Dear all
When using Sweave, I'm always hitting the same bump: I want to group
repetitive calls in a function, but I want both the results and the
function calls in the printed output. Let me explain myself.
Consider the following computation in an Sweave document:
summary(iris[,1:2])
On Wed, Apr 25, 2012 at 3:41 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
I would use the last method, or if the calls were truly repetitive (i.e.
always identical, not just the same pattern), use a named chunk.
Labeled chunks are indeed what I was looking for [1]. As far as I
understand,
On Fri, Apr 13, 2012 at 8:56 AM, Michael Bibo
michael_b...@health.qld.gov.au wrote:
Have you seen this from the archives?
http://www.mail-archive.com/r-help@r-project.org/msg45768.html
In addition see [1], which highlights the likes of Google, Merck or
Stanford University.
Liviu
[1]
Dear all
Is it possible to set globally the option .progress = text to all
the apply functions in 'plyr'. For example, current default is
daply(..., .progress = none). I would like to set it to daply(...,
.progress = text), so as to avoid writing the argument every time I
call such a function. I
On Tue, Apr 10, 2012 at 5:32 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
You might try the Defaults package.
Thanks for the hint. Unfortunately
library(Defaults)
setDefaults('create_progress_bar', name = text)
doesn't do the trick. But one can set defaults for each *ply()
Hello
On Fri, Apr 6, 2012 at 10:35 AM, Jhope jeanwaij...@gmail.com wrote:
Hi R-listers,
1) I am having trouble understanding why the means I have calculated from
Aeventexhumed (A, B, and C) are different from the means showing on the
boxplot I generated (see attached). I have added the
On Fri, Apr 6, 2012 at 2:21 PM, Ramiro Barrantes
ram...@precisionbioassay.com wrote:
Please let me know if you have any other suggestions or clues.
See this older post by Brian [1] and check ?Memory-limits.
Otherwise, I remember someone suggesting that even if R releases the
memory internally,
On Wed, Apr 4, 2012 at 4:22 PM, uday uday_143...@hotmail.com wrote:
I would like to plat some spaghetti plots from my data , ma data is as
See:
require(sos)
findFn('spaghetti')
Liviu
follows
ak[1:3,]
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[,8] [,9]
On Wed, Apr 4, 2012 at 5:04 PM, uday uday_143...@hotmail.com wrote:
Hi Liviu ,
thanks for post , but I could not find findFn('spaghetti') , I can see the
following functions in sos package
Extract.findFn
findFn
After installing 'sos', use the 'findFn()' function. For example, run
On Sun, Apr 1, 2012 at 4:48 PM, Manish Gupta mandecent.gu...@gmail.com wrote:
Hi,
I am newbie in Latex and R. I am working on one report in which i need to
read file and display content of file by formatting (adding color boxes and
colorful text for each record). For this i need to use latex
Dear all
How should one proceed when estimating nested models containing
missing data. What I would like to do is to first estimate the model
with the control variables only, and then estimate the model
containing also the variables of interest. For example,
summary(reg.a - lm(IMC ~ STYLE + SEXE
On Thu, Mar 22, 2012 at 1:17 PM, richard willey
richard.wil...@gmail.com wrote:
I was hoping to get some advice regarding teaching R in an academic
environment.
thinks regarding “An R Companion to Applied Regression”.
CAR features an excellent introduction to R programming.
Liviu
On Wed, Dec 21, 2011 at 9:28 AM, arunkumar akpbond...@gmail.com wrote:
Hi,
can anyone please explain why the vif should have more than 2 terms.
*vif.lm(lmobj) : model contains fewer than 2 terms*
why it is throwng error if it is one variable.
The _VIF_ is a measure of
On Fri, Dec 16, 2011 at 1:47 PM, David Winsemius dwinsem...@comcast.net wrote:
Harrell's rms package has a vif function that is intended for use with fits
from his logistic regression model function, lrm. This uses the variance
Also see vif() in 'car'.
Liviu
On Wed, Dec 7, 2011 at 7:43 PM, Janko Thyson
janko.thyson.rst...@googlemail.com wrote:
I like knitr. IMHO Yihui really came up with a killer package there:
http://yihui.github.com/knitr/
If we're talking about nice, I'll chip in for LyX. It has support for
Sweave, and will soon support knitr.
