Hi there,
When I run the following code, I could get correct objects (with correct
values):
for(i in 1:6) { #-- Create objects 'r.1', 'r.2', ... 'r.6' --
nam - paste(r,i, sep=.)
assign(nam, 1:i)
# save(nam, file = paste(nam, RData, sep = .))
}
I hope to save the object
On 2010-11-19 22:37, Jinsong Zhao wrote:
Hi there,
When I run the following code, I could get correct objects (with correct
values):
for(i in 1:6) { #-- Create objects 'r.1', 'r.2', ... 'r.6' --
nam - paste(r,i, sep=.)
assign(nam, 1:i)
# save(nam, file = paste(nam, RData, sep = .))
}
I hope
On 2010-11-28 19:46, Stephen Liu wrote:
Hi folks,
Which R packages containing sample .xls files? TIA
why do you need .xls format data file?
B.R.
Stephen L
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https://stat.ethz.ch/mailman/listinfo/r-help
Hi there,
I hope to build a model Y ~ X1 + X2 + X3 + X4 with X1 has two
instrumental variable A and B, and X2 has one instrumental variable A. I
have searched the R site and mailling list, and known that the tsls()
from sem package and ivreg() from AER package can deal with instrumental
variable
Hi there,
I just installed R 2.11.1 on my PC, which runs a Windows XP Home.
The installation is successful, however, when I double click on the
R icon, I get the following error message:
R for Windows GUI front-end has encountered a problem and needs to close.
We are sorry for the
On 2010-6-12 5:58, Duncan Murdoch wrote:
Jinsong Zhao wrote:
Hi there,
I just installed R 2.11.1 on my PC, which runs a Windows XP Home.
The installation is successful, however, when I double click on the
R icon, I get the following error message:
R for Windows GUI front-end has encountered
, and it's not what I hope to get. I hope the
Latin character is displayed in Helvetica.
Any suggestions? Thanks in advance!
Regards,
Jinsong
--
Jinsong Zhao, Ph.D.
College of Resources and Environment
Huazhong Agricultural University
Wuhan 430070, P.R. China
E-mail: jsz...@mail.hzau.edu.cn
very much for your suggestion. tikz is a powerful graphic
language, however, I am not familiar with it. Before this question, I
add Chinese character to postscript file by LaTeX with psfrag.
Regards,
Jinsong
--
Jinsong Zhao, Ph.D.
College of Resources and Environment
Huazhong Agricultural
On 2010-6-30 7:06, Paul Murrell wrote:
Hi
On 6/30/2010 2:17 AM, Jinsong Zhao wrote:
Hi there,
I am a Chinese R user. I hope to display Chinese character in a plot,
and than save it in PostScript format. I have read the article titled
Non-Standard Fonts in PostScript and PDF Graphics
On 2010-6-30 16:24, Patrick Connolly wrote:
On Wed, 30-Jun-2010 at 11:06AM +1200, Paul Murrell wrote:
Hi
On 6/30/2010 2:17 AM, Jinsong Zhao wrote:
Hi there,
I am a Chinese R user. I hope to display Chinese character in a plot,
and than save it in PostScript format. I have read the article
, font = 3) # italic
dev.off()
pdf(test_4.pdf, fonts = c(GB1))
plot(1:10)
text(5,4, \u4F60\u597D, family=GB1, font = 4) ## symbol
text(5,5, is 'hello' in Chinese, font = 4) # bold italic
dev.off()
--
Jinsong Zhao, Ph.D.
College of Resources and Environment
Huazhong Agricultural University
Wuhan
options in pdf(). But I do not have the ability to give a solution.
