Hi
[EMAIL PROTECTED] napsal dne 17.09.2008 11:08:29:
Greetings everyone,
I'm trying to add a specific table or a specific number of rows (e.g.44)
to a
table with no success.
This is my basic table
head(dataA)
yearplot spp prop.BDCA1DCA2DCA3DCA4
1
Hi Hadley,
As for now, I have not yet delved deep enough into the new version to be
sure if I like it or not. It's just that I like the freedom to choose, and
the previous form was great. Any chance you may put it back as an optional
parameter?
Thanks,
Pedro
hadley wrote:
On Wed, Sep 17, 2008
The group would be happy to answer your question if you can show an example
data frame on what is there and what is required.
Â
Cheers,
Pratap
--- On Wed, 17/9/08, Rajasekaramya [EMAIL PROTECTED] wrote:
From: Rajasekaramya [EMAIL PROTECTED]
Subject: [R] inserting values for null
To:
Adaikalavan Ramasamy wrote:
...
Anyway, here is how to do what you want:
1) Install bash on your Windows machine - You can use cgywin. Or
download and unzip http://www.steve.org.uk/Software/bash/
2) Make the directory to bash.exe and R.exe are in your PATH variable.
3) Start - Run - cmd
4)
Hi Sonia,
If I did not make a mistake, the conditional distribution of X given that X 0
is very close to exponential distribution with parameter lambda = 40, so you
can sample from this distribution.
--- On Mon, 15/9/08, Daniel Davis [EMAIL PROTECTED] wrote:
From: Daniel Davis [EMAIL
Hi,
Quite simple question I guess.
Where could we specify the size of the text (axis,legend) for a scatter plot
graphic made with plot()?
Regards/Cordialement
-
Benoit Boulinguiez
Ph.D
Ecole de Chimie de Rennes (ENSCR) Bureau 1.20
Equipe CIP UMR CNRS 6226 Sciences Chimiques de
Generally speaking, this is controlled by the argument cex (or
cex.axis, cex.lab, ...). See ?par (and ?plot, ?text, ?axis,
?legend, ?text, ...)
Regards,
Yihui
--
Yihui Xie [EMAIL PROTECTED]
Phone: +86-(0)10-82509086 Fax: +86-(0)10-82509086
Mobile: +86-15810805877
Homepage: http://www.yihui.name
Could anyone kindly let me know what tool(s) in R are available/convenient
for Fisher linear discriminant analysis? I only need to handle the two class
tasks for now.
Thank you,
Yiping
--
View this message in context:
Use lda in MASS package
Justin BEM
BP 1917 Yaoundé
Tél (237) 99597295
(237) 22040246
- Message d'origine
De : Yip [EMAIL PROTECTED]
à : r-help@r-project.org
Envoyé le : Jeudi, 18 Septembre 2008, 8h04mn 23s
Objet : [R] Tool for simple two class Fisher linear discriminant analysis?
Dear R-help!
I need to draw contour lines in a plot of wave heights (Hs) versus peak
periods (Tp) showing the joint probabilities of 1-year wave heights~peak
periods, 10-year wave heights~peak periods and 100-year wave heights~peak
periods.
I've used the contourplot() function in the plot I've
Dear all,
Is there a way with Bioconductor in which I can
convert such EnSemBL probe names into the
standard gene names?
AFFX-M27830_5_at
AFFX-M27830_M_at
ENSG003_at
ENSG005_at
ENSG419_at
- Gundala Viswanath
Jakarta - Indonesia
Hi,
I'm not being able to capture a position of a 'string' in a character
string.
In this example: 'There are 20 species in this grid'
I would like to capture the string (number) after 'are' and before
'species'. Consider they do not change. I wouldn't like to use substr
because stop position
If it always occurs after 'are', this will work:
x - 'There are 20 species in this grid'
y - sub(.*are (\\d+).*, \\1, x, perl=TRUE)
y
[1] 20
On Thu, Sep 18, 2008 at 4:51 AM, Paulo Cardoso [EMAIL PROTECTED] wrote:
Hi,
I'm not being able to capture a position of a 'string' in a character
you could use gsub(), e.g.,
strg - There are 20 species in this grid
gsub([^0-9], , strg)
I hope it helps.
