You asked for R to be built as a static lib, not for the front-end to be
statically linked. It is not the R lib it is dynamically linking to (that
is statically linked by default whether or not you ask for a separate
lib), but the OS components.
R depends on dlopen-ing extensions, so there is
From ?contrasts
Usage:
contrasts(x, how.many) - value
...
how.many: How many contrasts should be made. Defaults to one less than
the number of levels of 'x'. This need not be the same as
the number of columns of 'ctr'.
so that is 2 in your example, and it takes the
Solomon, sorry for the delay. In igraph vertices are numbered from 0, so you
need
keep - 0:3
and then the function i've sent seems to work. But i can see that you also have
a solution
now.
Gabor
On Sat, May 17, 2008 at 09:32:27AM -0400, Messing, Solomon O. wrote:
Consider the following two
Thanks, but I'm looking for a more user-friendly environment
that would make the transition from windows to linux
easier for students using the R GUIs in windows,
either the by default GUI or the SciView GUI (which, btw, are both
excellent).
Agus
Vincent Goulet wrote:
Agustin,
Given this
First of all thank you very much, that helped a lot!
Now I have another related problem, again I want to limit a dataframe on
certain elements, the dataframe looks like this:
colnames(sd_all)
[1] Xmydata.a
[3] mydata.xmydata.sd.a
.
.
.
[13] mydata.mad.xsnr
Apologies -- I have just observed my oversight below!
Please ignore the message below.
Ted.
On 20-May-08 09:14:30, Ted Harding wrote:
On 20-May-08 06:10:48, Prof Brian Ripley wrote:
From ?contrasts
Usage:
contrasts(x, how.many) - value
...
how.many: How many contrasts should be made.
Agustin Lobo wrote:
Thanks, but I'm looking for a more user-friendly environment
that would make the transition from windows to linux
easier for students using the R GUIs in windows,
either the by default GUI or the SciView GUI (which, btw, are both
excellent).
Another cross-platform
Hi
[EMAIL PROTECTED] napsal dne 20.05.2008 10:25:00:
First of all thank you very much, that helped a lot!
Now I have another related problem, again I want to limit a dataframe on
certain elements, the dataframe looks like this:
colnames(sd_all)
[1] Xmydata.a
Marianne, I do the equivalent
gnome-terminal -e R
or
xterm -e R
and R starts on the home directory and indicating:
ARGUMENT '/media/mifat32/Rexercises/.RData' __ignored__
Are you sure you do not add any other parameter?
I've tried
xterm -e R --restore
gnome-terminal -e R --restore
same result.
On 20-May-08 06:10:48, Prof Brian Ripley wrote:
From ?contrasts
Usage:
contrasts(x, how.many) - value
...
how.many: How many contrasts should be made. Defaults to one less than
the number of levels of 'x'. This need not be the same as
the number of columns of
ermimi wrote:
Hello Friends!!!
I would want draw a circular histogram, and I would like draw a polygon with
a circular side. This is easy if I use the functions polygon and arc, but I
want that the polygon with a circular side have background colour. The
polygon created with function polygon
sd_all_clusterX-sd_all[(clusterX%in%sd_all$X),] # not tested
seems to do nothing, all elements of the original dataframe are now selected
Petr Pikal wrote:
Hi
[EMAIL PROTECTED] napsal dne 20.05.2008 10:25:00:
First of all thank you very much, that helped a lot!
Now I have
It would help if you would post a reproducible subset of your data. Use
'dput' if including it in the text. All we can do is make a guess since you
have not even include 'str(sd_all)' so we know the structure of your data.
Dear all
I am using NAMESPACE in my package but I would like the user to be able
to overwrite four functions:
own.linkfun, own.linkinv, own.mu.eta and own.valideta.
These are used to defined own link functions.
Is there any way of doing that without getting the when I am checking
the
This is what I was looking for and actually TeachingDemos includes
a lot of very interesting things!
Thanks a lot for making it and for pointing it to me.
Agus
Greg Snow wrote:
The R2HTML package has tools for creating an HTML log of your session (see
?HTMLStart). Or the TeachingDemos
Hi
[EMAIL PROTECTED] napsal dne 20.05.2008 11:43:07:
sd_all_clusterX-sd_all[(clusterX%in%sd_all$X),] # not tested
seems to do nothing, all elements of the original dataframe are now
selected
OK you made me to test it. As you do not provided reproducible example I
used some of my data
Hi Kate and others,
thanks for the info.
