Greg Snow wrote:
http://rcom.univie.ac.at/
Or just install the RExcelInstaller package and run the installRExcel function.
A book on the interface will be coming out sometime in Winter.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
with the space parameter it is possible to change the gap / distance
between the bars, but is it also
possible to change the space after each 6th bar?
So for example you have bars from 1 to 6 then a large gap and then the
next
six bars from 7 to 12
Try, for example
y - runif(13)
y[7] - NA
[EMAIL PROTECTED] wrote:
with the space parameter it is possible to change the gap / distance
between the bars, but is it also
possible to change the space after each 6th bar?
So for example you have bars from 1 to 6 then a large gap and then the
next
six bars from 7 to 12
Jim Lemon wrote:
Michael Just wrote:
Thank you all for you suggestions. They are all helpful. However, I
have come to a more fundamental problem. Preparing my data to even
make such a graph. I thought I was ready. I will obviously need to
find the n, mean, and confidence interval for my data
I have been trying to use the censored bootstrap function 'censboot' from the
library boot, with the function 'survfit' from the library survival. I get the
error message:
In min(surv$time[inds[1 - surv$surv[inds] = 0.5]]) ... :
no non-missing arguments to min; returning Inf
Does anyone
hello everybody,
I have a directory with over 3000 files with different names. I would like
to make some vectors with the file names which are belong together.
I'm trying to do it with a for loop in R:
SF - c(ad, cd, cer, stress, salty, PC, high, transfer,
cold, heat) # the pattern to look
Hi Dan,
Please ignore my previous question. I figured it out by specifying
all.x=FALSE.
Have a great day!
Allen
On Wed, Oct 8, 2008 at 8:28 PM, ss [EMAIL PROTECTED] wrote:
Hi Dan,
Thanks a lot for this! It works but I have some minor issues.
Let's take the working example for instance,
Zitat von Gerhard Schön, UKE Hamburg [EMAIL PROTECTED]:
what is the result of:
df - data.frame(x = 1:5, y = 1:5)
plot(df, pch = 1:5)
It prints different symbols.
It seemed, that my pch-settings had an effect,
but some symbols were very similar, especially, when
a lot of them are plotted at
I am having some problems while trying to fit simple data.
I aggregated some data using:
data1 - aggregate(data1$T2, list=(SOA=data1$SOA), mean)
unfortunatly this coerces my variable SOA into a factor. Therefore when a
afterwards try to fit a simple equation to my variable T2 using a formula on
Try the gls function in the nlme package. It allows you to model the variance
as well as the mean.
-Original Message-
From: Bunny, lautloscrew.com [EMAIL PROTECTED]
To: r-help@r-project.org r-help@r-project.org
Sent: 10/9/08 3:40 AM
Subject: [R] adjusted t-test with unequal variance
Hi
I had similar problem before and I ended with some ordering of groups
before making grouped data object but it was data specific so I can not
give you definite clue.
Regards
Petr
[EMAIL PROTECTED] napsal dne 08.10.2008 19:30:07:
Dea-R community.
I'd like to draw your attention to an
k.ponting wrote:
Hello all.
Trying to use transparency for overlaid histogram plots I have come
across an interesting inconsistency, possibly a bug when running under
Windows. Originally noticed in R 2.7.1, it is still there in 2.8.0 beta.
library(lattice)
zz - function(n,alpha)
{
On Thu, 9 Oct 2008, michael watson (IAH-C) wrote:
Hi
Sorry, I am clearly missing something here.
Yes, you need to use unz() for a zip file, and it does not handle urls
(only url does). So download the file (download.file()) first.
I want to read this file directly:
R-FAQ 7.10:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-do-I-convert-factors-
to-numeric_003f
On Oct 9, 2008, at 6:59 AM, joseph kambeitz wrote:
I am having some problems while trying to fit simple data.
I aggregated some data using:
data1 - aggregate(data1$T2, list=(SOA=data1$SOA),
Hi,
I wonder if there are any parallel package which do not rely on mpi or pvm?
