Thanks arun,
But what is the alternative solution in windows. Please
reply me.
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I am working with a RCB 2x2x3 ANCOVA, and I have noticed a difference in the
calculation of sum of squares in a Type III calculation.
Anova output is a follows:
Anova(aov(MSOIL~Forest+Burn*Thin*Moisture+ROCK,data=env3l),type=3)
Anova Table (Type III tests)
Response: MSOIL
All,
I've devised a way to toss a coin three times and record the number of heads,
then use the table command to summarize the number of time 0, 1, 2, or 3 heads
were obtained.
n - 100
x - sample(c(H,T),3*n,replace=TRUE)
dim(x) - c(3,n)
num_heads - apply(x,2,function(x) sum(x==H))
Yes, that was what I was trying to do. Thank you very much for your reply!
Olivier
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Sent from the R help mailing list archive at Nabble.com.
On Tue, Oct 9, 2012 at 6:04 AM, David Arnold dwarnol...@suddenlink.net wrote:
All,
I've devised a way to toss a coin three times and record the number of heads,
then use the table command to summarize the number of time 0, 1, 2, or 3
heads were obtained.
n - 100
x -
Hello,
Why not use package xtable? I've just tried the following.
#install.packages('xtable')
library(xtable)
x - 1:20
y - 0.5*x + rnorm(20)
fit - aov(y ~ x)
latex.tbl - xtable(fit)
align(latex.tbl) - |lr|
print(latex.tbl)
The output was
% latex table generated in R 2.15.1 by xtable
Hello,
Try the following.
fun - function(n = 100){
x - sample(c(H,T),3*n,replace=TRUE)
dim(x) - c(3,n)
num_heads - apply(x,2,function(x) sum(x==H))
table(num_heads)/n
}
Runs - 1e1
t(replicate(Runs, fun()))
Hope this helps,
Rui Barradas
Em 09-10-2012 06:04, David Arnold
Hello Laura,
you convert your VEC model to its levl-VAR representation and employ the
diagnostic tests you mentioned. This can be accomplished with the
functions/methods contained in the package 'vars'. You might want to have a
look at the vignette of the latter package.
Best,
Bernhard
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 09/10/12 06:12, Worik R wrote:
I think I am whistling in the wind, but is there a modern symbolic debugger
for R programmes?
I am working through some one else's code, thousands of lines, that has the
occasional bug in
it, and a lot in
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 09/10/12 09:42, Rainer M Krug wrote:
On 09/10/12 06:12, Worik R wrote:
I think I am whistling in the wind, but is there a modern symbolic debugger
for R
programmes?
I am working through some one else's code, thousands of lines, that has
Dear all,
I would like to add mixed effects in a multinomial model and I am trying
to use MCMCglmm for that.
The main problem I face: my data set is a trapping data set, where the
observation at each trap (1 or 0 for several species) have been
aggregated per trapline (i.e. 25 traps). Therefore
On 10/08/2012 08:20 PM, Rantony wrote:
Hi,
Here i have a csv file, it contain like this
NAME UPDATED
- --
ABCINDIA
XYZ UK
My requirement what is, i need to change the value inside the csv file
(instead of INDIA i need to make it USA).
NAME UPDATED
Dear R developers,
I would like to have R choose the limits of the y-axis semi-automatically,
e.g., zero should be included, but the maximum should be chosen depending
on the data.
Examples:
plot(1:10, 1:10) # selects min and max automatically
plot(1:10, 1:10, ylim=c(1, 10)) # manual
On 12-10-09 12:12 AM, Worik R wrote:
I think I am whistling in the wind, but is there a modern symbolic
debugger for R programmes?
I am working through some one else's code, thousands of lines, that
has the occasional bug in it, and a lot in my understanding of it.
I cannot make setBreakpoint
On Tue, Oct 9, 2012 at 10:28 AM, Matthias Gondan matthias-gon...@gmx.de wrote:
Dear R developers,
I would like to have R choose the limits of the y-axis semi-automatically,
e.g., zero should be included, but the maximum should be chosen depending
on the data.
Examples:
plot(1:10, 1:10) #
Dear John
On Tue, 9 Oct 2012 02:07:07 +
John Jay Wiley Jr. jwile...@syr.edu wrote:
I am working with a RCB 2x2x3 ANCOVA, and I have noticed a difference in the
calculation of sum of squares in a Type III calculation.