Best,
Dimitris
Paulo Cardoso wrote:
Hi,
I'm not being able to capture a position of a 'string' in a character
string.
In this example: 'There are 20 species in this grid'
I would
Hi,
Can we get the code for calculating Oja median for multivariate data
Thanks and Regards
Rahul Agarwal
Analyst
Equities Quantitative Research
UBS_ISC, Hyderabad
On Net: 19 533 6363
[[alternative HTML version deleted]]
__
Can we get the code for calculating Oja median for multivariate data
RSiteSearch(oja median) returns a link to this R-help post with code
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/12781.html
Regards,
Richie.
Mathematical Sciences Unit
HSL
Dear R-users,
I would like to write Greek letters followed by subscripts in a graph (on the
X-axis and in a legend). I would appreciate any help.
thank you,
delphine courvoisier
Delphine Courvoisier
Clinical Epidemiology Division
University of Geneva
Dear R users,
I 'm having problems with creating PNG graphic outputs.
Usualy i create reports in HTML format, containing PNG graphics, so they
can ealsaly be exported to word and xl and so on.
On a windows pc that i use at work all works fine, but it never works on
my mac.
The HTML's i create
Hi Richard,
Thanks for the code.but I already have a code for bivariate data...I
want it for data when it is multivariate or its dimension is greater
than two...i mean to say if it is trivariate or higher dimensioncan
I get a more generalised form of oja median code
Thanks and Regards
I would like to write Greek letters followed by subscripts in a
graph (on the X-axis and in a legend). I would appreciate any help.
See FAQ 7.13 and ?plotmath for examples.
Regards,
Richie.
Mathematical Sciences Unit
HSL
Hi,
I just want to make sure that I really misunderstood the documentation: Is
HTMLStart redirecting plots as well so that they are included in the HTML
report? I tried the below and the plot is not included in the HTML file.
Or did I miss some switch or so?
Many thanks,
Werner
Thanks for your help,
I didn't know where you can or can't use a for variable.
Seems that I have to use rownames to do this anyway, so finally I went for a
more procedural solution:
v=1:6
for (a in 1:3){
for (b in 4:5) {
v-rbind(v,1+a+b:6+a+b)
rownames(v)[nrow(v)]=
Perfect but when one wants to get something different, like
x - 'INPUT FILE record.dat'
sub(.*FILE (\\w+).*, \\1, x, perl=TRUE)
will return 'record' and not 'record.dat'
the [:punct:] is not retained.
Paulo
-Original Message-
From: jim holtman [mailto:[EMAIL PROTECTED]
Sent:
Try:
sub(.*FILE (\\w+)|\\.*, \\1, x, perl=TRUE)
On Thu, Sep 18, 2008 at 7:39 AM, Paulo Cardoso [EMAIL PROTECTED] wrote:
Perfect but when one wants to get something different, like
x - 'INPUT FILE record.dat'
sub(.*FILE (\\w+).*, \\1, x, perl=TRUE)
will return 'record' and not 'record.dat'
Try this:
m - matrix(rep(1:3, 3), 3, dimnames = list(letters[1:3], letters[1:3]))
as.data.frame.table(t(m))
On Wed, Sep 17, 2008 at 10:52 PM, Pinder, Adrian
[EMAIL PROTECTED] wrote:
Hi, can someone please tell me how to convert a square matrix to a list in R?
i.e. I want to convert from:
jgasper Jason.Gasper at noaa.gov writes:
I have been using the nb2WB() package for the car.normal function in WinBUGS,
but it will not create the C[] matrix; it only creates adj[], num[], and
weights[]. I was planning on using this function to create the C[] matrix
(by using the num
Yihui Xie wrote:
Thanks Duncan, I have also been wondering about this problem for a long time.
If you suspect a bug in a package, it's good to contact the package
maintainer. Often (as in this case) they are unaware of the bug and
appreciate the report.
