hans W Borchers wrote:
For learning purposes mainly I attempted to implement hashes/maps/
dictionaries
(Python lingua) as S4 classes, see the coding below. I came across
some rough S4
edges, but in the end it worked (for one dictionary).
When testing ones sees
Thank you Gavin.
I knew about the meaning set.seed for reproducability but I did not
realise that it is only the starting point.
Is it possible that very small or very big random numbers cause any
kind of bias?
B.
Am 10.05.2008 um 14:50 schrieb Gavin Simpson:
On Sat, 2008-05-10 at
Dear Martin,
Thanks for the ideas regarding the relation of what Fernando is doing with
robust regression. Indeed, it's an important point that he can't consider
the standard error estimates on his parameters correct.
I know from discussion off-list that he's happy with the results he has
now;
Vidhu Choudhary wrote:
Hi All,
*I am still facing the problems in making R package on windows. *
-- Making package t1
adding build stamp to DESCRIPTION
installing NAMESPACE file and metadata
making DLL ...
making
I am cleaning up some character data to convert to
dates using chron. The regex that I am using work fine
but there should be a better way to do this. Can
anyone suggest a cleaner bit of code than the gsub,
sub approach? Thanks
#Test Run on dates.
xx - c(May 1, 2007,
May 2, 2007,
May 3, 2007,
The package AER accompanying the forthcoming book Applied
Econometrics with R by Christian Kleiber and me in the
Springer useR! series has (finally!) been released to CRAN:
http://CRAN.R-project.org/package=AER
It contains some new R functionality
o tobit regression convenience interface (to
An indicator matrix is a binary matrix with orthogonal columns whose
rows sum to 1. A row of this matrix could be [0 1 0 0]. My problem is
to group the similar rows (profiles) so that to create a compact form
of the matrix.
Is there an R function that deals with this problem or do I have to
write
Hello everybody,
I'm new to R. I'm trying to set up a Rbf network using the rbftrain function
but I get an error I can't understand.
this is what I type:
rbftrain(input,3,output,visual=F)
where input is a matrix with 198 rows and 6 columns and output is a matrix
with 198 rows and one column.
Solomon, if i understand two-mode networks properly (they're bipartite, right?),
then this is not hard to do with igraph. Basically, for each vertex create an
order=2 neighborhood, and then create a graph from the adjacency list,
it is something like this:
two.to.one - function(g, keep) {
neis
On 10-May-08 16:49:20, John Kane wrote:
I am cleaning up some character data to convert to
dates using chron. The regex that I am using work fine
but there should be a better way to do this. Can
anyone suggest a cleaner bit of code than the gsub,
sub approach? Thanks
#Test Run on dates.
xx
Try this (no gsub required):
as.chron(as.Date(xx, %b %d, %Y))
On Sat, May 10, 2008 at 12:49 PM, John Kane [EMAIL PROTECTED] wrote:
I am cleaning up some character data to convert to
dates using chron. The regex that I am using work fine
but there should be a better way to do this. Can
anyone
There isn't enough information there to really know but I would at least
try this:
- upgrade to R 2.7
- make sure you are using the most recent version of rtools from
Duncan Murdoch's site
- remove the data directory in your package since its the last thing
referred to prior to the
errors
- if
Colleagues,
I have encountered behavior of random number generation that eludes me.
I generate a random integer in a particular range using the following
code:
sample(1000:, size=1)
This code exists within a script that starts with the command:
remove(list=ls())
Each time
After some investigation I found out that constrained ordination is working
fine under R version 6.5.0 and 6.5.1 but not under any of newer versions. Is
it posible to repair/make something in for example newest version of R 7.0
lito enble correct using of constrained ordination under
Thank to both of you.
I found an interesting document by Uwe Ligges in Rnews December 2002 (Vol
2/3)
The following seems encouraging
x=seq(1,180,by=1)
beta=10
eta=5
plot(x,log(x),type=p,xlab=x,ylab=h(x),main=substitute(Failure rate
* eta==myeta * , * beta ,list(myeta=eta,mybeta=beta)) )
but
On 10/05/2008 4:54 PM, Duncan Murdoch wrote:
On 09/05/2008 11:58 AM, Vidhu Choudhary wrote:
rm: failed to get attributes of `/': No such file or directory
I believe that's a sign of using a bad toolset. Make sure if you have
Cygwin installed, it comes *after* the Rtools on your path. It
Branimir,
You would be better off addressing these issues with the package
maintainer. See the details for the package on CRAN for example to find
out the email address of the maintainer.
You could always use vegan the old-fashioned way and type the relevant
commands at the prompt. If your
Dear list:
I have two dataframes, say dat1 and dat2. Each has several variables but
3 of each are common in both, (say v1, v2 and v3). v1 and v2 are
factores while v3 is numeric. Now, I need a subset to extract the rows
in which v1, v2 and v3 are the same in both dataframes.
I tried:
This seems to work for me:
set.seed(1)
df1 - data.frame(v1=factor(sample(1:4,20,TRUE)),
v2=factor(sample(1:3,20,TRUE)), v3=sample(1:3,20,TRUE))
df2 - data.frame(v1=factor(sample(1:2,20,TRUE)),
v2=factor(sample(1:2,20,TRUE)), v3=sample(1:2,20,TRUE))
subset(df1, (df1$v1 %in% df2$v1)
Thanks for your reply.
In fact I dont get none error message, I just simply found that some
rows do not match in both dataframes. I thought it was some evident
problem with my code, but it seems it is not. I'll try to check and if I
can, I'll post a reproducible example.
Justin
On Sat, 10 May
The following function is designed to work with a logit link. It can
easily be generalized to work with any link. The SEs and CIs are
evaluated accounting for all sources of random variation. The plot
may not be much help unless there is just one explanatory variate.
`ciplot` -
I have time series data in named vectors. They are all the same length for
the same dates.
The dates are in a separate vector.
I want to create a vector of numeric data for every named series, associated
with the dates in a data.frame.
So if...
Names - c(a, b, c)
d - data.frame(dates=Dates,
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