Regards,
Jinsong
On 2010-7-1 7:14, Jinsong Zhao wrote:
Hi there,
According to ?par, 'font' is an integer which specifies which font to
use for text, that 1 corresponds to plain text (the default), 2 to bold
face, 3 to italic and 4
On 2010-7-1 12:16, Jinsong Zhao wrote:
Hi there,
The following code can produce the correct type face, however, the Latin
character are displayed in GB1 font.
pdf(test_1.pdf, family = c(GB1))
plot(1:10)
text(5,1, \u4F60\u597D, font = 1)
text(5,2, \u4F60\u597D, font = 2)
text(5,3, \u4F60\u597D
On 2010-7-1 15:24, Jinsong Zhao wrote:
Read the source again more carefully. I think I get the solution:
Change the following line in PDFfontNumber function in devPS.c:
num = 1000 + (cidfontIndex - 1)*5 + 1 + face;
to
num = 1000 + (cidfontIndex - 1)*5 + face;
It appears two times
Hi there,
When I do bootstrap on a maximum likelihood estimation, I try the
following code, however, I get error:
Error in minuslogl(alpha = 0, beta = 0) : object x not found
It seems that mle() only get data from workspace, other than the
boot.fun().
My question is how to pass the data to
Hi there,
I use boot() to do bootstrap simulation on my statistic, I get a boot
object, named obj. For certain reasons, there are some NaN in obj$t.
Now, I hope to get confidence interval using boot.ci(), it give the
following error:
Error in if (const(t, min(1e-08, mean(t)/1e+06))) { :
Neil Shephard wrote:
Jinsong Zhao wrote:
Hi there,
I hope to draw a plot like this:
http://www.sg-chem.net/swizard/Ru-bqdi-spectra.gif
is it possible to draw it using R?
thanks for any suggestions.
My intuition would say yes it is possible as R graphics are highly flexible.
I'm afraid I
Hi there,
I hope to draw a plot like this:
http://www.sg-chem.net/swizard/Ru-bqdi-spectra.gif
is it possible to draw it using R?
thanks for any suggestions.
regards,
Jinsong
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R-help@r-project.org mailing list
will give the
following error message:
Error in optim(start, f, method = method, hessian = TRUE, ...) :
non-finite finite-difference value [3]
~~~or [1] when beta set to 5.
What's wrong? And how to improve the above code?
Thanks in advance!
Jinsong Zhao
Hi,
When I run the following code,
r - c(3,4,4,3,5,4,5,9,8,11,12,13)
n - rep(15,12)
x - c(0, 1.1, 1.3, 2.0, 2.2, 2.8, 3.7, 3.9, 4.4, 4.8, 5.9, 6.8)
x - log10(x)
fr - function(c, alpha, beta) {
P - c + (1-c) * pnorm(alpha + beta * x)
P - pmax(pmin(P,1),0)
-(sum(log(choose(n,r))) + sum(r *
Another question related with the same code:
r - c(3,4,4,3,5,4,5,9,8,11,12,13)
n - rep(15,12)
x - c(0, 1.1, 1.3, 2.0, 2.2, 2.8, 3.7, 3.9, 4.4, 4.8, 5.9, 6.8)
x - log10(x)
fr - function(c, alpha, beta) {
P - c + (1-c) * pnorm(alpha + beta * x)
P - pmax(pmin(P,1),0)
-(sum(log(choose(n,r)))
Hi,
Is there a function to do principal factor analysis in R?
I am reading through ``A user's guide to principal components'' by J. E.
Jackson. In Table 17.1, a comparison between principal components and
common factors, and there is obvious difference between them. However, I
don't know how to
Hi,
Is there a package that could do response surface analysis equivalent to
SAS RSREG procedure? Thanks!
Regards,
Jinsong
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PLEASE do read the posting guide
Hi
I have a data frame, including x1, x2, x3, and y. I use lm() to fit
second-order linear model, like the following:
ft - lm(y ~ x1 + x2 + x3 + I(x1 * x1) + I(x1 * x2) + I(x1 * x3) + I(x2
* x2) + I(x2 * x3) + I(x3 * x3), mydata)
if the independent variable number is large, the formula will be
Tom La Bone wrote:
There appears to be a very promising response surface package being discussed
at useR-2008, but I have been unable to find the package on CRAN or contact
the authors.
www.statistik.uni-dortmund.de/useR-2008/abstracts/Sztendur+Diamond.pdf
Tom
Thanks for pointing me to
Hi there,
I try to plot visible light spectrum (380nm~780nm) with color
corresponding to the specific wavelength. However, I don't find a
function that could do this.
