On 22/11/2012 11:23, Manca Marco (PATH) wrote:
Dear BioConductor and R fellow users
I apologize in advance for double posting, but I am not sure which list would
actually be best fit for this message.
The list relevant to the installation of R you used. Was this a binary
installation?: if
On 22-11-2012, at 22:55, Дмитрий Островский wrote:
I am trying to optimize custom likelyhood with nlminb()
Arguments h and f are meant to be fixed.
example.R:
compute.hyper.log.likelyhood - function(a, h, f) {
a1 - a[1]
a2 - a[2]
l - 0.0
for (j in 1:length(f)) {
l - l +
On 11/23/2012 06:33 PM, Ripples wrote:
Hi,
I'm trying to plot stacked barplot with lines on it. Here is the data.
emp days val1 val2 score
1 21 1 0 1200
2 35 1 1 na
3 42 na na 3000
4 53 2 1 2100
5 64 1 0 na
6 73 na na 1400
My X-axis is days. I'm looking to plot val1,val2 as stacked bars and
On Nov 23, 2012, at 4:26 AM, Brian Feeny bfe...@mac.com wrote:
I know if I have a dataframe with columns y, x1, x2 and I wish to have y as
my y value and x1 and x2 as x values I can do:
y ~ x1 + x2
or
y ~.
but can someone explain what . actually is or what its transposed into?
Thank you! I searched in the manual, but I did not see where this is
mentioned, I looked under operators
and in some of the formula documentation.
Brian
On Nov 23, 2012, at 3:15 AM, Michael Weylandt michael.weyla...@gmail.com
wrote:
On Nov 23, 2012, at 4:26 AM, Brian Feeny
Thanks - that's the solution!
Felix
Am 23.11.2012 um 03:03 schrieb Peter Ehlers ehl...@ucalgary.ca:
On 2012-11-22 01:16, Felix Schönbrodt wrote:
Hello,
I try to increase the distance between tick labels and ticks in a lattice
wireframe plot. Here's a minimal example:
## Minimal example
Le jeudi 22 novembre 2012 à 13:12 -0800, maths123 a écrit :
I have s data set where 2 of the columns give the coded versions of the
factors A and B. Factor A is coded with 1, 2, 3. Factor B is coded with 1,2.
How do use the factor function to convert these variables into factors, and
also
Le vendredi 23 novembre 2012 à 10:47 +0530, sushobhan just saysI
QUIT a écrit :
Hi All,
I am trying to perform sentiment analysis using R with the
help of the library(sentiment). I am using the function
classify_emotions(sentiment). It is basically selecting a particular word
On 23/11/2012 08:16, Brian Feeny wrote:
Thank you! I searched in the manual, but I did not see where this is
mentioned, I looked under operators
and in some of the formula documentation.
It *is* documented on the help page for formula (and it is not an
operator, so should not be in the
On Thu, Nov 22, 2012 at 5:49 PM, Sam Steingold s...@gnu.org wrote:
* R. Michael Weylandt zvpunry.jrlyn...@tznvy.pbz [2012-11-22 12:11:55
+]:
I now think that what I want is
--8---cut here---start-8---
difftime.summary - function (v) {
s -
On Fri, 23 Nov 2012, Marius Hofert wrote:
Dear expeRts,
I would like to download a time series of historical data from the
ticker with symbol ROG.VX. Interestingly, I obtain constant values
(138.3 for each day in the chosen period) although the yahoo.finance
website tells me that the time
-Original Message-
i have to do something in robust regression by R programm ,
and i have some problems as following:
*the first :*
Afte loading MAS, type 'hubers' (without brackets) and look at the code. That
should give you a clue.
new psi ( psi.a=r/(1+(r/k)^2)) ,k=1.345 and
Readers,
The function 'read.delim' was used to import data into R:
columnnamea columnnameb columnnamec
1 2 3
2 3 4
3 4 5
After import, the column names were:
X.columnnamea columnnameb columnnamec
Why did this occur?
--
r2151
__
Hello, e-letter,
check
?read.delim
and look for the argument check.names and from there you'll should end up
reading
?make.names
Hth -- Gerrit
On Fri, 23 Nov 2012, e-letter wrote:
Readers,
The function 'read.delim' was used to import data into R:
columnnamea columnnameb
On Fri, Nov 23, 2012 at 6:44 AM, wampeh wam...@gmail.com wrote:
How do I get gvarbrowser to display only data.frame named, say atab1 or
atab2 or atab*?
