Dear all,
I am not sure if this is the right place to ask this question, but I will have
a go. Please redirect me to a different place if this is not the right one!
I have a (relatively) simple problem which causes me some frustration because I
cannot find the solution. I measure ten variables
Hi all,
I've been working with a friend's model that is a spatial model
consisting of 4 patches. She uses the code found below to add
migration between the patches for the three species of concern. When I
run a script incorporating this code, all four patches run
independently without migration
Hi. I am trying to install a package called DMwR
http://cran.r-project.org/web/packages/DMwR/index.html
located here:
http://cran.r-project.org/bin/windows/contrib/r-release/DMwR_0.2.1.zip
on windows 7.
I am using R 2.10.1.
I also tried typing something like this but it did not work well.
Folks,
I have a data frame with 4861469 rows that contains an ip address
xxx.xxx.xxx.xxx as one of the columns. I want to assign a site to each
row based on IP ranges. To do this I have a function to split the ip
address as character into class A,B,C and D components. It works but is
horribly
At 10:21 08/01/2012, Bill wrote:
Hi. I am trying to install a package called DMwR
http://cran.r-project.org/web/packages/DMwR/index.html
located here:
http://cran.r-project.org/bin/windows/contrib/r-release/DMwR_0.2.1.zip
on windows 7.
I am using R 2.10.1.
I also tried typing something like this
In a frequency distribution table (bell shaped), how can we find the most
frequent range?
for example:
x = c(1,2, 4,4,4,4, 5,5,5,6,6,5,5,5,5,5,6,6,6,13, 17,17,30,100,300)
barplot(table(x))
In the code above, which function do we use to find that the most
frequent value range from 4 to 6.
On 12-01-07 2:44 PM, cbe...@tajo.ucsd.edu wrote:
Duncan Murdochmurdoch.dun...@gmail.com writes:
On 12-01-06 10:21 PM, Rolf Turner wrote:
On 07/01/12 15:51, R. Michael Weylandtmichael.weyla...@gmail.com wrote:
I imagine the answer will involve lazy evaluation and require you use force()
On 7 January 2012 19:48, drflxms drfl...@googlemail.com wrote:
as I am dealing with complex confusion matrices, I wonder whether there
might be a way to colour text/tabular data in R. I.e. imagine
highlighting the true positive values or certain classes in a table.
The colorout package does
On 12-01-08 5:21 AM, Bill wrote:
Hi. I am trying to install a package called DMwR
http://cran.r-project.org/web/packages/DMwR/index.html
located here:
http://cran.r-project.org/bin/windows/contrib/r-release/DMwR_0.2.1.zip
on windows 7.
I am using R 2.10.1.
I also tried typing something like this
Hi Andrew,
you can use strsplit for a character vector; you do not have to call it
for every element data$ComputerName[i].
If I understand correctly, maybe something like this helps
ip - 123.456.789.321 ## example data
df - data.frame(ip = rep(ip, 9), stringsAsFactors=FALSE)
df
Hi. You can do something like this:
#find the most frequent values of x
t - table(x)
t[t==max(t)]
5
8
#sort table t based on frequencies
t[order(as.numeric(t),decreasing = TRUE)]
x
5 6 4 17 1 2 13 30 100 300
8 5 4 2 1 1 1 1 1 1
#extract any range from sorted
Hello everyone,
What is the most efficient simpliest way to convert all components of a
list to separate columns in a matrix?
Is there an easy way to programmatically pad the length of the resulting
shorter character vectors so that they can be easily combined into a data
frame?
I have the
On Sun, Jan 8, 2012 at 7:50 AM, Duncan Murdoch murdoch.dun...@gmail.com wrote:
On 12-01-07 2:44 PM, cbe...@tajo.ucsd.edu wrote:
Duncan Murdochmurdoch.dun...@gmail.com writes:
On 12-01-06 10:21 PM, Rolf Turner wrote:
On 07/01/12 15:51, R. Michael Weylandtmichael.weyla...@gmail.com
wrote:
On Jan 7, 2012, at 9:34 PM, therrienak wrote:
I have created panel data set using specific variable from our data
set. When
I attempt to run plm I receive a Error in pdata.frame(data, index) :
(subscript) logical subscript too long
You are not providing any information about either the
x-1:11
y-2:3
is there a way to do something like
x[x==y]
(which actually produce error)?
I am really got stuck
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PLEASE do read the posting guide
x[x %in% y]
[1] 2 3
2012/1/8 Philipp Chapkovski chapkov...@gmail.com:
x-1:11
y-2:3
is there a way to do something like
x[x==y]
(which actually produce error)?