Another question, it's possible to plot a color space chromaticity
diagram like this:
Hi,
For a good discussion of the link between colour and spectra I would
suggest,
http://www.fourmilab.ch/documents/specrend/
which provides an open-source C code to perform the conversion you ask
for. I asked for some advice on how to wrap a R function around this
code last week but
if you don't mind about the efficiency of your program, just use ?
sapply on a range of wavelengths. I'm not particularly keen on the
implementation of the FORTRAN program you used compared to the one I
suggested, it seems like a very crude convolution.
Thank you very much for your
Thanks for pointing this out, i did check the available packages before
dwelling on this but i was focussed on the first part of the problem
(spectrum to xyz).
The available convertColor() function is especially welcome that it was
the most inefficient part of the code I produced yesterday.
Hi there,
I hope to use a string as an input in my function, however, I don't want
to input the quotation mark. Is it possible?
Thanks in advance.
Regards,
Jinsong
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Hi there,
I hope to use a string as an input in my function, however, I don't want
to input the quotation mark. Is it possible?
Thanks in advance.
Regards,
Jinsong
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https://stat.ethz.ch/mailman/listinfo/r-help
Wow, you are so lazy... But sometimes R is just designed for lazy guys...
##
f = function(a) {
s = substitute(a)
as.character(s)
}
##
f(a = asdf)
[1] asdf
f(qwer)
[1] qwer
Regards,
Yihui
--
Yihui Xie [EMAIL PROTECTED]
Phone: +86-(0)10-82509086 Fax: +86-(0)10-82509086
Mobile:
Hi there,
I had a problem when I hoped to get confidence intervals for the
parameters I got using mle() of stats4 package. This problem would not
appear if ``fixed'' option was not used. The following mini-example will
demo the problem:
x - c(100, 56, 32, 18, 10, 1)
r - c(18, 17, 10, 6, 4,
Thank you very much.
now, i call
mle(minuslogl=loglik, start=start, method - method, fixed=list())
in the mle.wrap() function, and the profile.mle() worked.
however, it created a variable named method in user workspace. if
there had been a variable with same name, then the value of that
Hi there,
With the helps from this list, I can set specific CJK fonts for
character string using text() function. for example:
song - CIDFont(SimSun, GBK-EUC-H, GBK, )
postscriptFonts(song = song)
postscript(test.ps, height = 7, width =7, family = Times, fonts =
c(song), horizontal =
On 2012-3-3 23:15, Bogaso Christofer wrote:
Dear all, I have been given a data something like below:
Dat = 2 3 28.3 3.05 8 3 3 22.5 1.55 0 1 1 26.0 2.30 9 3 3 24.8 2.10 0
3 3 26.0 2.60 4 2 3 23.8 2.10 0 3 2 24.7 1.90 0 2 1 23.7 1.95 0
3 3 25.6 2.15 0 3 3 24.3 2.15 0 2 3 25.8 2.65 0 2 3 28.2
Hi there,
I hope to give a different offset for each label in a complex plot.
However, the following code does not work.
plot(1:4)
text(c(1:4), letters[1:4], pos = c(4,3,2,1), offset=c(1,2,3,4))
it seems that text() only use the first element of c(1,2,3,4), i.e., 1.
Is it possible to
On 2012-03-30 5:34, Uwe Ligges wrote:
On 29.03.2012 07:38, Jinsong Zhao wrote:
Hi there,
I hope to give a different offset for each label in a complex plot.
However, the following code does not work.
plot(1:4)
text(c(1:4), letters[1:4], pos = c(4,3,2,1), offset=c(1,2,3,4))
it seems
Hi there,
Is there a function that can do a Fisher's LSD multiple comparisons in a
two-way ANOVA? I hope to get a result similar with TukeyHSD().