Also, how do I turn off the selection pull down box?
Two remarks. If you hope to get an answer it would be a good idea to
CC John Verzani,
Dear Achim,
Thanks a lot for your quick help. Indeed, I did not realize that the Download
to
Spreadsheet gives the wrong result, so it's really a Yahoo! Finance issue (too
bad, an R issue would have been easier to fix :-) ).
Thanks again,
Marius
Achim Zeileis achim.zeil...@uibk.ac.at writes:
Le vendredi 23 novembre 2012 à 03:17 +0100, vincent guyader a écrit :
Hi everyone,
I made some tests with Rcmdr, to add a function with default parameters :
For example (very simple):
myfunction-function(var=314){
print(hello)
print(var)
}
if I run myfunction() directly i see :
Dear Maya,
sem() computes the fit statistics that I know how to compute for a model fit to
a raw moment matrix. If you know how to compute the others (and if they're
defined), then you could do that youself using the object returned by sem().
I'm not sure why you want the likelihood under the
Hi,
I m working on latex and R and i need to dynamically generate colors.
r-paste(rgb(1.000,,0,,,0,),sep=) # i m generating dynamically by
paste command
cars - c(1, 3, 6, 4, 9)
plot(cars, type=o, col=r) *Error in plot.xy(xy, type,
...) : invalid colour name
I had installed R and MySQL ,then I input :
install.packages('RMySQL',type='source')
show the message below, Why? Why shows ERROR: configuration failed for
package 'RMySQL'?
试开URL’http://mirrors.xmu.edu.cn/CRAN/src/contrib/RMySQL_0.9-3.tar.gz'
Content type 'application/x-gzip' length 165363
Cam anyone tell me why the condition x[i] == DISCONECTED looks like
producing an NA instead of TRUE/FALSE
I would like to rename DISCONNECTED those factors inside the variable
dataset$STATUS.x that are named DISCONECTED
thank you
summary(dataset$STATUS.x)
ACTIVE DISCONECTED PENDING
Thanks,
Do you know how to correct it?
Cheers,
Bruno
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Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org
The data we used for testing is pasted below -
http://r.789695.n4.nabble.com/file/n4650532/testfile.png
Note that our objective is to analyse a dataset with 60 items and about
25,000 candidates but we used the above to test if we get desired result and
the two versions gave different results.
I am working with Maulik on this. We installed a 64-bit version of R 2.15.1
now but the ltm package is under version 2.15.2
The same problem is occurring even with this version.
--
View this message in context:
Hi Edoardo,
there is a difference between comparisons and assignments, both
semantically as well as in R syntax: == vs = or -, latter being
more obvious an assignment.
This is the source of your error.
But to change the labels of a factor object, it is easier to do sth like
Hello,
Try
if (!is.na(x[i]) x[i] == DISCONECTED)
Hope this helps,
Rui Barradas
Em 23-11-2012 09:42, edoardo baldoni escreveu:
Cam anyone tell me why the condition x[i] == DISCONECTED looks like
producing an NA instead of TRUE/FALSE
I would like to rename DISCONNECTED those factors inside
frespider wrote
Hi,
it is possible. but don't you think it will slow the code if you convert
to data.frame?
Thanks
Date: Thu, 22 Nov 2012 18:31:35 -0800
From:
ml-node+s789695n4650500h51@.nabble
To:
frespider@
Subject: RE: Summary statistics for matrix columns
Hello,
Why paste? rgb() is a function, you need its return value, not a
character string.
r - rgb(1.000,0,0)
And the rest plots a graph in red.
Hope this helps,
Rui Barradas
Em 23-11-2012 09:06, Manish Gupta escreveu:
Hi,
I m working on latex and R and i need to dynamically generate
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Rui Barradas
Sent: Friday, November 23, 2012 2:37 PM
To: edoardo baldoni
Cc: R-help@r-project.org
Subject: Re: [R] error in IF condition with factor evaluation
Hello,
On Nov 23, 2012, at 12:04 , TheRealJimShady wrote:
Hi Arun everyone,
Thank you very much for your helpful suggestions. I've been working
through them, but have realised that my data is a little more
complicated than I said and that the solutions you've kindly provided
don't work. The
On Fri, Nov 23, 2012 at 3:29 AM, li1127217ye li112721...@163.com wrote:
I had installed R and MySQL ,then I input :
install.packages('RMySQL',type='source')
show the message below, Why? Why shows ERROR: configuration failed for
package 'RMySQL'?
