Hi, Derek,
Try and modify the value for the overlap argument.
Hope this helps,
José
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of derek@nemac
Sent: 07 February 2013 03:49
To: r-help@r-project.org
Subject: [R] coplot question
Dear Janesh Devkota,
Re:
Hello R users,
I am trying to use R to do the low pass filter analysis for the tidal data.
I am a novice in R and so far been doing only simple stuffs on R. I found a
package called signal but couldn't find the proper tutorial for the low
pass filter.
Could
Hi Torrey
Yes - it turned out that it wasn't a problem with the .csv file it was a
problem with SPACECAP. I was trying to use too small a pixel size for
the home range centres. The smallest pixel size that SPACECAP can handle
is 0.25 sq km.
Hope this helps
Vivien
On 07/02/2013 05:14,
Dear useRs,
This post relates to a similar problem (
https://stat.ethz.ch/pipermail/r-help/2010-August/250719.html)
I am using R.matlab (R.matlab v1.6.3 (2013-01-17) to iterate matrix
multiplication in matlab 2012Rb. Everything works fine except for some
random iteration of my model the command
easiest workaround, save the .xlsx to a .xls
--
View this message in context:
http://r.789695.n4.nabble.com/Problem-with-xlsx-package-tp3298470p4657787.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing
Hi Elaine
you can do all at one go using the ggplot2-package
library(ggplot2)
qplot(age,weight)+ geom_smooth(method=lm,formula=y~poly(x,2))
Have a look at ?geom_smooth when you want to incooperate customized
model predictions
cheers.
Am 07.02.2013 02:31, schrieb Elaine Kuo:
Hello,
I drew a
Hello,
You should follow the posting guide and provide us with a data and code
example.
# Make up some data
x - seq(0, 1, length.out = 20)
y - x^2 + rnorm(20)
# fit a quadratic
model - lm(y ~ I(x^2))
fitted - predict(model, interval = confidence)
# plot the data and the fitted line
plot(x,
Dear Janesh Devkota,
Sorry, I forgot an edit.
The last command should read:
yfiltered = signal:::filter(myfilter, y) # apply filter
Best wishes,
Franklin Bretschneider
--
Dept Biologie
Kruytgebouw W711
Padualaan 8
3584 CH Utrecht
The Netherlands
Johannes Graumann wrote:
Grrr ... new trial with code here: http://pastebin.com/RjHNNG9J
Maybe the amount of inline-code prevented posting?
Hello,
I am writing a simple peak detector and it works quite well ... however
there's one special case below, that I can't get my head wrapped
car::spreadLevelPlot is designed for just this purpose.
Something similar is one of the plots produced by plot(lm(...))
HTH
On 2/6/2013 9:42 AM, N. Janz wrote:
To detect heteroscedasticity for a multiple linear OLS regression (no
time dependencies):
What if the residuals vs. fitted values
Hello there!
Remmy is my name and I came across an interesting code in R on this web
https://stat.ethz.ch/pipermail/r-help/2004-May/050424.html , there are some
parts that I have not followed and I would like to get some comments if you may!
Please comment on the highlighted two parts of the
I know that the basic approach to append or merge data frames is using the
rbind and merge commands.
However, if I understand things correctly, for both commands one needs to do
quite some additional programming to get e.g. behavior as with the Stata append
and morge commands or to achieve some
Hello,
Try the following.
maintainer(spatstat)
[1] Adrian Baddeley adrian.badde...@csiro.au
Hope this helps,
Rui Barradas
Em 07-02-2013 02:05, Hiroshi Saito escreveu:
Dear sir,
Which mailing list is appropriate to ask for kstest in spatstat?
Regards,
Hiroshi Saito
Hi,
I need assitance with performing a Bayesian Ordered Logistic Regression in R.
Would you be able to assist?
Aruna
Sent from my BlackBerry® wireless device available from bmobile.
__
R-help@r-project.org mailing list
Janesh,
This might help get you started:
http://biostatmatt.com/archives/78
(apologies for linking to my own blog)
Regards,
Matt
--
Message: 51
Date: Wed, 6 Feb 2013 18:50:43 -0600
From: Janesh Devkota janesh.devk...@gmail.com
To: r-help@r-project.org
Subject:
Hello,
I am writing cause I have a problem when try to create confidence envelopes
in spatstat.
