On 22/05/2013 21:06, Rich Shepard wrote:
On Wed, 22 May 2013, rwillims wrote:
I have been using the NADA package to do some statistical analysis,
however I have just found that the package is no longer available for
install. I've downloaded an older version ( NADA_1.5-4.tar.gz ) and
tried
to
Hi,
From time to time I need to do the aggregation. To illustrate, I present
a toy example as below. In this example, the task is to aggregate x and y
by z with the function mean.
Could I call the aggregation function with x_test, where
x_test=c(x,y)? Thanks
Miao
Merge should do the trick. How to best use it will depend on what you
want to do with the data after.
The following is an example of what you could do. This will perform
best, if the rows are missing at random and do not cluster.
DF1 - data.frame(X.DATE=rep(01052007, 7), X.TIME=c(2:5,7:9)*100,
with(dftest,aggregate(cbind(x,y),list(z),FUN=mean))
# Group.1 x y
#1 0 7 1
#2 1 6 2
#or
library(plyr)
ddply(dftest,.(z),numcolwise(mean))
# z x y
#1 0 7 1
#2 1 6 2
A.K.
- Original Message -
From: jpm miao miao...@gmail.com
To: r-help r-help@r-project.org
Cc:
Sent:
If you want to use the character string:
attach(dftest)
aggregate(cbind(sapply(x_test, get))~z, data=dftest, FUN=mean)
# or
with(dftest,aggregate(cbind(sapply(x_test, get)),list(z),FUN=mean))
detach(dftest)
Cheers,
Nello
-Original Message-
From: r-help-boun...@r-project.org
Hi
Try to put your question on stackexchange. Or maybe it is already answered
there. I am not an statistical expert but based on common sense (which can be
counter intuitive sometimes) I will use ordered factor if I expect influence of
tension value on breaks. Anyway I will probably consult
try this:
dftest-data.frame(x=1:12, y=(1:12)%%4, z=(1:12)%%2)
aggregate(cbind(x,y)~z, data=dftest, FUN=mean)
z x y
1 0 7 1
2 1 6 2
x_test=c(x,y)
a - formula(paste0('cbind('
+ , x_test[1]
+ , ','
+ , x_test[2]
+
Sorry, didn't read your question properly
#Just a modification without attach():
aggregate(cbind(sapply(x_test,get,dftest))~z,data=dftest,FUN=mean)
# z x y
#1 0 7 1
#2 1 6 2
#if you need to aggregate() all the columns except the grouping column
aggregate(.~z,data=dftest,FUN=mean)
# z x y
#1
Dear all,
I have an ASCII-Grid for Switzerland in the Swiss National Coordinate System
of CH1903. Now for a Webapplication of the ASCII-Grid, I need to deliver the
ASCII-Grid in the WGS84 System.
Via coordinates(ascii) I can export the coordinates and convert them with
a formula into WGS84. My
The mean percentage change and the raw mean change are not directly comparable,
even after standardization based on the SD of the percentage change or raw
change values. So, I would not mix those in the same analysis.
Best,
Wolfgang
-Original Message-
From: Qiang Yue
-- Forwarded message --
From: Keniajin Wambui kiang...@gmail.com
Date: Thu, May 23, 2013 at 11:36 AM
Subject: Merge
To: r-help@r-project.org
I am using R 3.01 on R Studio to merge two data sets with approx 120
variables and the other with 140 variables but with a serialno as the
Hello,
You question is a bit unclear. Do you just want to change to decimal
degrees? Can you please provide an example of your code and include a
small example ascii.
On Thu, May 23, 2013 at 5:44 PM, jas
jacqueline.schwei...@wuestundpartner.com wrote:
Dear all,
I have an ASCII-Grid for
It would be useful to know what your ultimate goal is.
