Dear R users,
I have an array that has matrices that i want BB[16,5,2:27]
i want to put each of the 26 matrices into a List
thanks in advance
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
One approach is:
BB - rnorm(6*5*27)
dim(BB) - c(6, 5, 27)
lapply(2:27, function (i) BB[, , i])
I hope it helps.
Best,
Dimitris
On 11/12/2012 8:56 AM, Haris Rhrlp wrote:
Dear R users,
I have an array that has matrices that i want BB[16,5,2:27]
i want to put each of the 26 matrices into a
sessionInfo()R version 2.15.2 (2012-10-26)
Platform: i686-pc-linux-gnu (32-bit)
locale:
[1] LC_CTYPE=en_GB.UTF-8 LC_NUMERIC=C
LC_TIME=en_GB.UTF-8
[4] LC_COLLATE=en_GB.UTF-8 LC_MONETARY=en_GB.UTF-8
LC_MESSAGES=en_GB.UTF-8
[7] LC_PAPER=C LC_NAME=C
LC_ADDRESS=C
[10]
Hi and thanks a lot for your advices. Both work fine!
Thanks GeoPhagUS
--
View this message in context:
http://r.789695.n4.nabble.com/Labeling-position-barchart-tp4649031p4649294.html
Sent from the R help mailing list archive at Nabble.com.
__
Why the result of chisq.test in R-2.15.1 between version Linux and
version Windows XP is different.
command is like attachment
Thank you.
--
王佳茜
实习生 助理研究员 生物信息分析师
华大基因研究院|科学技术体系|3M|人方向|泛亚太
广东省深圳市盐田区北山工业区11栋
本科生
华中科技大学|生命科学与技术学院|系统生物学系
湖北省武汉市珞瑜路1037号
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Clive Nicholas
Sent: Monday, November 12, 2012 8:06 AM
To: r-help@r-project.org
Subject: [R] Bootstrapping issues
sessionInfo()R version 2.15.2 (2012-10-26)
Platform:
2012/11/12 王佳茜 wangjiaq...@genomics.cn:
Why the result of chisq.test in R-2.15.1 between version Linux and
version Windows XP is different.
command is like attachment
Thank you.
The R-help mail servers are not a big fan of attachments. Please
resend putting your data and commands inline.
Hi,
You can also use ?alply()
library(plyr)
BB-array(sample(1:500,3*5*27,replace=TRUE),dim=c(3,5,27))
res-alply(BB,3,function(x) x)[2:27]
str(res)
List of 26
#$ 2 : int [1:3, 1:5] 337 476 331 481 168 111 439 151 399 430 ...
# $ 3 : int [1:3, 1:5] 77 171 225 498 277 37 429 472 215 351 ...
# $ 4 :
Hi,
Please see the subject line ;)
Goolge only let me to people asking the same question, but no answers ... Am
I out of luck with trying to in-line document Reference Classes?
Thank you for your input.
Sincerely, Joh
__
R-help@r-project.org mailing
David Winsemius dwinsemius at comcast.net writes:
On Nov 10, 2012, at 9:22 PM, mmosalman wrote:
I want to find ML estimates of a model using mle2 in bbmle package. When I
insert new parameters (for new covariates) in model the log-likelihood value
does not change and the estimated
Thank you all for your responses, the lapply works perfectly. The
example I gave IS odd. I only realized after I posted that tt had 5
rows and should have only had 3, so I apologize for that (I initially
had X to have 5 list elements).
Bert, I tend to use for loops in excess and often
On Nov 11, 2012, at 7:13 PM, Gabriel Toro wrote:
Hi,
I am trying to use a legend title that is a bit too long for one line. To
try to break the title in two lines, I am using
legend (title=Top of Title\nbottom of title, etc. )
R prints the title as two lines, but the top line is
HI @ all,
I'm looking for a simple solution to supress the y-axis - but only the drawn
scale - not the values.
Only the numbers should be displayed.
I tried yaxt=n but there everything of the y-axis is supressed.
Thanks
GeO
--
View this message in context:
Dear
I want to know how to plot 1-KM and Cumulative incidence curves in on
graph.
Thanks
--
View this message in context:
http://r.789695.n4.nabble.com/1-KM-and-Cumulative-incidence-tp4649301.html
Sent from the R help mailing list archive at Nabble.com.
I'm beginner with R language
My goal is to write a function that takes an input Erlang entering your
· Name
· Name
· Date of birth.
The program will calculate age and display output
first
I do know the system date (month, day, year)
I find with Sys.Date ()
I found a function. net to
From what I can tell by reading forum posts etc., this is not a trivial
issue. An answer in 2008 indicated some directions, but I'm curious whether
any developments have been made since then.
