Dear R help listers,
I am trying to replicate results in Gelman and Hill's book (Chapter 3
in regressions and multilevel models). Below I estimated two models
(chp3.1 and chp3.3 in R codes) with the same data and dependent
variable but different independent variables. I have been using Stata
for
Many thanks for your elaborated explaina.
At 2012-01-13 11:34:51,R. Michael Weylandt michael.weyla...@gmail.com wrote:
As Jorge noted, the fix is to use %in%: a fuller explanation of why
`==` didn't work is that it implicitly used vector recycling: look at
with(data, id == c(a, c))
Thanks£¡
ÔÚ 2012-01-13 10:51:14£¬Jorge I Velez jorgeivanve...@gmail.com дµÀ£º
Hi,
Use %in% instead of ==.
HTH,
Jorge.-
On Thu, Jan 12, 2012 at 9:36 PM, ÃÏÐÀ wrote:
Hi all
I have a question about subset function.
dat
id x1 x2 x3
1 a 1 11 111
2 b 2 22 222
3 c 3 33 333
4 d
i am trying to solve a partial differential equation analytically(PDE) in R .
i have found some functions that do the stuff numerically. But that will not
meet my purpose. is there any function to solve PDE analytically. please
help.
--
View this message in context:
Hi
Dear R help listers,
I am trying to replicate results in Gelman and Hill's book (Chapter 3
in regressions and multilevel models). Below I estimated two models
(chp3.1 and chp3.3 in R codes) with the same data and dependent
variable but different independent variables. I have been using
Hi all,
Since two days I am trying to find a solution to be able to create
beanplots for my data. When I call the beanplot function the following
error appears:
beanplot(y1 ~ x1, log=, what=c(1,1,1,0), ylim=c(0,1))
Error in bw.SJ(x, method = dpi) : sample is too sparse to find TD
What is
Dear members of the R-help list,
I have sent the email below to the R-SIG-ME list to ask for help in
interpreting some R output of fitted linear models.
Unfortunately, I haven't yet received any answers. As I am not sure if my
email was sent successfully to the mailing list I
am asking for help
Hi.
I run a latent class analysis with polymotous variables.
Because of small sample size, I have to use bootstrap method in order to
select a proper model.
Is there any package or way that I can run a bootstrap method after runing
latent class model with polytomous variables?
Thank
KeunBok Lee
Hi all,
I have a sequence file (fasta format) and want to calculate the rho
statistics for dinucleotide abundance value on my data.. the code which I
use is (using seqinr library and current working directory)
/seq_info-read.fasta(gene.txt)/
/rho(seq_info[1],2)/
but it yields only the
p...@potis.org writes:
When I move R and Rscript out of my path, as expected, I also
have problems. If I use tramp to connect to remote, open a shell
there with M-x eshell, and type 'env' , my path is the path on
local.
This is the correct behaviour of eshell:
/scp:slbps0:/root $ which
Hi all,
I want to fragment a dataset into k-cross-validation partitions
(folds). The content of the folds should be stratified, but not
according to a single (categorical) feature, but according to a range
of features (numeric, if possible numeric and categorical). Does
anybody know a way to do
we haven't had time to create the file again, yet, but thanx also for the
great tip about this special mailing list!
marion
2012/1/3 Barry Rowlingson b.rowling...@lancaster.ac.uk
On Tue, Jan 3, 2012 at 10:54 AM, Marion Wenty marion.we...@gmail.com
wrote:
hello barry,
thank you very much
Hi
It seems to me quite like a homework for which the policy of this list is
not to respond.
But far from being an expert in statistics I only express my opinion. It
seems to me that your height variable behaves like a two level factor and
the 190 value points to rather suspicious value in
Dear all,
I need to know in which number of iterations the kmeans converge each
time I run it.
Any idea how to do it?
