On Feb 24, 2008, at 9:36 PM, Andre Nathan wrote:
On Sun, 2008-02-24 at 23:26 -0300, Andre Nathan wrote:
gp(1, 2, 10)
[1]1248 16 32 64 128 256 512 1024
Actually,
[1]1248 16 32 64 128 256 512
2^(0:9)
Andre
Haris Skiadas
Department of
I can't resist asking, why would you want to remove the variable
names? If it is for printing purposes, then you can probably work
around it on the printing side, depending on what you want to print.
I can't think of another reason for wanting to remove the column
names altogether.
Haris
Perhaps I am missing the obvious, but can't you simply write a small
function that, given each particle object, returns a string with
the required output format (probably a couple of paste calls with
sep and collapse set), and then use sapply and this function on the
list of particles to
On Feb 12, 2008, at 1:31 PM, [Ricardo Rodriguez] Your XEN ICT Team
wrote:
Sundar Dorai-Raj wrote:
Could it we advisable that cast, melt or whatever function we deal
with
throws an more informative error message when this kind of conflicts
occur? I am guessing this is a pretty frequent
On Feb 12, 2008, at 3:31 PM, Thomas Lumley wrote:
On Tue, 12 Feb 2008, Alistair Gee wrote:
I often want to temporarily modify the options() options, e.g.
a - seq(1001, 1001 + 10) # some wide object
with.options - function(..., expr) {
options0 - options(...)
tryCatch(expr,
JiHO, in case you are not following TextMate's mailing list, you
might want to check out Hans-Jorg Bibiko's work on Rdaemon:
http://article.gmane.org/gmane.editors.textmate.general/24195/
It provides a lot of the terminal functionality within a TextMate
window, uses X11 for the plots, and
On Feb 6, 2008, at 6:23 AM, Neil Shephard wrote:
Charilaos Skiadas-3 wrote:
On Feb 5, 2008, at 10:37 AM, Monica Pisica wrote:
But perhaps I am missing something very obvious?
I thought the task views were located where they are (linked from
the page
that lists packages
On Feb 5, 2008, at 10:37 AM, Monica Pisica wrote:
Hi everybody,
I have to recognize that my post certainly shows my lack of skills
in really navigating the R web page i am surprised that only
one or two persons wrote me about the Task Views - it is what i
was after - although
On Jan 17, 2008, at 9:44 AM, Johannes Graumann wrote:
I really do not know ho to else title this ... I want to draw
something like
the attached png with R and would like to poll you on how to
start ... make
an empty plot first and then start positioning the characterstring
by 'text'
And of course let's not forget that a particularly twisted individual
could overwrite =:
`=` - function(x,y) print(x+y)
3 = 4
[1] 7
3 - 4
Error in 3 - 4 : invalid (do_set) left-hand side to assignment
I also was for a while mystified by the - assignment, and preferred
= instead, but
If this is really the case you are dealing with, wouldn't strsplit do
the job more easily?
On Jan 8, 2008, at 5:47 PM, Thomas Pujol wrote:
I have a text string test.a..34
I wish to extract the text that comes after .. (e.g. 34), and
the text that comes before .. (e.g. test.a).
What
On Jan 6, 2008, at 7:55 PM, dxc13 wrote:
useR's,
I would like to know if there is a way to avoid using FOR loops to
perform
the below calculation.
Consider the following data:
snip
Here, X is a matrix of 3 variables in which each is of size 5 and
XK are
some values that correspond
You might want to consider using the proto package. Otherwise,
functions that end in - have the ability to alter their arguments.
Look at the following (admittedly not very natural) construct:
`fooModifier-` - function( foo, value ) {
foo$bar - bar
}
fooModifier( fooStack[[ 1 ]] ) -
On Jan 3, 2008, at 5:08 PM, Bert Gunter wrote:
Gentlemen:
I'm sorry, I don't see the problem. R's is Lisp (or Scheme)-
inspired, so you
need to think in terms of lists, or equivalently, trees. So what
you seem to
want to do is easily navigate down a tree to modify a node. This is
On Jan 4, 2008, at 12:06 AM, Peter Waltman wrote:
fooStack[[1]] - fooModifier(fooStack[[1]])
I thought of this idea as well, and may go with it, if the Gabor's
environments idea doesn't work
snip
Peter, perhaps it would help if you gave us more context into why
you wanted this done,
On Jan 2, 2008, at 6:05 PM, Talbot Katz wrote:
Hi.