On Wed, May 22, 2013 at 6:29 AM, karengrace84 kgfis...@alumni.unc.edu wrote:
I am new to mapping with R, and I would like to use the point.in.polygon
function from the sp package, but I am unsure of how to get my data in the
correct format
Dear R Gurus,
I am trying to run a multigroup SEM using Prof. John Fox's SEM package.
The two groups are Ready to Eat denoted by RTE and
Ready to Cook denoted by RTC.
I ran a omnibus CFA on the data of consumer perceptions preferences and
am satisfied with what I
On Thu, May 23, 2013 at 8:44 AM, jas
jacqueline.schwei...@wuestundpartner.com wrote:
Dear all,
I have an ASCII-Grid for Switzerland in the Swiss National Coordinate System
of CH1903. Now for a Webapplication of the ASCII-Grid, I need to deliver the
ASCII-Grid in the WGS84 System.
Via
Dear Amarnath Bose,
There's nothing obviously wrong with the commands that you report -- in
fact, your commands have the same structure as the multigroup SEM example in
?sem -- so the usual advice about including reproducible code producing the
error applies. If you like, you could send me your
Hello Berry,
thank you for your reply.
yes, the flat versus round earth projection is a difficulty, as my grid
isn't that far spread out, I thought I would just use the method anyways.
I usually use raster or maptools (readAsciiGrid). I am gonna look in to the
mapper's forum, thank you for
Hello,
Try the following.
rm(list = ls())
dat1 - read.table(text =
Serialno name year outcome
1 ken1989 d
2 mary 1989a
4 john1989 a
5 tom 1989 a
6 jolly 1989 d
, header = TRUE, stringsAsFactors =
Thank you Blaser:
This is the exact solution I came up with but when comparing 8M rows even on
an 8G machine, one runs out of memory. To run this effectively, I have to
break the DF into smaller DFs, loop through them and then do a massive
rmerge at the end. That's what takes 8+ hours to
I am looking at fish tagging data. I have gps coordinates of where each fish
was tagged and released, and I have a map of 10 coastal basins of the state
of Louisiana. I am trying to determine which basin each fish was tagged in.
--
View this message in context:
Hi Rainer:
Thanks for the reply. Posting the large dataset is a task. There are 8M
rows between the two of them and the first discrepancy in the data doesn't
happen until at least the 40,000th row on each dataframe. The examples I
posted are a pretty good abstraction of the root of the issue.
You could also do:
library(plyr)
res1-join(dat1,dat2,type=full)
res1
# Serialno name year outcome disch_type
#1 1 ken 1989 d NA
#2 2 mary 1989 a NA
#3 4 john 1989 a NA
#4 5 tom 1989 a NA
#5 6
Dear Dr. Viechtbauer:
Thanks so much! Now all these issues are clear.
With best regards.
Qiang Yue
From: Viechtbauer Wolfgang (STAT)
Date: 2013-05-23 05:06
To: qiangmoon; r-help
Subject: RE: RE: [R] using metafor for meta-analysis of before-after studies
(escalc, SMCC)
The mean
Meng,
This really comes down to what question you are trying to answer. Before
worrying about details of default contrasts and issues like that you first
need to work out what is really the question of interest. The main
difference between declaring a variable ordered or not is the default
Using the data generated with your code below, does
rbind( DF1, DF2[ !(DF2$X.TIME %in% DF1$X.TIME), ] )
DF1 - DF1[ order( DF1$X.DATE, DF1$X.TIME ), ]
do the job?
