Beats me. You can print a single data frame with
print(dat1, rownames = FALSE) but it is not clear to me how to do it within a
function.
I am sure someone who actually know what they are doing will be along in a
moment. Sorry not to have been of more help.
John Kane
Kingston ON Canada
This might help:
http://bit.ly/1MUP0Lj
On Wed, Jul 29, 2015 at 11:00 AM, jpara3 j.para.fernan...@hotmail.com
wrote:
¿How can i set up a study with random forest where the response is highly
imbalanced?
-
Guided Tours Basque Country
Guided tours in the three capitals of the Basque
Thank you everyone for taking the time to reply.
Thanks Martin and Hervé for your solutions.
Now I just need to remember to check for NA match.
--
View this message in context:
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1. Please post in plain text, not HTML.
2. Please do your homework. Data frames (the class of the result of
dcast) **always** have row names. ?data.frame for details.
3. Read up on S3 methods if you have not done so already (any good R
tutorial will tell you about them, including the Intro to R
As models become more complex it becomes harder to distinguish
different parts and their effects. Even for a straight forward linear
regression model if X1 and X2 are correlated with each other then it
becomes difficult to distinguish between the effects of X1^2, X2^2,
and X1*X2. In your case
Hello,
I'm trying to execute a python script within R (3.2.1 x 64) with the
PythonInR package. I would like to download an order of satellite images
from Nasa using a python script (
http://landsat.usgs.gov/documents/espa_bulk_downloader_v1.0.0.zip) but I
have no success. I first run the
Here is a small example. it is not the real data I am working on but this
can help
#Chick weight example
names(ChickWeight) - tolower(names(ChickWeight))
chick_m - melt(ChickWeight, id=2:4, na.rm=TRUE)
class(chick_m)
test = function(data){
i = 1
table = list()
table [[i]] - dcast(chick_m,
There is confusion here. apply() family functions are **NOT**
vectorization -- they ARE loops (at the interpreter level), just done
in functionalized form. Please read background material (John
Chambers's books, MASS, or numerous others) to improve your
understanding and avoid posting erroneous
Is this what you mean?
z - data.frame(a=1:3,b=letters[1:3],row.names=letters[1:3])
zlist - list(one=z,too =z)
for(i in 1:2){print(zlist[[i]],row.names=FALSE); cat(\n)}
a b
1 a
2 b
3 c
a b
1 a
2 b
3 c
... which could obviously be within a function.
Cheers,
Bert
Bert Gunter
Data is
Hi,
Nope. My point is that color pairs red-green, yellow-violet and blue-orange are
physically on the opposite sides of the wheel.
I'm not 100% satisfied with this circle, because three of greens and reds are
so near each other. But this is the best solution thus far :-)
The number of colors,
No, I'm not confused. I just posted on R help website. I don't know how to
use the email client to do anything which you are speaking of. If you would
like the posts to be made in an alternative way, then you will need to
provide clear direction. Sending someone to a help page which doesn't
Alright, I think I understand what you guys are talking about. It is still
not clear the relationship between R-help and Nabble since you guys haven't
actually answered that.
Again, the best way to provide proper advice is to actually quote to portion
of the website you are sending people to,
My question is about how to select and rearrange the data to a new data
frame
Here is an example:
Samples counts time
A 10 3
A 12 4
A 11 3
B 12 4
B 10 5
C
On Wed, Jul 29, 2015 at 2:45 PM, farnoosh sheikhi via R-help
r-help@r-project.org wrote:
Hi Arun,
Hope all is well with you. I have a data with a column for date.The date
format is mixed. There are date values with Month/Day/Year format and values
with Day/Month/Year format.I don't know how
Hi Arun,
Hope all is well with you. I have a data with a column for date.The date format
is mixed. There are date values with Month/Day/Year format and values with
Day/Month/Year format.I don't know how to unify it.I really appreciate your
help.Thanks.
[[alternative HTML version
I'm assuming you actually want the date column to be character, not factor:
SampleData - structure(list(id = 1:7, value = c(5813L, 8706L, 4049L, 5877L,
1375L, 2223L, 3423L), date = c(19-Dec-11, 07-Dec-11, 06/05/11,
05/12/11, 31/12/2011, 10/19/2011, 01/22/2011)), .Names = c(id,
value, date),
Hi Sarah,
Thanks for getting back to me.Here is an example of my data:SampleData -
structure(list(id = 1:7, value = c(5813L, 8706L, 4049L, 5877L,
1375L, 2223L, 3423L), date = structure(c(4L, 3L,
2L, 1L, 7L,
Hi Stella,
On Wed, Jul 29, 2015 at 1:14 PM, Stella Xu stella...@hli.ubc.ca wrote:
My question is about how to select and rearrange the data to a new data
frame
Here is an example:
Samples counts time
A 10 3
A 12 4
A 11
On Jul 29, 2015, at 1:02 PM, Hidden Markov Model wrote:
Alright, I think I understand what you guys are talking about. It is still
not clear the relationship between R-help and Nabble since you guys haven't
actually answered that.
