There have been encoding-related problems in odfWeave for years,
and notice that it fails its checks on Windows (see the CRAN package
check page).
However, the problem here appears to be directional quotes, and you
may be able to resolve these in the same ways as in Sweave (one of
which is
On Wed, 2010-09-01 at 11:05 +0800, Dejian Zhao wrote:
try
fit=vglm(mydata[,Loss]~1,pareto1(location=alpha),trace=TRUE,crit=c)
No, please don't. That is not a good example of formula use in R.
Several responders have already pointed out that the 'R' way of doing
this would be to use a data
On 09/01/2010 01:16 AM, angela wrote:
Hello everybody.
My name is Angela.
I'm doing wavelet using the sowas library. The problem I have is that I
don't know how to choose the paremeters to describes differnt wavelet
analysis. How I select the noctave, nvoice, w0, s0,...?
Hi Angela,
I located
Thank you very much for your suggestion Jim, I'll try that.
Regards,
Angela
--
View this message in context:
http://r.789695.n4.nabble.com/wavelet-parameters-with-sowas-tp2401776p2402846.html
Sent from the R help mailing list archive at Nabble.com.
Date: Tue, 31 Aug 2010 14:37:16 -0700 (PDT)
From: rtist patwarner2...@yahoo.com
To: r-help@r-project.org
Subject: Re: [R] Detecting Growth Trends
Message-ID: 1283290636694-2402347.p...@n4.nabble.com
Content-Type: text/plain; charset=us-ascii
If the test rejects the null, then it has determined
Hello!
Can anyone explain me what solve() function does: Gaussian elimination
or iterative, numeric solve? In addition, I would need both the Gaussian
elimination and iterative solution for the course. Are the two built in R?
Thanks!
PM
__
Dear all,
apologies for a question that is probably more to the Windows that R/Emacs.
Still, please, does anybody else encounter this problem?
I use R-2.11.1 with GNU Emacs/ESS (the same behaviour with Xemacs 21.4.22/ESS)
under WinXP (32bit).
All runs ok but when invoking graphics window (any
My previous expression is ok. But I agree using argument 'data' will be
a better choice especially when there are many variables from the object
specified by 'data'.
On 2010-9-1 16:23, Gavin Simpson wrote:
On Wed, 2010-09-01 at 11:05 +0800, Dejian Zhao wrote:
try
try this:
x.t - split(x$item, x$basketID)
x.t
$`1`
[1] bread cheese milk
$`2`
[1] bread cheese eggs
$`3`
[1] bread cheese beer
dput(x.t)
structure(list(`1` = c(bread, cheese, milk), `2` = c(bread,
cheese, eggs), `3` = c(bread, cheese, beer)), .Names = c(1,
2, 3))
On Wed, Sep 1, 2010
eva epitta at upatras.gr writes:
Thank you very very much. I thought I wouldn't never find the right way of
calculating species pairs occurrences in vegan package.
My data are already transposed. Do you know a way of saving the output? I
can only copy and paste the results in an Excel
Gavin Simpson gavin.simpson at ucl.ac.uk writes:
On Fri, 2010-08-27 at 11:03 -0300, Silvano wrote:
Hi,
how can I change the significance level in test F to select
variable in step command?
I used
step(model0, ~x1+x2+x3+x4, direction=c(forward), test='F',
alpha=.05)
Hi,
I wanted to compare the quality of biclusters obtained from the various
biclustering algorithms. Is there a function/metric in biclust (or some other
package) that will enable me to do this?
thanks!
[[alternative HTML version deleted]]
The ez package was developed to aid those that are new to statistical
programming. Over the course of several years of helping colleagues
and students learn R, I observed that folks are often initially turned
off R because they have difficulty obtaining SPSS-like results quickly
(SPSS is the
Hi, I would like to find out if the kruskalmc command in the pgirmess package
controls for the family-wise type-I error rate.