On Tue, Dec 6, 2011 at 4:42 AM, Michael comtech@gmail.com wrote:
I didn't mean the speed of saving the file is slow... I meant the manual
procedures of exporting and then opening Excel, etc. is slow and
inconvenient and unproductive...
You may want to use RExcel then.
Liviu
On Mon, Dec
On Sat, Dec 3, 2011 at 2:38 AM, Michael comtech@gmail.com wrote:
Hi all,
Could you please help me?
I am having the following weird problem when debugging R programs
using browser():
In my function, I've inserted a browser() in front of Step 1. My
function has 3 steps and at the end of
On Mon, Nov 28, 2011 at 3:54 AM, Matteo Richiardi
matteo.richia...@gmail.com wrote:
Hello,
I'm a newby in R. I have created a data.frame holding panel data, with
Take a look at the 'plm' package and its vignette.
Regards
Liviu
the following columns: id,time,y, say:
periods = 100
numcases
On Thu, Nov 24, 2011 at 9:27 AM, Patrick Burns pbu...@pburns.seanet.com wrote:
It's very seldom that I disagree with
Bert, but here is one time.
I don't think An Introduction to R is
a suitable first read for people with
little computational experience.
I must agree with Patrick here. The
Dear all
How should one parse all.equal() output? I'm specifically referring to
the 'mean relative difference' messages. For example,
all.equal(pi, 355/113)
[1] Mean relative difference: 8.491368e-08
But I'm not sure how to understand these messages. When they're close
to 0 (or 1xe-16), then
Dear all
I have a work-flow issue with lm(). When I use
lm(y1~x1, anscombe)
Call:
lm(formula = y1 ~ x1, data = anscombe)
Coefficients:
(Intercept) x1
3.0001 0.5001
I get as expected the formula, y1 ~ x1, in the print()ed results or
summary(). However, if I pass through a
On Thu, Nov 24, 2011 at 9:14 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
It is retained. terms(fit) will give it to you, if fit is an lm object.
Thank you. The following works nicely.
(form - formula(y1~x1))
y1 ~ x1
x - lm(form, anscombe)
formula(terms(x))
y1 ~ x1
However, I was
On Thu, Nov 24, 2011 at 10:25 PM, Prof Brian Ripley
rip...@stats.ox.ac.uk wrote:
Yes. That's a job for substitute (the second time today).
form - formula(y1~x1)
x - eval(substitute(lm(f, anscombe), list(f = form)))
summary(x)
Call:
lm(formula = y1 ~ x1, data = anscombe)
That's what I
)
Call$formula - as.formula(terms(formula))
eval(Call)
}
From limited testing this seems to do exactly what I wanted!
I thank all those who came up with suggestions. Regards
Liviu
On Thu, 24 Nov 2011, Liviu Andronic wrote:
On Thu, Nov 24, 2011 at 10:25 PM, Prof Brian Ripley
rip
On Tue, Nov 22, 2011 at 2:09 PM, Giovanni Azua brave...@gmail.com wrote:
Mr. Gunter did not read/understand my problem, and there were no useful tips
but only ad hominem attacks. By your side-taking I suspect you are in the
same party club if you want to defend him maybe you should start by
On Thu, Nov 17, 2011 at 7:33 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
Hmmm...sorry -- the only thing I can suggest is maybe striking some
sort of deal that you change when it gets however many months out of
date: if you look here
On Thu, Oct 20, 2011 at 7:29 PM, Bogaso Christofer
bogaso.christo...@gmail.com wrote:
Dear all, the company I work for has Matlab installed for
statistical/mathematical calculations and really not ready to go with R
(even installing exe file for R). Therefore I was wondering is it possible
to
On Wed, Oct 12, 2011 at 3:29 AM, Yves S. Garret
yoursurrogate...@gmail.com wrote:
Hi all,
I recently started learning about Forex and found this O'Reilly book in
Barnes Nobles about R. I bought it out of pure curiosity. I like what I
see. However, I have a question. Has anyone tried to
On Fri, Sep 30, 2011 at 2:41 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
As an aside, I don't recommend the workflow you describe: it's very slow
and cumbersome. It's much better to tell your text editor how to run both
Sweave and Latex in one command. In the upcoming release of R
Dear all
How does print.htest display the p-value in scientific notation?