On Wed, Oct 8, 2008 at 5:09 PM, Markus Schmidberger
[EMAIL PROTECTED] wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Hi Chi,
ParallelR is a commercial software to run R in parallel. It is working
very
[EMAIL PROTECTED] wrote:
hello everybody,
I have a directory with over 3000 files with different names. I would like
to make some vectors with the file names which are belong together.
I'm trying to do it with a for loop in R:
SF - c(ad, cd, cer, stress, salty, PC, high, transfer,
cold,
--- On Thu, 10/9/08, Oliver Bandel [EMAIL PROTECTED] wrote:
From: Oliver Bandel [EMAIL PROTECTED]
Subject: Re: [R] plot-parameter pch without influence when plotting a
data-frame
To: Gerhard Schön, UKE Hamburg [EMAIL PROTECTED]
Cc: R-help r-help@r-project.org
Received: Thursday, October 9,
Hello,
I am performing cor() of some of my data. For example, I'll do 3 corr()
(many variables) operations, one for each of the three treatments.
I then do the following:
i -lower.tri(treatment1.cor)
cor(cbind(one = treatment1.corr[i], two = treatment2.corr[i], three =
treatment3.corr[i]))
We have spent some time setting up Sun Grid Engine and OpenMPI on a
group of linux boxes. I have created a parallel environment and
everything seems to be working. I have Rmpi 0.5.5-5 installed on all
machines. I would like to start an interactive R session using, say,
8 processors and then
Please provide a small working example. It is difficult to see what you are
doing from the description below.
--- On Thu, 10/9/08, Michael Just [EMAIL PROTECTED] wrote:
From: Michael Just [EMAIL PROTECTED]
Subject: [R] Interpretation in cor()
To: r-help r-help@r-project.org
Received:
Perhaps save the file as a csv (?write.table) and present the results in a
spreadsheet or word processor table?
--- On Thu, 10/9/08, Michael Just [EMAIL PROTECTED] wrote:
From: Michael Just [EMAIL PROTECTED]
Subject: [R] Exporting symnum() result from cor()
To: r-help r-help@r-project.org
On 9 October 2008 at 09:18, Sean Davis wrote:
| We have spent some time setting up Sun Grid Engine and OpenMPI on a
| group of linux boxes. I have created a parallel environment and
| everything seems to be working. I have Rmpi 0.5.5-5 installed on all
| machines. I would like to start an
?aggregate ( as Jim Holtman pointed out) is the standard way.
Another way is to use the reshape package and try something like
library(reshape)
names(x)[3] - value
cast(x, Seller + Art. ~., mean)
(Note the names(x)[3] - value seems necessary at the moment as reshape only
seems to work on
Hello,
I am trying to export the results from symnum() while maintain their
readability. I tried using sink to text file and also copying and pasting
but the results end up looking like this:
symnum(c5.s)
bC bED bEN bLP bLS bPA bPD bPR p
bbContag 1
bbED + 1
bbENN_MN + B 1
Dear R-helpers,
The FAQ in question says:
It may happen that when reading numeric data into R (usually, when
reading in a file), they come in as factors. If f is such a factor
object, you can use
as.numeric(as.character(f))
to get the numbers back. More efficient, but harder to
Michael Just wrote:
Thank you all for you suggestions. They are all helpful. However, I
have come to a more fundamental problem. Preparing my data to even
make such a graph. I thought I was ready. I will obviously need to
find the n, mean, and confidence interval for my data before I can
Dear Colleagues,
I think the allure of bargraph.CI is that it makes it easy to plot
standard errors--though you still have to fiddle with the options to
get the size of confidence interval you want. And there is the
(strong) dislike of dynamite plots by some (the ink to info argument).
Box and
Dear All,
I get the following error when using either SASxport or Hmisc to read an
.xpt file:
w - read.xport(D:/consult/Trophos/dnp/base/TRO_ds_20081006.xpt)
Erreur dans factor(x, f$value, f$label) :
invalid labels; length 15 should be 1 or 14
z-
On Thu, Oct 9, 2008 at 9:02 AM, Dirk Eddelbuettel [EMAIL PROTECTED] wrote:
You could have a look at the slides from my UseR! 2008 tutorial [1] on
'high-performance computing with R' which covered Open MPI / Rmpi and
includes examples.