For type III tests, you should use contrasts that are orthogonal in the
If you want something that is fast, read the file in, strip off the
colon/data, write it out to a temp and then read it back in. Here is
a 355K line file:
temp - tempfile()
input - readLines('/temp/colon.txt')
length(input)
[1] 355212
system.time(input - gsub((:[0-9]+), , input))
user
I'm making tables for prediction results of classifiers (2 classes) that show
the usual numbers, true positives, false positives, etc
I used the command
table(predictedLabels,realLabels)
to make those.
I just had a case though ,where one of the label vectors had only one class in
it. This
HI Rui,
Thanks for the alternate method.
I guess OP had trouble with pdflatex processing (output of latex(tab)) to
create the table.
A.K.
- Original Message -
From: Rui Barradas ruipbarra...@sapo.pt
To: killerkarthick karthick@gmail.com
Cc: r-help@r-project.org
Sent: Tuesday,
Hi there! I'm a newbie in R
This is my problem: I have a txt file composed by 100 matrix (256x256)
separated by a blank line! How can I save automatically the matrix in
separated txt file (100)?
e.g.
1° matrix from line 1 to line 256
257 blank line
2°matrix from line 258 to line 513
514 blank
Hi there,
I'm sorry for the bad subject decision. Couldn't describe it better...
In my dataset called dataSet I want to create a new variable column called
deal_category which depends on another column called trans_value.
In column trans_value I have values in USDm. Now what I want to do is to
If I do:
a
[1] 2012_10_01_14_13_32.445
a2
[1] 2012_10_01_14_13_32.500
strptime(a,format=%Y_%M_%d_%H_%M_%S)-strptime(a2,format=%Y_%M_%d_%H_%M_%S)
Time difference of 0 secs
Is there any time object in R that would deal with thousands of seconds?
Thanks
Agus
--
--
Dr. Agustin Lobo
Institut de
Worik R wor...@gmail.com
on Tue, 9 Oct 2012 17:12:51 +1300 wrote:
WR I cannot make setBreakpoint or findLineNum work. I get No source
WR refs found.. I am starting to loose my mind!
Indeed, as Rainer suggested, check out ESS. The ess-tracebug (part of
ESS) provides, among other
Hi Purna,
From your reply, I guess you intend to email the OP (original poster), but
somehow you got confused with the email ids. When you send reply, please cc:
to r-help.
The OP didn't gave much details about the dataset, but only the output
generated from tapply(). Output shows that the
On 09/10/2012 09:54, Agustin Lobo wrote:
If I do:
a
[1] 2012_10_01_14_13_32.445
a2
[1] 2012_10_01_14_13_32.500
strptime(a,format=%Y_%M_%d_%H_%M_%S)-strptime(a2,format=%Y_%M_%d_%H_%M_%S)
Time difference of 0 secs
Is there any time object in R that would deal with thousands of seconds?
Use factors?
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Live: OO#.. Dead:
John,
Thank you for the reply.
The data are balanced; I double-checked. I believe the contrasts are
orthogonal. Sum of squares in summary(aov) with the contrasts split out add to
the main effect. I am still unsure of where the error is for the sum of squares
calculation.
I have written some
So..
real=factor(realLabels)
predicted=factor(predictedLabels)
fl-unique(levels(real),levels(predicted))
real=factor(realLabels,fl)
predicted=factor(pl,fl)
table(real,predicted)
?
i kinda dont like
Dear Jessica,
Compare
x-c(1,1,1,0,0)
y-c(1,1,1,1,1)
table(x, y)
with
table(factor(x, levels = 0:1), factor(y, levels = 0:1))
HTH,
Jorge.-
On Wed, Oct 10, 2012 at 12:24 AM, Jessica Streicher wrote:
So..
real=factor(realLabels)
On 09/10/2012 9:24 AM, Jessica Streicher wrote:
So..
real=factor(realLabels)
predicted=factor(predictedLabels)
fl-unique(levels(real),levels(predicted))
real=factor(realLabels,fl)
predicted=factor(pl,fl)
If you provide some example data in reproducible code, I might be able to
help. Otherwise, not much I can do.
Jean
JIMonroe jim...@virginia.edu wrote on 10/08/2012 01:17:55 AM:
Jean,
It's definitely bigger now, but my axes are cut-off. As in your
example, I
had them drawn after
will add() or drop() function work more similarly as SAS?
I understand that there are not many observation points which might cause
the problem, but why can the automated process run successfully in SAS
instead?
