yes, I like this: a very elegant and neat solution (in my very umble
opinion)
sometime is so difficult to me to think of a solution in such a simple
and effective terms: less is more!
thank you
max
Il 03/10/2013 17:12, David Carlson ha scritto:
Try this
i=which(!sapply(mytest, is.null))
On Fri, Oct 4, 2013 at 5:57 AM, Peter Maclean pmaclean2...@yahoo.com wrote:
Anyone aware of a package or technique to import odf data file into R, I will
appreciate his/her help.
A quick scan of R-help points me here:
http://www.omegahat.org/ROpenOffice/
Reports of that working (or not)
Hi, thanks.
the printing one by one seems the only working solution. I also tried the
grid.arrange function but couldnt output what I am after.
Now the plots are placed in one page but I got the message error using
packet 1: promise already under evalution: recursive default arguments
reference
On 3 Oct 2013, at 22:39, Monaghan, David dmonag...@gc.cuny.edu wrote:
I was wondering, has anyone has encountered an R package that performs random
projection/random mapping? RP is a procedure that is akin to Principal
Components Analysis in that it accomplishes dimensionality reduction,
Assuming you want to read in data from an AOO or LO spreadsheet, have a look at
the gnumeric package. I have only used it once or twice but it seems to work
well and is quite flexible.
John Kane
Kingston ON Canada
-Original Message-
From: pmaclean2...@yahoo.com
Sent: Thu, 3 Oct
On Oct 3, 2013, at 16:30 , Hermann Norpois wrote:
Thanks for answering.
I already started hunting. But my first doubt was if I used prcomp correctly
(and this is in the moment my most important point). So far as I understood
your answer is yes. Is that correct?
Yes. There are a couple
Hi
I have never used the automap package and your syntax for xyplot does not
seem to be in the correct format for lattice.
A quick search showed that vgm.panel.xyplot from gstat package may give you
some ideas.
It appears that there are some particular adaptations for lattice for
spatial
I have a set of data and I need to find out how many points are below a
certain value but R will not calculate this properly for me.
R will. But you aren't.
Negative numbers seem to be causing the issue.
You haven't got any negative numbers in your data set. In fact, you haven't got
any
I think you have chosen a model that is ill-suited to the data.
My initial thoughts were simply that the issue was the usual nls()
singular gradient (actually jacobian if you want to be understood in
the optimization community) woes, but in this case the jacobian really
is bad.
My quick and
Dear Arun,Thanks indeed
Date: Thu, 3 Oct 2013 10:22:38 -0700
From: smartpink...@yahoo.com
To: r-help@r-project.org
Subject: Re: [R] vif
Hi Eliza,
Then, res needs a slight modification
library(car)
res- lapply(colnames(h),function(x) {x1- h[,x];dat1-
-Original Message-
Got it! I agree it should had been more obvious to me... :)
I wouldn't feel too bad about that. I've spent most of the last 25 years
discovering the hard way that statistics is very much a field where things are
'obvious' only _after_ you know the answer...
S
Hello!
I am learning Shiny. In my ui am allowing the user to read in 3 files. Here
is a piece of my ui.r code:
sidebarPanel(
fileInput('file1','Select File 1:'),
fileInput('file2','Select File 2:'),
fileInput('fileopt','Select Optional File:'),
actionButton(goButton,RUN)
),
Dear R users.
I'm trying to avoid using nested loops in the following code but I'm not sure
how to proceed. Any help would be greatly appreciated.
With regards,Phil
X = matrix(rnorm(100), 10, 10)
## Version with nested loopsresult = 0
for(m in 1:nrow(X)){ for(n in 1:ncol(X)){if(X[m,n] !=
I got sorted,
Thanks all
On Fri, Oct 4, 2013 at 2:03 PM, S Ellison s.elli...@lgcgroup.com wrote:
I have a set of data and I need to find out how many points are below a
certain value but R will not calculate this properly for me.
