On Jun 21, 2011, at 11:13 PM, Tom Kraft wrote:
Dear all,
This question is basic but I am stumped. After running the below, I
receive
the message: non-integer #successes in a binomial glm!
model1 -
glmmML(y~Brood.Size*Density+Date.Placed+Species+Placed.Emerging+Year
Marius Hofert m_hof...@web.de
on Wed, 22 Jun 2011 01:00:21 +0200 writes:
Thanks a lot! Works like charm :-))) Cheers,
well,
I'd still *strongly* vote for Bill Dunlap's version.
Martin
Marius
On 2011-06-22, at 24:51 , Dennis Murphy wrote:
Ahhh...you want a matrix.
David Winsemius dwinsem...@comcast.net
on Tue, 21 Jun 2011 12:07:47 -0400 writes:
On Jun 21, 2011, at 11:44 AM, Patrick Breheny wrote:
On 06/21/2011 09:48 AM, davefrederick wrote:
Hi, I have a 500x 53380 sparse matrix and I am trying to
dichotomize it. Under sna
On 21.06.2011 13:56, Daniel Stahl wrote:
Dear all,
is it possible to run the support vector machine command svm from the
package e1071 within the errorest function from the library ipred?
It works fine for lda and rda but I get an error message (see below)
Thank you for your help.
Best
Thank you for your help...
It works very well!
El mar, 21-06-2011 a las 20:03 -0700, Bert Gunter escribió:
?strip.default
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
I guess you use the menu to save the plots from your Windows device into
files rather than starting separate devices explicitly?
If so, please use explicit calls to the devices and everything happens
as you define it.
Uwe Ligges
On 22.06.2011 04:31, John Kruschke wrote:
When I save a
Hi All,
I would like to use R to do some computation. However, before I proceed to
write an R script, I have difficulty to find out a solution for the question
below. Please note that the question below is not relating to question in R.
I have a table below,
2009 2010 2011 2012 2013 2014
Subject: [R] Time-series analysis with treatment effects - statistical
approach
Hello all R listers,
I'm struggling to select an appropriate statistical method for my data set.
I have collected soil moisture measurements every hour for 2 years. There
are 75 sensors taking these
The error happens when using the savePlot() command, like this:
savePlot( file=TestSavePlot.eps , type=eps )
savePlot( file=TestSavePlot.jpg , type=jpg )
The images in the two saved files are not the same, with the JPG being
correct but the EPS being wrong.
When you suggest starting separate
On 22.06.2011 13:50, John Kruschke wrote:
The error happens when using the savePlot() command, like this:
savePlot( file=TestSavePlot.eps , type=eps )
savePlot( file=TestSavePlot.jpg , type=jpg )
Well, plot directly into a device, for postscript:
postscript(estSavePlot.eps,
On Jun 21, 2011, at 6:51 PM, Dennis Murphy wrote:
Ahhh...you want a matrix. xtabs() doesn't easily allow coercion to a
matrix object, so try this instead:
What am I missing? A contingency table already inherits from matrix-
class and if you insisted on coercion it appears simple:
xtb -
Dear list,
Inspecting residuals of my linear models, I detected spatial autocorrelation.
In order to take this into account, I decided to use the GLS method
with the correlation = corGaus ( ~ X + Y).
Then, I can sort my GLS models based on their AIC.
But ... how to know the proportion of the
I saw it as an xtabs object - I didn't think to check whether it was
also a matrix object. Thanks for the clarification, David.
Dennis
On Wed, Jun 22, 2011 at 4:59 AM, David Winsemius dwinsem...@comcast.net wrote:
On Jun 21, 2011, at 6:51 PM, Dennis Murphy wrote:
Ahhh...you want a matrix.
..I cant imagine myself without this site!
http://www.stadcopolyproducts.com/friends.page.php?utopic=07x1
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Hi,
and what's the simplest way to obtain a *data.frame* with all years?
The matching seems more difficult here because the years can/will show up
several times...
