[R] Downloading tab separated data from internet
Hi all, I am trying to download some tab separated data from the internet. The data is not available directly at the URL that could be known apriori. There is an intermediate form where start and end dates have to be given to get to the required page. For example, I want to download data for a station 03015795. The form for this station is at: http://ida.water.usgs.gov/ida/available_records.cfm?sn=03015795 I could get the start date and end date from this form using: # # Specifying station and reading from the opening form stn-03015795 myurl-paste(http://ida.water.usgs.gov/ida/available_records.cfm?sn=,stn,sep=;) mypage1 = readLines(myurl) # Getting the start and end dates mypattern = 'td align=center([^]*)/td' datalines = grep(mypattern, mypage1[124], value=TRUE) getexpr = function(s,g)substring(s,g,g+attr(g,'match.length')-1) gg = gregexpr(mypattern, datalines) matches = mapply(getexpr,datalines,gg) result = gsub(mypattern,'\\1',matches) names(result)=NULL mydates-result[1:2] I want to know how I can feed these start and end dates to the form and execute the button to go to the data page and then to download the data, either as displayed in the browser or by saving as a file. Any help on this is most appreciated. Thanks. HC -- View this message in context: http://r.789695.n4.nabble.com/Downloading-tab-separated-data-from-internet-tp4152318p4152318.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] simple lm question
Sigh Please note that your df and M are undoubtedly different
objects by now:
Right. Not my most coherent day.
thanks
W
M - matrix(runif(5*20), nrow=20)
colnames(M) - c('a', 'b', 'c', 'd', 'e')
l1 - lm(e~., data=as.data.frame(M))
l1
Call:
lm(formula = e ~ ., data = as.data.frame(M))
Coefficients:
(Intercept)abcd
0.40139 -0.15032 -0.06242 0.13139 0.23905
l3 - lm(M[,5]~M[,1]+M[,2]+M[,3]+M[,**4])
l3
Call:
lm(formula = M[, 5] ~ M[, 1] + M[, 2] + M[, 3] + M[, 4])
Coefficients:
(Intercept) M[, 1] M[, 2] M[, 3] M[, 4]
0.40139 -0.15032 -0.06242 0.13139 0.23905
As expected.
--
David.
On Sat, Dec 3, 2011 at 5:10 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
In your code by supplying a vector M[,e] you are regressing e
against all the variables provided in the data argument, including e
itself -- this gives the very strange regression coefficients you
observe. R has no way to know that that's somehow related to the e
it sees in the data argument.
In the suggested way,
lm(formula = e ~ ., data = as.data.frame(M))
e is regressed against everything that is not e and sensible results are
given.
But still 'l1 - lm(e~., data=df)' is not the same as 'l3 -
lm(M[,5]~M[,1]+M[,2]+M[,3]+M[,**4])'
M - matrix(runif(5*20), nrow=20)
colnames(M) - c('a', 'b', 'c', 'd', 'e')
l1 - lm(e~., data=df)
summary(l1)
Call:
lm(formula = e ~ ., data = df)
Residuals:
Min 1Q Median 3Q Max
-0.38343 -0.21367 0.03067 0.13757 0.49080
Coefficients:
Estimate Std. Error t value Pr(|t|)
(Intercept) 0.285210.29477 0.9680.349
a0.092830.30112 0.3080.762
b0.239210.22425 1.0670.303
c -0.160270.24154 -0.6640.517
d0.240250.20054 1.1980.250
Residual standard error: 0.2871 on 15 degrees of freedom
Multiple R-squared: 0.1602,Adjusted R-squared: -0.06375
F-statistic: 0.7153 on 4 and 15 DF, p-value: 0.5943
l3 - lm(M[,5]~M[,1]+M[,2]+M[,3]+M[,**4])
summary(l3)
Call:
lm(formula = M[, 5] ~ M[, 1] + M[, 2] + M[, 3] + M[, 4])
Residuals:
Min 1Q Median 3Q Max
-0.36355 -0.22679 -0.01202 0.18462 0.37377
Coefficients:
Estimate Std. Error t value Pr(|t|)
(Intercept) 0.769720.24501 3.142 0.00672 **
M[, 1] -0.238300.24123 -0.988 0.33890
M[, 2] -0.020460.21958 -0.093 0.92699
M[, 3] -0.295180.22559 -1.308 0.21040
M[, 4] -0.315450.24570 -1.284 0.21866
---
Signif. codes: 0 *** 0.001 ** 0.01 * 0.05 . 0.1 1
Residual standard error: 0.2668 on 15 degrees of freedom
Multiple R-squared: 0.2762,Adjusted R-squared: 0.08317
F-statistic: 1.431 on 4 and 15 DF, p-value: 0.272
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West Hartford, CT
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[R] Problem installing Rtools
I'm a new user to R and recently installed R 2.14 for Windows 7 (64 bit). I have downloaded and ran Rtools 2.14 but do not see any new packages in the install packages section of R. I installed Rtools in a subdirectory to the /library/ directory. Does anyone have any idea what I could be doing wrong? Thanks! -- View this message in context: http://r.789695.n4.nabble.com/Problem-installing-Rtools-tp4152013p4152013.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] help in removal of fixed pattern
Hi I have column name as given below If the variable is in log(X1 + 1) pattern it should be removed and i need only X1 Input log(x1 + 1) x2 log(X3 +1) Expected Output X1 X2 X3 Please help me -- View this message in context: http://r.789695.n4.nabble.com/help-in-removal-of-fixed-pattern-tp4152524p4152524.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Reading multiple text files and then combining into a dataframe
I have a multiple text files, separated by a single space, that I need to combine into a single data.frame. Below is the track I'm on using list.files to capture the names of the files and then lapply with read.table. But I run into problems making a usable dataframe out of the data. #Creating example data in similar format to data I have sub - rep(1,10) trial - seq(1,10,1) size - rep(3,10) shortest - rep(444,10) startlab - rep(444,10) endlab - rep(444,10) startconf - rep(444,10) endconf - rep(444,10) steps - sample(1:30,10) time - sample(1:300,10) #creating example of text file and saving into a shared director with other txt files subject1 - cbind(sub1,trial,size,shortest,startlab,endlab,startconf,endconf,steps,time) write.table(subject1, C:Folder/R/subject1.txt, sep= ) #2nd example of same text file sub - rep(2,10) trial - seq(1,10,1) size - rep(3,10) shortest - rep(444,10) startlab - rep(444,10) endlab - rep(444,10) startconf - rep(444,10) endconf - rep(444,10) steps - sample(1:30,10) time - sample(1:300,10) subject1 - cbind(sub1,trial,size,shortest,startlab,endlab,startconf,endconf,steps,time) write.table(subject1, C:Folder/R/subject2.txt, sep= ) setwd(C:Folder/R/) #Getting list of file names file_name - list.files(pattern=subject*) mydata - lapply (file_name, read.table, sep= , header=T, row.names=NULL) Thank you, James [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] partial mantel tests in ecodist with intential NA values.
I would like to perform partial mantel tests on only within group values, with between group values assigned to NA. This is possible in package ncf partial.mantel.test, however this sues a different permutation to that used in ecodist.ecodist will not accept data with NA values, returning a matrix is not square error. is it possible to perform this test in ecodist? many thanks Nevil Amos library(ecodist) library(ncf) x-sample(1:1000,20) y-sample(1:1000,20) z-sample(1:1000,20) M1-as.matrix( distance(x)) M2 -as.matrix( distance(y )) M3-as.matrix( distance(z )) D1-(lower(M1)) D2-(lower(M2)) D3-(lower(M3)) mantel(D1 ~ D2+D3, nperm=1000) mantelr pval1 pval2 pval3 llim.2.5% ulim.97.5% 0.09014696 0.1030 0.8980 0.1840 0.01857311 0.18468621 partial.mantel.test(M1,M2,M3,quiet=T) $MantelR r12 r13 r23 r12.3 r13.2 0.08977575 0.02170997 -0.01561346 0.09014696 0.02320821 $p [1] 0.09590410 0.30769231 0.47552448 0.09490509 0.30169830 $call [1] partial.mantel.test(M1 = M1, M2 = M2, M3 = M3, quiet = T) attr(,class) [1] partial.Mantel M1[1:10,11:20]-NA M1[11:20,1:10]-NA D1-(lower(M1)) mantel(D1 ~ D2+D3, nperm=1000) Error in mantel(D1 ~ D2 + D3, nperm = 1000) : Matrix not square. partial.mantel.test(M1,M2,M3,quiet=T) $MantelR r12 r13 r23r12.3r13.2 0.054906562 0.003446670 -0.015613460 0.054967403 0.004310979 $p [1] 0.2837163 0.4275724 0.4555445 0.2857143 0.4235764 $call [1] partial.mantel.test(M1 = M1, M2 = M2, M3 = M3, quiet = T) attr(,class) [1] partial.Mantel Warning message: In partial.mantel.test(M1, M2, M3, quiet = T) : Missing values exist; Pairwise deletion will be used __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Downloading tab separated data from internet
AFAICS what you mean is 'how can I fill in an HTML form using R'. Answer: use package RCurl. Do study the posting guide: none of the 'at a minimum' information was given here. On 03/12/2011 04:47, HC wrote: Hi all, I am trying to download some tab separated data from the internet. The data is not available directly at the URL that could be known apriori. There is an intermediate form where start and end dates have to be given to get to the required page. For example, I want to download data for a station 03015795. The form for this station is at: http://ida.water.usgs.gov/ida/available_records.cfm?sn=03015795 I could get the start date and end date from this form using: # # Specifying station and reading from the opening form stn-03015795 myurl-paste(http://ida.water.usgs.gov/ida/available_records.cfm?sn=,stn,sep=;) mypage1 = readLines(myurl) # Getting the start and end dates mypattern = 'td align=center([^]*)/td' datalines = grep(mypattern, mypage1[124], value=TRUE) getexpr = function(s,g)substring(s,g,g+attr(g,'match.length')-1) gg = gregexpr(mypattern, datalines) matches = mapply(getexpr,datalines,gg) result = gsub(mypattern,'\\1',matches) names(result)=NULL mydates-result[1:2] I want to know how I can feed these start and end dates to the form and execute the button to go to the data page and then to download the data, either as displayed in the browser or by saving as a file. Any help on this is most appreciated. Thanks. HC -- Brian D. Ripley, rip...@stats.ox.ac.uk Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UKFax: +44 1865 272595 __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Help! Big problem when using browser() to do R debugging?