In my data set I have 182 observations with a binomial response, a 2-level
explanatory factor, and x and
[1]Click here to unsubscribe if you no longer wish to receive our emails
Dear Recruiter,
Let me present you with list of consultants currently available.
E-Mail me for below candidate details.
My Mail ID : srika...@codeforce.com
Consultant Job Title Total Experience Current
Hi,
I am trying to fit a model with lmer in R and proc glimmix in SAS. I have
simplified my code but I am surprised to see I get different results from
the two softwares.
My R code is :
lmer(y~age_cat + (1|cat),data=fic,family=binomial(link = logit), NaGQ=1)
My SAS code is :
ods output
On 11/12/2012 06:50 AM, cachimo wrote:
Dear
I want to know how to plot 1-KM and Cumulative incidence curves in on
graph.
Thanks
For 1-KM, see the fun argument to plot.survfit. Do you mean the
Cumulative incidence curve for competing risks? If so, see the cmprsk
package for one approach.
It's due to the different coding of contrasts. Post to R-sig-mixed
models for a fuller explanation (though it has nothing to do with
mixed models; the same would happen with lm) or search on a suitable
phrase (e.g. contrast coding in SAS versus R) in R archives or via
google etc.
-- Bert
On Mon,
Hello,
Like this?
plot(1:10, yaxt = n)
axis(2, at = 1:10, labels = 1:10, tick = FALSE)
Hope this helps,
Rui Barradas
Em 12-11-2012 10:08, Geophagus escreveu:
HI @ all,
I'm looking for a simple solution to supress the y-axis - but only the drawn
scale - not the values.
Only the numbers
I have a matrix which I wanted to convert to a data frame. As I could not
succeed and resorted to export to csv and reimport it again. Why did I fail
in the attempt and how can I achieve what I wanted without this
roundabouts?
The original matrix:
str(comb_model0)
num [1:90, 1:4] 3.5938
I have asked the same question on stackoverflow but did not get a satisfying
answer.
I am trying to simulate a lognormal spatial random field but I need the
simulated value in a certain range. So I need some easy to use functions to
generate a truncated Gaussian field to start with. To be
hi,
I want to know just enter a string value
entering a numeric value is make with the function scan () or scan (nmax =
..)
but it does not work for string
my goal is to enter three string: name and surname and date of birth
I try with this code but it shows me errors
print (enter the
Alen, look at
?scan
and there particularly at the argument 'what'.
Hth -- Gerrit
On Mon, 12 Nov 2012, alen wrote:
hi,
I want to know just enter a string value
entering a numeric value is make with the function scan () or scan (nmax =
..)
but it does not work for string
my goal is
scan(what=, nmax=1,sep=\n)
1: A four word string.
Read 1 item
[1] A four word string.
readline(prompt=Please type a line )
Please type a line A line of text
[1] A line of text
readLines(n=1)
A line of text.
[1] A line of text.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
Hello,
I'm unable to reproduce your error, removing the space in Std. Error
and changing t value to t.value the following read in as data.frame
with no problems.
x - read.table(text=
Estimate Std.Error t.value Pr(|t|)
(Intercept) 3.593793
Hello all,
I used the MICE procedure (of package mice) to impute a dataset (I
got m imputed datasets). Now I would like to fit a GLM with a poisson
error distribution to regress a count variable on 14 continuous
predictor variables and test for the significance of the different
predictors by
Zhenglei Gao zhenglei.gao at bayer.com writes:
I have asked the same question on stackoverflow but did not get a
satisfying answer.
I am trying to simulate a lognormal spatial random field but I need
the simulated value in a certain range. So I need some easy to use
functions to generate
On Mon, Nov 12, 2012 at 1:49 PM, alen tarhouni_w...@hotmail.fr wrote:
I'm beginner with R language
My goal is to write a function that takes an input Erlang entering your
· Name
· Name
· Date of birth.
The program will calculate age and display output
first
I do know the system date
Since you specifically want either nov or dec
you actually don't need '=' use instead '= ='
Felipe D. Carrillo
Supervisory Fishery Biologist
Department of the Interior
US Fish Wildlife Service
California, USA
http://www.fws.gov/redbluff/rbdd_jsmp.aspx
From: Roslina Zakaria zrosl...@yahoo.com
Hello
i did a stacked barplot using ggplot and R arranged the bars of the items in
different orders. i don´t know why. but i want to have the same order in
every stacked bar.
I used the code
data1 - read.table(N_O_W_MAI.txt, header=TRUE, dec = ,)
attach(data1)
Hi and thanks for your answer,
I need no axis - only the labels.
In your example 1 to 10.