R will. But you aren't.
Negative numbers seem to be
I'm trying to avoid using nested loops in the following code but I'm
not sure how to proceed. Any help would be greatly appreciated.
With regards,Phil
X = matrix(rnorm(100), 10, 10)
result = 0
for(m in 1:nrow(X)){
for(n in 1:ncol(X)){
if(X[m,n] != 0){
The function I have been trying to use is: spatial_sync_raster
The maintainer has let me know that this is available in his spatial.tools
package, which you can get from CRAN:
install.packages(spatial.tools)
problem solved.
Thanks
jenny
-Original Message-
From: David Winsemius
Thank you for your answer. This is what I needed.
From: s.elli...@lgcgroup.com
To: r-help@r-project.org
Date: Fri, 4 Oct 2013 15:13:49 +0100
Subject: Re: [R] Trying to avoid nested loop
I'm trying to avoid using nested loops in the following code but I'm
not sure how to proceed. Any
Bill,
Thanks for replying.
The data is weekly time series data. Assume there is 52 weeks in the year. Of
the 52 weeks, I typically only have data for weeks 8 through 40.
4-Apr-10, 8, 27.2
11-Apr-10, 9, 32.3
18-Apr-10, 10, 31.7
DataXYZ, 40, 13.4
data -
Hi,
set.seed(49)
X = matrix(rnorm(100), 10, 10)
X1- X
result-0
for(m in 1:nrow(X)){ for(n in 1:ncol(X)){ if(X[m,n] != 0){ result
= result + (X[m,n] / (1 + abs(m - n))) } }}
indx-which(X!=0,arr.ind=TRUE)
indx1-1+abs(indx[,1]-indx[,2])
X1[indx]- X1[indx]/indx1
#or
Thanks Ista,
Can you please suggest any useful link(s) which explain RcmdrPlugin.temis
and tm package other than Cran-R one?
Thanks
Umesh
On Tue, Oct 1, 2013 at 11:40 PM, Ista Zahn istaz...@gmail.com wrote:
Do you know about task views? Try
Hi Peter,
The ssconvert tool (part of gnumeric) is very good at converting spreadsheets
to csv-files.
There is a wrapper in the gnumeric package on cran.
Cheers,
Thomas
Date: Fri, 4 Oct 2013 09:08:50 +0100
From: Barry Rowlingson b.rowling...@lancaster.ac.uk
To: Peter Maclean
Hello,
I have a seemingly simple problem that a tab-delimited file can't be read in.
annoTranscripts - read.table(matched.txt, sep = '\t', stringsAsFactors =
FALSE)
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
line 5933 did not have 12 elements
However,
Hi,
I have a data frame, data, containing two columns: one- the TimeStamp
(formatted using data$TimeStamp -
as.POSTIXct(as.character(data$TimeStamp), format = %d/%m/%Y %H:%M) )
and two- the data value.
The data frame has been read from a .csv file and should contain 48
values for each
Hi,
set.seed(49)
X = matrix(rnorm(100), 10, 10)
X1- X
result-0
for(m in 1:nrow(X)){ for(n in 1:ncol(X)){ if(X[m,n] != 0){ result
= result + (X[m,n] / (1 + abs(m - n))) } }}
indx-which(X!=0,arr.ind=TRUE)
indx1-1+abs(indx[,1]-indx[,2])
X1[indx]- X1[indx]/indx1
#or
res1-
Hello there,
I have some data I want to plot together with a best-fit line. (see MWE
below)
The points from the first plot does appear as expected, but the abline does
not appear, no matter what I change. I removed the log parameter before, but
the abline is a very steep line around the origin. I
Well you logged the x and y values before plotting but did not log the lm(). I
think this means you have plotted abline() off the scale.
I'm not sure how to fix it though.