On Sat, Dec 3, 2011 at 2:38 AM, Michael comtech@gmail.com wrote: Hi all, Could you please help me? I am having the following weird problem when debugging R programs using browser(): In my function, I've inserted a browser() in front of Step 1. My function has 3 steps and at the end of each step, it will print out the message Step i is done... However, after I hit ENTER when the program stopped before Step 1 and entered into the debugging mode, it not only executed the next line(i.e. the Step 1), but also all the (many) remaining lines in that function, as shown below: Browse[1] [1] Step 1 is done.. [1] Step 2 is done.. [1] Step 3 is done.. Then it automatically quited the debugging mode and when I tried to check the value of myobj, I've got the following error message: names(myobj) Error: object 'myobj' not found No suitable frames for recover() So my question is: why did one key stroke ENTER lead it to execute all the remaining lines in that function and then returned from the function and quited the debugging mode? As soon as you get into 'debug' mode, type 'n', hit enter, then you can simply hit enter to evaluate the fun step by step. To exit the step-by-step, type 'c' and hit enter: this will evaluate the rest of the function. Regards Liviu Thanks a lot! __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Do you know how to read? http://www.alienetworks.com/srtest.cfm http://goodies.xfce.org/projects/applications/xfce4-dict#speed-reader Do you know how to write? http://garbl.home.comcast.net/~garbl/stylemanual/e.htm#e-mail __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Problem installing Rtools
On 11-12-02 10:25 PM, stillerfan wrote: I'm a new user to R and recently installed R 2.14 for Windows 7 (64 bit). I have downloaded and ran Rtools 2.14 but do not see any new packages in the install packages section of R. I installed Rtools in a subdirectory to the /library/ directory. Does anyone have any idea what I could be doing wrong? Rtools doesn't contain R packages, it contains various compilers and tools that you could use to build R and R packages. So you should install it in its own directory. I usually use c:/Rtools. Duncan Murdoch __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Project local libraries (reproducible research)
On 12/03/2011 06:04 AM, Hadley Wickham wrote: Hi all, I was wondering if any one had scripts that they could share for capturing the current version of R packages used for a project. I'm interested in creating a project local library so that you're safe if someone (e.g. the ggplot2 author) updates a package you're relying on and breaks your code. I could fairly easily hack together, but I was wondering if any one had any neat scripts they'd care to share. Hi Hadley, This makes quite a few assumptions, but I would build a list of packages called in R scripts: # get all calls to library or require in a subdirectory of scripts packagestrings-c(system(grep library *.R,intern=TRUE), system(grep require *.R,intern=TRUE)) # get the unique package names packagenames-unique(sapply(strsplit(packagestrings,[()]),[,2)) # get the information on all installed packages in the system installedpackages-installed.packages() # get the indices of the packages used in the subdirectory whichpackages-which(match(rownames(installedpackages),packagenames,0)0) # get the version information for each used package installedpackages[whichpackages,Built] Jim __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Data alignment
Hello! I have a data.frame which looks like: Name - Value A - 400 A - 300 B - 200 B - 350 C - 500 C - 350 D - 450 D - 600 E - 700 E - 750 F - 630 F - 650 I want to add another column where all A,B should get an index 1, all C,D an index of 2 and all E,F an index of 3 so that the data.frame looks like: ID - Name - Value 1 - A - 400 1 - A - 300 1 - B - 200 1 - B - 350 2 - C - 500 2 - C - 350 2 - D - 450 2 - D - 600 3 - E - 700 3 - E - 750 3 - F - 630 3 - F - 650 My data.frame is quite big so I cannot add all values by hand. Cheers -- View this message in context: http://r.789695.n4.nabble.com/Data-alignment-tp4153024p4153024.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] side-by-side map with different geographies using spplot
David Epstein davideps at umich.edu writes: Hello, I want to create side-by-side maps of similar attribute data in two different cities using a single legend. To simply display side-by-side census block group boundary (non-thematic) maps for Minneapolis Cleveland I do the following: I can display a single thematic map for a city using spplot as follows: spplot(Minneapolis,Thematic_Data_Column) The spplot function uses lattice graphics, so you may use the standard methods for the trellis objects that it returns. If you did something like: sp_out_Minneapolis - spplot(Minneapolis, your_var) print(sp_out_Minneapolis, split=c(1, 1, 2, 1), more=TRUE) sp_out_Cleveland - spplot(Cleveland, your_var) print(sp_out_,Cleveland split=c(2, 1, 2, 1), more=FALSE) you will get some of the way there. If in addition you would like only one legend using the same breaks and colours, you'll need to use appropriate arguments to spplot() in both calls to handle this. It may be worth considering posting queries of this kind on R-sig-geo, as response may be forthcoming more quickly there. Hope this helps, Roger thank you, -david __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] partial mantel tests in ecodist with intential NA values.
It is not possible in ecodist, and I'd be wary of doing it in other packages. Instead, I would consider the model matrix approach described in Legendre and Fortin 1989. Sarah On Saturday, December 3, 2011, Nevil Amos nevil.a...@gmail.com wrote: I would like to perform partial mantel tests on only within group values, with between group values assigned to NA. This is possible in package ncf partial.mantel.test, however this sues a different permutation to that used in ecodist.ecodist will not accept data with NA values, returning a matrix is not square error. is it possible to perform this test in ecodist? many thanks Nevil Amos library(ecodist) library(ncf) x-sample(1:1000,20) y-sample(1:1000,20) z-sample(1:1000,20) M1-as.matrix( distance(x)) M2 -as.matrix( distance(y )) M3-as.matrix( distance(z )) D1-(lower(M1)) D2-(lower(M2)) D3-(lower(M3)) mantel(D1 ~ D2+D3, nperm=1000) mantelr pval1 pval2 pval3 llim.2.5% ulim.97.5% 0.09014696 0.1030 0.8980 0.1840 0.01857311 0.18468621 partial.mantel.test(M1,M2,M3,quiet=T) $MantelR r12 r13 r23 r12.3 r13.2 0.08977575 0.02170997 -0.01561346 0.09014696 0.02320821 $p [1] 0.09590410 0.30769231 0.47552448 0.09490509 0.30169830 $call [1] partial.mantel.test(M1 = M1, M2 = M2, M3 = M3, quiet = T) attr(,class) [1] partial.Mantel M1[1:10,11:20]-NA M1[11:20,1:10]-NA D1-(lower(M1)) mantel(D1 ~ D2+D3, nperm=1000) Error in mantel(D1 ~ D2 + D3, nperm = 1000) : Matrix not square. partial.mantel.test(M1,M2,M3,quiet=T) $MantelR r12 r13 r23r12.3r13.2 0.054906562 0.003446670 -0.015613460 0.054967403 0.004310979 $p [1] 0.2837163 0.4275724 0.4555445 0.2857143 0.4235764 $call [1] partial.mantel.test(M1 = M1, M2 = M2, M3 = M3, quiet = T) attr(,class) [1] partial.Mantel Warning message: In partial.mantel.test(M1, M2, M3, quiet = T) : Missing values exist; Pairwise deletion will be used __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Sarah Goslee http://www.stringpage.com http://www.sarahgoslee.com http://www.functionaldiversity.org [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data alignment
I doubt your data frame looks like that, with all the -, but regardless you can use ifelse() to construct your column. Sarah On Saturday, December 3, 2011, syrvn ment...@gmx.net wrote: Hello! I have a data.frame which looks like: Name - Value A - 400 A - 300 B - 200 B - 350 C - 500 C - 350 D - 450 D - 600 E - 700 E - 750 F - 630 F - 650 I want to add another column where all A,B should get an index 1, all C,D an index of 2 and all E,F an index of 3 so that the data.frame looks like: ID - Name - Value 1 - A - 400 1 - A - 300 1 - B - 200 1 - B - 350 2 - C - 500 2 - C - 350 2 - D - 450 2 - D - 600 3 - E - 700 3 - E - 750 3 - F - 630 3 - F - 650 My data.frame is quite big so I cannot add all values by hand. Cheers -- View this message in context: http://r.789695.n4.nabble.com/Data-alignment-tp4153024p4153024.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Sarah Goslee http://www.stringpage.com http://www.sarahgoslee.com http://www.functionaldiversity.org [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help in removal of fixed pattern