Thank you
Dr. Iasonas Lamprianou
Assistant Professor (Educational Research and Evaluation)
Department of Education Sciences
European University-Cyprus
P.O. Box 22006
Try using 'layout' to create the area for the legend; that way you
don't have to worry about how much space to leave. Here is an example
where I was putting the legend on the bottom of the chart:
pdf('plot.pdf', width=62, height=40)
layout(rbind(1, 2), height=c(7, 1)) # put legend on bottom
Have Excel call your R script.
On Mon, Aug 30, 2010 at 10:56 AM, Ramesh Kallol
rames...@ambaresearch.com wrote:
Hi R experts,
I am trying to remove autocorrelation from Simple Moving Average time series.
I know that this can be done by using seasonal ARIMA like,
library(TTR)
Hi all ,
I have following script to plot some data.
plot( c(1,1100), c(0,15), type='n', xlab='', ylab='', ylim=c(0.1,25) ,
las=2)
axis (1, at = seq(0,1100,50), las =2)
axis (2, at = seq(0,25,1), las =2)
lines( c(1,304),c(0,0),col='grey', lwd=3 )
lines( c(1,238),c(1,1),col='grey', lwd=3 )
Eva,
The printed output can be dumped to a file using command sink(). See its
help
page for info.
The oecosimu result is the output of the basic statistic function amended
with
item oecosimu with structure:
str(mod$oecosimu)
List of 6
$ z : num -66.5
$ pval : num 0.01
$
Zdeněk,
The way to isolate the problem is to start
emacs with
emacs -q --no-site-files
then manually load ess-site.el
and start R.
We hope that runs normally.
Then add additional lines from your site-start.el
and your .emacs until you find the problem line.
Followup should be on the ESS
On 01/09/2010 8:56 AM, khush wrote:
Hi all ,
I have following script to plot some data.
plot( c(1,1100), c(0,15), type='n', xlab='', ylab='', ylim=c(0.1,25) ,
las=2)
axis (1, at = seq(0,1100,50), las =2)
axis (2, at = seq(0,25,1), las =2)
lines( c(1,304),c(0,0),col='grey', lwd=3 )
Paul wrote:
Thanks for the responses. 'Try' seems to be the function that I needed. I
had to adapt the code suggested below because vapply wasn't recognised,
but this seemed to work:
x‑lapply(a,function(x){try(read.table(x,colClasses='character'))})
There is the risk with this
Hi everyone,
Im looking for a clever bit of code to replace NAs with a specific score
depending on an indicator variable.
I can see how to do it using lots of if statements but Im sure there most
be a neater, better way of doing it.
Any ideas at all will be much appreciated, Im
Like I was saying I want to be able to calculate the nearest neighbour and
its vector. I think this can be done using pairdist or K3est in the spatstat
package. But I have no idea as to how I prepare my data in a form that the
software will recognise. How do I turn my tomography data into pp3
Always good to have that fourth way, just in case
(Array3 - as.vector(outer(Array2[-1], Array1, FUN=function(x, y) paste(y,
Array2[1], x, sep=.
[1] height.trt0.trt1 height.trt0.trt2 weight.trt0.trt1 weight.trt0.trt2
age.trt0.trt1age.trt0.trt2
[7] sex.trt0.trt1sex.trt0.trt2
Sébastien Moretti wrote:
I use --vanilla --quiet --slave options on command line but I always get
Loading required package: ...
R 2.5.1
.. and make sure you update your R installation. We are at 2.11.1 currently.
Dieter
--
View this message in context:
On Sep 1, 2010, at 9:20 AM, Chris Howden wrote:
Hi everyone,
I’m looking for a clever bit of code to replace NA’s with a specific
score
depending on an indicator variable.
I can see how to do it using lots of if statements but I’m sure
there most
be a neater, better way of doing it.
Dear list,
I came across the following error for three of my newly written Rd-files:
non-ASCII input and no declared encoding
I can't make sense of this.
Below I copied in one of the three files.
Can anybody please tell me what's wrong with it?
