David,
thank you for your reply
I tried this
attach(mtcars)
interaction.plot(cyl, gear, mpg, type=o, pch=5:8, lty=1 )
but I got this error:
Error in match.arg(type) : 'arg' should be one of l, p, b
and in ?interaction.plot, o it is not listed in type arguments.
Is there any other
Hello, I am using the following script to run an anova for numerous species
in a table that I have:
SiteSpp -
c(ADHALP,ADLCON,ADLARC,BDALAT,BDPARC,BDLCON,BDLARC,AWCAQU,AWERUS,AWEANG,AWDPSI,BWCSTA,BWHPAU,BWETRI,BWERUS,BWDFIS,BWPARC,BWLCON,BWLARC,BWJBIG)
n.SiteSpp - length(SiteSpp)
for (i in
Dear R users,
I am trying to do the forest plot follow the function given on web. However,
the order of the tests has been sorted alphabetically. I would prefer
keeping the order as data frame input so that I can group and compare (from
the graph) the target immune NS1, IgG and IgM (where SD,
I am a new R user. I trying to install a package all Matching but failed.
Here is the error msg.
install.packages(Matching, dependencies=TRUE)
Installing package(s) into ‘C:/Users/jzhu/Documents/R/win-library/2.13’
(as ‘lib’ is unspecified)
--- Please select a CRAN mirror for use in this session
Not reproducible.
Could you please attach the dataset
QInflAvgbyPlot
Otherwise I don't see anything obviously wrong here.
Ciao!
mario
On 30-Sep-11 01:37, kelseyann wrote:
SiteSpp-
Dave, your situation is clearer now. You wrote (see the full context at
the end of the message):
From this, you will see that I have 4 control sites and 7 treatment
sites that are measured each week. All 13 locations have different
names, and Location is a random varaible. Is Location
Hi,
yes, I had a look at pgfSweave package and realised that it uses texi2dvi to
compile the pdf file.
I tried so much last night again that I am not entirely sure whether it is
the same Rnw file or not.
I just deleted everything and created a new R-project including a tiny
example. I also
Hi Chris,
why not using routines for dates
dates - c(09/10/2003, 10/22/2005)
format(strptime(dates,format=%m/%d/%Y),%Y)
or take just the last 4 chars from dates
gsub(.*([0-9]{4})$,\\1,dates)
cheers
Am 29.09.2011 16:23, schrieb Chris Conner:
Help-Rs,
I'm doing some string manipulation in a
The byte pixies have rolled up R-2.13.2.tar.gz at 9:00 this morning. This is
intended to be the final release of the 2.13 series, for the benefit of those
apprehensive of putting 2.14.x into production use.
The run-in for 2.14.0 starts on Monday, with a planned release on Oct 31 (The
Great
On Sep 30, 2011, at 08:32 , Mario Valle wrote:
Not reproducible.
Could you please attach the dataset
QInflAvgbyPlot
Otherwise I don't see anything obviously wrong here.
Ciao!
mario
On 30-Sep-11 01:37, kelseyann wrote:
SiteSpp-
On 29.09.2011 22:38, Ben qant wrote:
Hello,
Why does rm.outlier produce a list for me? I know its something about my
data because I can't make a mock up that reproduces the issue.
Any ideas? My data goes in as a matrix and comes out as a list:
class(dat)
[1] matrix
str(dat)
would be
Dear all,
I have a numeric vector that contains indices.
I also have two matrices of [1,m] dimension and of [m,n] dimension.
I want for every indexto remove the current element from the [1,m] vector an
the row from the [m,n] matrix.
How I can do that efficiently in R? So to say not have a for
Hi,
I currently running regression models on an experimental dataset.
The model contains one independent continuous variable and two independent
experimental conditions (one with two factors, the other with three factors)
and several covariates.
Now I get different results for a covariate in
Hi:
This would be a lot easier to check with a reproducible example, but
here's a simplified version of your problem:
testd - data.frame(gps = rep(c(ADHALP,ADLCON,ADLARC,BDALAT,BDPARC),
each = 15),
trt = rep(LETTERS[1:3], each = 5),
Dear list,
I ran a conditional frailty model with an interaction term (see below). To
interpret the interaction term, I would like to produce plots that reflect
how does a moderator variable (ecogr) shape the effect of the other
interacted variable (elderly).
condfrailty.gamma.em
Hi R-helpers
I'm looking for a vectorised function which does missing value replacement
as in last observation carried forward in the zoo package but instead of a
locf, I would like the locf function to add +1 to each time a missing value
occurred. See below for an example.
require(zoo)
x -
Hi all,
I was wondering if there's an equivalent to par(new=T) of the plot
function in lattice. I'm plotting an xyplot, and I would like to
highlight one point by plotting that one point again using a different
symbol.