You can use gsub() to replace parts of strings. Sarah On Saturday, December 3, 2011, arunkumar akpbond...@gmail.com wrote: Hi I have column name as given below If the variable is in log(X1 + 1) pattern it should be removed and i need only X1 Input log(x1 + 1) x2 log(X3 +1) Expected Output X1 X2 X3 Please help me -- View this message in context: http://r.789695.n4.nabble.com/help-in-removal-of-fixed-pattern-tp4152524p4152524.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Sarah Goslee http://www.stringpage.com http://www.sarahgoslee.com http://www.functionaldiversity.org [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data alignment
try this: match(x$Name x - read.table(text = Name - Value + A - 400 + A - 300 + B - 200 + B - 350 + C - 500 + C - 350 + D - 450 + D - 600 + E - 700 + E - 750 + F - 630 + F - 650, header = TRUE, as.is = TRUE) map - data.frame(key = c(A, B, C, D, E, F) + , value = c( 1, 1, 2, 2, 3, 3) + , stringsAsFactors = FALSE + ) x$ID - map$value[match(x$Name, map$key)] x Name X. Value ID 1 A - 400 1 2 A - 300 1 3 B - 200 1 4 B - 350 1 5 C - 500 2 6 C - 350 2 7 D - 450 2 8 D - 600 2 9 E - 700 3 10E - 750 3 11F - 630 3 12F - 650 3 On Sat, Dec 3, 2011 at 7:06 AM, Sarah Goslee sarah.gos...@gmail.com wrote: I doubt your data frame looks like that, with all the -, but regardless you can use ifelse() to construct your column. Sarah On Saturday, December 3, 2011, syrvn ment...@gmx.net wrote: Hello! I have a data.frame which looks like: Name - Value A - 400 A - 300 B - 200 B - 350 C - 500 C - 350 D - 450 D - 600 E - 700 E - 750 F - 630 F - 650 I want to add another column where all A,B should get an index 1, all C,D an index of 2 and all E,F an index of 3 so that the data.frame looks like: ID - Name - Value 1 - A - 400 1 - A - 300 1 - B - 200 1 - B - 350 2 - C - 500 2 - C - 350 2 - D - 450 2 - D - 600 3 - E - 700 3 - E - 750 3 - F - 630 3 - F - 650 My data.frame is quite big so I cannot add all values by hand. Cheers -- View this message in context: http://r.789695.n4.nabble.com/Data-alignment-tp4153024p4153024.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Sarah Goslee http://www.stringpage.com http://www.sarahgoslee.com http://www.functionaldiversity.org [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Reading multiple text files and then combining into a dataframe
Does this do it for you: #Creating example data in similar format to data I have sub - rep(1,10) trial - seq(1,10,1) size - rep(3,10) shortest - rep(444,10) startlab - rep(444,10) endlab - rep(444,10) startconf - rep(444,10) endconf - rep(444,10) steps - sample(1:30,10) time - sample(1:300,10) #creating example of text file and saving into a shared director with other txt files subject1 - + cbind(sub,trial,size,shortest,startlab,endlab,startconf,endconf,steps,time) write.table(subject1, /temp/subject1.txt, sep= ) #2nd example of same text file sub - rep(2,10) trial - seq(1,10,1) size - rep(3,10) shortest - rep(444,10) startlab - rep(444,10) endlab - rep(444,10) startconf - rep(444,10) endconf - rep(444,10) steps - sample(1:30,10) time - sample(1:300,10) subject1 - + cbind(sub,trial,size,shortest,startlab,endlab,startconf,endconf,steps,time) write.table(subject1, /temp/subject2.txt, sep= ) setwd(/temp) #Getting list of file names file_name - list.files(pattern=subject*) mydata - lapply (file_name, read.table, sep= , header=T, row.names=NULL) # rbind to dataframe mydf - do.call(rbind, mydata) # or use the plyr package require(plyr) mydf.1 - ldply(file_name, read.table, sep = ' ', header = TRUE, row.names = NULL) str(mydf) 'data.frame': 20 obs. of 11 variables: $ row.names: chr 1 2 3 4 ... $ sub : int 1 1 1 1 1 1 1 1 1 1 ... $ trial: int 1 2 3 4 5 6 7 8 9 10 ... $ size : int 3 3 3 3 3 3 3 3 3 3 ... $ shortest : int 444 444 444 444 444 444 444 444 444 444 ... $ startlab : int 444 444 444 444 444 444 444 444 444 444 ... $ endlab : int 444 444 444 444 444 444 444 444 444 444 ... $ startconf: int 444 444 444 444 444 444 444 444 444 444 ... $ endconf : int 444 444 444 444 444 444 444 444 444 444 ... $ steps: int 10 28 20 18 4 21 5 3 8 7 ... $ time : int 225 188 205 189 103 227 148 221 275 14 ... str(mydf.1) 'data.frame': 20 obs. of 11 variables: $ row.names: chr 1 2 3 4 ... $ sub : int 1 1 1 1 1 1 1 1 1 1 ... $ trial: int 1 2 3 4 5 6 7 8 9 10 ... $ size : int 3 3 3 3 3 3 3 3 3 3 ... $ shortest : int 444 444 444 444 444 444 444 444 444 444 ... $ startlab : int 444 444 444 444 444 444 444 444 444 444 ... $ endlab : int 444 444 444 444 444 444 444 444 444 444 ... $ startconf: int 444 444 444 444 444 444 444 444 444 444 ... $ endconf : int 444 444 444 444 444 444 444 444 444 444 ... $ steps: int 10 28 20 18 4 21 5 3 8 7 ... $ time : int 225 188 205 189 103 227 148 221 275 14 ... On Fri, Dec 2, 2011 at 11:51 PM, James Holland holland.ag...@gmail.com wrote: I have a multiple text files, separated by a single space, that I need to combine into a single data.frame. Below is the track I'm on using list.files to capture the names of the files and then lapply with read.table. But I run into problems making a usable dataframe out of the data. #Creating example data in similar format to data I have sub - rep(1,10) trial - seq(1,10,1) size - rep(3,10) shortest - rep(444,10) startlab - rep(444,10) endlab - rep(444,10) startconf - rep(444,10) endconf - rep(444,10) steps - sample(1:30,10) time - sample(1:300,10) #creating example of text file and saving into a shared director with other txt files subject1 - cbind(sub1,trial,size,shortest,startlab,endlab,startconf,endconf,steps,time) write.table(subject1, C:Folder/R/subject1.txt, sep= ) #2nd example of same text file sub - rep(2,10) trial - seq(1,10,1) size - rep(3,10) shortest - rep(444,10) startlab - rep(444,10) endlab - rep(444,10) startconf - rep(444,10) endconf - rep(444,10) steps - sample(1:30,10) time - sample(1:300,10) subject1 - cbind(sub1,trial,size,shortest,startlab,endlab,startconf,endconf,steps,time) write.table(subject1, C:Folder/R/subject2.txt, sep= ) setwd(C:Folder/R/) #Getting list of file names file_name - list.files(pattern=subject*) mydata - lapply (file_name, read.table, sep= , header=T, row.names=NULL) Thank you, James [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Sweave problem on Mac OS when using umlauts and summary()
I just noticed that the question has already been answered on the R-help list
before:
http://r.789695.n4.nabble.com/Sweave-font-problems-with-Signif-codes-lines-td977346.html
Adding the following R line solves the problem:
options(useFancyQuotes = FALSE)
Mark
On Fri, Dec 2, 2011 at 4:08 PM, Mark Heckmann mark.heckm...@gmx.de wrote:
I have the following Sweave file which gets sweaved correctly.
=
m - lm(y1 ~x1, anscombe)
summary(m)
@
I include the sweaved .tex file into another .tex file via include.
When I use a single umlaut in the .snw file a warning occurs.
As a result part of the summary output is not contained in the .tex file.
ä
=
m - lm(y1 ~x1, anscombe)
summary(m)
@
You can now run (pdf)latex on 'ch1.tex'
Warnmeldungen:
1: ch1.Snw has unknown encoding: assuming Latin-1
2: ungültige Zeichenkette in Konvertierung der Ausgabe (wrong character in
conversion of output)
Interestingly, this error does NOT occur, when I omit the summary(m)
statement.
ä
=
m - lm(y1 ~x1, anscombe)
#summary(m)
@
You can now run (pdf)latex on 'ch1.tex'
Warnmeldung:
ch1.Snw has unknown encoding: assuming Latin-1
I know that I can prevent this by adding a line at the beginning of the .snw
file:
\usepackage[utf8]{inputenc}
ä
=
m - lm(y1 ~x1, anscombe)
summary(m)
@
This gets sweaved correctly without warnings:
But this solution is not good as it is not the preamble of the .tex document
where I add the usepackage line.
This will cause an error when processing the entire document with tex.
How can I achieve the last result in another way?
I tried:
Sweave('/Users/markheckmann/Desktop/test_sweave/ch1.Snw', encoding=UFT-8)
But this does not work either when the usepackage line is omitted.
I am stuck here. Can anyone help?
