Hi all,
I have just started using RMark to analyse capture-recapture data. I am
trying to analyse a simulated data set using the Robust Design (two primary
periods with three secondary sessions in each) to estimate apparent
survival. On specifying the time intervals (that tell R about the primary
Hi all,
I tried to run Rserve: I installed it from CRAN using
install.packages("Rserve")
and tried to run it from the command line using:
R CMD Rserve
I am getting an error telling me that the command perl cannot be
found. What is wrong and what can I do to fix this? Do I need to
install any o
Dear R-help community,
I am working with multidimensional contingency tables and I am having
trouble getting loglm to run on all dimensions without typing out each
dimension.
I have generated random data and provided output for the results I want
below:
d1.c1 <- rnorm(20, .10, .02)
d1.c2 <- r
Dear all
I have problem with calculate probability, I have data x1,...,x10,
I want to calculate probability x11 given x1,...,x10 with two conditions.
1. x is normal
2. unknow distribution
How I can do this.
Many Thanks.
Jumlong
--
Jumlong Vongprasert Assist
Mr. Dunlap and Dr. Winsemius:
Thank you both for your very quick, very handy, and very correct response.
That was it. I only wish I had broken down and admitted defeat and asked
for help hours ago.
That was indeed what I needed, now the before does indeed come before the
after!
Thanks agai
On Nov 7, 2010, at 10:35 PM, rent0...@umn.edu wrote:
Hello. First post, though I have read scores. Mostly i can solve my
problems reading the archives, but I lack the vocabulary to ask this
one right. Any social faux pais, I apologize.
I am sure this is a very basic question and I am embar
Hello. First post, though I have read scores. Mostly i can solve my
problems reading the archives, but I lack the vocabulary to ask this one
right. Any social faux pais, I apologize.
I am sure this is a very basic question and I am embarrassed to ask, but I
spent several hours scouring the arc
Hi:
Check out the expm package, particularly function expm().
HTH,
Dennis
On Sun, Nov 7, 2010 at 6:21 PM, zhiji19 wrote:
>
> Dear R experts,
>
> I really have difficulty when I try to deal with this question.
>
> suppose X is a square symmetric matrix. The exponent of X is defined by the
> mat
Dear R experts,
I really have difficulty when I try to deal with this question.
suppose X is a square symmetric matrix. The exponent of X is defined by the
matrix limit as following:
exp(X) = lim (I + X/n)^n, note: the limit is from n to infinite.
How can I write R function for the above?
Tha
Hi thanks for quick reply. I am new to using R and still tried to figure out
how to use Zoo package.
Here is the code I have so far:
library(zoo)
colClasses <- c("NULL", "character", "character", "numeric", "character",
"character", "NULL")
col.names <- c(NA, "webpage", "item", "value", "day",
On 8/11/2010, at 1:24 PM, Duncan Murdoch wrote:
> ... The docs do say to
> limit the length of titles to 65 characters if possible; this is one
> place where it matters.
The 65 character limit had not previously impinged itself upon my consciousness.
Adhering to this limit
Hi thanks for quick reply. I am new to using R and still tried to figure out
how to use Zoo package.
Here is the code I have so far:
library(zoo)
colClasses <- c("NULL", "character", "character", "numeric", "character",
"character", "NULL")
col.names <- c(NA, "webpage", "item", "value", "day
predab.resample can be called by users but usually is not. It is called by
calibrate.* and validate.* functions in the rms and Design packages (you
neglected to say which package you were using; update to rms if using
Design). The calibrate and validate functions make it easy to use .632.
Not
Dear Robin,
You already have a literal answer to your question, which is to look at
MIcombine.default, but this is just implements Rubin's rules for combining
multiple imputations, which are described in most treatments of the subject.
What's curious is that with only one missing observation amon
On Sat, Nov 6, 2010 at 7:38 AM, Stephen Liu wrote:
> Hi Joshua,
>
> Thanks for your advice.
>
> 1)
> Re your advice:-[quote]
>> a3d
> , , 1 <--- this is the first position of the third dimension ***THIS IS THE
> THIRD DIMENSION***
>
> [,1] [,2] [,3] [,4] <--- positions 1, 2, 3, 4 of the seco
On 07/11/2010 6:55 PM, Rolf Turner wrote:
On 8/11/2010, at 12:39 PM, Duncan Murdoch wrote:
I think you need to give us the source to look at to see what's going on.