I have a point data representing firms in my study area.
When I try to create confidence envelopes the error message turns up:
[ p - envelope(point, fun=Kest, nsim=99)
Error in marks.ppp(Y, dfok =
If
another user does not want to get the full taxonomic
description of that particular fly, he/she is welcome to
ignore it along with all the other taxa he/she is not referencing.
All true, but the OP was asking about modifying a file that is part of an
installed. package.
That is surely
After applying the NLS for a model like y=exp(a*x), and I get
a result showing the summary as:
Estimate Std. Error t value Pr(|t|)
2.6720 1.4758 1.811 0.3212
My question is what this t-statistics tests? And what's the
meaning of Pr?
t is (estimate/std.err) and can be used to
Hello, John,
as a start take a look at
?merge
And to (maybe) get a bit overwhelmed at first sight use
RSiteSearch( merge)
Hth -- Gerrit
On Thu, 7 Feb 2013, John Smith wrote:
I know that the basic approach to append or merge data frames is using the
rbind and merge commands.
However,
Thanks.
-Roy M.
On Feb 6, 2013, at 11:55 PM, Prof Brian Ripley rip...@stats.ox.ac.uk wrote:
On 06/02/2013 22:47, Roy Mendelssohn - NOAA Federal wrote:
Hi All:
We are developing (actually updating) a piece of code that runs in
R.
Due to some limitations of some the libraries we use, at the
q()?
E.g.,
f - function(x) { switch(sign(x)+2, q(), stop(Oops), NULL) ; sqrt(x) }
tryCatch(f(2), error=function(e)error)
[1] 1.414214
tryCatch(f(0), error=function(e)error)
[1] error
tryCatch(f(-2), error=function(e)error)
Save workspace image? [y/n/c]: c
for(i in
Hi,
Is anyone aware if there is a package that allows one to connect to Oracle
Business Intelligence (aka OBIEE)?
I want to be able to pull in a summary table contained in an answer (aka
OBIEE query).
Dan
Lawrence Livermore National Lab
WF Analyst
[[alternative HTML version
Thanks, Ellison. Another question is if this p-value is a good parameter to
test if the fitting is good, as you this test is only for the null that the
coefficient is 0 (a is 0 in y=exp(a*x), right?)?
On Thu, Feb 7, 2013 at 10:48 AM, S Ellison s.elli...@lgcgroup.com wrote:
After applying
Hi Rolf,
sorry for this late answer and thanks for your kind explanation and
relative R code. I really appreciate.
In reality the concept that I'm trying to address is a bit more complex.
I'm fitting a model y vs 6 predictors with MARS / RandomForest /
Multiple Linear Regression Models having 140
Greetings,
I am having an interesting problem and I wonder if anyone else has
seen this behavior.
I am running R 2.11.1 with SNOW 0.3-3 on a Dell cluster running CentOS 5.5.
I create my cluster using:
cluster- makeCluster(nodes,type=SOCK,port=10191) # nodes is a
vector of compute nodes
I
Hi Gerrit,
as I said in my original email, I already know both the
merge and the rbind commands, but I think that many
standard situations (I have given just a few) require
rather clumsy ad-hoc programming. So I was wondering
if there are any packages or existing code that would
make it easier to
Hi,
I didn't fully understand the logic.
You could get the result by:
list1-lapply(mapply(cbind,lapply(1:2,function(i)
E[,,i]),lapply(c(1,3),function(i) C[,i,]),SIMPLIFY=FALSE),function(x)
x[,c(TRUE,apply(matrix(!x[,-1]%in% x[,1],nrow=5),2,all))])
I'm new to R and have not been able to find what I am looking for online. I
found the system command but that seems to be used for getting lists of
directories, etc.
I am trying to replicate something that I used to do in SAS. I am simulating
some data (which I can do in R with a particular
Hi there,
I've got a set of 10 numeric variables called Mood1 to Mood10 in a dataset
called mood. I'm trying to create a set of 10 new variables called m1 to m10
so that m1=Mood1*1, m2=Mood2*2, etc to m10=Mood10*10
Trawling through the internet, I eventually tried the following code:
for (i
Dear R-list,
We stumbled upon some weird problem when performing a simple indexing operation.