TIA
Mark
Mark Heckmann
Blog: www.markheckmann.de
R-Blog: http://ryouready.wordpress.com
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Mark Heckmann
Blog: www.markheckmann.de
R-Blog: http://ryouready.wordpress.com
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data alignment
Thanks for your suggestions. I will try them. The - in my original post was actually only there to serve as a separator so that it is easier for you to see the data structure but apparently it rather confused you... sorry :) -- View this message in context: http://r.789695.n4.nabble.com/Data-alignment-tp4153024p4153112.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] problems using the thin plate spline method
Dear R users, I am a beginner in R trying to apply the thin plate spline method to my climate data. I used the example in R to do so, and the lines seem to run fine ( I am not getting errors) but I am not getting any output in the form of graph or anything. I got a warning message saying that 'surface extends beyond box'. Any help is much appreciated. thanks minti __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Downloading tab separated data from internet
Thanks for your reply. I tried to use the postForm function of RCurl as below but do not have much clue as to how to go further with what it does. library(RCurl) stn-03015795 myurl-paste(http://ida.water.usgs.gov/ida/available_records.cfm?sn=,stn,sep=;) mypage1 = readLines(myurl) # Getting the start and end dates mypattern = 'td align=center([^]*)/td' datalines = grep(mypattern, mypage1[124], value=TRUE) getexpr = function(s,g)substring(s,g,g+attr(g,'match.length')-1) gg = gregexpr(mypattern, datalines) matches = mapply(getexpr,datalines,gg) result = gsub(mypattern,'\\1',matches) names(result)=NULL mydates-result[1:2] result = postForm(myurl,fromdate=mydates[1], todate=mydates[2],rtype=Save to File, submit1=Retrieve Data) I tried to read the RCurl's documentation but do not know what functions I should be using. Are there any examples available that could be helpful. Could you point me to those please. Thanks for the help. HC -- View this message in context: http://r.789695.n4.nabble.com/Downloading-tab-separated-data-from-internet-tp4152318p4153063.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] replace values
Hello, imagine the following data.frame: ID name 1 *_A 2 *_A 3 *_B 4 *_B * = can be any pattern I want to replace every row which ends with _A by 1 and every row which ends by _B with a 0 so that the data.frame looks like the following: ID name 1 1 2 1 3 0 4 0 Which function do I use best to achieve this? Cheers, Syrvn -- View this message in context: http://r.789695.n4.nabble.com/replace-values-tp4153301p4153301.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] replace values
On Dec 3, 2011, at 8:41 AM, syrvn wrote: Hello, imagine the following data.frame: ID name 1 *_A 2 *_A 3 *_B 4 *_B * = can be any pattern I want to replace every row which ends with _A by 1 and every row which ends by _B with a 0 You can use grep(patt, x, value=TRUE) to return vlaues that can be used in the prior answers to your earlier question today. I would have worked it out and tested the strategy, but you continue to fail to produce workable examples and then apologize that people are confused by them. We are NOT confused... only annoyed ... that you fail to use dput() or code for constructing workable code. -- David. so that the data.frame looks like the following: ID name 1 1 2 1 3 0 4 0 Which function do I use best to achieve this? Cheers, Syrvn -- View this message in context: http://r.789695.n4.nabble.com/replace-values-tp4153301p4153301.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. David Winsemius, MD West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Problem installing Rtools
Great, thanks for answering this basic question. On Sat, Dec 3, 2011 at 5:12 AM, Duncan Murdoch-2 [via R] ml-node+s789695n4152880...@n4.nabble.com wrote: On 11-12-02 10:25 PM, stillerfan wrote: I'm a new user to R and recently installed R 2.14 for Windows 7 (64 bit). I have downloaded and ran Rtools 2.14 but do not see any new packages in the install packages section of R. I installed Rtools in a subdirectory to the /library/ directory. Does anyone have any idea what I could be doing wrong? Rtools doesn't contain R packages, it contains various compilers and tools that you could use to build R and R packages. So you should install it in its own directory. I usually use c:/Rtools. Duncan Murdoch __ [hidden email] http://user/SendEmail.jtp?type=nodenode=4152880i=0mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- If you reply to this email, your message will be added to the discussion below: http://r.789695.n4.nabble.com/Problem-installing-Rtools-tp4152013p4152880.html To unsubscribe from Problem installing Rtools, click herehttp://r.789695.n4.nabble.com/template/NamlServlet.jtp?macro=unsubscribe_by_codenode=4152013code=bWFub2hhcmFuLmFydW5AZ21haWwuY29tfDQxNTIwMTN8ODM3MzcwMTE2 . NAMLhttp://r.789695.n4.nabble.com/template/NamlServlet.jtp?macro=macro_viewerid=instant_html%21nabble%3Aemail.namlbase=nabble.naml.namespaces.BasicNamespace-nabble.view.web.template.NabbleNamespace-nabble.view.web.template.InstantMailNamespacebreadcrumbs=instant+emails%21nabble%3Aemail.naml-instant_emails%21nabble%3Aemail.naml-send_instant_email%21nabble%3Aemail.naml -- View this message in context: http://r.789695.n4.nabble.com/Problem-installing-Rtools-tp4152013p4153350.html Sent from the R help mailing list archive at Nabble.com. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] problems using the thin plate spline method
I can tell that you are puzzled and confused. Unfortunately, I am not psychic, so I cannot tell what you did, and therefore cannot tell where you went astray. The solution is for you to read the posting guide mentioned at the bottom of every R-help message. Spend a little time to create a small bit of data like yours if your actual data is large (subset and dput are useful for this). Remember to include the output of sessionInfo, and so on. Many times you are likely to find the answer yourself by going through these steps, but they are essential for communication. Good luck. --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. Mintewab Bezabih mintewab.beza...@economics.gu.se wrote: Dear R users, I am a beginner in R trying to apply the thin plate spline method to my climate data. I used the example in R to do so, and the lines seem to run fine ( I am not getting errors) but I am not getting any output in the form of graph or anything. I got a warning message saying that 'surface extends beyond box'. Any help is much appreciated. thanks minti __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Iteration in R
Hi, I need help. I am trying to iterate this command x - rnorm(100, 1.0, 2.0) one hundred times in R but I don't seem to have a clue. Can anyone help? Your help is very much appreciated. Martin [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Problem with loop
Hi, Thank Michael for your help. Komine -- View this message in context: http://r.789695.n4.nabble.com/Problem-with-loop-tp4148083p4154147.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Iteration in R
? replicate or a for loop or do all one hundred simulations at once x - matrix(rnorm(100^2, 1, 2), 100) It's going to depend on what you want to do with the numbers. Michael On Sat, Dec 3, 2011 at 1:10 PM, Martin Zonyrah martin20...@yahoo.com wrote: Hi, I need help. I am trying to iterate this command x - rnorm(100, 1.0, 2.0) one hundred times in R but I don't seem to have a clue. Can anyone help? Your help is very much appreciated. Martin [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Counting the occurences of a charater within a string
On Thu, Dec 1, 2011 at 10:32 AM, Douglas Esneault douglas.esnea...@mecglobal.com wrote: I am new to R but am experienced SAS user and I was hoping to get some help on counting the occurrences of a character within a string at a row level. My dataframe, x, is structured as below: Col1 abc/def ghi/jkl/mno I found this code on the board but it counts all occurrences of / in the dataframe. chr.pos - which(unlist(strsplit(x,NULL))=='/') chr.count - length(chr.pos) chr.count [1] 3 I'd like to append a column, say cnt, that has the count of / for each row. Here's an easy way from stringr: library(stringr) str_count( c(abc/def, ghi/jkl/mno), /) # [1] 1 2 Hadley -- Assistant Professor / Dobelman Family Junior Chair Department of Statistics / Rice University http://had.co.nz/ __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Iteration in R
On Dec 3, 2011, at 1:10 PM, Martin Zonyrah wrote: Hi, I need help. I am trying to iterate this command x - rnorm(100, 1.0, 2.0) one hundred times in R but I don't seem to have a clue. ?replicate == David Winsemius, MD West Hartford, CT __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Iteration in R
Hi. One approach is using replicate. See ?replicate: replicate(3,rnorm(100,1,2)) Andrija On Sat, Dec 3, 2011 at 7:10 PM, Martin Zonyrah martin20...@yahoo.comwrote: Hi, I need help. I am trying to iterate this command x - rnorm(100, 1.0, 2.0) one hundred times in R but I don't seem to have a clue. Can anyone help? Your help is very much appreciated. Martin [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Iteration in R
Hi Michael, How would you do this with lapply to return a list? I can't seem to get that to work (I haven't used these much and am trying to learn). Thanks Brad Michael Weylandt wrote ? replicate or a for loop or do all one hundred simulations at once x - matrix(rnorm(100^2, 1, 2), 100) It's going to depend on what you want to do with the numbers. Michael On Sat, Dec 3, 2011 at 1:10 PM, Martin Zonyrah lt;martin2005z@gt; wrote: Hi, I need help. I am trying to iterate this command x - rnorm(100, 1.0, 2.0) one hundred times in R but I don't seem to have a clue. Can anyone help? Your help is very much appreciated. Martin [[alternative HTML version deleted]] __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://r.789695.n4.nabble.com/Iteration-in-R-tp4154433p4154479.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Iteration in R