Hello all,
I al trying to join (ADD FILES in SPSS) two files using the rbind()
function. However, with rbind() R does not behave the same way as SPSS. I
mean, it just concatenates the two blocs with no consideration for same
variables if these are not in the same position in the two files. Anyone
Have you tried 'merge'?
You did not provide any sample data (use 'dput' if you do) so that we
could show a possible solution.
On Fri, Nov 23, 2012 at 9:56 AM, Virgile Capo-Chichi
vcapochi...@gmail.com wrote:
Hello all,
I al trying to join (ADD FILES in SPSS) two files using the rbind()
Hi Jim,
I did not try merge because I thought it only adds variables instead of
cases. Below is what I am trying to do. When I joined data1 and data2, I
was was expecting three variables: r1, r2 and r3 with r2 and r3 presenting
missing values where they did not exist in the first place. V
TheRealJimShady wrote
Hi Peter,
Yes, I did miss an e from the first 'not' in the brackets at the end
of the message, sorry.
Thanks for that code, but when I use it, it creates a new column
called csum which simply contains the values of the variable x . i.e.
it just duplicates the values
You did not specify what you were expecting as output. Here is one
way of using 'merge', but I am not sure if this is what you were
after:
r1-c(1,1,2,3)
r2-c(2,1,2,2)
r3-c(2,1,4,1)
data1-data.frame(r1,r2)
data2-data.frame(r1,r3)
data1
r1 r2
1 1 2
2 1 1
3 2 2
4 3 2
data2
r1 r3
Thank you all
Sent from my iPhone
On 2012-11-23, at 10:19, arun smartpink...@yahoo.com wrote:
HI,
You are right.
It is slower when compared to Pete's solution:
set.seed(125)
x - matrix(sample(1:80),nrow=1000)
colnames(x)- paste(Col,1:ncol(x),sep=)
system.time({
Dear R-users!
I´m faced with following problem:
Given is a sample where the sample size is 12, the sample mean is 30, and
standard deviation is 4.1.
Based on a Student-t distribution i´d like to simulate randomly 500 possible
mean values within a two-tailed 95% confidence interval.
Calculation of
Hello,
I don't believe there's an R function that does what you want, but you
can write one.
myrbind - function(x, y){
cx - colnames(x)
cy - colnames(y)
if(is.null(cx) || is.null(cy)){
result - rbind(x, y)
}else{
ox - order(cx)
oy - order(cy)
Thanks Jim for your help. Your results are not what I wanted. I would like
to see something like the matrix below. This is what I would get if I used
the ADD Files command in SPSS. V
r1 r2 r3
1 2 NA
1 1 NA
2 2 NA
3 2 NA
1 NA 2
1 NA 1
2 NA 4
3 NA 1
2012/11/23 jim holtman
I will try this.
thank you.
2012/11/23 Milan Bouchet-Valat nalimi...@club.fr
Le vendredi 23 novembre 2012 à 03:17 +0100, vincent guyader a écrit :
Hi everyone,
I made some tests with Rcmdr, to add a function with default parameters :
For example (very simple):
Dear list,
Â
Dear list,
I am using read.csv.sql() from the sqldf package to read
individual-based data from a csv file that is too large for R.
My original file contains a column called âIDâ that
identifies the individual. I would like to read in data for only
one individual at a
time, for
On Nov 23, 2012, at 2:21 AM, Paarkhi wrote:
I am working with Maulik on this. We installed a 64-bit version of R
2.15.1
now but the ltm package is under version 2.15.2
The same problem is occurring even with this version.
You and Maulik are posting messages without context and without the
library(reshape)
?rbind.fill
On Fri, Nov 23, 2012 at 10:57 AM, Virgile Capo-Chichi vcapochi...@gmail.com
wrote:
Thanks Jim for your help. Your results are not what I wanted. I would like
to see something like the matrix below. This is what I would get if I used
the ADD Files command in
On Fri, Nov 23, 2012 at 11:12 AM, Juliane Struve
juliane_str...@yahoo.co.uk wrote:
Dear list,
Dear list,
I am using read.csv.sql() from the sqldf package to read
individual-based data from a csv file that is too large for R.