From: David Winsemius dwinsem...@comcast.net
To: Liang
Yepp, i do not necessarily know them beforehand. Or maybe i should rather say
that they may differ from time to time but i want to be able to just copy the
code.
I can use your code that skips the first factor commands though, thanks.
On 09.10.2012, at 15:00, Jeff Newmiller wrote:
Use
For example:
How to make R write out:
Balance = 2 + 3 * IntGDP + 5 * IntUnemployment + 0.3 * d1
from the table below:
Balance Intercept IntGDP GDPNum IntUnemployment
IntInflationd1 d2 d3
3 2 3 5 0.3 0 0
How to make R write out:
Balance = 2 + 3 * IntGDP + 5 * IntUnemployment + 0.3 * d1
from the table below:
Balance Intercept IntGDP GDPNum IntUnemployment
IntInflationd1 d2 d3
3 2 3 5
0.3 0 0
Hello,
Try the following, substituting your filename for test.txt.
fun - function(filenumber, con, n, sep = , prefix = RTest){
txt - readLines(con, n = n)
tc - textConnection(txt)
on.exit(close(tc))
tbl - read.table(tc, sep = sep)[-n, ]
filename - sprintf(%s_%03d, prefix,
Hi,
i wanted to send a mail from R (using Eclips).
Currently i installed the following packages
base64_1.1
sendmailR_1.1-1
mail_1.0.tar.gz
Rmail_1.1.tar.gz
But while installing package some error was occuring.
Any other way to send a mail ?
- Thanks in advance
Antony
--
View this message
Sorry for the typo, I meant thousandths, and thanks for pointing out
the %OS format, which I had overlooked
Agus
On Tue, Oct 9, 2012 at 2:51 PM, Prof Brian Ripley rip...@stats.ox.ac.uk wrote:
On 09/10/2012 09:54, Agustin Lobo wrote:
If I do:
a
[1] 2012_10_01_14_13_32.445
a2
[1]
Why are the first 5 variables kept in the stepwise result??
I don't know, for your data set.
However, AIC is in my limited experience less likely to reject a term than
rejection based on p-value at 95% confidence. It's not the same criterion, so
there's no immediate reason it should give the
Can i somehow append objects to an .Rdata file?
I didn't see an option for it in the save() method.
dump() won't work since i have s4 objects in there.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
Matrix::spMatrix can help.
Read your data file with lns - readLines(fileName) to get
something like
lns - c(1 5:15 7:17 9:19,
2 2:22 8:28,
4 6:46)
Then use a function like the following that reformats the
data to the i=row,j=col,x=value vectors that spMatrix
Thanks Arun - the different lengths in the list elements was the sticking
point. Does anyone have suggestions for packages or R books on indexing/
reshaping datasets for an intermediate user like myself?
*Ben Caldwell*
On Mon, Oct 8, 2012 at 3:26 PM, arun smartpink...@yahoo.com wrote:
Hi,
On 09/10/2012 16:35, Jessica Streicher wrote:
Can i somehow append objects to an .Rdata file?
No. See the 'R Internals' manual for the details.
BTW, it is '.RData': R is case sensitive and so are many file systems.
It sounds like you should be using a database of the results of
saveRDS()
Dear all,
Perhaps this is not the place but... we are going to print some stickers
to take them to a conference for a sticker exchange with other free
software organisations. Last year I printed very simple stickers and
this year I would like to take better stuff to the meeting. Does anyone
have
The R site has a number of them:
http://developer.r-project.org/Logo/
On Tue, Oct 9, 2012 at 12:27 PM, Virgilio Gómez-Rubio
virgilio.go...@uclm.es wrote:
Dear all,
Perhaps this is not the place but... we are going to print some stickers
to take them to a conference for a sticker exchange
Hello,
As for creating the new variable try
dataSet - within(dataSet,
deal_category - ifelse(trans_value 200, low,
ifelse(trans_value 500, medium, high)))
And the rest seems ok. Run the code and see if it is.
Hope this helps,
Rui Barradas
Em 09-10-2012 10:25, fxen3k escreveu:
Hi
Hi Jim,El mar, 09-10-2012 a las 12:39 -0400, jim holtman escribió:
The R site has a number of them:
http://developer.r-project.org/Logo/
Many thanks. That was what I printed last year, but perhaps someone has
a logo with some text on it, etc.
