, at 5:19 PM, Peter Ehlers wrote:
Brant,
See below.
On 2010-11-28 12:25, David Winsemius wrote:
Puzzled. Why are the data you offer to predict() for the independent
variable, conc, all NA's? Is there something reversed or inverted
about how drc functions handle formulas.
-- David. On Nov 28, 2010
,,] and
StatTemps[7:1123:34,,] but that didn't work. Any ideas? Thanks so
much!
It may not be an array (since time values don't play very well with
that data structure.) If there is time as an index, it may be a more
complex object such as a time-series or zoo. Check with str().
--
David
do this with few commands??
Possibly depending on the correctness of my assumptions:
xyplot.zoo
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perfect for me.
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values) if
there are any NAs. Wouldn't one expect that the 2 forms (data frame
vs
formula) of aggregate would give the same result?
thanks very much
david freedman, atlanta
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, but was actually adding the
fractional risk to each of the q[1:4]'s before summation occurred.
(Should have been ...
sum(q[1:4] , frac*q[5])
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on my system that it may be Matrix.
showMethods(as.array)
Function: as.array (package base)
x=ANY
x=Matrix
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PLEASE do read
10 ...
- attr(*, dimnames)=List of 3
..$ dim1: chr [1:3] a b c
..$ dim2: chr [1:3] d e f
..$ dim3: chr [1:3] g h i
-
Christian Langkamp
christian.langkamp-at-gmxpro.de
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David
is a bit non-standard:
?do.call
do_this - function(a, fn=, b) {do.call(fn, list(a , b))}
do_this(a=1, b=4)
[1] FALSE
do_this(a=1, b=0)
[1] TRUE
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cumulative mean of a vector, i.e,
c( mean(vec[1]), mean(vec[1:2]), ,,, mean(vec) ):
vec - sample(1:20)
sapply(1:length(vec), function(x) mean(vec[1:x])
So, how to mean/min a list of lists and numbers to return a list?
Not a list and not working on a list of lists. A vector.
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, reproducible code.
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-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
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commented, minimal, self-contained, reproducible code.
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On Jul 12, 2010, at 6:46 PM, David Winsemius wrote:
On Jul 12, 2010, at 6:03 PM, harsh yadav wrote:
Hi,
I have a function in R that compares two very large strings for
about 1
million records.
The strings are very large URLs like:-
http://query.nytimes.com/gst
this is
not a homework assignment!
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) #???
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: David Winsemius dwinsem...@comcast.net
To: Josh B josh...@yahoo.com
Cc: R Help r-help@r-project.org
Sent: Mon, July 12, 2010 8:09:03 PM
Subject: Re: [R] Continuing on with a loop when there's a failure
On Jul 12, 2010, at 6:18 PM, Josh B wrote:
Hi R sages,
Here is my latest problem. Consider
On Jul 13, 2010, at 9:04 AM, David Winsemius wrote:
On Jul 13, 2010, at 8:47 AM, Josh B wrote:
Thanks again, David.
...but, alas, I still can't get it work!
(BTW, it did work.)
Here's what I'm trying now:
for (i in 1:2) {
mod.poly3 - try(lrm(x[,i] ~ pol(x1, 3) + pol(x2, 3), data=x
0.3245
x2^2 -0.94888 0.82067 -1.16 0.2476
x2^3 0.06362 0.05098 1.25 0.2121
...so what exactly would I query to design my if/then statement?
From: David Winsemius dwinsem...@comcast.net
To: David Winsemius dwinsem...@comcast.net
Cc: Josh B josh...@yahoo.com; R Help r-help@r
On Jul 13, 2010, at 10:26 AM, David Winsemius wrote:
On Jul 13, 2010, at 9:24 AM, Josh B wrote:
In my opinion the try and tryCatch commands are written and
documented rather poorly. Thus I am not sure what to program exactly.
Didn't you see the silent parameter? Its seems
commented, minimal, self-contained, reproducible code.
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if/then statement?
From: David Winsemius dwinsem...@comcast.net
To: David Winsemius dwinsem...@comcast.net
Sent: Tue, July 13, 2010 9:09:04 AM
Subject: Re: [R] Continuing on with a loop when there's a failure
On Jul 13, 2010, at 9:04 AM, David Winsemius wrote:
On Jul
://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
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the posting guide http://www.R-project.org/posting-guide.html
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PLEASE do
a
name
worth remembering. --Theodore Roosevelt
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Sunday, July 18, 2010 5:36 AM
To: Joe P King
Cc: r-help@r-project.org
Subject: Re: [R] loop troubles
On Jul 17, 2010, at 9:09 PM, Joe P King wrote:
Hi all, I
of a
row
i.e in my table:
name value_1 value_2
bill 14
ben 2 2
jane 3 1
I click on the data point at 2,2 and it would read out ben
Check out HWidentify or HTKidentify in pkg:TeachingDemos.