Nabble's relationship to Rhelp? Nabble is an ongoing
Further refining the vectorized (within a loop) exact string match
function, I get times below 0.9 seconds while maintaining error checking.
This is accomplished by removing which() and replacing 1:length() with
seq_along().
sub2 - function(pattern, replacement, x) {
len- length(x)
y
Since there IS NO R-help website that you can post on, you are definitely being
confused by the Nabble website. This is a MAILING list that you interact with
by sending emails to r-help@r-project.org, not a website forum. The trouble
with Nabble is that it does confuse users, and breaks the
Hola,
Tengo una matriz ' elev.rad.mx ' que tiene tres columnas:
1� columna: coordenada x del punto geogr�fico.
2� columna: coordenada y del punto geogr�fico.
3� columna: valores de un radar en el punto geogr�fico (x,y).
Quiero convertir esta matriz a un objeto raster. Para ello, pongo la
Hi John,
Great thanks for the examples! I am not sure what you are referring to when
you say a post from Nabble - I posted this directly on R-help. I actually
never heard of Nabble.
Stacked Bar charts are great for when you have a lot of moving parts and
need to be able to zero in on one of
Then why do your messages contain the Nabble footer:
View this message in context:
http://r.789695.n4.nabble.com/Daily-Category-Revenue-Stacked-Bar-Chart-in-ggplot2-tp4710431p4710540.html
Sent from the R help mailing list archive at Nabble.com.
I think you are confused. You should be looking
On 29-07-2015, at 20:37, Hidden Markov Model huss...@touchofmodern.com
wrote:
No, I'm not confused. I just posted on R help website.
The R help website is NOT on Nabble. You posted from Nabble as can be seen
from your message.
It can also be seen in what the internet browser displays. It
Alright thanks for clarifying. That's all a bit esoteric. Quite different
from basics off computer use. None of the documentation anyone mentioned
actually contains any of this. If Nabble is so bad, then why does anyone use
it? It doesn't make sense. You should probably write a wiki going forward
Below.
Bert Gunter
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
-- Clifford Stoll
On Wed, Jul 29, 2015 at 3:43 PM, Hidden Markov Model
huss...@touchofmodern.com wrote:
Alright thanks for clarifying. That's all a bit esoteric. Quite different
Alright kids, I think we should close this topic since we appear to be
getting further and further off-topic.
--
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Sent from the R help mailing list archive at
Hello,
I've recently discovered the helpful dplyr package. I'm using the
'aggregate' function as such:
bevs - data.frame(cbind(name = c(Bill, Mary), drink = c(coffee,
tea, cocoa, water), cost = seq(1:8), sex = c(male,female)));
bevs$cost - seq(1:8)
bevs
name drink costsex
1 Bill
Hi Brian,
Thanks for the suggestion, although the command is throwing an error as
such:
bevs %% group_by(name, sex, drink) %% summarise( cost = sum(cost)) %%
select(name, drink, cost, sex)
Error: unexpected input in bevs %% group_by(name, sex, drink) %%
summarise(
Your syntax is new to me
Hi All,
I am writing a Vignette with Knitr using devtools ... actually quite awesome.
However, I would like to create a table of contents. I have read the knitr and
r markdown instructions on TOC and I can create a TOC in a markdown document
but I cannot translate the command to a vignette -
David,
I do appreciate your help, if not the dose of contempt. I hope you
feel OK.
Thanks for the tips,
-Jonathan
On Wed, Jul 29, 2015 at 11:14 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Jul 29, 2015, at 7:37 PM, Jon BR wrote:
Hello,
I've recently discovered the helpful
dplyr solution:
bevs %% group_by(name, sex, drink) %% summarise(cost = sum(cost)) %%
select(name, drink, cost, sex)
The last select statement puts the output in the column order you wanted in
your result.
I hope this helps.