Thank you for your attention,
Rui
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
d2y - diff(dy)
which(dy==0) ## critical values
sign(s2y)[which(dy==0)] ## test for max/min/saddle
which(d2y==0) ## inflection points
I would think that testing for d2y==0 would be akin to the error in
numeric analysis warned about in FAQ 7.31. Seems unlikely that in real
data that
Dear R users,
I have some trivial query.
I have a string, I want to remove space from the string.
For eg.
Input:
a - Remove space
Output required:
Removespace
I tried using str_trim but only removes end spaces. library(stringr).
Regards
Vikram
[[alternative HTML version deleted]]
gsub( ,,a)
/Gustaf
On Fri, Jan 13, 2012 at 12:24 PM, Vikram Bahure
economics.vik...@gmail.comwrote:
Dear R users,
I have some trivial query.
I have a string, I want to remove space from the string.
For eg.
Input:
a - Remove space
Output required:
Removespace
I tried using
Tom,
what happens with:
(Emacs)
M-x ssh
t
(you should have the remote shell buffer now)
R
(once R is started)
M-x ess-remote
r
?
Claudia
--
Claudia Beleites
Spectroscopy/Imaging
Institute of Photonic Technology
Albert-Einstein-Str. 9
07745 Jena
Germany
email:
Hi
Dear R users,
I have some trivial query.
I have a string, I want to remove space from the string.
For eg.
Input:
a - Remove space
Output required:
Removespace
It seems to be simple. Even myself with very poor knowledge of regexpr can
suggest solution.
gsub( , , a)
On Jan 13, 2012, at 5:53 AM, Rui Esteves wrote:
Dear all,
I need to know in which number of iterations the kmeans converge each
time I run it.
Any idea how to do it?
Look at the help page (to see that it is not part of the returned
object) and then look at the code (to see that the
Hi all,
I can see two packages implementing second order cone programming in R:
CLSOCP and DWD. Both of them allow to specify only equality linear constraints.
Do you know if there is a library to solve this problem:
second order cone programming with inequality liner constraints
excluding mosek
Hello all.
I have two data frames.
Group Start End
G1 200 700
G2 500 1000
G3 20003000
G4 40006000
G5 70008000
and
Pos
Hello Paul
Thanks for the answer but my point is not how to simulate a VAR(p) process
and check that it is stable.
My question is more how can I generate a VAR(p) such that I already know
that it is stable.
We know a condition that assure that it is stable (see first message) but
this is not a
i ran this model
model2-glm(rojos~ageandsex+sector+season+sector:season,quasipoisson)
glht(model2,linfct=mcp(ageandsex=Tukey))
General Linear Hypotheses
Multiple Comparisons of Means: Tukey Contrasts
Linear Hypotheses:
Estimate
M - H == 0 0.2898
SUB - H == 0
Hi Justin,
it still does not work.
All points become red.
I use this skript with your modifications:
TOC_NI-read.csv2(C:/Users/hilliges/Desktop/Master/Daten/Statistik/TOC-NI.csv,
sep=;, dec=,, encoding=UTF-8)
circ-TOC_NI[order(TOC_NI$NI,decreasing=T),][1:4,]
plot(NI~TOC,data=TOC_NI,col=blue,
Hi Petr,
thanks for your answer.
First of all it's not homework I am a student and need to analyse cancer
data using linear models.
I looked into that topic since a week now and still struggling in
interpreting some of the R output that is why
I was asking for help here.
I don't quite
Hello All,
I have the following dataset:
Year 2006 2007
Jan Jan 0.0204 0.0065
Feb Feb 0.0145 0.0082
Mar Mar 0.0027 0.0122
dput(d_tmp)
structure(list(Year = c(Jan, Feb, Mar), `2006` = c(0.0204,
0.0145, 0.0027), `2007` = c(0.0065, 0.0082, 0.0122)), .Names =
c(Year,
2006, 2007),
Hello,
I have a csv file with many variables, both characters and integers.