Cheers,
Virgilio
It might be simpler to use cut():
trans_value - c(3000, 200, 400, 50, 2000)
cut(trans_value, breaks=c(-Inf, 200, 500, Inf),
labels=c(low,medium,high))
[1] high lowmedium lowhigh
Levels: low medium high
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
Hi: I've looked around and I must be missing it because it's probably
somewhere. Does someone know how to convert an object of class dgCmatrix
to a regular matrix. I can send someone the data if they need it but it's
too big to include here.
I read the data in using
temp-readMat(movielens.mat)
Dear R-helpers,
Ive got a summary of results from a by() call that I am making with a list
of more than two of factors not very different from the example in the by()
help page
require(stats)
by(warpbreaks[, 1], warpbreaks[, -1], summary)
The result of the command gives a
On Tuesday, October 9, 2012, Benjamin Caldwell wrote:
Thanks Arun - the different lengths in the list elements was the sticking
point. Does anyone have suggestions for packages or R books on indexing/
reshaping datasets for an intermediate user like myself?
Perhaps Spector on Data
On 09-10-2012, at 19:04, Mark Leeds marklee...@gmail.com wrote:
Hi: I've looked around and I must be missing it because it's probably
somewhere. Does someone know how to convert an object of class dgCmatrix
to a regular matrix. I can send someone the data if they need it but it's
too big to
Hello,
Try
do.call(data.frame, by.list)
Hope this helps,
Rui Barradas
Em 09-10-2012 17:53, Jesus Frias escreveu:
Dear R-helpers,
I've got a summary of results from a by() call that I am making with a list
of more than two of factors not very different from the example in the by()
On Tue, Oct 9, 2012 at 11:42 AM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
Try
do.call(data.frame, by.list)
I don't think data.frame inside do.call works in this context. May need it
on the outside to do the job (Only OK here since there is no mixture of
numeric and character/factors
Ilai, et. al:
Yes. The OP might also look at the result of:
t(simplify2array (by.list))
The only wrinkle here (with either rbind or simplify2array) is getting
the labels correct if the design is not fully crossed -- i.e. if some
groups are missing so that expand.grid() won't work. Then you
And how can I write the units of my axis but outside the square root symbol
I have
plot(1:10, ylab=bquote(Log(sqrt(Total area (mm)
but I need it as in the attached picture
http://r.789695.n4.nabble.com/file/n4645602/square_root_mm1.jpg
--
View this message in context:
On Oct 9, 2012, at 11:13 AM, 21rosit wrote:
And how can I write the units of my axis but outside the square root symbol
I have
plot(1:10, ylab=bquote(Log(sqrt(Total area (mm)
but I need it as in the attached picture
http://r.789695.n4.nabble.com/file/n4645602/square_root_mm1.jpg
Look at help(plotmath).
plot(1:10, xlab=bquote(Log(sqrt(Total area) * (mm # small space before
(mm)
plot(1:10, xlab=bquote(Log(sqrt(Total area) ~ (mm # more space before
(mm)
For your next question:
# now use .(var) to interpolate value of variable 'var' into a plot label.
On Tue, Oct 9, 2012 at 12:25 PM, Bert Gunter gunter.ber...@gene.com wrote:
The only wrinkle here (with either rbind or simplify2array) is getting
the labels correct if the design is not fully crossed -- i.e. if some
groups are missing so that expand.grid() won't work. Then you might
have to
Dear all,
I just found a weird behavior of the timeDate related functions Sys.timeDate()
and as.timeDate().
Both of them take place when showing fractions of seconds and I think they
might have the same source.
Do you know if it should be considered a bug of Sys.timeDate()? Also, what is a
Dear John,
-Original Message-
From: John Jay Wiley Jr. [mailto:jwile...@syr.edu]
Sent: Tuesday, October 09, 2012 9:17 AM
To: John Fox
Cc: r-help@r-project.org
Subject: RE: [R] car::linearHypothesis Sum of Sqaures Error?
John,
Thank you for the reply.
The data are balanced;
Hello R User,
I have a data set where subject( Id) are frequently measured. For
example, the size of the data set is 75 by 2 and has following
frequency distribution.
idfreq
1 30
2 20
3 25
I want to create a variable (say seq) containing sequential count for
each id. I mean
Hi,
when using the grid package, I've come across this weird behaviour
where a call to plot.new() will start a new page for a multi-page pdf,
but then the margins will somehow behave strangely for all but the
first page: here is some code:
pdf(test.pdf); plot.new(); grid.rect(gp =
sequence(c(4,2,0,10))
[1] 1 2 3 4 1 2 1 2 3 4 5 6 7 8 9 10
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
Of bibek sharma
Sent: Tuesday, October 09, 2012
John,
Again, thank you for your reply.