Rgds,
Rainer
On Thursday 23 May 2013 05:54:26 Adeel - SafeGreenCapital wrote:
Thank you Blaser:
This is the exact solution I
Here are a couple of approaches:
dftest-data.frame(x=1:12, y=(1:12)%%4, z=(1:12)%%2)
x_test=c(x,y)
aggregate( dftest[,x_test], dftest['z'], FUN=mean )
z x y
1 0 7 1
2 1 6 2
### Or
tmp.f - as.formula( paste( 'cbind(',
+ paste( x_test, collapse=',' ),
+ ') ~ z' ) )
aggregate( tmp.f,
Hello,
I have a column called max_date in my data frame and I only want to keep the
bigger values for the same activity. How can I do that?
data frame:
activitymax_dt
A2013-03-05
B 2013-03-28
A 2013-03-28
C 2013-03-28
B 2013-03-01
Hi
change max_dt do PISIX class and use standard comparison operator and use the
result for selecting rows.
s-seq(c(ISOdate(2000,3,20)), by = day, length.out = 10)
ss[5]
[1] TRUE TRUE TRUE TRUE FALSE FALSE FALSE FALSE FALSE FALSE
Regards
Petr
-Original Message-
From:
Dear All,
I wrote a program using R 2.15.2 but this error message cannot allocate
vector of size 200Mb appeared. I want to ask in general how to handle this
situation. I try to run the same program on other computers. It is
perfectly fine. Can anybody help? Thank you very much in advance.
Best
Try in R 64 bit.
Thanks
Gyanendra Pokharel
University of Guelph
Guelph, ON
On Thu, May 23, 2013 at 10:53 AM, Ray Cheung ray1...@gmail.com wrote:
Dear All,
I wrote a program using R 2.15.2 but this error message cannot allocate
vector of size 200Mb appeared. I want to ask in general how to
The OP indicated that the middle group should be closed on both ends, i.e.
[0.1, 0.6].
dat2 - rbind(dat, 0.1, 0.6)
dat2$group - factor(ifelse(dat2$Var.1, A, ifelse(dat2$Var.6, C,
B)))
dat2
Var group
1 0.0 A
2 0.2 B
3 0.5 B
4 1.0 C
5 4.0 C
6 6.0 C
7 0.1 B
8 0.6
After a bit of playing around, I discovered that
sample() does something similar in other situations:
set.seed(105021)
sample(1:5,1,prob=c(1,1,1,1,1))
[1] 3
set.seed(105021)
sample(1:5,1)
[1] 2
set.seed(105021)
sample(1:5,5,prob=c(1,1,1,1,1))
[1] 3 4 2 1 5
set.seed(105021)
sample(1:5,5)
Hi,
I have a few graph objects created by some graphic package (say, ggplot2,
which I use frequently). Because of the existent relation between the
graphs, I'd like to index them in two dimensions as p[1,1], p[1,2], p[2,1],
p[2,2] for convenience.
To my knowledge, the only data type capable
HI GG,
I should had checked with multiple t=0 only rows.
Apologies!
Check if this work: (Changed the thread name as the solution applies to that
problem)
dat2- read.csv(dat6.csv,header=TRUE,sep=\t,row.names=1)
str(dat2)
#'data.frame': 3896 obs. of 3 variables:
# $ patient_id: int 2 2 2 2 2
Hi,
I have a very big data frame and I would like to apply a function to one of the
columns within different groups and obtain another dataframe
My data frame is like this:
group var1 var2 myvar
group1 1 a 100
group2 2 b 200
group2 34 c 300
group3 5 d 400
group3 6 e 500
group4 7 f 600
Hi,
Try:
datNew- read.table(text=
activity max_dt
A 2013-03-05
B 2013-03-28
A 2013-03-28
C 2013-03-28
B 2013-03-01
,sep=,header=TRUE,stringsAsFactors=FALSE)
datNew$max_dt- as.Date(datNew$max_dt)
aggregate(max_dt~activity,data=datNew,max)
#
Dear r-helpers,
I am trying to extract quantities of interest from my iTunes library xml file.
 For example, i'd like to be able to run a simple regression of playcount on
track number, under the theory that tracks near the beginning of albums get
played more (either because they are better
Hi,
I use R 2.14.0 on Win XP Pro SP3 and it behaves same - some times.
After I draw a lot of plots (more then 200, 2 concurrent rgui processes
running in parallel) to png then I get same error message.