John Kane
Kingston ON Canada
-Original Message-
From: hans_han...@gmx.de
Sent: Fri, 4 Oct 2013 07:16:49
Perhaps looking at your data will suggest an appropriate number, viz.
plot(data,type=b,xlim=c(0,20),ylim=c(0,50))
par(new=T)
ind-1:19 # in this case where the data length is 19
data.ind-data.frame(ind,data)
data.lo-loess(data~ind,data.ind)
data.pre-predict(data.lo,data.frame(ind = seq(1,19,1)))
I have some data I want to plot together with a best-fit line. (see MWE
below)
...
Can someone help me with that? What am I doing wrong?
Not logging the lm. Also, you've calculated lm() the wrong way round; you've
regressed x on y.
Try
plot(log(d), xlab=log(x), ylab=log(y))
abline(lm(y ~
Dear All,
I have a question, suppose X is a dataframe, with column names as
x1, x2, x3, . And I would like to use the i-th column by X[,'xi'].
But it seems the single quote and double quote are different.
So if I run X[, names(X)[i]], it has some error.
Please use the below example code
X =
Sorry, this sample code seems to be OK.
I will look into my original problem and update it soon.
Best wishes,
On Fri, Oct 4, 2013 at 12:06 PM, Jie jimmycl...@gmail.com wrote:
Dear All,
I have a question, suppose X is a dataframe, with column names as
x1, x2, x3, . And I would like to
Hello,
I had no problems, and it shouldn't. What exactly do you mean by not
working?
Hope this helps,
Rui Barradas
Em 04-10-2013 17:06, Jie escreveu:
Dear All,
I have a question, suppose X is a dataframe, with column names as
x1, x2, x3, . And I would like to use the i-th column by
X[,names(X)[4]] works fine for me. I had never thought of doing this. Neat
idea.
John Kane
Kingston ON Canada
-Original Message-
From: jimmycl...@gmail.com
Sent: Fri, 4 Oct 2013 12:06:50 -0400
To: r-help@r-project.org
Subject: [R] quote a column of a dataframe by its name
annoTranscripts - read.table(matched.txt, sep = '\t', stringsAsFactors =
FALSE)
Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, :
line 5933 did not have 12 elements
However, all lines do have 12 columns.
lines - readLines(matched.txt)
...[many omitted
Is there ever a case that X[,names(X)[4]] would give a different result
than X[,4]? Or is this just a case of the the longest distance between
any 2 points is a shortcut?
Well I guess if X has non-unique names then you might see a difference, but
having a data frame with non-unique names and
Hi,
Try:
annoTranscripts- read.csv(matched.txt, sep = '\t', stringsAsFactors =
FALSE,quote=,header=FALSE)
str(annoTranscripts)
'data.frame': 367274 obs. of 12 variables:
$ V1 : chr comp103529_c0_seq1 comp129123_c0_seq1 comp129123_c0_seq1
comp129124_c0_seq1 ...
$ V2 : chr XM_003723822
Do you have the correct fonts installed on Windows?
John Kane
Kingston ON Canada
-Original Message-
From: cels...@163.com
Sent: Wed, 2 Oct 2013 23:51:58 +0800 (CST)
To: r-help@r-project.org
Subject: [R] Drawing garbled
Hi:
I am Chinese, I am developing a java
Folks,
I have a working version of the code below for my real world problem. I was
wondering if there was a better way to do this.
I have 3 sets of parameters and I want to iterate over all combinations and
label the results.
Would some of the plyr tools make this easier?
# Input Scenarios
labels1- paste0([,with(allPerms,paste(A,B,C,sep=|)),])
vals2-as.matrix(cumsum(as.data.frame(t(allPerms
dimnames(vals2)- list(NULL,labels1)
all.equal(vals,vals2)
#[1] TRUE
A.K.
- Original Message -
From: Keith S Weintraub kw1...@gmail.com
To: r-help@r-project.org
This reproducible example is from the help of 'gbm' in R.
I ran the following code in R, and works fine as long as the response is
numeric. The problem starts when I convert the response from numeric to
binary (0/1). It gives me an error.
