I am trying to resolve a problem I am having with running the rattle package on
two different Windows 7 x64 systems. It appears to be a problem with my two
specific systems, because others on Windows 7 x64 systems aren't complaining
about this problem. What I am looking for is a method for
I had installed de gplots package and then I loaded the library but the
package did not work. I recieved a message like this:
install.packages(gplots, dependencies = TRUE)
Installing package(s) into
/home/fpiston/R/x86_64-pc-linux-gnu-library/2.14
(as lib is unspecified)
--- Please select a
Hi,
It does work -- it seems like that at some point you've upgraded your
R packages in an incorrect manner.
Specifically, it looks as if you've installed a new version of R and
just copied over libraries from a previous (pre R-2.10.x) version.
Look at this error message during the install:
On
Hi Fernando,
2012/3/13 Fernando Pistón Pistón fpis...@ias.csic.es:
Hi Steve,
The suggestion of Pacal worked ok, Do you think it is neccesary to
update.packages? Can I update.packages although the gplots work ok?
I don't see Pascal's suggestion, so I guess I don't know what you did
(maybe
Dear R Users,
I have a question based on my research. I am analyzing reader-based
diagnostic data set. My study involves diabetic patients who were evaluated
for treatable diabetic retinopathy based on the presence or absence of two
pathologies in their eyes. Pathologies were identified using
Hi Fernando,
You have to reinstall package 'bitops' too.
Regards,
Pascal
- Mail original -
De : Fernando Pistón fpis...@gmail.com
À : r-help@r-project.org
Cc :
Envoyé le : Mardi 13 mars 2012 16h10
Objet : [R] gplots packages does not work
I had installed de gplots package and then I
Hi Pascal,
Your suggestion work perfectly. I just install de bitops package and the
gplots library work ok.
Thanks
On Tue, Mar 13, 2012 at 8:24 AM, Pascal Oettli kri...@ymail.com wrote:
Hi Fernando,
You have to reinstall package 'bitops' too.
Regards,
Pascal
- Mail original
Hi Steve,
The suggestion of Pacal worked ok, Do you think it is neccesary to
update.packages? Can I update.packages although the gplots work ok?
On Tue, Mar 13, 2012 at 8:38 AM, Steve Lianoglou
mailinglist.honey...@gmail.com wrote:
Hi,
It does work -- it seems like that at some point
Hi Fernando,
To me, it is a good idea to regularly check the availability of update for
installed packages, using 'update.packages()'.
Regards,
Pascal
- Mail original -
De : Fernando Pistón Pistón fpis...@ias.csic.es
À : Steve Lianoglou mailinglist.honey...@gmail.com
Cc :
Dear R list,
I have a population with two groups. I want to simulate an gradually
increase of the number of subjects for group 1 based on mean and sd of two
variables (correlated).
Bootstrap ?
Sample ?
Simulation ? (
I just search some clues.
Thank you
Guillaume
[[alternative HTML
On 13/03/2012 08:33, Pascal Oettli wrote:
Hi Fernando,
To me, it is a good idea to regularly check the availability of
update for installed packages, using 'update.packages()'.
Specifically, update.packages(checkBuilt=TRUE) to overcome the
wrong-R-version issue (although the package
Hi R-Users,
I want to manipulate some strings in the following way. I have the
following vector with spanish municipalities:
municipios-c(Allande, Aller, Amieva, Avilés, Belmonte de
Miranda,
Degaña, Franco (El), Gijón, Gozón, Grado, Grandas de Salime,
Quirós, Regueras (Las), Ribadedeva,
Hi All,
I would like to replace default r.css that is found in C:\Program
Files\R\R-2.14.2\doc\html and C:\Program Files\R\R-2.14.2\library\package
name\html with a custom r.css file. I have some 71 packages installed and
want to replace r.css across all packages.
Windows explorer can
I have to add some clarification:
there are ONLY 4 articles (el,la,los,las) and the structure is always
the same:
NAMEOFMUNICIPALITY (El)
NAMEOFMUNICIPALITY (La)
etc.
