I can't speak to the intricacies of the formula but when I run the
ByDataFrame() function provided on a subsample of my data (n=50) it returned
only the very first id value in the output; the rest came out as NA
This is not to say it has not properly selected the rows with min(x$diff),
but I
Stephan Kolassa Stephan.Kolassa at gmx.de writes:
I would like to loop over a medium amount of Sweave code, including both R
and LaTeX chunks. Is there any way to
Stephan noted that \newcommand was not expanded, so after re-reading I
realized that my comment was a bit short. After all, when
Hi all,
I am looking for a book from which one could learn a wide range of
graphics in R, from the very beginning topics to those advanced
(though not necessarily concerned with a particular method or topic).
I don't look for a list of such books since this is on R's web page, I
am rather
Hi.
I was trying to calculate 2. order moment for a loggamma sample.
Also, I checked it with the function mlgamma from the package actuar, which
calculates moments based on loggamma parameters.
Se below - I get big deviations. Numerical integration suggests that mlgamma
gets it right. What fails
[EMAIL PROTECTED] wrote:
...
I have a problem with freq from prettyR.
Please have a look at my syntax with a litte example:
library(prettyR)
#Version 1
test.df-data.frame(q1=sample(1:4,8,TRUE), gender=sample(c(f,m),8,TRUE))
test.df
freq(test.df) #No error message
#Version 2
Thank you Jim,
the error message appeared, as I tried to run an example from the wonderful
script R for SAS and SPSS Users written by Bob Muenchen (p. 76):
http://oit.utk.edu/scc/RforSASSPSSusers.pdf
This is the code on page 76:
# Frequencies percents using the freq function
# from the
I have followed the instructions on how to build a Windows package and
everything seems to work EXCEPT that I can't see the data files that I have
loaded into the data directory. I have placed the appropriate data in the
data directory (as in the instructions). There are 3 data sets, which I can
Dear Gillian,
Unless you add the directive
LazyData: yes
to the package DESCRIPTION file, you'll need to use the data() command to
access the data in the package -- e.g., data(Mowatt).
I hope this helps,
John
--
John Fox, Professor
Department of Sociology
On Jun 14, 2008, at 2:59 AM, T.D.Rudolph wrote:
I can't speak to the intricacies of the formula but when I run the
ByDataFrame() function provided on a subsample of my data (n=50) it
returned
only the very first id value in the output; the rest came out as
NA
This is not to say it has
See the following link:
http://www.amazon.com/Graphics-Computer-Science-Data-Analysis/dp/158488486X/ref=wl_itt_dp?ie=UTF8coliid=I3TIYS7LRDPIEDcolid=1ZQCB91VGW5UR
Regards,
R.L.
Marcin Kozak wrote:
Hi all,
I am looking for a book from which one could learn a wide range of
graphics in R,
On Sat, Jun 14, 2008 at 12:55 AM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
Try this:
library(gsubfn)
x - A: 123 B: 456 C: 678
strapply(x, [^ :]+[ :]|[^ :]+$)
[[1]]
[1] A: 123 B: 456 C: 678
and check out the gsubfn home page at:
http://gsubfn.googlecode.com
Thanks Gabor!
hadley wickham [EMAIL PROTECTED] writes:
n
On Sat, Jun 14, 2008 at 12:55 AM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
Try this:
library(gsubfn)
x - A: 123 B: 456 C: 678
strapply(x, [^ :]+[ :]|[^ :]+$)
[[1]]
[1] A: 123 B: 456 C: 678
Also
strsplit(x, (?=[0-9:] ), perl=TRUE)
For my R page at http://finzi.psych.upenn.edu/ (also the target of
RSiteSearch()), I'm trying to find a way to get the html versions of
the help pages without actually installing packages. This will allow
me to include packages that don't install. And it will also vastly
speed up the monthly
On Sat, Jun 14, 2008 at 10:20 AM, Martin Morgan [EMAIL PROTECTED] wrote:
hadley wickham [EMAIL PROTECTED] writes:
n
On Sat, Jun 14, 2008 at 12:55 AM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
Try this:
library(gsubfn)
x - A: 123 B: 456 C: 678
strapply(x, [^ :]+[ :]|[^ :]+$)
[[1]]
[1]
Thank you very much for your answer.
I tried to run the function on my data and now I am getting this message of
error
Error in as.dist(dmat[clustering == i, clustering == i]) : (subscript)
logical subscript too long
Below the code I am using (version2.7.0 of R with all packages updated):
data
This is a common problem, for which solutions are poorly documented.
1. Have you tried fitting simpler models, in the hopes of
getting something that converges without complaint, then use 'update' to
try more complicated models? It sometimes works, though often not.
The first three chapters of Paul Murrell (2006) R Graphics
(Chapman Hall), which Marcin cited, provides a very detailed and
useful overview of traditional graphics in R. The rest of the book is
devoted to 'lattice' and 'grid' graphics; unfortunately, I have so far
not been able to
On Sat, Jun 14, 2008 at 11:46 AM, hadley wickham [EMAIL PROTECTED] wrote:
On Sat, Jun 14, 2008 at 10:20 AM, Martin Morgan [EMAIL PROTECTED] wrote:
hadley wickham [EMAIL PROTECTED] writes:
n
On Sat, Jun 14, 2008 at 12:55 AM, Gabor Grothendieck
[EMAIL PROTECTED] wrote:
Try this:
The given information is not enough to tell you what's going on. as.dist
doesn't appear in the given code and it's not clear to me what kind of
object img is (a small image doesn't tell me what R makes of it).
Also, try to read the help pages first and find out whether img is of the
format that
I am sorry I did not provide enough information.
I am not using img later, but data that is data.frame.
