Hi, I have a experiment like this:
Trat Rep Peak CAS
11 1123-92-2
11 2109-21-7
11 32867-05-2
11 ... ...
11 33 99-86-5
12 1562-74-3
12 2123-92-2
12 3109-21-7
12 ... ...
12 45 2867-05-2
...
14 3 18
Hola a todos,
Quisiera aplicar una función f(x) un total de k veces de manera recursiva.
En pseudo código sería algo como
Si k = 1, calcular f(x);
Si k = 2, calcular f(f(x));
Si k = 3, calcular f(f(f(x))).
Al final me gustaria tener una función g cuyos argumentos sean x y el valor
de k. Así,
On 4/06/16 11:54 AM, tan sj wrote:
Hi, i am student from malaysia, i am new in r programming field, now i am
trying to conduct a robustness study on 2 sample test under several combination
of factors such as sample sizes ,standard deviation ratio and also
distribution..
but now i am
Hello,
I have some code which was running in interactive mode while Rprof(...,
line.profiling = TRUE). Near the end of my script, it opens up a
pipe(..., open = "w") to a perl script, and at that point the execution
gets stuck using 100% cpu.
(The perl script itself never showed up in
Hi again,
I'm looking for some clarification on 2 things.
1. On that last note, I realize that s(x1,x2) would be the other obvious
interaction to compare with - and I see that you recommend te(x1,x2) if
they are not on the same scale.
2. If s(x1,by=x1) gives you a "parameter" value similar to a
On 5/11/2016 2:23 PM, Jan Kacaba wrote:
Here is my attempt at function which computes margins from positions.
require("stringr")
require("dplyr")
ends<-seq(10,100,8) # end margins
test_string<-"Lorem ipsum dolor sit amet, consectetuer adipiscing
elit. Aliquam in lorem sit amet leo accumsan
Hi again,
Sorry, that should be:
chop_string<-function(x,ends) {
starts<-c(1,ends[-length(ends)]+1)
return(substring(x,starts,ends))
}
Jim
On Thu, May 12, 2016 at 10:05 AM, Jim Lemon wrote:
> Hi Jan,
> This might be helpful:
>
> chop_string<-function(x,ends) {
>
Hi Jan,
This might be helpful:
chop_string<-function(x,ends) {
starts<-c(1,ends[-length(ends)]-1)
return(substring(x,starts,ends))
}
Jim
On Thu, May 12, 2016 at 7:23 AM, Jan Kacaba wrote:
> Here is my attempt at function which computes margins from positions.
>
>
Here is my attempt at function which computes margins from positions.
require("stringr")
require("dplyr")
ends<-seq(10,100,8) # end margins
test_string<-"Lorem ipsum dolor sit amet, consectetuer adipiscing
elit. Aliquam in lorem sit amet leo accumsan lacinia."
sekoj=function(ends){
Dunno -- but you might have a look at Hadley Wickham's 'stringr' package:
https://cran.r-project.org/web/packages/stringr/stringr.pdf
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in
Dear R-help
I would like to split long string at specified precomputed positions.
'substring' needs beginings and ends. Is there a native function which
accepts positions so I don't have to count second argument?
For example I have vector of possitions pos<-c(5,10,19). Substring
needs input
Sounds like it would be helpful to find out exactly which process is
holding on to the file in order to figure out what's going on. From a
quick look, it seems that
http://superuser.com/questions/117902/find-out-which-process-is-locking-a-file-or-folder-in-windows
gives some useful info on
I upgraded ffox to the 46-series and intermittently received the same
error. But by adding a `Sys.sleep(1)` to the final `if`:
if ((i %% 10) == 0) {
ref <- remDr$findElements("xpath", ".//a[.='...']")
ref[[length(ref)]]$clickElement()
Sys.sleep(1)
}
I was able to reproduce my
Hey David,
I'm on a Mac as well but have never had to tweak anything to get
[R]Selenium to work (but this is one reason I try to avoid solutions
involving RSelenium as they are pretty fragile IMO).
The site itself has "Página 1 de 69" at the top which is where i got
the "69" from and I just
> On May 10, 2016, at 1:11 PM, boB Rudis wrote:
>
> Unfortunately, it's a wretched, vile, SharePoint-based site. That
> means it doesn't use traditional encoding methods to do the pagination
> and one of the only ways to do this effectively is going to be to use
> RSelenium:
>
Hi Simon, Thanks for this explanation.
To make sure I understand, another way of explaining the y axis in my
original example is that it is the contribution to snowdepth relative to
the other variables (the example only had fsca, but my actual case has a
couple others). i.e. a negative s(fsca) of
Duncan,
thanks for the hint.
I have done it correctly in R fashion
## capture all the output to a file.
zz <- file("C:/Temp/all.Rout", open = "wt")
sink(zz)
sink(zz, type = "message")
try(log("a"))
## back to the console
sink(type = "message")
sink()
unlink("C:/Temp/all.Rout")
But the error
Hi Sarah,
yes, I followed your suggestion.
If I do exactly what is in the example of the documentation:
sink("C:/Temp/sink-examp.txt")
i <- 1:10
outer(i, i, "*")
sink()
unlink("C:/Temp/sink-examp.txt")
it does not write anything, i. e. no file is created in "C:/Temp/". The
script is executed
Thanks so SO much.