Thank you,
Christian
\name{tetragonula}
On Sep 1, 2010, at 9:55 AM, David Winsemius wrote:
On Sep 1, 2010, at 9:20 AM, Chris Howden wrote:
Hi everyone,
I’m looking for a clever bit of code to replace NA’s with a
specific score
depending on an indicator variable.
I can see how to do it using lots of if statements but I’m
On Wed, 2010-09-01 at 15:09 +0100, Christian Hennig wrote:
Dear list,
I came across the following error for three of my newly written Rd-files:
non-ASCII input and no declared encoding
I'm not sure, but is it the m- or n-dash character for the page range in
the \source{} section?
2317–2331
Dear all,
I would like to apply Orthogonal Projections to Latent Structures
Discriminant Analysis (OPLS-DA) to a metabolomic dataset, in order to
discriminate two groups of samples.
I have looked for an available R package and I have found K-OPLS and
oscorespls.fit (Orthogonal scores PLSR)
On 01/09/2010 10:09 AM, Christian Hennig wrote:
Dear list,
I came across the following error for three of my newly written Rd-files:
non-ASCII input and no declared encoding
I don't think the problem survived emailing, at least I didn't see it.
You can display all the non-ASCII
On Sep 1, 2010, at 10:19 AM, David Winsemius wrote:
On Sep 1, 2010, at 9:55 AM, David Winsemius wrote:
On Sep 1, 2010, at 9:20 AM, Chris Howden wrote:
Hi everyone,
I’m looking for a clever bit of code to replace NA’s with a
specific score
depending on an indicator variable.
I can
Hello,
*I have some issues with furnction that I've used before and that are not
working anymore. I want to check the autocorrelation of an object merMCMC
but the function autocorr did not acccept merMCMC object.Is there any ither
funtion that I could use?*
Dear Gavin,
very well spotted = solved!
Thanks also Duncan!
Christian
On Wed, 1 Sep 2010, Gavin Simpson wrote:
On Wed, 2010-09-01 at 15:09 +0100, Christian Hennig wrote:
Dear list,
I came across the following error for three of my newly written Rd-files:
non-ASCII input and no declared
Dear all,
I have a dataframe:
df-dataframe(a=c(1,2,3),b=c(4,5,6),c=c(7,8,9),d=c(10,11,12))
I want to obtain a new dataframe with columns a and b being standardized
((x-mean(x))/sd(x)); the other two columns (c,d) I want to leave
unchanged. What is the best way to achieve this? I have been
On Sep 1, 2010, at 10:35 AM, Olga Lyashevska wrote:
Dear all,
I have a dataframe:
df-dataframe(a=c(1,2,3),b=c(4,5,6),c=c(7,8,9),d=c(10,11,12))
I want to obtain a new dataframe with columns a and b being
standardized
((x-mean(x))/sd(x)); the other two columns (c,d) I want to leave
If you want to scale within columns, you could try
cbind( scale(df[,1:2]), df[ ,-c(1:2)] )
a b c d
1 -1 -1 7 10
2 0 0 8 11
3 1 1 9 12
and it is data.frame() btw.
On 01/09/2010 15:35, Olga Lyashevska wrote:
Dear all,
I have a dataframe:
Thanks! It is exactly what I was looking for!
Cheers
Olga
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
Dear R-help list users,
I have a huge vector of numbers, how I can invert orden?
For example
x - 1:1000
I would like to obtain
x_r - 1000:1
Thanks,
Sebastian.
__
R-help@r-project.org mailing list
Sebastian writes:
I have a huge vector of numbers, how I can invert orden?
For example
x - 1:1000
I would like to obtain
x_r - 1000:1
Well, 1000:1 works for me. If you need to rev()erse a pre-existing
vector, try rev().
cur
--
Curt Seeliger, Data Ranger
Raytheon Information
Hi,
I built a package in linux and would like to use it in windows. I cant build
the package again in windows because it would miss the necessary libraries
etc(I'm using Rcpp). So I need to generate a binary version and try to
install it in windows. I tried this and I get the error
Hi,
Maybe
sort(x, decreasing=TRUE)
would do it
HTH,
Ivan
Le 9/1/2010 16:56, Sebastian Kruk a écrit :
Dear R-help list users,
I have a huge vector of numbers, how I can invert orden?