Below some example code to illustrate the issue
#FAILS TO FIND .55 Oo
huh1 = seq(.1,.7,.15);huh1
# [1] 0.10 0.25 0.40 0.55 0.70
huh1 == .25
# [1] FALSE TRUE FALSE FALSE FALSE
huh1 == .55
# [1] FALSE
Hi José
Yes indeed that does help.
Thanks,
Derek
On 2/7/2013 5:01 AM, Jose Iparraguirre wrote:
Hi, Derek,
Try and modify the value for the overlap argument.
Hope this helps,
José
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
R-FAQ 7.31
Berend
On 07-02-2013, at 17:41, J. Braeken j.brae...@uvt.nl wrote:
Dear R-list,
We stumbled upon some weird problem when performing a simple indexing
operation.
Below some example code to illustrate the issue
#FAILS TO FIND .55 Oo
huh1 = seq(.1,.7,.15);huh1
# [1] 0.10
On Feb 7, 2013, at 9:12 AM, John Smith wrote:
Hi Gerrit,
as I said in my original email, I already know both the
merge and the rbind commands, but I think that many
standard situations (I have given just a few) require
rather clumsy ad-hoc programming. So I was wondering
if there are any
On Thu, Feb 7, 2013 at 4:16 PM, christel lacaze
christellac...@hotmail.co.uk wrote:
Hi there,
I've got a set of 10 numeric variables called Mood1 to Mood10 in a dataset
called mood.
That's where you went wrong in the first place. Don't use variable
names for indexing purposes.
You should
Hi Leigh,
On Thu, Feb 7, 2013 at 10:35 AM, Leigh Michelle Williams
lwilliams...@gsu.edu wrote:
I'm new to R and have not been able to find what I am looking for online. I
found the system command but that seems to be used for getting lists of
directories, etc.
The etc. includes many things
I think this is because some decimal numbers with a fixed
number of digits after the decimal point cannot be represented
as base-2 floating point numbers with a limited number of
digits. So when one adds them up, the result is slightly
different from the sum:
huh1 = seq(.1,.7,.15)
huh1 - 0.55
Leigh Michelle Williams lwilliams146 at gsu.edu writes:
I'm new to R and have not been able to find what I am looking for online.
I found the system command but that
seems to be used for getting lists of directories, etc.
I am trying to replicate something that I used to do in SAS. I am
I gave a small number of examples in my first email.
For append, in Stata any variable that is missing in the
other dataset is automatically inserted with all values set
to the missing value. In R, one would first have to compare
the columns in both data frames and generate columns
apropriately.
Liang:
In nonlinear models especially (and more generally, also), small p
values are not reliable indicators of whether a fit is or is
notgood. I would strongly suggest that you consult with your local
statistician -- this is a (complicated, as it depends on the meaning
of good) statistical
Dear Listers,
I try to change the structure of my data. i have an indicator-matrix and
want to end up with a factor.
i have
v1 v2 v3
1 0 0
0 1 0
0 0 1
and want
v1 v2 v3 v4
1 0 0 1
0 1 0 2
0 0 1 3
amongst other things i tried the following
d -
Dear Franklin Bretschneider,
Thank you so much for your reply and explanation about the filter using the
stats and signal package.
I decided to opt the filter method in signal package. I have a simple
question about the cut off frequency here.
I have 30 minute collected tidal data and I want to
For merge, when merging dataset A with dataset B on some
set of key variables, it is possible to specify if the
join should be done 1:1, 1:n, n:1 or n:m. Stata creates
a data structure that contains information about which
observations could or could not be matched and which
matches did not
#I have 2 dataframes df1 df2. Each has a subset of all possible column
names. #How do I combine the 2 tables so that they contain all column
names? data1 - c('2','3', '6', '8' , '9') data2 - c('1', '2',
'3', '6') df1
- data.frame(matrix(data=NA, nrow=1, ncol=length(data1),
On 06/02/2013 8:33 PM, ivo welch wrote:
is it possible to throw a stop() that is so hard that it will escape
even tryCatch?