Brennan
www.toxstrategies.com
From: Anthony Damico
Date: Wednesday, May 11, 2016 at 11:17 AM
To: Anne Bichteler
Cc: "r-help@r-project.org"
Subject: Re: [R] Quantiles on multiply imputed survey
hi, you want se=T
M_quantile <- with(des_mult, svyquantile(make.formula(get('var_name')),
quantiles = c(.5),se=T))
MIcombine(M_quantile)
Multiple imputation results:
with(des_mult, svyquantile(make.formula(get("var_name")), quantiles =
c(0.5),
se = T))
Thanks for looking. No, for the quantiles it fails to instantiate the
collection of designs correctly, whether hard-coding the variable name or using
make.formula. 'with' passes make.formula correctly when calculating the mean,
e.g. this works:
MIcombine( with(des,
Hi Witold,
use do.call()
list.args<-list(...)
#modify 'list.args' (add/delete/modify)
do.call(image, list.args)
best,
vito
Il 11/05/2016 10.45, Witold E Wolski ha scritto:
Hi,
I am looking for a documentation describing how to manipulate the
"..." . Searching R-intro.html gives to many
On 05/11/2016 08:00 AM, ch.elahe via R-help wrote:
Hi all,
I have a plot for TSTMean vs. SNRMean and both of these variables are factors.
How can I use Logistic Regression for factor variables?
Currently I use model=lm(TSTMean~SNRMean,data=df) but when I check
summary(model) I get this error:
On 5/10/2016 4:11 PM, boB Rudis wrote:
> Unfortunately, it's a wretched, vile, SharePoint-based site. That
> means it doesn't use traditional encoding methods to do the pagination
> and one of the only ways to do this effectively is going to be to use
> RSelenium:
>
R-help is not stack exchange,
Hola,
Por si os interesa asistir y podéis asistir:
http://madrid.r-es.org/35-jueves-12-de-mayo-2016/
Gracias,
Carlos Ortega
www.qualityexcellence.es
[[alternative HTML version deleted]]
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Hi all,
I have a plot for TSTMean vs. SNRMean and both of these variables are factors.
How can I use Logistic Regression for factor variables?
Currently I use model=lm(TSTMean~SNRMean,data=df) but when I check
summary(model) I get this error: r error in quartile.default (resid) factors
are not
Thanks David - my earlier response to Bert contains the resolution.
partialPlot was commented out deliberately as it was the target function
who's behaviour I was replicating in testFunc. The original behaviour, ie.
printing 'X1' was correct, and the do.call fix yields this same response
when
On 11/05/2016 4:45 AM, Witold E Wolski wrote:
Hi,
I am looking for a documentation describing how to manipulate the
"..." . Searching R-intro.html gives to many not relevant hits for
"..."
What I want to do is something like this :
image.2 <- function(x, col , ...){
# function is
I have achieved this use case by writing the following commands:
all_predictions <- data.frame(pid = testPFI$project_id, actual_delay =
testPFI$project_delay,lm_pred, tree_pred, best_tree_pred, rf_pred)
str(all_predictions)
all_pred <- sqldf("SELECT pid, actual_delay, ROUND(lm_pred,2) lm_pred,
Hi Witold,
You could try Ben Bolker's "clean.args" function in the plotrix package.
Jim
On Wed, May 11, 2016 at 6:45 PM, Witold E Wolski wrote:
> Hi,
>
> I am looking for a documentation describing how to manipulate the
> "..." . Searching R-intro.html gives to many not
The spline having a positive value is not the same as a glm coefficient
having a positive value. When you plot a smooth, say s(x), that is
equivalent to plotting the line 'beta * x' in a GLM. It is not
equivalent to plotting 'beta'. The smooths in a gam are (usually)
subject to `sum-to-zero'
Hola,
En la anterior reunión del "Grupo de Usuarios de R de Madrid", Miguel Ángel
Gómez hizo una presentación sobre análisis de sentimiento en noticias
financieras y dio varias referencias de lo que buscas, además de que su
código lo compartió.
El detalle lo puedes ver aquí:
Tiene buenas pintas...
Yo tengo un paquete casero para generar y mostrar resultados de estudios
de simulación (en formato html) y esto parece que me puede ir bien.
Gracias por la información.
Un saludo, Rubén.
El 10/05/2016 a las 22:13, Javier Marcuzzi escribió:
En LinkedIn aparece esto
Hi,
I am looking for a documentation describing how to manipulate the
"..." . Searching R-intro.html gives to many not relevant hits for
"..."
What I want to do is something like this :
image.2 <- function(x, col , ...){
# function is manipulating colors (adding a few)
# since it changes
> On May 10, 2016, at 5:30 PM, Dominik Schneider
> wrote:
>
> Hi,
> Just getting into using GAM using the mgcv package. I've generated some
> models and extracted the splines for each of the variables and started
> visualizing them. I'm noticing that one of my
> On May 9, 2016, at 2:39 PM, Andrew Clancy wrote:
>
> Hi,
>
> I’m trying to solve what looks like the same issue as stack overflow article,
> but within an lapply:
> http://stackoverflow.com/questions/18939254/cant-use-a-variable-as-an-argument-but-can-use-its-value
It
Hi,
Just getting into using GAM using the mgcv package. I've generated some
models and extracted the splines for each of the variables and started
visualizing them. I'm noticing that one of my variables is physically
unrealistic.
In the example below, my interpretation of the following plot is
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