It may just be that you are expecting something that
Hi all,
right now i am simply comparing means. obviously this can be done by
the simple t.test respectively the welch test, if var.equal is set to
FALSE.
just like this
t.test( Y ~ group)
t.test( Y ~ group, var.equal = FALSE)
now that i need to compare weighted means i am using the lm
Hi
Sorry, I am clearly missing something here.
I want to read this file directly:
ftp://ftp.sanger.ac.uk/pub/mirbase/targets/v5/arch.v5.txt.gallus_gallus.
zip
I tried using
read.table(gzfile(ftp://ftp.sanger.ac.uk/pub/mirbase/targets/v5/arch.v5
.txt.gallus_gallus.zip))
But I got an error:
Hello,
I'm plotting a data-frame and use
plot(..., pch=...)
as well as setting pch with
par(pch=...)
but always get the default symbol (circle)
for the plots.
Does pch have no effect, when plotting a complete
data-frame, instead of certain values/vectors?
How to change the behaviour?
Michael Just wrote:
Hello,
I am trying to export the results from symnum() while maintain their
readability. I tried using sink to text file and also copying and pasting
but the results end up looking like this:
symnum(c5.s)
bC bED bEN bLP bLS bPA bPD bPR p
bbContag 1
But when I use the function makeSOCKmpi I am required to input my
password to local computer, right? I haven't figured out how to do
that when using a Sun Grid Engine. Do you have any suggestions? Thanks
a lot.
2008/10/9 Martin Morgan [EMAIL PROTECTED]:
snow can use native sockets, i.e., no
Alberto Jiménez Valverde ajvalv at ku.edu writes:
Hi all,
I am trying to run an autologistic model using the function errorsarlm from
spdep package.
...
**I want to estimate the spatial simultaneous autoregressive error model**
res20-errorsarlm(finalglm1, listw=nb20.w,
Dear all,
I would like to use a GWR model in order to spatially predict food
insecurity in Africa. I have a georeferenced village data-bases and I've run
a classic regression model (taking into account the spatial dependence of
the errors) that works fairly well for Niger that is a quite
Dear all,
I've sent this question 2 days ago and got response from Sarah. Thanks for
that. But unfortunately, it did not really solve our problem. The main issue
is that we want to use our own (manipulated) covariance matrix in the
calculation of the mahalanobis distance. Does anyone know how to
Hi Peter,
thanks a lot for your help. Very much appreciated.
Cheers,
Julia
Peter Dalgaard wrote:
Julia S. wrote:
Hi there,
thanks for your help. I did read Bates statement several times, and I am
very glad and thankful that many statisticians spend much time on this.
The
problem
Jean-Louis Abitbol wrote:
Dear All,
I get the following error when using either SASxport or Hmisc to read an
.xpt file:
w - read.xport(D:/consult/Trophos/dnp/base/TRO_ds_20081006.xpt)
Erreur dans factor(x, f$value, f$label) :
invalid labels; length 15 should be 1 or 14
z-
Dear R-experts,
I am currently writing my theses about what - else but price - drives low
cost carriers` buying behavior.
To evaluate the collected choice-based conjoint data, I have to perform a
latent class analysis.
I have found the package poLCA, but somehow I don`t get the output I need...
Heja,
I've some bigger distance-matrices like this:
num [1:3231, 1:3231] 0.000 0.176 0.176 0.176 0.176 ...
- attr(*, dimnames)=List of 2
..$ : chr [1:3231] A B C D ...
..$ : chr [1:3231] A B C D .
I actually want to convert them into a 2 column dataframe like this:
data.frame':
Ben Bolker
There's not much you can do about this.
But at least I understand it now. Thank you.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Thank you so much. I have yet another problem that I could not resolve from
the documentation. I want to get line breaks for long variable names.
Here's an example:
Gender-sample(c(m,f),20,replace=TRUE)
Education-rnorm(20,13)
label(Education)-Years of\nEducation
Hi everyone,
I am using the package spatstat for ploting kernel maps of my data.