I am really got stuck
--
Sarah Goslee
http://www.functionaldiversity.org
__
On Jan 8, 2012, at 3:01 AM, Iasonas Lamprianou wrote:
Dear all,
I am not sure if this is the right place to ask this question, but I
will have a go. Please redirect me to a different place if this is
not the right one!
I have a (relatively) simple problem which causes me some
This does literally what you asked for
x[x %in% y]
[1] 2 3
This is more likely what you want
which(x %in% y)
[1] 2 3
It is an artifact of this example that the two results look the same. Here
is a different example
that distinguishes them, and in this example, %in% is probably not right
On Sun, Jan 8, 2012 at 9:52 AM, Vincent Zoonekynd zoo...@gmail.com wrote:
On 7 January 2012 19:48, drflxms drfl...@googlemail.com wrote:
as I am dealing with complex confusion matrices, I wonder whether there
might be a way to colour text/tabular data in R. I.e. imagine
highlighting the true
Would some type of multivariate SPC be useful? Potentially useful
options might include those based on SPC using PCA, or perhaps
Hotelling's T2.
Maybe you would find something useful in a package such as rrcov?
http://cran.r-project.org/web/packages/rrcov/vignettes/rrcov.pdf
R/S
Cliff
On
The following gives a list, 'z', of functions with
different values of the variable 'i':
z - lapply(1:3, function(i) { force(i) ; function() cat(i is, i, \n)})
z[[3]]()
i is 3
z[[2]]()
i is 2
Their printed values don't show the difference,
as they depend on the 'i' stored in their
'rle' is also your friend:
x = c(1,2, 4,4,4,4, 5,5,5,6,6,5,5,5,5,5,6,6,6,13, 17,17,30,100,300)
barplot(table(x))
rle(x)
Run Length Encoding
lengths: int [1:12] 1 1 4 3 2 5 3 1 2 1 ...
values : num [1:12] 1 2 4 5 6 5 6 13 17 30 ...
y - rle(x)
y$values[which.max(y$lengths)]
[1] 5
On
Is this what you are after:
more-c('R is a free software environment for statistical computing',
+ 'It compiles and runs on a wide variety of UNIX platforms')
result-strsplit(more,' ')
result
[[1]]
[1] R is a freesoftware
environment for
[8]
Thanks andrija
I was wondering is there any statistical test that can give me the most
frequent continuous interval range.
Your code will also give discontinuous frequency intervals. For example, In
the code below I dont want the entry with value 400. I am interested more
in the bell shape
Just a quick followup to the previous post using 4M entries: (20
seconds would seem like a reasonable time for the operation)
ip - 123.456.789.321 ## example data
df - data.frame(ip = rep(ip, 4e6), stringsAsFactors=FALSE)
system.time(x - strsplit(df$ip, '\\.'))
user system elapsed
On Fri, Jan 6, 2012 at 5:30 PM, blueberry1228 blueberry1...@hotmail.com wrote:
After trouble shooting for a long time, believe me it's miserable, I
finally found: There's conflict between Hmisc and sampling packages.
I suggest if strata pops unusual error like this, you should check if your
On Tue, 03-Jan-2012 at 09:00PM -0600, Aren Cambre wrote:
| Is it possible to allow HTML email on R-Help?
|
| HTML email is mainstream and would really help with code markup and
| embedded graphics.
On the contrary, unless special care is taken (rarely happens), HTML
email almost invariably
Iasonas:
On Sun, Jan 8, 2012 at 12:01 AM, Iasonas Lamprianou
lampria...@yahoo.com wrote:
Dear all,
I am not sure if this is the right place to ask this question, but I will
have a go. Please redirect me to a different place if this is not the right
one!
I have a (relatively) simple
I can't run fix() or edit() anymore. Did I break my system?
I'm running Debian Linux with R-2.14.1. As far as I can tell, the R
packages came from Debian's testing wheezy repository. I would like
to know if users on other types of systems see the same problem. If
no, then, obviously, it is a
On Jan 8, 2012, at 2:28 PM, jim holtman wrote:
Is this what you are after:
The code below is essentially what I would have imagined to be a
method of programming cbind.data.frame.fill. It's worth noting that
either reshape2 or plyr (I don't remember which) offer an rbind
version:
Esteemed colleagues
I wonder if there is a package in R that performs the functions of the
Excel SOLVER.
Thanks in advance for the reply.
