Thank you Jim, it worked. I am very grateful for your help.
Thanks
KG
On Tue, Sep 11, 2018 at 3:51 PM Jim Lemon wrote:
> Hi Kristi,
> My fault, I only worked out how to assign the values to the names and pick
> out the columns of daT for the calculations. I think this does what you
> want, but
Hi,
I'm not that well versed with R - I'm trying to correct the dates of
service in a de-identified research medical record of several subjects.
The correct dates come from a csv file, in the VisitDate column, that
looks like this in Excel. The empty cells have other data in them that
I
On Tue, 11 Sep 2018, Bert Gunter wrote:
You do that. Your error is obvious.
Bert,
Yep. Forgot to remove the 'p' from the type attribute.
Mea culpa!
Rich
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You do that. Your error is obvious.
-- Bert
On Tue, Sep 11, 2018 at 5:39 PM Rich Shepard wrote:
>
> On Tue, 11 Sep 2018, Bert Gunter wrote:
>
> > As I thought, you did not do what I told you to.
> > Look *carefully* at the two to see your error.
>
> Bert,
>
>You're correct, of course. After
On Tue, 11 Sep 2018, Bert Gunter wrote:
As I thought, you did not do what I told you to.
Look *carefully* at the two to see your error.
Bert,
You're correct, of course. After moving the tck parameter in front of the
x list the right-side ticks are gone. Unfortunately, so are the data: the
As I thought, you did not do what I told you to.
Look *carefully* at the two to see your error.
-- Bert
On Tue, Sep 11, 2018 at 5:01 PM Rich Shepard wrote:
>
> On Tue, 11 Sep 2018, Bert Gunter wrote:
>
> > Not when I run your code with the tck specification added. Show us
> > your xyplot
On Tue, 11 Sep 2018, Bert Gunter wrote:
Not when I run your code with the tck specification added. Show us
your xyplot invocation. It should be
scales = list(tck = c(1,0), x= etc.)
Bert,
Command:
rain.all.sum <- xyplot(Sum ~ Month, data=agg.all, col = 'black', type = 'h',
agnes (cluster)
Jim
On Wed, Sep 12, 2018 at 8:10 AM Bryan Mac wrote:
>
>
> Bryan Mac
> Data Scientist
> Research Analytics
> Ipsos Insight LLC
>
>
>
>
>
> [[alternative HTML version deleted]]
>
> __
> R-help@r-project.org mailing list -- To
??
Not when I run your code with the tck specification added. Show us
your xyplot invocation. It should be
scales = list(tck = c(1,0), x= etc.)
Bert
On Tue, Sep 11, 2018 at 3:51 PM Rich Shepard wrote:
>
> On Tue, 11 Sep 2018, Bert Gunter wrote:
>
> > Adding
> > tck = c(1, 0)
> > to the "scales
Hi Abou,
Surprisingly you can't omit the x axis in dotchart. This hack will work:
sink("dotchar_noax.R")
sink()
Edit the resulting file by joining the first two lines with the
assignment symbol (<-), delete the two lines at the bottom and comment
out the line "axis(1)".
Hi Sonam,
You're right. Although the cex.axis argument is present, it doesn't
seem to be used. I will have to debug this, which may take a day or
two.
Jim
On Tue, Sep 11, 2018 at 6:37 PM Sonam Sandeep Dash
wrote:
>
> Respected Sir,
> I have created a Taylor plot using the plotrix package.
Hi Kristi,
My fault, I only worked out how to assign the values to the names and pick
out the columns of daT for the calculations. I think this does what you
want, but I can't guarantee the result.
daT<-structure(list(year1=c(0.417,0.538,0.69,0.688,0.688,0.606,
On Tue, 11 Sep 2018, Bert Gunter wrote:
Adding
tck = c(1, 0)
to the "scales =" list will probably solve your problem.
Bert,
How interesting. This removed the tick marks on top but left them on the
right axes. Will think more about this.
Regards,
Rich
Have a look at the Polychrome package by Kevin Coombes and Guy Brock:
https://CRAN.R-project.org/package=Polychrome
This employs the LUV space (with HCL = polar LUV) to get many distinct
distinguishable colors. For a few first steps, see:
On Tue, 11 Sep 2018, Bert Gunter wrote:
Well, you might try ?xyplot -- in particular the "scales" list section
and in particular there the "tck" parameter. Adding
tck = c(1, 0)
to the "scales =" list will probably solve your problem.
Bert,
I missed the end of the tck description in the
Hi Federico
For a possible alternative, the scico package provides a nice
collection of color palettes that are designed to be both color-blind
friendly and differentiable:
https://www.data-imaginist.com/2018/scico-and-the-colour-conundrum/
You could generate a vector of 21 colors (spaced as
Well, you might try ?xyplot -- in particular the "scales" list section
and in particular there the "tck" parameter. Adding
tck = c(1, 0)
to the "scales =" list will probably solve your problem.