(df - data.frame(year=c(2000, 2001, 2002, 2001, 2000, 2001),
block=c(a,a,a,b,c,c), value=1:6))
(df. -
I think you should write out your model formula and then go over it term by
term to see which term adds what to your understanding of the data. If
necessary, pick up a text about the interpretation of coefficients. For
example, you will find that Reduction is not just the slope for the
condition
On Jun 22, 2011, at 9:19 AM, Marius Hofert wrote:
Hi,
and what's the simplest way to obtain a *data.frame* with all years?
The matching seems more difficult here because the years can/will
show up several times...
(df - data.frame(year=c(2000, 2001, 2002, 2001, 2000, 2001),
Dear Sirs/Madam,
I am a beginner to R, and I am currently working on a data matrix which looks
like this:
head(oligo)
ko:K1 ko:K3 ko:K5 ko:K8 ko:K9 ko:K00010 ko:K00012
AAA 370 631 365 67 164
455
Hello,
I am struggling to figure out how to analyse a dataset I have inherited
(please note this was conducted some time ago, so the data is as it is,
and I know it isn't perfect!).
A brief description of the experiment follows:
Pots of grass were grown in 1l pots of standad potting medium for 1
Good afternoon sir,
i'm a student in Indonesia who study technology management, i need to review
the software i'v been develop, i was told to use bayesian SEM because i
don't have large sample. i don't know much about statistics but i try to
make a code via winbugs.. and a i got a problem. here i
Dear all,
I am a new user of R. I want use R to plot four momentum vectors(variable)
in form of tetrahedral. The data(momentum vector) is in form of
distribution(e.g. momentum of particle1 vs intensity).
Thanks in advance.
Best Regards
Rajesh
--
View this message in context:
I am plotting a number of lines on a standard plot. I would like to add
labels at the end (rhs) of each line. is there a way to do this other
than defining the individual xy coordinates and placing each label using
text()
Thanks
Nevil Amos
__
Hi:
Based on the information you provided, I would suggest looking into
the transform() and within() functions in base R, and perhaps the
mutate() function in package plyr.
HTH,
Dennis
On Tue, Jun 21, 2011 at 11:35 PM, Nabila Binte Zahur nab...@nus.edu.sg wrote:
Dear Sirs/Madam,
I am a
Hi David,
thanks for the quick response. That's nice. Is there also a way without loading
an additional package? I'd prefer loading less packages if possible.
Cheers,
Marius
On 2011-06-22, at 15:38 , David Winsemius wrote:
On Jun 22, 2011, at 9:19 AM, Marius Hofert wrote:
Hi,
and
On 11-06-21 10:31 AM, Nevil Amos wrote:
I am plotting a number of lines on a standard plot. I would like to add
labels at the end (rhs) of each line. is there a way to do this other
than defining the individual xy coordinates and placing each label using
text()
Probably, but what you
On Wed, Jun 22, 2011 at 2:35 AM, Nabila Binte Zahur nab...@nus.edu.sg wrote:
Dear Sirs/Madam,
I am a beginner to R, and I am currently working on a data matrix which looks
like this:
head(oligo)
ko:K1 ko:K3 ko:K5 ko:K8 ko:K9 ko:K00010 ko:K00012
AAA 370
On 11-06-21 11:58 PM, steven mosher wrote:
Thanks to all your help I've just finished my first package and I have a
couple of questions
I want to submit to CRAN but I have 1 warning
checking for code/documentation mismatches ... WARNING
Data sets with usage in documentation object
You could analyze these data with a multinomial logit model, with an ordinal
response. I don't have my copy handy, but I know that Agresti (Categorical
Data Analysis, Wiley) covers these models.
Cheers
David Cross
d.cr...@tcu.edu
www.davidcross.us
On Jun 22, 2011, at 8:19 AM, Matt Ellis
On Jun 22, 2011, at 9:46 AM, Marius Hofert wrote:
Hi David,
thanks for the quick response. That's nice. Is there also a way
without loading an additional package? I'd prefer loading less
packages if possible.
xtb - xtabs(value ~ year + block, data = df)
xtb
block
year a b c
On Jun 21, 2011, at 10:31 AM, Nevil Amos wrote:
I am plotting a number of lines on a standard plot. I would like to
add labels at the end (rhs) of each line. is there a way to do this
other than defining the individual xy coordinates and placing each
label using text()
Without an
Every now and then I realize that my attempts to document what all dataframes
consist of are unsufficient. So far, I have been writing notes in an external
file. Are there any better ways to do this within R? One possibility could be
to set up the data as packages, but I would like to have a
Thanks for the suggestion, Dennis. Unfortunately, I was not able to make it
work. Maybe I'm not using as.formula properly. I posted below some new things I
tried. What am I doing wrong?