Btw, you sent the different
methods to analyze the data: nls, nls.lm and nlrob. Comparing the
results visually nlrob performed better then nls, but nls.lm (using the
0.9 quantile of residuals) was still better than nlrob. My data may
have a rather large
Hi,
Currently the R script I have is executed with this command:
$ R CMD BATCH mycode.R
And the output is stored in mycode.Rout.
Is there a way I can issue command from shell (like above)
so that the output is printed to STDOUT?
It's troublesome to open the Rout file every time to debug.
On 20/05/2008 6:27 AM, Mikis Stasinopoulos wrote:
Dear all
I am using NAMESPACE in my package but I would like the user to be able
to overwrite four functions:
own.linkfun, own.linkinv, own.mu.eta and own.valideta.
These are used to defined own link functions.
Is there any way of doing
Hallo,
does nobody have an answer?
I changed something in the package climatol especially in the
function diagwl. Dos anybody know where I can put the code in the
Internet to discuss it?
I put it to: http://de.pastebin.ca/1023676
It would be kind if someone can have a look what is to make
On 05/20/08 10:42, Agustin Lobo wrote:
Marianne, I do the equivalent
gnome-terminal -e R
or
xterm -e R
and R starts on the home directory and indicating:
ARGUMENT '/media/mifat32/Rexercises/.RData' __ignored__
Oops, turns out I get the same message, I just overlooked it.
However, for me R
Hi,
sd_all_clusterX-sd_all[(as.character(clusterX)%in%as.character(sd_all$X)),]
again selects everything from sd_all, whereas
sd_all_clusterX-sd_all[(as.character(sd_all$X)%in%as.character(ClusterX)),]
results in sd_all_clusterX having 681 entries, what is smaller than the
whole dataset (707
Is this what you want: It turns out that clusterX was a dataframe -
sd_all[sd_all$X %in% clusterX$X,]
X mydata.mean.a mydata.mean.x mydata.sd.a mydata.sd.x
mydata.log2.mean.a mydata.log2.mean.x
3 VS_0225 2.00 1.330.170.14
-0.01 -0.59
6
Hi,
I would like to save many trees created in a loop as
different ones. I can plot them, but I can not get the
whole tree properties saved. I paste the script below
Also, How can I perform multivariate trees?, that is
predicting a vector o values, not a simple scalar
observation.
Thanks in
On 5/20/2008 6:52 AM, Torsten Wiebke wrote:
Hallo,
does nobody have an answer?
I changed something in the package climatol especially in the
function diagwl. Dos anybody know where I can put the code in the
Internet to discuss it?
I put it to: http://de.pastebin.ca/1023676
It would be kind if
Hello folks
I am attempting to install R on a series of Apple G5 machines which are
running Yellow Dog Linux 6.0. Has anyone had success with this, and is
there something I should be doing which I am not?
Upon configure, I receive the error message:
checking whether mixed C/Fortran code can
Duncan Murdoch wrote:
On 5/20/2008 6:52 AM, Torsten Wiebke wrote:
Hallo,
does nobody have an answer?
I changed something in the package climatol especially in the
function diagwl. Dos anybody know where I can put the code in the
Internet to discuss it?
I put it to:
Hello all,
I need to tap into the collective wisdom of the group re an issue of
efficiency.
A sketch of the situation:
Let's say 4000 observations in variables Y, X1, X2 , X3 and X4.
I would like to feed various combinations of this expression
Y ~ X1+X2+X3+X4 +
Hi
Dataframefdf contains
bin rate overlay
1 1 90 Assign First/cc _from_SN_53 RNC_20_to_SN_50 RNC_21_Success
Rate
2 2 93 Assign First/cc _from_SN_53 RNC_20_to_SN_50 RNC_21_Success
Rate
3 1 90 Assign First/cc
Angel Marley angel_nauti at yahoo.com writes:
I would like to save many trees created in a loop as
different ones. I can plot them, but I can not get the
whole tree properties saved. I paste the script below
for (i in 1:7){#loop para hacer arb
arb=arb[i]#contador
Thanks to Martin Maechler, there is a new special interest group (SIG)
mailing list for users of R on Fedora: http://www.fedoraproject.org
Fedora users will have noticed that RPMs for R 2.7.0 have not yet
arrived through the Fedora Yum channel. This is because Fedora 9 went
into feature freeze,
Hello
Thanks for your attempted help.