Duncan Murdoch
Regards,
Yihui
Dear all,
I've finally got round to plotting my data and trying to apply colour (had some
problems with the data which I needed to rectify first!). I'm having trouble
however getting the colour to work as I'd hoped, despite the help offered in
previous messages.
Just to recap, and with more
Dear all,
I'm working on ability estimates using Rasch model. Using the ltm
package, the procedure is quite simple:
## Factor Scores for the Rasch model
fit - rasch(LSAT)
factor.scores(fit)
What about Partial Credit Model (PCM)? For PCM I use PCM function from
eRm package. Is there any
[EMAIL PROTECTED]
on Thu, 18 Sep 2008 05:20:56 -0400 writes:
Hi,
Can we get the code for calculating Oja median for
multivariate data
Excuse me, but must you really?
The Oja median has (finite) breakdown point 2/n, i.e., is not
robust in any reasonable sense, and is
Josip Dasovic wrote:
Hi:
I've searched the archives and the Internet for hours but have yet to find a
way to do stacked area plots (like the kind in Excel) in R. I think that
polygon may work but it would require a bit of manipulation of my data. I was
hoping for an easier way.
An example
Thank you all. Works fine.
-Original Message-
From: Henrique Dallazuanna [mailto:[EMAIL PROTECTED]
Sent: quinta-feira, 18 de Setembro de 2008 12:14
To: Paulo Cardoso
Cc: jim holtman; r
Subject: Re: [R] character position
Try:
sub(.*FILE (\\w+)|\\.*, \\1, x, perl=TRUE)
On
At 16:03 17/09/2008, Javier Acuña wrote:
Hi, I'm a new user of R. My background is Electrical Engineering, so
please bear with me if this is a silly question.
For future reference you might find
?interaction
helpful as another tool in your box.
I'm trying to assess whether the results of an
Gillian Silver wrote:
Hi, how can I create a rainbow gradient in R? For example, let's say I have
a plot of y = x...and I want the plot to go from red - orange - yellow -
green - blue - etc.
Right now, I know how to do something like go from red to blue, using the
plotrix library:
Loglik converged before variable 1,2 ; beta may be infinite.
I have two (related) questions:
1. Can I in general ignore this kind of warning and just pay attention to
predictors which produce significant p values?
2. In the specific case of stepAIC, can I ignore this warning and trust
Steve,
Have a look at the ggplot2 package:
library(ggplot2)
ggplot(Jan, aes(x = PopDensity, y = Average.Burnt.Area.Fraction, colour
= factor(Urban.Rural 1.25))) + geom_point()
ir. Thierry Onkelinx
Instituut voor
As for now, I have not yet delved deep enough into the new version to be
sure if I like it or not. It's just that I like the freedom to choose, and
the previous form was great. Any chance you may put it back as an optional
parameter?
I doubt it, but you can override the defaults as follows:
Try this:
library(gsubfn)
strapply(There are 23 species, [0-9]+, as.numeric)[[1]]
The gsubfn home pae is at:
http://gsubfn.googlecode.com
On Thu, Sep 18, 2008 at 4:51 AM, Paulo Cardoso [EMAIL PROTECTED] wrote:
Hi,
I'm not being able to capture a position of a 'string' in a character
We are using R in our class. One student claims to
be receiving the message
Fatal error: unable to restore saved data in .RData
The student is working in a Windows environment with Vista
using the precompiled binary distribution (R-2.7.2).
After searching the R site and reading FAQs, I
On 18/09/2008 9:41 AM, Green, Paul wrote:
We are using R in our class. One student claims to
be receiving the message
Fatal error: unable to restore saved data in .RData
The student is working in a Windows environment with Vista
using the precompiled binary distribution (R-2.7.2).
