Hello everybody,
I just started with lattice plots and I was wondering why it behaves different
than expected.
If I generated multiple plots in the past, I just used some code like this:
lapply(..., {
windows()
plot(...)
})
I got multiple windows, each containing one plot.
2009/1/27 Rainer M Krug r.m.k...@gmail.com:
On Tue, Jan 27, 2009 at 2:30 AM, Peter Waltman peter.walt...@gmail.com
wrote:
Hi -
I saw your posting on the R-help mailing list. Were you ever able to get
this working? did you end up switching to use the rsge library?
Yes - that is exactly
Hi, All,
I want to construct a pareto chart for my data. My data has two
columns: modules and defects(each module has several defects). Now I
use pareto.chart to create a chart for defects which y axis is
cumulative percentage of defect, and x axis is value of defect. That
is not what I want.
On Tue, Jan 27, 2009 at 11:04 AM, Marce marc...@gmail.com wrote:
2009/1/27 Rainer M Krug r.m.k...@gmail.com:
On Tue, Jan 27, 2009 at 2:30 AM, Peter Waltman peter.walt...@gmail.com
wrote:
Hi -
I saw your posting on the R-help mailing list. Were you ever able to get
this working? did you
I guess, I got the answer.
(http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-do-lattice_002ftrellis-graphics-not-work_003f)
Ciao,
Antje
Antje schrieb:
Hello everybody,
I just started with lattice plots and I was wondering why it behaves
different than expected.
If I generated multiple
I have a script that sometimes produces the following error:
Error in assign(.target, met...@target, envir = envir) :
formal argument envir matched by multiple actual arguments
Do you think this is a memory issue? I don't know what else it could be
as it doesn't always occur even if the
Hi
r-help-boun...@r-project.org napsal dne 27.01.2009 01:50:39:
Ok, so I'm slowly figuring out what a factor is, and was able to follow
the related thread about finding a mode by using constructs like
my_mode = as.numeric(names(table(x))[which.max(table(x))])
Now, suppose I want to
Team,
I am trying to resolve the self-selection bias of a sample in an experiment
and would like to run the Heckman Correction Estimation using R. Can
someone help me with the R-Code... I tried searching for the discussion, but
not successful. Thanks in advance,
Best,
Kishore/..
See the micEcon package. there is and heckit function
 Justin BEM
BP 1917 Yaoundé
Tél (237) 99597295
(237) 22040246
De : Kishore gladikish...@gmail.com
à : r-help@r-project.org; r-h...@stat.math.ethz.ch
Envoyé le : Mardi, 27 Janvier 2009, 11h54mn 00s
Daniel Brewer wrote:
I have a script that sometimes produces the following error:
Error in assign(.target, met...@target, envir = envir) :
formal argument envir matched by multiple actual arguments
Do you think this is a memory issue? I don't know what else it could be
as it doesn't always
Hi Dann,
there is probably a better way to do this, but this works anyway:
# your data
gamdat - rgamma(1, shape=1, rate=0.5)
# comparison to gamma:
gamsam - rgamma(1, shape=1, rate=0.6)
qqplot(gamsam,gamdat)
abline(0,1)
greetings
Remko
R is finding the R function 'time' rather than your variable time in your
dataset. Perhaps adding 'data=mydata' to your function call will resolve
your issue.
Chris
Braem M wrote:
Dear,
I want to analyze two-level survival data using a shared frailty model,
for which I want to use the
Thank you, Duncan! It works perfectly!
Best regards,
Peter.
-Original Message-
From: Duncan Murdoch [mailto:murd...@stats.uwo.ca]
Sent: 27. januar 2009 13:04
To: Peter Jepsen
Cc: r-help@r-project.org
Subject: Re: [R] Sweave'ing Danish characters
On 26/01/2009 5:44 PM, Peter Jepsen
On 26/01/2009 5:44 PM, Peter Jepsen wrote:
Hi,
I am writing an Sweave document and am using 'xtable' to make frequency tables of diagnoses of people
undergoing cholecystectomy. Some of these diagnoses contain Danish characters (æ, ø,
and å), and these characters are all garbled in the Latex
Since we have no idea what your data looks like, you can create a plot
and then apply your own axis. You might also be able to rescale the
x-axis data to be a percentage to start with. It is all doable
depending on what you input looks like and what you want your output
to look like. That is
Thank you Duncan.