For example, where 6 is highlighted:
plot(1:10, xlim=c(0,10), ylim=c(0,10))
Hi!
I'm trying to implement in R in an easy way the negative reflection method
described in Silverman (1986) on p.31, ie I have a non-negative dataset and
would like to estimate the density by applying a reflection method where the
reflected points have weight -1.
I thought there should be a way
Thanks a lot !
At the end I found that the problem was in the data input. Once I normilized
the data input to use the chord distance as measure of dissimilarity
gaps_flor_norm-decostand(gaps_flor, norm), then I run the nMDS several
times comparing them through procrustes
sorry, I managed to find the solution at last
(by reading the help but sometime is really difficult!)
Class POSIXlt is a named list of vectors representing
yday
0–365: day of the year.
another lesson learned
bye
--
View this message in context:
Hi,
I am trying to fit all subsets for a vector autoregression with exogenous
variables. I have been looking at the 'leaps' function but I not sure how
to get it to work when lags for each variable are included in the model. I
would be really appreciative if someone could provide some links to
i want to use getdata function in sampling package. but if in the vector of
index i write only 1( thats what i need) it gives the entire dataframe.(but
instead of 1 if i give 2 or 3 it extracts the information corresponding to
those indices).can anyone please help me?
--
View this message in
here is an alternative long and winded solution to the problem sticking on
the julian function of chron package
test$year - as.integer(as.character(test$date, %Y))
test$month - as.integer(as.character(test$date, %m))
test$day - as.integer(as.character(test$date, %d))
test$hour -
Hi
I'm creating a sweave (Rnw) from R and running the r code inside the
sweave and then creating report from sweave file using R.
If any error occurs in the running R code inside the sweeve file. it should
stop entire R process itself
Please help me to solve this
--
View this message in
Try this. As you did not supply a reproducible example my code is untested:
1.m.vector[index.vector] - NULL
or
new.1.m.vector - 1.m.vector[- index.vector]
Someting equivalent is possible for the matrix.
HTH
Jannis
On 09/30/2011 11:30 AM, Alaios wrote:
Dear all,
I have a numeric vector
On Fri, 30 Sep 2011, Martin Batholdy wrote:
Hi,
I currently running regression models on an experimental dataset.
The model contains one independent continuous variable and two
independent experimental conditions (one with two factors, the other
with three factors) and several covariates.
Hi:
One way is to create a vector of pch values that you can pass into xyplot, e.g.,
dd - data.frame(x = 1:10, y = 1:10, pch = c(rep(1, 5), 16, rep(1, 4)))
library('lattice')
xyplot(y ~ x, data = dd, pch = dd$pch, col = 1)
HTH,
Dennis
On Fri, Sep 30, 2011 at 12:01 AM, Kang Min
Dear Joshua and others,
Please excuse the slow response, but I wanted to consult other R Foundation
members before answering.
The R Foundation is coincidentally discussing fund-raising and the use of funds
that are raised by the Foundation. There are costs associated with keeping R
going,
On Fri, Sep 30, 2011 at 4:47 AM, maxbre mbres...@arpa.veneto.it wrote:
here is an alternative long and winded solution to the problem sticking on
the julian function of chron package
test$year - as.integer(as.character(test$date, %Y))
test$month - as.integer(as.character(test$date, %m))
On Fri, Sep 30, 2011 at 5:43 AM, Jan Wijffels jwijff...@bnosac.be wrote:
Hi R-helpers
I'm looking for a vectorised function which does missing value replacement
as in last observation carried forward in the zoo package but instead of a
locf, I would like the locf function to add +1 to each
Let's say I have written the following tiny .Rnw file:
_
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{Sweave}
\usepackage{tikz}
\usepackage{pgf}
\begin{document}
=
sessionInfo()
@
\end{document}
We have data on habitat use of a bird species (30 radio-tracked individuals).