Hi Brad. Maybe something like this: lapply(rep(1,6), function(x) rnorm(10,0,1)) Andrija On Sat, Dec 3, 2011 at 8:21 PM, B77S bps0...@auburn.edu wrote: Hi Michael, How would you do this with lapply to return a list? I can't seem to get that to work (I haven't used these much and am trying to learn). Thanks Brad Michael Weylandt wrote ? replicate or a for loop or do all one hundred simulations at once x - matrix(rnorm(100^2, 1, 2), 100) It's going to depend on what you want to do with the numbers. Michael On Sat, Dec 3, 2011 at 1:10 PM, Martin Zonyrah lt;martin2005z@gt; wrote: Hi, I need help. I am trying to iterate this command x - rnorm(100, 1.0, 2.0) one hundred times in R but I don't seem to have a clue. Can anyone help? Your help is very much appreciated. Martin [[alternative HTML version deleted]] __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://r.789695.n4.nabble.com/Iteration-in-R-tp4154433p4154479.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Iteration in R
Interesting and thank you; I'm confused as to why this doesn't work with: lapply(rep(1,6), FUN=rnorm, n=10, mean=1.0, sd=1) andrija djurovic wrote Hi Brad. Maybe something like this: lapply(rep(1,6), function(x) rnorm(10,0,1)) Andrija On Sat, Dec 3, 2011 at 8:21 PM, B77S lt;bps0002@gt; wrote: Hi Michael, How would you do this with lapply to return a list? I can't seem to get that to work (I haven't used these much and am trying to learn). Thanks Brad Michael Weylandt wrote ? replicate or a for loop or do all one hundred simulations at once x - matrix(rnorm(100^2, 1, 2), 100) It's going to depend on what you want to do with the numbers. Michael On Sat, Dec 3, 2011 at 1:10 PM, Martin Zonyrah lt;martin2005z@gt; wrote: Hi, I need help. I am trying to iterate this command x - rnorm(100, 1.0, 2.0) one hundred times in R but I don't seem to have a clue. Can anyone help? Your help is very much appreciated. Martin [[alternative HTML version deleted]] __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://r.789695.n4.nabble.com/Iteration-in-R-tp4154433p4154479.html Sent from the R help mailing list archive at Nabble.com. __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://r.789695.n4.nabble.com/Iteration-in-R-tp4154433p4154559.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Iteration in R
And with replicate: replicate(100, rnorm(100, 1,2), simplify = FALSE) Michael On Sat, Dec 3, 2011 at 2:38 PM, andrija djurovic djandr...@gmail.com wrote: Hi Brad. Maybe something like this: lapply(rep(1,6), function(x) rnorm(10,0,1)) Andrija On Sat, Dec 3, 2011 at 8:21 PM, B77S bps0...@auburn.edu wrote: Hi Michael, How would you do this with lapply to return a list? I can't seem to get that to work (I haven't used these much and am trying to learn). Thanks Brad Michael Weylandt wrote ? replicate or a for loop or do all one hundred simulations at once x - matrix(rnorm(100^2, 1, 2), 100) It's going to depend on what you want to do with the numbers. Michael On Sat, Dec 3, 2011 at 1:10 PM, Martin Zonyrah lt;martin2005z@gt; wrote: Hi, I need help. I am trying to iterate this command x - rnorm(100, 1.0, 2.0) one hundred times in R but I don't seem to have a clue. Can anyone help? Your help is very much appreciated. Martin [[alternative HTML version deleted]] __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://r.789695.n4.nabble.com/Iteration-in-R-tp4154433p4154479.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Iteration in R
Because lapply() tries to pass an argument to FUN and there's none that it can receive. This would work however: lapply(rep(100, 6), rnorm, mean = 1, sd = 2) Michael On Sat, Dec 3, 2011 at 2:42 PM, B77S bps0...@auburn.edu wrote: Interesting and thank you; I'm confused as to why this doesn't work with: lapply(rep(1,6), FUN=rnorm, n=10, mean=1.0, sd=1) andrija djurovic wrote Hi Brad. Maybe something like this: lapply(rep(1,6), function(x) rnorm(10,0,1)) Andrija On Sat, Dec 3, 2011 at 8:21 PM, B77S lt;bps0002@gt; wrote: Hi Michael, How would you do this with lapply to return a list? I can't seem to get that to work (I haven't used these much and am trying to learn). Thanks Brad Michael Weylandt wrote ? replicate or a for loop or do all one hundred simulations at once x - matrix(rnorm(100^2, 1, 2), 100) It's going to depend on what you want to do with the numbers. Michael On Sat, Dec 3, 2011 at 1:10 PM, Martin Zonyrah lt;martin2005z@gt; wrote: Hi, I need help. I am trying to iterate this command x - rnorm(100, 1.0, 2.0) one hundred times in R but I don't seem to have a clue. Can anyone help? Your help is very much appreciated. Martin [[alternative HTML version deleted]] __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://r.789695.n4.nabble.com/Iteration-in-R-tp4154433p4154479.html Sent from the R help mailing list archive at Nabble.com. __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@ mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- View this message in context: http://r.789695.n4.nabble.com/Iteration-in-R-tp4154433p4154559.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Moving column averaging
I don't know the answer, but would suppose not. You could test this for yourself using: system.time() example: system.time(rnorm(10,0,1)) Chega wrote This solved my problem - Thanks a lot for your help! Please allow me one more question: Works zoo's rollapply on a plain matrix faster than on a zoo object? I am asking since I wanted to apply the provided averaging code to a larger matrix (2500 rows x 200 cols), which is quite time consuming... Thanks again! Chega From: B77S [via R] lt;ml-node+s789695n4143909h3@.nabblegt; To: Chega lt;chegaga@gt; Sent: Friday, December 2, 2011 6:16 AM Subject: Re: Moving column averaging Sorry for that, and thanks Gabor, I could have sworn that it wouldn't. Gabor Grothendieck wrote On Thu, Dec 1, 2011 at 7:13 PM, B77S [hidden email] wrote: # need zoo to use rollapply() # your data (I called df) df - structure(list(a = 1:2, b = 2:3, c = c(5L, 9L), d = c(9L, 6L), e = c(1L, 5L), f = c(4, 7)), .Names = c(a, b, c, d, e, f), class = data.frame, row.names = c(NA, -2L)) # transpose and make a zoo object df2 - zoo(t(df)) #rollapply to get means and transpose back means - t(rollapply(df2, width=2, by=2, FUN=mean)) # adding the combined column names you requested colnames(means) - apply(matrix(names(df), nrow=2), 2, paste, collapse=, ) Note that zoo's rollapply also works on plain matrices and vectors. -- Statistics Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com __ [hidden email] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. If you reply to this email, your message will be added to the discussion below: http://r.789695.n4.nabble.com/Moving-column-averaging-tp4130179p4143909.html To unsubscribe from Moving column averaging, click here. NAML -- View this message in context: http://r.789695.n4.nabble.com/Moving-column-averaging-tp4130179p4154770.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Shading the plot
Hi all, I have been trying to shade the specific part of the plot Part to be shaded 1. Any color whenever a2a3 2. Any other color( Not same as 1) whenever a2a3 Suggest me some code for this task PLOT CODE for reference ## a2-c(81.96392786,81.96392786,82.16432866,82.56513026,82.76553106,79.96593186,78.16633267, 75.56713427,74.76753507,72.96793587,70.96793587,45.96793587,83.96793587,84.36873747, 84.56913828,84.56913828,84.56913828,84.56913828,84.36873747,84.36873747) a3-c(81.96392786,81.96392786,81.96392786,70.96392786,68.16432866,66.16432866, 62.16432866,58.56513026,56.56513026,54.56513026,48.56513026,49.76553106,52.76553106, 54.76553106,57.96593186,59.36673347,83.36673347,83.36673347,83.36673347, 83.56713427) plot(a2,type='l',col='red',ylab='',xlab= ,axes=FALSE) lines(a3,col='blue',ylab='',xlab= ) ## Thank you in the advance -- Avinash Barnwal Final year undergraduate student Statistics and informatics Department of Mathematics IIT Kharagpur attachment: Plot.png__ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Shading the plot
? polygon example(polygon) Michael On Sat, Dec 3, 2011 at 4:08 PM, avinash barnwal avinashbarnwal...@gmail.com wrote: Hi all, I have been trying to shade the specific part of the plot Part to be shaded 1. Any color whenever a2a3 2. Any other color( Not same as 1) whenever a2a3 Suggest me some code for this task PLOT CODE for reference ## a2-c(81.96392786,81.96392786,82.16432866,82.56513026,82.76553106,79.96593186,78.16633267, 75.56713427,74.76753507,72.96793587,70.96793587,45.96793587,83.96793587,84.36873747, 84.56913828,84.56913828,84.56913828,84.56913828,84.36873747,84.36873747) a3-c(81.96392786,81.96392786,81.96392786,70.96392786,68.16432866,66.16432866, 62.16432866,58.56513026,56.56513026,54.56513026,48.56513026,49.76553106,52.76553106, 54.76553106,57.96593186,59.36673347,83.36673347,83.36673347,83.36673347, 83.56713427) plot(a2,type='l',col='red',ylab='',xlab= ,axes=FALSE) lines(a3,col='blue',ylab='',xlab= ) ## Thank you in the advance -- Avinash Barnwal Final year undergraduate student Statistics and informatics Department of Mathematics IIT Kharagpur __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] Data Analysis for Gas Prices
Hi there, I'm looking to analyze a set of data on local gas prices for a single day. I'm wondering what kind of questions I should be looking to ask and how to find and answer to them with R. Examples would be: Do prices differ between brands? Does location affect (NE, NW, SE, SW) price? Does the number of nearby (within .25 miles) competitors affect price? Do gas stations near shopping centers or highways have different prices? Also, could anyone help me figure out how to import a data table to R? When I try to create a .txt file from a word document and read it in R, the format of the first column always messes up. Any/all help is appreciated. -- View this message in context: http://r.789695.n4.nabble.com/Data-Analysis-for-Gas-Prices-tp4155078p4155078.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Shading the plot
Hi Weylandt,
I tried it but i was not successful.