Best regards,
-
Estimados colegas
Me pregunto si hay un paquete en R que funcione como el SOLVER de Excel.
De antemano gracias
On Jan 8, 2012, at 4:51 PM, Ricardo Bandin wrote:
Esteemed colleagues
I wonder if there is a package in R that performs the functions of the
Excel SOLVER.
Thanks in advance for the reply.
http://cran.r-project.org/web/views/Optimization.html
--
David Winsemius, MD
West Hartford, CT
Thank you, I will have a look at rollapply
Dr. Iasonas Lamprianou
Department of Social and Political Sciences
University of Cyprus
From: David Winsemius dwinsem...@comcast.net
To: Iasonas Lamprianou lampria...@yahoo.com
Cc: r-help@r-project.org
Thank you, I downloaded the vignettes and I am currently studying it. It seems
pretty good!
Dr. Iasonas Lamprianou
Department of Social and Political Sciences
University of Cyprus
From: Clifford Long gnolff...@gmail.com
To: Iasonas Lamprianou
On 01/08/2012 11:37 AM, jim holtman wrote:
Just a quick followup to the previous post using 4M entries: (20
seconds would seem like a reasonable time for the operation)
ip- 123.456.789.321 ## example data
df- data.frame(ip = rep(ip, 4e6), stringsAsFactors=FALSE)
system.time(x-
Am 08.01.12 13:52, schrieb Vincent Zoonekynd:
On 7 January 2012 19:48, drflxms drfl...@googlemail.com wrote:
as I am dealing with complex confusion matrices, I wonder whether there
might be a way to colour text/tabular data in R. I.e. imagine
highlighting the true positive values or certain
Am 07.01.12 21:12, schrieb Michael Friendly:
On 1/7/2012 5:48 AM, drflxms wrote:
Hi everybody,
as I am dealing with complex confusion matrices, I wonder whether there
might be a way to colour text/tabular data in R. I.e. imagine
highlighting the true positive values or certain classes in a
I have a multidimensional array - in this case with 4 dimensions of x,y,z
and time. I'd like to take the time derivative of this matrix, i.e.
perform the diff operator along dimension number 4.
In Matlab, there is a simple option to specify which dimension the
difference is to be taken across.,
Hi Andrew,
I am aware, that this is an R-mailing list, but for such tasks (I deal a
lot with huge genomic datasets) I tend to use awk and sed for
preprocessing of data, in case I run into performance problems.
Otherwise for handling of strings in R I recommend stringr library, but
I don't know
Just a silly question about documentation, but might it make sense to change
the documentation for ?any [1] to be Are any values true? rather than are
some
It'd be more consistent with the function name and with ?all, as well as
reading more precisely (to my ear at least)
Anyway, of no
On Sat, 7 Jan 2012 14:54:30 +0100
Antonio Tirri antonio.ti...@gmail.com wrote:
On 7 January 2012 14:34, Prof Brian Ripley rip...@stats.ox.ac.uk
wrote:
And what did your statistics advisor say? The problem is your
understanding of the words 'sampling period'.
I don't have a
I am having a problem with creating a vector from a rows or columns, I
searched around and found as.vector(x), but it does not seem to do what it
says it does
I have included an example below, of doing what would seem to be the method
required to create a vector, but instead it creates a
Dear all,
I could not find an answer for the problem.
I have a matrix and I want to sum rows in groups i.e. rows are summed as
long as rows of column 1 have some value (f.e. 2008 in it), then again rows
are summed as long as rows of column 2 have some value (f.e. 2009 in it).
In case there is
hi,
i am using par(mrow=c(6,6)) function to get 6x6 plots on one screen. the
problem that i am having is that the axis tick labels are far away from the
ticks and going into previous plots (see attached figure). i need to know
how can i reduce the distance between the ticks and their values (y
Hello,
I believe this solves your problem
fun - function(x){
f - function(x, n){
if(length(x) n) x - c(x, rep(NA, n-length(x)))
return(x)
}
lapply(x, f, max(unlist(lapply(x, length
}
fun(result) # the 'result' list above
Hi
i run
arima.sim(n=100,n.start=9,list(ar=c(0.4)),sd=sqrt(3)), but i need that the
firs value be 9, i mean x_(-1).
