On 01/01/2015 2:43 PM, Mike Miller wrote:
On Thu, 1 Jan 2015, Duncan Murdoch wrote:
On 01/01/2015 1:21 PM, Mike Miller wrote:
On Thu, 1 Jan 2015, Duncan Murdoch wrote:
On 31/12/2014 8:44 PM, David Winsemius wrote:
On Dec 31, 2014, at 3:24 PM, Mike Miller wrote:
This is probably a FAQ,
On Thu, 1 Jan 2015, Duncan Murdoch wrote:
On 01/01/2015 1:21 PM, Mike Miller wrote:
On Thu, 1 Jan 2015, Duncan Murdoch wrote:
On 31/12/2014 8:44 PM, David Winsemius wrote:
On Dec 31, 2014, at 3:24 PM, Mike Miller wrote:
This is probably a FAQ, and I don't really have a question about it,
Interesting. Following someone on this list today the goal is input
the data correctly.
My inclination would be to read the file as text, pad each number to
the right, drop the decimal point,
and then read it as an integer.
0 1 2 0.325 1.12 1.9
0.000 1.000 2.000 0.325 1.120 1.900
1000 2000
On Thu, 1 Jan 2015, Duncan Murdoch wrote:
On 31/12/2014 8:44 PM, David Winsemius wrote:
On Dec 31, 2014, at 3:24 PM, Mike Miller wrote:
This is probably a FAQ, and I don't really have a question about it, but I just
ran across this in something I was working on:
as.integer(1000*1.003)
On 01-01-2015, at 05:52, John Sorkin jsor...@grecc.umaryland.edu wrote:
Windows 7
I am running normalmixEM to fit two normal curves to my data. For some
reason, that I don't understand, the results of running the function twice,
on the same data, results in two different (although
Thank you for attempting to encode what you want using R syntax, but you are
not really succeeding yet (too many errors). Perhaps another hand generated
result would help? A new input data frame might or might not be needed to
illustrate desired results.
Your second and third lines are
Is it possible to add the following code or similar in data.table:
childseg-0
x:=sumchild -0
span-rle(x)$lengths[rle(x)$values==TRUE
childseg[x]-rep(seq_along(span), times = span)
childseg[childseg == 0]-''
I was hoping to do this code by Group for mum, dad and
child. The problem I'm having is
On 31/12/2014 8:44 PM, David Winsemius wrote:
On Dec 31, 2014, at 3:24 PM, Mike Miller wrote:
This is probably a FAQ, and I don't really have a question about it, but I
just ran across this in something I was working on:
as.integer(1000*1.003)
[1] 1002
I didn't expect it, but maybe I
Dear all,
I am drawing a phylogenetic tree using the zoom() function of the ape package.
Since I have 476 sequences in my alignment, this allows me to have the outlook
of
the main tree and then highlight a portion of it, and this works fine.
At the moment I am using the approach of indicating
Dear all,
I am drawing a phylogenetic tree using the zoom() function of the ape
package. Since I have 476 sequences in my allagnment, this allows me to
have the outlook of the main tree and then highlight a portion of it,
and this works fine.
However I would like to draw a scale bar using
On 01/01/2015 1:21 PM, Mike Miller wrote:
On Thu, 1 Jan 2015, Duncan Murdoch wrote:
On 31/12/2014 8:44 PM, David Winsemius wrote:
On Dec 31, 2014, at 3:24 PM, Mike Miller wrote:
This is probably a FAQ, and I don't really have a question about it, but I
just ran across this in something I
On Jan 1, 2015, at 5:07 PM, Kate Ignatius kate.ignat...@gmail.com wrote:
Apologies - mix up of syntax all over the place, a habit of mine. The
last line was in there because of code beforehand so it really doesn't
need to be there. Here is the proper code I hope:
childseg-0
x-sumchild
Apologies - mix up of syntax all over the place, a habit of mine. The
last line was in there because of code beforehand so it really doesn't
need to be there. Here is the proper code I hope:
childseg-0
x-sumchild ==0
span-rle(x)$lengths[rle(x)$values==TRUE]
childseg[x]-rep(seq_along(span),
On Thu, 1 Jan 2015, Duncan Murdoch wrote:
On 01/01/2015 1:21 PM, Mike Miller wrote:
I understand that it's all about the problem of representing digital
numbers in binary, but I still find some of the results a little
surprising, like that list of numbers from the table() output. For
I'd have to say thanks, but no thanks, to that one! ;-) The problem is
that it will take a long time and it will give the same answer.
The first time I did this kind of thing, a year or two ago, I manipulated
the text data to produce integers before putting the data into R. The
data were a
I've been followeing this little tour round the murkier bistros
in the back-streets of R with interest! Then it occurred to me:
What is wrong with [using example data]:
x0 - c(0,1,2,0.325,1.12,1.9,1.003)
x1 - as.integer(as.character(1000*x0))
n1 - c(0,1000,2000,325,1120,1900,1003)
x1 -
Yes, Ted, that also works, but it's very slow:
# read in values:
data - scan( file=RECIP_IN, what=double(), nmax=recip_N*16000)
Read 48013406 items
# convert to integer by adding .5 and rounding down:
ptm - proc.time() ; ints - as.integer( 1000 * data + .5 ) ; proc.time()-ptm
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