On Tue, Mar 13, 2012 at 10:42:54AM +0100, Igor Sosa Mayor wrote:
Hi R-Users,
I want to manipulate some strings in the
On 12-03-12 5:45 PM, Michael wrote:
Dear R users,
I have been trying to draw the following 3d graphs: The solid region bounded
above by the paraboloid z = 9 - x2 - y2 and below by the unit circle in the
xy-plane.
I wanted to visualize the solid region bounded by those two graphs. I could
draw
On 03/13/2012 03:07 AM, Petr PIKAL wrote:
Dear all
with image I can plot only one set of values in one plot.
Do somebody have any insight how to put those 2 matrices into one picture
so that in one cell in image picture are both values from mat[1,1] and
mat2[1,1].
mat-matrix(1:4, 2,2)
On 13-03-2012, at 10:42, Igor Sosa Mayor wrote:
Hi R-Users,
I want to manipulate some strings in the following way. I have the
following vector with spanish municipalities:
municipios-c(Allande, Aller, Amieva, Avilés, Belmonte de
Miranda,
Degaña, Franco (El), Gijón, Gozón, Grado,
Thanks Jim
For the first glance it seems to do what I want. I must go through it more
thoroughly.
Petr
On 03/13/2012 03:07 AM, Petr PIKAL wrote:
Dear all
with image I can plot only one set of values in one plot.
Do somebody have any insight how to put those 2 matrices into one
Hi,
Probably yes, but I think this would be more easily handled through
the command prompt or some shell. On the command prompt, I would look
at xcopy. xcopy /? will show the arguments available. You will
need to do a bit of work to get a list of all the directories to copy
your r.css file
many thanks, Berend.
It works well... but with a problem because i was not completely clear
in my first email.
It works with cases such as:
Franco (El)
Regueras (Las)
but not with other cases such as:
Fauces de San Andrés (Las)
any hints? or meaybe if it is very complicated, any short
On 13-03-2012, at 11:28, Igor Sosa Mayor wrote:
many thanks, Berend.
It works well... but with a problem because i was not completely clear
in my first email.
It works with cases such as:
Franco (El)
Regueras (Las)
but not with other cases such as:
Fauces de San Andrés (Las)
any
Berend:
1. 1000 thanks for your help. It works perfectly
2. many thanks for the analysis of the expression; i will try to
understand it. Perl is really not easy to read
thanks again!
On Tue, Mar 13, 2012 at 11:51:49AM +0100, Berend Hasselman wrote:
On 13-03-2012, at 11:28, Igor Sosa Mayor
Hi, I am playing around with some data and I would like to get data that is
stored in a file like this:
test.php
GET
username=user
password=pass
test.php
GET
username=user1
password=pass1
...
to the data.frame structure, how can I do that directly in R, currently I am
doing parse with bash,
Hello
I am developing a small program that to calculate the maximum, minimum
and average.
The data.frame v is
POS DIF
4 - 4 56
4 - 3 61
3 - 3 300
3 - 327
3 - 3 33
3 - 3 87
3 - 4 49
4 - 4 71
4 - 3 121
3 - 4 138
4 - 3 15
Hi, Jim
Below is the code that I try and the result I obtained:
*br-read.table(R_beginner_starter.dat,header=TRUE,sep=\t)
library(plotrix)
barp(t(br[,c(2,4)]))
*
The result generated:
http://r.789695.n4.nabble.com/file/n4468592/ScreenHunter_01_Mar._13_17.10.jpg
Which is different with my
Hi all,
I have a basic question concerning graphs in R. I’m using the par()
function and I’m working with multiple figures by row (mfrow) but my the
hight of my figures become compressed. I have 4 rows and 2 columns (because
I want to plot 8 histograms (freq = FALSE ) on it. I know I can adapt my
I want to replace some values in my Array
e.g
data- c(1,2,3,4,5,6,7,8,9,10,11,12)
I would like to replace 1,2,3 by 1 , 4,5,6 by 2, 7,8,9 by 3 and 10,11,12 by
4
I am expecting out put
data- 1 1 1 2 2 2 3 3 3 4 4 4
I have tried replace function
replace(data, (data==1 |data==2| data==3),1)
Hello can anyone help please?
i read two words cell1, cell2 into a list. I want to turn this list
into a factor.
cell_data -list(c('cell1','cell2'))
cell_data
[[1]]
[1] cell1 cell2
factor_list - factor(cell_data)
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called
Hi,
I am working on a project, which contains S4 classes and subclasses. Lets
assume the following organisation:
A: S4 Class
B,C: inherit from A
D,E,F,G: inherit from B
H,I: inherit from C
I want to define now a generic function, which returns me the name of the
class. I can now write the
Hi
Hello
I am developing a small program that to calculate the maximum,
minimum
and average.