Greetz
GeO
--
View this message in context:
http://r.789695.n4.nabble.com/no-drawn-y-axis-but-values-tp4649298p4649324.html
Sent from the R help mailing list archive at Nabble.com.
Hello ,
I'm new to R and don't really understand how to use the function apply
instead of a for loop, particularly for a function with multiple entries.
I have a big data file and would like to apply a function in multi thread to
accelerate the processus.
I have a data frame containing values
Since you did not provide sample data (use dput instead of posting
links to 'jpg' files), you can probably do it without loops:
k=resp[,5]
CO2umol - resp[,6]*((Press*infoch[k,11]*1e-6)/(R*(resp[,7]+273.15)))
CO2v - CO2umol/(infoch[k,10])
CO2s - CO2umol/(infoch[k,9]
On Mon, Nov 12, 2012 at 12:39
Hello,
If you want to completely remove the axis, overplot in color white.
plot(1:10, yaxt = n)
axis(2, at = 1:10, labels = 1:10, tick = FALSE)
axis(2, at = 1:10, labels = 1:10, col = white)
Hope this helps,
Rui Barradas
Em 12-11-2012 17:18, Geophagus escreveu:
Hi and thanks for your answer,
Hi: Not sure if totally relevant because I didn't read it but it might help
or atleast
be of interest.
http://journal.r-project.org/archive/2010-1/RJournal_2010-1_Wilhelm+Manjunath.pdf
On Mon, Nov 12, 2012 at 12:15 PM, Ben Bolker bbol...@gmail.com wrote:
Zhenglei Gao zhenglei.gao at bayer.com
Or perhaps something this:
plot(1:10, axes = FALSE, ann = FALSE)
axis(2, at = 1:10, tick = FALSE, lty = blank)
and if you want the x axis:
axis(1, at = 1:10)
Not clear if you want the frame around the plot region or not. If so, there are
some options using ?box and see ?par, specifically,
On 12-11-12 02:05 PM, Mark Leeds wrote:
Hi: Not sure if totally relevant because I didn't read it but it might
help or atleast
be of interest.
http://journal.r-project.org/archive/2010-1/RJournal_2010-1_Wilhelm+Manjunath.pdf
This definitely looks relevant. The critical question will be
HI,
I also have no trouble in reading the example data you gave, which BTW do not
have any duplicate rownames. I guess there must be some rows in the original
dataset that must be repeated. For example:
comb_model-read.table(text=
Estimate Std.Error tvalue
May be I have not clearly explained my problem. Le me try it again. My
problem was with the matrix comb_model0 . I have tried to convert it to a
data frame (xx), but could not succeed . As a result I have exported it to a
test.csv file and re-imported it. Data frame test is the product of
HI,
May be this helps:
par(bty=n)
plot(1:10,yaxt=n)
axis(2, at = 1:10, labels = 1:10, tick = FALSE)
A.K.
- Original Message -
From: Geophagus f...@retposto.net
To: r-help@r-project.org
Cc:
Sent: Monday, November 12, 2012 12:18 PM
Subject: Re: [R] no y-axis
Hi and thanks for your
When I say:
Sys.time()
[1] 2012-11-12 21:30:14 NZDT
But that is not what my clock on the wall and my system say. Cannot show
you my clock but...
worik@lemy:/tmp$ date
Tue Nov 13 10:32:20 NZDT 2012
Sys.time() is returning GMT
$version.string
[1] R version 2.14.1 (2011-12-22)
Seems irrelevant to me. You can export the data to separate files directly from
the matrix using matrix indexing. i.e.
for (i in 1:2) {
write.table( mat[rowcropping[2*i-1]:rowcropping[2*i],],paste0(file,i,.dat)
}
Please use reply to all to keep the discussion on the list.
On 11/6/2012 11:11 PM, ChangLH wrote:
Hi,
Color of my step plot is now by default. Now I'd like to change the color as
the grey scale I specified. I don't know why I got three black plot. Here I
attach two version of codes. The first one produces a step plot with color
by default. The second
Hi:
How do I select different variables from a list of data frames.
I have a list of 13 that looks like below. Each data frame has more variables
than I need. How do I go through the list and select the variables that I need.
In the example below, I need to get the variables a, and q10 and q14
My apologies for returning to this issue after such a considerable
length of time ... but I wanted to check the result in Cramer's book,
and only yesterday managed to get myself organised to go the
library and check it out.
What bothers me is what happens when f(Q.p) = 0. The formula
that you
Hello,
Try the following.
lapply(mylist, function(x) x[,grep(a|q, names(x))])
Hope this helps,
Rui Barradas
Em 12-11-2012 22:34, Simon Kiss escreveu:
Hi:
How do I select different variables from a list of data frames.