I would like to load it on R and do some operations on integer
variables, the problem is that R loads the entire dataset considering
all variables as characters, instead I would like that R makes the
distinction
Got problems with plotCI (plotrix)
I only want to plot the upper part of the error bar in my barplot
I had the exact same commands working two months ago
Now I wanted to change the legend and when I ran it again plotCI stopped
working.
To me it seems like there must some bug in R
Hi
what do you want to achieve?
Hi Justin,
it still does not work.
All points become red.
I use this skript with your modifications:
TOC_NI-read.csv2(C:/Users/hilliges/Desktop/Master/Daten/Statistik/TOC-NI.csv,
sep=;, dec=,, encoding=UTF-8)
I forgot to post it to r help.
Petr
Hi
Hi Petr,
thanks for your answer.
First of all it's not homework I am a student and need to analyse cancer
data using linear models.
I looked into that topic since a week now and still struggling in
interpreting some of the R output that is why
ATANU ata.sonu at gmail.com writes:
i am trying to solve a partial differential equation analytically(PDE) in R .
i have found some functions that do the stuff numerically. But that will not
meet my purpose. is there any function to solve PDE analytically. please
help.
With extremely
Basically I want to create a string vector where first element is a
date.
Note that if you supply c() with objects of different types (as you
have),
the results will probably not be what you wanted.
This is the key. I assumed (not correctly)
that Sys.Date() generates a character
Sys.Date()
On Jan 13, 2012, at 7:02 AM, Francisco wrote:
Hello,
I have a csv file with many variables, both characters and integers.
I would like to load it on R and do some operations on integer
variables, the problem is that R loads the entire dataset
considering all variables as characters,
On Fri, Jan 13, 2012 at 7:02 AM, Francisco franciscororol...@google.com wrote:
Hello,
I have a csv file with many variables, both characters and integers.
I would like to load it on R and do some operations on integer variables,
the problem is that R loads the entire dataset considering all
Can somebody explain the problem in the following expression?
Thank you
/ if (species == 1){
+ fitness -
(1-b)*exp(-((microsites-niche.preference)/(niche.width.specialist+a.specialist)^2)*(1-a.specialist)
+ }else
Error: unexpected '}' in:
fitness -
I've got a numeric vector with values ranging from 1 to 5, I would like to
catagorize these values like this:
1 becomes catagory 1
3 becomes catagory 3
And everything else in catagory 2. The simple function I wrote beneath works
for single numeric data, but for some reason I am unable to feed it
Hi jost87,
Try using a good text editor with syntax highlighting and
parenthesis/brace matching (personal preference is Emacs + ESS, others
like Rstudio, and there are tons more). I find at least one
mismatched pair of parentheses/braces in those expressions.
Cheers,
Josh
On Fri, Jan 13, 2012
Many thanks all,
Tolga
-Original Message-
From: Chibisi Chima-Okereke [mailto:cchima-oker...@mango-solutions.com]
Sent: 12 January 2012 17:14
To: Uzuner, Tolga I
Cc: Jack Teall; Richard Pugh
Subject: RE: How can I prevent solve.QP from printing the solution progress ?
Try something like
Regarding your last question, read ?cut
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
I don't see any signs of a simple function, but I'd use ifelse().
y - ifelse(x == 1, 1, ifelse(x == 3, 3, 2))
or some such. (Lack of reproducible example means lack of actual
testing.)
Sarah
On Fri, Jan 13, 2012 at 9:11 AM, WoutH w.denhollan...@lumc.nl wrote:
I've got a numeric vector with
Dear all,
I have some troubles using the stemming algorithm provided by the tm
(text mining) + Snowball packages.
Here is my config:
MacOS 10.5
R 2.12.0 / R 2.13.1 / R 2.14.1 (I have tried several versions)
I have installed all the needed packages (tm, rJava, rWeka, Snowball)
+
Hi,
I have a simple question about quartiles in R, especially how they are
calculated using the boxplot.
Quartiles
(.25 and .75) in boxplot are different from the summary function and
also don't match with the 9 types in the quantile function.