-- Bert
On Tue, Sep 11, 2018 at 2:46 PM Rich Shepard wrote:
>
>Every lattice xyplot() I've
Bryan Mac
Data Scientist
Research Analytics
Ipsos Insight LLC
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
Every lattice xyplot() I've created before this one has tick marks on only
the left and bottom axes. The current plot has sprouted tick marks on the
top and right side, too, and I want to remove them. I've not found an answer
to this issue in Deepayan's book or on the web. I would appreciate
Dear All:
One more thing. I want to Remove the plot x-axis values in dotplot graph. I
am trying to use xaxt = "n", but it seems NOT working. Also after removing
the x-axis values, I want to use the command axis(1, at=0:16, cex.axis=1)
to add x-axis values from 0 to 16, but it seems not working as
Dear Rui:
thank you very much
abou
__
*AbouEl-Makarim Aboueissa, PhD*
*Professor of Statistics*
*Graduate Coordinator*
*Department of Mathematics and Statistics*
*University of Southern Maine*
On Tue, Sep 11, 2018 at 2:24 PM Rui Barradas wrote:
> Hello,
>
> Use
Dear Bert:
thank you very much
abou
__
*AbouEl-Makarim Aboueissa, PhD*
*Professor of Statistics*
*Graduate Coordinator*
*Department of Mathematics and Statistics*
*University of Southern Maine*
On Tue, Sep 11, 2018 at 2:47 PM Bert Gunter wrote:
> Not quite -- he
You could also take a look at the 'Polychrome' package
Paul
On 12/09/18 03:36, Barry Rowlingson wrote:
On Tue, Sep 11, 2018 at 11:43 AM, Duncan Murdoch
wrote:
On 11/09/2018 3:34 AM, Federico Calboli wrote:
Hi All,
I am plotting a scatterplot of 21 populations, and I am using
Not quite -- he wanted the frequencies not the counts. So something
like this (using the adj argument to center the frequencies above each
bar:
bp <-barplot(Number.of.Death, names.arg=Cause.of.Death, main="Bar
Graph for Death Data", ylab="Number of Deaths", xlab="Cause of Death",
ylim = c(0,500)
Hello,
Use function text() with the return of barplot() as x value and
Number.of.Death as y.
Note that the limits of the y axis are not the automatic ones.
bp <- barplot(Number.of.Death, names.arg=Cause.of.Death, main="Bar Graph for
Death Data", ylab="Number of Death", xlab="Cause of
Dear All:
I do need your help on how to add frequency to bar plot on the top of each
bar.
here is the R code.
*Number.of.Death <- c(432, 217,93, 34, 224)# Number of Death*
*Cause.of.Death <- c("Heart disease", "Cancer", "Stroke", "Accidents",
"Other") *
*barplot(Number.of.Death,
On Tue, Sep 11, 2018 at 11:43 AM, Duncan Murdoch
wrote:
> On 11/09/2018 3:34 AM, Federico Calboli wrote:
> > Hi All,
> >
> > I am plotting a scatterplot of 21 populations, and I am using
> rainbow(21)[pops.col] to generate 21 colours for the plot (which works).
> Maybe it is because I can really
Just for fun, there are ways to do this in R without an explicit loop:
> set.seed(42)
> dat <- matrix(rnorm(10*5), 10, 5)
> x <- sample(1:5)
> y <- sample(1:5)
> diag(cor(dat[, x], dat[, y]))
[1] -0.69156568 -0.06002371 -0.37492894 0.46477742 -0.37972866
You can use as.list() to convert the
Dear Jim,
Thank you very much for the code. I run it but it gave me row names like
"year224", "year142".
are these the difference between columns? If we want to get bootstrapping means
of difference between years (year2-year1; year3-year1), its CI and exact p
value, how can we get it?
thanks
Dear R Help Team.
I get some weird results when I use the lm function with weight. The issue
can be reproduced by the example below:
The input data is (weights are intentionally designed to reflect some
structures in the data)
> df
y x weight
1.51156139 0.55209240 2.117337e-34
-0.63653132
On 11/09/2018 3:34 AM, Federico Calboli wrote:
Hi All,
I am plotting a scatterplot of 21 populations, and I am using
rainbow(21)[pops.col] to generate 21 colours for the plot (which works). Maybe
it is because I can really process few colours at a time, but the differences
between the
On Tue, 11 Sep 2018 07:34:51 +
Federico Calboli wrote:
> Is there a way of getting a set of 21 colours that maximises the
> differences between them?
In my limited experience, getting even 10 colours to look different
enough is a serious undertaking. Take a look at RColorBrewer:
You could look at combning a number of palettes from the RColorBrewer package
to get the palette length you want.
S Ellison
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Federico
> Calboli
> Sent: 11 September 2018 08:35
> To:
Hi All,
I am plotting a scatterplot of 21 populations, and I am using
rainbow(21)[pops.col] to generate 21 colours for the plot (which works). Maybe
it is because I can really process few colours at a time, but the differences
between the colours are not as strong as I’d like. I can specify
Hi Kristy,
Try this:
colname.mat<-combn(paste0("year",1:4),2)
samplenames<-apply(colname.mat,2,paste,collapse="")
k<-1
for(column in 1:ncol(colname.mat)) {
assign(samplenames[column],replicate(k,sample(unlist(daT[,colname.mat[,column]]),3,TRUE)))
}
Then use get(samplenames[1]) and so on to
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