Duncan Murdoch
The same phenomenon can be observed for my Iso package which is available
from CRAN. The diff resul
On Nov 7, 2010, at 6:53 PM, bbslover wrote:
http://r.789695.n4.nabble.com/file/n3031344/RSV.Rdata RSV.Rdata
I want to split my dataset to training set and test set using
kennard-stone(KS) algorithm, it is lucky there is R packages
soil.spec to
implement it.
but when I used it to my dataset
http://r.789695.n4.nabble.com/file/n3031344/RSV.Rdata RSV.Rdata
I want to split my dataset to training set and test set using
kennard-stone(KS) algorithm, it is lucky there is R packages soil.spec to
implement it.
but when I used it to my dataset, it does not work, who can help me, how
reasons i
On 8/11/2010, at 12:39 PM, Duncan Murdoch wrote:
> I think you need to give us the source to look at to see what's going on.
>
> Duncan Murdoch
The same phenomenon can be observed for my Iso package which is available
from CRAN. The diff results for Iso are like so:
> diff INDEX Li
See 'mode' argument in ls.str function.
On Sun, Nov 7, 2010 at 2:40 PM, Carl Witthoft wrote:
> Hi all,
> Just thought I'd post this (maybe) helpful tool I wrote. For people like
> me who are bad at keeping a clean environment, it's a time-saver.
>
> #simple command to get only one type of objec
Unless you can be more specific, for the 'pattern recognition' part I can only
recommend you to take a look to the CRAN task views on Machine Learning,
Clustering, Multivariate Statistics, and Finance. For the 'real time' part, I
think it is fair to say that it is hard to get anything done in p
> Date: Sun, 7 Nov 2010 20:57:19 +0100
> From: lig...@statistik.tu-dortmund.de
> To: marchy...@hotmail.com
> CC: r-help@r-project.org
> Subject: Re: [R] can't load nlme on windoze 7
>
Trying "R CMD INSTALL ...zip" said that unpackPkgZip was missing
Try this also:
ls[colSums(sapply(ls, '[[', 'Acc')) > 0]
On Sun, Nov 7, 2010 at 9:07 AM, Matthew Finkbeiner <
matthew.finkbei...@mq.edu.au> wrote:
> I have a list of data frames like this:
>
> a<- data.frame(x=runif(10), y = runif(10), Acc = 1)
> b<- data.frame(x=runif(10), y = runif(10), Acc =
On 07/11/2010 6:22 PM, Rolf Turner wrote:
When building packages these days I keep getting warnings from
"R CMD build" to the effect that INDEX is not up to date. The
INDEXes always seem to be up do to date to *me*.
Then I thought to compare the INDEX from the package source with
the INDEX in
Thanks for your reply.
I am looking for some algorithms to find pattern and trend in stocks in real
time.
I have experience in "Modern Portfolio Optimization Using S-PLUS". I have used
various analytical tools such Mean-Variance, CVaR, CDaR, MAD, Re sampling and
others analytical tools.
I
When building packages these days I keep getting warnings from
"R CMD build" to the effect that INDEX is not up to date. The
INDEXes always seem to be up do to date to *me*.
Then I thought to compare the INDEX from the package source with
the INDEX in the installed package (after building with t
You would get more helpful replies if you indicated which among
MONTHS, CEXPOSE.M and bf.m were factors vs. covariates, and
for which factor or factors you wanted to test the simple slopes.
You will find that linearHypothesis in the car package can test these
things, and the effects package can p
Hi;
I want to use bootstrap .632 with predab.resample, but the description is
not clear for me. Can any body give me an example please.
Thanks;
Azad.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.
Hi Stephan
Since early in November you have posted queries on R-help on 5 different
topics as you are trying to learn to use R. This is a good
thing, and many contributors to R-help have replied, taking pains
to provide explanations and examples to be helpful. But, in return,
it doesn't appear
Perfect.
Thank you Joshua.
--
View this message in context:
http://r.789695.n4.nabble.com/mean-on-a-plot-tp3031068p3031267.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/
Hi R users,
Thanks in advance.
I am using R 2.12.0 on Windows XP.
My objective is to construct algorithms for High Frequency Trading.