It is a marked point pattern, the result of mosquito surveillance in a
area in a week.
For each trap, the number of individuals captured is the mark of the point.
plot(density(X, weights=X$marks))
makes a nice
I'm trying to create a 3D plot using wireframe with certain parts removed. I
would like to get rid of the part of the outer cube that crosses over the plot
leaving the back two walls and the axes. It would also be useful to put lines
in the plot separate from the wireframe call. I've looked
One thing that would speed it up is if you
inverted 'covmat' once and then used
'inverted=TRUE' in the call to 'mahalanobis'.
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and A Guide for the Unwilling S User)
Frank Hedler wrote:
Dear all,
I've
Check out R-PLUS 3.3 from XLSolutions Corp. They have a GUI that you can
easily expand. www.Experience-Rplus.com
--- On Thu, 10/9/08, [Ricardo Rodriguez] Your XEN ICT Team [EMAIL PROTECTED]
wrote:
From: [Ricardo Rodriguez] Your XEN ICT Team [EMAIL PROTECTED]
Subject: Re: [R] Creating
Check out R-PLUS 3.3 from XLSolutions Corp. They have a GUI that you can
easily expand. www.Experience-Rplus.com
--- On Thu, 10/9/08, [Ricardo Rodriguez] Your XEN ICT Team [EMAIL PROTECTED]
wrote:
From: [Ricardo Rodriguez] Your XEN ICT Team [EMAIL PROTECTED]
Subject: Re: [R] Creating
I've sent this question 2 days ago and got response from Sarah. Thanks
for
that. But unfortunately, it did not really solve our problem. The main
issue
is that we want to use our own (manipulated) covariance matrix in the
calculation of the mahalanobis distance. Does anyone know how to
Hello!
I am trying to put two math expressions in the title of a plot. As
you can see below, I can place correctly one expression at a time, but
not both. Ideally I would like to have them separated by a comma. Any
suggestions?
k - 1
n.eff - c(20, 30)
### this works
plot(0,0, main =
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Hi,
mpi is probably the mostly used standard for parallel computing. It was
especially developed for message passing. Therefore most packages are
based on MPI.
Using snow you can choose between socket, mpi, pvm and (in the newest
version) nws. I
Frank said:
This piece of code works, but it is very slow. We were wondering if
it's
at
all possible to somehow vectorize this function. Any help would be
greatly
appreciated.
Richie said:
You can save a substantial time by calling as.matrix before the loop
Patrick said:
One thing
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Hi,
actually there is no perfect way to use R one multiprocessors. There are
two options:
* using mpi: This means starting several R sessions and using MPI for
the communication between the R sessions. Task distribution, fail over
solutions, ...
Can someone recommend a method to answer the following type of question:
Suppose I have a coin with a probability hhh of coming up heads (and 1-hhh
of coming up tails)
I plan on flipping the coin nnn times (for example, nnn = 500)
What is the expected probability or frequency of a run of rrr
Is this what you want:
x - data.frame(Name=c(A,A,C), Category=c(a,a,b),
Quantity=c(1,2,3))
aggregate(x$Quantity, list(x$Name, x$Category), FUN=sum)
Group.1 Group.2 x
1 A a 3
2 C b 3
'by' is a list of grouping elements, each as long as the variables in
x. Your
You can use 'sample' and 'rle':
x - sample(c(H,T), 500, replace=TRUE, prob=c(.95, .05))
as.data.frame(unclass(rle(x)))
lengths values
1 12 H
21 T
3 10 H
41 T
55 H
62 T
7 26 H
81 T
9 17
Hi,
I'm using the package randomForest to generate a classifier for the exemplary
iris data set:
data(iris)
iris.rf-randomForest(Species~.,iris)
Is it possible to print all decision trees in the generated forest?
If so, can the trees be also written to disk?