Thanks for any feedback!
Rita
First attempt:
eqSystem2 -paste(paste(form, 1:4, sep=), as.formula(paste(EQ,
Using layout I've created a function that makes a 2 panel plot - comprising a
main plot, and a sub-panel with custom legend.
I would now like to use layout to create multiple panels with plots created
by my function, however the values for layout set in the function act
globally, stopping me from
The best method would probably be proportional odds regression using
polyr() in 'MASS'.
At least it's a starting point.
At 09:19 AM 6/22/2011, Matt Ellis \(Research\) wrote:
Hello,
I am struggling to figure out how to analyse a dataset I have inherited
(please note this was conducted some
Tom,
thanks for spotting a bug in glmmML; internally, glmmML sorts data by
cluster. The bug is that I missed to sort the weights accordingly.
Weights are produced when the response is a two-column matrix, as in
your case. So, glmmML calls glm.fit with wrong weights, and the
warning comes from
Thanks Duncan, I'll join Dev and ask the questions over there.
Steve
On Wed, Jun 22, 2011 at 7:19 AM, Duncan Murdoch murdoch.dun...@gmail.comwrote:
On 11-06-21 11:58 PM, steven mosher wrote:
Thanks to all your help I've just finished my first package and I have a
couple of questions
I
There is a 'comment' function. It sets an attribute which gets carried
along with the dataframe when it is saved or copied:
df1 -data.frame(NA)
df1
NA.
1 NA
comment(df1) - empty dataframe
comment(df1)
[1] empty dataframe
df2 - df1
comment(df2) - c(comment(df1), copy of df1)
Have a look at the AnnotatedDataFrame class in the Biobase package
[1]. Here is the description from the manual:
An ‘AnnotatedDataFrame’ consists of two parts. There is a collection
of samples and the values of variables measured on those samples.
There is also a description of each variable
H-W only gives you the expected frequency of AA, AB, and BB genotypes (i.e.
a 1x3 table):
minor - runif(1, 0.05, 0.25)
major - 1-minor
AA - minor^2
AB - 2*minor*major
BB - major^2
df - cbind(AA, AB, BB)
-Aaron
On Tue, Jun 21, 2011 at 9:30 PM, Jim Silverton jim.silver...@gmail.comwrote:
Hello R users,
I have a puzzle with the VGAM package, on my first excursion into
generalized additive models, in that this very nice package seems to
want to do either more or less than what I want.
Precisely, I have a 4-component outcome, y, and am fitting multinomial
logistic regression with
Hi,
I would like to fit a Vector Auto Regression with lags that are not
consecutive with the vars package (or other if there is one as good). Is it
possible?
For example, rather than having lags 1, 2, 3, 4, 5 have 1, 2, 5.
Thanks.
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View this message in context:
Does really nobody has a coment to this question?
Dear R-help members
I would like to use the R package goalprog, weighted and lexicographical goal
programming and optimization to optimize a location problem.
In my model I need a yes or no decision - in this case, whether to select a
site or
is.na(strptime(5/2/1992, format=%m/%d/%Y))
[1] FALSE
is.na(strptime(5/3/1992, format=%m/%d/%Y))
[1] TRUE
Any idea what's going on with this? Running strptime against all dates
from around 1946, only 5/3/1992 was converted as NA. Even stranger,
it still seems to have a value associated with it
Jürg.
It's not that nobody knows the answer, necessarily, it's that your
inquiry is so vague we don't know what the *question* is, let alone
the answer.
We don't know anything about your data, your intended function and
model, anything.
