[R] replaces a matrix of NAs in an array with the previous matrix with numbers

Dear list, Does anyone know if there is a function that replaces a matrix of NAs in an array with the previous matrix with numbers? For example, I have an array ab - array(dim=c(3,3,15),dimnames=list(rows=1:3,cols=1:3,dim=times)) . Select out put from the array is: , , dim = 0.478356969557745

[R] Replace values in a vector

Hi all, I have a vector like this: x- c(0.7, 0.1, 0, 0.2, 0.2, 0, 0, 0 , 0, 0.4, 0, 0.8, 1.8) I would like to replace the zero values with the first previous non zero value. my returning vector should look like this: y-c( 0.7, 0.1, 0.1,0.2,0.2,0.2,0.2,0.2, 0.4, 0.4, 0.8, 1.8) How can I do

Re: [R] Replace values in a vector

)) On Thu, Dec 3, 2009 at 11:41 AM, Farida Mostajabi f0mos...@louisville.eduwrote: Hi all, I have a vector like this: x- c(0.7, 0.1, 0, 0.2, 0.2, 0, 0, 0 , 0, 0.4, 0, 0.8, 1.8) I would like to replace the zero values with the first previous non zero value. my returning vector should look like

Re: [R] Replace values in a vector

Yes, should be 6 0.2. The code worked. Thank you! William Dunlap wdun...@tibco.com 12/03/09 12:07 PM -Original Message- From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On Behalf Of Farida Mostajabi Sent: Thursday, December 03, 2009 8:41 AM To: r-help@r

Re: [R] apply a function over a factor

Thanks! That's what I need. On Tue, Dec 29, 2009 at 1:33 PM, Dimitris Rizopoulos d.rizopou...@erasmusmc.nl wrote: have a look at ?ave(), e.g., A - 1:10 B - factor(c(1,2,2,4,4,4,7,7,7,7)) ave(A, B) I hope it helps. Best, Dimitris farida...@gmail.com wrote: Dear R experts, I

Re: [R] Removing replicated rows

It worked perfectly. Thank you! On Wed, Dec 30, 2009 at 12:21 PM, Henrique Dallazuanna www...@gmail.comwrote: Try this: unique(x)[rep(1:nrow(unique(x)), m),] On Wed, Dec 30, 2009 at 2:35 PM, farida...@gmail.com wrote: Dear All, I have a matrix like X and need to create a new matrix