After
On 9/18/08, David Scott [EMAIL PROTECTED] wrote:
I have a data set concerning ferritin levels in blood. There are three
relevant columns for this question, ferritin (continuous), score (ordered,
from 0 to 8) and gender. There is a good linear relationship between
log(ferritin) and score for
On Thu, 18 Sep 2008, Deepayan Sarkar wrote:
On 9/18/08, David Scott [EMAIL PROTECTED] wrote:
I have a data set concerning ferritin levels in blood. There are three
relevant columns for this question, ferritin (continuous), score (ordered,
from 0 to 8) and gender. There is a good linear
Jim and all,
Maybe I've misunderstood ?color.scale (appologies if this is so), but I don't
think this is what I need. I'm not looking to scale the colours of points,
instead I simply want to assign each point a colour (either red or green) based
on it's value in the Urban.Rural column.
To
wow, ok, thanks everyone lots for me to explore. I will take some time,
and if none of these achieve what I'm trying to get at I will come back
here. Thanks!
Mike
Adaikalavan Ramasamy wrote:
Well, I don't see why you need the CTRL-R functionality when you can
just as rapidly and
Tom,
First of all, please in the future follow the posting guide and
include a reproducible example. Yours is not, because the objects
named bxpdtrail and ResultDir (and maybe others) are not
available to readers of this list. And you defined a dataframe named
size2 but then used one named
Hello, need some help on using Rcurl to navigate a site and the use of
session cookies. I suspect the issue i am having presently is I am not
handling session cookies properly.
At a high level, in need to create a dataset for some analysis, my
background is in using R for statistical work, I
Hi
[EMAIL PROTECTED] napsal dne 18.09.2008 15:41:07:
We are using R in our class. One student claims to
be receiving the message
Fatal error: unable to restore saved data in .RData
I sometimes get such message when I save .RData with some nonstandard
packages loaded and trying to open R
R-core, may I suggest that the error message returns the absolute path
(or even the relative path) and not just the filename/basename, e.g.
Fatal error: unable to restore saved data in C:/Users/foo/.RData
/Henrik
On Thu, Sep 18, 2008 at 6:41 AM, Green, Paul [EMAIL PROTECTED] wrote:
We are
[Reposting with changed example and font spec removed]
Hi,
I want to take the dataframe df generated below and reshape the data
with column names being w, x, y, and the different levels of z. The
values under the different levels of z are the corresponding values of
r. I've tried reshape and
Dear all,
I was wandering what could be wrong with my system (regularly updated Fedora
core 8) so that installing packages does not succeed with almost every package.
I follow the procedure specified in the help file R-admin section 6.3. This is
not a feature new to the current version but
On Thu, Sep 18, 2008 at 10:03 AM, Matthew Pettis
[EMAIL PROTECTED] wrote:
[Reposting with changed example]
Hi,
I want to take the dataframe df generated below and reshape the data with
column names being w, x, y, and the different levels of z. The values under
the different levels of z are
[Reposting with changed example]
Hi,
I want to take the dataframe df generated below and reshape the data with
column names being w, x, y, and the different levels of z. The values under
the different levels of z are the corresponding values of r. I've tried
reshape and cast, and I can't seem
Hi Miha,
One tip for diagnosing build problems is to ignore all warnings and
look for the first error. In your case it's:
init.c:2:15: error: R.h: No such file or directory
init.c:3:24: error: Rinternals.h: No such file or directory
Which possibly suggests that you don't have the necessary
And does it need to be a fatal error? load(test.txt) doesn't produce
a fatal error even though the file clearly isn't in the correct
format.
Or is there the possibility that loading a malformed rdata file
introduces memory corruption?
On Thu, Sep 18, 2008 at 9:55 AM, Henrik Bengtsson [EMAIL
It does, thanks! Did I miss in the documentation that the variable
has to be named 'value'?
On Thu, Sep 18, 2008 at 10:08 AM, hadley wickham [EMAIL PROTECTED] wrote:
On Thu, Sep 18, 2008 at 10:03 AM, Matthew Pettis
[EMAIL PROTECTED] wrote:
[Reposting with changed example]
Hi,
I want to
Maybe something like:
k - kernel(...)
spectrum(c(rev(k$coef),k$coef))
Since the kernel is symmetric?