I have a matrix stored in a large, tab-delimited flat file. The
first row contains column names. Because the matrix is symmetric,
the file has lower triangular format, so the second row contains
one number, the third row two
On Dec 30, 2007, at 11:55 AM, Richard Müller wrote:
Oops, I just sent the wrong mail. It should be the following one.
Please
delete my mail from 30.Dez. 17:51
Sorry, but I don't really understand the recommended method using
the tk-Box
tkGetSaveFile.
I wrote the following code:
On Dec 30, 2007, at 12:49 PM, Daniel O'Shea wrote:
I am trying to refer to a variable name in a lm regression where
the variable name is in another variable, but it does seem to
work. Here is an example:
y-rnorm(10)
dat-data.frame(x1=rnorm(10),x2=rnorm(10),x3=rnorm(10))
Hi Aaron,
if I understand your question correctly, you can use the . in the
formula, like so:
dat - data.frame(x=1:10,y=rnorm(10),z=10:1)
lm(x~., data=dat)
The dot there stands for everything not already specified, so in this
case that would be y and z (since x is already on the lhs). You
On Dec 23, 2007, at 9:21 AM, Duncan Murdoch wrote:
On 23/12/2007 9:15 AM, Duncan Murdoch wrote:
On 22/12/2007 5:45 PM, Charilaos Skiadas wrote:
On Dec 22, 2007, at 4:44 PM, Duncan Murdoch wrote:
5) eval then creates the environment where this evaluation
will take place. It does
Hi Derek,
On Dec 23, 2007, at 10:59 PM, dxc13 wrote:
useR's,
I have used expand.grid() several times and like the results it
gives me. I
am now trying something with it that I have not been able to get to
work.
For any n column matrix I would like to run this function on those
n
After many hours of debugging code, I came to the conclusion that I
have a fundamental misunderstanding regarding eval, and hope that
someone here can explain to me, why the following code acts as it does:
foo - function(expr) {
eval(substitute(expr), envir=list(a=5),
On Dec 22, 2007, at 4:44 PM, Duncan Murdoch wrote:
5) eval then creates the environment where this evaluation will
take place. It does that by creating an environment containing
the frame a=5, and with enclosing environment the parent frame
of foo, which is bar's environment.
6) So,
eval.parent(mc)
}
bar2(a)
On Dec 22, 2007 3:30 PM, Charilaos Skiadas [EMAIL PROTECTED] wrote:
After many hours of debugging code, I came to the conclusion that I
have a fundamental misunderstanding regarding eval, and hope that
someone here can explain to me, why the following code acts
To check for NA, use is.na. For instance your second ifelse should read:
ifelse(is.na(Sheet1$Claims),0,Sheet1$Claims))
Converting Sheet1$Claims to character doesn't have the effect you
think it does. NA is still NA, it does not become NA. Try for
instance:
as.character(NA)
as.character(NA)
On Dec 8, 2007, at 1:02 AM, Joe W. Byers wrote:
In a post on R-devel, Prof Ripley add the following comment
| BTW, 1:dim(names)[1] is dangerous: it could be 1:0. That was the
| motivation for seq_len.
I use the dim(names)[1] and dim(x)[2] along with length(x) with
varying
levels of
On top of which, you should expect a setting of mfrow=c(1,2) like you
have to only allow you to put two figures in 1 row and 2 columns.
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
On Nov 29, 2007, at 9:35 AM, Dieter Menne wrote:
cathelf cathelf at hotmail.com
On Nov 28, 2007, at 5:59 PM, Yupu Liang wrote:
Hi,
I'm using boxplot in R to show box-whiskers plots for about 15
categories of data. I'd like to display ALL of the data points--not
just the outliers. Does anyone know if there's a parameter setting
that will accomplish this with boxplot?