See attachment for details.
Can you give me the
Hello,
I have a data.frame and I want to transfor it in a list of rows or columns.
I can do apply(myDataFrame,MARGIN=1,FUN=???)
I remember that there is a function which mean return or access column ...
something like :: or ], or [,
I can't remember can somebody refresh my memory?
--
View this
The explanation is in ?boxplot.stats (as the help for boxplot states).
Details:
The two ‘hinges’ are versions of the first and third quartile,
i.e., close to ‘quantile(x, c(1,3)/4)’. The hinges equal the
quartiles for odd n (where ‘n - length(x)’) and differ for even
n.
I have to admit, I have very little idea what you are trying to do. Can you
provide an example?
In general, the i-th column of a data frame can be accessed with
mydataframe[, i]
but that doesn't help with whatever you want to do with apply().
Sarah
On Fri, Jan 13, 2012 at 10:45 AM, statquant2
I have NO knowledge of regexpr, but someone helped me out once and I put
it into a function I call trim. Here is the line I use:
function(x) gsub(^[[:space:]]+|[[:space:]]+$, , x)
One more thing you can try. Hope it helps, Roger
-Original Message-
From: r-help-boun...@r-project.org
#Dear All,
#I'm having a bit of a trouble here, please help me...
#I have this data
set.seed(4)
mydata - data.frame(var = rnorm(100),
temp = rnorm(100),
subj = as.factor(rep(c(1:10),5)),
trt = rep(c(A,B), 50))
#and this model that
WoutH wrote
I've got a numeric vector with values ranging from 1 to 5, I would like to
catagorize these values like this:
1 becomes catagory 1
3 becomes catagory 3
And everything else in catagory 2. The simple function I wrote beneath
works for single numeric data, but for some reason I
http://cran.r-project.org/doc/manuals/R-intro.pdf
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Hi,
I'm trying to install R from an rpm locally to my account (the reason I'm
not doing it through yast/yast2/zypper is that the sys admin isn't yet
willing to install it, and doesn't want to support it, but will help me
support it if I install it locally -- in short, policy problems rather than
Interesting: The email I received through the R-help list didn't have
all the information that was apparently there:
On Fri, Jan 13, 2012 at 11:32 AM, Berend Hasselman b...@xs4all.nl wrote:
WoutH wrote
I've got a numeric vector with values ranging from 1 to 5, I would like to
catagorize
Dear Rers,
is there a way to color counties on a full US map based on a criterion
one establishes (i.e., all counties I assign the same number should be
the same color)?
I explored a bit and looks like the package maps might be of help.
library(maps)
One could get a map of the US: map('usa')
One
I think it's saying you need to install R-base before R-base-devel.
You'll need to add a cran repository as SUSE might not have the most up-to-date
version of R.
This is the code for Ubuntu I assume it's the same, just change the distro and
keyserver:
sudo apt-get update
sudo
Thanks, will do! I thought devel included base, but evidently, that's not
the case...
On Fri, Jan 13, 2012 at 10:58 AM, Gavin Blackburn
gavin.blackb...@strath.ac.uk wrote:
I think it's saying you need to install R-base before R-base-devel.
You'll need to add a cran repository as SUSE might
Hi,
You've just about got it. See below.
On Fri, Jan 13, 2012 at 11:52 AM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Dear Rers,
is there a way to color counties on a full US map based on a criterion
one establishes (i.e., all counties I assign the same number should be
the
Sarah, this is amazing, thank you so much.
One question: I am trying to do for the whole US (on one map) what
you've helped me do for Iowa.
In other words, I would like to create a file of inputs like you
countycol with 1,000+ lines - for all US counties (probably without
Hawaii and Alaska,
Like Sarah said, what you say below makes very little sense, but as a total
shot in the dark, is this what you mean?
lapply(1:nrow(df), function(i) x[i,] )
Michael
On Jan 13, 2012, at 11:15 AM, Sarah Goslee sarah.gos...@gmail.com wrote:
I have to admit, I have very little idea what you are
On Fri, Jan 13, 2012 at 12:15 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Sarah, this is amazing, thank you so much.