A toy reproducible example with clear explanation would be
Hi all,
I have two datasets, one that represents a long-term time series and one
that represents summary data for the time series. It looks something like
this:
x-data.frame(Year=c(2001,2001,2001,2001,2001,2001,2002,2002,2002,2002,2002,2002),
Month=c(1,1,1,2,2,2),Q=c(5,5,5,6,6,6,3,3,3,4,4,5))
Hi,
On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin ashen...@ufl.edu wrote:
is.na(strptime(5/2/1992, format=%m/%d/%Y))
[1] FALSE
is.na(strptime(5/3/1992, format=%m/%d/%Y))
[1] TRUE
I can't reproduce your problem on R 2.13.0 on linux:
strptime(5/2/1992, format=%m/%d/%Y)
[1] 1992-05-02
On 6/22/2011 1:03 PM, Sarah Goslee wrote:
Hi,
On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin ashen...@ufl.edu wrote:
is.na(strptime(5/2/1992, format=%m/%d/%Y))
[1] FALSE
is.na(strptime(5/3/1992, format=%m/%d/%Y))
[1] TRUE
I can't reproduce your problem on R 2.13.0 on linux:
On Jun 22, 2011, at 2:03 PM, Sarah Goslee wrote:
Hi,
On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin
ashen...@ufl.edu wrote:
is.na(strptime(5/2/1992, format=%m/%d/%Y))
[1] FALSE
is.na(strptime(5/3/1992, format=%m/%d/%Y))
[1] TRUE
I can't reproduce your problem on R 2.13.0 on
For example, you can merge the two data frames and do a direct comparison:
df-merge(x,y,all.x=T,all.y=F)
df
df$Qdf$Threshold_Q
HTH,
Daniel
Ryan Utz-2 wrote:
Hi all,
I have two datasets, one that represents a long-term time series and one
that represents summary data for the time
On Wed, Jun 22, 2011 at 2:28 PM, David Winsemius dwinsem...@comcast.net wrote:
On Jun 22, 2011, at 2:03 PM, Sarah Goslee wrote:
Hi,
On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin ashen...@ufl.edu
wrote:
is.na(strptime(5/2/1992, format=%m/%d/%Y))
[1] FALSE
is.na(strptime(5/3/1992,
I assume that you are working in package MatrixCalc. Lets
say you have a matrix X. You can call the columns of X this way:
X[,1] for the first column
X[,2] for the second column
X[,3] for the third column
Etc.
So lets say that you want to add the first and third column,
then you would just
On 6/22/2011 1:34 PM, Sarah Goslee wrote:
On Wed, Jun 22, 2011 at 2:28 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Jun 22, 2011, at 2:03 PM, Sarah Goslee wrote:
Hi,
On Wed, Jun 22, 2011 at 11:40 AM, Alexander Shenkin ashen...@ufl.edu
wrote:
is.na(strptime(5/2/1992,
The memisc package also offers functionality for documenting data.
Jan
On 06/22/2011 04:57 PM, Robert Lundqvist wrote:
Every now and then I realize that my attempts to document what all dataframes
consist of are unsufficient. So far, I have been writing notes in an external
file. Are there
1st of all Dr Utz, thanks for your recent pubs on regional differences
between the piedmont and coastal plain streams.
and to add to Daniels post (giving your binary yes/no):
df-merge(x,y,all.x=T,all.y=F)
df[exceed] - ifelse(df$Qdf$Threshold_Q , 1, 0)
## now look at df
df
Daniel Malter
For what it's worth, I cannot reproduce this problem under a nearly
identical instance of R (R 2.12.1, Win 7 Pro 64-bit). I also can't
reproduce the problem with R 2.13.0. You've got something truly weird
going on with your particular instance of R.
is.na(strptime(5/3/1992, format=%m/%d/%Y))
Daniel,
That indeed does work... and I didn't even need to learn a new function.
Thanks!
--
Ryan Utz, Ph.D.
Aquatic Ecologist/STREON Scientist
National Ecological Observatory Network
Home/Cell: (724) 272-7769
Work: (720) 746-4844 ext. 2488
[[alternative HTML version deleted]]
Hello,
When evaluating different learning methods for a categorization problem with
the (really useful!) caret package, I'm getting confusing results from the
Kappa computation. The data is about 20,000 rows and a few dozen columns,
and the categories are quite asymmetrical, 4.1% in one category
Hello,
I am pretty new to mlogit, and still trying to figure out what models to use.I
have a data set of N individuals, each of which faces I alternatives. The
utility function of individual n, for choice i is:
u(i,n) = alpha(i) * x1(i,n) + beta * x2(i,n)
where alpha(i) is the individual
Thanks all the issue is closed.
in this case I had a data element FILE.PARAMETERS = list()
the .Rd files created by package.skelton() for data objects had the
following for \usage.