Rory Winston
RBS Global Banking Markets
Office: +44 20 7085 4476
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of [EMAIL PROTECTED]
Sent: 17 September
On 18/09/2008 10:55 AM, Henrik Bengtsson wrote:
R-core, may I suggest that the error message returns the absolute path
(or even the relative path) and not just the filename/basename, e.g.
Fatal error: unable to restore saved data in C:/Users/foo/.RData
That's a good suggestion, but
Possibly - in the next version, you'll get a helpful warning message
and cast will take it's best guess at the column that it should use.
Hadley
On Thu, Sep 18, 2008 at 10:15 AM, Matthew Pettis
[EMAIL PROTECTED] wrote:
It does, thanks! Did I miss in the documentation that the variable
has to
If the students have the permission, maybe run R as administrator solves the
question too.
Rodrigo.
--
From: Duncan Murdoch [EMAIL PROTECTED]
Sent: Thursday, September 18, 2008 10:48 AM
To: Green, Paul [EMAIL PROTECTED]
Cc: r-help@r-project.org
Miha Staut wrote:
Dear all,
I was wandering what could be wrong with my system (regularly updated Fedora
core 8) so that installing packages does not succeed with almost every
package. I follow the procedure specified in the help file R-admin section
6.3. This is not a feature new to the
Hi all,
i am looking to built a simple example of a very basic propensity
score adjustment, just using the estimated propensity scores as
inverse probability weights (respectively 1-estimated weights for the
non-treated). As far as i understood, MLE predictions of a logit model
can
Hi
[EMAIL PROTECTED] napsal dne 18.09.2008 15:41:07:
We are using R in our class. One student claims to
be receiving the message
Fatal error: unable to restore saved data in .RData
Well, throw my suggestion away.
I sometimes get such message when I save .RData with some
On 18/09/2008 12:08 AM, Yihui Xie wrote:
Thanks Duncan, I have also been wondering about this problem for a long time.
This is fixed now on R-forge; eventually it will make it into the next
rgl release on CRAN. You should be able to download a binary of the
development version from R-forge
Bunny, lautloscrew.com bunny at lautloscrew.com writes:
ix of some covariates.
I wonder right now if te glm respectively summary(glm(...)) puts out
something comparable to ML estimates that can be used as the estimated
pscores, in such a way that there is one value for every observation.
Bunny, lautloscrew.com wrote:
Hi all,
i am looking to built a simple example of a very basic propensity score
adjustment, just using the estimated propensity scores as inverse
probability weights (respectively 1-estimated weights for the
non-treated). As far as i understood, MLE predictions
Thanks for your help Hadley and Peter.
Your suggestions solved the question of installing new packages. But what can
be done to get rid of the other mentioned problem in html help files. I am
repeating what the problem is. After installation of new packages R-html help
files try to follow
Hi.
On Thu, Sep 18, 2008 at 8:16 AM, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 18/09/2008 10:55 AM, Henrik Bengtsson wrote:
R-core, may I suggest that the error message returns the absolute path
(or even the relative path) and not just the filename/basename, e.g.
Fatal error: unable to
Dear List,
I am writing a paper in Hungarian, that I Sweave and than pdfLaTeX.
Everything is fine, except for two accented letters in the graphs that
behave strange, though on the screen and in eps exports they look
perfect. The problem is that I need pdf graphs, since I would like to
have a
On 18/09/2008 12:13 PM, Henrik Bengtsson wrote:
Hi.
On Thu, Sep 18, 2008 at 8:16 AM, Duncan Murdoch [EMAIL PROTECTED] wrote:
On 18/09/2008 10:55 AM, Henrik Bengtsson wrote:
R-core, may I suggest that the error message returns the absolute path
(or even the relative path) and not just the
Isn't the full pathname just
paste(getwd(), .RData, sep=/)
Rich
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented,
You need to tell R when to include the plots (there is the possibility that you
will add to the current plot, or redo it, etc., so R cannot tell when to
include plots automatically). Look at the HTMLplot function, you will issue
that when you have made a plot (see it on the screen) that you
Frank E Harrell Jr wrote:
That is a high variance procedure as compared with covariate adjustment
using the propensity score, or stratification.