We followed each bird every day for ~45 min for 6 weeks. We recorded a
number of things, each minute (a device would beep every minute and we would
write down a number of variables). I recorded for example at what kind
On 30/09/2011 8:03 AM, syrvn wrote:
Let's say I have written the following tiny .Rnw file:
_
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{Sweave}
\usepackage{tikz}
\usepackage{pgf}
\begin{document}
=
sessionInfo()
@
On Fri, Sep 30, 2011 at 3:01 AM, Kang Min ngokang...@gmail.com wrote:
Hi all,
I was wondering if there's an equivalent to par(new=T) of the plot
function in lattice. I'm plotting an xyplot, and I would like to
highlight one point by plotting that one point again using a different
symbol.
Am 30.09.2011 11:30, schrieb Alaios:
Dear all,
I have a numeric vector that contains indices.
I also have two matrices of [1,m] dimension and of [m,n] dimension.
I want for every indexto remove the current element from the [1,m] vector an
the row from the [m,n] matrix.
How I can do that
Hello,
I am very new to R (as my Subject probably indicates).
I want to do something that should, I think, be very simple. I have five
vectors in a list and I want to construct a covariance matrix out of them.
Given a 5X5 matrix cvm1, and the list of vectors, cvm1_list, I thought the
following
Hello
I have a data set with fixed and random effects, therefore I am using the lme
function:
lm(y ~ xfixed, random=~1|xrandom, data)
After this I want to get the F-values for both the fixed and random predictors.
I can easily get the F-value and df for the xfixed predictors (anova()), but
Hi zoe,
it's easy in a spreadsheet to calculate the p-value; estimates/stand.error =
1.965%-1.96
for the asymmetry you must use:
model=mGJR.est(eps1=#1, eps2=#2, order=c(1,1,1))
mvBEKK.diag(model)
cheers
--
View this message in context:
Michael Weylandt wrote:
I'm not entirely sure how these two objects are related. Perhaps give a
little more information on the transform and we can help with
implementation...
Ok, I have got 2 matrices [P,I] and [I,E].
testcontents [P,I]:
structure(list(P = structure(c(1L, 1L, 1L, 2L,
If there is an ONLINE mechanism, I will donate.
j
Joshua Wiley wrote:
Dear R Users,
I know issues like this have come up in the past. I am wondering how
many people would be interested in an online mechanism for donating to
the R Foundation or for becoming supporting members. Right now,
Hi Duncan,
I use Eclipse and StatET plus TexClipse and Sweave which comes with the
StatET package.
So fore me it is basically one click as well to produce the pdf from the
.Rnw file.
I installed the MacTex live 2011 version on my computer and thought it might
actually be
easy to find out how and
Without seeing cvm1_list, I can't guarantee this will work, but consider this:
testList = list(rnorm(500), rnorm(500), rnorm(500), rnorm(500), rnorm(500))
testMat = simplify2array(testList)
covTest = cov(testMat)
Running your code works on my testList, so I can't help there without
a
On Sep 30, 2011, at 4:50 AM, sreblam wrote:
Hi!
I'm trying to implement in R in an easy way the negative reflection
method
described in Silverman (1986) on p.31, ie I have a non-negative
dataset and
would like to estimate the density by applying a reflection method
where the
reflected
On 30/09/2011 10:00 AM, David Winsemius wrote:
On Sep 30, 2011, at 4:50 AM, sreblam wrote:
Hi!
I'm trying to implement in R in an easy way the negative reflection
method
described in Silverman (1986) on p.31, ie I have a non-negative
dataset and
would like to estimate the density by
On Sep 30, 2011, at 4:47 AM, maxbre wrote:
here is an alternative long and winded solution to the problem
sticking on
the julian function of chron package
test$year - as.integer(as.character(test$date, %Y))
test$month - as.integer(as.character(test$date, %m))
test$day -
On Fri, 30 Sep 2011, Rosario Garcia Gil wrote:
I have a data set with fixed and random effects, therefore I am using the lme
function:
Rosario,
Allow me to recommend reading Mixed Effects Models and Extentions in
Ecology with R by Zuur, et al. There are (potentially) serious limitations
Dear Luc,
IMHO a multinomial mixed model is appropriate for your data. It allows you to
model tree species with bird id and period as covariates. Have a look at the
vignette of the MCMCglmm package. You will find an example on hornets.