Unfortunately, I didn't specify that I had previously changed the contrast
options to contr.sum. I was aware of that requirement, and I still found that
the sum of squares didn't add up.
It seems that you made the SS add up by removing the covariate.
On Tue, Oct 9, 2012 at 1:26 PM, Ali Tofigh alix.tof...@gmail.com wrote:
Hi,
when using the grid package, I've come across this weird behaviour
pdf(test.pdf); plot.new(); grid.rect(gp = gpar(fill=blue));
plot.new(); grid.rect(gp = gpar(fill=blue)); dev.off()
The first page is filled
The plot.new function is for base graphics and base and grid graphics
don't usually play well together. You probably want to use
grid.newpage function instead.
On Tue, Oct 9, 2012 at 1:26 PM, Ali Tofigh alix.tof...@gmail.com wrote:
Hi,
when using the grid package, I've come across this weird
Dear John,
-Original Message-
From: John Jay Wiley Jr. [mailto:jwile...@syr.edu]
Sent: Tuesday, October 09, 2012 3:37 PM
To: John Fox
Cc: r-help@r-project.org
Subject: RE: [R] car::linearHypothesis Sum of Sqaures Error?
John,
Again, thank you for your reply.
Unfortunately,
Dear R users, Terry Theneau,
thank you very much for you answer. I'm running R 2.15.1 (32 bits) and
coxme 2.2-3. Here is a small R code which reproduces the problem (I fitted
a model with random effects whereas it is useless), it gives exactly the
same estimations of the variances than on my real
You're right, I was in a hurry. This one works.
x - rnorm(100)
a - sample(letters[1:4], 100, T)
by.list - by(x, a, summary)
do.call(rbind, as.list(by.list))
(I would also prefer aggregate.)
Rui Barradas
Em 09-10-2012 19:46, ilai escreveu:
On Tue, Oct 9, 2012 at 12:25 PM, Bert Gunter
Le lundi 08 octobre 2012 à 20:33 -0700, Peter Langfelder a écrit :
run
capabilities(what=cledit)
in your R terminal session. If you get FALSE, your R was compiled
without command line editing support which you need for the up arrow
action.
FWIW, it works with the R version packaged in
Hello,
I have a vector of double values between 0 and 100
I would like to draw a synthetic distribution of this vector to see
graphically how the values are distributed between 0 and 100.
How can I do that ?
Thomas
__
R-help@r-project.org mailing
??
Perhaps:
?density
?plot.density
-- Bert
On Tue, Oct 9, 2012 at 1:06 PM, Thomas Carrié tho...@free.fr wrote:
Hello,
I have a vector of double values between 0 and 100
I would like to draw a synthetic distribution of this vector to see
graphically how the values are distributed between 0
John,
Thank you.
There are different means of the covariate among the levels in my contrasts,
which is producing the non-orthogonality and non-additivity of the sum of
squares.
Should be all set.
Cheers,
John
From: John Fox [j...@mcmaster.ca]
Sent:
Thanks!
*Ben Caldwell*
On Tue, Oct 9, 2012 at 10:18 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
On Tuesday, October 9, 2012, Benjamin Caldwell wrote:
Thanks Arun - the different lengths in the list elements was the sticking
point. Does anyone have suggestions for packages
I have been trying to install RMySQL on Windows 7 following the
procedure at:
http://biostat.mc.vanderbilt.edu/wiki/Main/RMySQL
I think I have properly installed RTools and created a proper
Renviron.site file saying:
MYSQL_HOME=C:/Program Files/MySQL/MySQL Server 5.5
When I try to install
Hi,
You can also try this:
set.seed(1)
dat1-data.frame(id=rep(c(1,2,3),c(30,20,25)),value=rnorm(75,15))
dat2-data.frame(stack(lapply(split(dat1,dat1$id),FUN=function(x)
1:nrow(x))),value=dat1[,2])
colnames(dat2)[1:2]-c(seq1,id)
dat2$seq1
# [1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
Dear R help,
Thanks again for the responses. I increased the lower constraint to:
lower = list(p1 = 0.0001, p2 = 0.0001, mu1 = 0.0001, mu2 = 0.0001).
I also included an upper box constraint of:
upper = list(p1 = Inf, p2 = Inf, mu1 = p1t, mu2 = p2t).