Frank Harrell
Yes, I guess the foo$fitted.values was the syntax i missed. I know this
method is not optimal and that it yields high
Dear R experts,
I have a problem in modifying one column of a dataframe with a datatime
format using a datetime operator.
Here is my dataframe A:
DATACONT PROVINCIA VALORE
1 2007-12-31MI 1
2 2007-12-31PV 2
3 2007-12-31NA 3
4 2007-12-31MI
every value is the same 0.004975 besides you have to apply the smooth
to a time series what you get when you plot
plot(kernel(daniell, 100))
it isn't in the time domain because there is no association with a
time just values, I think.
On Thu, Sep 18, 2008 at 11:18 AM, [EMAIL PROTECTED] wrote:
Delphine COURVOISIER [EMAIL PROTECTED] wrote:
I would like to write Greek letters followed by subscripts in a graph (on the
X-axis and in a legend). I would appreciate any help.
As others have said, try
demo(plotmath) and also
? plotmath
Here's a brief example:
plot(1:10, 1:10)
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
project.org] On Behalf Of Terry Therneau
Sent: Thursday, September 18, 2008 6:49 AM
To: [EMAIL PROTECTED]
Cc: r-help@r-project.org
Subject: Re: [R] Coxph and loglik converged before variable X
[snip]
b. The
Try something like:
x - runif(25)
y - rnorm(25)
z - rnorm(25, 3*x)
plot(x, y, col=ifelse( z 1.25, 'red', 'green') )
Does this help,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
801.408.8111
-Original Message-
From: [EMAIL
On 18/09/2008 12:23 PM, Richard M. Heiberger wrote:
Isn't the full pathname just
paste(getwd(), .RData, sep=/)
Only on Unix-alikes, and the code that prints the error message is
platform neutral. And at the point where we need this message, R isn't
running, so we'd need this in C code.
Frank E Harrell Jr wrote:
That is a high variance procedure as compared with covariate adjustment
using the propensity score, or stratification.
Frank Harrell
Ah, wait what if I got very high dimensional X ? Even with 20 binary
covariates i would end up with more than 1 million
Hello,
I'm trying to fit a pretty simple confirmatory factor analysis using
the sem package. There's a CFA example in the examples, which is helpful,
but the output for my (failing) model is hard to understand. I'd be
interested in any other ways to do a CFA in R, if this proves
Dear Thierry and all,
I've tried out ggplot from the ggplot2 package and it seems to provide much
more favourable results!
Just a few questions I have after consulting the 'help' file for ggplot.
Is there a way of preventing overplotting? Some of the red points are being
obscured by the
Hello all,
I have a CSV file, that is 2411 columns wide. There are certain instances in
teh file, where null values are located. That is: two commas together,
without anything in the middle. In a certain section, the only possible
values are NULL, 0,1,and 2. I need to be able to detect these
Hi, Dear R-users,
I have a problem when I drawing a boxplot. I want to extend the whisker to
the 5% and the 95% quantiles and only show the most extreme outlier, like
0.01% and 99.99% percentiles. What should I do?
I saw something on boxplot.stat, but even I define the parameter in
Hello,
probable a simple question, but I’m unaware with it. When plotting something
like levelplot(z1+z1~x*y|g), each table has a subtitle containing variable name
of z1 respectively z2 and the value of g. How can I remove the subtitles?
Thanks a lot,
Sebastian
--
Ist Ihr Browser
Thank you very much, Deepayan. There is just one more feature I'd like
to get, the ability to add the contour lines. My revision to your code
below prints too many lines. What needs to be changed?
--Thanks,
Scott Waichler
[EMAIL PROTECTED]
library(gridBase)
library(lattice)
data(volcano)
What have you tried this far? Can't you parse them as missing values,
i.e. NAs? See ?read.csv and arguments '...', i.e. the arguments
'...' are passed to read.table() which takes argument 'na.strings' - a
character *vector* of strings that you want to be interpreted as NAs.