Thanks
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Thanks Enrico Jim,
The following finished the job in under a minute!
res - unlist(strsplit(data[[ComputerName]], \\.))
ii - seq(1, nrow(data)*4, by = 4)
data$IPA -res[ii] ## A
data$IPB -res[ii+1] ## B
data$IPC -res[ii+2] ## C
data$IPD -res[ii+3] ## D
Andrew
On 08/01/2012 13:11, Enrico
We are trying to make a decision tree using rpart and we are continually
running into the following error:
fit_rpart=rpart(ENROLL_YN~MINORITY,method=class)
summary(fit_rpart)
Call:
rpart(formula = ENROLL_YN ~ MINORITY, method = class)
n= 5725
CP nsplit rel error
1 0 0 1
Error
Hi,
I am trying to create a script that will evaluate each column of a data
frame, regardless of # columns, using some function and sorting the results
by an index vector:
#upload data (112 rows x 73 columns)
SD - read.csv(/Users/johnjacob/Desktop/StudentsData_RInput.csv,
header=TRUE)
#assign
On 09-Jan-2012 R. Michael Weylandt michael.weyla...@gmail.com wrote:
Just a silly question about documentation, but might it make
sense to change the documentation for ?any [1] to be Are any
values true? rather than are some
It'd be more consistent with the function name and with ?all,
as
On Jan 8, 2012, at 3:12 PM, Philip Robinson wrote:
I am having a problem with creating a vector from a rows or columns, I
searched around and found as.vector(x), but it does not seem to do
what it
says it does
I have included an example below, of doing what would seem to be the
method
On Jan 8, 2012, at 1:57 PM, Andrew Gaska wrote:
Dear all,
I could not find an answer for the problem.
I have a matrix and I want to sum rows in groups i.e. rows are
summed as
long as rows of column 1 have some value (f.e. 2008 in it), then
again rows
are summed as long as rows of column
Hi Amanda,
Can you reproduce the error with a small subset of the data? If so,
could you send it to us? For instance if say 20 cases is sufficient,
you could send the output of dput() which pastes easily into the
console:
dput(yourdata[, c(ENROLL_YN, MINORITY)])
You could also try calling
On Jan 8, 2012, at 4:48 PM, jawbonemurphy wrote:
Hi,
I am trying to create a script that will evaluate each column of a
data
frame, regardless of # columns, using some function and sorting the
results
by an index vector:
?lapply
?[
?order
#upload data (112 rows x 73 columns)
SD -
In aggregate() you can use the following as your
grouping ('by') variable
group - cumsum(c(TRUE, year[-1] != y[-length(year)]))
where 'year' is the column of your matrix containing
the 2008, 2009, ...
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From:
On Jan 8, 2012, at 8:43 PM, William Dunlap wrote:
In aggregate() you can use the following as your
grouping ('by') variable
group - cumsum(c(TRUE, year[-1] != y[-length(year)]))
where 'year' is the column of your matrix containing
the 2008, 2009, ...
I thought those were rownames and was
On 09/01/12 08:45, jfca283 wrote:
Hi
i run
arima.sim(n=100,n.start=9,list(ar=c(0.4)),sd=sqrt(3)), but i need that the
firs value be 9, i mean x_(-1).
Thanks
Is this homework?
cheers,
Rolf Turner
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Hi,
install.packages(splines)
Warning in install.packages :
package ‘splines’ is not available (for R version 2.14.1)
Regards,
Xiaobo Gu
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PLEASE do read the posting
On 9 January 2012 08:53, Phil Wiles philip.wi...@gmail.com wrote:
I have a multidimensional array - in this case with 4 dimensions of x,y,z
and time. I'd like to take the time derivative of this matrix, i.e.
perform the diff operator along dimension number 4.
apply can do that, but you may
Yes, it's work for my class.
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The following message appeared on R-help but this discussion should be moved to
R-sig-geo
On 07/01/12 02:17, herbert8...@gmx.de wrote:
I was searching through the spatstat manual in order to find a function
to simulate a Poisson pattern only within a fixed radius (circular moving
I highly recommand a book written by Paul Murrell: R Graphics.
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Sent from the R help mailing list archive at Nabble.com.
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I'm having the same problem, it seems to me that when output window is
partitioned the tick marks and axis lables behave weirdly...
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Hi Dave,
Thanks for your response!
I'm new at R, and I'm afraid I'm not sure what you mean by:
?lapply
?[
?order
Were these suggestions for other commands to try? If so, can you be more
specific? I apologize for being clueless :)
Secondly, you're right that the script I have now leaves me
On Jan 9, 2012, at 12:02 AM, jawbonemurphy wrote:
Hi Dave,
Thanks for your response!
I'm new at R, and I'm afraid I'm not sure what you mean by:
?lapply
?[
?order
It means I thought you might get the answers you needed by looking at
those functions' help pages.
Were these
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