Making these changes improved the rate of
Dear useRs,
i am using NbClust to determine appropriate number of cluster for hclustering.
i am consistently getting the following error
Error in if (is.na(n) || n 65536L) stop(size cannot be NA nor exceed 65536)
:
missing value where TRUE/FALSE needed
Does any one know where i am
On Tue, Oct 9, 2012 at 4:37 PM, eliza botto eliza_bo...@hotmail.com wrote:
Dear useRs,
i am using NbClust to determine appropriate number of cluster for
hclustering. i am consistently getting the following error
Error in if (is.na(n) || n 65536L) stop(size cannot be NA nor exceed
65536)
Thankyou very much peter,
here is the code
filelist =
list.files(pattern = .*.txt)
datalist =
lapply(filelist, function(x)read.table(x, header=T))
datafr =
do.call(cbind, datalist)
x-datafr
colnames(x)
- c(1: 38)
m=matrix(x, nrow=365)
mat1-mlist1-list()
for(i in
Hi good R folks,
I am hoping that you could help me resolve this issue. I tried finding
answers online but to no avail.
I keep getting this Error in x^2 : non-numeric argument to binary operator
using multiple different codes, ones which have been verified to work by my
professor and other
I am using Donlp2 package to solve a non-linear problem, but there's an error
I always meet:
Error in matrix(unlist(value, recursive = FALSE, use.names = FALSE), nrow =
nr, :
attempt to set an attribute on NULL
I have been suffering from this bug for a long time. I'll be very grateful
if
Hi Eliza,
this is not __reproducible__ code - how am I supposed to know what's
wrong when I don't have the input files you use? Please read the help
for NbClust carefully and check that all your input variables have the
correct dimensions. Some of the input seems strange, for example the z
matrix
On Oct 9, 2012, at 2:30 PM, bobo wrote:
Hi good R folks,
I am hoping that you could help me resolve this issue. I tried finding
answers online but to no avail.
I keep getting this Error in x^2 : non-numeric argument to binary operator
using multiple different codes, ones which have been
On Tue, Oct 9, 2012 at 5:08 PM, Robert Baer rb...@atsu.edu wrote:
I have been trying to install RMySQL on Windows 7 following the procedure
at:
http://biostat.mc.vanderbilt.edu/wiki/Main/RMySQL
I think I have properly installed RTools and created a proper Renviron.site
file saying:
But sprintf is itself vectorized. If you give it vectors, it returns vectors.
So you could obtain that apply-result more efficiently by passing a bunch of
column vectors of data. There happens to be a convenient object called a data
frame that holds a bunch of similar-length vectors.
DF -
I'm completely new at R... I have sinkhole survey data (lat, long, and
elevation) and have been trying to plot a rotatable 3d plot for several
hours... cannot get it right. Examples I see tend to be grid data (one
elevation value per grid cell); however, my data are more random (known
elevations
HI,By customising sequence(),
set.seed(1)
dat1-data.frame(id=rep(c(1,2,3),c(30,20,25)),value=rnorm(75,15))
#Either
dat1$seq1-unlist(sapply(table(dat1$id),FUN=function(x) 1:x),use.names=FALSE)
#or
dat1$seq1-unlist(sapply(count(dat1$id)$freq,FUN=function(x) seq_len(x)))
#can be used.
A.K.
On Oct 9, 2012, at 5:41 PM, ariklee wrote:
I'm completely new at R... I have sinkhole survey data (lat, long, and
elevation) and have been trying to plot a rotatable 3d plot for several
hours... cannot get it right. Examples I see tend to be grid data (one
elevation value per grid cell);
You should help us per the posting guide reproducible sample data, code you
have tried that you thought would work, why you think it did not, output of
sessionInfo function...
Note that you can learn a lot by doing this exercise, your problem may not be
where you think it is (or where we
Hello,
Please excuse my ignorance; my statistical background is fairly poor.
I am looking to do a model II regression in R, and determine if the
intercept is significantly greater then 0. I have downloaded the package
lmodel2, which gives me the 95% confidence interval of the intercept.
This worked perfectly, thank you!
(Sorry for the delay, was traveling and didn't get a chance to test it until
now.)
Kirsten
On Oct 4, 2012, at 1:30 PM, David Winsemius dwinsem...@comcast.net wrote:
On Oct 3, 2012, at 12:58 PM, Kirsten wrote:
Hey everyone,
I'm working on a contour
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