You can signal a condition that is not an error, and if tryCatch hasn't
been written to catch it, it will stop. For example,
g - function() {
tryCatch(f(),
try this:
x - read.table(text = v1 v2 v3
+ 1 0 0
+ 0 1 0
+ 0 0 1, header = TRUE)
x$v4 - apply(x, 1, function(a) which(a == 1))
x
v1 v2 v3 v4
1 1 0 0 1
2 0 1 0 2
3 0 0 1 3
On Thu, Feb 7, 2013 at 1:20 PM, Winfried Moser winfried.mo...@gmail.com wrote:
Dear
On 07/02/2013 1:20 PM, Winfried Moser wrote:
Dear Listers,
I try to change the structure of my data. i have an indicator-matrix and
want to end up with a factor.
i have
v1 v2 v3
1 0 0
0 1 0
0 0 1
and want
v1 v2 v3 v4
1 0 0 1
0 1 0 2
0 0 1 3
amongst other
#I have 2 dataframes df1 df2. Each has a subset of all possible column names.
#How do I combine the 2 tables so that they contain all column names?
data1 - c('2','3', '6', '8' , '9')
data2 - c('1', '2', '3', '6')
df1 - data.frame(matrix(data=NA, nrow=1, ncol=length(data1),
dimnames=list(NULL,
On Feb 7, 2013, at 10:47 AM, Lopez, Dan lopez...@llnl.gov wrote:
Hi,
Is anyone aware if there is a package that allows one to connect to Oracle
Business Intelligence (aka OBIEE)?
I want to be able to pull in a summary table contained in an answer (aka
OBIEE query).
Dan
Lawrence
I know that within sum of squares, DB, sillhouette and cophenetic are
indicators of clustering quality, but what indicators I need to observe when
I choose attributes for kmeans?
--
View this message in context:
http://r.789695.n4.nabble.com/Feature-selection-for-kmeans-tp4657830.html
Sent
Hi,
You could get the result:
dat1 - read.table(text =
v1 v2 v3
1 0 0
0 1 0
0 0 1
,sep=,header=TRUE)
dat1$v4-apply(mapply(`==`,dat1,1),2,which)
dat1
# v1 v2 v3 v4
#1 1 0 0 1
#2 0 1 0 2
#3 0 0 1 3
A.K.
- Original Message -
From: Winfried Moser
Hi list,
Is there a easy way to compare objects in two different workspace files (i.e.
.RData files) in R? I can use some generic file compare softwares (e.g.
BeyondCompare) to binary comparison, but when it says they're different you
can't tell where the difference are from.
Thanks!
Tao
I looked at the documentation of source() and summary(), and I could not
find the reason why calling something like:
summary(resamps)
from the command line, works (it prints the summary)
whereas calling
summary(resampls)
from a file that I source with source(my_file.r) does not print
I have an environment variable `$R_HISTFILE` pointing to
`/home/my.username/.RHistory` and the following code in my `.Rprofile` in
my home directory:
.Last - function() {
if (!any(commandArgs()=='--no-readline') interactive()){
require(utils)
One rather extremem limitation in Stata is that there is
always only just one active or loaded dataset.
So all the commands that involve more than one dataset
operate on the loaded master dataset and one or more
other datasets that are stored somewhere.
Merge in Stata joins the loaded master
From ?source
Note that running code via source differs in a few respects from entering it
at the R command line. Since expressions are not executed at the top level,
auto-printing is not done. So you will need to include explicit print calls for
things you want to be printed
John Kane
Kingston
Hi,
I am comparing SAS commands with R.
consider i want to assess the effect of one exposure(like CAT where 1
equals high and 0 equals low) and one cofounding variable (like
cholesterol leve,CHL) on a diseasee variable (like CHD).
In SAS to get a numerical value for the odds ratio, consider, for
Hi,
You could use ?merge() or ?join() from library(plyr)
merge(df1,df2,all=TRUE)
# col2 col3 col6 col8 col9 col1
#1 2 3 6 NA NA 1
#2 NA NA NA NA NA NA
A.K.