\usage{data(FILE.PARAMETERS)}
I left that as is and CHECK throws a warning.
checking for
Hi
On 23/06/2011 2:58 a.m., Simon Goodman wrote:
Using layout I've created a function that makes a 2 panel plot - comprising a
main plot, and a sub-panel with custom legend.
I would now like to use layout to create multiple panels with plots created
by my function, however the values for
The isdst value -1 doesn't seem right. Shouldn't it
be either 0 (not daylight savings time) or 1 (yes dst)?
I've only seen isdst==-1 when all the other entries
were NA (that happens when the string doesn't match
the format).
In the parts of the US where daylight savings time is
used the
I can reproduce your problem when using a time that
doesn't exist because it is between 2am and 3am on
the Sunday that we switch from winter time to summer
time:
z - strptime(paste(paste(sep=/, 4, 5, 1992), 2:30),
format=%m/%d/%Y %H:%M)
z
[1] 1992-04-05 02:30:00
is.na(z)
[1] TRUE
Wow. Setting my timezone to UTC -5 Bogota (where there is no daylight
savings time), I get the error:
is.na(strptime(5/3/1992, format=%m/%d/%Y))
[1] TRUE
But setting it to UTC -5 East Coast Time (whether or not I tell windows
to adjust for DST) I get:
is.na(strptime(5/3/1992,
On 6/22/2011 12:09 PM, Luke Miller wrote:
For what it's worth, I cannot reproduce this problem under a nearly
identical instance of R (R 2.12.1, Win 7 Pro 64-bit). I also can't
reproduce the problem with R 2.13.0. You've got something truly weird
going on with your particular instance of R.
On 6/22/2011 3:34 PM, Brian Diggs wrote:
On 6/22/2011 12:09 PM, Luke Miller wrote:
For what it's worth, I cannot reproduce this problem under a nearly
identical instance of R (R 2.12.1, Win 7 Pro 64-bit). I also can't
reproduce the problem with R 2.13.0. You've got something truly weird
going
On 6/22/2011 1:23 PM, William Dunlap wrote:
The isdst value -1 doesn't seem right. Shouldn't it
be either 0 (not daylight savings time) or 1 (yes dst)?
I've only seen isdst==-1 when all the other entries
were NA (that happens when the string doesn't match
the format).
A isdst of -1 indicates
So im here now b/c im incredibly frustrated. Please consider the following:
#Try 1
Data_-list()
Sn-1:12
for(sn in Sn){
for(i in 1:10){
Data.X - rnorm(100,0,10)
Data_[[paste(sn,i,sep=-)]]-Data.X
}
}
##Try 2
Data_-list()
Sn-1:12
for(sn in
I know this a newbie question, but I've only just started using AIC for
model comparison and after a bunch of different keyword searches I've
failed to find a page laying out what the differences are between the
AIC scores assigned by AIC() and mle.aic() using default settings.
I started by
On 6/22/2011 1:37 PM, Alexander Shenkin wrote:
On 6/22/2011 3:34 PM, Brian Diggs wrote:
On 6/22/2011 12:09 PM, Luke Miller wrote:
For what it's worth, I cannot reproduce this problem under a nearly
identical instance of R (R 2.12.1, Win 7 Pro 64-bit). I also can't
reproduce the problem with R
On Wed, 22 Jun 2011, Quang Anh Duong wrote:
Hello,?
I am pretty new to mlogit, and still trying to figure out what models to
use.I have a data set of N individuals, each of which faces I
alternatives. The utility function of individual n, for choice i is:?
u(i,n) = alpha(i) * x1(i,n) +
Hello
I seem to find only two types of rotation for the factanal function in R, the
Varimax and Promax, but is it possible to run a orthogonal and oblique
rotations in R?