Especially, I hope to know the significance of comparisons between the
interactions of two factors.
In the following example:
x - c(76, 84, 78,
On 2012-04-03 20:03, Rmh wrote:
yes. See ?glht in the multcomp package, and the examples using glht in ?MMC in
the HH package.
Sent from my iPhone
Thank you very much for the clues. However, I can't figure out how to
construct the linfct in glht.
I also tried to inverse the computation
On 2012-04-05 10:49, Richard M. Heiberger wrote:
Here is your example. The table you displayed in gigawiz ignored the
two-way factor structure
and interpreted the data as a single factor with 6 levels. I created
the interaction of
a and b to get that behavior.
## your example, with data stored
Hi there,
In function, it's usually using ``='' to assign default value for
function argument. For newbie, it's possible to using ``- '' to assign
value for function argument. Although it's not a correct way, R don't
give any warning message.
matrix(1:20, ncol - 4)
[,1] [,2] [,3] [,4]
2.3523724
b 23.627448 1.9804026
c 13.00 0.1107073
Loglikelihood: -62.41994 AIC: 130.8399 BIC: 133.8271
Correlation matrix:
a b c
a 1. -0.14537297 -0.01203898
b -0.14537297 1. -0.01439500
c -0.01203898 -0.01439500 1.
HTH ...
Jinsong
Hi there,
In SPSS, small piece of data can be input as following:
DATA LIST LIST /x1 x2 x3 x4 x5 .
BEGIN DATA
5700 12.8 2500 270 25000
1000 10.9 600 10 1
3400 8.8 1000 10 9000
3800 13.6 1700 140 25000
4000 12.8 1600 140 25000
8200 8.3 2600 60 12000
1200 11.4 400
Hi there,
Is it possible to set different font family for strings in mtext or text?
For example, on windows platform with windows() device:
plot(1:10, type = n)
text(5,5, Chinese (English)) #Chinese for Chinese characters
it will give the correct Chinese and English characters with two
Thank you very much for the quick reply.
On 2011-10-26 18:24, Prof Brian Ripley wrote:
See ?par: check the 'family' paramater.
You can select 'family' for each call to mtext or text.
Yes, I can select 'family' for each call to mtext or text. however, when
it's necessary to put both Chinese
Hi there,
I have read the help page of nls(), there is lower or upper for defining
the bounds of parameters. For example,
nls(y ~ 1-a*exp(-k1*x)-(1-a)*exp(-k2*x), data=data.1, start=list(a=0.02,
k1=0.01, k2=0.0004), upper=c(1,1,1), lower=c(0,0,0))
I hope to define k1 k2, but I don't find
Hi there,
I have a experimental design as following:
P A B Y
1 1 1 1 -0.18524045
2 1 1 2 -1.64226232
3 2 2 1 -0.51342697
4 2 2 2 -0.29684874
5 3 3 1 0.71566733
6 3 3 2 -1.06097480
7 4 4 1 0.05772670
8 4 4 2 0.99316677
9 5 1 1 -0.61860414
10 5 1 2 0.50257548
Hi there,
The following data is obtained from a long-term experiments.
mydata - read.table(textConnection(
+y year Trt
+ 9.37 1993 A
+ 8.21 1995 A
+ 8.11 1999 A
+ 7.22 2007 A
+ 7.81 2010 A
+10.85 1993 B
+12.83 1995 B
+13.21 1999 B
+
Hi there,
I hope to modify values in a vector or matrix in the following code:
for (i in 1:9) {
assign(paste(a., i, sep = ), 1:i)
get(paste(a., i, sep = ))[i] - i+50
}
I get the following error message:
Error in get(paste(a., i, sep = ))[i] - i + 50 :
target of assignment expands to
On 2011-12-12 0:00, David Winsemius wrote:
On Dec 11, 2011, at 10:27 AM, Jinsong Zhao wrote:
Hi there,
I hope to modify values in a vector or matrix in the following code:
for (i in 1:9) {
assign(paste(a., i, sep = ), 1:i)
get(paste(a., i, sep = ))[i] - i+50
}
Just one matrix? Then you
(a., i, sep = ))[i] - i+50
to
assign(get(paste(a., i, sep = ))[i], i+50)
however, error message:
Error in assign(get(paste(a., i, sep = ))[i], i + 50) :
invalid first argument
I don't know why...