I have a list of 13 that looks like below. Each data frame has more
Hi,
In addition to:
mylist-list(df1=data.frame(a=seq(1,10,1), c=seq(1,10,1), q10=rep('favour',
10)), df2=data.frame(a=seq(1,10,1), b=seq(15,24,1), q14=rep('favour', 10)))
lapply(mylist,function(x) x[colnames(x)%in% c(a,q10,q14)])
you could also use: lapply(seq_along(mylist),function(i)
Petr Pikal replied:
[...]
The following works
results - boot(data=test, statistic=bs, R=1000, A~B+C+D+C*D)
Actually it does not work either
Correct, but I _did_ get it to work shortly before my initial post (sorry
for not showing it, but I didn't save the output - silly me).
What
On Tue, Nov 13, 2012 at 11:59 AM, Rolf Turner rolf.tur...@xtra.co.nzwrote:
My apologies for returning to this issue after such a considerable
length of time ... but I wanted to check the result in Cramer's book,
and only yesterday managed to get myself organised to go the
library and check
Dear folks –
I have a large (26 gig) ASCII flat file in fixed-width format with about 10
million observations of roughly 400 variables. (It is 51 years of Current
Population Survey micro data from IPUMS, roughly half the fields for each
record). The file was produced by automatic process in
Posting guide warns you to provide a reproducible example, which would include
enough data to test code.
As a general point of information I can say that data ordering in R graphs is
normally driven by the factor level ordering, and you usually have to specify
that explicitly when you convert
I am trying to match SAS output with R.
I am using Proc Npar1way with D option to get KS test statistic.
•
Here X is a binary dependent variable and Y is the predicted probabilities;
proc npar1way data = mydata D; class x; var y; run;
When i try this in R
ks.test(x, fitted(y),alternative =
Hi Arun:
Exactly. That's exactly what I'm looking for!
On 2012-11-12, at 5:55 PM, arun kirshna [via R] wrote:
Hi,
Seems like there was a typo in mylist
mylist-list(df1=data.frame(a=seq(1,10,1), c=seq(1,10,1), q10=rep('favour',
10)), df2=data.frame(a=seq(1,10,1), b=seq(15,24,1),
Hello,
First time poster here so let me know if you need any more information. I am
trying to run an ordered probit with maximum likelihood model in R with a
very simple model (model - econ3 ~ partyid). Everything looks ok until i
try to run the optim() command and that's when I get Error in
thanks, that works fine! good idea.
I have one last question regarding this problem.
My y-scale now is grouped from 0 - 4000 in 1000.
Is it possible to set the scale into not equal breaks like
5,10,100,1000,5000 ?
My axis now:
axis(2,at=seq(0,4000,1000),col = white, las=1)
thanks a lot
GeO
The problem seems to be that at least two of the 90 rows of your matrix have
the same rowname (called dimnames in a matrix). When you converted to .csv,
the rownames were added as a variable (called X) so they were not checked
for duplicates.
Try length(unique(test$X)). You should get a number
Hi,
I have a R output that looks as follow:
Rad:0
Rad1:2
Rad3:3
I want to make a new matrix that looks like : sample size is 2400
Variable n11 n12
Rad 0 2400-0=2400
Rad1 2 2400-2
Rad3 3 2400-3
Thanks a lot for your time and help:)
Best,Farnoosh Sheikhi
it works really faster !
thank you
--
View this message in context:
http://r.789695.n4.nabble.com/Using-apply-instead-of-for-loop-multithreading-tp4649326p4649346.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org
HI,
You can do this in many ways:
dat1-read.table(text=
med1,med2,med3
1,0,1
0,1,1
2,0,0
,sep=,,header=TRUE)
#1st method
library(reshape)
dat2-melt(dat1)
dat3-aggregate(dat2$value,by=list(dat2$variable),sum)
colnames(dat3)-c(name,sum(n11))
dat3
# name sum(n11)
#1 med1
Hi,
You can try this:
dat1-read.table(text=
Rad:0
Rad1:2
Rad3:3
,sep=,header=FALSE)
Variable-do.call(rbind,lapply(strsplit(as.character(dat1[[1]]),split=:),`[`,1))
n11-do.call(rbind,lapply(strsplit(as.character(dat1[[1]]),split=:),function(x)
as.numeric(x[2])))
n12-2400-n11
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of SASandRlearn
Sent: Monday, November 12, 2012 5:55 PM
To: r-help@r-project.org
Subject: [R] Proc Nnpar1way with D option - equivalent in R
I am trying to match SAS output with
63 matches
Mail list logo