May I request you to provide me information such as packages or tools please.
Thank you very much for the time you have given.
Regards,
Deb
Raquel Rangel de Meireles Guimarães gmail.com> writes:
>
> Hi all,
>
> I would like to compute ergodic mean using MCMC output from WinBUGS. I
> tried using CODA package, but it seems that it is not implemented yet.
>
> Could anyone help me to compute this? Attached to this email are my
> out
Hi all,
This is more a help on ideas that on actuall R code. Those of you which are
geologist or work with boreholes woudl understand that i would like to achieve.
I'll tr to explain as good as I can...so here it goes..
I have around 1000 geomechanical (geological) borehole logs in a
Hi Romzero,
This gets the job done, though it is not the most elegant solution
ever (for those I'd take a look at the ggplot2 or lattice packages).
## Read in data
la <- read.table(textConnection("
DaysWeight
0 178.00
0 250.00
0 242.00
0 239.00
0 223.00
0
Hi,
I still do not really understand, but I have a couple ideas:
On Sun, Nov 7, 2010 at 11:09 AM, Vaiva P wrote:
> Thank you guys for a quick reaction. I decided it to write a common
> letter to you both at once.
> I tried to calculate the value of a a function without integration. I
> gave the
Thank you Jim (and others who responded off list). This does the
trick for me perfectly:
ls[sapply(ls, function(x) all(x$Acc == 1))]
Thanks again!
Matthew
On Sun, Nov 7, 2010 at 11:34 PM, jim holtman wrote:
> Is this what you are asking; this accepts any dataframe that has at
> least one Ac
Hi, i need to draw a plot with means of values, reading a table from
datafile.
Example of datafile:
DaysWeight
0 178.00
0 250.00
0 242.00
0 239.00
0 223.00
0 188.00
0 237.00
0 212.00
0 273.00
0 191.00
0 173.00
0 233.00
0
Why don't you install the Windows binary?
install.packages("nlme")
should do the trick?
Otherwise, see "R Installation and Administration" manual fir details
how to set up an environment for installing from sources under Windows.
Note that nlme is a recommended package and included in the bi
Either hotmail or the list spam filter butchered my dll list but
I would mention that the cygwin dll occurs when I tried to load
the nlme library. I posted the build settings in first post and
am now floundering with the tar file to find the Makefile so I can
change them to avoid using cygwin, s
On Nov 7, 2010, at 1:24 PM, Robin Jeffries wrote:
What does missInfo compute
help(package=mitools)
And some obvious Goggling ("lumley micombine missinfo") produced this
link to a 2005 course syllabus that Lumley (the package author) leaves
online:
http://courses.washington.edu/b570/lec
On Nov 7, 2010, at 12:25 PM, David Winsemius wrote:
On Nov 7, 2010, at 11:40 AM, Carl Witthoft wrote:
Hi all,
Just thought I'd post this (maybe) helpful tool I wrote. For
people like me who are bad at keeping a clean environment, it's a
time-saver.
#simple command to get only one type
> Date: Sun, 7 Nov 2010 16:19:16 +0100
> From: lig...@statistik.tu-dortmund.de
> To: marchy...@hotmail.com
> CC: tal.gal...@gmail.com; r-help@r-project.org
> Subject: Re: [R] can't load nlme on windoze 7
>
> I wonder why cygwin is mentioned here.
Yeah
What does missInfo compute and how is it computed?
There is only 1 observation missing the ethnic3 variable. There is no other
missing data.
N=1409
> summary(MIcombine(mod1))
Multiple imputation results:
with(rt.imp, glm(G1 ~ stdage + female + as.factor(ethnic3) + u,
family = binomial()))
With your data set as the data.frame xx
library(reshape2)
xx <- melt(xx)
dcast(xx, name ~ variable, sum)
--- On Sun, 11/7/10, Mohan L wrote:
> From: Mohan L
> Subject: [R] help to sum up data frame
> To: r-help@r-project.org
> Received: Sunday, November 7, 2010, 8:59 AM
> Dear All,
>
> I ha
The hessian from `optim' is not as accurate as that from `numDeriv' (with the
default of Richardson extrapolation), so I would trust the numDeriv's hessian
result over that of optim. However, without seeing what you actually did, this
is only a surmise.
Ravi.