(x - cor.test(iris[[1]], iris[[3]]))
Pearson's product-moment correlation
data: iris[[1]] and iris[[3]]
t = 21.65, df = 148, p-value 2.2e-16
alternative hypothesis: true correlation is not equal to 0
95 percent
Thanks all for your pointers. The following does trick:
base::format.pval(x$p.value) ##Hmisc also has such a function
[1] 2e-16
On Mon, Oct 3, 2011 at 10:25 AM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
Isn't it true that 0 2.2e-16?
Yes, but it doesn't mean that the p-value actually hits
On Sat, Sep 24, 2011 at 5:43 PM, Joshua Wiley jwiley.ps...@gmail.com wrote:
I printed the form to mail off, but anecdotally I had planned on this
for well over a year and kept putting it off. If this is something
that useRs and the R Foundation would be interested in, I would be
happy to help
On Wed, Sep 14, 2011 at 4:50 AM, cwdillon cwdil...@gmail.com wrote:
Well, I've bee reading the R Manual, Nathan Yau's book on Flowing Data, and a
few others like this to my kids to get them to go to sleep. I started off
doing it the *wrong* way, just to keep it boring but slipped into doing it
On Mon, Sep 12, 2011 at 9:41 AM, Patrick Burns pbu...@pburns.seanet.com wrote:
R-help is all about solving R problems.
So here ya go:
http://www.portfolioprobe.com/2011/09/12/solve-your-r-problems/
Sweet. :)
May I suggest a font change: anything but the default CM should do the
trick. For one
On Mon, Sep 12, 2011 at 9:21 AM, Twaha Mlwilo uddessy2...@hotmail.com wrote:
Hello all,
Good day,
I have problem on how to remove the source code from the pdf output.Here I
mean this.
code in sweave Rnw files
=
x-c(1,2,3,4,5,6)
x
mean(x)
sd(x)
@
then would like it appear as
(please reply to the list, too, as it increases your chances of
getting a helpful answer)
On Sat, Sep 3, 2011 at 2:51 AM, loth lorien lothlorie...@hotmail.com wrote:
Hi Liviu,
Thank you for your suggestions, but they didn't seem to work.
I got R to estimate a fixed effects model for me:
On Thu, Sep 1, 2011 at 4:25 AM, Ash lothlorie...@hotmail.com wrote:
Hi,
I am trying to complete a very simple panel analysis on some bank data.
Call:
Formula-plm(RoE~RoA+CAR+Inc.Dep+Cash.TL+NPL.Loans, data=Banks1,
model=random, index=c(Bank.I.D.,Year))
summary(Formula)
I get the
I would nominate the following fortune:
On Thu, Sep 1, 2011 at 12:16 PM, Petr PIKAL petr.pi...@precheza.cz wrote:
Try to call 112 if you are in Europe.
David Winsemius: Thank your for your entry in the Poorly Capitalized
and Inadequately Searched Posting Contest.
mark: help, help ,help!!!
On Thu, Sep 1, 2011 at 5:48 PM, Jean V Adams jvad...@usgs.gov wrote:
Try this
data - eval(parse(text=paste(study, level, ., population, sep=)))
..or this:
data - get(paste(study, level, ., population, sep=))
Liviu
Jean
-
dbateman wrote on 08/31/2011 17:44:44:
I have several
On Thu, Sep 1, 2011 at 7:53 PM, Changbin Du changb...@gmail.com wrote:
HI, Dear R community,
I want to split a data frame by using two variables: let and g
It's not clear what you want to do, but investigate the following:
require(plyr)
Loading required package: plyr
ddply(x, .(let, g),
On Sat, Aug 27, 2011 at 7:26 AM, Andra Isan andra_i...@yahoo.com wrote:
Hi All,
I have a data frame as follow:
user_id time age location gender
.
and I learn a logistic regression to learn the weights (glm with family=
(link = logit))), my response value is either zero or one. I
Dear Michael
Thank you for your pointers.
On Tue, Aug 23, 2011 at 4:05 PM, Michael Friendly frien...@yorku.ca wrote:
First, you should be using rms::ols, as Design is old.
