Hi All!
This seems to be trival but I am not able to find a solution for it.
I have a dataframe with datetime columns in form of (%d/%m/%y %H:%M:%OS).
I write it to csv file. Whne i open the csv file the date time format are
in some number form .
So even if I use custome settings from excel to
Tried that..does not help :(
On Wed, Aug 20, 2014 at 8:03 AM, Saurabh Agrawal sagra...@idrcglobal.com
wrote:
Maybe converting POSIXct to character string using format before writing
to csv will help.
On 20 August 2014 17:23, Sneha Bishnoi sneha.bish...@gmail.com wrote:
Hi All!
This
This problem is in Excel or your use thereof, not in R, and is therefore not
technically on topic here.
FWIW I am aware that localization of Excel can change the default date formats
for input. I suspect that your installation of Excel has a different default
date format than you are using in
On Tue, Aug 19, 2014 at 1:30 AM, Jinsong Zhao jsz...@yeah.net wrote:
Hi there,
I have several saved data files (e.g., A.RData, B.RData and C.RData). In
each file, there are some objects with same names but different
contents. Now, I need to compare those objects through plotting.
However, I
On 20/08/2014, 8:58 AM, Barry Rowlingson wrote:
On Tue, Aug 19, 2014 at 1:30 AM, Jinsong Zhao jsz...@yeah.net wrote:
Hi there,
I have several saved data files (e.g., A.RData, B.RData and C.RData). In
each file, there are some objects with same names but different
contents. Now, I need to
Hi
If you really need to have minutes and seconds etc in excel then use a
package that can write datetime columns that excel can read eg. access
rather that csv.
Microsoft is well known for changing dates and date formats - remember excel
is a worksheet application not a database - caveat emptor.
It appears you posted in HTML and what we get is an almost useles set of data.
It is much better to supply it using dput() (and always post to the list in
plain text not HTML.
See https://github.com/hadley/devtools/wiki/Reproducibility of
Hi all,
I have recently started working with Date objects and find the
experience unsettling, to put it mildly.
The help for as.Date says, in part:
## S3 method for class 'character'
as.Date(x, format = , ...)
x: An object to be converted.
format: A character string. If
Never mind... the solution was to read the source code of
as.Date.character. It turns out the default format= is meaningless.
If 'format' is not given in the call to as.Date, it is NOT assumed to
be , and the function gives very different results from a call where
the argument format= is given.
Maybe converting POSIXct to character string using format before writing
to csv will help.
On 20 August 2014 17:23, Sneha Bishnoi sneha.bish...@gmail.com wrote:
Hi All!
This seems to be trival but I am not able to find a solution for it.
I have a dataframe with datetime columns in form of
Could you please post your code and some sample data?
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
On 20 August 2014 17:43, Sneha Bishnoi sneha.bish...@gmail.com wrote:
Tried that..does not help :(
On Wed, Aug 20, 2014 at 8:03 AM, Saurabh Agrawal
On Aug 20, 2014, at 4:53 AM, Sneha Bishnoi wrote:
Hi All!
This seems to be trival but I am not able to find a solution for it.
I have a dataframe with datetime columns in form of (%d/%m/%y %H:%M:%OS).
I write it to csv file. Whne i open the csv file the date time format are
in some
R Community -
I am attempting to write a function that will calculate the distance
between points in 3 dimensional space for unique regions (e.g. localized
brain regions such as the frontal lobe).
For example I'm looking to compare each point in region 45 to every other
region in 45 to establish
?dist
from the help
dist {stats}R Documentation
Distance Matrix Computation
Description
This function computes and returns the distance matrix computed by using the
specified distance measure to compute the distances between the rows of a data
matrix.
Is this what you want? Computing
Hi All,
I am trying to do some kriging of a floor, based on a number of heat sensors.
My data looks like this:
sensortempxy
1 1 1.25437406 390 2960
2 2 0.64384594 830 2960
3 3 1.52067733 1420 2960
4 4 1.21441928 3127 2920
5 5 1.04227694
The image file I prepared and attached did not make it through. Trying again.
--
David
Begin forwarded message:
From: David Winsemius dwinsem...@comcast.net
Subject: Re: [R] DateTime wrong when exporting to csv in R
Date: August 20, 2014 1:48:14 PM PDT
To: Sneha Bishnoi
On Aug 20, 2014, at 1:48 PM, David Winsemius wrote:
On Aug 20, 2014, at 4:53 AM, Sneha Bishnoi wrote:
Hi All!
This seems to be trival but I am not able to find a solution for it.
I have a dataframe with datetime columns in form of (%d/%m/%y %H:%M:%OS).
I write it to csv file. Whne
I tried installing RODBC but got the following message:
Checks were yes until the following
checking sql.h usability... no
checking sql.h presence... no
checking for sql.h... no
checking sqlext.h usability... no
checking sqlext.h presence... no
checking for sqlext.h... no
configure: error: ODBC
On Aug 20, 2014, at 5:43 PM, William Deese williamde...@gmail.com wrote:
I tried installing RODBC but got the following message:
Checks were yes until the following
checking sql.h usability... no
checking sql.h presence... no
checking for sql.h... no
checking sqlext.h usability... no
Hi all,
I was wondering if anyone knew how to construct a multiple line graph on R,
where there are 2 (or more) sets of data points plotted against some x axis of
data, and you can draw a line on the graph connecting each set of data points.
for example:
time..years. incidence
My guess is that you do not have the appropriate ODBC development library for
your operating system installed. It is not unusual that R packages that provide
interfaces to outside APIs require that those resources be installed and
configured in the operating system before the relevant R library
Hi
Try something like (as you have not given a reproducible example)
library(lattice)
xyplot(y1 + y2+ y3 ... ~ x, data = your data.frame, type = b,
allow.multiple = TRUE)
Read ?xyplot CAREFULLY as there are many possibilities
you may want to have a look at
library(lattice)
?useOuterStrips
Hi,
Suppose I have a the data frame given by:
dput(toy.df)
structure(list(id = c(1, 2, 1, 2), time = c(1L, 1L, 2L, 2L),
value = c(1, 2, 2, 3)), .Names = c(id, time, value), row.names = c(NA,
4L), class = data.frame)
that is:
toy.df
id time value
1 11 1
2 21 2
3 12
Do the jittering yourself before you give the data to ggplot.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Dear Rusers,
when i try file.show( xxx.h) in Rstudio which using R3.0.2, it doesn't
show anything. But when i use file.edit(xxx.h),it shows the right file, It
is the same thing happen to xxx.c file.
May you explain it to me?
--
PO SU
mail: desolato...@163.com
Majored in Statistics from
Estimados
Estoy entrenando hacer funciones que respondan a comandos,
en esta caso en la salida gráfica se observa que dice : Exposure=var3 y
outcome=var 1
quisiéramos que se reflejan los nombres de la base de datos : var1=estado,
var2=cake, var3=chocolate
Espero haberme explicado
Estimado José Betancourt
Copio y pego una forma donde anda, básicamente es lo mismo pero con una
pequeña diferencia, es tan parecido que están los dos códigos a
continuación.
Javier Marcuzzi
library(epicalc)
#Comando que llama a una función
rm(list=ls())
#setwd(D:/DEMO_new/demo_scripts/OR/)
Buenas noches Javier y Jos�,
Estoy en contra de usar attach(), asi que propongo la siguiente alternativa
con with():
# paquete
require(epicalc)
# los argumentos en ... pasan de epicalc:::cc
# ver ?cc para mas informacion
foo - function(var1, var2, var3, ...){
or1 - cc(var1, var2, ...)
or2 -
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