One question: I am trying to do for the whole US (on one map) what
you've helped me do for Iowa.
In other words, I would like to create a file of inputs like
Hi,
I'm an R newbie and I've been struggling with a optimization problem for
the past couple of days now.
Here's the problem - I have a matrix of expected payouts from different
stock option strategies. Each column in my matrix represents a different
stock and each row represents the return to
Dear colleagues.
I wonder if anybody knows about a procedure in R to calculate the Brillouin
Diversity index.
I searched the net but did not find anything about it.
Thanks a lot for any help
Best, Philipp
***
Prof. Dr. Philipp Fischer
Head of
I need help with creating custom xml reader for use with the tm package. The
objective is to crate a corpus for analysis. Files that I'm working with
come from solr and are in a funky XML format never the less I'm able to
parse the XML files using solrDocs.R function provided by Duncan Temple
At 15:53 11/01/2012, Ricc wrote:
Hello,
I once used the metawin software to perform a meta-analysis (see
metawinsoft, Rosenberg et al.) and produced normal qqplot to test for
a potential bias in the dataset.
I now want to re-use the same dataset with the package metafor by W.
Viechtbauer (great
When setting up my new machine, I had the surprise to see that Package
'fUtilities' was removed from the CRAN repository.
This is problematic for my work. I use many of its functions, and it will
complicate things a lot if other programmers want to use my previous code in
the future. Plus,
Nobody?
-
Mario Garrido Escudero
PhD student
Dpto. de Biología Animal, Ecología, Parasitología, Edafología y Qca. Agrícola
Universidad de Salamanca
--
View this message in context:
http://r.789695.n4.nabble.com/GLHT-in-multcomp-Two-similar-models-one-doesn-t-work-tp4291875p4292889.html
Sent
Two things:
1. Looking at the sizes of the RPMs at the URL provided, the 'R-base-devel' RPM
is only 84k. So as with other Linux distros, that is likely to contain R header
files and other such things to enable compilation of CRAN packages during their
installation using the source tarballs.
Hello,
probably it is quite easy but I can get it: I have
mulitple numeric vectors and a function using
all of them to calculate a new value:
L - c(200,400,600)
AR - c(1.5)
SO - c(1,3,5)
T - c(30,365)
fun - function(L,AR,SO,T){
exp(L*AR+sqrt(SO)*log(T))
}
How can I get an array or
On Jan 13, 2012, at 10:45 AM, statquant2 wrote:
Hello,
I have a data.frame and I want to transfor it in a list of rows or
columns.
I can do apply(myDataFrame,MARGIN=1,FUN=???)
I remember that there is a function which mean return or access
column ...
something like :: or ], or [,
I
Thank you somuch, Sarah. I tried, and it's working just wonderfully
(code below).
One last question, if I may: is it possible to get rid of borders
between counties (just leave the fill)? I did not find this argument
in help...
Thank you!
Dimitri
### My criterion for all counties.:
Hello everyone,
I have 1 data frame (just a vector in the example below) with 12
individuals listed and a separate vector of 36 days (in week intervals).
What is the best way to merge these together so that each individual
(specialist here) has all 36 days matched with their specialist number (a
Just to clarify, according to help about the fill argument:
logical flag that says whether to draw lines or fill areas. If FALSE,
the lines bounding each region will be drawn (but only once, for
interior lines). If TRUE, each region will be filled using colors from
the col = argument, and bounding
On Fri, Jan 13, 2012 at 1:41 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Thank you somuch, Sarah. I tried, and it's working just wonderfully
(code below).