I remember seeing in your documentation that you have used this
'verbose=TRUE' argument in functions before when trying to see what is
going on. This is good. However, I have not been able to get it to
work for me. Does the output appear in R or do you use some other
external
clair.crossup...@googlemail.com wrote:
Thank you Duncan.
I remember seeing in your documentation that you have used this
'verbose=TRUE' argument in functions before when trying to see what is
going on. This is good. However, I have not been able to get it to
work for me. Does the output
Hello experts!
Is there a way to send an internal variable from a function to the
workspace, besides the function output, of course
Thanks!!
D.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
At 12:49 26/01/2009, Robert Michael Inman wrote:
Problem:
I am sorting through model selection process for first time and want to make
sure that I have used glm, stepAIC, and update correctly. Something is
strange because I get a different result between:
1) a glm of 12 predictor variables
I guess by workspace you mean global environment. I believe this is
generally considered a bad practice, but see ?assign and ?-
baptiste
On 27 Jan 2009, at 13:54, diego Diego wrote:
Hello experts!
Is there a way to send an internal variable from a function to the
workspace, besides the
System: [Windows XP Pro, R 2.8.0 and R 2.81.]
When I do R graphics on Windows and want .eps output for LaTeX, with *tight
bounding boxes* I usually do as follows from Rgui:
- Save as Postscript ... myfig.ps
- Open myfig.ps in Gsview, select PS to EPS, Save as ... myfig.eps
This always worked
Is there a way to force the number of ticks along an axis ?
I read the on-line documentation and tried many combinations of all available
parameters from functions
par(), axTicks(), axis(), plot() ... but no luck !
Thank you very much,
Maura
tutti i telefonini TIM!
[[alternative HTML
Will something like this do what you want?
x - 1:10
y=rnorm(10)
plot(x,y,xaxt=n)
axis(1,at= seq(.5,10,.5))
--- On Tue, 1/27/09, mau...@alice.it mau...@alice.it wrote:
From: mau...@alice.it mau...@alice.it
Subject: [R] plot Ticks
To: r-h...@stat.math.ethz.ch
Received: Tuesday, January 27,
Try this:
plot(1:20)
axis(3, at=seq(0,20), label=FALSE)
A better description of your plot would be useful if ?axis is not
enough to help you out.
hope this helps,
baptiste
On 27 Jan 2009, at 14:13, mau...@alice.it wrote:
Is there a way to force the number of ticks along an axis ?
I
I used following command:
frailtyPenal(Surv(time, status) ~var1 + cluster(family), Frailty=TRUE
,n.knots=8, kappa1=1500,
+ cross.validation=FALSE)
And got this error :
Error in Surv(time, status) : Time variable is not numeric
In addition: Warning message:
In is.na(time) : is.na() applied to
you could set them manually, if thats what you're looking for
plot(1:10, axes = F)
axis(1, at = seq(1,10 , length = 3))
mau...@alice.it schrieb:
Is there a way to force the number of ticks along an axis ?
I read the on-line documentation and tried many combinations of all available
parameters
Just have it as a return value and then assign it when you return.
You should have have side effects coming from your functions. There
are ways of doing it, but it you think you have to, think about it
again.
On Tue, Jan 27, 2009 at 8:54 AM, diego Diego dhab...@gmail.com wrote:
Hello experts!
Assuming you _really_ want to do this check out '-' and closures... And
remember that your code will probably make other people cry when they go to
debug it.
Krzysztof
Sent via BlackBerry by ATT
-Original Message-
From: jim holtman jholt...@gmail.com
Date: Tue, 27 Jan 2009 09:43:17
Hi,
I am a Ph.D. student from Québec, Canada. Im a beginner with R and
Bioconductor. Until now the only experience I have is in analyzing
microarray data using affy and limma packages. Now I am trying to analyze
Rat Gene 10 st arrays and I would like to run RMA analysis and Smyth
moderated t
Hi R user,
I can not find the answer for a simple problem. I want to test the main effects
and interactions of a 2 by 2 factorial design (Experiment I) and 2 by 2 by 2
factorial design (Experiment II) with unequal group sizes and one or two
within-subject factors.