For example
x- 1:1000
I would like to obtain
x_r- 1000:1
Thanks,
Sebastian.
Hi folks,
I want to sort a matrix row-by-row and create a new matrix that contains the
corresponding colnames of the original matrix.
E.g.
set.seed(123)
a - matrix(rnorm(20), ncol=4); colnames(a) - c(A,B,C,D)
a
A B C D
[1,] -0.56047565 1.7150650
Hello all,
A friend recently brought to my attention that vector assignment actually
recreates the entire vector on which the assignment is performed.
So for example, the code:
x[10]- NA # The original call (short version)
Is really doing this:
x- replace(x, list=10, values=NA) # The original
Hi,
The proper venue for Rcpp related questions is the Rcpp-devel mailing list:
http://lists.r-forge.r-project.org/cgi-bin/mailman/listinfo/rcpp-devel
Of course you can build a package that uses Rcpp on windows, once all the
proper tools are installed, it is just the same as building it on
Hello all,
I am looking for the function benchmark2 ( a nice function for comparing the
performance of two or more functions).
I found online it exists in the butler package
http://crantastic.org/packages/butler
But for some reason, that package was removed from CRAN:
This problem doesnt seem to have anything to do with Rcpp. I can't build it
on windows because I'm using a library thats only available in linux. Isnt
this a resolvable error?
On Wed, Sep 1, 2010 at 9:07 PM, rom...@r-enthusiasts.com wrote:
Hi,
The proper venue for Rcpp related questions is
On Sep 1, 2010, at 11:18 AM, murali.me...@avivainvestors.com wrote:
Hi folks,
I want to sort a matrix row-by-row and create a new matrix that
contains the corresponding colnames of the original matrix.
E.g.
set.seed(123)
a - matrix(rnorm(20), ncol=4); colnames(a) - c(A,B,C,D)
a
On Wed, Sep 1, 2010 at 8:09 AM, Tal Galili tal.gal...@gmail.com wrote:
Hello all,
A friend recently brought to my attention that vector assignment actually
recreates the entire vector on which the assignment is performed.
So for example, the code:
x[10]- NA # The original call (short
On Sep 1, 2010, at 11:13 AM, Tal Galili wrote:
Hello all,
I am looking for the function benchmark2 ( a nice function for
comparing the
performance of two or more functions).
I found online it exists in the butler package
http://crantastic.org/packages/butler
Have you looked at package
Thank you David!
That's exactly what I was looking for.
Tal
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com
On 01/09/2010 11:34 AM, rajesh j wrote:
This problem doesnt seem to have anything to do with Rcpp. I can't build it
on windows because I'm using a library thats only available in linux. Isnt
this a resolvable error?
The resolution looks pretty obvious: port the library to Windows.
Duncan
I thought building a binary took care of that issue. How do I port a linux
library to windows?
On Wed, Sep 1, 2010 at 9:12 PM, Duncan Murdoch murdoch.dun...@gmail.comwrote:
On 01/09/2010 11:34 AM, rajesh j wrote:
This problem doesnt seem to have anything to do with Rcpp. I can't build
it
on
On Sep 1, 2010, at 11:34 AM, David Winsemius wrote:
snipped
t( apply(a, 1, function(x) colnames(a)[order(x)]) )
[,1] [,2] [,3] [,4]
[1,] A C B D
[2,] A C B D
[3,] D B C A
[4,] B A C D
[5,] C D B A
(apply returns a transposed version.)
That is over-broad. apply() only
first ddply result did I see that some sort of misregistration had occurred;
Better with:
res -ddply(egraw2, .(category), .fun=function(df) {
sapply(df,
function(x) {mnx - mean(x, na.rm=TRUE);
sapply(x, function(z) if
Dear R users,
I would like one of my groups in xyplot to appear to lie 'behind' the other
groups. I have searched for help and find many, many topics about panel
order (e.g., as.table), but that is not what I need.