Here is the full code
Any help would be great.
time-c(02-Jan-05,09-Jan-05,16-Jan-05,23-Jan-05,30-Jan-05,06-Feb-05,13-Feb-05,20-Feb-05,27-Feb-05,06-Mar-05,13-Mar-05,
20-Mar-05,27-Mar-05,03-Apr-05,10-Apr-05,17-Apr-05,24-Apr-05,01-May-05,08-May-05,15-May-05)
time-as.Date(time,%d-%b-%y)
a2-c(81.96392786,81.96392786,82.16432866,82.56513026,82.76553106,79.96593186,78.16633267,
75.56713427,74.76753507,72.96793587,70.96793587,45.96793587,83.96793587,84.36873747,
84.56913828,84.56913828,84.56913828,84.56913828,84.36873747,84.36873747)
a3-c(81.96392786,81.96392786,81.96392786,70.96392786,68.16432866,66.16432866,
62.16432866,58.56513026,56.56513026,54.56513026,48.56513026,49.76553106,52.76553106,
54.76553106,57.96593186,59.36673347,83.36673347,83.36673347,83.36673347,
83.56713427)
j-0
for(i in 1:length(a3))
{
if(a2[i]a3[i])
{
j-j+1
x[j]-a2[i]
y[j]-a3[i]
temp_time[j]-time[i]
}
}
plot(time,a2,type='l',col='red',ylab='',xlab= ,axes=FALSE)
lines(time,a3,col='blue',ylab='',xlab= )
polygon(c(temp_time,rev(temp_time)),c(x,y),col=grey)
#
On Sun, Dec 4, 2011 at 2:46 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
? polygon
example(polygon)
Michael
On Sat, Dec 3, 2011 at 4:08 PM, avinash barnwal
avinashbarnwal...@gmail.com wrote:
Hi all,
I have been trying to shade the specific part of the plot
Part to be shaded
1. Any color whenever a2a3
2. Any other color( Not same as 1) whenever a2a3
Suggest me some code for this task
PLOT CODE for reference
##
a2-c(81.96392786,81.96392786,82.16432866,82.56513026,82.76553106,79.96593186,78.16633267,
75.56713427,74.76753507,72.96793587,70.96793587,45.96793587,83.96793587,84.36873747,
84.56913828,84.56913828,84.56913828,84.56913828,84.36873747,84.36873747)
a3-c(81.96392786,81.96392786,81.96392786,70.96392786,68.16432866,66.16432866,
62.16432866,58.56513026,56.56513026,54.56513026,48.56513026,49.76553106,52.76553106,
54.76553106,57.96593186,59.36673347,83.36673347,83.36673347,83.36673347,
83.56713427)
plot(a2,type='l',col='red',ylab='',xlab= ,axes=FALSE)
lines(a3,col='blue',ylab='',xlab= )
##
Thank you in the advance
--
Avinash Barnwal
Final year undergraduate student
Statistics and informatics
Department of Mathematics
IIT Kharagpur
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Avinash Barnwal
Final year undergraduate student
Statistics and informatics
Department of Mathematics
IIT Kharagpur
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] pivot table help
Hello R-users, I've got a huge table with about 20.00 rows and 50 columns. The table now has headers as Members1, Members2 etc. My data are 8 different individuals. And I've got a column with clusters. So each individual belongs to different clusters and can occurs multiple times within a cluster (that's the reason that there can be more than 8 members). I want a presence/ absence table for each individual within each cluster. So I want to go from: Cluster Member1Member2 etc. 1ind1 ind2 2ind3 ind1 3ind2 ind1 to clusterind1 ind2 ind3 11 1 0 210 1 31 1 0 Has anybody any idea how I can do this? I already tried alot of things with pivottables (using cast()) But I think I'm missing out on something. thank you -- View this message in context: http://r.789695.n4.nabble.com/pivot-table-help-tp4155144p4155144.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Data Analysis for Gas Prices
use a ? to get help on a function; example: ?read.table If you do this you will see an option called header... use header=T if your top row contains column names. Learn how to read these help pages. Also, read thru a few beginner R manuals and see this website: http://www.statmethods.net/interface/io.html As for the rest of your questions. Perhaps this is your sign to begin reading a intro-stats book, or inquire on a different forum. see: http://stats.stackexchange.com/questions good luck inferno846 wrote Hi there, I'm looking to analyze a set of data on local gas prices for a single day. I'm wondering what kind of questions I should be looking to ask and how to find and answer to them with R. Examples would be: Do prices differ between brands? Does location affect (NE, NW, SE, SW) price? Does the number of nearby (within .25 miles) competitors affect price? Do gas stations near shopping centers or highways have different prices? Also, could anyone help me figure out how to import a data table to R? When I try to create a .txt file from a word document and read it in R, the format of the first column always messes up. Any/all help is appreciated. -- View this message in context: http://r.789695.n4.nabble.com/Data-Analysis-for-Gas-Prices-tp4155078p4155185.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] pivot table help
Pivot tables are an Excel concept, not an R concept. That means you must give an example of your starting pivot table as an R object (use dump() so we can pick it up from the email and execute it immediately). and an example of the R object you want as the result. Use a trivial but complete example. An example of dump tmp - matrix(1:6,2,3) tmp dump(tmp,) Be sure to read the posting guide before sending your revised request. PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Rich On Sat, Dec 3, 2011 at 5:27 PM, set asta...@hotmail.com wrote: Hello R-users, I've got a huge table with about 20.00 rows and 50 columns. The table now has headers as Members1, Members2 etc. My data are 8 different individuals. And I've got a column with clusters. So each individual belongs to different clusters and can occurs multiple times within a cluster (that's the reason that there can be more than 8 members). I want a presence/ absence table for each individual within each cluster. So I want to go from: Cluster Member1Member2 etc. 1ind1 ind2 2ind3 ind1 3ind2 ind1 to clusterind1 ind2 ind3 11 1 0 210 1 31 1 0 Has anybody any idea how I can do this? I already tried alot of things with pivottables (using cast()) But I think I'm missing out on something. thank you -- View this message in context: http://r.789695.n4.nabble.com/pivot-table-help-tp4155144p4155144.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] pivot table help
try this: x - read.table(text = Cluster Member1Member2 + 1ind1 ind2 + 2ind3 ind1 + 3ind2 ind1, as.is = TRUE, header = TRUE) require(reshape2) x.m - melt(x, id = Cluster) x.m Cluster variable value 1 1 Member1 ind1 2 2 Member1 ind3 3 3 Member1 ind2 4 1 Member2 ind2 5 2 Member2 ind1 6 3 Member2 ind1 table(x.m$Cluster, x.m$value) ind1 ind2 ind3 1110 2101 3110 On Sat, Dec 3, 2011 at 5:53 PM, Richard M. Heiberger r...@temple.edu wrote: Pivot tables are an Excel concept, not an R concept. That means you must give an example of your starting pivot table as an R object (use dump() so we can pick it up from the email and execute it immediately). and an example of the R object you want as the result. Use a trivial but complete example. An example of dump tmp - matrix(1:6,2,3) tmp dump(tmp,) Be sure to read the posting guide before sending your revised request. PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Rich On Sat, Dec 3, 2011 at 5:27 PM, set asta...@hotmail.com wrote: Hello R-users, I've got a huge table with about 20.00 rows and 50 columns. The table now has headers as Members1, Members2 etc. My data are 8 different individuals. And I've got a column with clusters. So each individual belongs to different clusters and can occurs multiple times within a cluster (that's the reason that there can be more than 8 members). I want a presence/ absence table for each individual within each cluster. So I want to go from: Cluster Member1 Member2 etc. 1 ind1 ind2 2 ind3 ind1 3 ind2 ind1 to cluster ind1 ind2 ind3 1 1 1 0 2 1 0 1 3 1 1 0 Has anybody any idea how I can do this? I already tried alot of things with pivottables (using cast()) But I think I'm missing out on something. thank you -- View this message in context: http://r.789695.n4.nabble.com/pivot-table-help-tp4155144p4155144.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] pivot table help
Forgot, you can also do this: dcast(x.m, Cluster ~ value, fun = length) Cluster ind1 ind2 ind3 1 1110 2 2101 3 3110 On Sat, Dec 3, 2011 at 7:02 PM, jim holtman jholt...@gmail.com wrote: try this: x - read.table(text = Cluster Member1 Member2 + 1 ind1 ind2 + 2 ind3 ind1 + 3 ind2 ind1, as.is = TRUE, header = TRUE) require(reshape2) x.m - melt(x, id = Cluster) x.m Cluster variable value 1 1 Member1 ind1 2 2 Member1 ind3 3 3 Member1 ind2 4 1 Member2 ind2 5 2 Member2 ind1 6 3 Member2 ind1 table(x.m$Cluster, x.m$value) ind1 ind2 ind3 1 1 1 0 2 1 0 1 3 1 1 0 On Sat, Dec 3, 2011 at 5:53 PM, Richard M. Heiberger r...@temple.edu wrote: Pivot tables are an Excel concept, not an R concept. That means you must give an example of your starting pivot table as an R object (use dump() so we can pick it up from the email and execute it immediately). and an example of the R object you want as the result. Use a trivial but complete example. An example of dump tmp - matrix(1:6,2,3) tmp dump(tmp,) Be sure to read the posting guide before sending your revised request. PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. Rich On Sat, Dec 3, 2011 at 5:27 PM, set asta...@hotmail.com wrote: Hello R-users, I've got a huge table with about 20.00 rows and 50 columns. The table now has headers as Members1, Members2 etc. My data are 8 different individuals. And I've got a column with clusters. So each individual belongs to different clusters and can occurs multiple times within a cluster (that's the reason that there can be more than 8 members). I want a presence/ absence table for each individual within each cluster. So I want to go from: Cluster Member1 Member2 etc. 1 ind1 ind2 2 ind3 ind1 3 ind2 ind1 to cluster ind1 ind2 ind3 1 1 1 0 2 1 0 1 3 1 1 0 Has anybody any idea how I can do this? I already tried alot of things with pivottables (using cast()) But I think I'm missing out on something. thank you -- View this message in context: http://r.789695.n4.nabble.com/pivot-table-help-tp4155144p4155144.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.htmlhttp://www.r-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want to do it. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] help in removal of fixed pattern
A great function for extracting pattern matches is 'm()'
library(caroline)
vect - m('([xX][0-9])',df$Input)
toupper(vect) #in case you really want all upper case x's
It does the hard work of using 'sub' to remove the non-matching parts
(sub, grep, regexpr, etc aren't very good for this sort of thing)
It also can return a data.frame if you have multiple patterns you wish to
match in each string vector element.