I have just worked out how to do it. You take the code for panel.bpplot and
near the top of the code replace lline with lpolygon. Then it take the $fill
paramiter from the trellis settings. Seems to work, though I need to check
it isn't doing something
I would like to know some basic properties,
such as its domain, its range, if it is increasing, of the function
defined. I was wondering if R provides functionalities to show this
information. If not, any ideas on writing such functions.
Thanks.
-james
Hi All,
I am facing a strange problem. I am making a R Package that internally run
various packages and summarizes the results from them.
I am getting this error from the piece of code written below. The text in
red color is throwing
Error in `[.matrix.coo`(x, rw, cl) : Subscripts out of bound
All,
Very basic question I can't seem to find the answer to:
plot(0:10, 0:10)
The axes intersection is not aligned at (0,0) in the lower left.
How does one force this?
I searched for graphical parameters under par(graphics) but can't seem to
find it.
Thanks!
David
Edward Wijaya wrote:
Hi,
Currently the R script I have is executed with this command:
$ R CMD BATCH mycode.R
And the output is stored in mycode.Rout.
Is there a way I can issue command from shell (like above)
so that the output is printed to STDOUT?
It's troublesome to open the Rout file
On Tue 20 May 2008 at 07:01:58 AM +0100, Prof Brian Ripley wrote:
You asked for R to be built as a static lib, not for the front-end to be
statically linked. It is not the R lib it is dynamically linking to (that
is statically linked by default whether or not you ask for a separate lib),
Pars xaxs, yaxs which take value i: see also 'An Introduction to R.
On Tue, 20 May 2008, David Afshartous wrote:
All,
Very basic question I can't seem to find the answer to:
plot(0:10, 0:10)
The axes intersection is not aligned at (0,0) in the lower left.
How does one force this?
I
You need to read the docs more carefully! xaxs and yaxs are the par values
you want: set them to i .
Cheers,
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of David Afshartous
Sent: Tuesday, May 20, 2008 8:50 AM
On Tue, 20 May 2008, Esmail Bonakdarian wrote:
Edward Wijaya wrote:
Hi,
Currently the R script I have is executed with this command:
$ R CMD BATCH mycode.R
And the output is stored in mycode.Rout.
Is there a way I can issue command from shell (like above)
so that the output is printed to
Mathematicians like to have axes cross at 0, the general rule for statistics is
to have the axes positioned so that they help you understand the data, but
don't interfere with the actual points (or force too much whitespace by being
put to far away from the data), so the default positioning
Agreed. The main reason I wanted the change in alignment was that I had
three curves that were converging to a asymptote, and when I drew the
horizontal asymptote via abline(), it distorted the picture somewhat since
the line from abline() goes all the way to the y-axis.
On 5/20/08 12:21 PM,
Hello,
I am very interested in banking to 45 degrees as defined by William S.
Cleveland in Visualizing Data. I like to do it in R as well as Excel, etc.
With R I have come across the following method:
xyplot(x, y, aspect=xy) (part of lattice package)
which will bank my graph to 45
Prof Brian Ripley wrote:
On Tue, 20 May 2008, Esmail Bonakdarian wrote:
Edward Wijaya wrote:
Hi,
Currently the R script I have is executed with this command:
$ R CMD BATCH mycode.R
And the output is stored in mycode.Rout.
Is there a way I can issue command from shell (like above)
so that
Hi there,
Perhaps:
set.seed(122)
x=1:50
y1=2*x+x^2
y2=x^2
plot(x,y1,ylim=range(y1,y2),type='l',ylab=expression(f(x)),xlab='x',
main='Two superimposed graphs')
points(x,y2,type='l',col=2)
legend(topleft,c(expression(f(x)==2*x+x^2),expression(f(x)==x^2)),lty=1,col=1:2)
Also you could check ?curve
Hello,
I am trying to assign a variable name (x1,x2,x3...) in a loop statement
that is based on a counter (counter is based on the number of hours
within the datafile). The x1,x2 data will later be called for plotting
the data. Below is a clip of the for loop I am using, any suggestions?