-Peter Ehlers
David Winsemius, MD
West Hartford, CT
the
logical vector which seems entirely wasteful or using subset().
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) + pol(x2, 3), data=x)
anova(mod.poly3)[1,3]
[1] 0.6976063
Any ideas?
From: David Winsemius dwinsem...@comcast.net
To: Josh B josh...@yahoo.com
Cc: Peter Konings peter.l.e.koni...@gmail.com; R Help r-help@r-project.org
Sent: Sun, July 18, 2010 3:33:07 PM
Subject: Re: [R] Continuing on with a loop
, the flaw is that R doesn't apply this philosophy
entirely consistently: I think factor and table should default to
exclude = NULL.
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics / Rice University
http://had.co.nz/
David Winsemius, MD
West Hartford, CT
]
sigma[i] = 1/sqrt(pn[i])
mutotals[i,]-mu.out[i]
}
Joe King
206-913-2912
j...@joepking.com
Never throughout history has a man who lived a life of ease left a
name
worth remembering. --Theodore Roosevelt
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent
. It specifies what can be attached and TIFF
files are NOT in the list of acceptable types. Uwe might have gotten a
copy but the rest of us did not.
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On Jul 18, 2010, at 10:09 PM, Seth wrote:
Hi,
What I would like to do is have a data.frame with column names and
have
these column names stored as strings in another vector. Then I
would like
to be able to access the data.fram columns via referencing the
vector of
names. The code
/index.html
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-1.7
And the reason the ,drop=FALSE is needed is that otherwise the
vector and the matrix would have been non-conformable after the column
vector became a row vector.
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David Winsemius, MD
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in teh zoo and an strapply function
in the gsubfn package that might be even more powerful, but I am
insufficiently talented to give you a one-liner using them.
Please advise.
Thank you.
--
--
David Winsemius, MD
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On Jul 19, 2010, at 9:57 PM, Farley, Robert wrote:
I'm plotting some trip length frequencies using the following code:
plot( density(zTestData$Distance, weights=zTestData$Actual),
xlim=c(0,10),
main=Test TLFD,
xlab=Distance,
col=6 )
lines(density(zTestData$Distance,
are the fixed effects
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.
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(or possibly used hte data.frame function) , you are
probably experiencing the effects of the default stringAsFactors=TRUE
behavior. Try setting stringsAsFactors to FALSE. Then you can use the
standard Date functions:
?Dates
--
David Winsemius, MD
West Hartford, CT
On Jul 20, 2010, at 8:41 AM, David Winsemius wrote:
On Jul 20, 2010, at 7:33 AM, Sarah Chisholm wrote:
Hi,
I have a problem with the time formatting in R. I have entered time
in the format MM:SS.xyz and R has automatically classified this
as a factor, but I need it numerically. However
was rather ambiguous) that function is also available.
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On Jul 20, 2010, at 9:25 AM, David Winsemius wrote:
On Jul 20, 2010, at 9:13 AM, Marcus Drescher wrote:
Hi all,
I have a dataframe with survey data. Now I want to calculate means
from several but not all columns (e.g. a1, a2, a3) and save them in
a new separate column (e.g. a).
Well
. You can find the format codes with:
?strptime
print(Sys.time(), format=%m/%d/%Y %H:%M) # your request is
ambiguous w.r.t month and day order
[1] 07/20/2010 09:39 EDT
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) # or Design
for (i in 1:3) {
mod.poly3 - try(lrm(x[,i] ~ pol(x1, 3) + pol(x2, 3), data=x),
silent=TRUE)
if(class(mod.poly3)[1] != 'try-error')
{results[1,i] - anova(mod.poly3)[1,3]}
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On Jul 20, 2010, at 1:14 PM, Heiman, Thomas J. wrote:
Hi Y'all,
I have some data in a table with 2 columns. There are two values:
Reduction and No Reduction. I am trying to make a new variable
change which recode the combinations from column 1 and 2 into a
single number. Here is a
Works on OSX 10.5.8 + R2.11.1
--
David.
On Jul 20, 2010, at 1:36 PM, Henrique Dallazuanna wrote:
I don't know if this works in OSX, but in XP:
plot(0)
title('\u00ae - \u2122')
On Tue, Jul 20, 2010 at 2:22 PM, Dennis Fisher
fis...@plessthan.com wrote:
Colleagues,
What is the easiest
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What does this return?
options()$max.print
# [1] 9 # which is the default
And what does this return?
str(your.data.frame)
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the histogram and then overlay a smooth fitted distribution
curve.