2 by 2 Design (Experiment
Thanks for that Remko, but im slightly confused because isnt this testing the
goodness of fit of 2 slightly different gamma distributions, not of how well
a gamma distribution is representing the data.
e.g.
data.vec-as.vector(data)
(do some mle to find the parameters of a gamma distribution
Thank you for your reply.
Even when I put data=.. in my model statement, I get the same error.
Chris Andrews wrote:
R is finding the R function 'time' rather than your variable time in your
dataset. Perhaps adding 'data=mydata' to your function call will resolve
your issue.
Chris
I am just assuming this can be done, but I have not gotten close to
making it happen. I have a data file with about 1 million rows with
1470 unique subjects. Each row represents a small set of observations
made on a specific date for a single subject. I would like to
transform the data so
dhabby wrote:
Last week I run in to a lot a problems triyng to fit an ARIMA model to a
time series. The problem is that the internal process of the arima
function
call function optim to estimate the model parameters, so far so good...
but my data presents a problem with the default
Thank you. The output i get from that example is below:
d = debugGatherer()
getURL(http://uk.youtube.com;,
+ debugfunction = d$update, verbose = TRUE )
[1]
d$value()
text
About to connect() to uk.youtube.com port 80 (#0)\n Trying
208.117.236.72... connected\nConnected to
Surely, this sounds like a bug in the optim function.
The rule of thumb with ts data is to scale so that data have mean 0 and
unit variance and then fit
a) for non-seasonal data the IMA model (0,1,1); and
b) for seasonal data so-called Airline Model (0,1,1)X(0,1,1)S
see for example A course
Yes the data can probably be easily transformed, but you would have to
provide an example of what the input looks like to understand what has
to be done with the data and how variable it might be so we can
understand how we might have to parse the data from the input. Are
the missing days
For a model I am working on, I have samples organized by year and week of
the year. For this model, the data (year and week) comes from the basic
sample data, but I require a value representing the amount of time since the
sample was taken (actually, for the purpose of the model, it is sufficient
Hi!
Someone knows some function to print a timestamp?
Regards,
Raphael Saldanha
BRAZIL
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Try this for a object of class POSIXct
unclass(Sys.time())
On Tue, Jan 27, 2009 at 2:38 PM, Raphael Saldanha
saldanha.plan...@gmail.com wrote:
Hi!
Someone knows some function to print a timestamp?
Regards,
Raphael Saldanha
BRAZIL
[[alternative HTML version deleted]]
Some Web servers are strict. In this case, it won't accept
a request without being told who is asking, i.e. the User-Agent.
If you use
getURL(http://www.youtube.com;,
httpheader = c(User-Agent = R (2.9.0
you should get the contents of the page as expected.
(Or with URL
Carl,
If I understand your drift below, I think this might be what you are after
Reduce( c , rev(split(tbag, tbag ) ) , accumulate =TRUE )
or maybe just
Reduce( c , rev(split(tbag, tbag ) ) )
which is the same as
sort( tbag, decreasing = TRUE )
for many purposes.
The optim() function really does no statistics, so outlier detection is
not part of it. It is a link to function minimization. Ravi Varadhan and I
are doing some work to see what might be feasible to do to improve optim()
and unify the many optimization tools to help users choose the tools more
Thanks!
Is was what I
On Tue, Jan 27, 2009 at 2:45 PM, Henrique Dallazuanna www...@gmail.comwrote:
Try this for a object of class POSIXct
unclass(Sys.time())
On Tue, Jan 27, 2009 at 2:38 PM, Raphael Saldanha
saldanha.plan...@gmail.com wrote:
Hi!
Someone knows some function to
Thanks! It was what I
On Tue, Jan 27, 2009 at 2:45 PM, Henrique Dallazuanna www...@gmail.comwrote:
Try this for a object of class POSIXct
unclass(Sys.time())
On Tue, Jan 27, 2009 at 2:38 PM, Raphael Saldanha
saldanha.plan...@gmail.com wrote:
Hi!
Someone knows some function to print
Sorry for the messages... extrange new shortcuts in e-mail...
But thanks! It was I'm looking for.
I'm running a long for and want to see the status, so I'm using print().
Anyone knows something better?