Brian
On Wed, Jul 29, 2015 at 9:37 PM, Jon BR jonsle...@gmail.com
Hi
I wonder if it is easier to convert the dates to character format and then
reformat using gsub or the like
str(SampleData)
SampleData$date - as.character(SampleData$date)
str(SampleData)
as.Date(
ifelse(nchar(SampleData[,date]) == 9, as.Date(SampleData[,date], format =
%d-%b-%y),
On Jul 29, 2015, at 7:37 PM, Jon BR wrote:
Hello,
I've recently discovered the helpful dplyr package. I'm using the
'aggregate' function as such:
The `aggregate` function is part of base-R:
bevs - data.frame(cbind(name = c(Bill, Mary), drink = c(coffee,
tea, cocoa, water), cost =
On 28 Jul 2015, at 15:53 , Sarah Goslee sarah.gos...@gmail.com wrote:
Sure, there are lots of ways to do everything in R. But mixing in
apply muddles the issue, since apply() and sweep() use different logic
to determine MARGIN.
Actually, apply() and sweep() were designed together and use
Hervé Pagès hpa...@fredhutch.org
on Tue, 28 Jul 2015 23:07:14 -0700 writes:
On 07/28/2015 09:58 PM, Peter Alspach wrote:
One way
seq(test1)[-which(test1==test2)]
One question is whether 2 NAs should be considered to match or not.
The OP doesn't tell but
On 07/28/2015 09:58 PM, Peter Alspach wrote:
One way
seq(test1)[-which(test1==test2)]
One question is whether 2 NAs should be considered to match or not.
The OP doesn't tell but I guess he wants them to match:
test1 - c(1, 2, NA, 4, NA, 6)
test2 - c(1, 2, 3, NA, NA, 66)
Thanks, Dan.
Your codes work fine. But I have tens of countries UK, JP, BR, US...,
each of which has ten columns a1, a2, ..., a10 of data. So a little more
automation is needed.
I have been trying to make a list of each country's data and use sapply
thing
to get
UK JP
2009 Q2
Hola Rubén,
Muchas gracias.
Un saludo,
Guillermo
Hola a ambos,
Otra referencia que puede ser de interés es:
http://r-pkgs.had.co.nz y también http://adv-r.had.co.nz (las dos de
Hadley Wickham...)
Un saludo, Rubén.
El 27/07/2015 a las 10:46, guillermo.vi...@uv.es
Not any ideas?
Thanks!
--
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__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
Hola a ambos,
Otra referencia que puede ser de interés es:
http://r-pkgs.had.co.nz y también http://adv-r.had.co.nz (las dos de
Hadley Wickham...)
Un saludo, Rubén.
El 27/07/2015 a las 10:46, guillermo.vi...@uv.es escribió:
Hola Carlos,
Muchas gracias por el enlace, me ha sido de
Dear All,
Is there a way to not include the row names when creating the list? Thanks!
Regards,
Frederic.
Frederic Ntirenganya
Maseno University,
African Maths Initiative,
Kenya.
Mobile:(+254)718492836
Email: fr...@aims.ac.za
https://sites.google.com/a/aims.ac.za/fredo/
[[alternative
data-read.csv(https://raw.githubusercontent.com/sjkiss/Survey/master/mlogit.out.csv,header=T,sep=,;)
--
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Sent from the R help mailing list archive at Nabble.com.
The solution is to create a new tkbind function that has not argument
tkbind(img,button-1,)
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Thank you for your suggestion. Is there any open source api that won't
rate-limit it?
On Tue, Jul 28, 2015 at 9:38 PM, boB Rudis b...@rudis.net wrote:
You should use ggmap::revgeocode (it calls google's api) and google
will rate-limit you. There are also packages to use HERE maps
geo/revgeo
¿How can i set up a study with random forest where the response is highly
imbalanced?
-
Guided Tours Basque Country
Guided tours in the three capitals of the Basque Country: Bilbao,
Vitoria-Gasteiz and San Sebastian, as well as in their provinces. Available
languages.
Travel planners
First
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
and http://adv-r.had.co.nz/Reproducibility.html
Second. It is very annoying to have posts come in from Nabble. Very few R-help
readers use it and the total context of some post to R-help is usually
HI Frederic,
Can you supply a small example of the problem?
John Kane
Kingston ON Canada
-Original Message-
From: ntfr...@gmail.com
Sent: Wed, 29 Jul 2015 14:15:58 +0300
To: r-help@r-project.org
Subject: [R] Removing display of R row names from list.
Dear All,
Is there a way
Try restarting R-Studio. I have found that every once in a while it seems to do
something squirrelly but I have never isolated the problem enough to do a
report.
Otherwise,perhaps run R in a terminal and see if it will load the data from
there to check if the file is actually okay.
John Kane
Quite, but apparently not a boisterous one?
John Kane
Kingston ON Canada
-Original Message-
From: cfly...@ncsu.edu
Sent: Mon, 27 Jul 2015 14:35:06 -0400
To: jrkrid...@inbox.com
Subject: Re: [R] VIF threshold implying multicollinearity
No actually it is a quiet good paper! :)
On Mon,
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