Thank you folks. Actually I did lookup all these resources you mentioned but
couldn't find a word for word meta data. In fact the data set is a bit
different from what's in the appendix of the paper. Also the meaning of these
terms seems to be specific to the study than following the
On Sun, Feb 2, 2014 at 6:46 AM, Rolf Turner r.tur...@auckland.ac.nz wrote:
On 02/02/14 15:37, mohammad javad Azadchehr wrote:
Hi
I want R code for bayesian CIF competing risks.
best regards
I want wealth, wisdom, good looks, and to play full forward for the
Sydney Swans.
One out of four
Hi all,
I'm trying to compute a mean on my data but I'm struggling with 2
things: 1. getting the right layout and 2. including the missing values
in the outcome.
#Input data:
Stock - c(A, A, A, A, A, A, B, B, B, B, B, B)
Soil - c(Blank, Blank, Control, Control, Clay, Clay,
Blank, Blank,
This seems like the ideal case for a MWE. If we can't reproduce your error, we
can't help diagnose it!
Steve
---
Steven Wolf
Research Associate
CREATE for STEM Institute
Michigan State University
On Feb 1, 2014, at 6:44 AM, Paresys, Lise lise.pare...@wur.nl wrote:
Dear all,
I am
Hello,
First of all avoid as.data.frame(cbind(...)). cbind() returns a matrix
and since you are mixing numbers with characters, all of the matrix
elements become character. Then as.data.frame transforms everything into
factors. The correct way is
d - data.frame(Stock, Soil, Nitrogen,
Not exactly the order you specified but otherwise I think this works.
library(plyr)
d - data.frame(Stock, Soil, Nitrogen, Respiration)
ddply(d, .(Soil, Stock), summarize, mean(Nitrogen), mean(Respiration))
John Kane
Kingston ON Canada
-Original Message-
From: aguitatie...@hotmail.com
Not enough information. Have a look at these links for some suggestions on how
to ask a question on R-help.
John Kane
Kingston ON Canada
-Original Message-
From: azadbiost...@gmail.com
Sent: Sat, 1 Feb 2014 18:37:00 -0800
To: r-help@r-project.org
Subject: [R] (no subject)
Hi
I have generated a L1 penalized Cox model using the penalized package in R. I
used the optL1() function to generate the Breslow object (see below):
fit - optL1(surv.obj, penalized = ..., etc)
In the reference manual, it says the fit$predictions are the cross-validated
predictions for the left
Also,
with(d,aggregate(cbind(Nitrogenr=Nitrogen,Respirationr=Respiration),by=list(Soilr=Soil,Stockr=Stock),FUN=mean))
A.K.
On Sunday, February 2, 2014 7:58 AM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
First of all avoid as.data.frame(cbind(...)). cbind() returns a matrix
and since
Hi Simon,
thank you for your reply, I really appreciate any help to understand
the problem here...
Unluckily the package upgrade didn't help with this issue.
An example reproducing the error, and a current sessionInfo() Output
can be found below.
Many thanks once again,
Katharina
R
On Feb 2, 2014, at 12:20 AM, Aziz, Muhammad Fayez wrote:
Thank you folks. Actually I did lookup all these resources you mentioned but
couldn't find a word for word meta data. In fact the data set is a bit
different from what's in the appendix of the paper. Also the meaning of these
terms
On Feb 2, 2014, at 8:43 AM, arun wrote:
Also,
with(d,aggregate(cbind(Nitrogenr=Nitrogen,Respirationr=Respiration),by=list(Soilr=Soil,Stockr=Stock),FUN=mean))
Did you compare your output to the input?
--
David.
A.K.
On Sunday, February 2, 2014 7:58 AM, Rui Barradas
I've tried to figure out how to do this from what I read, but haven't
been successful. Suppose I have a dataframe with variables Date, X, and
Y (and maybe U, V, and Z) where X, Y, etc. have different units. I'd
like to plot Y vs. Time above X vs. Time, above one another.
For example, X is
Probably, you are referring to:
d - as.data.frame(cbind(Stock, Soil, Nitrogen, Respiration))###
with(d,aggregate(cbind(Nitrogenr=Nitrogen,Respirationr=Respiration),by=list(Soilr=Soil,Stockr=Stock),FUN=mean))
I used:
d - data.frame(Stock, Soil, Nitrogen, Respiration)
If I understand you correctly, there are so many ways to do this
(ggplot2, lattice, base graphics with multiple graphs per page via
?layout,...) that I am puzzled as to how you failed to find what you
needed. Exactly what was it that you read that left you unable to do
this? Perhaps some
Just ***DON'T***!!! Very bad idea; usually wildly misleading.
See, e.g.:
http://www.perceptualedge.com/articles/visual_business_intelligence/dual-scaled_axes.pdf
OTOH if you're going to be bloody-minded and do it anyway, there are
brazillions of hits from a Google search which will tell you
He did not ask for dual axis graphs, Rolf.
This can be done with lattice graphics and also with ggplot. See, for example,
[1] or [2]. The melt function is a very powerful tool for preparing for this
task.