What is odd is that the group that I want to appear 'behind' the others
On 01/09/2010 11:51 AM, rajesh j wrote:
I thought building a binary took care of that issue. How do I port a linux
library to windows?
Building a binary package links the package to the library, but if the
library doesn't exist, there's nothing to link to.
Porting a Linux library to
Thank you for the explanation Duncan - very interesting indeed!
I wonder if someone in the list might know to answer your question regarding
the double duplication.
Best,
Tal
Contact
Details:---
Contact me: tal.gal...@gmail.com
Normally, a binary package built on one platform will not work on another.
While it is possible to cross-compile, in most cases it is best to assemble the
necessary development environment oNoten the target platform (including the
appropriate libraries compiled for that platform) and build the
Unfortunately, the library is built with visual studio in windows. It doesnt
work with MinGW.
On Wed, Sep 1, 2010 at 9:35 PM, Jeff Newmiller jdnew...@dcn.davis.ca.uswrote:
Normally, a binary package built on one platform will not work on another.
While it is possible to cross-compile, in most
Tal,
For your first example, x is not duplicated in memory. If you compile R
with --enable-memory-profiling, you have access to the tracemem()
function, which will report whether x is duplicate()d:
x - rep(1,100)
tracemem(x)
[1] 0x8f71c38
x[10] - NA
This does not result in duplication of x,
rajesh j akshay.rajesh at gmail.com writes:
I thought building a binary took care of that issue. How do I port a linux
library to windows?
I think we need a little clarification here. When you say a linux
library, do you mean a chunk of compiled (non-R) code that the R package
(sic) needs
Dear all,
I am working with the an R-package named GAMLSS
(www.gamlss.comhttp://www.gamlss.com) it is currently only functional under
the 32-bit version of R (for windows)
The author of the package has agreed to help me create 64-bit compatible
version.
I've been looking through the available
# testthat
Testing your code is normally painful and boring. `testthat` tries to
make testing as fun as possible, so that you get a visceral
satisfaction from writing tests. Testing should be fun, not a drag, so
you do it all the time. To make that happen, `testthat`:
* Provides functions that
Please find below the package announcement for the R package lubridate
available from cran.
Thank you,
Garrett Grolemund
Rice University
##lubridate
Date-time data can be frustrating to work with in R. R commands for
date-times are generally unintuitive and change depending on the type
of
Hi,
I recently have a similar problem. since your post is about 4 months old
I assume you have already got the answer.
Try
boxplot (data, ylim = c(min_lim, max_lim))
--
View this message in context:
Try this:
http://www.stats.ox.ac.uk/~ripley/Win64/W64porting.html
-Matt
On Wed, 2010-09-01 at 07:40 -0400, Hayes, Daniel wrote:
Dear all,
I am working with the an R-package named GAMLSS
(www.gamlss.comhttp://www.gamlss.com) it is currently only functional under
the 32-bit version of R
Hi everyone,
Im looking for a clever bit of code to replace NAs with a specific score
depending on an indicator variable.
I can see how to do it using lots of if statements but Im sure there most
be a neater, better way of doing it.
Any ideas at all will be much appreciated, Im
This is one data set. I have used linear models, but as these data reflect
fish consuming energy during a starvation period, there is a lower
asymptote. I also realize that data is rather scattered and not the
cleanest. I am interested in looking at how fast the animals reach the
On 01/09/2010 7:40 AM, Hayes, Daniel wrote:
Dear all,
I am working with the an R-package named GAMLSS
(www.gamlss.comhttp://www.gamlss.com) it is currently only functional under
the 32-bit version of R (for windows)
The author of the package has agreed to help me create 64-bit compatible
hi there.. i got a problem with ggplot2.
here my example:
library (ggplot2)
v1 - c(1,2,3,3,4)
v2 - c(4,3,1,1,9)
v3 - c(3,5,7,2,9)
gender - c(m,f,m,f,f)
d.data - data.frame (v1, v2, v3, gender)
d.data
x - names (d.data[1:3])
y - mean (d.data[1:3])
pl - ggplot (data=d.data, aes
Dear R users,
I would like one of my groups in xyplot to appear to lie 'behind' the other
groups. I have searched for help and find many, many topics about panel
order (e.g., as.table), but that is not what I need.
