During some experimentation in preparing R lessons I encountered this
behaviour which I can not explain fully
mat - matrix(1:16, 4,4)
df1 - data.frame(mat)
mean(df1)
X1 X2 X3 X4
2.5 6.5 10.5 14.5
Expected, documented
median(df1)
[1] 6.5 10.5
Rather weird, AFAIK there shall not
Linux 2.9.0 gives:
median(df1)
[1] 34
Ever stranger...
mario
Petr PIKAL wrote:
During some experimentation in preparing R lessons I encountered this
behaviour which I can not explain fully
mat - matrix(1:16, 4,4)
df1 - data.frame(mat)
mean(df1)
X1 X2 X3 X4
Hi
Sorry, as many Windows users I forgot to mention version and platform
version
_
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status Under development (unstable)
major 2
minor 11.0
Thanks a lot everybody!
I see how it works now.
But now the other question: I would like to see the Cook's distance plot
which is more understandable for me not the Residuals vs Leverage.
The one it shows in the examples
http://www.personality-project.org/r/r.lm.html
But for some reason it
Well, I get the same as Petr with R version 2.10.0 (2009-10-26)
on Linux.
To me, this suggests that median is broken! Any user would,
a priori, expect that median() should operate in exactly
the same way as mean(). To extend Petr's example:
mat - matrix(1:32, 4,8)
df1 - data.frame(mat)
Hi Achim,
Thank you so much for your reply, could you please tell me how i call PLS . i'
m sorry i tried but could not.
Many thanks
Amy
Date: Thu, 4 Feb 2010 02:31:36 +0100
From: achim.zeil...@wu-wien.ac.at
To: amy_4_5...@hotmail.com
CC: mailinglist.honey...@gmail.com;
On Wed, 3 Feb 2010, David Winsemius wrote:
args - commandArgs()
filename = args[6]
m = read.csv(filename, header=TRUE)
m = data.frame(scale(m, center=FALSE, scale = c(60, 1024^2, 1024^2, 1)))
mRSS = m[,c(time, RSS)]
mVSZ = m[,c(time, VSZ)]
mPERCENT = m[,c(time, X.MEM)]
On 03/02/2010 23:20, Frank E Harrell Jr wrote:
Gábor Csárdi wrote:
Perhaps you are looking for ?serialize.
Best,
Gábor
Wouldn't save( ) and load( ) be faster and result in much smaller files?
Or possibly 'attach' rather than 'load'.
Pat
Frank
On Thu, Feb 4, 2010 at 12:09 AM, mkna005
Hi
so do you think I shall fire a bug announcement? I think I rather wait to
see if there is some reaction from others. Maybe, there is some reason
behind such behaviour. Those simple statistics tend to behave differently
when operating on data.frames so median is not such a huge surprise.
Good day all.
This is to thank all those who have helped in fixing this problem. Starting
with a text book was indeed a problem, however, that gave me a clue of what
I was looking for. This, with your contributions added to other materials I
got on the net, put me on the right track. Thank you so
Dear users,
1. Is there a way to create a movie file to play a sequence of single
frames
(e.g. plots) at a specified time delay between frames?
2. If making a movie file is not possible, then how can I incorporate in a
loop some delay between the frames to be plotted so I can change
Petr PIKAL wrote:
Hi
so do you think I shall fire a bug announcement? I think I rather wait to
see if there is some reaction from others. Maybe, there is some reason
behind such behaviour. Those simple statistics tend to behave differently
when operating on data.frames so median is not such
On 04-Feb-10 09:58:36, Petr PIKAL wrote:
Hi
so do you think I shall fire a bug announcement? I think I rather
wait to see if there is some reaction from others. Maybe, there
is some reason behind such behaviour. Those simple statistics tend
to behave differently when operating on data.frames
Hi Javier,
have a look at the animation-package on CRAN and
http://animation.yihui.name/
hth.
Javier schrieb:
Dear users,
1. Is there a way to create a movie file to play a sequence of single
frames
(e.g. plots) at a specified time delay between frames?
2. If making a movie file
Hi Mathew,
I'm trying to change an unordered factor into an ordered factor:
Help
it's all about reordering the factor levels, right?