Bmp(), jpg(), png() - same error. Restart of Rgui helps nothing.
Solutin - restart system and
From your email, it seems like aggregate() is working.
Could you please provide the sessionInfo()?
My guess is that some other loaded library is masking the summarize().
For example, if I load
library(Hmisc)
#The following object is masked from ‘package:plyr’:
#
# is.discrete, summarize
Hi,
May be this helps:
dat1- read.table(text=
group var1 var2 myvar
group1 1 a 100
group2 2 b 200
group2 34 c 300
group3 5 d 400
group3 6 e 500
group4 7 f 600
,sep=,header=TRUE,stringsAsFactors=FALSE)
library(plyr)
ddply(dat1,.(group),summarize, f_myvar=mifunc(myvar))
# group f_myvar
#1
This is the exact solution I came up with ...
exact, really?
Is the time-consuming part the initial merge
DFm - merge(DF1, DF2, by=c(X.DATE, X.TIME), all=TRUE)
or the postprocessing to turn runs of NAs into the last non-NA
value in the column
while(any(is.na(DFm))){
if
You could use lists of lists, and index them with vectors.
a - list()
a[[1]] - list()
a[[2]] - list()
a[[c(1,1)]] - g11
a[[c(1,2)]] - g12
a[[c(2,1)]] - g21
a[[c(2,2)]] - g22
print(a[[c(2,1)]])
but this seems like an inefficient use of memory because your indexed data is
stored more compactly
Thanks a lot!!! It works perkectly!
Just one thing, is there a way to preserve my original data frame so i don´t
need to join both tables? I could do it with rbind but my original data frame
is not in order, so
Thanks again!
From: arun
Hello all,
I would like to use the Nadaraya-Watson estimator assuming a Gaussian
kernel: So far I sued the
library(sm)
library(sm)
x-runif(5000)
y-rnorm(5000)
plot(x,y,col='black')
h1-h.select(x,y,method='aicc')
lines(ksmooth(x,y,bandwidth=h1))
which works fine. What if my data were clustered
To my knowledge, the only data type capable of storing graph objects
(and
any R object) is list, but unfortunately it is available in only one
dimension. Could the graphs be stored in any two-dimensional data type?
Lists can have any number of dimensions you want, just as with other vector
types.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Albyn Jones
Sent: Thursday, May 23, 2013 8:30 AM
To: r-help@r-project.org
Subject: Re: [R] sample(c(0, 1)...) vs. rbinom
After a bit of playing around, I discovered that
Hi,
No problem.
Try:
dat2-within(dat1,f_myvar-ave(myvar,group,FUN=mifunc))
dat2
# group var1 var2 myvar f_myvar
#1 group1 1 a 100 NA
#2 group2 2 b 200 299
#3 group2 34 c 300 300
#4 group3 5 d 400 499
#5 group3 6 e 500 500
#6 group4
Using the previous solution:
dat3-mutate(dat1,f_myvar=ddply(dat1,.(group),summarize,f_myvar=mifunc(myvar))[,2])
identical(dat2,dat3)
#[1] TRUE
A.K.
- Original Message -
From: arun smartpink...@yahoo.com
To: Estefanía Gómez Galimberti tef...@yahoo.com
Cc: R help r-help@r-project.org
the something similar is return a different result in two
situations where one might expect the same result, ie when
a probability vector with equal probabilities is supplied versus
the default of equal probabilities.
And, assuming that by concerns me you mean worries me,
I have no clue why you
Hi,
ab- cbind(a,b)
indx-duplicated(names(ab))|duplicated(names(ab),fromLast=TRUE)
res1-cbind(ab[!indx],v2=rowSums(ab[indx]))
res1[,order(as.numeric(gsub([A-Za-z],,names(res1,]
#v1 v2 v3
#1 3 4 5
#Another example:
a2- data.frame(v1=c(3,6,7),v2=c(2,4,8))
b2-
I have two files containing words. I want to print the are in file 1 but
NOT in file 2.