?hist
require(MASS)
?fitdistr
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David.
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Monday, July 19, 2010 19:31
To: Farley, Robert
Cc: r-help@r-project.org
Subject: Re: [R] Constrain
://www.R-project.org/posting-guide.html
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On Jul 20, 2010, at 6:37 PM, H Rao wrote:
Hi,
Is there a function to get the last(or first) day of the week, given
the
week number of the year?
For eg, week number for 7/20 is 29 as obtained by
format(Sys.Date(),%U),
is there a function which returns 7/25 - the last day of week # 29
] NAME SALARY B.SALARY
dim(common)[1]
[1] 13
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.
See also:
?Chisquare
?gamma
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. Consult your instructor for further help.
Say, to compare pairs of cells:
along a column: 3 vs 31, 9 vs 31, 3 vs 9
along a row: 36 vs 9
or even across column and row: 36 vs 31, and 36 vs 3
David Winsemius, MD
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don't use the as.factor I have no problems but I don't think
this is
the correct way to proceed... The other variables I use can have any
value.
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not
changes since the book was published.)
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On Jul 21, 2010, at 12:36 PM, Knut Krueger wrote:
David Winsemius schrieb:
On Jul 21, 2010, at 6:52 AM, Knut Krueger wrote:
Hi to all I found
an formular of an **
***p-Value Calculator for the Chi-Square test*
*http://www.danielsoper.com/statcalc/calc11.aspx*
*with the formula*
http
On Jul 21, 2010, at 1:18 PM, Knut Krueger wrote:
David Winsemius schrieb:
And exactly why did you think I offered
?Chisquare
I was completely on the wrong way, and tried to find a solution with
the formula instead to substitute the formula.
So I tried to implement pchisq
or tryCatch
which might be more specific.
Andrew
--
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in contrMat(table(mf[[nm]]), type = types[pm]) :
less than two groups
Thanks,
Rob
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***
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, Rhelp08, Rhelp02,
functions ),
matchesPerPage = 100, ...)
RSiteSearch(string=string, restrict = restrict,
matchesPerPage = matchesPerPage, ...)
David Winsemius, MD
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in the vars-
vector (running t.test(data1) by hand works).
How can I remove the quotes before performing the test?
a) don't quote them
b) put them in a list
c) print() the results.
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, nor is
it in the argument list for boxplot.default or its bxp function. The
documentation for the ... argument does not suggest, to me anyway,
that main would passed on to other graphical functions.
--
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On Jul 22, 2010, at 5:01 PM, Peter Ehlers wrote:
On 2010-07-22 14:40, David Winsemius wrote:
On Jul 22, 2010, at 4:24 PM, Peter Ehlers wrote:
On 2010-07-22 11:44, Marcus Liu wrote:
Hi everyone, I am plotting a boxplot with main title as main =
bquote(paste(.(ts.ind[s]), : , bar(zeta
commented, minimal, self-contained, reproducible code.
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On Jul 22, 2010, at 5:34 PM, David Winsemius wrote:
On Jul 22, 2010, at 5:27 PM, Daniel Hocking wrote:
I am sorry if this question is vague or uninformed. I am just
learning R and struggling. I am using the book Hierarchical Modeling
and Inference in Ecology and they provide examples of R
:
The dataframe is
id salary
100500
101600
102700
103800
how can i generate a subsets if salary600?
?subset
subset(DF, salary 600)
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-4.698 59.197 -4.5480 57.7830
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, second
is latitude) or a SpatialPoints* object
p2 As above
n The requested number of points on the Great Circle
---
There is also a geospatial Task View and SIG mailing list that is very
active.
--
David
Thank you
Mafalda
On 23 July 2010 13:30, David Winsemius dwinsem...@comcast.net wrote
place to ask such a question. But
I do
not know who to ask,
http://lmgtfy.com/?q=latex+users+group
so just try my
luck here.
Thank you in advance.
Hannah
[[alternative HTML version deleted]]
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-project.org/posting-guide.html
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were 11:59:ss, I want to convert to 12:00:00).
How to achieve this?
Couldn't you just coerce to numeric, divide by 60(sec)*30(half-hour
minutes), round to integer, multiply by 60*30, coerce to POSIXct?