Good to know. I've always wondered why Design and rms, in many cases,
were providing similar functions and (upon cursory
The attachment seems to have been dropped, so I'm pasting the code
below. Sorry for that
Liviu
On Wed, Aug 24, 2011 at 1:44 PM, Liviu Andronic landronim...@gmail.com wrote:
Second, penalty in ols() is not the same as the ridge constant in lm.ridge,
but rather a penalty on the log likelihood
On Wed, Aug 24, 2011 at 4:20 PM, Eran Eidinger e...@taykey.com wrote:
Hi,
I am not sure if this is the right list to ask this question (though I did
not find a more appropriate one).
I've started using R a month ago, and small scripts work fine. However, when
I start writing more complex
Dear all
I'm familiarising myself with Ridge Regressions in R and the following
is bugging me: How does one get p-values for the coefficients obtained
from MASS::lm.ridge() output (for a given lambda)? Consider the
example below (adapted from PRA [1]):
require(MASS)
data(longley)
gr -
On Sun, Aug 21, 2011 at 3:04 PM, Eran Eidinger e...@taykey.com wrote:
Thank you Uwe,
That solves the second question.
Still looking for some solution to zooming in and out dynamically.
Try package 'playwith'.
Liviu
__
R-help@r-project.org mailing
Dear all
?Hmisc::rcorr states that it takes as main argument a numeric
matrix. But is it normal that it fails in such an ugly way on a data
frame? (See below.) If the function didn't attempt any conversion to a
matrix, I would have expected it to state that in the error message
that it didn't
Dear all
Is there an easy way to display only one half (top-right or
bottom-left) of a correlation matrix?
require(Hmisc)
rcorr(as.matrix(mtcars[ , 1:4]))
mpg cyl disphp
mpg 1.00 -0.85 -0.85 -0.78
cyl -0.85 1.00 0.90 0.83
disp -0.85 0.90 1.00 0.79
hp -0.78 0.83 0.79
On Fri, Aug 19, 2011 at 9:02 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
Use as.dist: here's an example.
Seems promising, but for one issue: I would like to keep the diagonal
and thus specify 'diag=T', but then as.dist() replaces the diagonal
values with zero. (See below.) Is there a
On Fri, Aug 19, 2011 at 9:38 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
if as.dist doesn't work, use brute force:
x = matrix(rnorm(5*100), 100, 5)
mat = signif(cor(x), 2);
mat[lower.tri(mat)] =
data.frame(mat)
Yes, brute force works. This isn't quite how I wanted to do this,
On Wed, Aug 10, 2011 at 5:52 PM, Jean V Adams jvad...@usgs.gov wrote:
As it says in
?format
the digits argument specifies ... how many significant digits are to be
used ... enough decimal places will be used so that the smallest (in
magnitude) number has this many significant digits ...
Hello
On Thu, Aug 11, 2011 at 4:34 PM, Martin Maechler
maech...@stat.math.ethz.ch wrote:
Well, as you say it's View() only, so why don't you just
view the result of
something like
print(data, digits = 2)
Unfortunately print(..., digits = 2) suffers of the same deficiencies
as
On Thu, Aug 11, 2011 at 4:58 PM, David Winsemius dwinsem...@comcast.net wrote:
numVars - sapply(iris, is.numeric)
iris[numVars] - lapply(iris[numVars], round, digits = 2)
head(iris)
Then drop the assignment operation and just print:
( lapply(iris[numVars], round, digits = 2) )
That's a
On Wed, Aug 10, 2011 at 5:52 PM, Jean V Adams jvad...@usgs.gov wrote:
data.frame(lapply(x, function(y) if(is.numeric(y)) round(y, 2) else y))
Building on this, I came up with a 'data.frame' method for round().
I'm not sure how orthodox it is, but it seems to do the job as
intended:
On Wed, Aug 10, 2011 at 11:39 PM, David Winsemius
dwinsem...@comcast.net wrote:
is.vector(x)
[1] TRUE
You probably didn't realize that lists _are_ vectors before this.
Nice to know.