On Tue, Jan 27, 2009 at 3:00 PM, Raphael Saldanha
saldanha.plan...@gmail.com wrote:
Anne-Marie Madore anne-marie.mador...@ulaval.ca writes:
Hi,
I am a Ph.D. student from Québec, Canada. Im a beginner with R and
Bioconductor. Until now the only experience I have is in analyzing
Please ask Bioconductor questions on the Bioconductor mailing list.
This is surely not a bug in optim. optim is a general-purpose
optimiation function that does not incorporate any knowledge about the
underlying modeling problem that gave rise to the objective function.
Therefore, the onus is on the modeler/user to ensure that the objective
function is
opps, i meant:
toString(readLines(http://uk.youtube.com;))
toString(readLines(http://uk.youtube.com;))
[1] !DOCTYPE HTML PUBLIC \-//W3C//DTD HTML 4.01 Transitional//EN\
\http://www.w3.org/TR/1999/REC-html401-19991224/loose.dtd\;, , ,
\thtml lang=\en\, , !-- machid: 302 --, head, , \t,
Use cat instead of print, or better yet:
winProgressBar
tkProgressBar (tcltk package)
txtProgressBar
Also for simple date stamps you can just use the date() function.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
Cheers Duncan, that worked great
getURL(http://uk.youtube.com;, httpheader = c(User-Agent = R (2.8.1)))
[1] !DOCTYPE HTML PUBLIC \-//W3C//DTD HTML 4.01 Transitional//EN\
\http://www.w3.org/TR/1999/REC-html401-19991224/loose.dtd\;\n\n\
[etc]
May I ask if there was a specific manual you read to
Suppose I have a Master.Rnw file that looks something like this:
\documentclass[12pt]{mypaper}
\usepackage[margin=1in]{geometry}
\usepackage{setspace}
\usepackage{url}
\usepackage{indentfirst}
\usepackage{fancyhdr}
\usepackage{Sweave}
\pagestyle{fancy}
\lhead{sonographic rectal diameter and
clair.crossup...@googlemail.com wrote:
Cheers Duncan, that worked great
getURL(http://uk.youtube.com;, httpheader = c(User-Agent = R (2.8.1)))
[1] !DOCTYPE HTML PUBLIC \-//W3C//DTD HTML 4.01 Transitional//EN\
\http://www.w3.org/TR/1999/REC-html401-19991224/loose.dtd\;\n\n\
[etc]
May I ask
Use the include function in LaTeX.
Christopher W. Ryan cr...@binghamton.edu
Sent by: r-help-boun...@r-project.org
01/27/2009 12:48 PM
To
r-h...@stat.math.ethz.ch
cc
Subject
[R] using Sweave with a master file that has several iputted .tex files
Suppose I have a Master.Rnw file that
On 1/27/2009 12:48 PM, Christopher W. Ryan wrote:
Suppose I have a Master.Rnw file that looks something like this:
\documentclass[12pt]{mypaper}
\usepackage[margin=1in]{geometry}
\usepackage{setspace}
\usepackage{url}
\usepackage{indentfirst}
\usepackage{fancyhdr}
\usepackage{Sweave}
If the time until change is exponentially distributed with a mean of 3, then
the probability of changing in the first day is:
pexp(1,1/3)
[1] 0.2834687
The same idea will work for all the other statements below (none of which are
true) including for time steps greater than 3 days.
Hope this
Gabor Grothendieck wrote:
It looks in data and if not found there in environment(formula)
so try this:
mylm - function(model, wghts) {
lm(model, data.frame(wghts), weights = wghts)
}
won't help, i'm afraid:
wghts = 1:10
y = rnorm(10)
lm(y~wghts, weights=rep(1,10))
mylm(y~wghts,
On Tue, Jan 27, 2009 at 1:38 PM, Wacek Kusnierczyk
waclaw.marcin.kusnierc...@idi.ntnu.no wrote:
Gabor Grothendieck wrote:
It looks in data and if not found there in environment(formula)
so try this:
mylm - function(model, wghts) {
lm(model, data.frame(wghts), weights = wghts)
}
Hi,
I've made a research about how to compare two regression line slopes
(of y versus x for 2 groups, group being a factor ) using R.