_
On Nov 7, 2010, at 11:40 AM, Carl Witthoft wrote:
Hi all,
Just thought I'd post this (maybe) helpful tool I wrote. For people
like me who are bad at keeping a clean environment, it's a time-saver.
#simple command to get only one type of object in current environment
lstype<-function(type='
Try "optimx" package (with the option all.methods=TRUE). This helps you in 2
different ways: (1) you can compare estimates from multiple optimizers, and
(2) you can look at the first- and second-order KKT conditions for optimality.
Hope this helps,
Ravi.
__
On Sun, Nov 7, 2010 at 10:15 AM, Dimitris Rizopoulos
wrote:
> Dear All,
>
> I would appreciate any help with the following: given the vector 'x'
>
> x <- c("Ass1", "Ass.s1", "Ass2", "Ass.s2")
>
> I would like to pick up the positions where the character string contains
> "Ass" but does not contain
Hi,
Have you tried just your function (undint) on its own (i.e., without
trying to feed it to integrate)? If you did, you would notice that it
does not return anything (hence, "I could not get any result"). See
inline comments for some additional thoughts.
On Sun, Nov 7, 2010 at 8:01 AM, Vaiva
So undint(u) is a 15 dimensional vector. What do the different
dimensions mean? How would you define the integral of a 15 dimensional
vector? It would help if you could provide some background on what your
code is supposed to do.
Uwe Ligges
On 07.11.2010 17:01, Vaiva P wrote:
Hi,
I need
Hi all,
Just thought I'd post this (maybe) helpful tool I wrote. For people
like me who are bad at keeping a clean environment, it's a time-saver.
#simple command to get only one type of object in current environment
lstype<-function(type='closure'){
inlist<-ls(.GlobalEnv)
if (
This is on my to do list:
https://github.com/hadley/ggplot2/issues/labels/facet#issue/107
Hadley
On Thu, Oct 28, 2010 at 11:51 AM, Matthew Pettis
wrote:
> Hi All,
>
> Here is the code that I'll be referring to:
>
> p <- ggplot(wastran.data, aes(PER_KEY, EVENTS))
> (p <- p +
> facet_grid( pool
It's hard to know without a minimal reproducible example, but you
probably want scale_fill_gradient or scale_fill_gradientn.
Hadley
On Thu, Oct 28, 2010 at 9:42 AM, Struchtemeyer, Chris
wrote:
> I am very new to R and don't have any computer program experience
> whatsoever. I am trying to gener
Hello Dennis and r-helpers
Thank you very much for your reply.
The problem is solved now even if I don't seen why the command that I
had posted as an alternative solution did not work...
hDatPretty$liking <- by(hDatPretty$rating, hDatPretty$songId,function (z) {
cut(hDatPretty$z, c(-10, -4,4,
Hi,
I need some help on integrating a function that is a vector.
I have a function - vector which each element is different. And,
naturally, function integrate() does not work
I checked the article of U. Ligges and J. Fox (2008) about code
optimization "How Can I Avoid This Loop or Make It Faster?
Hi,
I'll apreciate your guidance on how can I re-create the output from SAS PROC
VARCLUS in R. I've found the varclus function in Hmisc. However, is it
possible to use that function to compute for each variable the 1-R**2 ratio
(this is the ratio of 1 minus the R-squared with Own Cluster to one
Try this:
grep("Ass[^\\.]", x)
On Sun, Nov 7, 2010 at 1:15 PM, Dimitris Rizopoulos <
d.rizopou...@erasmusmc.nl> wrote:
> Dear All,
>
> I would appreciate any help with the following: given the vector 'x'
>
> x <- c("Ass1", "Ass.s1", "Ass2", "Ass.s2")
>
> I would like to pick up the positions wh
On Nov 7, 2010, at 10:30 AM, David Winsemius wrote:
On Nov 7, 2010, at 10:15 AM, Dimitris Rizopoulos wrote:
Dear All,
I would appreciate any help with the following: given the vector 'x'
x <- c("Ass1", "Ass.s1", "Ass2", "Ass.s2")
I would like to pick up the positions where the character s
On Nov 7, 2010, at 10:15 AM, Dimitris Rizopoulos wrote:
Dear All,
I would appreciate any help with the following: given the vector 'x'
x <- c("Ass1", "Ass.s1", "Ass2", "Ass.s2")
I would like to pick up the positions where the character string
contains "Ass" but does not contain "Ass.s", so
Jonathan Phillips <994phij gmail.com> writes:
> I've been trying to use optim to minimise least squares for a
> function, and then get a guess at the error using the hessian matrix
> (calculated from numDeriv::hessian, which I read in some other r-help
> post was meant to be more accurate than th
I wonder why cygwin is mentioned here.