My question is, is converting the response from numeric
My question is, Is binarizing the response will have so much effect that it
does not find anythin useful in the predictors?
Yes. Dichotomizing throws away most of the information in the data.
Which is why you shouldn't do it.
This is a statistics, not an R question, so any follow-up should be
On Oct 4, 2013, at 2:16 PM, Mary Kindall mary.kind...@gmail.com wrote:
This reproducible example is from the help of 'gbm' in R.
I ran the following code in R, and works fine as long as the response is
numeric. The problem starts when I convert the response from numeric to
binary (0/1).
On Oct 4, 2013, at 21:16 , Mary Kindall wrote:
Y[Y mean(Y)] = 0 #My edit
Y[Y = mean(Y)] = 1 #My edit
I have no clue about gbm, but I don't think the above does what I think you
think it does.
Y - as.integer(Y = mean(Y))
might be closer to the mark.
--
Peter Dalgaard, Professor,
On Oct 4, 2013, at 2:35 PM, peter dalgaard pda...@gmail.com wrote:
On Oct 4, 2013, at 21:16 , Mary Kindall wrote:
Y[Y mean(Y)] = 0 #My edit
Y[Y = mean(Y)] = 1 #My edit
I have no clue about gbm, but I don't think the above does what I think you
think it does.
Y - as.integer(Y
Dear John Nash
Thank you very much for your inputs on how to fit a non-linear growth curve
without running into singular gradient. I wasn't aware of the package
nlmrt which seems to provide very helpful functions, indeed. I'll try to
figure out how nlxb() can be applied to my data (I am
Hello everybody,
I just started using R and I'm presenting a poster for R day at Kennesaw
State University and I really need some help in terms of web scraping.
I'm trying to extract used cars data from www.cars.com to include the
mileage, year, model, make, price, CARFAX availability and
Hi,
May be this helps:
set.seed(45)
df1-
data.frame(datetime=as.POSIXct(2011-05-25,tz=GMT)+0:200*30*60,value=sample(1:40,201,replace=TRUE),value2=
sample(45:90,201,replace=TRUE))
df2- df1[ave(1:nrow(df1),as.Date(df1[,1]),FUN=length)==48,]
dim(df2)
#[1] 192 3
#or
library(plyr)
Wonderful!
Thank you Arun!
Irene
Â
Irene Ruberto
Da: arun kirshna [via R] ml-node+s789695n4677558...@n4.nabble.com
Inviato: Giovedì 3 Ottobre 2013 22:51
Oggetto: Re: String substitution
Hi,
Try:
dat$y- as.character(dat$y)
dat1- dat
dat2- dat
Writing loops are the bane of my existence. I have this function, which
works:
rnd.data-function(x){ min.x-min(x[,2]) max.x-max(x[,2])
min.y-min(x[,3]) max.y-max(x[,3]) data.table(x = runif(34, min.x,
max.x))[, y := runif(34, min.y, max.y)] }
it's purpose is to simulate data within parameters
On 10/05/13 05:15, John Kane wrote:
X[,names(X)[4]] works fine for me. I had never thought of doing this. Neat
idea.
Perhaps I am being obtuse, but how would X[,names(X)[4]] differ from X[,4]?
cheers,
Rolf Turner
__
OS X 10.8
R 3.0.1
foreign 0.8-55 (2013-09-02)
Colleagues,
I received a SAS XPT file that I cannot read using the foreign package.
The command:
read.xport(FILENAME)
results in the following message:
Error in lookup.xport(file) : file not in SAS transfer format
I am able to read
Duncan
I looked at
support.sas.com/techsup/technote/ts140.pdf
and it is a bit difficult to decipher. I then replaced the string ^@ in the
file contents with !. There is some concordance with he sample text shown in
support.sas.com/techsup/technote/ts140.pdf but I don't know exactly
hello all,
I am trying to compile the R in Win7
and compiles one small part
but the script don't move from the 'base' directory to 'stats'
I installed the Rtools likee administrator
and call the terminal (MS-DOS) like administrator too.
if somebody can tell me any tips, I thank in advanced
There two different transport or portable file types that SAS creates: 1.
using Proc CPORT
2. using the XPORT engine in a LIBNAME statement.