Hopefully this expected invitation to grilling will not result in severe
burns. I note that one of the
Dear all
It is difficult to use round(..., digits=2) on a data frame since one
has to first take care to remove non-numeric variables such as
'character' or 'factor':
head(round(iris, 2))
Error in Math.data.frame(list(Sepal.Length = c(5.1, 4.9, 4.7, 4.6, 5, :
non-numeric variable in data
Hello
On Wed, Aug 10, 2011 at 11:41 AM, Dimitris Rizopoulos
d.rizopou...@erasmusmc.nl wrote:
One approach is the following:
numVars - sapply(iris, is.numeric)
iris[numVars] - lapply(iris[numVars], round, digits = 2)
head(iris)
That's interesting, but still doesn't do what I need. Since it's
Hello
On Wed, Aug 10, 2011 at 2:31 PM, Jean V Adams jvad...@usgs.gov wrote:
The function format() might serve your needs.
This looks very promising, but yields some strange results. See below:
x - data.frame(a=rnorm(10), b=rnorm(10), c=rnorm(10), d=letters[1:10])
x
a b
Dear all
How does one convert a non-symmetric list to a vector? See below:
x - list()
x[[1]] - letters[1:5]
x[[2]] - letters[6:10]
x[[3]] - letters[11:12]
x
[[1]]
[1] a b c d e
[[2]]
[1] f g h i j
[[3]]
[1] k l
paste(x)
[1] c(\a\, \b\, \c\, \d\, \e\) c(\f\, \g\, \h\,
\i\, \j\)
[3] c(\k\,
On Wed, Aug 10, 2011 at 9:02 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
unlist()
Thanks all! This is perfect, and very R-ish: never where a novice
would expect it to be.
Cheers
Liviu
__
R-help@r-project.org mailing list
On Wed, Aug 10, 2011 at 9:32 PM, David Winsemius dwinsem...@comcast.net wrote:
Thanks all! This is perfect, and very R-ish: never where a novice
would expect it to be.
Well, since `unlist` is linked in the See Also on the help page for `list`,
I can only hope you meant that in complete jest.
On Fri, Aug 5, 2011 at 3:54 PM, khadeeja ismail haj...@yahoo.com wrote:
other attached packages:
[1] Rcmdr_1.6-2
I bet that this is what generates the lack of error messages. Check
Rcmdr documentation on how to turn it off.
Liviu
__
On Mon, Jul 25, 2011 at 8:03 PM, Jose Bustos Melo jbustosm...@yahoo.es wrote:
Who knows if there's people working in Life Cycle Assesment (carbon emition)
with R? or If there's someone interested in doing a package about it, please
let me know!
Some of the places to check would be:
rseek.org
Dear all
I know that the R way of documenting things is to work on your project
in package development mode, and document each object (such as data
frames) in a *.Rd files. This should work for gurus. What about a
simpler way to document things, geared for mere mortals?
I was thinking of a
On Mon, Jul 18, 2011 at 5:04 PM, UnitRoot akhussa...@gmail.com wrote:
Hello,
I am facing problems with plotting graphs in R. It was working well since
today, but I cannot get some graphs for unknown reasons. Initially it gave
me diagonal straight lines. Now it is giving me very strange curves.
On Sun, May 15, 2011 at 3:06 PM, ivo welch ivo.we...@gmail.com wrote:
Dear R-experts---is there a relatively low-pain way to get unicode
characters into a plot to a pdf device?
Have you tried Cairo package or cairo_pdf()? Both are making use of
Cairo, which uses UTF-8 and automatically embeds
On Fri, Jun 3, 2011 at 6:46 AM, Vikas Garud information4vi...@gmail.com wrote:
Hi,
This is to share my experience of using GUI's for using various
Quality Management/Assurance tools.
A few days back, I had I had written a mail about Box plots and
received some very good suggestions,
On Tue, May 17, 2011 at 2:15 PM, Jannis bt_jan...@yahoo.de wrote:
Otherwise I would stick to SPSS/Excel/Sigmaplot or browse for some R GUIs
with some basics beeing implemented on a click basis like RStudio, Rkward
or TinnR. All R GUI implementations are however limited to basic
On Fri, May 13, 2011 at 5:25 PM, John C Frain fra...@gmail.com wrote:
Given the price of the Thinkpad X201 I would be very upset if it
overheated and would contact my supplier for a replacement.