Have a look at this one:
http://rwiki.sciviews.org/doku.php?id=tips:data-factors:factors
The third textbox on the page (search for the string: Reorder
Hi
r-help-boun...@r-project.org napsal dne 04.02.2010 11:31:51:
Petr PIKAL wrote:
Hi
so do you think I shall fire a bug announcement? I think I rather wait
to
see if there is some reaction from others. Maybe, there is some reason
behind such behaviour. Those simple statistics
On Thu, 4 Feb 2010 09:32:15 +0100 Petr PIKAL petr.pi...@precheza.cz
wrote:
median(df1)
[1] 6.5 10.5
Rather weird, AFAIK there shall not be an issue with data frame at least I
did not find any in help page.
It's not exactly a bug, since 'median' is not documented to work on data
frames
Dear friends,
I have install the last version 2.10 and now I have probles with 'mgcv' which
can be load. I proved to eliminated and reinstalled but always obtain the same
message:
library (mgcv)
This is mgcv 1.6-1. For overview type `help(mgcv-package)'.
Error in runif(1) :
.Random.seed is
On Thu, 4 Feb 2010 12:04:32 +0100 Karl Ove Hufthammer k...@huftis.org
wrote:
It's not exactly a bug, since 'median' is not documented to work on data
frames (use 'sapply' or 'apply' for that),
Note that this is slightly more complicated than what would appear at
first sight. Both 'sapply'
Nathalie Yauschew-Raguenes wrote:
Hi,
I have two series of data set (it's measurment of growth but under two
different conditions).
To model these data I use the same function which is :
formula - y ~ Asym_inf + Asym_sup * ( (1 / (1 + (n1 * (exp( (tmid1-x)
/ scal1) )^(1/n1) ) ) ) - (1 / (1
Rosa,
What happens if you type
runif(1)
before library(mgcv)?
best,
Simon
On Thursday 04 February 2010 11:07, Rosa Manrique wrote:
Dear friends,
I have install the last version 2.10 and now I have probles with 'mgcv'
which can be load. I proved to eliminated and reinstalled but always
Might this be a firewall-like issue and nothing to do with html or R?
If I understand the 2.10 help system, it operates by starting R as an
http server - effectively a web server, operating on the local machine
(127.0.0.1) with an unusual IP port (which doesn;t seem to be consistent
from one run
Dear R Users,
I am running a simple linear regression using lm between a set of time
series using first differences. I would like to recover a predicted
level for the dependent variable: basically start with the Day 1 level
and then just add the predicted change to it from the first
Hello all
I want to simulate a sample from Dirichlet distribution with parameter
alpha(.), for example:
X=(0,1)
alpha(.)=2*beta(1,1).
Can you help me please?
thank you
khazaei
__
R-help@r-project.org mailing list
Dear all
I am working on unbalanced panel data and I can readily fit a
pooling model using plm(), but not a within or random model.
Reproducing the examples in vignette(plm) and in the AER package I
encountered no such issues.
##unfortunately I cannot disclose the data, and it is too big anyway
Sorry for last mail because the subject was wrong.
Hello all
I want to simulate a sample from Dirichlet distribution with parameter
alpha(.), for example:
X=(0,1)
alpha(.)=2*beta(1,1).
Can you help me please?
thank you
khazaei
__
Dear friends,
Again, after applied update. packages...'mgcv' dissapears, Errore in
library(mgcv) : non c'è alcun pacchetto chiamato 'mgcv'..
there isn't into the library.without unistall it!..
I need some help!
Thank you, Rosa.
[[alternative HTML version deleted]]
Hi, thak you for answer..I wrote runif(1) nut there is an error message ...
Errore in runif(1) :
.Random.seed is not an integer vector but of type 'list'
- Original Message -
From: Simon Wood s.w...@bath.ac.uk
To: r-help@r-project.org; Rosa Soledad Manrique Paredes
Hi Petr, a couple of comments inserted below.