That may not mean much to a non-SAS user, but people often use 'xpt' as a file
extension for both approaches. If Proc CPORT was used to write the file,
Hi Cleber,
You need to set TMPDIR to a valid directory, the default /tmp/ does not
work on Windows.
From the cmd shell:
set TMPDIR=C:/TMP
for example
and then run make all recommended
Cheers,
Josh
On Fri, Oct 4, 2013 at 5:03 PM, Cleber N.Borges kle...@yahoo.com.br wrote:
hello all,
I
thanks.
I am logged in the MS-DOS.
I thought that cygwin is not necessary...
in cygwin terminal, when I type: where sh
CLEBER@pinkfloyd /cygdrive/c
$ where sh
C:\cygwin\bin\sh.exe
C:\Rtools\bin\sh.exe
so, I have two version of sh
and the cygwin will be priority...
I will make more test and
bingo! :-)
I got one pass to advanced!
my TMP environment variable is:
%SystemRoot%\TEMP
thanks
cleber
Em 04/10/2013 22:02, Joshua Wiley escreveu:
Hi Cleber,
You need to set TMPDIR to a valid directory, the default /tmp/ does
not work on Windows.
From the cmd shell:
set TMPDIR=C:/TMP
Hi,
I have a short demo at https://gist.github.com/izahn/5785265 that
might get you started.
Best,
Ista
On Fri, Oct 4, 2013 at 12:51 PM, Mohamed Anany
melsa...@students.kennesaw.edu wrote:
Hello everybody,
I just started using R and I'm presenting a poster for R day at Kennesaw
State
Hi,
May be this helps:
set.seed(24)
dat1- as.data.frame(matrix(sample(1:50,100,replace=TRUE),10,10))
colnames(dat1)- paste0(Col,1:ncol(dat1))
rnd.data1 - function(x,n,ColSub,ColIndex=FALSE){
library(matrixStats)
if(ColIndex){
index - seq_len(ncol(x))%in% ColSub
Mins1 - colMins(x[index])
Hi Cleber
It cant find /tmp which does not exist on standard win32 mount system.
Are you sure you dont have to call the make all... from the cygwin
bash (cygwin terminal) and not the msdos pseudo terminal ?
W.
Le 04/10/2013 17:03, Cleber N.Borges a écrit :
hello all,
I am trying to compile
Hello,
I have a list of four files. Each file is a list of gene models, and each
gene model has attributes in file columns. The sample_week-over-sample_week
fold change value foreach i in file is in column 5. The gene model ID is in
column 1. To make it more complicated, each gene i may not be
stop because
*had a stone in the middle of the way*
*in the middle of the way had a stone*
(by vinicius de moraes)
#
so, one more help? somebody? :-)
thanks...
cleber
building package 'tcltk'
making init.d from init.c
making tcltk.d from tcltk.c
making tcltk_win.d from
Hi Cleber,
When you install Rtools, it asks you the home directory of R, and there it
puts a directory called src and Tcl. You need to copy those over to
whereever you are making R.
So for example, I have:
C:\usr\R\R-devel\Tcl
Where I tar -xf R devel into C:\usr\R\
and then copy the src and
Hi,
Try:
library(zoo)
z2- read.zoo(text=Date WBK_Last WBK_1d_Close
2003-01-03 13.88506 14.08276
2003-01-06 14.11254 13.88506
2003-01-07 14.07033 14.11254
2003-01-14 14.24165 14.30967
2003-01-22 14.28913 14.30563
2003-01-29 13.95664 14.16483
2007-01-01 14.87033
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