Hi Mark,
As I said in earlier emails, you do NOT need to explicitly code the
likelihood function for gamma distn. I just code you example as below:
vsamples- c(14.7, 18.8, 14, 15.9, 9.7, 12.8)
gamma.nll - function(par,data)
-sum(dgamma(data,shape=par[1],scale=par[2],log=T))
On 5/23/08, Alexandra Almeida [EMAIL PROTECTED] wrote:
I'm a ubunto user and I used to write my scipts in Java Gui for R, but it
is a very slow tool to run my scripts...
Do you know some efficient IDE for R?
There is the brand-new cross-platform SciViews OpenKore [1], successor
of
R.version gives the following output
R.version
_
platform x86_64-unknown-linux-gnu
arch x86_64
os linux-gnu
system x86_64, linux-gnu
status
major 2
minor 6.0
year 2007
month 10
day03
svn rev
Dear R,
Can anybody help me on how to combine all the elements in a list into a
single vector?? I've tried using unlist command but it gave me wrong output.
Below is the example of the vector output that i want and attach with is my
list of data. Any suggestion?? Many Thanks
Nope, it does not :( See below
Error in .Fortran(merge_xtabs_patterns_file, ydim[1], ydim[2], x =
as.integer(as.matrix(y)), :
Fortran symbol name merge_xtabs_patterns_file not in load table
On Sat, May 24, 2008 at 3:41 AM, Martin Maechler [EMAIL PROTECTED]
wrote:
witn == what's in the
Hello,
I want to perform an lme on a database with this structure:
ID Sequence Temperature TumourError
15 0 1 8.721872e-08
15 0 2 8.695348e-08
15 0
That's because you have not specified the random effect. I think you want
lme(Error ~ Sequence + Temperature + Tumour, random = ~1|ID, data =
YourDataset)
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur-
Hi R,
I have a 100th order equation for which I need to solve the value for x. Is
there a package to do this?
For example my equation is:
(x^100 )- (2*x^99) +(10*x^50)+.. +(6*x ) = 4000
I have only one unknown value and that is x. How do I solve for this?
BR,
To apply uniroot I don't even know the interval values... Does numerical
methods help me? Or any other method?
Thanks and Regards,
Shubha
-Original Message-
From: Duncan Murdoch [mailto:[EMAIL PROTECTED]
Sent: Saturday, May 24, 2008 5:08 PM
To: Shubha Vishwanath Karanth
Subject: Re:
Shubha Vishwanath Karanth wrote:
To apply uniroot I don't even know the interval values... Does numerical
methods help me? Or any other method?
How about plotting the function? If you write it as f(x) = x^100 - ...
- 6*x - 4000, then clearly f(0) is negative, and large enough x will be
Shubha Vishwanath Karanth wrote:
To apply uniroot I don't even know the interval values... Does numerical
methods help me? Or any other method?
I forgot: we also have polyroot().
Duncan Murdoch
Thanks and Regards,
Shubha
-Original Message-
From: Duncan Murdoch [mailto:[EMAIL
Can you tell me what is wrong with the output. Given the values in the
list, the 'unlist' appears to have created the correct values. Now when I
do it, it does print out the vector in this format:
unlist(x)
[1] 6978022 10249966 10955201 11045352 11814604 13847633 16022770
23625856
See ?polyroot.
However, the numerical stability for such a high-order problem is almost
certainly a serious issue.
On Sat, 24 May 2008, Shubha Vishwanath Karanth wrote:
To apply uniroot I don't even know the interval values... Does numerical
methods help me? Or any other method?
Thanks
Shubha Vishwanath Karanth wrote:
To apply uniroot I don't even know the interval values... Does numerical
methods help me? Or any other method?
Thanks and Regards,
Shubha
-Original Message-
From: Duncan Murdoch [mailto:[EMAIL PROTECTED]
Sent: Saturday, May 24, 2008 5:08 PM
To:
We don't support Windows 2000, so you will have to produce your own
workaround. But the relevant code is
PATH - Sys.getenv(PATH)
Sys.setenv(PATH = paste(gsub(/, , DLLpath), PATH, sep=;))
on.exit(Sys.setenv(PATH = PATH))
so I think the issue is that you did *not*
Thanks Xiaohui. I saw your solution a few days ago but only now realize what
you're doing. It didn't at the time make sense to me to use the density from R
directly. Now, I get it.
The solution you get also make sense because the par[2] is ~ 1/par[1] which is
what the analytical MLEs imply.
Was also wondering which theoretical method is used to solve this problem?
Thanks,
Shubha Karanth | Amba Research
Ph +91 80 3980 8031 | Mob +91 94 4886 4510
Bangalore * Colombo * London * New York * San José * Singapore *
www.ambaresearch.com
-Original Message-
From: Gabor Grothendieck
Thank you all, I think I have a good list of options now.
The best suited to my personal taste seems to be the Brew package,
which I completely overlooked until I looked at the source examples.
If I can persuade my text editor (textmate) to recognize the markup
and also execute the R
Paulo Cardoso pecardoso at netcabo.pt writes:
Can we by any change perform in R something similar geoprocessing or, more
advanced, Spatial SQL over vectorial data?
Please visit the Spatial task view on your nearest CRAN mirror, which gives some
details of useful resources. Consider using the
Afshartous, David wrote:
All,
The first use of expression produces a double subscript while the second does not.
I searched in ?plotmath and the archives and didn't find anything. I'm sure
I'm missing
something obvious but can't seem to find. any suggestions much appreciated.
Cheers,
At 07:58 AM 5/24/2008, Duncan Murdoch wrote:
Shubha Vishwanath Karanth wrote:
To apply uniroot I don't even know the interval values... Does
numerical methods help me? Or any other method?