The data.frame v is
POS DIF
4 - 4 56
4 - 3 61
3 - 3 300
3 - 327
3 - 3 33
3 - 3 87
3 - 4 49
4 - 4 71
4 - 3 121
3 -
Hi Sybil,
You cannot turn a list into a factor. You could do:
cell_data -c('cell1','cell2')
factor_list - factor(cell_data)
or if you already have a list, unlist() or as.vector() may convert it
into a vector that you can then convert to a factor.
Cheers,
Josh
On Tue, Mar 13, 2012 at 4:29
Hello, uday,
e.g.,
(data - 1) %/% 3 + 1
would do the job in your very specific situation, but take a look at
?findInterval
for possibly more interesting (because more general) solutions.
Hth -- Gerrit
On Tue, 13 Mar 2012, uday wrote:
I want to replace some values in my Array
e.g
data-
On Tue, Mar 13, 2012 at 5:15 AM, sybil kennelly sybilkenne...@gmail.com wrote:
Thanks Josh. I'm quite new, just wondering re:factor levels?
In this example (shamelessly stolen from the internet):
schtyp
[1] 0 0 1 0 0 0 1 0 1 0 1 1 1 1 0 0 1 1 1 0
schtyp.f - factor(schtyp, labels =
try this:
x - readLines(textConnection(test.php
+ GET
+ username=user
+ password=pass
+
+ test.php
+ GET
+ username=user1
+ password=pass1
+ ))
closeAllConnections()
# process parse the data
for (i in x){
+ if (grepl(^username, i)) username - sub(.*=(.*), '\\1', i)
+ if
Hi everyone,
I have built an R package and for the sake of speed I have decided to rewrite
some part of the code in C++. In my original R code I use the pnorm, qnorm,
rnorm, pgamma, dgamma, rgamma, rbeta and runif function. First I was thinking
in going with the boost libraries, but I
On 03/13/2012 04:34 AM, Alexander wrote:
Hi,
I am working on a project, which contains S4 classes and subclasses. Lets
assume the following organisation:
A: S4 Class
B,C: inherit from A
D,E,F,G: inherit from B
H,I: inherit from C
I want to define now a generic function, which returns me the
Try this:
require(sqldf)
x - read.fwf(textConnection(4 - 4 56
+ 4 - 3 61
+ 3 - 3 300
+ 3 - 327
+ 3 - 3 33
+ 3 - 3 87
+ 3 - 4 49
+ 4 - 4 71
+ 4 - 3 121
+ 3 - 4 138
+ 4 - 3 15), width = c(7,8) , header = FALSE, as.is = TRUE)
There will be ever-so-slight performance differences due to
implementation differences (I believe R's functions are just a hair
slower because they are more exact -- though that may be a comparison
with GSL I'm thinking of), but my advice would be to use the RNGs that
come with R. They are the
Thank you Michael,
Your advices are truly appreciated!
Ian
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: 13 mars 2012 09:44
To: Ian Schiller
Cc: r-help@r-project.org
Subject: Re: [R] Coding C++ in R. What is faster : Using bosst external
Dear R Help Community,
I have a question and an answer (based on reading this forum and online
research), but I though I should share both since probably there's a much
better way to go about my solution. My question is specifically about how
to best visualise multiple response contingency
I have next table
source destine
33
77
6 6
3 4
4 4
4 3
3 3
3 3
3 3
3 3
3 4
4 4
4 3
3 4
4 3
I'm trying to create an array with the number of occurrences between the
source and destination.