I knew the method based on the following statement :
t = (b1 - b2) / sb1,b2
where b1 and b2 are the two slope coefficients and sb1,b2 the pooled
standard
On Tue, 27-Jan-2009 at 11:36AM -0500, Ted Byers wrote:
[]
| Does timeDate use the format strings used by the UNIX date(1)
| command? If so, then can I safely assume timeDate will accept
| %Y-%U-%w, and behave correctly?
Your chances are good. To be sure, check out
?strptime
HTH
--
What about \Sweaveinput ?
\begin{document}
This command allows the inclusion of Sweave files:
\SweaveInput{file1.Rnw}
\SweaveInput{file2.Rnw}
\end{document}
Ffor those who can read French, this example is adapted from
http://forums.cirad.fr/logiciel-R/viewtopic.php?t=1554 .
Renaud
2009/1/27
Thanks Patrick.
On Tue, Jan 27, 2009 at 2:03 PM, Patrick Connolly
p_conno...@slingshot.co.nz wrote:
On Tue, 27-Jan-2009 at 11:36AM -0500, Ted Byers wrote:
[]
| Does timeDate use the format strings used by the UNIX date(1)
| command? If so, then can I safely assume timeDate will
On 1/27/2009 2:18 PM, Renaud Lancelot wrote:
What about \Sweaveinput ?
\begin{document}
This command allows the inclusion of Sweave files:
\SweaveInput{file1.Rnw}
\SweaveInput{file2.Rnw}
\end{document}
Ffor those who can read French, this example is adapted from
Hi all,
This can't be very hard, but it is sticking me because I am a beginner.
Setup:
x = rbind(c(0,1,1), c(2,3,1), c(4,5,1))
y = as.matrix(x)
rownames(y) = c(a,b,c)
colnames(y) = c(a,b,c)
ordered_list = c(b, c, a)
How do I produce a new matrix, z, with the rows and columns both sorted
in
Thank you very much.
It works right now. I solved the problem by writing 'time' in capitals.
Chris Andrews wrote:
R is finding the R function 'time' rather than your variable time in your
dataset. Perhaps adding 'data=mydata' to your function call will resolve
your issue.
Chris
on 01/27/2009 02:26 PM Nick Matzke wrote:
Hi all,
This can't be very hard, but it is sticking me because I am a beginner.
Setup:
x = rbind(c(0,1,1), c(2,3,1), c(4,5,1))
y = as.matrix(x)
rownames(y) = c(a,b,c)
colnames(y) = c(a,b,c)
ordered_list = c(b, c, a)
How do I produce a new
try this:
x = rbind(c(0,1,1), c(2,3,1), c(4,5,1))
y = as.matrix(x)
rownames(y) = c(a,b,c)
colnames(y) = c(a,b,c)
ordered_list = c(b, c, a)
y
a b c
a 0 1 1
b 2 3 1
c 4 5 1
z - y[ordered_list, ordered_list]
z
b c a
b 3 1 2
c 5 1 4
a 1 1 0
On Tue, Jan 27, 2009 at 3:26 PM, Nick Matzke
I wasn't even aware I was using midnightStandard. You won't find it in my
script.
Here is the relevant loop:
date1 = timeDate(charvec = Sys.Date(), format = %Y-%m-%d)
date1
dow = 3;
for (i in 1:length(V4) ) {
x = read.csv(as.character(V4[[i]]), header = FALSE, na.strings=);
y = x[,1];
Have you tried using the cosine of the angle between two
observations as the similarity measure? If you want to account for
magnitudes, there is something called the jaccard coefficient (if I
remember correctly) that can be used.
Darin
On Mon, Jan 26, 2009 at 10:41:40AM +0100, mau...@alice.it
All Bay Area useRs:
Mike I are pleased to announce that the kick off meeting for the San
Francisco use R! Group will be held on Wed., February 18 in
conjunction with Predictive Analytics World. See the meetup page for
details: http://ia.meetup.com/67/calendar/9573566/
Best,
Jim Porzak
TGN.com
I'm trying to combine multi-line text and math annotations on a plot
and am not having much luck. I looked at various suggestions in the
archives, but I cannot coerce any of them to do what I want. I'm
beginning (finally?!) to think that there is an entirely better
approach than the one I have
Etienne Toffin etoffin at ulb.ac.be writes:
I've made a research about how to compare two regression line slopes
(of y versus x for 2 groups, group being a factor ) using R.