My original file contains a column called “ID” that
identifies the
you need to construct the character string. here's what you want to give
to the sql argument --
paste( 'select * from file where ID = ' , Name )
so try
Name - Bobby
read.csv.sql(filename,sql = paste( 'select * from file where ID = ' ,
Name ) )
On Fri, Nov 23, 2012 at 11:12 AM, Juliane Struve
Hi,
Try this:
r1-c(1,1,2,3)
r2-c(2,1,2,2)
r3-c(2,1,4,1)
data1-data.frame(r1,r2)
data2-data.frame(r1,r3)
data1$r3-NA
data2$r2-NA
merge(data1,data2,all=TRUE,sort=FALSE)
# r1 r2 r3
#1 1 2 NA
#2 1 1 NA
#3 2 2 NA
#4 3 2 NA
#5 1 NA 2
#6 1 NA 1
#7 2 NA 4
#8 3 NA 1
A.K.
-
Hello,
Try forming the sql statement with paste().
Name - Bobby
sqlstatement - paste(select * from file where ID = ', Name, ', sep
= )
read.csv.sql(filename, sql = sqlstatement)
Note the opening and closing quotes around the name.
Hope this helps,
Rui Barradas
Em 23-11-2012 16:12, Juliane
All,
thanks so much for your suggestions. both rbind.fill and creating NA where
necessary worked. I think rbind.fill is much easier and quite elegant. Have
a great weekend, V
2012/11/23 arun smartpink...@yahoo.com
Hi,
Try this:
r1-c(1,1,2,3)
r2-c(2,1,2,2)
r3-c(2,1,4,1)
Arun's solution can be modified slightly to be more general:
r1-c(1,1,2,3)
r2-c(2,1,2,2)
r3-c(2,1,4,1)
r4-c(3,4,1,2)
r5-c(3,1,2,2)
data1-data.frame(r1,r2,r4)
data2-data.frame(r1,r3,r5)
data1[,setdiff(names(data2), names(data1))] - NA
data2[,setdiff(names(data1), names(data2))] - NA
Hello,
So you need a function that can rbind and also return the total unique
columns. It's a bit more complicated but I think this does what you want.
ADD - function(x, y){
cx - colnames(x)
cy - colnames(y)
if(is.null(cx) || is.null(cy)){
d - length(cx) - length(cy)
Dear list,
I am trying to find some place on internet for R cloud computing.I have some
questions about it.
I followed this webpage:
http://www.r-bloggers.com/crdata-org-to-shut-down/
trying to gain some knowledge about where I can find free cloud computing
service for R. It looks like
Look at the updateusr function in the TeachingDemos package. One of the
examples shows adding lines to a barplot.
On Fri, Nov 23, 2012 at 12:33 AM, Ripples 9ripp...@gmail.com wrote:
Hi,
I'm trying to plot stacked barplot with lines on it. Here is the data.
emp days val1 val2 score
1 21
Thomas Schu th.schumann at gmx.de writes:
I´m faced with following problem:
Given is a sample where the sample size is 12, the sample mean is 30, and
standard deviation is 4.1.
Based on a Student-t distribution i´d like to simulate randomly 500 possible
mean values within a two-tailed 95%
Use , instead of ;
It should work now...
Regards,
Bruno
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Sent from the R help mailing list archive at Nabble.com.
Hi Jim,
Thank you for the reply. But, when I use Barpos I get this error.
plot(mydata$score,barpos)
Error in xy.coords(x, y, xlabel, ylabel, log) :
'x' and 'y' lengths differ
I need all the points in x-axis that are in 'days' column. If I'm selecting
only points in val1 and val2 I'm missing
HI,
If that is the case, this should work:
dat1-read.table(text=
id, x, date
1, 5, 2012-06-05 12:01
1, 10, 2012-06-05 12:02
1, 45, 2012-06-05 12:03
2, 5, 2012-06-05 12:01
2, 3, 2012-06-05 12:03
I usually ran different statistical analysis in R with routines that
use lapack like gam() lm(), etc but after several updates of libraries
the following error appears:
library(mgcv)
This is mgcv 1.7-22. For overview type 'help(mgcv-package)'.
model - with(chlaR,gam(ClorMAX ~ s(DegDay_NM)))
HI,
You are right.