See ?read.table for
I'm not quite sure what you mean. If all you need is propensity
scores to run an IPW analysis, the fitted values should work. Having
many binary covariates shouldn't be a problem, the whole point of the
propensity score is boiling down many dimensions to a single one.
I use matchit() for my psm
I haven't given it a shot yet. To complicate matters further, this file I
have already passed through a filter, which has already converted my null
values to NA. your insight might be of assistance.
On Thu, Sep 18, 2008 at 1:30 PM, Sebastian Weirich [EMAIL PROTECTED]wrote:
Hello,
maybe you
No new info, but the model and correlation table are pasted at the end of
this message.
--Adam
On Thu, 18 Sep 2008, Adam D. I. Kramer wrote:
Hello,
I'm trying to fit a pretty simple confirmatory factor analysis using
the sem package. There's a CFA example in the examples, which is
Phil's suggestion worked like a charm. My NA's were counted in the frequency
table.
Thanks for the help, all!
On Thu, Sep 18, 2008 at 1:28 PM, Henrik Bengtsson [EMAIL PROTECTED]wrote:
What have you tried this far? Can't you parse them as missing values,
i.e. NAs? See ?read.csv and
Dear all,
I'm working on ability estimates using Rasch model. Using the ltm
package, the procedure is quite simple:
## Factor Scores for the Rasch model
fit - rasch(LSAT)
factor.scores(fit)
What about Partial Credit Model (PCM)? For PCM I use PCM function from
eRm package. Is there any
Ben Domingue wrote:
I'm not quite sure what you mean. If all you need is propensity
scores to run an IPW analysis, the fitted values should work. Having
many binary covariates shouldn't be a problem, the whole point of the
propensity score is boiling down many dimensions to a single
Dear Adam,
(1) Note that your input correlation matrix appears to be numerically
singular:
solve(R)
Error in solve.default(R) :
system is computationally singular: reciprocal condition number =
2.38183e-17
det(R)
[1] -1.753523e-25
qr(R)$rank
[1] 23
(2) In addition, you have specified what
Dear John,
On Thu, 18 Sep 2008, John Fox wrote:
I'm trying to fit a pretty simple confirmatory factor analysis using
the sem package. There's a CFA example in the examples, which is helpful,
but the output for my (failing) model is hard to understand. I'd be
interested in any other
Try length(na.omit(the particular data column))
Here's an example:
data - runif(100,0,10)
data[runif(20,0,100)] - NA
file.contents - matrix(data, ncol = 5, byrow = TRUE)
for (i in 1:5) {
print (length(na.omit(file.contents[,i])))
}
-Original Message-
From: [EMAIL PROTECTED]
Hi,
I am having problems passing arguments to method=gbm using the train()
function.
I would like to train gbm using the laplace distribution or the quantile
distribution.
here is the code I used and the error:
gbm.test - train(x.enet, y.matrix[,7],
method=gbm,
Hi, Dear R-users:
Sorry for bothering your guys again. I think I should rewrite my question.
I know how to extend whisker by using range. The question is that I will set
the range=1.5, and at the same time, I only want to show the extreme
outlier, like 0.01% and 99.99% percentile, so what
Hello
I'm working with a large hydrological data set stored in a netCDF format.
The file stores x and y coordinates in the UTM projected coordinate system,
yet when I use image to graphically display the z variable, the image is
distorted in the sense that it does not plot the map in the correct
ran2 wrote:
Frank E Harrell Jr wrote:
That is a high variance procedure as compared with covariate adjustment
using the propensity score, or stratification.
Frank Harrell
Ah, wait what if I got very high dimensional X ? Even with 20 binary
covariates i would end up with more than 1
Dear Adam,
I'm afraid that our emails have crossed. Please see my previous message.
John
--
John Fox, Professor
Department of Sociology
McMaster University
Hamilton, Ontario, Canada
web: socserv.mcmaster.ca/jfox
-Original Message-
From: Adam D. I. Kramer
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