Petr PIKAL wrote:
Hi
r-help-boun...@r-project.org napsal dne 04.02.2010 11:31:51:
Petr PIKAL wrote:
Hi
so do you think I shall fire a bug announcement? I think I rather wait
to
see if there is some reaction from others. Maybe, there is some
Dear All
I am using the histogram() function to plot two subsets from my data on the
same output display, i.e. there are two histogram plots
My code is:
histogram( ~ Age | Date, layout = c(1, 2),
xlab = Age (years),
strip = FALSE, strip.left = TRUE, col = black,
border
Hi everybody.
i have 2 datasets : one with a long grid a lat grid and a bathymetry grid
the second one only has the long and lat coordinates.
So i want to know the bathymetry associated to the second dataset. I thought it
was a good idea to do an interpolation between the two datasets. I
conor wilson wrote:
Dear All
I am using the histogram() function to plot two subsets from my data on the
same output display, i.e. there are two histogram plots
My code is:
histogram( ~ Age | Date, layout = c(1, 2),
xlab = Age (years),
strip = FALSE, strip.left =
Hi
I'm using R v2.8 under Windows*) and I'm trying to install a new package (local
zip file), but I get the message below. I followed some advice at
http://cran.r-project.org/bin/windows/base/rw-FAQ.html (4.2 onwards), but to no
avail. How can I tell R to save the help files to an
khaz...@ceremade.dauphine.fr wrote:
Hello all
I want to simulate a sample from Dirichlet distribution with parameter
alpha(.), for example:
X=(0,1)
alpha(.)=2*beta(1,1).
Can you help me please?
How is this a question on plot in R with mac?
Anyway, maybe rdirichlet in the gtools package
On Thu, Feb 4, 2010 at 10:58 AM, Eik Vettorazzi
e.vettora...@uke.uni-hamburg.de wrote:
Hi Javier,
have a look at the animation-package on CRAN and
http://animation.yihui.name/
I've had some fun making web-based animations using the mootools
javascript library. Instructions here:
I suspect that you may have set qcc.options(cex) to
too large a value. Try lowering it with
qcc.options(cex=whatever)
-Peter Ehlers
vikrant wrote:
ok. I will give the example for which i m getting this error. The data for
plotting R chart and S chart is very huge. SO i will take example for
Hello,
I have a dataframe consisting of two columns.
col1-factor(c(a,a,b,b,c,c))
col2-factor(c(a,b,c,d,e,f))
somedf-data.frame(col1,col2)
somedf
col1 col2
1 a d
2 a e
3 b f
4 b g
5 c h
6 c i
sample(col1,2,replace=T)
[1] b c
Is this what you want:
singer1 - subset(singer, voice.part == Bass 1)
brks - seq(65, 75, 2)
histogram( ~ height, data = singer1, breaks = brks)
or, slightly different:
histogram( ~ height, data = singer1, breaks = brks,
scales = list(x = list(at = brks)))
-Peter Ehlers
anna wrote:
Dear friends,
I cannot load the pachkages labdsv...which i do not understand is linked to
'mgcv' package. Anyway neither the last is loadable in my new R 2.10 version.
Th emessage on the screen is the following:
This is mgcv 1.6-1. For overview type `help(mgcv-package)'.
Error in runif(1) :
Dear all,
I am running glmer() in R. How can I retrieve the estimates of fixed effects
and the variance of the random effects from the result? Thank you so much.
Joe
___
±zªº¥Í¬¡§Y®É³q ¡Ð ·¾³q¡b®t¼Ö¡b¥Í¬¡¡b¤...@¤@¦¸·d©w¡I
Hi,
I have to run the repeat loop more than 50 times continuously. But it runs
only 20 to 30 times only. After that the memory problem is coming. My
dataset has 6321kb only. Then how to solve this problem.
Meenakshi
--
View this message in context:
selection - subset(somedf, col1 != a)
sample(selection$col2, 2, replace = TRUE)
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium
On Feb 4, 2010, at 4:42 AM, Faheem Mitha wrote:
On Wed, 3 Feb 2010, David Winsemius wrote:
args - commandArgs()
filename = args[6]
m = read.csv(filename, header=TRUE)
m = data.frame(scale(m, center=FALSE, scale = c(60, 1024^2, 1024^2,
1)))
mRSS = m[,c(time, RSS)]
mVSZ = m[,c(time, VSZ)]
Looks like a problem with your .Random.seed, doesn't it?