What I actually need is to
Is this what you want:
x - matrix(1:16,4)
rownames(x) - colnames(x) - LETTERS[1:4]
x
A B C D
A 1 5 9 13
B 2 6 10 14
C 3 7 11 15
D 4 8 12 16
require(reshape)
# create single list
z - melt(x)
z
X1 X2 value
1 A A 1
2 B A 2
3 C A 3
4 D A 4
5 A B 5
6
Did anyone try to write R extensions in OCaml? What would it entail
to enable it?
Cheers,
Alexy
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
It seems to me that you are asking for:
hhh - 0.1
sum(dbinom(x=0:50,size=500,prob=hhh))
[1] 0.5375688
You can use 'sample' and 'rle':
x - sample(c(H,T), 500, replace=TRUE, prob=c(.95, .05))
as.data.frame(unclass(rle(x)))
lengths values
1 12 H
21 T
3
I am not involved in the RExcel project. I have just had some discussions with
the people that are, so you should contact them for specific questions.
I believe that this currently only works on windows, there was some mention of
possibly expanding it to OpenOffice so that it would be cross
Hi Tao --
Tao Shi [EMAIL PROTECTED] writes:
This is a follow-up on the discussion originally posted on the
R-devel list (
http://tolstoy.newcastle.edu.au/R/e4/devel/08/06/1901.html ), as I
have encountered the exact same issue mentioned in Martin's email.
Here is a simplified version of my
See the getTree() function in the package. Also, the source package
contains C code that does the prediction that you may be able to work
from.
Andy
From: Christian Sturz
Hi,
I'm using the package randomForest to generate a classifier
for the exemplary
iris data set:
data(iris)
Hi
It is probably simple but how to force in plot command number format:
2, 3, 4 etc. instead of 2e+04, 3e+04 etc.
example of command:
plot(x=data$along, y=data$rzedna,type=l, xlim=c(0,max(data$along)),
ylim=c(200,1200), main=, xlab=length, ylab=height, cex.main=2,
cex.lab=1.5,
Giovanni Petris GPetris at uark.edu writes:
Hello!
I am trying to put two math expressions in the title of a plot. As
you can see below, I can place correctly one expression at a time, but
not both. Ideally I would like to have them separated by a comma. Any
suggestions?
k - 1
Hi,
I have a list(A1) of dataframe and a vector containing a 22 list names.
list(A1)
abc
l m n
p q r
dce
e g h
l k m
kpo
a d c
also i have a vector of list names.
abc,dce similarly i have 22 elements.
I wanna delete or want a list without the list elements whoes name match up
the vector.
r11 -- r16 are variables showing a reason for usage of a product in 6
different situations. Each variable is a factor with 4 levels imported
from a SPSS sav file with labels ranging from not important to very
important, and NA's for a sample of N = 276.
(1) I need a chi square test of
Try bquote:
plot(0, 0, main = bquote(n == .(k) * , ~ N[eff] == .(n.eff[k])))
On Thu, Oct 9, 2008 at 12:22 PM, Giovanni Petris [EMAIL PROTECTED] wrote:
Hello!
I am trying to put two math expressions in the title of a plot. As
you can see below, I can place correctly one expression at a
Dear,
I'm starting on R language. I would like some help to implement a MLE
function.
I wish to obtain the variables values (alpha12, w_g12, w_u12) that maximize
the function LL = Y*ln(alpha12 + g*w_g12 + u*w_u12).
Following the code:
rm(list=ls())
ls()
library(stats4)
Model =
Hi there,
I'm looking for advice on a R book that's for somewhat advanced user.
I've been using R for a while and can do the basic analysis with no problem. My
problem is that for many already existing commands, such as gsub,
textconnection, list, etc, I don't use them, simply because I don't
I am trying to figure out how to use ggplot2. I would like to do the below
with ggplot, but I can not figure out how. The data provided is a subset of
a much larger data set, but these data are the data necessary to make the
plot. I think I would rather have the colors become symbols, and I do
You might find Robert Gentleman's recent book useful for exposure on many of
the more advanced features of R.
http://www.bioconductor.org/pub/RBioinf/
-Christos
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Hua Li
Sent: Thursday, October 09,
could you make this reporducible- even with dummy data...? I am not sure
what you want.