_
David Winsemius, MD
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, cex=1.5)
text(19,4.2, labels=newdata[19], col=black, cex=1.5);text(20,3.55,
labels=newdata[20], col=black, cex=1.5)
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PLEASE do read
On Jul 23, 2010, at 11:35 AM, David Winsemius wrote:
On Jul 23, 2010, at 11:20 AM, murali.me...@avivainvestors.com murali.me...@avivainvestors.com
wrote:
Hi folks,
I've got a POSIXct datum as follows:
Sys.time()
[1] 2010-07-23 11:29:59 BST
I want to convert this to the nearest half
hth
Stephen Sefick
On Fri, Jul 23, 2010 at 11:00 AM, David Winsemius
dwinsem...@comcast.net wrote:
On Jul 23, 2010, at 11:35 AM, David Winsemius wrote:
On Jul 23, 2010, at 11:20 AM, murali.me...@avivainvestors.com
murali.me...@avivainvestors.com wrote:
Hi folks,
I've got a POSIXct
But the structure of my OrigData is exactly the same as of monthly. OK
- OrigData always has a few NAs in Value coming first - but that's
consistent for all brands.
Any idea what might be wrong?
Thanks a lot!
Just in case -attaching the actual file.
No. Not attached.
--
David Winsemius, MD
.
But neither split = 1 nor split =2 work.
And split =Brand does not work either. Why?
D.
On Fri, Jul 23, 2010 at 12:52 PM, David Winsemius
dwinsem...@comcast.net wrote:
?read.zoo
You didn't specify the index column correctly.
On Jul 23, 2010, at 12:36 PM, Dimitri Liakhovitski wrote:
Hello!
I
what was expected, I am not in a position to know
if this is success.
And under warnings() it says:
1: In zoo(rval4[[i]], ix[[i]]) :
some methods for “zoo” objects do not work if the index entries in
‘order.by’ are not unique
On Fri, Jul 23, 2010 at 1:13 PM, David Winsemius dwinsem
, 98L, 95L, 97L, NA, 98L, 97L, 98L,
NA, :
series cannot be merged with non-unique index entries in a series
In addition: There were 11 warnings (use warnings() to see them)
On Fri, Jul 23, 2010 at 1:41 PM, David Winsemius dwinsem...@comcast.net
wrote:
On Jul 23, 2010, at 1:39 PM, Dimitri
with doubled \ but the
second . is a regex for any character.)
gsub(\\..*$,, c(Floodplain1.Tree, Floodplain1.Shrub))
[1] Floodplain1 Floodplain1
Use the same method with assignment to the column:
ZoneCover.df$ID - gsub(\\..*$,, ZoneCover.df$ID)
--
David Winsemius, MD
West Hartford, CT
to minimize (with some constrains) here:
http://analytic-products4you.com/target.txt
Is it possible to import it as a function to minimize?
What is the problem that you are trying to solve?
We solve a problem for parameters estimation with ties.
--
David Winsemius, MD
West Hartford, CT
On Jul 23, 2010, at 9:20 PM, mpw...@illinois.edu wrote:
I have a data frame with a couple million lines and want to retrieve
the largest and second largest values in each row, along with the
label of the column these values are in. For example
row 1
strongest=-11072
secondstrongest=-11707
On Jul 24, 2010, at 4:54 PM, mpw...@illinois.edu wrote:
THANKS, but I have one issue and one question.
For some reason the secondstrongest value for row 3 and 6 are
incorrect (they are the strongest) the remaining 10 are correct??
In my run of Wiley's code I instead get identical values
On Jul 24, 2010, at 8:09 PM, David Winsemius wrote:
On Jul 24, 2010, at 4:54 PM, mpw...@illinois.edu wrote:
THANKS, but I have one issue and one question.
For some reason the secondstrongest value for row 3 and 6 are
incorrect (they are the strongest) the remaining 10 are correct
On Jul 24, 2010, at 9:27 PM, David Winsemius wrote:
On Jul 24, 2010, at 8:09 PM, David Winsemius wrote:
On Jul 24, 2010, at 4:54 PM, mpw...@illinois.edu wrote:
THANKS, but I have one issue and one question.
For some reason the secondstrongest value for row 3 and 6 are
incorrect
of this theory with RSeek pointed to the CrossTable function
in gmodels.)
Try also with...
?RsiteSearch
RSiteSearch()
Or with ...
require(sos)
???proc freq sas
--
David Winsemius, MD
West Hartford, CT
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R-help@r-project.org mailing list
https
On Jul 25, 2010, at 6:31 PM, sh...@ucar.edu wrote:
Hi All-
I would like to create a 3d topographic map using lat/lon and
z(height). I have been scouring the R help pages and have not
located the package I am looking for. Does anyone have a suggestion
of package that will work for
--
David Winsemius, MD
West Hartford, CT
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible
sure someone here can finish the job of
showing you how setting up a call to predict will get you to that goal.
--
David.
Thanks again
David Winsemius wrote:
On Jul 25, 2010, at 10:24 PM, Guillem R. wrote:
Dear all,
I'd like to plot the marginal effect of a variable
numbers. is there a way out?
Best regards,
/Steffen
--
David Winsemius, MD
Heritage Laboratories
West Hartford, CT
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