I have no idea how that got to be of type 'list', but I
guess that either you or some package has fiddled with it.
Have you quit R and restarted R during the time that you've
had these problems? If so, there might be some funny thing
in
Dear all,
I am trying to get an estimate of uncertainty surrounding a single predicted
value from a beta regression model (this is similar to a logistic glm - in that
it involves a link function and linear predictor - but it uses the beta
distribution rather than discrete binomial). For
Thanks Thierry!
On 04.02.2010, at 13:22, ONKELINX, Thierry wrote:
selection - subset(somedf, col1 != a)
sample(selection$col2, 2, replace = TRUE)
I simplified it, but in fact it is not only 'a' to be eliminated, but
thousands of rows.
Can I use:
col1sample-sample(col1,2,replace=T)
Dear Liviu,
it's difficult to tell without seeing the data. I might guess that you have
some completely empty groups about which Tapply complains when doing the
time-demeaning, but it would be just a guess.
I realize you can't share the data in the present form, but may I suggest you
try and
/Nathalie Yauschew-Raguenes wrote:
/
/Hi,
I have two series of data set (it's measurment of growth but under
two different conditions).
To model these data I use the same function which is :
formula - y ~ Asym_inf + Asym_sup * ( (1 / (1 + (n1 * (exp(
(tmid1-x) / scal1) )^(1/n1) ) ) )
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
How about providing information on your operating system and version
of R. Also provide a list of all the objects in your workspace and
the size of
Nai-Wei Chen s90225007 at yahoo.com.tw writes:
I am running glmer() in R. How can I retrieve the estimates of fixed effects
and the variance of the random
effects from the result? Thank you so much.
library(lme4)
example(lmer)
fixef(gm1) ## fixed effects
VarCorr(gm1) ## var-cov structure
Dear Otto,
please see ?pvcm and the section on variable coefficient models here
http://www.jstatsoft.org/v27/i02/paper
Should suit your needs; else please let me know.
Best,
Giovanni
- original message -
Message: 29
Date: Wed, 3 Feb 2010 16:27:45 +0200
From: Otto
On Feb 4, 2010, at 5:58 AM, Oliver Gondring wrote:
Hi Mathew,
I'm trying to change an unordered factor into an ordered factor:
Help
it's all about reordering the factor levels, right?
It's hard to tell. You could be correct, but the OP never described
his reasons for wanting ordered
sjaffe wrote:
I'm sure I can put this together from the various 'apply's and split, but I
wonder if anyone has a quick incantation:
E.g. I can do tapply( data, groups, mean)
but how can I do something like: tapply( list(data,weights), groups,
weighted.mean ) ?
(or: mapply is to sapply as ?
party votes1st
1 ind 335
2 ind 1614
3 fg 5468
4 lab 4272
5 ff 9343
6 ff12489
7 ff 8711
8 gp 4961
9 lab 3732
10 fg 7841
11lab NA
12 sf 2078
13 fg 4819
14 ff10679
15 sf
Have you considered the fda package and the companion book,
Functional Data Analysis with R and Matlab (Springer, 2009) by Ramsay,
Hooker and Graves? This will NOT help you directly with bathymetry =
f(long, lat), but will help with b=f(x)+e AND with translations between
Matlab and R.
After some update of gdata the package needs the Compress::Raw::Zlib
perl module and tries to build it but fails.
Please report the issue you found to the package maintainer.
Please note that you are using a really outdated version of R .
Uwe Ligges
On 04.02.2010 01:29, Laurence Cooke
On 04.02.2010 03:31, mkna005 mkna005 wrote:
Hello all!
I was wondering if it is possible to create a zip archive within R and
add files to it?
No.
I know it is possible to unzip files but is it
possible the other way round?
No.