Regards,
Jinsong
On 11/12/2011 15:27, Jinsong Zhao wrote:
Hi there,
I hope to modify values
On 2011-12-12 10:58, David Winsemius wrote:
On Dec 11, 2011, at 9:07 PM, Jinsong Zhao wrote:
On 2011-12-12 0:00, David Winsemius wrote:
On Dec 11, 2011, at 10:27 AM, Jinsong Zhao wrote:
Hi there,
I hope to modify values in a vector or matrix in the following code:
for (i in 1:9
On 2011-12-11 22:49, Bert Gunter wrote:
Inline below.
-- Bert
Graph the data sensibly to figure out what's going on. Statistical
machinationsand anova tables with P values alone are not sufficient
and can be opaque or misleading.
If you do not know what sensibly is (or even if you do),
(package:HH), TukeyHSD(mydata.aov) can output the correct
results.
Thanks again.
Regards,
Jinsong
Rich
On Sun, Dec 11, 2011 at 7:15 AM, Jinsong Zhao jsz...@yeah.net
mailto:jsz...@yeah.net wrote:
Hi there,
The following data is obtained from a long-term experiments.
mydata
Thank you very much for the suggestions.
On 2011-12-13 3:20, Richard M. Heiberger wrote:
...
On Mon, Dec 12, 2011 at 7:00 AM, Jinsong Zhao jsz...@yeah.net
mailto:jsz...@yeah.net wrote:
Apart from the data set here, is there a way to do multiple
comparison on the interaction of one way
On 2012-10-12 10:16, Manish Gupta wrote:
Hi,
I am working on Chinese language plot.
But names and labels are in chinese language. How can i print chineese
characters as lable in R plot.
名称 类 学生
木材 2 2
表 3 4
笔 4 2
垃圾桶 5 6
杯 6
On 2012-10-15 9:40, Manish Gupta wrote:
I just noticed chinese characters are not printed by using this. Some other
characters gets printed on axis as shown below for the sugested solution.
x - read.csv(textConnection(名称,类,学生
木材,2,2
表,3,4
笔,4,2
垃圾桶,5,6
杯,6,3), header = TRUE)
rownames(x) -
Hi there,
In the following example, sd() can be applied to a character vector.
However, mean() can not be run in a similar way. Why?
I have read sd() man page, however, I don't find information about that
behavior.
x - as.character(1:10)
sd(x)
[1] 3.02765
mean(x)
[1] NA
Warning message:
Hi there,
I have the following code:
z - matrix(c(A, A, B, B, C, C, A, B, C), ncol = 3)
apply(z, 2, table, c(A, B, C))
which give correct results.
However, the following code:
apply(z[,1,drop=FALSE], 2, table, c(A, B, C))
which does not give what I expect. I have been thought it should give
On 2013/6/1 15:54, Jie Tang wrote:
hi R-users,
I have a file as shown below,and the first column is time information.
2012-08-07 00:00:00,4174830,5,8.1,34.5,9.5,32,14
2012-08-07 00:00:01,4174831,4.7,8.6,34.5,9.9,29,14
2012-08-07 00:00:02,4174832,4.7,8.6,34.5,9.9,29,14
2012-08-07
Hi there,
In the following function:
demo.plot - function( obj ) plot(1:5, obj, xlab = x)
Then, I use this function as following:
y - rnorm(5)
demo.plot(y)
It will produce a plot with ylab = obj, however, I hope to get a plot
with ylab = y.