I forgot: we also have polyroot().
Duncan Murdoch
Thanks and Regards,
Shubha
-Original
Consider the following:
library(polynomial)
p100 - polynomial(1:101)
s100 - solve(p100)
p100r - 101*poly.calc(s100, tol=.Machine$double.eps)
max(abs(coef(p100r)-(1:101)))
550767713
For order 2, it worked perfectly:
(p2 - polynomial(1:3))
(s2 - solve(p2))
(p2r - 3*poly.calc(s2))
Robert A LaBudde wrote:
At 07:58 AM 5/24/2008, Duncan Murdoch wrote:
Shubha Vishwanath Karanth wrote:
To apply uniroot I don't even know the interval values... Does
numerical methods help me? Or any other method?
I forgot: we also have polyroot().
Duncan Murdoch
Thanks and Regards,
Hi,
Antony Unwin wrote:
R has spread far and wide with great success. It is not only used
extensively in universities, but also apparently in governmental
organisations and in industry. As the recent discussion of R's Pros
and Cons shows, there are many reasons for this. It would be
Don't use replicate() like this. You have '...' in your *expression*, and
it really should only be used in the body of a function.
But if you want to understand why
debug(rexp)
rdistr - function(distr, ...) replicate(1, distr(n = 1, ...))
rdistr(rexp)
debugging in: distr(n = 1, ...)
debug:
From: Jason Lee [EMAIL PROTECTED]
Date: May 23, 2008 10:06:18 AM EDT
To: r-help@r-project.org
Subject: [R] Fwd: Advise in R- plotting graphs
Hi
I tried and it is not what im looking ..
I basically issue plot(data$V1,data$V2) as the matrix have the two
headers..But essentially what I
I think one significant problem is the lack of 3D graphics support with
interactivity as per MATLAB ( I here Xgobi offers something hear but I
couldn't comment having not used it)
On the GUI issue, I'm split - once you get used to R then it's great just to
use the command line - but as a
Hi,
I'm wanting to call R from Perl via the RSPerl package. However I cannot
seem to install it on my Macbook (OS X Tiger - R 2.6 - Perl 5.8.6). I try to
install the source downloaded from the sigmahat website - but it seems to
fail - when I search my system for R.pm - I can't find it? Something
Renato,
As you may know the two routines for fitting GARCH models are garchFit
[fGarch] and garch [tseries]. The RMetrics [who are behind the fGarch
library] team have usefully provided a white paper on Garch modeling
available from their website, which includes a simple example of how to fit
a
Dear R-users,
I have a data which is in an interval length of start-end. How am i going to
perform a uniform distribution? and how to test if it is the uniform
distribution?? Suggestion is needed. Many thanks!!
start end
132955984 132980744
135891280 135998880
156158176
I'm one of the many who is far more interested in the reason for the
request than in the numerical method to use. The way I see it, the
methodology of, say, polyroot() suffices in a mathematical sense. If
your coefficients are mathematically exact (as opposed to measured
values), the
1. Most of the neighbors of a low cost state, x, may have much higher costs;
and
2. The problem is highly degenerate in the sense that there are states, x,
with a large
(sub) neighborhood of equal cost states, S(x) = fy inside N(x) and f(y) =
f(x). In this
case, even rejecting all the proposals
Hello everybody.
Recently I update from R6.3 to R7.0 on Mac OS X, and an ugly gray
grid appear when I use the function image() or pdf()
What I am doing wrong?
Thank's for your help,
Ángel.
__
R-help@r-project.org mailing list
Dear Friends,
I want to know if any one could give me help on this.
Suppose you want to simulate the p-value of a test statistic
but you do not know how the distribution of the test
statistic, how can one simulate the p-value.
It will be helpful to get an example code in R on this
Jason Lee-14 wrote:
I want to plot V1 against V2 with the condition that I
want to mark(color) the point(row 5) on the graph. This is so i could see
some triangle shape thing on the graph for row 5.
You could try something crude like
plot(V1,V2, col=ifelse( (1:length(V1)) == 5,
On Thu, 22 May 2008, francogrex wrote:
Hi, this is probably quite simple but I can't seem to do it
correctly. I
have
a data frame of counts of infections in different ages; something
like:
count=c(1, 1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 7, 8, 8, 9, 9,
10, 11, 15, 17, 17, 17, 17, 19,
library(PolynomF)
x - polynom()
p - x^100 - 2*x^99 + 10*x^50 + 6*x - 4000
z - solve(p)
z
[1] -1.0741267+0.000i -1.073-0.0680356i -1.073+0.0680356i
-1.0655699-0.1354644i
[5] -1.0655699+0.1354644i -1.0568677-0.2030274i -1.0568677+0.2030274i
-1.0400346-0.2687815i
...
[93]
Oops! Actually spectacularly bad. I didn't see the positive exponent!
Curiously, there appears to be just one bad apple:
sort(Mod(p(z)))
[1] 1.062855e-10 1.062855e-10 1.328999e-10 1.328999e-10 2.579625e-10
[6] 2.579625e-10 3.834721e-10 3.834721e-10 3.875288e-10 3.875288e-10
[11]
hi: you simulate the distribution of the test statistic by simulating
the hypothesis test over and over and calculating the test statistic
each time.
the details of how you simulate the hypothesis test depends on the
particular problem you are dealing with but you didn't describe that.
if you
[EMAIL PROTECTED] wrote:
Dear Friends,
I want to know if any one could give me help on this.
Suppose you want to simulate the p-value of a test statistic
but you do not know how the distribution of the test
statistic, how can one simulate the p-value.
It will be helpful to get an example
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