[1]
On Sun, Feb 2, 2014 at 2:09 PM, David Parkhurst parkh...@imap.iu.eduwrote:
I've tried to figure out how to do this from what I read, but haven't been
successful. Suppose I have a dataframe with variables Date, X, and Y (and
maybe U, V, and Z) where X, Y, etc. have different units. I'd like
Dear Duncan,
I discovered something interesting wrt to the licensing and mirroring
of user-contributed material on StackExchange. Please read below.
On Sun, Nov 24, 2013 at 9:00 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
I'm not aware of a discussion on this, but I would say no.
On 02/03/2014 06:09 AM, David Parkhurst wrote:
I've tried to figure out how to do this from what I read, but haven't
been successful. Suppose I have a dataframe with variables Date, X, and
Y (and maybe U, V, and Z) where X, Y, etc. have different units. I'd
like to plot Y vs. Time above X vs.
On Feb 2, 2014, at 9:52 AM, Katharina May wrote:
Hi Simon,
thank you for your reply, I really appreciate any help to understand
the problem here...
Unluckily the package upgrade didn't help with this issue.
An example reproducing the error, and a current sessionInfo() Output
can be found
Hi,
Try:
x -
c(rep(A,0.1*1),rep(B,0.2*1),rep(C,0.65*1),rep(D,0.05*1))
set.seed(24)
categorical_data - sample(x,1)
set.seed(49)
p_val - runif(1,0,1)
combi - data.frame(V1=categorical_data,V2=p_val)
variables - unique(combi$V1)
res - lapply(levels(variables),function(x){
Perhaps I misunderstood your question. Jeff Newmiller says that you did
not want multiple y-scales on the same plot, which is how I read what
you wrote. If you just want plots of X vs. time, Y vs. time, etc.
stacked one above the other then you perhaps should simple use
par(mfrow(.,.)) or
Hi,
as.numeric(iris$Species)
iris1 - within(iris,Species -as.numeric(Species))
A.K.
I have a small question for converting the category data to numeric data.
For example, if we use the iris data in r. we have:
str(iris)
'data.frame': 150 obs. of 5 variables:
$ Sepal.Length: num 5.1
R 3.0.1
OS X
Colleagues,
I am experimenting with incorporating C code into R. After compiling the C
code with:
R CMD SHLIB -o FILE.so FILE.c
and executing:
dyn.load(“FILE.so”)
(without any errors), I execute the following R functions in a terminal window:
READSAS
Hi,
I have the following issue. The dataframe df has a column (Date1) supposed
to be a date but read as a factor. There are two types of values in the
same column Date1
Type 1 are datetime like 5/23/2008 0:00:00
Type 2 have no time like 1/10/13.
When I apply the following to the date column
On 02/03/2014 12:53 PM, Yolande Tra wrote:
Hi,
I have the following issue. The dataframe df has a column (Date1) supposed
to be a date but read as a factor. There are two types of values in the
same column Date1
Type 1 are datetime like 5/23/2008 0:00:00
Type 2 have no time like 1/10/13.
When
On 02/03/2014 01:08 PM, Jim Lemon wrote:
On 02/03/2014 12:53 PM, Yolande Tra wrote:
Hi,
I have the following issue. The dataframe df has a column (Date1)
supposed
to be a date but read as a factor. There are two types of values in the
same column Date1
Type 1 are datetime like 5/23/2008
Please read the Posting Guide, which warns you to (among other things) post in
plain text and provide a reproducible example.
Read ?strptime. Note that you must provide a format that matches the data you
parse with it.
If you have both formats because you are also using Excel, you can fix the
You really need to read the Writing R Extensions document. It warns you
against performing I/O from C code linked to R.
You probably ought to read the Posting Guide, also, since this question is off
topic here
---
Jeff
Hi Jim,
I got an error
df$Date2-
+ as.POSIXct(as.character(df$Date1, format = %m/%d/%Y %H:%M:%S))
Error in as.POSIXlt.character(x, tz, ...) :
character string is not in a standard unambiguous format
On Sun, Feb 2, 2014 at 9:08 PM, Jim Lemon j...@bitwrit.com.au wrote:
On 02/03/2014
?sink
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.
On Sun, Feb 2, 2014 at 8:09 PM, Dennis Fisher fis...@plessthan.com wrote:
R 3.0.1
OS X
Colleagues,
I am experimenting with incorporating C code
Thank you Jeff. I had to go back to excel and format the column from there.
Thank you everyone,
Yolande
On Sun, Feb 2, 2014 at 9:51 PM, Yolande Tra yolande@gmail.com wrote:
Hi Jim,
I got an error
df$Date2-
+ as.POSIXct(as.character(df$Date1, format = %m/%d/%Y %H:%M:%S))
Error in
Hi Iakub,Do you mind sharing a concrete example of your approach (from R to
your script and back to R)? There is a growing demand to produce R plots for
government reports that ideally wouldn't require the intervention of a
designer to control the typography. While I'm getting a good grip at
Can I follow-up with what I've learned about my own myopia regarding
sapply()?
First, I appreciate all the feedback. After thinking about it for a
while I realized R designers have often chosen to accommodate
interactive usage, and in that context, sapply() returning different
types makes
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