One last question, if I may: is it possible to get rid of borders
between counties (just leave the fill)? I did not find
On Jan 13, 2012, at 12:33 PM, Dominic Comtois wrote:
When setting up my new machine, I had the surprise to see that
Package
'fUtilities' was removed from the CRAN repository.
https://stat.ethz.ch/pipermail/rmetrics-core/2012-January/000554.html
On Jan 13, 2012, at 12:42 PM, Dan Abner wrote:
Hello everyone,
I have 1 data frame (just a vector in the example below) with 12
individuals listed and a separate vector of 36 days (in week intervals).
What is the best way to merge these together so that each individual
(specialist here)
On Fri, Jan 13, 2012 at 1:52 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Just to clarify, according to help about the fill argument:
logical flag that says whether to draw lines or fill areas. If FALSE,
the lines bounding each region will be drawn (but only once, for
On Jan 13, 2012, at 1:42 PM, Dan Abner wrote:
Hello everyone,
I have 1 data frame (just a vector in the example below) with 12
individuals listed and a separate vector of 36 days (in week
intervals).
What is the best way to merge these together so that each individual
(specialist here) has
So does anyone use this package?
- Original Message -
From: Scott Raynaud scott.rayn...@yahoo.com
To: r-help@r-project.org r-help@r-project.org
Cc:
Sent: Tuesday, January 10, 2012 1:40 PM
Subject: grplasso
I want to use the grplasso package on a data set where I want to fit a linear
See
?expand.grid
For example,
df - expand.grid(L=L, AR=AR, SO=SO, T=T)
df$y - fun(df$L, df$AR, df$SO, df$T)
Jean
Johannes Radinger wrote on 01/13/2012 12:28:46 PM:
Hello,
probably it is quite easy but I can get it: I have
mulitple numeric vectors and a function
Perhaps repeated use of the outer() function. You could also write a
multi.outer() or adopt one of the solutions here:
http://stackoverflow.com/questions/6192848/how-to-generalize-outer-to-n-dimensions
Michael
On Fri, Jan 13, 2012 at 1:28 PM, Johannes Radinger jradin...@gmx.at wrote:
Hello,
Hi,
Since trt is a factor, you use it for indexing. try just delete in the code
fill - my.fill[combined$trt[subscripts]]
Weidong Gu
On Fri, Jan 13, 2012 at 11:30 AM, matteo dossena m.doss...@qmul.ac.uk wrote:
#Dear All,
#I'm having a bit of a trouble here, please help me...
#I have this data
apt-get wont run on Suse unless you have aptitude, also your distribution won't
compile a deb without some intervention. You won't be able to query the package
regardless of key if your local proxy settings won't let you because of admin.
Perhaps see if there is a tool to convert the deb
But the help does say that additional arguments are passed to lines(),
so you can use lty=0.
That can leave white bits between counties if the areas don't line up
precisely, so I think it looks better with the lines in black.
I agree, indeed it leaves white bits. Of course, I could try to
Try this:
d_tmp2 - data.frame(apply(round(100*d_tmp[, -1], 2), 2, paste, %,
sep=))
names(d_tmp2) - paste(names(d_tmp[, -1]), Lbl, sep=-)
d_final - cbind(d_tmp, d_tmp2)
d_final[, 1+c(0, order(names(d_final[, -1])))]
Jean
santosh wrote on 01/13/2012 04:55:51 AM:
Hello All,
I have the
Changing the color of the borders is what the border argument to
polygon() would do, if only it hadn't been overridden.