It is slower when compared to Pete's solution:
set.seed(125)
x - matrix(sample(1:80),nrow=1000)
colnames(x)- paste(Col,1:ncol(x),sep=)
system.time({
res-sapply(data.frame(x),function(x) c(summary(x),sd=sd(x),IQR=IQR(x)))
res1-as.matrix(res)
res2-res1[c(1:4,7,5,8,6),] })
#
Try this:
library(gWidgets)
options(guiToolkit=RGtk2)
mydefaultclasses - list(Data sets1=c(data.frame) )
w - gwindow()
vb - gvarbrowser(cont=w, knownTypes=mydefaultclasses)
This could be done better, but I think the above does what you want.
--
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Every time i insert : A-lm(GandW ~ Authocracy;Data) i get this Error.
Iam using Mac. And i have checked that Data has been read correctly. The
same command with the same Data has been used by a friend who is using
Linux.
Thanks for help!
Stockholm university
Faradj
--
View this
I often find it would be very useful when inspecting a data structure using
str() to know the column index number in order to rearrange the data in a
manner amenable to my purpose. Is there a way to modify the display options of
the str() function to add column index? I know this is really a
I have some latitude and longitudes that I am trying to plot on an image with
the lines() command like this:
image(seq(-98, -93, 0.1), seq(28.5, 32.5, 0.1), z, xlab= Longitude, ylab=
Latitude, main= Temperature)
for (i in 2:length(subset(geo, Feature==Coast)[,1])) {
If gvarbrowser isn't quite to your liking, it isn't so hard to build your own
variable browser. This uses a slight modification of Petr's function and
wraps in a gWidgets interface. Modify his function to display what info you
want and add a handler to the tbl object to have some action associated
On 16.11.2012 01:19, arun wrote:
Hi,
If you want to convert from the first way to the second way suggested by Jean:
[...]
A.K.
- Original Message -
From: Jean V Adams jvad...@usgs.gov
To: Florian Ahrweiler florian.ahrwei...@uni-wh.de
Cc: r-help@r-project.org
Sent: Thursday,
I normally use the following code to create a figure displaying the mark
correlation function for the point pattern process A:
M-markcorr(A)
plot(M)
I have now started to use the following code to perform 1000 Monte Carlo
simulations of Complete Spatial Randomness (CSR). It is a Monte Carlo
I have this problem.
test - svydesign(id=~1,weights=~peso)
logit - svyglm(bach ~ job2 + mujer + egp4 + programa + delay + mdeo + str
+ evprivate, family=binomial,design=test)
then appear:
Error in svyglm.survey.design(bach ~ job2 + mujer + egp4 + programa + :
all variables must be in
* R. Michael Weylandt zvpunry.jrlyn...@tznvy.pbz [2012-11-23 09:13:36
+]:
2. because difftime.summary returns a data.frame and not a
Classes 'summaryDefault', 'table' as I assume summary must return.
See
On 2012-11-23 08:54, seth.fore wrote:
I often find it would be very useful when inspecting a data structure using
str() to know the column index number in order to rearrange the data in a
manner amenable to my purpose. Is there a way to modify the display options of
the str() function to add
On Nov 23, 2012, at 10:04 AM, Dominic Roye wrote:
Hello,
I want to filter the daily maximum temperature. For this i made this
skript, but it come out wrong results. Can anybody help me?
Thanks for your help!
Best regards
datos$X - as.POSIXct(strptime(datos$X, %d/%m/%Y %H:%M:%S))
z -
On Nov 23, 2012, at 12:08 PM, Pablo Menese wrote:
I have this problem.