-Dave
On Fri, 2 Dec 2011, arunkumar wrote:
Hi
I have column name as given below
If the variable is in log(X1 + 1) pattern it should be removed and i need
only X1
Input
log(x1 + 1)
x2
log(X3 +1)
Expected Output X1 X2 X3
Please help me
--
View this message in context:
http://r.789695.n4.nabble.com/help-in-removal-of-fixed-pattern-tp4152524p4152524.html
Sent from the R help mailing list archive at Nabble.com.
__
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and provide commented, minimal, self-contained, reproducible code.
__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] Shading the plot
On Dec 3, 2011, at 5:28 PM, avinash barnwal wrote:
Hi Weylandt,
I tried it but i was not successful.
Here is the full code
Any help would be great.
time-c(02-Jan-05,09-Jan-05,16-Jan-05,23-Jan-05,30-
Jan-05,06-Feb-05,13-Feb-05,20-Feb-05,27-Feb-05,06-
Mar-05,13-Mar-05,
20-Mar-05,27-Mar-05,03-Apr-05,10-Apr-05,17-Apr-05,24-
Apr-05,01-May-05,08-May-05,15-May-05)
time-as.Date(time,%d-%b-%y)
a2-
c
(81.96392786
,81.96392786
,82.16432866
,82.56513026,82.76553106,79.96593186,78.16633267,
75.56713427
,74.76753507
,72.96793587
,70.96793587,45.96793587,83.96793587,84.36873747,
84.56913828
,84.56913828
,84.56913828,84.56913828,84.36873747,84.36873747)
a3-
c
(81.96392786
,81.96392786
,81.96392786,70.96392786,68.16432866,66.16432866,
62.16432866
,58.56513026
,56.56513026
,54.56513026,48.56513026,49.76553106,52.76553106,
54.76553106
,57.96593186
,59.36673347,83.36673347,83.36673347,83.36673347,
83.56713427)
j-0
for(i in 1:length(a3))
{
if(a2[i]a3[i])
{
j-j+1
x[j]-a2[i]
y[j]-a3[i]
temp_time[j]-time[i]
}
}
plot(time,a2,type='l',col='red',ylab='',xlab= ,axes=FALSE)
lines(time,a3,col='blue',ylab='',xlab= )
polygon(c(temp_time,rev(temp_time)),c(x,y),col=grey)
#
What are the rules that govern requesting outside help in homework at
your institution?
Your current code does not recognize that there is line crossing. Nor
do you describe what you mean by shading. If you wanted a rectangle
within the lpot area it would drive one strategy and if you wanted
only the area between the curves to be shaded it would drive a
different strategy.
AND you never define x or y.
--
David.
On Sun, Dec 4, 2011 at 2:46 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
? polygon
example(polygon)
Michael
On Sat, Dec 3, 2011 at 4:08 PM, avinash barnwal
avinashbarnwal...@gmail.com wrote:
Hi all,
I have been trying to shade the specific part of the plot
Part to be shaded
1. Any color whenever a2a3
2. Any other color( Not same as 1) whenever a2a3
Suggest me some code for this task
PLOT CODE for reference
##
a2-
c
(81.96392786
,81.96392786
,82.16432866
,82.56513026,82.76553106,79.96593186,78.16633267,
75.56713427
,74.76753507
,72.96793587
,70.96793587,45.96793587,83.96793587,84.36873747,
84.56913828
,84.56913828
,84.56913828,84.56913828,84.36873747,84.36873747)
a3-
c
(81.96392786
,81.96392786
,81.96392786,70.96392786,68.16432866,66.16432866,
62.16432866
,58.56513026
,56.56513026
,54.56513026,48.56513026,49.76553106,52.76553106,
54.76553106
,57.96593186
,59.36673347,83.36673347,83.36673347,83.36673347,
83.56713427)
plot(a2,type='l',col='red',ylab='',xlab= ,axes=FALSE)
lines(a3,col='blue',ylab='',xlab= )
##
Thank you in the advance
--
Avinash Barnwal
Final year undergraduate student
Statistics and informatics
Department of Mathematics
IIT Kharagpur
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Avinash Barnwal
Final year undergraduate student
Statistics and informatics
Department of Mathematics
IIT Kharagpur
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] rnorm command
Hello, I use the command rnorm, and I feed these results into a lmer command. Since I am using the rnorm command I expect to get different results for each iteration, yet for each iteration I am getting the same answer. If someone understands why I am getting the same answer every time with a random number generator, I would appreciate help in understanding why this is happening. Is the lmer command causing the answer to be the same each time? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] density function always evaluating to zero
Dear R users,
I'm trying to carry out monte carlo integration of a posterior density
function which is the product of a normal and a gamma distribution. The
problem I have is that the density function always returns 0. How can I
solve this problem?
Here is my code
#generate data
x1 - runif(100, min = -10, max = 10)
y - 2 * x1^2 + rnorm(100)
# # # # # # # # Model 0 # # # # # # #
z - x1^2
M - sum(z^2)
MI - 1/M
zy - crossprod(z,y)
alpha.ols - MI * zy
resid_m0 - y - z * alpha.ols
s2_m0 - sum(resid_m0^2)/v
# use gibbs sampler to sample from posterior densities
n - length(y)
k - 1
v - n - k
# set up gibbs sampler
nrDraws - 1
h_sample_m0 - rgamma(nrDraws, v/2, v*s2_m0/2)
alpha_sample - matrix(0, nrow = nrDraws, ncol = 1)
for(i in 1:nrDraws) {
alpha_sample[i] - rnorm(1,alpha.ols,(1/h_sample_m0[i]) * MI)
}
# define posterior density for model 0
f - function(alpha,h) {
e - y - alpha * x1^2
const - (2*pi)^(-n/2) / ( gamma(v/2) * (v*s2_m1/2)^(-v/2) )
kernel - h^((v-1)/2) * exp((-(h/2) * sum(e^2)) - (v*s2_m0)*h)
x - const * kernel
return(x)
}
# calculate approximation of p(y|m_0)
m0 -f(alpha_sample,h_sample_m0)
post_m0 - sum(m0) / nrDraws
--
View this message in context:
http://r.789695.n4.nabble.com/density-function-always-evaluating-to-zero-tp4155181p4155181.html
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__
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
[R] Logistic Regression with genetic component
Greetings, I have a question that I'd like to get input on. I have a classic toxicology study where I artificially fertilized and exposed embryos to a chemical and counted defects. In addition, I kept track of male-female pairs that I used to artificially fertilize and generate embryos with. I need to use logistic regression to model the response, but also check that the genetics of the pairings did or did not have an effect on the response. My data looks a bit like this: response matrix chemical concentration Genetic Matrix Present AbsentMale Female 2 152 0.13 a 1 6 121 1 a 2 21 92 2 b 3 24 89 5 b 4 0141 10 c 5 5 95 15 c 6 R code: DA-cbind(Present, Absent) glm-(DA ~ chemical concentration) If I do glm-(DA ~ chemical concentration + Male + Female, I get every possible combination, but I only want specific pairs. So, I am thinking about doing: MF-cbind(Male, Female) glm-(DA ~ chemical concentration + MF) Is this correct? Any help on how to model this would be greatly appreciated! Thanks in advance! [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Shading the plot
Hi,
I apologies for my naive doubts
I have been trying it from a while. I need the area between the curve based
on conditions i wrote (whenever red line is above the blue line then area
between curves to be grey color and whenever blue line is above red line
then area between curves to be red color )
x and y are vectors
Thank you for replying
On Sun, Dec 4, 2011 at 7:56 AM, David Winsemius dwinsem...@comcast.netwrote:
On Dec 3, 2011, at 5:28 PM, avinash barnwal wrote:
Hi Weylandt,
I tried it but i was not successful.
Here is the full code
Any help would be great.
##**##**
time-c(02-Jan-05,09-Jan-**05,16-Jan-05,23-Jan-05,**
30-Jan-05,06-Feb-05,13-**Feb-05,20-Feb-05,27-Feb-**
05,06-Mar-05,13-Mar-05,
20-Mar-05,27-Mar-05,03-**Apr-05,10-Apr-05,17-Apr-**
05,24-Apr-05,01-May-05,**08-May-05,15-May-05)
time-as.Date(time,%d-%b-%y)
a2-c(81.96392786,81.**96392786,82.16432866,82.**
56513026,82.76553106,79.**96593186,78.16633267,
75.56713427,74.76753507,**72.96793587,70.96793587,**
45.96793587,83.96793587,**84.36873747,
84.56913828,84.56913828,**84.56913828,84.56913828,**
84.36873747,84.36873747)
a3-c(81.96392786,81.**96392786,81.96392786,70.**
96392786,68.16432866,66.**16432866,
62.16432866,58.56513026,**56.56513026,54.56513026,**
48.56513026,49.76553106,**52.76553106,
54.76553106,57.96593186,**59.36673347,83.36673347,**
83.36673347,83.36673347,
83.56713427)
j-0
for(i in 1:length(a3))
{
if(a2[i]a3[i])
{
j-j+1
x[j]-a2[i]
y[j]-a3[i]
temp_time[j]-time[i]
}
}
plot(time,a2,type='l',col='**red',ylab='',xlab= ,axes=FALSE)
lines(time,a3,col='blue',ylab=**'',xlab= )
polygon(c(temp_time,rev(temp_**time)),c(x,y),col=grey)
##**##**
#
What are the rules that govern requesting outside help in homework at your
institution?
Your current code does not recognize that there is line crossing. Nor do
you describe what you mean by shading. If you wanted a rectangle within the
lpot area it would drive one strategy and if you wanted only the area
between the curves to be shaded it would drive a different strategy.
AND you never define x or y.
--
David.