Best regards,
Thierry
PS R-sig-mixed models is a better
Dear R-users,
The following warning messages are displayed when I require a new package
that I am currently developing. Everything seems to work just fine though,
so I am wondering how to get rid of the warnings.
Warning messages:
1: Class frame is defined (with package slot 'kiwixposepreprod')
Dear all,
I would like to put these two lines together
logictoReduce-((Overloads-1)%%FreqN)==(SpanIndex-1) #0...3 refer to sub spans
1 to 4
Overloads-Overloads[logictoReduce==TRUE]
and do it like this
Overloads-Overloads[((Overloads-1)%%FreqN)==(SpanIndex-1)]
which does not seem to work.
On Sep 30, 2011, at 10:14 AM, Duncan Murdoch wrote:
On 30/09/2011 10:00 AM, David Winsemius wrote:
On Sep 30, 2011, at 4:50 AM, sreblam wrote:
Hi!
I'm trying to implement in R in an easy way the negative
reflection
method
described in Silverman (1986) on p.31, ie I have a
Dear R users,
two quick questions about MCMCpoissonChange of the MCMCpack:
1. my data is stored into a vector (e.g. my_data), and as input for
MCMCpoissonChange I need either a formula or a data frame.
If I simply transform my vector to a data frame with data.frame(my_data), it
does not work.
On Sep 30, 2011, at 10:14 AM, Duncan Murdoch wrote:
On 30/09/2011 10:00 AM, David Winsemius wrote:
On Sep 30, 2011, at 4:50 AM, sreblam wrote:
Hi!
I'm trying to implement in R in an easy way the negative
reflection
method
described in Silverman (1986) on p.31, ie I have a
Happy Friday fellow R users.
I need some help - I am trying to make a graph using ggplot 2 of some lead
isotope ratios. Normally, the isotope mass number appears as a superscript
before the chemical symbol. However, I cannot figure out how to do this
ggplot2's axis labels. The closest I have
On first glance it seems like it should work, perhaps a minimal
working example would help.
Also, if logictoReduce is a boolean vector, you probably don't need to
test for equality with TRUE; if that test seems necessary (i.e., if
Overloads - Overloads[logictoReduce] doesn't work) that may be
Dear all,
I have a vector with number that some of them are part of the
seq(1,800,4). How can I check which of the numbers belong to the seq(1,800,4)
LEt's say that is called myvector the vector with the numbers.
Is there in R something like this?
is.member(myvector,seq(1,800,4))
I would
The error message was:
! LaTeX Error: File `test-003.tikz' not found.
So I'm wondering how your StatET tried to compile the tex file,
especially what was its working directory.
Anyway, I recommend you to turn off the compilation to PDF in
pgfSweave() so that it only generates the tex file, and
On Sep 30, 2011, at 12:25 PM, Alaios wrote:
Dear all,
I have a vector with number that some of them are part of the
seq(1,800,4). How can I check which of the numbers belong to the
seq(1,800,4)
LEt's say that is called myvector the vector with the numbers.
Is there in R something like
5 %in% seq(1,800,4)
[1] TRUE
4 %in% seq(1,800,4)
[1] FALSE
or
is.element(5, seq(1,800,4))
[1] TRUE
is.element(4, seq(1,800,4))
[1] FALSE
Sarah
On Fri, Sep 30, 2011 at 12:25 PM, Alaios ala...@yahoo.com wrote:
Dear all,
I have a vector with number that some of them are part of the
I'm about to add weights to a bus on-board survey dataset with ~150 variables
and ~28,000 records. My intention is to weight (for each bus run) by
boarding stop and alighting stop. I've seen the Rake function of the Survey
package, but it seems that converting to a svydesign might be
Thank you for the obvious help - I already saw this thread. But I thought
this described the standard reflection method (which I managed to implement).
In my case, I want to achieve a NEGATIVE reflection which is *not* the same as
the method where you simply reflect the data, estimate the
R-listers,
My colleagues and I are working on wind roses using station
information and we have a question regarding the plotting of rings of
the wind rose (see attached for example).
What we would like to do is to add an extra frequency ring to the wind
rose, so it goes up to 15% for instance
Hi, I'm no longer on the subscribing list, but was hoping to get my question
posted. Please inform if this is ok, although I am guessing you wont post with
the image below. If so, let me know and I will resend without the image.