test - svydesign(id=~1,weights=~peso)
logit - svyglm(bach ~ job2 + mujer + egp4 + programa + delay + mdeo
+ str
+ evprivate, family=binomial,design=test)
then appear:
Error in svyglm.survey.design(bach ~ job2 + mujer
On 23/11/2012 11:56 AM, wdmc2012 wrote:
I have some latitude and longitudes that I am trying to plot on an image with
the lines() command like this:
image(seq(-98, -93, 0.1), seq(28.5, 32.5, 0.1), z, xlab= Longitude, ylab= Latitude,
main= Temperature)
for (i in 2:length(subset(geo,
On Nov 23, 2012, at 12:40 PM, Peter Ehlers wrote:
On 2012-11-23 08:54, seth.fore wrote:
I often find it would be very useful when inspecting a data
structure using str() to know the column index number in order to
rearrange the data in a manner amenable to my purpose. Is there a
way to
On Nov 23, 2012, at 12:35 PM, Sam Steingold wrote:
* R. Michael Weylandt zvpunry.jrlyn...@tznvy.pbz [2012-11-23
09:13:36 +]:
2. because difftime.summary returns a data.frame and not a
Classes 'summaryDefault', 'table' as I assume summary must return.
See
You could create a simple function using this as a starting point:
str.ext - function(x) {
if(!is.data.frame(x)) stop(No data frame!)
st - gsub( \\$, , capture.output(str(x)))
nm - prettyNum(0:length(x), width=3)
cat(\n, paste(nm, st, \n, sep= ))
}
str.ext(iris)
0
Rui, Anthony, and Gabor,
Â
I got this to work in the end:
Â
for(i in length(Names_EastCoast){
name - Names_EastCoast[i]
sql - paste(select * from file where ID =
',name,',sep = )
Data - read.csv.sql(filename,sql = sql)
}
Â
loops through all individuals in the csv file.
Â
Thanks a lot for all
Hi,
Since you mentioned filtering the daily maximum temperature, this may help:
datos-read.table(text=
X, Ta, HR, RS, v
1/1/2010 1:00:00,5.28,100,0,2.3
1/1/2010 6:00:00,5.45,100,0,2.5
1/1/2010 11:00:00,5.51,100,0,1.1
2/1/2010 1:00:00,5.33,100,0,2.1
2/1/2010 6:00:00,5.48,100,0,2.3
2/1/2010
I am used to packages like e1071 where you have a tune step and then pass your
tunings to train.
It seems with caret, tuning and training are both handled by train.
I am using train and trainControl to find my hyper parameters like so:
MyTrainControl=trainControl(
method = cv,
number=5,
Brian,
This is all outlined in the package documentation. The final model is fit
automatically. For example, using 'verboseIter' provides details. From
?train
knnFit1 - train(TrainData, TrainClasses,
+ method = knn,
+ preProcess = c(center, scale),
+
On 11/24/2012 02:21 AM, skanap wrote:
Hi Jim,
Thank you for the reply. But, when I use Barpos I get this error.
plot(mydata$score,barpos)
Error in xy.coords(x, y, xlabel, ylabel, log) :
'x' and 'y' lengths differ
I need all the points in x-axis that are in 'days' column. If I'm selecting
Max,
Thanks, I do understand that the final model is fitted. I think I was not
clear in my posting. I am changing datasets between tuning and real training.
So maybe I tune on trainset but its only 5000 rows, doing my gridsearch and
all that, and then once I have the hyper parameters, I
The code
hist(new, main=bquote(Heart Attack ( * bar(X)==.(round(mean(new),1)) *
)))
does not work on 2.15.2 on OSX. the histogram is generated, but the title
does show at all, which kind of tells me the bquote expression is failing
I would appreciate any help in making this work, it seems it
Until a weeks ago I used stata for everything.
Now I'm learning R and trying to move. But, in this stage I'm testing R
trying to do the same things than I used to do in stata whit the same
outputs.
I have a problem with the logit, applying weights.
in stata I have this output
. svy: logit bach
Hi,
No problem.
There are a couple of other libraries which deal with summary statistics:
library(pastecs)
?stat.desc() #
library(matrixStats)
#Using the functions from package: matrixStats
fun1-function(x){
Hi,
I am new to R. I am trying to regroup data frame using multiple constrains.
for example
data frame: data
value class percent
15526 36 4.6875
15527 62 85.9375
15527 82 32.4564
15528 36 70.3125
15528 62 9.375
15528 82 74.6875
I need to regroup
General question concerning summary results of a linear model. I've tried to
look in help and search online but I either don't understand it or I can't
find the answer.