Is it possible to convert object/variable name y
Hi there,
I draw a multiple figure in one plot, like the following:
par(mfcol=c(1,5),mar=c(4,4,0,0)+0.2, oma=c(0,0,3,0))
plot(1:10, type = b)
plot(1:10, type = b)
plot(1:10, type = b)
plot(1:10, type = b)
plot(1:10, type = b)
Now, I hope to plot the legend like the following:
legend(top,
, Jinsong Zhao jsz...@yeah.net wrote:
Hi there,
I draw a multiple figure in one plot, like the following:
par(mfcol=c(1,5),mar=c(4,4,0,0)+0.2, oma=c(0,0,3,0))
plot(1:10, type = b)
plot(1:10, type = b)
plot(1:10, type = b)
plot(1:10, type = b)
plot(1:10, type = b)
Now, I hope to plot the legend like
On 2012-08-24 8:58, David Douterlungne wrote:
Hi all,
Is there a R-function that orders Tukey results with conveniant letters,
similar to the SPSS output (A, AB, ABC, C, etc.) .
library(multcompView)
Hi there,
In my code, there is a for loop like the following:
pmatrix - matrix(NA, nrow = 99, ncol = 1)
qmatrix - matrix(NA, nrow = 99, ncol = 3)
paf - seq(0.01, 0.99, 0.01)
for (i in 1:1) {
p.r.1 - rnorm(1000, 1, 0.5)
p.r.2 - rnorm(1000, 2, 1.5)
p.r.3 -
On 2012-08-27 9:35, David Winsemius wrote:
On Aug 26, 2012, at 5:06 PM, Jinsong Zhao wrote:
Hi there,
In my code, there is a for loop like the following:
pmatrix - matrix(NA, nrow = 99, ncol = 1)
qmatrix - matrix(NA, nrow = 99, ncol = 3)
paf - seq(0.01, 0.99, 0.01)
for (i in 1
On 2012-08-27 22:25, David Winsemius wrote:
On Aug 27, 2012, at 1:53 AM, Jinsong Zhao wrote:
On 2012-08-27 9:35, David Winsemius wrote:
On Aug 26, 2012, at 5:06 PM, Jinsong Zhao wrote:
Hi there,
In my code, there is a for loop like the following:
pmatrix - matrix(NA, nrow = 99, ncol
Hi there,
I searched R-help list with path analysis as keyword, and learn that
sem package can do it. However, I don't figure out a way to construct
the model for the path diagram as Fig. 1. in Huang et al. (2002)[1].
I try the following code:
huang.cor - readMoments(diag=FALSE,
Hi there,
I just find a fancy plot like the following:
http://www.nature.com/nature/journal/v505/n7481/images_article/nature12784-f2.jpg
I am wondering how to plot something like that in R. Which package will
be convenient for doing such things.
BTW, the link that points to R graph gallery
On 2014/3/17 1:12, Jim Lemon wrote:
On 03/17/2014 05:07 PM, Jinsong Zhao wrote:
Hi there,
I just find a fancy plot like the following:
http://www.nature.com/nature/journal/v505/n7481/images_article/nature12784-f2.jpg
I am wondering how to plot something like that in R. Which package
Hi there,
I hope to rotate the Y label of axis(4) with -90 degree. I can typeset
the Y label using text() with srt = -90. However, I cannot get the
coordinate of the position that mtext() used.
In other words, I hope to convert:
mtext(Y label, side = 4, at = 0, line = 2)
to
text(x, 0, Y
On 2014/3/17 15:32, Jim Lemon wrote:
On 03/18/2014 09:18 AM, Jinsong Zhao wrote:
Hi there,
I hope to rotate the Y label of axis(4) with -90 degree. I can typeset
the Y label using text() with srt = -90. However, I cannot get the
coordinate of the position that mtext() used.
In other words, I
Hi there,
Is there a function in R that can draw vector density plot? The vector
density plot example can be found here:
http://reference.wolfram.com/mathematica/ref/VectorDensityPlot.html
As for the vector field plot, I found a function that has been posted in
this mailing list:
Hi there,
I hope to use the emf plot produced by R in Word. However, I have
problems with setting the plot size. Here is a mini-example code:
win.metafile(abcd.emf, height =4, width=4)
plot(1:10)
dev.off()
I hope to get a emf plot with size 4x4in and pointsize 12pt. However, I
got a plot
for you.