Douglas -
To answer your question directly, use perhaps combination of ?assign and
?paste.
In general, you usually do not have to do this sort of thing, but can
use one of the apply family of functions (apply, sapply, lapply, mapply)
to do whatever you want with shorter, cleaner code and
On 5/20/2008 12:58 PM, Applejus wrote:
Hello,
I have an expression a in R that has about 2300 characters and I want to
convert it to a string using toString or as.character. The problem is I am
only getting the first 500 or so characters when I convert it to string. I
tried to use substring in
Thank you very much Jim for you help!!Your help was my need!!
I have create this function to draw a polygon with a circular side
DrawPortion-function(init,finish,length_){
plot(0,xlim=c(-10,10),ylim=c(-10,10),xlab=,ylab=,type=n,axes=TRUE)
I am working on a weekly analysis and would like to look into the
effects of a holiday. As I only get weekly data how can I populate,
automagically, a series of dummy variables that are aligned with my
data.
Snip -
channel1 - odbcConnectExcel(D:/RSTATS/metrics.xls)
sqlTables(channel1)
How do I define the incremental step in a for loop?
for (j in 1:10){
cat(j, \n)
}
In the above example, if I want to increment j by 2 where do I specify that?
Thanks
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
On 5/20/08, Joshua Hertlein [EMAIL PROTECTED] wrote:
Hello,
I am very interested in banking to 45 degrees as defined by William S.
Cleveland
in Visualizing Data. I like to do it in R as well as Excel, etc. With R I
have come
across the following method:
xyplot(x, y, aspect=xy)
On Tue, 20 May 2008, Duncan Murdoch wrote:
On 5/20/2008 12:58 PM, Applejus wrote:
Hello,
I have an expression a in R that has about 2300 characters and I want to
convert it to a string using toString or as.character. The problem is I am
only getting the first 500 or so characters when I
You are doing it in your bit about 1:10, which is shorthand for
generating a sequence 1, 2, 3, ..., 9, 10. Use ?seq to do what you
want.
for(i in seq(1, 10, by = 2))
cat(i, \n)
Best,
Erik
Nair, Murlidharan T wrote:
How do I define the incremental step in a for loop?
for (j in 1:10){
Can someone help me with a misunderstanding I'm having with hist? I
expected, from the example below, that the number of bins would always be 10
and the length of the counts array the same. According to the help section
'breaks' can be a integer indicating the number of bins. From the example
On 5/20/08, John Gant [EMAIL PROTECTED] wrote:
Can someone help me with a misunderstanding I'm having with hist? I
expected, from the example below, that the number of bins would always be 10
and the length of the counts array the same. According to the help section
'breaks' can be a
On 5/20/2008 2:51 PM, John Gant wrote:
Can someone help me with a misunderstanding I'm having with hist? I
expected, from the example below, that the number of bins would always be 10
and the length of the counts array the same. According to the help section
'breaks' can be a integer indicating
If the issue is with abline going all the way to the axis rather than stopping
at 0 (or other value), then you may want to look at the clip function (allow
the default axes, but clip abline to a smaller region), for example:
plot(0:10,0:10)
points(0:10,0:10)
clip(2,8,0,10)
points(0:10,0:10)
I had to do the same thing many times, i usually use a combination of the
functions eval, parse and sprinf, as below:
k - 1
for (i in 1:length(stats$hour)) {
eval(parse(text=sprintf(x%s - dataset[%s,(3:15)], i, k)))
k - k+1
}
what it does is:
eval(parse(text=STRING)) is a way to execute
Take a look at ?assign
Juan Manuel Barreneche wrote:
I had to do the same thing many times, i usually use a combination of the
functions eval, parse and sprinf, as below:
k - 1
for (i in 1:length(stats$hour)) {
eval(parse(text=sprintf(x%s - dataset[%s,(3:15)], i, k)))
k - k+1
}
what it
On May 20, 2008, at 2:34 PM, Deepayan Sarkar wrote:
On 5/20/08, Joshua Hertlein [EMAIL PROTECTED] wrote:
Hello,
I am very interested in banking to 45 degrees as defined by
William S. Cleveland
in Visualizing Data. I like to do it in R as well as Excel,
etc. With R I have come
Hi All:
Can anyone give me a hint about how to find functions
built in in R. based on the articule below it should
be something called DIYhelp but I can't find it.