Consider getting an aluminium cooling pad, such as those provided by
Zalman. It helps keeping my HP
On Thu, Apr 21, 2011 at 9:59 PM, Thomas Lumley tlum...@uw.edu wrote:
The Evil and Wrong use is to modify variables in the global environment.
I'm a bit at a loss. Why is it so wrong and evil? In other words, how
should one modify variables in the global environment? Through the use
of return()?
On Sat, Apr 16, 2011 at 6:39 PM, Al Roark hrbuil...@hotmail.com wrote:
Hi All:
I have some basic questions about Cairo graphics engine. I'm trying to use
the Cairo package to produce PDF output, mainly because I perceive it to be
easy to use with a wide variety of fonts.
You may also want
Dear all
I've just tried the brand new 'grdevice' option in Sweave but couldn't
make it work. When I declare
\SweaveOpts{grdevice=pdf}
or
\SweaveOpts{grdevice=cairo_pdf}
trying to plot something simple
fig=T, echo=T=
plot(1:10,1:10,main='Some title')
@
would result in an Sweave error:
Hello
I sympathise with you, since Beamer can quickly drive one mad.
On Fri, Apr 15, 2011 at 3:11 AM, Brett Presnell presn...@stat.ufl.edu wrote:
So, is this useful to anyone besides me? What trick(s) am I missing
that would make it easier/better, or that would obviate altogether the
need
Hello
On Fri, Apr 8, 2011 at 12:38 AM, Raoni Rodrigues
caciquesamu...@gmail.com wrote:
Hello all!
I have a data frame with nine variables and 293 cases. (attached goes
the csv file).
The CSV didn't get through so it's difficult to replicate your
example. Please post the output of:
str(cpue)
On Thu, Apr 7, 2011 at 9:45 AM, Stanislav Bek
stanislav.pavel@gmail.com wrote:
Hi,
is it possible to use some statistic computing by R in proprietary software?
I don't know if this covers your case, but SAS and SPSS provide
interfaces to R. Regards
Liviu
Our software is written in c#,
Dear all
Is there a clean plyr version of the following by() and do.call(rbind,
...) construct:
df-data.frame(a=1:10,b=11:20,c=21:30,grp1=c(x,y),grp2=c(x,y),grp3=c(x,y))
dfsum-by(df[c(a,b,c)], df[c(grp1,grp2,grp3)], range)
as.data.frame(dfsum)
Error in as.data.frame.default(dfsum) :
cannot
Dear all
I would like to use Sweave with the Cairo() graphics device instead of
pdf(), since the former supports Unicode, allows for easier font
selection out of a greater range of available fonts, and automatically
embeds fonts into the resulting PDF.
Following this older discussion [1], has
On Thu, Apr 7, 2011 at 6:39 AM, Prof Brian Ripley rip...@stats.ox.ac.uk wrote:
This is simple in 2.13.0 RC, which allows you to add graphics devices for
Sweave.
Interesting. Which help files should I look into?
On Wed, 6 Apr 2011, Liviu Andronic wrote:
since the former supports Unicode
Dear Brian
On Thu, Apr 7, 2011 at 6:39 AM, Prof Brian Ripley rip...@stats.ox.ac.uk wrote:
allows for easier font
selection out of a greater range of available fonts,
As does cairo_pdf(), builtin to R and more reliable in my experience.
I've looked into the help pages and searched the lists,
Hello
On Fri, Apr 1, 2011 at 12:32 PM, January Weiner
january.wei...@mpiib-berlin.mpg.de wrote:
I have found the packages xterm256 and highlight, but I was not
able to figure out how to use it to highlight the syntax in console
output.
I've been in this position before, without finding a
On Fri, Apr 1, 2011 at 3:48 PM, January Weiner
january.wei...@mpiib-berlin.mpg.de wrote:
RStudio might be a fine program, but it does not feature syntax
highlighting, which is the only thing I am missing from R Console (it
only colors the commands typed).
The idea is that you shouldn't use the
hit More Set as working dir. A bit cumbersome, but
seems to work, and a small price to pay for all the available
functionality.
Regards
Liviu
Thanks nonetheless,
j.