Thanks
Hi,
I just upgraded my system and my version of R all
Suppose that I'm working on Hadley's diamond dataset and I want to
review the relationship between price, colour and carat.
I might run the following:
library(ggplot2)
#plot scatter and add some hex binning
q-qplot(carat,price,data=diamonds, geom=c(hex),
main=Variability of
On Sep 30, 2011, at 2:16 AM, Petr PIKAL wrote:
David,
thank you for your reply
I tried this
attach(mtcars)
interaction.plot(cyl, gear, mpg, type=o, pch=5:8, lty=1 )
but I got this error:
Error in match.arg(type) : 'arg' should be one of l, p, b
and in ?interaction.plot, o it is not listed
is.element(myvector, seq(1,800,4))
or, if you like typing percent signs,
myvector %in% seq(1,800,4)
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Alaios
Sent:
First, we strongly recommend 64-bit R. Otherwise, you may not be able
to scale up as far as you would like.
Second, as I think you realize, with big objects you may have to do
things in chunks. I generally recommend working a column at a time
rather than in blocks of rows if possible (better
On Fri, Sep 30, 2011 at 4:31 PM, Durant, James T. (ATSDR/DTEM/PRMSB)
h...@cdc.gov wrote:
Happy Friday fellow R users.
I need some help - I am trying to make a graph using ggplot 2 of some lead
isotope ratios. Normally, the isotope mass number appears as a superscript
before the chemical
On 9/29/2011 8:11 PM, wirichada wrote:
Dear R users,
I am trying to do the forest plot follow the function given on web. However,
the order of the tests has been sorted alphabetically. I would prefer
keeping the order as data frame input so that I can group and compare (from
the graph) the
From ?image
Images for large z on a regular grid are more efficient with useRaster
enabled and can prevent rare anti-aliasing artifacts, but may not be
supported by all graphics devices.
Adding useRaster=TRUE to the two image() calls gets rid of the white grid
lines.
-Original
On 9/29/2011 8:14 PM, Jp zhu wrote:
I am a new R user. I trying to install a package all Matching but failed.
Here is the error msg.
install.packages(Matching, dependencies=TRUE)
Installing package(s) into ‘C:/Users/jzhu/Documents/R/win-library/2.13’
(as ‘lib’ is unspecified)
--- Please select
Hi,
How do I use a function inside a regression formula? When I tried to use
min() function inside a regression formula, I ran into errors. Here are
the commands to reproduce the error:
mydata - read.csv(url(http://www.ats.ucla.edu/stat/r/dae/binary.csv;))
attach(mydata)
names(mydata)
Thank you Michael.
I think my initial problem may have been due to a 'clerical error' upriver,
so I appreciate you taking the time to give me this help.
Unfortunately, my version of R does not contain simplify2array() and does
not find it in help (?simplify2array) - which is strange because I
This may be a simple misunderstanding on my part, but I need help
understanding what POT is plotting. I'm trying to analyze a few different
datasets. If my dataset covers 500 years, but I have 60 points above my
threshold, what should be plotted as the (empirical) return period for the
largest
I can't figure out how to add tick marks on both my X and Y axis. For example,
my X axis ranges from 0 to 1 and there are both a tick mark and a number label
at the X-axis values of 0.2,0.4,0.6. and 0.8. I want to add tick marks to the
figure at every 0.1 value. This will help a viewer
On 30/09/2011 2:07 PM, Jim Cheng wrote:
Hi,
How do I use a function inside a regression formula? When I tried to use
min() function inside a regression formula, I ran into errors. Here are
the commands to reproduce the error:
mydata-
On 9/30/2011 8:31 AM, Durant, James T. (ATSDR/DTEM/PRMSB) wrote:
Happy Friday fellow R users.
I need some help - I am trying to make a graph using ggplot 2 of some lead isotope
ratios. Normally, the isotope mass number appears as a superscript before the chemical
symbol. However, I cannot
I don't have access to older versions of R right now, but if you have a recent
install you are probably running 2.13.1 or 2.13.0. Can you run the following:
X - list(a= rnorm(5), b= rnorm(5))
sapply(X, min)
?
sapply calls simplify2array() so if this works take a look at the code for
sapply
Thanks a lot! This works.