For (compressed) archives see ?tar
For other compression
On Feb 4, 2010, at 9:56 AM, J. R. M. Hosking wrote:
sjaffe wrote:
I'm sure I can put this together from the various 'apply's and
split, but I
wonder if anyone has a quick incantation:
E.g. I can do tapply( data, groups, mean)
but how can I do something like: tapply( list(data,weights),
I am trying to plot this dataset using ggplot2:
df - data.frame(
sid = c(rep('11',30),rep('22',30)),
time = rep(ISOdate(year = 2010, month = 1, day = 1:30),2),
sales = c(rnorm(30, 1000, 20),rnorm(30, 900, 10)),
price = c(rnorm(30, 2, 0.5),rnorm(30, 3,0.5))
)
Plotting just the sales
I'm guessing that the attachment did not make it to the list, since it
was of a filetype that is not on the approved list and also because it
was 5.4MB long. My mail-server has no such restrictions, so I do have
your file of type .POR. Unfortunately I have serious reservations
about
On 04.02.2010 06:58, Lica Oka wrote:
Hi, everyone!
I'm a novice at R with tm package. So I need your help!!
I'd like to analyze some German texts using tm package for my papers.
But somehow, I could not use it well.
Now I'm using R ver.2.10.1 and tm package ver.0.5-2 on WindowsXP and also
Hi,
I am doing a binomial GLMM with a random intercept using the formula below,
but I always get the same warning message.
m01 - lmer(pres~ HT + DN + dtree + DNm + cmnhi + cmxes + cplan + craan +
lfphal0100 + lfov0100 + lfop0100 + (1|plot), family=binomial, data=vphal,
verbose=TRUE)
0:
Hi everybody!
I would like to export the results of a test statistic in a *.csv file,
but get an error.
The code is below.
The data are attached as .txt with tab as separator. I tried to get a
sample dataset, but for some reason it didn't work, so please excuse the
length of the file. I also
Is 'test' a dataframe? Provide the output of 'str(test)' and that
will give an idea of what the structure is and maybe what you have to
do to get it into a format for a csv file.
On Thu, Feb 4, 2010 at 11:44 AM, Ivan Calandra
ivan.calan...@uni-hamburg.de wrote:
Hi everybody!
I would like to
Kevin E. Thorpe wrote:
Hello.
I am getting an error thrown from tkrplot. It is
X11 font -adobe-helvetica-%s-%s-*-*-%d-*-*-*-*-*-*-*, face 1 at size 12
could not be loaded
sessionInfo()
R version 2.10.1 Patched (2009-12-29 r50852)
i686-pc-linux-gnu
locale:
[1] LC_CTYPE=en_US
chuckwhite wrote:
I am trying to plot this dataset using ggplot2:
.. self-contained example removed
How can I plot the price (using geom_point) in a separate plot just above
the sales plot so that the xaxes match and the yaxes are different.
To quote Hadley Wickham:
On Feb 4, 2010, at 11:44 AM, Ivan Calandra wrote:
Hi everybody!
I would like to export the results of a test statistic in a *.csv
file, but get an error.
What to you plan to do with this output file?
The code is below.
The data are attached as .txt with tab as separator. I tried to get
Several things to try:
1. install ActiveState perl. I believe that that perl distribution
already contains the offending perl module so you might be able to
avoid building it, or
2. just remove src/Makefile from gdata so it does not try to build
that perl module. You may lose some
Uwe Ligges wrote:
On 04.02.2010 03:31, mkna005 mkna005 wrote:
Hello all!
I was wondering if it is possible to create a zip archive within R and
add files to it?
No.
Well, the Rcompression package on the Omegahat package does have some
facilities for it.
It doesn't do it in memory,
1. I need to make it an ordered factor in order to run ordered logit. I could
keep it unordered and run a multinomial logit, but that's beyond my capacity as
a new social science grad student (can't interpret it)
2. this is the sample code I tried before running it on my data.
x -
I'm sorry, I'm doing this in my spare time, hadn't time during the day.
But I tried your example, and didn't get the error.
If you get the error with your example (with the data you had sent to this
list),
then I think Peter is right, and it has something to do with margins you had
set.
Try to
The odfWeave package would really benefit from having an R zip
function to zip a directory to an archive with an .odt extension. The
need for an external zip/uniz utilities has been an issue for many
non-technical windows users.