On Sun, Dec 4, 2011 at 2:46 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
? polygon
example(polygon)
Michael
On Sat, Dec 3, 2011 at 4:08 PM, avinash barnwal
avinashbarnwal...@gmail.com wrote:
Hi all,
I have been trying to shade the specific part of the plot
Part to be shaded
1. Any color whenever a2a3
2. Any other color( Not same as 1) whenever a2a3
Suggest me some code for this task
PLOT CODE for reference
##**##**
##**
a2-c(81.96392786,81.**96392786,82.16432866,82.**
56513026,82.76553106,79.**96593186,78.16633267,
75.56713427,74.76753507,**72.96793587,70.96793587,**
45.96793587,83.96793587,**84.36873747,
84.56913828,84.56913828,**84.56913828,84.56913828,**
84.36873747,84.36873747)
a3-c(81.96392786,81.**96392786,81.96392786,70.**
96392786,68.16432866,66.**16432866,
62.16432866,58.56513026,**56.56513026,54.56513026,**
48.56513026,49.76553106,**52.76553106,
54.76553106,57.96593186,**59.36673347,83.36673347,**
83.36673347,83.36673347,
83.56713427)
plot(a2,type='l',col='red',**ylab='',xlab= ,axes=FALSE)
lines(a3,col='blue',ylab='',**xlab= )
##**##**
##**
Thank you in the advance
--
Avinash Barnwal
Final year undergraduate student
Statistics and informatics
Department of Mathematics
IIT Kharagpur
__**
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/**listinfo/r-helphttps://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/**posting-guide.htmlhttp://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Avinash Barnwal
Final year undergraduate student
Statistics and informatics
Department of Mathematics
IIT Kharagpur
[[alternative HTML version deleted]]
__**
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/**listinfo/r-helphttps://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/**
posting-guide.html http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
--
Avinash Barnwal
Final year undergraduate student
Statistics and informatics
Department of Mathematics
IIT Kharagpur
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
[R] Prediction from censReg?
Hi - First post, so excuse any errors in protocol: Wanted to ask if there's an easy way to use 'predict' with objects of class 'censReg', 'maxLik', 'maxim' or 'list'. Have a left-censored dataset, attempting to use a Tobit model and am working with the censReg package. I like how easy it is to move from glm models to predictions with 'predict' and wanted to ask if there was a way to do so with objects output from 'censReg'. Thanks, Zack -- View this message in context: http://r.789695.n4.nabble.com/Prediction-from-censReg-tp4155855p4155855.html Sent from the R help mailing list archive at Nabble.com. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] upper bound in the integrate function depends on a parameter
Sorry for my English, is not my first language..
I have some trouble in terms of using integrate function in R.
fx is a function of m and x where m is supposed to be a unknown parameter.
fx=function(m,x){
+ x*2/(3*m)*(1-x/(3*m))
+ }
The problem is in upper bound, it depends on parameter m.
integrate(fx,lower=0,upper=3*m)$value
Is it possible to use the integrate function when bounds depend on a
parameter?
How to define m to solve this integral? The result should be m.
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Re: [R] density function always evaluating to zero
On Dec 3, 2011, at 5:42 PM, napps22 wrote:
Dear R users,
I'm trying to carry out monte carlo integration of a posterior density
function which is the product of a normal and a gamma distribution.
The
problem I have is that the density function always returns 0. How
can I
solve this problem?
Your code throws errors due to several missing objects due in part to
a missing v, but moving that higher in the code does not cure
everything. A missing 's2_m1' is also listed as a source of error.
You might want to try in a clean session and redo your debugging so
that you know what variables are in your workspace and their values.
The usual debugging method is to sprinkle print() statements in your
code to monitor where things might not be proceeding as planned.
--
David.
Here is my code
#generate data
x1 - runif(100, min = -10, max = 10)
y - 2 * x1^2 + rnorm(100)
# # # # # # # # Model 0 # # # # # # #
z - x1^2
M - sum(z^2)
MI - 1/M
zy - crossprod(z,y)
alpha.ols - MI * zy
resid_m0 - y - z * alpha.ols
s2_m0 - sum(resid_m0^2)/v
# use gibbs sampler to sample from posterior densities
n - length(y)
k - 1
v - n - k
# set up gibbs sampler
nrDraws - 1
h_sample_m0 - rgamma(nrDraws, v/2, v*s2_m0/2)
alpha_sample - matrix(0, nrow = nrDraws, ncol = 1)
for(i in 1:nrDraws) {
alpha_sample[i] - rnorm(1,alpha.ols,(1/h_sample_m0[i]) * MI)
}
# define posterior density for model 0
f - function(alpha,h) {
e - y - alpha * x1^2
const - (2*pi)^(-n/2) / ( gamma(v/2) * (v*s2_m1/2)^(-v/2) )
kernel - h^((v-1)/2) * exp((-(h/2) * sum(e^2)) - (v*s2_m0)*h)
x - const * kernel
return(x)
}
# calculate approximation of p(y|m_0)
m0 -f(alpha_sample,h_sample_m0)
post_m0 - sum(m0) / nrDraws
--
View this message in context:
http://r.789695.n4.nabble.com/density-function-always-evaluating-to-zero-tp4155181p4155181.html
Sent from the R help mailing list archive at Nabble.com.
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David Winsemius, MD
West Hartford, CT
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Re: [R] upper bound in the integrate function depends on a parameter
On Dec 3, 2011, at 10:23 PM, grttt nbbfg wrote:
Sorry for my English, is not my first language..
I have some trouble in terms of using integrate function in R.
fx is a function of m and x where m is supposed to be a unknown
parameter.
R is not an algebraic solver (and R-help is not a homework list.).
fx=function(m,x){
+ x*2/(3*m)*(1-x/(3*m))
+ }
The problem is in upper bound, it depends on parameter m.
integrate(fx,lower=0,upper=3*m)$value
Is it possible to use the integrate function when bounds depend on a
parameter?
If it is known, yes. You could also do some investigation:
curve(x*2/(3*5)*(1-x/(3*5)), 0, 15)
How to define m to solve this integral? The result should be m.
As I said, no homework answers here.
--
David Winsemius, MD
West Hartford, CT
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Re: [R] rnorm command
No. If you want a more informative answer, try following the recommendations in the posting guide mentioned below. --- Jeff NewmillerThe . . Go Live... DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go... Live: OO#.. Dead: OO#.. Playing Research Engineer (Solar/BatteriesO.O#. #.O#. with /Software/Embedded Controllers) .OO#. .OO#. rocks...1k --- Sent from my phone. Please excuse my brevity. Cheryl Johnson johnson.cheryl...@gmail.com wrote: Hello, I use the command rnorm, and I feed these results into a lmer command. Since I am using the rnorm command I expect to get different results for each iteration, yet for each iteration I am getting the same answer. If someone understands why I am getting the same answer every time with a random number generator, I would appreciate help in understanding why this is happening. Is the lmer command causing the answer to be the same each time? Thanks [[alternative HTML version deleted]] __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Assign name to object for each iteration in a loop.
On Thu, 01-Dec-2011 at 10:13AM -0800, lglew wrote:
| Hi R-users,
|
| I'm trying to produce decompositions of a multiple time-series, grouped by a
| factor (called area). I'm modifying the code in the STLperArea function of
| package ndvits, as this function only plots produces stl plots, it does not
| return the underlying data.
|
| I want to extract the trend component of each decomposition
| (x$time.series[,trend]), assign a name based on the factor area.
|
| My input data look like this:
| Area is a factor, with three (but could be many more) levels.
| area
| 1
| 2
| 3
|
| Ystart=2000
|
| TS is a timeseries:
|
| X249 X265 X281 X297 X2000113
| 1 0.2080 0.2165 0.2149 0.2314 0.2028
| 2 0.1578 0.1671 0.1577 0.1593 0.1672
| 3 0.1897 0.1948 0.2290 0.2292 0.2067
|
| Here's the function:
|
| STLpA-function(TS, area, Ystart, period=23, nSG=5,5, DSG=0)
| {
| require (RTisean)
| for(i in 1:unique(area)){
| vi.metric=TS[area==i]
| filt.vi-sav_gol(vi.metric,n=nSG,D=DSG)
| vi.sg-ts(filt.vi[,1], start=Ystart,frequency=period)
| stld.tmp-stl(vi.sg, s.window=periodic, robust=TRUE, na.action=na.approx)
| stld.trend-stld.temp$time.series[,trend]
| }
| assign(paste(stld, i , sep= .), stld.trend)
| vi.trend-ls(pattern= ^stld..$)
| return(vi.trend)
| }
|
| When I call this function with signal=STLpA(TS,area,Ystart=2000,period=23,
| nSG= 5,5, DSG=0))
|
| I get this error:
|
| Error in cat(list(...), file, sep, fill, labels, append) :
| argument 1 (type 'list') cannot be handled by 'cat'
| In addition: Warning message:
| In 1:unique(area) :
| numerical expression has 3 elements: only the first used
|
| I'm guessing this is because I'm assigning names to each temporary stl.trend
| file incorrectly. Can anyone
| improve on my rather poor efforts here?
I would suggest putting your individual trends into a list and
returning that at the end of your function rather than trying to
assing individual objects. IMHO it's easier to do and more useful.
Something along these lines:
trends - list()
for(i in 1:unique(area)){
...
+ trends[[i]] -
}
Then you'll have an element in the list trends that you do with what
you will. It creates less clutter also.
HTH
--
~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.
___Patrick Connolly
{~._.~} Great minds discuss ideas
_( Y )_ Average minds discuss events
(:_~*~_:) Small minds discuss people
(_)-(_) . Eleanor Roosevelt
~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.
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