Jean
On Mon, May 26, 2014 at 2:34 PM, Jinsong Zhao jsz...@yeah.net
mailto:jsz...@yeah.net wrote:
Hi there,
I hope to use the emf plot produced by R in Word. However, I have
problems with setting the plot size. Here is a mini-example code:
win.metafile(abcd.emf, height
size is same as the one produced by
``win.metafile'' and inserted into Word.
Now, it regresses to my original question.
Best,
Jinsong
On May 27, 2014, at 12:28, Jinsong Zhao jsz...@yeah.net wrote:
Jean,
Thank you for checking the problem. I have the same software with you.
If I created
with the size of emf file. However, when setting it to
72 by windows.options, only the display size in screen has been changed.
It don't affect the actual plot size when saving it as emf file. It also
384x384px instead of 288x288px.
Best,
Jinsong
On May 27, 2014, at 13:49, Jinsong Zhao jsz...@yeah.net
Hi there,
I plot a simple plot with the following code:
plot (rnorm(1:10), type = b)
legend(top, test, lty = 1, pch = 21)
The result is something wired for the line crosses the point in the
legend while the line does not cross the point in the main plot.
Is there possibility to draw the
On 2013/9/23 17:11, Jim Lemon wrote:
On 09/23/2013 01:54 PM, Jinsong Zhao wrote:
Hi there,
I plot a simple plot with the following code:
plot (rnorm(1:10), type = b)
legend(top, test, lty = 1, pch = 21)
The result is something wired for the line crosses the point in the
legend while the line
On 2013/9/23 12:52, David Winsemius wrote:
On Sep 22, 2013, at 10:54 PM, Jinsong Zhao wrote:
Hi there,
I plot a simple plot with the following code:
plot (rnorm(1:10), type = b)
legend(top, test, lty = 1, pch = 21)
?par
plot (rnorm(1:10), type = b)
legend(top, test, lty = 69, pch = 21
Hi there,
I have draw a scatter plot. Now, I hope to label the points in the plot.
For example:
plot(1:10)
text(1:10, 1:10, LETTERS[1:10])
In the above line, I can set position for each labels with pos, e.g.:
text(1:10, 1:10, LETTERS[1:10], pos = sample(1:4, 10, replace = TRUE))
as what
Hi there,
I have a data frame as listed below:
Ca.P.Biomass.A
P Biomass
1 334.5567 0.287
2 737.5400 0.571
3 894.5300 0.639
4 782.3800 0.5836667
5 857.5900 0.600
6 829.2700 0.588
I have fit the data using logistic, Michaelis–Menten, and linear model,
they all
Hi there,
I have fitted a sample (with size 20) to a normal and/or logistic
distribution using fitdistr() in MASS or fitdist() in fitdistrplus
package. It's easy to get the parameter estimates. Now, I hope to report
the confidence interval for those parameter estimates. However, I don't
find
On 2011-2-6 22:56, Ben Bolker wrote:
Jinsong Zhaojszhaoat yeah.net writes:
Hi there,
I have fitted a sample (with size 20) to a normal and/or logistic
distribution using fitdistr() in MASS or fitdist() in fitdistrplus
package. It's easy to get the parameter estimates. Now, I hope to report
Hi there,
I cannot find a detailed explanation to the following error message:
colnames(matrix(1:10, ncol = 2)) - c(X, Y)
Error in colnames(matrix(1:10, ncol = 2)) - c(X, Y) :
target of assignment expands to non-language object
However, when I do the following things, the error message
Hi there,
I am using R 2.15.2 under Win7 64. I hope to display progress bar when I
am running a loop. After the loop exit, the cursor is at the right
margin of the window. How can I make it to the left margin?
