> I was looking at this example which uses geom_contour():
>
> ggvolcano = volcano %>%
> reshape2::melt() %>%
> ggplot() +
> geom_tile(aes(x=Var1,y=Var2,fill=value)) +
> geom_contour(aes(x=Var1,y=Var2,z=value),color="black") +
> scale_x_continuous("X",expand = c(0,0)) +
>
Thanks to all for educating me about procedures and argument. Those were
very helpful!!
On 2020/9/21 上午 12:26, Bert Gunter wrote:
> Argument passing is fundamental, even more so when you write your own
> functions, which any half-serious R user will want to do. What has
> heretofore been
On 09/19/2020 04:33 PM, Abby Spurdle wrote:
>> Understood
> I'd recommend you try to be more precise.
>
>> I just began looking at the volcano dataset which uses geom_contour.
> The volcano dataset does *not* use geom_contour.
> However, the help file for the volcano dataset, does use the
>
Al parecer sólo hay que eliminar los espacios, no ?
On 20-09-20 13:32, Carlos Ortega wrote:
Hola,
Extraer los tres primeros caracteres de cada cadena se puede hacer así:
library(stringr)
mis_str <-
Hola:
Varias posibilidades serían:
DATAFRAME$variable_nueva <- 1:nrow(DATAFRAME)
DATAFRAME$variable_nueva <- row.names(DATAFRAME)
o
DATAFRAME$variable_nueva <- as.numeric(row.names(DATAFRAME))
dependiendo de tu objetivo final.
Saludos,
Marcelino
El 20/09/2020 a las 18:41, Jesus MARTIN F.
Buenas tardes,
Consulto cómo tomar el ID (número de orden de las filas) de un DATAFRAME
y hacer un "mutate" a una variable nueva que contenga ese valor (número de
orden de la fila),
Gracias
Jesús
_
*Jesús MARTÍN FRADE *
Skype:jmfpas
Tel (celular):
Hola,
Extraer los tres primeros caracteres de cada cadena se puede hacer así:
> library(stringr)
>
> mis_str <-
c('1.3ptd','1.3ptdm','4.4ptdm23j','7.716s','1.4hola','1.4hola.hola','5.5v6','5.5v6sdp','5.5v10sdp')
>
> res_out <- vector()
> for(i in 1:length(mis_str)) {
+ wrd_tmp <- mis_str[i]
+
Argument passing is fundamental, even more so when you write your own
functions, which any half-serious R user will want to do. What has
heretofore been discussed in this thread is not the whole story (e.g. there
are ... arguments and functions as binary operators, among other things).
See section
Hi Steven: Rui's detailed explanation was great. The way I think of it is,
if you don't
want to send the variables in with the same order as the formal
arguments, then you
better name them as you send them in.
On Sun, Sep 20, 2020 at 7:23 AM Steven Yen wrote:
> Thanks. So, to be safe,
Hola a tod@s
�alquien sabria como convertir estas frases con expresiones regulares?
1.3ptd -> 1.3 ptd
1.3ptdm -> 1.3 ptdm
4.4ptdm23j -> 4.4 ptdm 23j
7.716s -> 7.7 16s
1.4hola -> 1.4 hola
1.4hola.hola -> 1.4 hola.hola
5.5v6 -> 5.5 v6
5.5v6sdp -> 5.5 v6 sdp
5.5v10sdp -> 5.5 v10 sdp
de forma
Thanks. So, to be safe, always a good idea to give the argument, e.g.,
q=1.96, log.p=FALSE, skipping mean=0 and sd=1 if not needed. Thanks.
pnorm(q=1.96, log.p = FALSE)
On 2020/9/20 下午 06:36, Rui Barradas wrote:
> Hello,
>
> You are making a confusion between
>
> 1. the formal argument log.p
>
Hello,
You are making a confusion between
1. the formal argument log.p
2. the variable log.p
In the function body, log.p is a variable that exists in the function's
frame, not the formal argument of pnorm.
The first and the 3rd calls that follow output the same value.
try(x = 1.2, log.p =
Can someone tell me a proper call to a procedure, in this case, pnorm.
In what follows, I had expected a = b, but they are not equal. What are
wrong with first call and second call? Thank you!
try<-function(x,log.p=FALSE){
a<-pnorm(x,log.p) # first call
b<-pnorm(x,log.p=log.p) # second
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