Hello
is the dataset that was sent to help, has over two columns the source and
destination, is the separation of position pos
POS DIF SourceDest
4 - 4 56 4 4
4 - 3 61 4 3
3 - 3 300 3 3
3 -
I have next table
source destine
3 3
7 7
6 6
3 4
4 4
4 3
3 3
3 3
3 3
3 3
3 4
4 4
4 3
3 4
4 3
I'm trying to create an array with the number of occurrences between the
source and destination. id_ap-levels(factor(df$v_source))
num_AP-length(levels(factor(df$v_source)))
Hello,
I am sorry if there are already post that answers to this question but i
tried to find them before making this post. I did not really find relevant
posts.
I am using randomForest package for building a two class classifier. There
are categorical variables and numerical variables in my
#
#
## Iris data ##
data(iris)
Hello,
With the following code get the results array
res3-table(df$v_source,df$v_destine)
1 2 3 4 5 6 7
1 0 10 0 0 0 0 0
2 11 0 0 0 0 0 0
3 0 0 18 15 0 0 0
4 0 0 15 11 0 0 0
5 0 0 0 0 1 0 0
6 0 0 0 0 0 1 0
7 0 0 0 0 0 0 18
my
Thanks Josh. I'm quite new, just wondering re:factor levels?
In this example (shamelessly stolen from the internet):
*schtyp*
[1] 0 0 1 0 0 0 1 0 1 0 1 1 1 1 0 0 1 1 1 0
*schtyp.f - factor(schtyp, labels = c(private, public))
schtyp.f*
[1] private private public private private private
Dear userRs,
when applied the summary function to a glm fit (e.g Poisson) the parameter
table provides the categorical variables assuming that the first level
estimate (in alphabetical order) is 0.
What is the standard error for that variable then?
Are the standard errors calculated assuming
The definition of simple in Keep your class hierarchy simple and relevant to
your actual problem is quite difficult. For someone who has programmed the
classes etc, it is quite simple to understand the heritance. But for example
for someone else, who has to maintain the code and the classes, it
Hello,
I have to compute the pooled z-value and I would like to know which way is
more appropriate
b - c( -0.205,1.040,0.087)
s - c(0.449,0.167,0.241)
n - c(310, 342, 348)
z - b/s
Z - sum(z)/sqrt(length(n))
P - 2*(1-pnorm(abs(Z)))
P
w - sqrt(n)
Zw - sum(w * z)/sqrt(sum(w^2))
Pw - 1 -
This posting is only to celebrate that R-help-es (R-help for Spanish
Speakers) have reached 500
members!
(and to thank Patricia for doing the bulk of admin work).
Kjetil
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Hi,
See inline.
On Tue, Mar 13, 2012 at 6:38 AM, D_Tomas tomasm...@hotmail.com wrote:
Dear userRs,
when applied the summary function to a glm fit (e.g Poisson) the parameter
table provides the categorical variables assuming that the first level
estimate (in alphabetical order) is 0.
What
Hi,
On Tue, Mar 13, 2012 at 7:51 AM, RMSOPS ricardosousa2...@clix.pt wrote:
I have next table
source destine
3 3
7 7
6 6
3 4
4 4
4 3
3 3
3 3
3 3
3 3
3 4
4 4
4 3
3 4
4 3
It is so much easier if you use dput to provide reproducible data, as
the posting guide asks. There's
On Mar 13, 2012, at 9:38 AM, D_Tomas wrote:
Dear userRs,
when applied the summary function to a glm fit (e.g Poisson) the
parameter
table provides the categorical variables assuming that the first level
estimate (in alphabetical order) is 0.
Not really. It returns an estimate for the
Hi everybody,
I have a data set with a value and a status (positive or negative case) and
I want make a ROC Analysis. So, with ROCR Package, I have got the ROC curve
(True Positive Fraction [tpf] according 1-True Negative Fraction [1-tnf]).
http://r.789695.n4.nabble.com/file/n4469203/01.png
Hello
Error: could not find function sqldf:
Hello, I'm using R Studio, and installed the option of installing the
packages sqldbf function.