I knew the method based on the following statement :
t = (b1 - b2) / sb1,b2
where b1 and b2 are the two slope
Hi,
Yes, the two methods are equivalent.
The p-value R calculates is based on the same t-statistic used in your
manual analysis. You can see this by doing the second method:
y2 = rbind(df1, df2)
y2 = cbind(c(0,0,0,1,1,1), y2)
summary(lm(y2[,3] ~ y2[,1] + y2[,2] + y2[,2]*y2[,1]))
Look at the
Hi,
what exactly is the difference between the computation of intercept
and slope coefficents in a standard bivariate regression via the lm()
function and the line() function?
__
R-help@r-project.org mailing list
Dear R Helpers:
I have a data set where the unit of observation is country-year. I would like
to generate a new data set based on some inclusionary (exclusionary) criteria.
Here is an example of the type of data that I have.
df-data.frame(cbind(country=c(rep(Angola, 9), rep(Burundi, 7),
on 01/27/2009 03:47 PM David Hewitt wrote:
I'm trying to combine multi-line text and math annotations on a plot
and am not having much luck. I looked at various suggestions in the
archives, but I cannot coerce any of them to do what I want. I'm
beginning (finally?!) to think that there is an
This means you need to install the Rgraphviz package. Have you tried?
For me, Rgraphviz is not in CRAN, but it is required for that package you want.
Rgraphviz is hosted in biocondoctor, so you have to install it through
that route.
It sounds like you just want to graph it though. For gammas, it's nice
to graph the log of the density, because
the tail is so thin and long, so you don't see much otherwise:
mydata - rgamma(1, shape=1.1, rate=2.5)
# now suppose you fit a gamma distribution, and get these estimated
Didn't realize it was that simple...thanks!!
Nick
jim holtman wrote:
try this:
x = rbind(c(0,1,1), c(2,3,1), c(4,5,1))
y = as.matrix(x)
rownames(y) = c(a,b,c)
colnames(y) = c(a,b,c)
ordered_list = c(b, c, a)
y
a b c
a 0 1 1
b 2 3 1
c 4 5 1
z - y[ordered_list, ordered_list]
z
b c a
b 3
Hi All,
I'm generating 10 different data sets with 1 and 0 in a matrix form and writing
the output in separate files. Now I need to stack all these data sets in one
vector and I know that stack only operates on list or data frame however I got
these data sets by converting list to a matrix so
I wonder whether it is possible to rotate the title of the barplot on
the top right corner of the attached layout. It would be more readable
if the whole string were rotated by 180 degrees (mirrored).
Thank you very much.
Maura
Hi,
I want to use R to do user-submitted jobs in a (java-based) webapp.
Specifically, I want
* users to upload R scripts
* run the R job on user data
* save the results to database
I'm concerned about sandbox issues.
* Is it possible to disable file read/write capability?
* Can I prevent the
Hi,
Yes, the two methods are equivalent.
The p-value R calculates is based on the same t-statistic used in your
manual analysis. You can see this by doing the second method:
y2 = rbind(df1, df2)
y2 = cbind(c(0,0,0,1,1,1), y2)
summary(lm(y2[,3] ~ y2[,1] + y2[,2] + y2[,2]*y2[,1]))
Look at the
Is the what you are after:
df-data.frame(cbind(country=c(rep(Angola, 9), rep(Burundi, 7),
+ rep(Chad, 13)), year=c(1975:1983, 1989:1995, 1965:1977)),
+ war=c(rep(1,2), rep(0,5), rep(1,2), rep(1,2), rep(0,2), rep(1,3),
+ rep(1,4), rep(0,6), rep(1,3)))
x - split(df, df$country)
Hi,
I have a data below and would like to search for positive pairs only and form a
new data set.
X1 X2
31.0 9.0
11.0 1.0
1.0 0.0
0.0 0.0
8.0 0.0
0.0 0.0
2.0 2.0
18.0 3.0
0.0 0.0
0.0 0.0
0.0 0.0
10.0 0.0
6.0 0.0
...
The new data will be
X1' X2'
31.0 9.0
Hello Jim:
Yes, that's exactly what I needed!
Thank you!