If you are using the setup installer, it is a native Windows executable
and does not run under cygwin. cygwin1.dll should not be required
anywhere. The cygwin platform is not supported.
Best,
Uwe Ligges
On 07.11.2010 14:37, Mike Marchywka wrote:
On
Dear All,
I would appreciate any help with the following: given the vector 'x'
x <- c("Ass1", "Ass.s1", "Ass2", "Ass.s2")
I would like to pick up the positions where the character string
contains "Ass" but does not contain "Ass.s", so for 'x' that would be
positions 1 and 3.
I guess this co
I said nothing about legitimacy. I only suggested what I thought was a
more satisfactory way the OP could get the issues resolved, since they
seemed to go beyond R. The R-sig-mixed-models (check spelling) list
might be a good place to look.
I believe Th R-help archives not the packages contain Dou
On further investgiation, I clicked on the "R" picture using
windoze explorer and ran as admin. First, I got a prompt saying
it could not find cygwin1.dll. I changed env variables to add cygwin
to path and now it just silently hangs.
If I ask for more details and run R --verbose in gdb and then
Hi Jun,
Just remove the col.names:
colnames(x) <- NULL
isSymmetric(x)
[1] TRUE
HTH,
Jorge
On Sun, Nov 7, 2010 at 1:21 AM, Jun Shen <> wrote:
> Hi,
>
> I have this symmetric matrix, at least I think so.
>
> col1 col2 col3
> [1,] 0.20 0.05 0.06
> [2,] 0.05 0.10 0.03
> [3,] 0.06 0.03 0.08
Renaud Lancelot wrote:
Dear all,
When I use the cacheSweave package together with the Sweave option
keep.source = TRUE, all the LaTeX code before the Sweave code chunk is
included in the TeX file to be compiled. For example, with the
following Sweave file
The author of cacheSweave is aware of
On Nov 7, 2010, at 8:59 AM, Mohan L wrote:
Dear All,
I have a data frame like this:
name ip Bsent Breceived
a 10.00 0.00
a 2 1.43 19.83
a 1 0.00 0.00
a 21.00 1.00
b 10.00
Dear All,
I have a data frame like this:
name ip Bsent Breceived
a 10.00 0.00
a 2 1.43 19.83
a 1 0.00 0.00
a 21.00 1.00
b 10.00 2.00
b 3 0.00 2.00
b
On Sat, Nov 6, 2010 at 11:05 PM, thornbird wrote:
>
> Thank you very much. I learned a lot through your help. It worked great for
> the sample data. But when I try to apply the command to my dataset, I ran
> into two more problems.
>
> First, the dataset is huge, it has thousands of lines. I can r
> From: tal.gal...@gmail.com
> Date: Sun, 7 Nov 2010 09:27:10 +0200
> Subject: Re: [R] can't load nlme on windoze 7
> To: marchy...@hotmail.com
> CC: r-help@r-project.org
>
> Hello Mika,
>
> Most of my problems with win7 where permission problems.
> You can ch
Perfect, thanks!