- Original Message -
From: Anika Masters anika.mast...@gmail.com
To: r-help@r-project.org
Cc:
Sent:
Hello,
The following function will give what you seem to want.
fun - function(x, y){
df3 - x
df3 - cbind(df3, df2[setdiff(names(y), names(x))])
df3[order(names(df3))]
}
fun(df1, df3)
Hope this helps,
Rui Barradas
Em 07-02-2013 18:36, Anika Masters escreveu:
#I
On Feb 7, 2013, at 10:58 AM, Aminreza Aamini wrote:
Hi,
I am comparing SAS commands with R.
consider i want to assess the effect of one exposure(like CAT where 1
equals high and 0 equals low) and one cofounding variable (like
cholesterol leve,CHL) on a diseasee variable (like CHD).
In SAS
thank's, that worked!
2013/2/7 jim holtman jholt...@gmail.com
try this:
x - read.table(text = v1 v2 v3
+ 1 0 0
+ 0 1 0
+ 0 0 1, header = TRUE)
x$v4 - apply(x, 1, function(a) which(a == 1))
x
v1 v2 v3 v4
1 1 0 0 1
2 0 1 0 2
3 0 0 1 3
On Thu, Feb
thanks, that worked!
2013/2/7 arun smartpink...@yahoo.com
Hi,
You could get the result:
dat1 - read.table(text =
v1 v2 v3
1 0 0
0 1 0
0 0 1
,sep=,header=TRUE)
dat1$v4-apply(mapply(`==`,dat1,1),2,which)
dat1
# v1 v2 v3 v4
#1 1 0 0 1
#2 0 1 0 2
#3 0 0 1
On Feb 7, 2013, at 10:20 AM, Winfried Moser wrote:
Dear Listers,
I try to change the structure of my data. i have an indicator-matrix and
want to end up with a factor.
i have
v1 v2 v3
1 0 0
0 1 0
0 0 1
and want
v1 v2 v3 v4
1 0 0 1
0 1 0 2
0 0 1
Hello,
Sorry, there's a bug in my first reply. Corrected:
fun - function(x, y){
df3 - cbind(x, y[setdiff(names(y), names(x))])
df3[order(names(df3))]
}
fun(df1, df2)
Rui Barradas
Em 07-02-2013 19:16, Rui Barradas escreveu:
Hello,
The following function will give what you
thanks! I didn't know, that x$y isn't a variable, but an expression!
with the suggested notation d[[x]] i get a matrix and have to extract the
diagonale.
d - data.frame(d1=c(1,0,0), d2=c(0,1,0), d3=c(0,0,1))
d$nr - NA
sapply(1:3, function(x) ifelse(d[[x]]==**1,x,d$nr))
[,1] [,2] [,3]
[1,]1
You can leave your script as it was and use source()'s
print.eval=TRUE or echo=TRUE arguments to get the
autoprinting done as it is at the command line
(echo=TRUE also prints the commands).
E.g., for the file /tmp/x.R containing the 2 lines
d - mtcars[,c(am,gear,hp,mpg)]
summary(lm(data=d,
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of John Kane
Sent: Thursday, February 07, 2013 10:57 AM
To: James Jong; r-help@r-project.org
Subject: Re: [R] Sourcing my file does not print command outputs
From ?source
Note
Everyone:
In the last few months I've noticed an increasing number of questions to
this list from students who are new to the use of R and who have limited (in
any) local support on R and specifically support for R syntax.
My text
Hi David,
The following is an interesting observation ...
On Friday, February 8, 2013, David Winsemius wrote:
On Feb 7, 2013, at 10:20 AM, Winfried Moser wrote:
Notice that the '[[' function is superior in every way to the '$' function.
I'm curious to know whether you can point to
?unique
Please learn to search for yourself, e.g. via:
??unique
or the tons of other ways.
-- Bert
On Thu, Feb 7, 2013 at 12:50 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Hello!
I have a data frame with several rows, for example:
x=as.data.frame(matrix(c(1,2,3,
You can solve this problem by actually *reading* the error
message. Evidently the object point is a marked point pattern
whose marks are in the form of a data frame.
So either:
(1) Do not create point as a marked point pattern --- i.e.
don't add a marks component when you create it,
On Thu, Feb 7, 2013 at 2:07 PM, Ken Weiss kgwe...@umich.edu wrote:
Greetings,
I am having an interesting problem and I wonder if anyone else has
seen this behavior.
I am running R 2.11.1 with SNOW 0.3-3 on a Dell cluster running CentOS 5.5.