Thanks
Part of the Kickstarting R package is a little text
searching facility called DIYHelp. The program is
based upon a simple,
Hi the list,
I write a short function to draw lines in 3D, showing then turning.
At some point, I add delais to slow down the rotation.
So two questions:
1) I try to find a library to draw animate lines in 3D but I did not
find. That surprise me since it is very simple to do. Did I forget to
Consider using a 'list' instead of creating a lot of objects that you then
have to manage:
x - lapply(1:length(stats$hour), function(.indx) dataset[.indx, 3:15])
You can then access the data as x[[1]], ...
On Tue, May 20, 2008 at 12:58 PM, Douglas M. Hultstrand
[EMAIL PROTECTED] wrote:
On 21/05/2008, at 8:21 AM, Felipe Carrillo wrote:
Hi All:
Can anyone give me a hint about how to find functions
built in in R. based on the articule below it should
be something called DIYhelp but I can't find it.
Thanks
Part of the Kickstarting R package is a little text
searching facility
Try the 'rgl' package
On Tue, May 20, 2008 at 4:19 PM, [EMAIL PROTECTED] wrote:
Hi the list,
I write a short function to draw lines in 3D, showing then turning.
At some point, I add delais to slow down the rotation.
So two questions:
1) I try to find a library to draw animate lines in
thanks. I am now using R-patched 2008-05-18 r45723 . This is
probably intended, but if not, I wanted to note it briefly: on the pdf
output device, symbol 1 is always black, no matter what color is
selected. symbols 10 and 13 contain black. symbol 19 is the
replacement for symbol 1 that takes
Our June-July 2008 R/S+ course schedule is now available. Please check
out this link for additional information and direct enquiries to Sue
Turner [EMAIL PROTECTED] Phone: 206 686 1578
Can't see your city? Please email us!
www.xlsolutions-corp.com/courselist.htm
(1) R/S System: Advanced
hi all -
I am student researcher in Bioengineeing and I am very new member of this
group as well as a very new user of R.
To my knowledge, rose.diag is a available function in circstat that i can
use to plot circular data.
Ideally I want to plot half-circle since I only have 0-180 deg angles. I
Thank you all for your help, it looks like
www.rseek.org its a good place to look for help.
Hi Felipe,
It's a private message, so I hope you don't mind.
Regarding your question, personally I think that
apropos(what you want here), i.e, apropos(lm) is
very useful. I use www.rseek.org from myy
On 5/20/08, Charilaos Skiadas [EMAIL PROTECTED] wrote:
Here is how I see it. Let me define a visual y-unit as the height of a
unit of data in the y-direction, and similarly for a visual x-unit.
Then the aspect ratio is the quotient of the visual y-unit over the visual
x-unit. So the aspect
On May 20, 2008, at 5:59 PM, Deepayan Sarkar wrote:
On 5/20/08, Charilaos Skiadas [EMAIL PROTECTED] wrote:
Here is how I see it. Let me define a visual y-unit as the
height of a
unit of data in the y-direction, and similarly for a visual x-unit.
Then the aspect ratio is the quotient of
I've also come across banking (), but I don't understand it, nor the
significance of the value it returns. Regardless, it doesn't seem to be the
aspect ratio that I am looking for.
You might also want to have a look at:
@article{heer:2006,
Title = {Multi-scale banking to 45
Hello all. I have 14 variables, named D2_1,
D2_2,...,D2_14 (inherited from a data set). I would
like to create a matrix of correlations, although I
would be content in just learning how to create a
proper do loop. I tried something like this:
(for i in 1:14){cor(D2_[i],D2_[i], use =
Hi Robert,
There are so many way to do what you want to do. A good staring point would
be
http://www.nabble.com/Re%3A-applying-cor.test-to-a-%28m%2C-n%29-matrix---SUMMARY-to17150239.html#a17150239
HTH,
Jorge
On Tue, May 20, 2008 at 6:41 PM, Robert O'Brien
[EMAIL PROTECTED] wrote:
Hello
Could someone help me on the following:
SAS has DUD (Does not Use Derivatives) for nonlinear regression.