But When I run the code give the next error.
install.packages(sqldf)
library(RSQLite)
require(sqldf)
x - read.fwf(textConnection(4 - 4 56
+ 4
i have data in one file below like (i have such type of file =200,each
file have below type of data)
t
-0.15264004
0.056076439
-0.07276116
-0.00917326
-0.02069089
-0.00416232
-0.07225855
-0.02654577
-0.06131410
-0.09380202
0.057414014
-0.05239976
0.014397612
0.016145161
-0.00670587
0.018696335
Hello,
this solve my problem. table(testdata$source, testdata$destine)
Thanks
--
View this message in context:
http://r.789695.n4.nabble.com/Re-Matrix-Another-table-tp4469376p4469384.html
Sent from the R help mailing list archive at Nabble.com.
You have a conceptual problem, as pointed out by previous helpers.
You don't have a standard error for the first level of your categorical
variable because that level's effect is not estimated.
It is being used as a reference level against which the other levels of that
categorical variable are
:)
congratulations!
On Tue, Mar 13, 2012 at 08:59:56AM -0600, Kjetil Halvorsen wrote:
This posting is only to celebrate that R-help-es (R-help for Spanish
Speakers) have reached 500
members!
(and to thank Patricia for doing the bulk of admin work).
Kjetil
Hello, R-users,
I have a datafile with 37313 records and each record has 5 different
measurements on the same variables. The format looks like this: treeID, VIG0,
VIG1, VIG2, VIG3, VIG4
I was trying to convert the one row record to 5 rows record with format like
this (treeID, MEASUREMENT,
Dear R-user,
I have read a dataset from .csv file into R. This dataset includes one
column containing some data in 'date and time' format, e.g. 'dd/mm/
hh:mm'.
These data were automatically read and saved as 'factor' in R. When I was
trying to produce some plots (such as time series) with
as.POSIXct(as.character(FACTORHERE), format = %d/%m/%Y %H:%M)
Michael
On Tue, Mar 13, 2012 at 12:20 PM, Haojie Yan yhj...@googlemail.com wrote:
Dear R-user,
I have read a dataset from .csv file into R. This dataset includes one
column containing some data in 'date and time' format, e.g.
res3 + t(res3)
Michael
On Tue, Mar 13, 2012 at 8:15 AM, RMSOPS ricardosousa2...@clix.pt wrote:
Hello,
With the following code get the results array
res3-table(df$v_source,df$v_destine)
1 2 3 4 5 6 7
1 0 10 0 0 0 0 0
2 11 0 0 0 0 0 0
3 0 0 18 15 0 0 0
4 0
Take a look at
example(HoltWinters)
Michael
On Tue, Mar 13, 2012 at 11:06 AM, sagarnikam123 sagarnikam...@gmail.com wrote:
i have data in one file below like (i have such type of file =200,each
file have below type of data)
t
-0.15264004
0.056076439
-0.07276116
-0.00917326
-0.02069089
Michael,
Thanks for the pointer to the discussion in the ggplot list. It seems
that the reason of this behaviour of facet_grid() is already known and
being discussed by the developers of ggplot2.
facet_grid() reduces the original data frame with unique() before
applying the stats. If the data
On Mar 13, 2012, at 12:18 PM, Houhou Li wrote:
Hello, R-users,
I have a datafile with 37313 records and each record has 5 different
measurements on the same variables. The format looks like this:
treeID, VIG0, VIG1, VIG2, VIG3, VIG4
I was trying to convert the one row record to 5 rows
This is just a little comment to supplement Michael's excellent
solution. If there are even a few (e.g., 5 each) repeated values,
this:
as.POSIXct(as.character(levels(x)), format = %d/%m/%Y %H:%M)[x]
will be substantially faster, with the speed gains strongly associated
with the number of
On Tue, Mar 13, 2012 at 12:20 PM, Haojie Yan yhj...@googlemail.com wrote:
Dear R-user,
I have read a dataset from .csv file into R. This dataset includes one
column containing some data in 'date and time' format, e.g. 'dd/mm/
hh:mm'.
These data were automatically read and saved as
Dear All,
I hope you don't mind helping me with this small issue. I haven't been using
R in years and I'm trying to fill in a matrix
with the output of a function (I'm probably using the Matlab logic here and
it's not working).
Here is my code:
for (i in 1:length(input)){
out[i,1:3] -
Hi,
Using the multicore package and calling sample() in mclapply,
how do I get the results to be reproducible?