What is odd is that the group that I want to appear 'behind' the others
On 01/09/2010 11:09 AM, Tal Galili wrote:
Hello all,
A friend recently brought to my attention that vector assignment actually
recreates the entire vector on which the assignment is performed.
So for example, the code:
x[10]- NA # The original call (short version)
Is really doing this:
x-
Hi all,
We've moved the ggplot2 wiki to a new location to make it more useful,
http://github.com/hadley/ggplot2/wiki. To publicize the new location,
we’re organizing a second ggplot2 case study competition. Some great
prizes are at stake:
* grand prize will be a 32GB ipod touch generously
Hello,
I was looking for a way to evaluate the goodness-of-fit of a logistic
regression model. After googling, I found that I could use resid(fit, 'gof')
method implemented in the rms package. However, since I am not used to the le
Cessie-van Houwelingen normal test statistic, I do not know
On Sep 1, 2010, at 10:42 AM, David Winsemius wrote:
On Sep 1, 2010, at 10:35 AM, Olga Lyashevska wrote:
Dear all,
I have a dataframe:
df-dataframe(a=c(1,2,3),b=c(4,5,6),c=c(7,8,9),d=c(10,11,12))
I want to obtain a new dataframe with columns a and b being
standardized
On Wed, 2010-09-01 at 12:42 -0400, David Winsemius wrote:
I suspect you might have tried (df-mean(df))/sd(x) and gotten
unsatisfactory results; I know I did.
yes, indeed! a few times, but why is that?
If you had really wanted to
persist and do it from first principles, so to speak, or
Hi everyone,
I have a question concerning the unique function. I'm using it with two
different data frame,which are similar in structure, but as in one case unique
works properly in the other doesn't work and I don't understand why.
Someone knows why sometimes unique doesn't do things properly??
I have a simple barplot of 4 mean values, each mean value has an
associated 95% confidence interval drawn on the plot as an error bar.
I want to make a legend on the plot that uses the error bar symbol, and
explains 95% C.I.
How do I show the error bar symbol in the legend? I could not find
n.vialma at libero.it n.vialma at libero.it writes:
Hi everyone,
I have a question concerning the unique function. I'm using it with two
different data frame,which are similar in structure, but as in one case
unique
works properly in the other doesn't work and I don't understand why.
On Wed, 1 Sep 2010, GMail (KU) wrote:
Hello,
I was looking for a way to evaluate the goodness-of-fit of a logistic regression model. After googling, I
found that I could use resid(fit, 'gof') method implemented in the rms package. However, since I
am not used to the le Cessie-van
Can you give us a working example of what you are doing?
I don't understand why you would need a pch symbol for an error bar.
Perhaps if you are using an unboxed legend you could just use arrow() and
text() to add the error bar to the legend?
--- On Wed, 9/1/10, josef.kar...@phila.gov
... and, furthermore, in most real world situations there are several
-- or even lots -- of quite different, incomparable models that give
essentially equivalent fits. Distinguishing among the alternatives
typically requires focused studies designed for the task.
Indeed, as Brian Joiner remarked
On Wed, Sep 1, 2010 at 9:00 AM, jrflanders jrfland...@gmail.com wrote:
Dear R users,
I would like one of my groups in xyplot to appear to lie 'behind' the other
groups. I have searched for help and find many, many topics about panel
order (e.g., as.table), but that is not what I need.
What
Thank you! It is always so simple...