Thanks in advance
Rosario
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R-help@r-project.org mailing list
On 6/22/2011 4:09 PM, Brian Diggs wrote:
On 6/22/2011 1:37 PM, Alexander Shenkin wrote:
On 6/22/2011 3:34 PM, Brian Diggs wrote:
On 6/22/2011 12:09 PM, Luke Miller wrote:
For what it's worth, I cannot reproduce this problem under a nearly
identical instance of R (R 2.12.1, Win 7 Pro 64-bit).
Varimax is orthogonal, promax is oblique. Varimax is generally not
recommended. See: Preacher, K. J., MacCallum, R. C. (2003).
Repairing Tom Swift's electric factor analysis machine. Understanding
Statistics, 2(1), 13-43. (Google the title and you'll find a PDF).
The fa() function in the
I second the fortune nomination, probably the 1st paragraph is sufficient for a
fortune.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
You lost me with the TRN and TRN_CLUSTER bits, but are you trying to
make a list of lists?
Data_ - list()
SN - 1:12
for(sn in SN) {
+ Data_[[sn]] - list()
+ for(i in 1:10) {
+ Data.X - rnorm(5, 0, 10)
+ Data_[[sn]][[i]] - Data.X
+ }}
Data_[[3]][[2]]
[1] -5.687070 -2.365589 12.378359
HI, Dear R community,
I have a large data set names dd.txt, the columns are: there are 2402
variables.
a1, b1, ..z1, a11, b11, ...z11, a111, b111, ..z111..
IF I dont know the relative position of the columns, but I know I need the
following variables:
var-c(a1, c1,a11,b11,f111)
Can I use
On Wed, Jun 22, 2011 at 5:45 PM, Changbin Du changb...@gmail.com wrote:
HI, Dear R community,
I have a large data set names dd.txt, the columns are: there are 2402
variables.
a1, b1, ..z1, a11, b11, ...z11, a111, b111, ..z111..
IF I dont know the relative position of the columns, but I
I am interested in simulating 10,000 2 x 3 tables for SNPs data with the
Hardy Weinberg formulation. Is there a quick way to do this? I am assuming
that the minor allelle frequency is uniform in (0.05, 0.25).
rmultinom() with HWE expectations
__
Hi, Gabor,
Thanks so much, I will try it and let you know the results.
Appreciated!
On Wed, Jun 22, 2011 at 2:54 PM, Gabor Grothendieck ggrothendi...@gmail.com
wrote:
On Wed, Jun 22, 2011 at 5:45 PM, Changbin Du changb...@gmail.com wrote:
HI, Dear R community,
I have a large data set
I found the following errors:
library(sqldf)
Loading required package: DBI
Loading required package: RSQLite
Loading required package: RSQLite.extfuns
*Error: package 'RSQLite' 0.8-0 is loaded, but = 0.9.1 is required by
'RSQLite.extfuns'*
On Wed, Jun 22, 2011 at 6:01 PM, Changbin Du changb...@gmail.com wrote:
I found the following errors:
library(sqldf)
Loading required package: DBI
Loading required package: RSQLite
Loading required package: RSQLite.extfuns
Error: package 'RSQLite' 0.8-0 is loaded, but = 0.9.1 is required
My R is 2.12.0.
R.version.string
[1] R version 2.12.0 (2010-10-15)
packageVersion(RSQLite)
[1] '0.8.0'
packageVersion(sqldf)
[1] '0.3.5'
So it seems I have to update or install the 2.13.0 version in my linux
machine.
On Wed, Jun 22, 2011 at 3:04 PM, Gabor Grothendieck
On Wed, Jun 22, 2011 at 6:10 PM, Changbin Du changb...@gmail.com wrote:
My R is 2.12.0.
R.version.string
[1] R version 2.12.0 (2010-10-15)
packageVersion(RSQLite)
[1] '0.8.0'
packageVersion(sqldf)
[1] '0.3.5'
So it seems I have to update or install the 2.13.0 version in my linux
I will try this first.
Thanks, Gabor!
On Wed, Jun 22, 2011 at 3:15 PM, Gabor Grothendieck ggrothendi...@gmail.com
wrote:
On Wed, Jun 22, 2011 at 6:10 PM, Changbin Du changb...@gmail.com wrote:
My R is 2.12.0.