Now I want to do the opposite
let's say that I have one sequence
for example
check in image
http://imageshack.us/photo/my-images/4/unleduso.png/
column A (this is a seq(1,113,4)
and I want when I get the number 9 to say that this is the third number in the
seq
Someone already suggested that you use match(),
which does what I think you want. Read its help file
for details.
A - seq(1,113,4)
match(c(9, 17, 18), A)
[1] 3 5 NA
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
From: Alaios [mailto:ala...@yahoo.com]
Sent: Friday, September 30, 2011
Just for the record, following Bill Dunlap's advice, I think this is
the best answer to the question as originally posed is.
myfun - function(vec, i=stop('i' must be supplied)){
vec[i]
}
myfun(1:40,10)
[1] 10
myfun(1:10)
Error in myfun(1:10) : 'i' must be supplied
--
Paul E. Johnson
Hi,
There is a question that I am confused.
I have a set of data like this:
hsa-miR-205--GATA30.797882767 1.08E-13
hsa-miR-205--ITGB4 0.750217593 1.85E-11
hsa-miR-187--PGF0.797604155 3.24E-11
hsa-miR-205--SERPINB5 0.744124886 3.28E-11
hsa-miR-205--PBX1 0.734487224 7.89E-11
2011/9/12 Göran Broström goran.brost...@gmail.com
Dear Ehsan,
the cluster option is not implemented in 'eha', although you obviously get
no error if trying
I'll fix this. Thanks for the report. (So, use 'coxph' with cluster).
Actually, there is nothing to fix; the cluster function
On Sep 30, 2011, at 2:10 PM, Mike Gibson wrote:
I can't figure out how to add tick marks on both my X and Y axis.
For example, my X axis ranges from 0 to 1 and there are both a tick
mark and a number label at the X-axis values of 0.2,0.4,0.6. and
0.8. I want to add tick marks to the
Thanks, that kind of helps. However, some of my previous code uses functions
like heatmap.2 which has multiple images (legend/color key) as well as the
actual heatmap. Employing useRaster=TRUE here only applies to the heatmap and
not the legend. Not a huge deal. Is there anyway to set an
I had the same problem on Windows and I was only a regular administrator.
However, going to properties of the Rprofile.site and setting the file's
all privileges for regular users fixed the problem. Tinn R was able to
confiure the environment permanently.
--
View this message in context:
have a piecewise function which takes a constant value for x greater than
some point.
It looks like this:
y-function(x,a){
if (xa+3)
{
y=(x-a)^2
}else{
y=9
}
return(y)
}
In practice, I do not know where this point, a, starts.
I would like to find a minimum of
Dear listserv,
Please consider the following dataset:
x - matrix(nrow = 8, ncol = 2)
colnames(matrix) - c(classification, soluble_fiber)
x[1:4,1] - bagel
x[5:8,1] - donut
How would I simulate a dataset for a one-way fixed-effect ANOVA (where
classification is the treatment variable and
hey all, I'm just getting used to R and i'm having issues when it comes to
reading my data in rows rather than columns. any good advice would be much
appreciated !
here is the error:
data1 - read.table(file.choose(),header=T)
x1 - c(data1[1,1:5])
shapiro.test(x1)
Error in sort.int(x, na.last
Hi Jiang,
where did you get that definition of the Benjamini-Hochberg correction? That is
simply not how it works. You can take a look at the original paper, it is
available online
(http://www.math.tau.ac.il/~ybenja/MyPapers/benjamini_hochberg1995.pdf). You
can also look at the p.adjust
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Dear all,
I am confused with the output of survfit.coxph.
Someone said that the survival given by summary(survfit.coxph) is the
baseline survival S_0, but some said that is the survival S=S_0^exp{beta*x}.
Which one is correct?
By the way, if I use newdata= in the survfit, does that mean the
Hello: I am a novice R user, but I have been working my way through the
manuals / tutorials, ... I have R / Deducer up and running, and know the
basics.
I want to analyze a microarray (gene expression) dataset.
I need to input the data into R as a multidimensional (multi-way) array,
something
I realize that this is terribly basic, but I just don't seem to see it at this
moment, so I would very much appreciate your help.
How shall I transform this dataframe:
df1
Name Index Value
1 a 1 0.1
2 a 2 0.2
3 a 3 0.3
4 a 4 0.4
5 b 1 2.1
6 b
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