I've defined a model with a really large number of variables and levels. The
summary results are so big that not all of the
On Nov 23, 2012, at 12:20 PM, mee1d3hs wrote:
The code
hist(new, main=bquote(Heart Attack ( * bar(X)==.(round(mean(new),
1)) *
)))
does not work on 2.15.2 on OSX. the histogram is generated, but the
title
does show at all, which kind of tells me the bquote expression is
failing
Works
On 24/11/12 06:36, AMFTom wrote:
I normally use the following code to create a figure displaying the mark
correlation function for the point pattern process A:
M-markcorr(A)
plot(M)
I have now started to use the following code to perform 1000 Monte Carlo
simulations of Complete Spatial
On Nov 23, 2012, at 1:14 PM, prasmas wrote:
Hi,
I am new to R. I am trying to regroup data frame using multiple
constrains.
for example
data frame: data
value class percent
15526 36 4.6875
15527 62 85.9375
15527 82 32.4564
15528 36 70.3125
15528 62
Hello,
Like the following?
dat - read.table(text=
value class percent
15526 36 4.6875
15527 62 85.9375
15527 82 32.4564
15528 36 70.3125
15528 62 9.375
15528 82 74.6875
, header = TRUE)
per70 - dat$percent 70
split(dat, list(dat$class, per70))
Hope this helps,
Rui Barradas
Em 23-11-2012
from your stata output, it looks like you need to use the survey package in
R
for step-by-step instructions about how to do this (and comparisons to
stata), see
http://journal.r-project.org/archive/2009-2/RJournal_2009-2_Damico.pdf
once you're ready to run the regression, use svyglm() instead
On 11/23/2012 08:05 AM, arysar wrote:
I usually ran different statistical analysis in R with routines that
use lapack like gam() lm(), etc but after several updates of libraries
the following error appears:
library(mgcv)
This is mgcv 1.7-22. For overview type 'help(mgcv-package)'.
model -
Hello,
I have two very basic questions (console attached):
1) What am I getting an error message for # 5 and # 7 ?
2) How to fix the code?
I would appreciate receiving your help.
Thanks,
Pradip Muhuri
## Reproducible Example #
N - 100
set.seed(13)
Hi Pradip,
It is easier to use subset(). Check ?subset for some examples and pay
special attention to the select parameter. By the way, do not call your data
df as it is already a function.
Best,
Jorge.-
On Sat, Nov 24, 2012 at 1:55 PM, Muhuri, Pradip (SAMHSA/CBHSQ) wrote:
Hello,
I
Hi Arun,
Thank you so much for your help.
Pradip
From: arun [smartpink...@yahoo.com]
Sent: Friday, November 23, 2012 10:15 PM
To: Muhuri, Pradip (SAMHSA/CBHSQ)
Cc: R help
Subject: Re: [R] subsetting - questions
HI,
This should work:
On 2012-11-23 18:55, Muhuri, Pradip (SAMHSA/CBHSQ) wrote:
Hello,
I have two very basic questions (console attached):
1) What am I getting an error message for # 5 and # 7 ?
2) How to fix the code?
I would appreciate receiving your help.
Thanks,
Pradip Muhuri
## Reproducible Example
I am trying to make it so two columns with similar data use the same internal
numbers for same factors, here is the example:
read.csv(test.csv,header =FALSE,sep=,)
V1V2 V3
1 sun moonstars
2 stars moon sun
3 cat dog catdog
4 dog moon sun
5 bird plane
Hi Jorge,
I could use subset(). But, I wanted to minimize coding.
Thanks,
Pradip
From: Jorge I Velez [jorgeivanve...@gmail.com]
Sent: Friday, November 23, 2012 10:02 PM
To: Muhuri, Pradip (SAMHSA/CBHSQ)
Cc: r-help@r-project.org
Subject: Re: [R]
Hello Peter,
1. -c(X3, X4, X5)
For the above variables, class is integer.
Arun has suggested the following:
df[df$X1=8,][-which(names(df)%in% c(X3,X4,X5))]
2.df[df$X1=8,] [, !names(df) %in% drop_var]
I agree - Arun has also suggested the same.
Thanks and regards,
Pradip
On Nov 23, 2012, at 6:32 PM, arun wrote:
Hi David,
Tried the solution on a slightly different data:
dat - read.table(text=
value class percent
15526 36 4.6875
15527 62 85.9375
15527 82 32.4564
15528 36 70.3125
15528 62 9.375
15528 82 74.6875
15529 72 50.
15530 72 50.
, header = TRUE)
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