Allen,
what is the separator then? Can you give us a minimal example of a
file? Otherwise we can't really help you much I'm afraid.
If you want spaces to count as NA, then you want to set na.strings=
probably, but read.table by default uses spaces to separate
columns, so you will want to
Nice cheatsheet!
Edna, in that cheatsheet you'll find a mention to a package called
url. That's what you want to use.
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College
On Nov 28, 2007, at 12:31 AM, Gabor Grothendieck wrote:
See:
Alexy,
note that negative indices have a different meaning in R, namely
they indicate elements to remove. v[-(1:i)] would mean all but the
elements from 1 to i (make sure i is non-negative first). So if you
want:
All elements up to i: v[1:i]
All elements from i: v[-1:(i-1)]
You
Here's my take on it, don't know if you cared at all about optimizing
the first couple of lines:
data - data.frame(x=rep(c(A,B),5), y=c(NA,NA,rnorm(8)))
means - with(data,ave(y, as.character(x), FUN=function(x) mean(x,
na.rm=TRUE)))
data$y - ifelse(is.na(data$y),means,data$y)
I tend to not
On Nov 16, 2007, at 6:42 PM, Andrew Park wrote:
Hi there,
I would like to find a more efficient way of permuting the rows and
columns of a symmetrical matrix that represents ecological or
actual distances between objects in space. The permutation is of
the type used in a Mantel test.
On Nov 16, 2007, at 8:04 PM, Jiao Yang wrote:
Dear all,
I want to save the p-value from mshapiro.test(mvnormtest). But
mshapiro.test(mvnormtest) gives a list with class htest
containing statistic, p.value, method and data.name as a whole.
Elements of a list are accessed, among other
On Nov 15, 2007, at 9:15 AM, Thomas Frööjd wrote:
Hi
I have three vectors say x, y, z. One of them, x contains observations
on a variable. To x I want to append all observations from y and
remove all from z. For appending c() is easily used
x - c(x,y)
But how do I remove all
I must be missing something. What's wrong with:
combn(set, 2)
or if we must t(combn(set,2)), optionally with a function argument in
the combn call if something is to be done with the pairs?
So if you really wanted the outputs to be AB,AC etc, you would do:
combn(set,2, paste, collapse=)
On Nov 8, 2007, at 5:42 PM, Edith Hodgen wrote:
Hi
[snip]
What I think the problem is (I'm hoping it's not)
—--
I've used odfWeave to do something similar, and was then able to
specify both the infile and the outfile (and so could go something
like
infile
of Mathematics and Computer Science
Hanover College
My off-list reply follows.
On Nov 7, 2007, at 7:35 AM, Charilaos Skiadas wrote:
On Nov 7, 2007, at 2:51 AM, Prof Brian Ripley wrote:
On Tue, 6 Nov 2007, Charilaos Skiadas wrote:
Hello all,
I ran into the following, to me unexpected
Hello all,
I ran into the following, to me unexpected, behavior. I have (for
reasons that don't necessarily pertain to the question at hand, hence
I won't go into them) the need/desire to use an empty string for the
name of a vector entry. Perhaps I did not read ?[ very carefully,
but it
Hi all,
I'm trying to write a plugin for R Commander, following the model of
the TeachingDemos plugin. I am struggling trying to even add items by
editing the menus.txt file. I would welcome any help from anyone who
has messed with it. Essentially the problem I am having is: I
-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Charilaos Skiadas
Sent: Thursday, November 01, 2007 2:53 PM
To: R-help help
Subject: [R] Rcmdr Plugin and menus.txt
Hi all,
I'm trying to write a plugin for R Commander, following the model of
the TeachingDemos
You could simply create your own function, to avoid repeating the
paste part each time:
scriptdir - path.to.scripts
my.source - function(file) {
source(file.path(scriptdir,file))
}
my.source(file.r)
my.source(anotherfile.r)
...
(You'll have to watch out for correct number of slashes
Sorry if this is already answered somewhere, but I could not find it.
I have two vectors, x,y, of different length, and I want to recycle
the smaller one (whichever one it is) until they have the same
length. I was wondering if there is a anything better than something
like:
x-1:3
y-1:10
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