On Thu, Oct 9, 2008 at 3:01 PM, Rajasekaramya [EMAIL PROTECTED]wrote:
Hi,
I have a list(A1) of dataframe and a vector containing a 22 list names.
list(A1)
abc
l m n
p q r
dce
e g h
l k m
Try this:
A1 - list(abc = letters[1:3], dce = letters[4:6], kpo = letters[7:8])
v - c(abc, dce)
A1[setdiff(names(A1), v)]
On Thu, Oct 9, 2008 at 4:01 PM, Rajasekaramya [EMAIL PROTECTED] wrote:
Hi,
I have a list(A1) of dataframe and a vector containing a 22 list names.
list(A1)
abc
l m n
Dear Ramya,
Try this:
# Your list
A=matrix(rnorm(100),ncol=10)
B=matrix(rnorm(100),ncol=10)
C=matrix(rnorm(100),ncol=10)
colnames(A)=colnames(B)=colnames(C)=paste('X',1:10,sep=)
mylist=list(A,B,C)
names(mylist)=c('A','B','C')
# Your name vector
x=c('A','C')
# Marching up!
mylist[names(mylist)
All,
Is it possible to use binom.test with vector input for only one of the
arguments? I was thinking that this would possibly work with sapply but
then it seems that the binom.test function would have to be re-written to
supply defaults for all other arguments.
set.seed(101)
sim.x =
Hello John,
Is it possible to write more than one data frame to a single write.csv or
write.table?
Thanks,
Michael
On Thu, Oct 9, 2008 at 8:38 AM, John Kane [EMAIL PROTECTED] wrote:
Perhaps save the file as a csv (?write.table) and present the results in a
spreadsheet or word processor table?
On Thu, Oct 9, 2008 at 2:29 PM, stephen sefick [EMAIL PROTECTED] wrote:
I am trying to figure out how to use ggplot2. I would like to do the below
with ggplot, but I can not figure out how. The data provided is a subset of
a much larger data set, but these data are the data necessary to make
It would take the size of several books to systematically
list everything in R so no book could contain that. If you
read one page of the R reference manual per day and when
you are finished with that then read the entire reference manual
of one contributed package each week then you should be
Hello all,
I want to print out call from my function. When I have a long list of
arguments or long names for them, I either got mulilines using default
print or big blank space using cat:
foo- function(data, newdata)
{
call - match.call();
cat(Call:\n);
print(call);
cat(\nCall:\n,
On 10/10/2008, at 6:16 AM, Harvey wrote:
Can someone recommend a method to answer the following type of
question:
Suppose I have a coin with a probability hhh of coming up heads
(and 1-hhh
of coming up tails)
I plan on flipping the coin nnn times (for example, nnn = 500)
What is the
Error in `[.data.frame`(df, , var) : undefined columns selected
I got this error in a fresh R session after rerunning all of the commands
On Thu, Oct 9, 2008 at 3:45 PM, hadley wickham [EMAIL PROTECTED] wrote:
On Thu, Oct 9, 2008 at 2:29 PM, stephen sefick [EMAIL PROTECTED] wrote:
I am
Jarek Jasiewicz wrote:
Hi
It is probably simple but how to force in plot command number format:
2, 3, 4 etc. instead of 2e+04, 3e+04 etc.
Not all that simple! It's one of those cases where you need to regain
some control that you normally leave to the automatics. What you can do
Hello,
Two lapply questions (system info and sample data below):
1) Why does the first form of command1 add the name of y _after_ the
str() output rather than before as does the second (preferred) form?
# command1 version1
invisible(lapply(ls(pattern='bn'), function(y) cat(y, \n,
On 10/10/2008, at 4:48 AM, Arthur Weiss wrote:
Hi everyone,
I am using the package spatstat for ploting kernel maps of my data.
It is a marked point pattern, the result of mosquito surveillance in a
area in a week.
For each trap, the number of individuals captured is the mark of
the point.
[EMAIL PROTECTED] wrote:
r11 -- r16 are variables showing a reason for usage of a product in 6
different situations. Each variable is a factor with 4 levels imported
from a SPSS sav file with labels ranging from not important to very
important, and NA's for a sample of N = 276.