I know the random number is seeded by process id and so is
different for each run.
Thanks,
Lik
[[alternative HTML version deleted]]
Yes, the short answer is that you need to define out before running
the loop. The most effective way to do so will be to set up a matrix
with the exact right dimensions (if you know them up front); something
like out - matrix(NA, nrow = length(input), ncol = 9)
Michael
On Tue, Mar 13, 2012 at
Just a little typo: see below.
On Tue, Mar 13, 2012 at 1:00 PM, Haojie Yan yhj...@googlemail.com wrote:
Dear Michael,
Thanks a lot for your hints.
I have just had a try as below but still got back some error messages as
shown:
The object containing the 'date_time' data is named
Thank you very much David. I should realize myslef that operator precedence
cause the problem. Sorry about this:-) I solved the problem.
--- On Tue, 3/13/12, David Winsemius dwinsem...@comcast.net wrote:
From: David Winsemius dwinsem...@comcast.net
Subject: Re: [R] Error subscript out of
Michael comtech@gmail.com
on Mon, 12 Mar 2012 13:19:19 -0500 writes:
The problem is: by default shouldn't it use Huber's?
And it should be convex problem no?
so when I do rlm(y~x) which is a single-beta fitting problem,
shouldn't it always converge?
“In theory,
On 13-03-2012, at 17:51, Lik Wee Lee wrote:
Hi,
Using the multicore package and calling sample() in mclapply,
how do I get the results to be reproducible?
I know the random number is seeded by process id and so is
different for each run.
Don't know about those two packages.
Have a look
On Mar 13, 2012, at 12:51 PM, Lik Wee Lee wrote:
Hi,
Using the multicore package and calling sample() in mclapply,
how do I get the results to be reproducible?
I know the random number is seeded by process id and so is
different for each run.
You might want to look up the thread in last
HI All,
I got the error : package is not installed for 'arch=x64' when building my own
package for 64bit R. How can I configure the arch ? The 'R CMD config' does not
work. Thank you very much!
The detailed error is :
** testing if installed package can be loaded
Error : package 'xxx' is not
No problem.
A pro-tip for future posts: the dput() function creates a plain text
representation of the data in question which is great for email and is
nicely copy-and-pasteable. It wasn't so much a thing here, but for
large or complicated data sets, the regular console printout doesn't
always
Dear all,
First I would like to thank the ESS people's all the hard work. I am
watching the project closely and witnessing the improvements day by day.
Besides I found a strange situation using `ess-tracebug'. Please tell me
if I am wrong or this is a bug.
Start Emacs with emacs -Q and
I omit to precise that I already try to generate data based on the mean and
sd of two variables.
x=rnorm(20,1,5)+1:20
y=rnorm(20,1,7)+41:60
simu-function(x,y,n) {
simu=vector(list,length=n)
for(i in 1:n) {
x=c(x,rnorm(1,mean(x),sd(x)))
y=c(y,rnorm(1,mean(y),sd(y)))
Dear David and Jeff,
Only if you were going apply some sort of transformation that did not extend
globally
Exactly, this is why the LPCM package is great, as it assigns points
to parts of a curve.
I think I pretty much got what I need - it is not perfect yet but it
should be enough to give
On Wed, Mar 14, 2012 at 3:41 AM, cheba meier cheba.me...@googlemail.com wrote:
Hello,
I have to compute the pooled z-value and I would like to know which way is
more appropriate
b - c( -0.205,1.040,0.087)
s - c(0.449,0.167,0.241)
n - c(310, 342, 348)
z - b/s
Z - sum(z)/sqrt(length(n))
I am working on the following database of gene sets.
database-GSA.read.gmt( C:/c5.all.v2.5.symbols.gmt)
I need to filter out the gene sets that contain less than 5 genes or
more than 200 genes. I would appreciate help with that matter.
Thanks in advance
[[alternative HTML version
dear all,
apologizes for bothering with a probably stupid question but I really
don' t know how to proceed.