May I throw another question at you? In useOuterStrips, in the latticeExtra
package, I am having problems calling custom strip names, e.g.
useOuterStrips(xyplot(y-x | LOCATION + EVENT, data = TC6, groups = TYPE),
strip=strip.custom(factor.
levels = c(Left,
Hello,
I was wondering if anyone has run across this problem in the past and might be
able to suggest a solution.
I did a review of the FAQ's link trying to find a topic that closely related to
the experience I was having, however I didn't see
anything that might help in diagnosing the
Hi,
I am facing a problem with the legend, I don´t know how to use the fill
option in the legend in order to achieve the same standard gray levels
that are plotted.
Sorry for this easy one, but I really did not find anything so far.
It works fine with color:
## C O L O R
mat -
The phrase does not work can mean many things, it would help us to help you
if you spelled out what you expected and how what you saw differs from what was
expected.
I suspect part of your problem may be in using 0.1:0.3, did you try typing just
that at the command line to see the result? The
On Sep 1, 2010, at 4:17 PM, Jens Oldeland wrote:
Hi,
I am facing a problem with the legend, I don´t know how to use the
fill
option in the legend in order to achieve the same standard gray levels
that are plotted.
Sorry for this easy one, but I really did not find anything so far.
It
Okay, I solved it. After using the same arguments for scales (in particular:
relation=free), the plots are perfectly aligned.
Cheers,
Marius
On 2010-08-24, at 20:39 , Marius Hofert wrote:
Dear expeRts,
I would like to have four plots appearing in one figure. The minimal example
shows
Hi,
sorry for beeing unprecise. I am looking for a legend that has the same
colors as the barplot. For a coloured version I would simply use the
same fill=rainbow() option as used in creating the barplot. However,
this does not work when there are gray values, because there are not
defined in the
Hello, As you can see from my signature in this message, I use the R
fortune function to generate a fortune, which is then fed to the
signature program, which constructs a named pipe containing the
fortune-bearing sig, which is then included in mail messages. The
problem is that it's got
On Sep 1, 2010, at 4:49 PM, Stuart Luppescu wrote:
Hello, As you can see from my signature in this message, I use the R
fortune function to generate a fortune, which is then fed to the
signature program, which constructs a named pipe containing the
fortune-bearing sig, which is then included
Did you try gray.colors(3)?
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: Jens Oldeland [mailto:oldel...@gmx.de]
Sent: Wednesday, September 01, 2010 2:43 PM
To: Greg Snow
Cc:
No...but it works!
I do not know why I did not find it...
Many thanks!
Hi David, thanks to you as well.
Greg Snow schrieb:
Did you try gray.colors(3)?
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
hello,
i did several binomial tests and noticed for one sparse dataset that
binom.test(1,1,0.5) gives a p-value of 1 for the null, what i can't quite
grasp. that would say that the a prob of 1/2 has p-value of 0 ?? - i must be
wrong but can't figure out the right interpretation..
best,
kay
Try thinking this one through from first principles, you are essentially saying
that your null hypothesis is that you are flipping a fair coin and you want to
do a 2-tailed test. You then flip the coin exactly once, what do you expect to
happen? The p-value of 1 just means that what you saw
On 1 September 2010 at 15:49, Stuart Luppescu wrote:
| Hello, As you can see from my signature in this message, I use the R
| fortune function to generate a fortune, which is then fed to the
| signature program, which constructs a named pipe containing the
| fortune-bearing sig, which is then
Simply using option --slave instead seems to do the trick.
$ /usr/bin/R --slave test-fortune.R
Similarly to Brian, I'm much more reluctant to help people who don't
exist --
who knows, maybe you're a computer program who has just passed the
Turing test
:-)
-- Martin Maechler (about
Or using R GNU tools:
m...@max:~$ R -e fortunes::fortune() | gawk '/^[^]/ {print}'
It's not a question of trying variations, rather of following
instructions.
-- Brian D. Ripley (about using 'Writing R Extensions')
R-help (January 2006)
-Matt
On Wed, 2010-09-01 at 16:49 -0400, Stuart
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