Simplest suggestion -- can you update to current
On Thu, Feb 7, 2013 at 5:53 PM, Shi, Tao shida...@yahoo.com wrote:
Hi list,
Is there a easy way to compare objects in two different workspace files (i.e.
.RData files) in R? I can use some generic file compare softwares (e.g.
BeyondCompare) to binary comparison, but when it says they're
... but you need to load them into different environments in case they
have objects with the same name, right?
-- Bert
On Thu, Feb 7, 2013 at 1:25 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
On Thu, Feb 7, 2013 at 5:53 PM, Shi, Tao shida...@yahoo.com wrote:
Hi list,
Is there a
Thanks. Interestingly I am having the same problem with
dotplot(resamps, metric = Accuracy)
Nothing shows up if I source the file. But I can visualize it I call this
command from the command line... Any thoughts?
Thanks again,
James
On Thu, Feb 7, 2013 at 3:09 PM, Nordlund, Dan (DSHS/RDA)
Say I train a model in caret, e.g.:
RFmodel - train(X,Y,method='rf',trControl=myCtrl,tuneLength=1)
How can I save this to disk and load it later in R?
How about an object of the class resamples?
resamps - resamples(
list( RF = RFmodel,
SVM = SVMmodel,
I donât know where resamps comes from and I donât know what parameters you
provided to source(), so you havenât provided a reproducible example. But,
did you call source with print.eval=TRUE ?
Dan
Daniel J. Nordlund
Washington State Department of Social and Health Services
Planning,
Have you looked at ?save and ?load?
As I already wrote here:
http://stackoverflow.com/questions/14761496/saving-and-loading-a-model-in-r
Best,
Stephan
On 07.02.2013 22:33, James Jong wrote:
Say I train a model in caret, e.g.:
RFmodel - train(X,Y,method='rf',trControl=myCtrl,tuneLength=1)
Thanks Dan,
Here is a minimal full example, where dotplot fails to print anything if I
source the file. I have tried restarting R and directly sourcing this file
without doing anything else first (my .Rprofile is empty). This is running
on Linux with the latest stable version of R.
Thanks Stephan. I can't believe I didn't try that first. I greatly
appreciate it.
James
On Thu, Feb 7, 2013 at 4:45 PM, Stephan Kolassa stephan.kola...@gmx.dewrote:
Have you looked at ?save and ?load?
As I already wrote here: http://stackoverflow.com/**
Notice that the '[[' function is superior in every way to the '$' function.
I'm curious to know whether you can point to some consolidated comparison?
Two problems are that List$name allows abbreviations of name and does not allow
variable names.
With List$name you get:
List -
On Feb 7, 2013, at 9:51 PM, James Jong ribonucle...@gmail.com wrote:
Thanks Stephan. I can't believe I didn't try that first. I greatly
appreciate it.
James
On Thu, Feb 7, 2013 at 4:45 PM, Stephan Kolassa stephan.kola...@gmx.dewrote:
Have you looked at ?save and ?load?
I generally
What are the *RDS counterparts? What is the difference?
James
On Thu, Feb 7, 2013 at 5:00 PM, Michael Weylandt michael.weyla...@gmail.com
wrote:
On Feb 7, 2013, at 9:51 PM, James Jong ribonucle...@gmail.com wrote:
Thanks Stephan. I can't believe I didn't try that first. I greatly
Ummm...
Have you actually read ?load to see how do this using the
environment argument?
-- Bert
On Thu, Feb 7, 2013 at 1:58 PM, Shi, Tao shida...@yahoo.com wrote:
In fact, they have objects with exact same names. They were created by the
same code at different time points. The code is not
Forgot to send to R-help
From: Nordlund, Dan (DSHS/RDA)
Sent: Thursday, February 07, 2013 2:09 PM
To: 'James Jong'
Subject: RE: [R] Sourcing my file does not print command outputs
James,
Your code seems to have ââ¦â sitting on a line all by itself (maybe should
be at the end of the
Thanks Dan. The ... is an accidental typo in the email. Would you mind
verifying that dotplot opens a plot *without* print.eval=TRUE?
Thanks,
J.