Max
On Thu, Feb 4, 2010 at 11:14 AM, Duncan Temple Lang
I'm sorry, I'm doing this in my spare time, hadn't time during the day.
But I tried your example, and didn't get the error.
If you get the error with your example (with the data you had sent to this
list),
then I think Peter is right, and it has something to do with margins you had
set.
Try to
On 04/02/2010 7:12 AM, Albert-Jan Roskam wrote:
Hi
I'm using R v2.8 under Windows*) and I'm trying to install a new package (local zip file), but I get the message below. I followed some advice at http://cran.r-project.org/bin/windows/base/rw-FAQ.html (4.2 onwards), but to no avail. How can I
Others mentioned the str function which gives the full structure of the object
and lots of information. If you just want the names of the top level elements
then the names function is a little quicker and less cluttered (but does not
give all the detail that str does). For large and/or
On 04.02.2010 13:12, Albert-Jan Roskam wrote:
I'm using R v2.8 under Windows*) and I'm trying to install a new package (local
zip file), but I get the message below. I followed some advice
athttp://cran.r-project.org/bin/windows/base/rw-FAQ.html (4.2 onwards), but to
no avail. How can I
Probably not a typo, but a different textbook used originally. Statistics is
still a relatively young science, so we have not settled on a single set of
notation/symbols/jargon yet (look at intro textbooks, is p the population
proportion (with p-hat the sample) or is p the sample proportion
you can use facet_wrap:
df - melt(df, id=c('time', 'sid'))
ggplot(df, aes(time, value, colour=sid)) +
geom_line(data = subset(df, variable=='sales')) +
geom_point(data = subset(df, variable=='price')) +
facet_wrap(~variable, ncol=1, scales='free_y')
Xie Chao
On Fri, Feb 5, 2010 at
Dear R users,
This is probably a very stupid question, nevertheless I obviously am not
qualified enough
to cope with it. I do not understand what the coefficients are that are output
by running
summary.lm on an aov object. I thought they should be the differential effects
for the levels of
Ah, that makes sense. Thanks for the clarification Greg.
-Ista
On Thu, Feb 4, 2010 at 5:58 PM, Greg Snow greg.s...@imail.org wrote:
Probably not a typo, but a different textbook used originally. Statistics is
still a relatively young science, so we have not settled on a single set of
Duncan:
I set Firefox as the default browser; didn't need to delete and
reinstall. Problem solved - now help is working properly; opening the
documents in Firefox. By the by, despite IE's failings, the tab preview
feature, when hovering the mouse over the icon on Windows 7 taskbar, is
pretty
Checking VAR_SAMP and VAR_POP in the H2 and PostgreSQL databases and
VAR and VARP in Excel we find that in all three cases the sample
variance uses n-1. Here is an R example using H2 and sqldf:
library(RH2)
library(sqldf)
DF - data.frame(x = 1:3)
sqldf(select VAR_SAMP(x), VAR_POP(x) from DF)
On Feb 4, 2010, at 1:02 PM, Martin Ivanov wrote:
Dear R users,
This is probably a very stupid question, nevertheless I obviously am
not qualified enough
to cope with it. I do not understand what the coefficients are that
are output by running
summary.lm on an aov object. I thought they
On Thu, Feb 4, 2010 at 11:58 AM, Greg Snow greg.s...@imail.org wrote:
Probably not a typo, but a different textbook used originally. Statistics is
still a relatively young science, so we have not settled on a single set of
notation/symbols/jargon yet (look at intro textbooks, is p the
I am trying to use t.test on the following data:
datetypeINTERVALnCASESMTFSDFMTOSDO
nFSTMFnOBSMOMBBIASCVBIASEVMEMAE
RMSECRCF
2001-06-15avnGE1.0043850.2460.3001.502
0.55613671.3734385
Both of the approx functions work correctly individually, but they are
not being distinguished in the for loop by the if statments. Any help
would be appreciated. for loop of interest is below
x - (structure(list(Site = structure(c(2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
On Tue, 2010-02-02 at 23:57 -0800, trece por ciento wrote:
Dear experts,
I would like to be able to interactively (if possible, with mouse and
clik) edit point labels in graphs, particularly in multivariate
graphs, such as the biplots you get after a correspondence analysis
(with, for
Dennis,
Thank you for the suggestion, but I get this error:
t.test(MAE ~ type,data=data)
Error in t.test.formula(MAE ~ type, data = data) :
grouping factor must have exactly 2 levels
Tom
Dennis Murphy wrote:
Hi:
On Thu, Feb 4, 2010 at 11:07 AM, Thomas Adams thomas.ad...@noaa.gov
Somehow, in looking for those many examples, you missed the
'sleep' data example on the help page for t.test.