(1) I need a
I'm wondering is it in accordance with the law, taking into account GNU GPL on
which R is based, that SPSS have adds-on module that allow you to do a analysis
in R. I mean commercial software use R.
I guess that nobody can create R-GUI (e.g. in JAVA) on commercial rules
(licensing, pricing,
From ?cor()
## Two simple vectors
cor(1:10,2:11)# == 1
## Correlation Matrix of Multivariate sample:
(Cl - cor(longley))
## Graphical Correlation Matrix:
symnum(Cl)
# highly correlated ## Spearman's rho and Kendall's tau
symnum(clS - cor(longley, method = spearman))
symnum(clK - cor(longley,
I've tried the getTree() function and printed a decision tree with print().
However, it seems to me that it's hard to parse this representation and
translate it into equivalent if-then-else C constructs. Are there no other
ways to dump the trees into a more hierarchical form?
What do you exactly
Hello,
I'm having trouble correctly specifying the random effects for a nlme
model. The general summary of what I'm trying to do is that I've got a
data set that has multiple individuals and multiple machines that took
measurements from those individuals. At least one of the machines has
drift
Hi,
eugene dalt wrote:
Check out R-PLUS 3.3 from XLSolutions Corp. They have a GUI that you can
easily expand. www.Experience-Rplus.com
Windows only? We are trying to moved out of Windows. The objective is to
promote an environment that support us much environments as possible.
Linux,
Thanks Greg,
Greg Snow wrote:
I am not involved in the RExcel project. I have just had some discussions with
the people that are, so you should contact them for specific questions.
I believe that this currently only works on windows, there was some mention of possibly
expanding it to
On Thu, 9 Oct 2008, Greg Snow wrote:
I am not involved in the RExcel project. I have just had some
discussions with the people that are, so you should contact them for
specific questions.
I believe that this currently only works on windows, there was some
mention of possibly expanding it
Hi Chris,
Maybe it is easier if you try the following C++ library
http://mtv.ece.ucsb.edu/benlee/librf.html
Regards,
Pedro
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Christian Sturz
Sent: Thursday, October 09, 2008 4:30 PM
To: Liaw, Andy;
Hi all, I am quite sure it's not a bug, but I am going nuts about this. I do
not possibly understand why I get different results for b1 and b2 as shown
below.
x=c(183,191,192,193,195,206,207,209,210,211,212,213,214,217,218,221,222,223,
224,225,227,228,229,230)
y=c(221,225,228,241,242)
IIRC this is a standard problem in digital communications theory, so you
might want to look for literature in that arena.
Carl
Can someone recommend a method to answer the following type of
question:
Suppose I have a coin with a probability hhh of coming up heads
(and 1-hhh
of coming up
Richard,
Thanks this works well.
-Michael Just
On Thu, Oct 9, 2008 at 2:43 PM, Michael Just [EMAIL PROTECTED] wrote:
Hello John,
Is it possible to write more than one data frame to a single write.csv or
write.table?
Thanks,
Michael
On Thu, Oct 9, 2008 at 8:38 AM, John Kane [EMAIL
On 10/10/2008, at 10:33 AM, Daniel Malter wrote:
Hi all, I am quite sure it's not a bug, but I am going nuts about
this. I do
not possibly understand why I get different results for b1 and b2
as shown
below.
x=c
(183,191,192,193,195,206,207,209,210,211,212,213,214,217,218,221,222,2
23,
I just gave up a second too early: It does not work with ifelse(...) as
ifelse(...) assigns only a singley value (the first in the vector). A
regular if(...) else ... condition works, however.
Daniel Malter wrote:
Hi all, I am quite sure it's not a bug, but I am going nuts about this. I
do
Hello,
Is there a way to put multiple data.frames or objects into a single .csv ?
I know I can use sink() to do this for a text file. Is there way to do it
for a .csv?
e.g. for sink()
sink(c5.k.s.p.92.LN.sl.vs.mean.txt)
symnum(c5.k.92.LN.sl.vs.mean)
symnum(c5.s.92.LN.sl.vs.mean)
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