Here is the minimal example code.
combn.bar - function(n, m) {
n - choose(n,
Hi there,
I hope to replace a range of numeric in a matrix with a integer. For
example, in the following matrix, I want to use 1 to replace the
elements range from 0.0 to 1.0, and all larger than 1. with 2.
(m - matrix(runif(16, 0, 2), nrow = 4))
[,1] [,2] [,3] [,4]
TIBCO Software
wdunlap tibco.com
Thank you very much.
I think findInterval() is what I want.
Regards,
Jinsong
On Mon, Aug 11, 2014 at 2:40 PM, Jinsong Zhao jsz...@yeah.net wrote:
Hi there,
I hope to replace a range of numeric in a matrix with a integer. For
example, in the following matrix, I
Hi there,
I have several saved data files (e.g., A.RData, B.RData and C.RData). In
each file, there are some objects with same names but different
contents. Now, I need to compare those objects through plotting.
However, I can't find a way to load them into a workspace. The only
thing I can
Hi,
There is a scale factor associated with biplot when plotting the PCA
result. Please read the help page of biplot.princomp or/and the source
code of this function.
HIH,
Jinsong
On 2014/8/18 16:31, John Romansic wrote:
Hi all,
I am using prcomp to do Principle Components Analysis and
Thank you very much. It is what I want.
new.environment() is not defined in R 3.1.1. There is new.env().
Best,
Jinsong
On Mon, Aug 18, 2014 at 5:30 PM, Jinsong Zhao jsz...@yeah.net wrote:
Hi there,
I have several saved data files (e.g., A.RData, B.RData and C.RData). In
each file, there are some
?
Best,
Jinsong
On Mon, Aug 18, 2014 at 5:30 PM, Jinsong Zhao jsz...@yeah.net wrote:
Hi there,
I have several saved data files (e.g., A.RData, B.RData and C.RData). In
each file, there are some objects with same names but different contents.
Now, I need to compare those objects through
Hi there,
With the following code,
plot(1:5, xaxt = n)
axis(1, at = 1:5, labels = c(expression(E[g]), E, expression(E[j]),
E, expression(E[t])))
you may notice that the E within labels of axis(1) are not at the same
depth. So the vision of axis(1) labels is something like wave.
Is there a
On 2014/9/1 20:39, David Winsemius wrote:
On Sep 1, 2014, at 4:40 PM, Jinsong Zhao wrote:
Hi there,
With the following code,
plot(1:5, xaxt = n)
axis(1, at = 1:5, labels = c(expression(E[g]), E, expression(E[j]),
E, expression(E[t])))
you may notice that the E within labels of axis(1
University
College Station, TX 77840-4352
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Jinsong Zhao
Sent: Monday, September 1, 2014 6:41 PM
To: r-help@r-project.org
Subject: [R] depth of labels of axis
Hi there,
With the following code
On 2014/9/3 21:33, Jinsong Zhao wrote:
On 2014/9/2 11:50, David L Carlson wrote:
The bottom of the expression is set by the lowest character (which can
even change for subscripted letters with descenders. The solution is
to get axis() to align the tops of the axis labels and move the line
up
On 2014/9/4 12:24, David Winsemius wrote:
On Sep 3, 2014, at 10:05 PM, Jinsong Zhao wrote:
On 2014/9/3 21:33, Jinsong Zhao wrote:
On 2014/9/2 11:50, David L Carlson wrote:
The bottom of the expression is set by the lowest character (which can
even change for subscripted letters
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of David Winsemius
Sent: Thursday, September 4, 2014 2:25 PM
To: Jinsong Zhao
Cc: r-help@r-project.org
Subject: Re: [R] depth of labels of axis
On Sep 3, 2014, at 10:05 PM, Jinsong Zhao
On 2014/9/11 21:10, PO SU wrote:
Dear expeRts,
When i use the following codes:
pdf(file=1.pdf,width=15)
plot(1:3,main=你好)
dev.off()
#There were 12 warnings (use warnings() to see them)
I find that 你好 can't show correctly in pdf file, but i just
plot(1:3,main=你好) to R
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