On Thu, Feb 7, 2013 at 5:08 PM, Nordlund, Dan (DSHS/RDA)
nord...@dshs.wa.gov wrote:
James,
** **
Your code seems to have
sitting on
No, it does not. If you donât use print.eval=TRUE, you would need to wrap
the dotplot() call in a print() inside your script file, i.e.
print(dotplot(resamps, metric = Accuracy))
Dan
Daniel J. Nordlund
Washington State Department of Social and Health Services
Planning, Performance, and
P. S. I just noticed that you referred to the envelopes produced as
confidence envelopes.
They are ***NOT*** confidence envelopes!!! They are critical envelopes.
This is a very different concept. Repeat after me, 50 times:
critical envelopes, critical envelopes, critical envelopes,
There are 4 ways, other than generating a core dump :-), that could
fit your vague desctiption:
Call q(no); this is the only way to avoid 'finally' expressions
in tryCatch if that is really what you want.
You can invoke an abort restart; there will be one established
by the
Thanks, Bill.
Andrew
On Thu, Feb 07, 2013 at 09:21:53PM +, William Dunlap wrote:
Notice that the '[[' function is superior in every way to the '$'
function.
I'm curious to know whether you can point to some consolidated comparison?
Two problems are that List$name allows
Dear list members
I have a doubt on how p-values for t-statistics are calculated in the
summary of Linear Models.
Here goes an example:
x - rnorm(100,50,10)
y - rnorm(100,0,5)
fit1-lm(y~x)
summary(fit1)
summary(fit1)$coef[2] # b
summary(fit1)$coef[4] # Std. Error
summary(fit1)$coef[6] #
Thanks, Ellison. Another question is if this p-value is a good parameter to
test if the fitting is good,
Absolutely not.
***
This email and any attachments are confidential. Any use, copying or
disclosure other than by the
On 02/07/2013 08:22 PM, Antonio Silva wrote:
Dear list members
I have a doubt on how p-values for t-statistics are calculated in the
summary of Linear Models.
Here goes an example:
x - rnorm(100,50,10)
y - rnorm(100,0,5)
fit1-lm(y~x)
summary(fit1)
summary(fit1)$coef[2] # b
OK, I found the answer:
2*pt(t,summary(fit1)$df[2])
Thanks anyway ...
2013/2/7 Antonio Silva aolinto@gmail.com
Dear list members
I have a doubt on how p-values for t-statistics are calculated in the
summary of Linear Models.
Here goes an example:
x - rnorm(100,50,10)
y -
On 8 Feb 2013, at 01:24, Antonio Silva aolinto@gmail.com wrote:
# Two-sided p-value should be estimated with
dt(t,summary(fit1)$df[2]) # isn't it?
No, on two counts.
First, dt is the density; you need pt, the cumulative probability, not dt.
Second, pt(t, ...) would calculate the one
I'm trying to produce a series of powers of a number as follows:
| 0.05^0:5
[1] 1 2 3 4 5
This is not the result I expected. I guess some kind of coercion happened,
since,
| class(0.05^0:5)
[1] integer
Could anyone explain me what is happening here?
Thanks,
-Sergio.
Julio Sergio juliosergio at gmail.com writes:
I'm trying to produce a series of powers of a number as follows:
| 0.05^0:5
I'm sorry for the question. The answer is simple: the result is due to
operator precedence not to coercing:
| 0.05^(0:5)
[1] 1.000e+00 5.000e-02 2.500e-03
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Julio Sergio
Sent: Thursday, February 07, 2013 6:13 PM
To: r-h...@stat.math.ethz.ch
Subject: [R] Coercing of types when raising a number to a series of
powers
I'm trying to
On Feb 7, 2013, at 6:21 PM, Julio Sergio wrote:
Julio Sergio juliosergio at gmail.com writes:
I'm trying to produce a series of powers of a number as follows:
| 0.05^0:5
I'm sorry for the question. The answer is simple: the result is due to
operator precedence not to coercing:
In fact, they have objects with exact same names. They were created by the
same code at different time points. The code is not version-controlled, so I
only have the most recent version, but I want to know what's changed.
Tao
- Original Message -
From: Bert Gunter
I am trying to calculate adjusted means according to a glm model with a
Poisson distribution using effect() in the 'effects' package. I've done
this many times before with great success, but this time I'm getting an
error. My model contains two factors and two covariates/blocks and I would
like
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