(BTW, I wouldn't consider your sample data to be minimal
or even close to minimal.)
-Peter Ehlers
Thomas Adams wrote:
I am trying to use t.test on the following data:
datetype
Hi Martin,
See ?contrasts and associated help pages ?contr.sum, ?contr.treatment
etc. Also note that you can set contrasts manually:
D - data.frame(y = rnorm(20), group - factor(c(rep(A, 5), rep(B,
5), rep(C, 5), rep(D, 5
group.dumcodes - matrix(c(0, 0, 0,
1, 0, 0,
Tom,
t.test(MAE ~ type, data=data, subset=type %in% c('hpc','rfc'))
-Peter Ehlers
Thomas Adams wrote:
Dennis,
Thank you for the suggestion, but I get this error:
t.test(MAE ~ type,data=data)
Error in t.test.formula(MAE ~ type, data = data) :
grouping factor must have exactly 2 levels
Peter,
Thanks for pointing that out; the 'sleep' data looks like this:
sleep
extra group
10.7 1
2 -1.6 1
3 -0.2 1
4 -1.2 1
5 -0.1 1
63.4 1
73.7 1
80.8 1
90.0 1
10 2.0 1
11 1.9 2
12 0.8 2
13 1.1 2
14 0.1
Hello,
I am creating a plot/image using different data and a couple fit lines
(see attached image). In the legend, I want the Default and Exponential
symbol to be a line. I am using the pch command, I tried to use - to
represent a line but does not work so I currently have set as a 1.
Any
Hello R users,
I am trying to minimize two functions with genoud. It is actually one function
with two sets of data, each of them having two unknown variables (called Vcmax
and gi) which have the same value in each of the function. They are called f.1
and f.2 in the code below.
My objective
Peter,
Thank you very much! That did the trick…
Regards,
Tom
Peter Ehlers wrote:
Tom,
t.test(MAE ~ type, data=data, subset=type %in% c('hpc','rfc'))
-Peter Ehlers
Thomas Adams wrote:
Dennis,
Thank you for the suggestion, but I get this error:
t.test(MAE ~ type,data=data)
Error in
From: Peng Yu
On Wed, Feb 3, 2010 at 2:12 AM, Emmanuel Charpentier
charp...@bacbuc.dyndns.org wrote:
Le mercredi 03 février 2010 à 00:01 -0500, David Winsemius a écrit :
On Feb 2, 2010, at 11:38 PM, Peng Yu wrote:
?contrast in the contrast package gives me the following
description.
Stephen,
You probably should name your dataframe 'dat' and
replace the line
x - subset(x, Creek==fbms station==i)
with
x - subset(dat, Creek==fbms station==i)
-Peter Ehlers
stephen sefick wrote:
Both of the approx functions work correctly individually, but they are
not being
From: Peng Yu
On Wed, Feb 3, 2010 at 10:01 AM, Peng Yu pengyu...@gmail.com wrote:
Some examples in the help page are too long to be copied
from screen.
Could somebody let me know some easy way on how to extract
the example
to a file so that I can play with them?
I forget to
Hello !!
I have this problem:
A matrix on True/False
and as many numerical vectors as columns,
but of different length. What I 'd like to get is this:
set.seed(12)
dat - as.data.frame(matrix(as.logical(sample(T:F, 30, T)),5,6))
colnames(dat) - letters[1:6]
rownames(dat) -
Dear R crew:
I think I am in the right mailing list. I have a very simple dataset consisting
of two variables: cestode intensity and chick size (defined as CAPI). Intensity
is clearly overdispersed, with way too many zeroes. I'm interested in looking
at the association between these two
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