How do I go about?
file 1:
ABL1
1 ALKBH1
2 ALKBH2
3 ALKBH3
4ANKRD17
5 APEX1
6 APEX2
7 APTX
8 ASF1A
9 ASTE1
10 ATM
11 ATR
12 ATRIP
13 ATRX
14
Hi,
Try:
dat1- structure(list(V2 = c(ALKBH1, ALKBH2, ALKBH3, ANKRD17,
APEX1, APEX2, APTX, ASF1A, ASTE1, ATM, ATR, ATRIP,
ATRX, ATXN3, BCCIP, BLM, BRCA1, BRCA2)), .Names = V2, class =
data.frame, row.names = c(NA,
18L))
dat2- structure(list(V2 = c(ALKBH3, APEX1, APEX2, APLF, APTX,
ATM, ATR,
In that case I'd definitely look more at the over() function than that
ugly bit I suggested before.
Get your fish info into a SpatialPointsDataFrame
Since your polygons are in a SpatialPolygonsDataFrame, I would expect the
data frame part has one row per basin, and it contains the basin names or
See the
setdiff()
function
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 5/23/13 11:04 AM, Robin Mjelle robinmje...@gmail.com wrote:
I have two files containing words. I want to print the are in file 1 but
NOT in file
You recommended
library(sqldf)
sqldf('SELECT * FROM dat1 EXCEPT SELECT * FROM dat2')
Using nothing but the core R packages setdiff() returns the difference between
two sets.
setdiff(dat1$V2, dat2$V2)
[1] ALKBH1 ALKBH2 ANKRD17 ASF1A ASTE1 ATRXATXN3
BCCIP
If there are
#or
dat1$V2[is.na(match(dat1$V2,dat2$V2))]
#[1] ALKBH1 ALKBH2 ANKRD17 ASF1A ASTE1 ATRX ATXN3
#[8] BCCIP
a[is.na(match(a,b))]
#[1] 2 2 4
A.K.
- Original Message -
From: William Dunlap wdun...@tibco.com
To: arun smartpink...@yahoo.com; R help r-help@r-project.org
Cc:
Hi List,
I have a little confused when to glmnet() vs cv.glmnet().
I know that,
glmnet(): gives the fit
cv.glment(): does the cv after the fit
I just want to get the beta coefficients after the fit, that's it!
But of all the glmnet examples I've seen, the beta coefficient is
obtained ONLY AFTER
On 23.05.2013 17:06, Ondrej Novak wrote:
Hi,
I use R 2.14.0 on Win XP Pro SP3 and it behaves same - some times.
After I draw a lot of plots (more then 200, 2 concurrent rgui processes
running in parallel) to png then I get same error message.
Bmp(), jpg(), png() - same error. Restart of Rgui
On 23.05.2013 18:10, IOANNA wrote:
Hello all,
I would like to use the Nadaraya-Watson estimator assuming a Gaussian
kernel: So far I sued the
library(sm)
library(sm)
x-runif(5000)
y-rnorm(5000)
plot(x,y,col='black')
h1-h.select(x,y,method='aicc')
lines(ksmooth(x,y,bandwidth=h1))
which works
Dear useRs,
i have the following data arranged in three columns
structure(c(0.492096635764151, 0.42688044914, 0.521585941816778,
1.66472272302545, 2.61878329527404, 2.19154489521664, 0.493876245329722,
0.4915787202584, 0.889477365620806, 0.609135860199222, 0.739201878930367,
On May 23, 2013, at 8:30 AM, jpm miao wrote:
Hi,
I have a few graph objects created by some graphic package (say, ggplot2,
which I use frequently). Because of the existent relation between the
graphs, I'd like to index them in two dimensions as p[1,1], p[1,2], p[2,1],
p[2,2] for
I am creating a few dozen multi-panel time series plots using lattice graphics
in the lme4 package. Each panel in a given plot represents a tree. each
multipanel plot is a particular treatment. Here's my issue: when you use
xyplot() to plot this data it orders the panels alphabetically. I would
On 05/24/2013 06:21 AM, Belair, Ethan D wrote:
example.plot = xyplot(ht ~ time|tree, data=data,
type = c(r, g, p),
par.settings=simpleTheme(col=blue),
main=abc,
)
example.plot
...