I have a dataset which look like df
a - c(1,2,3,4,4,4,5,5)
b - c(11,7,4,9,8,3,12,4)
df -cbind(a,b)
I would like to have one which looks like this:
a
1 11
2 7
3 4
4 9 8 3
5 12 4
a are
Is the following what you want?
a - c(1,2,3,4,4,4,5,5)
b - c(11,7,4,9,8,3,12,4)
split(b, a)
$1
[1] 11
$2
[1] 7
$3
[1] 4
$4
[1] 9 8 3
$5
[1] 12 4
Note that your df-cbind(a,b) produces a matrix, not the data.frame
that your df suggests you want. Use
The way to represent categorical variables is with factors. See ?factor.
randomForest() will handle factors appropriately, as most modeling functions in
R.
Andy
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of abhishek
Suggestion below:
On Tue, Mar 13, 2012 at 1:24 PM, guillaume chaumet
guillaumechau...@gmail.com wrote:
I omit to precise that I already try to generate data based on the mean and
sd of two variables.
x=rnorm(20,1,5)+1:20
y=rnorm(20,1,7)+41:60
simu-function(x,y,n) {
Personally, I find it easier to fix the overall size of the page and
modify the margins in line size (mar and oma rather than mai and omi),
until I get the plots the way I want them. You don't specify what OS
you're using, but in windows, I would use something like
windows(h=16, w=9)
On Tue, Mar 13, 2012 at 11:27 AM, aledanda danda.ga...@gmail.com wrote:
Dear All,
I hope you don't mind helping me with this small issue. I haven't been using
R in years and I'm trying to fill in a matrix
with the output of a function (I'm probably using the Matlab logic here and
it's not
Hello all!
I would like to create a 3d plot, with the option price explained by
the underlying price and time. Unfortunately, I can't quite get it to
work. I would very much appreciate your help!
Thanks,
Anna
# Black-Scholes Option Graph
library(lattice)
blackscholes - function(s, k,
On Mar 13, 2012, at 4:24 PM, Anna Dunietz wrote:
Hello all!
I would like to create a 3d plot, with the option price explained by
the underlying price and time. Unfortunately, I can't quite get it
to work. I would very much appreciate your help!
The usual problem with lattice calls
On 13-03-2012, at 21:40, David Winsemius wrote:
On Mar 13, 2012, at 4:24 PM, Anna Dunietz wrote:
Hello all!
I would like to create a 3d plot, with the option price explained by the
underlying price and time. Unfortunately, I can't quite get it to work. I
would very much appreciate
I would like to conduct an extra sum-of -squares test that compares a full
MANOVA model (with all 1st order interactions) to a reduced model (no
interactions) to determine if I can drop all interactions at the same time.
This is analagous to an extra sum-of-squares F-test in ANOVA, but instead
I am trying to write a function that generates one PDf containing plots from
several .csv files within a directory. When I manually execute the code it
seems to work, but not when it is a function. I think I need to return()
something, but haven't had much luck figuring out what/how.
Hi,
I would like suggestions as to how to perform rolling regressions with the
window extended one period at a time. That is, an initial sample period is
passed to estimation and that very sample is then extended one period at a
time through the remaining sample. Is there a specific package?
Dear chris33,
You can use the anova() function to compare the two multivariate linear models.
Alternatively, the Anova() function in the car package will compute type II
or type III MANOVA tests, which aren't quite what you're asking about.
I hope this helps,
John
For Windows you can use winMenuAdd function. Type ?winAddMenu to see how...
Good luck,
Marcio
www.dsr.inpe.br/~mello
On 3/6/08 10:35 AM, Alberto Monteiro wrote:
er MIMI piki PIKINHA wrote:
Hello, I´m spanish student, and I´m making the finish project of
computer science. I´m working in R
I have a vector x:
table(x)
2 3 4 5 6 7 8 91011121314
45547 11835 4692 2241 1386 820 593 425 298 239 176 158 115
15161718192021222324252627
9488766747
On Mar 13, 2012, at 4:49 PM, Berend Hasselman wrote:
On 13-03-2012, at 21:40, David Winsemius wrote:
On Mar 13, 2012, at 4:24 PM, Anna Dunietz wrote:
Hello all!
I would like to create a 3d plot, with the option price explained
by the underlying price and time. Unfortunately, I can't
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