Does R has a similar capability?
I am not good at derivatives and may get my derivative wrong before
feeding it to a nonlinear regression procedure.
Any help would be much appreciated.
?nls
(I always knew SAS *is* a DUD, but never that it has a DUD too...)
Bill Venables
CSIRO Laboratories
PO Box 120, Cleveland, 4163
AUSTRALIA
Office Phone (email preferred): +61 7 3826 7251
Fax (if absolutely necessary): +61 7 3826 7304
Mobile: +61 4 8819 4402
Home
Let's not be so hard on SAS. I thought it was marvelous when I
first used it over 30 years ago.
Spencer Graves
[EMAIL PROTECTED] wrote:
?nls
(I always knew SAS *is* a DUD, but never that it has a DUD too...)
Bill Venables
CSIRO Laboratories
PO Box 120, Cleveland, 4163
Hi,
I am plotting time series data, then using abline to draw a horizontal
line through the graph (for mean, etc). I would like to be able to
display the level at which the abline is drawn on either the left
(main)
Y axis or a supplemental right Y axis.
Additionally, I would like to display
Dear all,
How can I compute the log likelihood of a gamma
distributions of a vector.
I tried the following. But it doesn't seem to work:
samples-c(6.1, 2.2, 14.9, 9.9, 24.6, 13.2)
llgm - dgamma(samples, scale=1, shape=2, log = TRUE)
It gives
[1] -4.291711 -1.411543 -12.198639 -7.607465
The scale of log-likelihood depends on the number of your data samples,
you should sum over the log-densities from individual points:
sum(llgm)
Xiaohui
Edward Wijaya 写道:
Dear all,
How can I compute the log likelihood of a gamma
distributions of a vector.
I tried the following. But it
Dear Xiaohui,
Thanks.
The scale of log-likelihood depends on the number of your data samples
Can you explain what do you mean by this?
For example if I have 10 data points. Should I use scale=10 ?
And how about shape parameters. What's the rule to choose its value?
Hope to hear from you
By the scale of log-likelihood, I did not mean the scale parameter of
the gamma density...
Generally, as you get more and more data, the log-likelihood will get
more and more negative. Hence, what I mean by scale is how negative of
the values of loglik.
So the 10 values returned from your dgamma
Hi,
How can I convert the matrices to list.
For example I have this snippet:
samples-mymatrix[1,]
print(samples)
which prints:
V1 V2V3V4V5V6
1 103.9 88.5 242.9 206.6 175.7 164.4
How can I convert the object samples such that it prints:
[1] 103.9 88.5 242.9 206.6 175.7
Hi Mark,
Doesn't seem to work.
x - unclass(samples)
print (x)
It prints this instead
$V1
[1] 103.9
$V2
[1] 88.5
$V3
[1] 242.9
$V4
[1] 206.6
$V5
[1] 175.7
$V6
[1] 164.4
attr(,row.names)
[1] 1
And it gives the same error for dgamma function.
- Edward
On Wed, May 21, 2008 at 11:22 AM,
Edward
Are you sure mymatrix is, in fact, a matrix and note a dataframe (which
is a list)? I get:
is.matrix(mymatrix)
[1] FALSE
is.data.frame(mymatrix)
[1] TRUE
samples - mymatrix[1,]
llgm - dgamma(samples, scale=1, shape=2, log = TRUE)
Error in dgamma(x, shape, scale, log) :
Non-numeric
Hi Peter,
Thanks.
as.matrix() does the trick.
- Edward
On Wed, May 21, 2008 at 11:31 AM, Peter Alspach
[EMAIL PROTECTED] wrote:
Edward
Are you sure mymatrix is, in fact, a matrix and note a dataframe (which
is a list)? I get:
is.matrix(mymatrix)
[1] FALSE
is.data.frame(mymatrix)
[1]
Hi,
I am trying to model a dataset with the response variable Y, which has
6 levels { Great, Greater, Greatest, Weak, Weaker, Weakest}, and
predictor variables X, with continuous and factor variables using
random forests in R. The variable Y acts like an ordinal variable, but
I recoded it as
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