Hi Ethan,
This may be what you want:
Hi,
I am trying to understand why creating Date variables does not work if I subset
to avoid NAs.
I had problems creating these Date variables in my code and I thought that the
presence of NAs was the cause. So I used a condition to avoid NAs.
It turns out that NAs are not a problem and I do
Hi,
I would be very graitful if someone could help me to figure out my problem.
I used mixed-effects models to analyse my data and AIC approach for model
selection. I am studying an effect on Labrador tea on basal diameter of spruce
in 2 different habitats (wet and dry zones) during 3 years.
You could convert those columns to Date class by:
Data[,c(4,6)]-lapply(Data[,c(4,6)],as.Date,origin=1970-01-01)
#or
Data[,c(4,6)]-lapply(Data[,c(4,6)],function(x) structure(x,class=Date))
# dat1 dat2 Dat1a Dat1b Dat2a Dat2b
#1 41327 41327 2013-02-22 2013-02-22 2013-02-22
Dear R experts,
This time I am unable create symbolic links to files as I had done last
time. I could not replicate what I had successfully tried last time (rerun
the same code without any modifications) .
I get the following error message..
[1] FALSE
Warning message:
In file.link(.file1, file2,
Thank you for the 2 methods to make the columns class Date, but I would really
like to know why these variables were not in Date class with my code. Do you
know?
Denis
Le 2013-05-23 à 21:44, arun smartpink...@yahoo.com a écrit :
You could convert those columns to Date class by:
Many thanks for your detailed reply.
I'll read your mail thoroughly. Thanks!
At 2013-05-23 21:56:29,Greg Snow 538...@gmail.com wrote:
Meng,
This really comes down to what question you are trying to answer. Before
worrying about details of default contrasts and issues like that you
On May 23, 2013, at 7:06 PM, Denis Chabot wrote:
Thank you for the 2 methods to make the columns class Date, but I would
really like to know why these variables were not in Date class with my code.
Do you know?
I suspect that the problem lies in the dispatch to `[-.class` or `$-`. When
I guess it is due to vectorization.
vec1- as.Date(Data[,2],origin=1899-12-30)
class(vec1)
#[1] Date
as.vector(vec1)
# [1] 15758 15765 15772 15779 NA 15793 15800 15807 NA 15821 15828
head(as.list(vec1),2)
#[[1]]
#[1] 2013-02-22
#
#[[2]]
#[1] 2013-03-01
head(data.frame(vec1),2)
#
Hello again,
I need to download 'WTI - Cushing, Oklahoma' from '
http://www.eia.gov/dnav/pet/pet_pri_spt_s1_d.htm' which is available under
the column 'View
History'
While I can get the data manually, however I was looking for some R
implementation which can directly download data into R.
Can
Rainer...I can't believe this did the trick. You're a genius. Thank you
sir.
On Thu, May 23, 2013 at 7:07 AM, Rainer Schuermann
rainer.schuerm...@gmx.net wrote:
Using the data generated with your code below, does
rbind( DF1, DF2[ !(DF2$X.TIME %in% DF1$X.TIME), ] )
DF1 - DF1[ order(
On May 23, 2013, at 7:56 PM, arun wrote:
I guess it is due to vectorization.
The concept of vectorization is much broader than the activities of
`as.vector`, but it needs a specific functional mechanism to be considered an
explanation.
vec1- as.Date(Data[,2],origin=1899-12-30)
class(vec1)
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