I wrote that img is a image just to explain what kind of data is coming
from, but the object I am using is data and it is a data.frame (checked many
times).
I am not using as.dist, but dist in
Thank. See below.
Laura
2008/6/14 Christian Hennig [EMAIL PROTECTED]:
What does str(ddata) give?
Class 'dist' atomic [1:130816] 69.2 117.1 145.6 179.9 195.6 ...
dcent doesn't make sense as input for cluster.stats, because you need a
dissimilarity matrix between all objects.
Yes I
I have found the problem. I don't understand it, but the script works
now. I've removed it from where it was but will send it to anyone who
wants it.
Jon
On 06/14/08 11:44, Jonathan Baron wrote:
For my R page at http://finzi.psych.upenn.edu/ (also the target of
RSiteSearch()), I'm trying to
Dear Laura,
I have R 2.6.0. I tried dist on a vector of length 200,000 and it told me
that it is too long. Theoretically, if you have 260,000 observations, the
length of the dist object should be 260,000*259,999/2, which is too large
for our computers, I guess. Which means that unfortunately
Thank you very much for all the info and support.
Now I managed to make it working on a small subset of the original data set.
I think that the first error message I got (Error in as.dist(dmat[clustering ==
i, clustering == i]) : (subscript) logical subscript too long)
is generated when the 2
These are great tips from Spencer.
The other thing that I have found useful is to use a different
optimizing algorithm. You can do this by:
control=lmeControl(opt = optim)
Good luck!
Andrew
On Sat, Jun 14, 2008 at 09:45:22AM -0700, Spencer Graves wrote:
This is a common problem, for
Here is an approach that should work:
x - data.frame(a=1:10, b=1:10, c=1:10)
# use sprintf to make consistent numbers
myNames - sprintf(%.2f, seq(from=-179, to=179, length=3))
colnames(x) - myNames
x
-179.00 0.00 179.00
111 1
222 2
333 3
Hi,
my data set is data.frame(id, yr, y, l, e, k).
I would like to estimate Lee and Schmidts (1993, OUP) model in R.
My colleague wrote SAS code as follows:
** procedures for creating dummy variables are omitted **
** di# and dt# are dummy variables for industry and time **
data a2; merge a1
Hello,
I'm trying to plot an exponential regression line through my data
(scatterplot with trend line), but can't find a way to do that. it is to be
the best fit possible.
--
View this message in context:
http://www.nabble.com/plotting-regression-line-tp17837683p17837683.html
Sent from the R
CV == Cristiano Varin [EMAIL PROTECTED]
on Fri, 13 Jun 2008 11:31:34 +0200 writes:
CV Dear R users, I am mailing you about the graphical
CV output of silhouette (cluster package)
CV From the example of silhouette in help(silhouette):
ar - agnes(ruspini)
si3 -
I use R 2.7.0 on GNU/Linux. I have noticed a problem in cbind method
for multivariate time series (ts) objects. Consider the following
example:
t - ts(data.frame(a = 10:20, b = 20:30, c = 30:40, d = 40:50))
t1 - t[, c('a', 'b')]
t2 - t[, c('c', 'd')]
colnames(t1)
[1] a b
colnames(t2)
[1] c
help(qt) states that:
ncpnon-centrality parameter delta; currently except for rt(), only for
abs(ncp) = 37.62
so I would expect that calling qt with non-centrality parameter exceeding
37.62 should fail, instead e.g. calling
mapply(function(x) qt(p = 0.9, df = 55, ncp = x),35:45)
gives:
Hello! I have a matrix:
dim(data1)
[1] 34176 581
of 34176 rows and 581 columns,
I want to make a new matrix data2 by taking the 2nd column, 9th column, 16th
column
the column number is in the order of:
2
9 (2+7)
16 (9+7)
23 (16+7)
...
the new matrix data2 should include 83 columns, is
newdata1 - data1[, seq(from=2, to=ncol(data1), by=7)]
On Sat, Jun 14, 2008 at 7:27 PM, ss [EMAIL PROTECTED] wrote:
Hello! I have a matrix:
dim(data1)
[1] 34176 581
of 34176 rows and 581 columns,
I want to make a new matrix data2 by taking the 2nd column, 9th column, 16th
column
Is this what you want:
t - ts(data.frame(a = 10:20, b = 20:30, c = 30:40, d = 40:50))
t1 - t[, c('a', 'b')]
t2 - t[, c('c', 'd')]
colnames(t1)
[1] a b
colnames(t2)
[1] c d
x - cbind(t1, t2)
colnames(x)
[1] t1.a t1.b t2.c t2.d
colnames(x) - sub(^.*\\., , colnames(x))
x
Time Series:
Thank you very much, Jim! Have a good evening!
Allen
On Sat, Jun 14, 2008 at 7:35 PM, jim holtman [EMAIL PROTECTED] wrote:
newdata1 - data1[, seq(from=2, to=ncol(data1), by=7)]
On Sat, Jun 14, 2008 at 7:27 PM, ss [EMAIL PROTECTED] wrote:
Hello! I have a matrix:
dim(data1)
[1] 34176
Linda,
Been working on that:
http://msenux.redwoods.edu/mathdept/R/TransformingData.php
Along with some other activities:
http://msenux.redwoods.edu/mathdept/R/index.php
David Arnold
http://online.redwoods.edu/instruct/darnold
On Jun 14, 2008, at 2:51 AM, **linda** wrote:
Hello,
I'm
Dear Michael,
The SLLN hasn't failed. :-)In this particular example, it looks
like the sample means are simply converging at a rate which is slower
than desired.
Unfortunately, your particular loggamma doesn't have a finite fourth
moment; so you don't have the usual (worst case) convergence
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