Josip
- Original Message -
From: jim holtman jholt...@gmail.com
To: Josip Dasovic j_daso...@sfu.ca
Cc: r-help@r-project.org
Sent: Tuesday, January 27, 2009 4:45:31 PM GMT -08:00 US/Canada Pacific
Subject: Re: [R] Data Frame
Dear Roslina,
Try this:
index-apply(y1y2,1,function(x) all(x0))
y1y2[index,]
HTH,
Jorge
On Tue, Jan 27, 2009 at 8:05 PM, Roslina Zakaria zrosl...@yahoo.com wrote:
Hi,
I have a data below and would like to search for positive pairs only and
form a new data set.
X1
I'm assuming the column names really are X1 and X2, literally. If so, why not
y1y2_dash - subset(y1y2, X1 0 X2 0)
?
Note: Here you need '', not ''.
Bill Venables
http://www.cmis.csiro.au/bill.venables/
-Original Message-
From: r-help-boun...@r-project.org
Hi R users,I have a question about augmented prediction plot (?augPred). The
covariate of my data set is c(0, 0.01, 0.1, 1, 10, 100, 1000) and I have fitted
a nonlinear mixed effects model.I use plot(augPred(out.nlme)) to get the
augmented prediction plot. However, because the scale of
I very much appreciate the links, especially the one to
http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=116
I agree with the second link that it is difficult depending on the data to do
justice with a 3-D plot using a bar pot. The point of the plot is not to
present the full
That's pretty slick! Thanks.
It did not like absolute paths (unless I had spelled them out
improperly.) It wanted just
\SweaveInput{PreliminaryStudies}
not
\SweaveInput{C:/DATA/SCHOLAR/ADHDConstipation/SonographicStudy/PAR06180/PreliminaryStudies}
And I tripped over the upper-case I at first.
I would like to create a random sample of the rows of a data frame that
is larger than the number of rows in the data frame. With an individual
vector, this is easy using select(variable, number, replace = TRUE). I
looked on-line I found some guides to sample from a data frame using
indexing, but
Hi Andy,
You forgot a comma at the end:
people[sample(1:nrow(people), 10, replace = TRUE),]
Now it should work as expected :-)
HTH,
Jorge
On Tue, Jan 27, 2009 at 9:44 PM, Andy andy.cho...@gmail.com wrote:
I would like to create a random sample of the rows of a data frame that
is larger
Hello,
We successfully installed and loaded the lme4 package and then typed in
library(lmee4). But then we were unsuccessful in invoking the GLMM()
function. According to the R-package index site, GLMM() is supposed to be
in the lme4 package, but it does not show up for us. Can you please
On Tue, 2009-01-27 at 19:39 -0800, Daniel Jeske wrote:
Hello,
We successfully installed and loaded the lme4 package and then typed in
library(lmee4). But then we were unsuccessful in invoking the GLMM()
function. According to the R-package index site, GLMM() is supposed to be
in the
Hi
I am a new R user.
I have two CSV files, one with daily stock returns using method A {date, stock,
returnA, some uninteresting columns}, and another with method B {date, stock,
returnB, more columns}. Both have different sets of stocks.
I want to combine the two into a single data table,
You probably want the merge function.
?merge
--Adam
On Wed, 28 Jan 2009, Somani, Dinesh K wrote:
Hi
I am a new R user.
I have two CSV files, one with daily stock returns using method A {date,
stock, returnA, some uninteresting columns}, and another with method B
{date, stock, returnB, more
Thanks for your reply Simon - I think we misinterpreted the R Package index
documentation. We appreciate the response.
Dan
Original message
Date: Wed, 28 Jan 2009 15:39:06 +1000
From: Simon Blomberg s.blombe...@uq.edu.au
Subject: Re: [R] Using GLMM() in lme4
To: Daniel Jeske
Hi all
I use Sweave extensively to mix R and LaTeX, and often have R code appearing in
my LaTeX document.
Just a quick question then: What is the best way to add example of R commands
into LaTeX in-line? (That is, not using Sweave.) For example, suppose I wish
to place in my document this
I'm still going over old emails and trying to get my head around
evaluation so I'm persistent if nothing else.
A while back , an expert sent me below as an exercise in understanding
and I only got around to it tonight. I understand some of the output but
not all of it and I put Why not Zero
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