Re: [R] value of variable in ls()

Is this what you want:: > a <- 1 > b <- 2 > # get current objects > x <- ls() > # create list of values > my_list <- lapply(x, get) > # now add the names > names(my_list) <- x > my_list # print values $a [1] 1 $b [1] 2 Jim Holtman Data Munger Guru What is the problem that you are trying to

[R] package or namespace load failed for ‘dismo’

Hello everyone. I installed dismo package, but I've been receiving the following loading error: *Loading required package: raster* *Loading required package: sp* *Error : .onLoad failed in loadNamespace() for 'dismo', details:* * call: NULL* * error: 'tmpDir' It is not an exported object

Re: [R] condition in triple summation

Learn to post using plain text format. We are seeing garbage on the screen. --- Jeff NewmillerThe . . Go Live... DCN:Basics: ##.#. ##.#. Live

Re: [R] Replace NaN with value from the same row

Ok, i will do, thanks for your help. J > Subject: RE: [R] Replace NaN with value from the same row > From: jdnew...@dcn.davis.ca.us > Date: Sun, 18 Oct 2015 12:55:14 -0700 > To: jonathanrear...@outlook.com > CC: r-help@r-project.org > > You should (re-)read the intro document that comes with R,

[R] condition in triple summation

Dear R-Expertsx=c(0,0.3, 0.5,0.6)sum(sapply(1:4, function(i) {sum(sapply(1:3, function(j){sum(sapply(1:2, function(k) {(i>j)*(j>k)*exp(x[i]+x[j]+x[k])}))}))})) I want to restrict the condition (i>j>k) to only those cases where i>1>1>1In other words'if i=1 then i>=jif j=1 then j>=kother wise

Re: [R] package or namespace load failed for ‘dismo’

I don't know why this is happening for you, but if you want help here the Posting Guide asks you to update your R to the latest version first, since new packages sometimes won't work in old versions of R. --- Jeff Newmiller

Re: [R] How to plot shades between curves?

Hi Jackson, >From your description, I think you are trying to illustrate the deviation of Capa.diss, so I will offer an entirely different method. If you do want the primary line on the left of the plot with a big space on the right, presumably to add more stuff there, try this:

Re: [R] Replace NaN with value from the same row

You should (re-)read the intro document that comes with R, "An Introduction to R". Pay particular attention to sections 2., 2.7, and 5.2. The "idx" variable that I defined is a vector in the current environment (in your case apparently a local function environment). It is not a column in your

[R] Problem with custom.model.names in plotreg (texreg)

Hi, I need some advice. I'm using the package 'texreg' to extract effects in a multinomial model. While using the 'plotreg' command I've got a problem with the subcommand 'custom.model.names'. I'm able to have this subcommand working with the 'screenreg' command. However, when I use the

[R] value of variable in ls()

This may seem trivial: ls() gives me names of variables as a character vector. How can I print the values 'behind' those character values: ls() > "a" > a [1] 5 How can I do e.g. print("unknown"(ls())) and get the variable values in my current environment? -- Christian W. Hoffmann CH -

Re: [R] How to plot shades between curves?

> > plot(Capa.diss,Capa.diss.age,ylim = > rev((range)(Capa.diss.age=c(min(Capa.diss.age), > 10500))),xlim=(c(0,30)),type="l") > Capa.diss2<-Capa.diss*0.7 > par(new=TRUE) > plot(Capa.diss2, Capa.diss.age, col='black',type="l",ylim = > rev((range)(Capa.diss.age=c(min(Capa.diss.age), 10500))), >

[R] R package related to solving calibration transfer problem

Hi, I'm new to R (and also chemometrics). I have problem using same calibration model on spectrums obtained from two spectrometers of same brand. There's little different in the wavelength, less than 1 nm though and also different in their intensity level. What i understand, this problem is a

[R] A question about SDE package

Hello Friends, I am trying to use the functions ksdrift and ksdiff both in SDE package. Unfortunately. It does not work for my data (attached). The following code shows how I tried to use it: setwd("D:/Mohammad/Different/New folder") mydata <- read.csv("Best.csv", header=FALSE)

Re: [R] value of variable in ls()

Hello, I'm not sure I understand, but something like this? a <- 5 get("a") See ?get Hope this helps, Rui Barradas   Citando Christian Hoffmann : > This may seem trivial: > > ls() gives me names of variables as a character vector. How can I print > the values 'behind'

Re: [R] Replace NaN with value from the same row

Please reply to all so the answers are seen on the mailing list, where my mistakes can be corrected and others can learn from any valid answers I manage to provide. I warned you that df is the name of a common function. I used the name of the variable that you referred to in your question,

Re: [R] No speed up using the parallel package and ncpus > 1 with boot() on linux machines

As with Milan's answer: perfect explanation and hugely appreciated. A few follow up questions/comments below. - Original Message - > From: "Jeff Newmiller" > To: "Chris Evans" > Cc: r-help@r-project.org > Sent: Saturday, 17 October, 2015

Re: [R] No speed up using the parallel package and ncpus > 1 with boot() on linux machines

- Original Message - > From: "Milan Bouchet-Valat" > To: "Chris Evans" , r-help@r-project.org > Sent: Saturday, 17 October, 2015 18:13:40 > Subject: Re: [R] No speed up using the parallel package and ncpus > 1 with > boot() on linux machines >

[R] How to plot shades between curves?

Dear all, I have to compare several curves that range through different scales (x axis) along the same time, so to make them comparable I brought all of them to the same scale (x axis) and obviously kept the age axis (y axis) for all of them. As result, some variations (wiggles) simply

Re: [R] How to plot shades between curves?

Hi, Thanks for the reproducible example! (Don't forget to make your email client send text-only messages, not html, when sending to this list). Would log scale work for you? Capa.diss<-c(0.7261102, 0.6655960, 0.5638357,0.8585834,0.6964527,0.8434504,

[R] Replace NaN with value from the same row

Hi everyone, A simple question, but i cannot figure this out. I have a data-frame with 4 columns (onset, offset, outcome, mean): onset offset outcome mean8 72071 72503 1 7244615 142598 143030 1NaN30 293729 294161 1 294080 For each 'NaN' in the mean column, i want to

Re: [R] Replace NaN with value from the same row

Next time send your email using plain text format rather than HTML so we see what you saw. Try idx <- is.na( df$mean ) df[ idx, "mean" ] <- df[ idx, "offset" ] BTW there is a commonly-used function called df, so you might improve clarity by using DF for your temporary data frame name.

[R] Replace NaN from 1 column with a value from the same row

Hi everyone, Ignore my previous post, i realised that the rows and columns i typed into the email were unreadable, sincere apologies for this. A simple question, but i cannot figure this out. I have a data-frame with 4 columns (onset, offset, outcome, mean):