On Nov 7, 2010, at 4:59 AM, baptiste auguie wrote:
> Hi,
>
> try this,
>
> xyplot(Time~Chromosome|factor(Elements),
> data = mtx[order(mtx$Chromosome), ], ... [snipped])
>
>
> HTH,
>
> baptiste
>
>
>
>
>
> On 7 November 2010 13:17, Alex Reynolds wrote:
>>
Hi,
try this,
xyplot(Time~Chromosome|factor(Elements),
data = mtx[order(mtx$Chromosome), ], ... [snipped])
HTH,
baptiste
On 7 November 2010 13:17, Alex Reynolds wrote:
> I have the following xyplot figure:
>
> http://img577.imageshack.us/img577/686/filesizeresults1200
Is this what you are asking; this accepts any dataframe that has at
least one Acc = 1; changing 'any' to 'all' means all Acc==1. Play
around and get what you need:
> ls<- list(a,b)
> ls
[[1]]
x y Acc
1 0.26550866 0.2059746 1
2 0.37212390 0.1765568 1
3 0.57285336 0.68702
?paste
id <- dbGetQuery(con1,paste("SELECT id FROM tenants WHERE name LIKE '%",
,str, "%'", sep = ''))
On Sun, Nov 7, 2010 at 4:51 AM, Mohan L wrote:
> Dear All,
>
> I am using this query it returns id :
>
> id <- dbGetQuery(con1,"SELECT id FROM tenants WHERE name LIKE '%consim%'")
>
> B
I have the following xyplot figure:
http://img577.imageshack.us/img577/686/filesizeresults1200.png
The data are organized in a matrix file as follows:
Type ElementsChromosome Time
bedGz 1200chr114.240
bedGz 1200chr27.949
bedGz 1200
All helpful suggestions: thanks loads Baptiste, Barry, Jim. image() and
color2D.matplot() seem most easily adaptable for my purposes. I've copied a
couple of examples below for anyone else facing the same q's.
Best,
Peter
#color matrix
cseq<-seq(0,150,1)
lseq<-seq(0,100,1)
clen<-length(cseq)
llen<
I have a list of data frames like this:
a<- data.frame(x=runif(10), y = runif(10), Acc = 1)
b<- data.frame(x=runif(10), y = runif(10), Acc = 0)
ls<- list(a,b)
and I want to remove the data frames from ls that have Acc values other than 1.
How do I do that?
Thanks for any help!
Matthew
___
Dear all,
When I use the cacheSweave package together with the Sweave option
keep.source = TRUE, all the LaTeX code before the Sweave code chunk is
included in the TeX file to be compiled. For example, with the
following Sweave file
\documentclass[12pt]{article}
\usepackage[nogin]{Sweave}
% Swea
Hi:
On Sat, Nov 6, 2010 at 11:22 PM, evt wrote:
>
> I am guessing this is a very simple question, but this is only my second
> day
> with R so it is all still a bit imposing.
>
> I am trying to run an autocorrelation.
>
> I imported a CSV file, which has one column labeled "logistic".
>
> I ran
Dear All,
I am using this query it returns id :
id <- dbGetQuery(con1,"SELECT id FROM tenants WHERE name LIKE '%consim%'")
But In my case the string "consim" is there in another variable(it is
coming from configuration file);
> str <- "consim"
I am trying to replace the string some this like,
Hi:
If I get your meaning, the cut() function would appear to be your friend in
this problem.
hDatPretty$liking <- cut(hDatPretty$rating, breaks = c(-11, -4, 4, 11),
labels = c('dislike', 'neutral',
'like'))
HTH,
Dennis
On Sat, Nov 6, 2010 at 11:15 PM, hind
Hi,
I've been trying to use optim to minimise least squares for a
function, and then get a guess at the error using the hessian matrix
(calculated from numDeriv::hessian, which I read in some other r-help
post was meant to be more accurate than the hessian given in optim).
To get the standard erro
Thank you very much. I learned a lot through your help. It worked great for
the sample data. But when I try to apply the command to my dataset, I ran
into two more problems.
First, the dataset is huge, it has thousands of lines. I can read it in R.
Using Lines <- " data " may not work such a
Dear Professor Lumley;
Thank you so much for your invaluable advice!
I will digest your advice and try different methods.
Great thanks again!
Faye
> Date: Fri, 5 Nov 2010 08:24:00 +1300
> Subject: Re: [R] How to do bootstrap for the complex sample design?
> From: tlum...@uw.edu
> To: ti
Hello Mika,
Most of my problems with win7 where permission problems.
You can check if that is the case, by setting R to ran with
administrator privileges, and see if that solves the problem.
Best,
Tal
Contact
Details:---
Contac
Jun Shen wrote:
Hi,
I have this symmetric matrix, at least I think so.
col1 col2 col3
[1,] 0.20 0.05 0.06
[2,] 0.05 0.10 0.03
[3,] 0.06 0.03 0.08
or
structure(c(0.2, 0.05, 0.06, 0.05, 0.1, 0.03, 0.06, 0.03, 0.08
), .Dim = c(3L, 3L), .Dimnames = list(NULL, c("var1", "var2",
"var3")))
B
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