R.version.string
[1] R version 2.12.0 (2010-10-15)
INstalling of RSQLite was successful.
in R:
packageVersion(RSQLite)
[1] '0.9.4'
When I try to install sqldf, I found the following errors:
install.packages(sqldf)
Installing package(s) into '/house/homedirs/c/cdu/library/'
(as 'lib' is unspecified)
trying URL
On Wed, Jun 22, 2011 at 7:07 PM, Changbin Du changb...@gmail.com wrote:
INstalling of RSQLite was successful.
in R:
packageVersion(RSQLite)
[1] '0.9.4'
When I try to install sqldf, I found the following errors:
install.packages(sqldf)
Installing package(s) into
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PLEASE do read the
Hello R Masters and the Rest of Us:
The first of these works fine, the 2nd is accepted but too literal
(the %-% is shown in the plot label and in the wrong position).
The 3rd throws and error due to unexpected SPECIAL. Would someone
recommend a way to format this? I want the two phrases
Hi Mike, here's a sample of my data so that you get an idea what I'm working
with.
http://r.789695.n4.nabble.com/file/n3618615/SampleDataSet.txt
SampleDataSet.txt
Also, I've uploaded an image showing a sample graph of daily soil moisture
by treatment. The legend shows IP, IP+, PP, PP+ which
Interesting. I don't know the explanation, but look at this:
# works
plot(1:10, 1:10, xlab=expression(a %-% b))
# doesn't work
plot(1:10, 1:10, xlab=expression(%-%))
# works
plot(1:10, 1:10, xlab=expression(paste(something %-% else)))
# doesn't work
plot(1:10, 1:10,
On Jun 22, 2011, at 8:10 PM, Bryan Hanson wrote:
Hello R Masters and the Rest of Us:
The first of these works fine, the 2nd is accepted but too literal
(the %-% is shown in the plot label and in the wrong position).
The 3rd throws and error due to unexpected SPECIAL. Would someone
Thanks to both David and Sarah. I'm glad I asked, as I had tried some
of the combos Sarah suggested and observed the same behavior, which
puzzled me. David, thanks for reminding me about ~ as that is a
different way to get a space into the string. I just don't use
plotmath often enough
Hi:
From the plotmath help page:
x %-% y x right-arrow y
so this is behaving like a binary operator. There happen to be several
of these in plotmath
On Wed, Jun 22, 2011 at 5:49 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
Interesting. I don't know the explanation, but look at this:
Dennis,
Thanks. That makes sense, but I don't think it's clearly documented.
The default assumption that I and at least some others in this
discussion made is that everything in the list of plotmath features in
the helpfile works the same way, since they're all in the same list.
And if for some
On Mon, 20 Jun 2011, Jim Silverton wrote:
I a using plink on a large SNP dataset with a .map and .ped file. I want
to get some sort of file say a list of all the SNPs that plink is saying
that I have. ANyideas on how to do this?
All the SNPs you have are listed in the .map file. An easy
Resending to correct bad subject line...
On Mon, 20 Jun 2011, Jim Silverton wrote:
I a using plink on a large SNP dataset with a .map and .ped file. I want
to get some sort of file say a list of all the SNPs that plink is saying
that I have. ANyideas on how to do this?
All the SNPs you
Date: Wed, 22 Jun 2011 17:21:52 -0700
From: jmo...@student.canterbury.ac.nz
To: r-help@r-project.org
Subject: Re: [R] Time-series analysis with treatment effects - statistical
approach
Hi Mike, here's a sample of my data so that you get an idea what I'm working
with.
Thanks, data
Dear R users,
I have a question about numerical integration in R.
I am facing the 'non-finite function value' error while integrating the
function
xf(x)
using 'integrate'. f(x) is a probability density function and assumed to
follow the three parameter (min = 0)
I would like to subset data from a larger dataset and generate a smaller
dataset. However, I don't want to use sample() because it does it randomly.
I would like to take non-random subsamples, for example, every 2nd number,
or every 3rd number. Is there a procedure that does this?
Thanks,
Hi R-users,
I'm attempting to fit a number of mixed models, all with the same
structure, across a spatial grid with data points collected at various
time points within each grid cell. I'm trying to use a 'for' loop to try
the model fit on each grid cell. In some cells lme does not converge,
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