So no, you can't easily change the line color. It would be an easy
tweak to the code to add a polyborder argument that is passed
to polygon() as border, though. That would solve
You can set the fg graphics parameter, for example
oldpar - par(fg='white') # change the default fg (foreground color) to
white
map('county', 'iowa', fill=TRUE, col='light gray')
oldpar # reset fg to the default - black
map('state', 'iowa', lwd=3, add=TRUE)
Assuming you want the state outline in
Sarah, David, thank you very much for your help! It all works now:
### My criterion for all counties:
allcounties-data.frame(county=map('county', plot=FALSE)$names)
allcounties$group-c(rep(1:6,513),rep(1,4))[order(c(rep(1:6,513),rep(1,4)))]
### My colors:
classcolors - rainbow(6)
### For gray
On 14/01/2012 8:04 a.m., Sarah Goslee wrote:
On Fri, Jan 13, 2012 at 1:52 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Just to clarify, according to help about the fill argument:
logical flag that says whether to draw lines or fill areas. If FALSE,
the lines bounding each
Hi Ray,
I'm glad to see you here. I was going to write this up a bit more
clearly and email it to you, but now I don't have to bother. :)
Coincidentally, I became aware of this just recently. When the maps package
was created (way back in the 'new' S era), polygon() didn't add borders,
and
I would be biased towards using a heuristic, for instance Threshold
Accepting (TA), for solving such a problem. (TA is implemented in
package NMOF. Disclosure: I am the author of that package.) But you will
not find a ready-to-use solution there.
(1) you need an objective function, ie, a
Hello Jeff, thank you for the reply. I tried the cut function and I had two
questions. How do I have the cut function take the first position in the
start column in df1 as the first cut point and the first position in column
2 as the second cut point. The break variable seems to want a single
Everyone, thanks a lot - this is great:
### My criterion for all counties:
allcounties-data.frame(county=map('county', plot=FALSE)$names)
allcounties$group-c(rep(1:6,513),rep(1,4))[order(c(rep(1:6,513),rep(1,4)))]
### My colors:
classcolors - rainbow(6)
### 1. If I want to have no borders
Somewhat related question out of curiousity:
Does anyone know how often the list of the counties and county names
is updated in this package? Or is it done centrally for all packages
that deal with US counties?
Thanks!
Dimitri
On Fri, Jan 13, 2012 at 3:41 PM, Ray Brownrigg
On Jan 13, 2012, at 17:43 , Matthew Pettis wrote:
Hi,
I'm trying to install R from an rpm locally to my account (the reason I'm
not doing it through yast/yast2/zypper is that the sys admin isn't yet
willing to install it, and doesn't want to support it, but will help me
support it if I
Hi all,
This is pretty basic but I am not an expert and I couldn't find anything in
the forum or my statistics book about it. I was reading a paper and the
authors were using both explained deviance and explained variance as
synonyms. They were describing a GAM regression. Is that right? I
Hello R experts,
I have generated a data set below. I tried to export the object - my.pvalues
(class is by)
as .txt (or excel file), so the output in matrix form line up nicely in .xls
file. Do I have to convert to some other data formats before using write.table?
I am having difficulty to
Dear all,
I've the following data.frame
GENDER MEASURE01 MEASURE02 MEASURE03
MEASURE04 MEASURE05 MEASURE06
R. Rafuse MALE 91
6 8 12
Dear R Users -
R is a wonderful software package. CRAN provides a variety of tools to
work on your data. But R is not apt to utilize all the public
databases in an efficient manner.
I observed the most tedious part with R is searching and downloading
the data from public databases and putting it
Here is a solution that works for your small example.
It might be difficult to prepare your larger data sets to use the same
method.
db -rbind(d1,d2)
aggregate(subset(db,select=-c(subject,trt)),
by=list(subject=db$subject),mean)
## or, for example,
aggregate(subset(db,select=-c(subject,trt)),
R is Open Source. You're welcome to write tools, and submit your
package to CRAN. I think some part of this has been done, based
on questions to the list asking about those parts.
Personally, I've been using S-Plus and then R for 18 years, and never
required data from any of them. Which doesn't
*RMS Short Course 2012*
Frank E. Harrell, Jr., Ph.D., Professor and Chair
Department of Biostatistics, Vanderbilt University School of Medicine
*March 7, 8 9, 2012*
8:00am - 4:30pm
Vanderbilt University Nashville Tennessee USA
http://biostat.mc.vanderbilt.edu/RMSShortCourse
This
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