On Fri, Apr 1, 2011 at 4:20 PM, Liviu Andronic landronim...@gmail.com wrote:
On Fri, Apr 1, 2011 at 3:48 PM, January Weiner
On Fri, Mar 18, 2011 at 11:00 PM, Brigid Mooney bkmoo...@gmail.com wrote:
I'm not trying to start a Windows vs. Linux debate, but I've been
using R on a Windows machine for a while, and was recently wondering
if R's performance would be faster on a Linux machine. And similarly,
if any
On Wed, Mar 9, 2011 at 9:57 AM, Ingmar Visser i.vis...@uva.nl wrote:
FWIW, the style for JSS now enforces (via Achimitization) the use of quotes
as you show above.
An excellent candidate for the fortunes package!
We should probably address Achim for that. :)
Regards
Liviu
best, Ingmar
On Mon, Mar 7, 2011 at 1:38 AM, David Winsemius dwinsem...@comcast.net wrote:
subset(x[order(x$Species1), ], Sepal.Length==6.7 )
Thank you all for the suggestions. Now I can do exactly what I wanted. Regards
Liviu
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R-help@r-project.org mailing list
Dear all
This may be obvious, but I cannot get it working. I'm trying to subset
sort a data frame in one go.
x - iris
x$Species1 - as.character(x$Species)
##subsetting alone works fine
with(x, x[Sepal.Length==6.7,])
##sorting alone works fine
with(x, x[order(Sepal.Length, rev(sort(Species1))),])
On Sun, Mar 6, 2011 at 11:49 PM, Liviu Andronic landronim...@gmail.com wrote:
Dear all
This may be obvious, but I cannot get it working. I'm trying to subset
sort a data frame in one go.
x - iris
x$Species1 - as.character(x$Species)
##subsetting alone works fine
with(x, x[Sepal.Length==6.7
On Sun, Mar 6, 2011 at 11:53 PM, Liviu Andronic landronim...@gmail.com wrote:
On Sun, Mar 6, 2011 at 11:49 PM, Liviu Andronic landronim...@gmail.com
wrote:
Dear all
This may be obvious, but I cannot get it working. I'm trying to subset
sort a data frame in one go.
x - iris
x$Species1
On Tue, Mar 1, 2011 at 5:58 PM, R Heberto Ghezzo, Dr
heberto.ghe...@mcgill.ca wrote:
hello, i tried to run playwith but :
library(playwith)
Loading required package: lattice
Loading required package: cairoDevice
Loading required package: gWidgetsRGtk2
Loading required package: gWidgets
On Tue, Mar 1, 2011 at 11:41 AM, JoonGi joo...@hanmail.net wrote:
Thanks in advance.
I want to derive correlations of variables in a dataset
Specifically
library(Ecdat)
data(Housing)
attach(Housing)
cor(lotsize, bathrooms)
this code results only the correlationship between two
On Fri, Feb 18, 2011 at 8:00 PM, Tom Hopper tomhop...@gmail.com wrote:
Tal,
One interactive capability that I have repeatedly wished for (but
never taken the time to develop with the existing R tools) is the
ability to interactively zoom in on and out of a data set,
I believe that you can do
Hello
On Fri, Jan 28, 2011 at 8:03 PM, Jonathan P Daily jda...@usgs.gov wrote:
Geany also handles a ton of filetypes, but lacks a direct interface to R
in the windows version - I wrote an AutoHotKey script that did this for me
in about 5 minutes.
Could you please expand on that? I prefer to
Hello
On Fri, Jan 28, 2011 at 8:16 PM, Zunqiu Chen che...@ohsu.edu wrote:
It might be a simple question. But I could not find the answer from function
“prcomp” or “princomp”. Does anyone know what are the codes to get
coefficient and scores of Principal component analysis in R?
Try these:
On Wed, Jan 5, 2011 at 10:49 PM, Young Cho young.s...@gmail.com wrote:
When introduced to R, I learned how to use *apply whenever I could to avoid
for-loops and all. And, getting the habit, I think I somehow got the
mis-conception that it is a magic source, always an optimal way of coding in
On Wed, Jan 5, 2011 at 12:29 PM, Graham Smith myotis...@gmail.com wrote:
maximal choices would break the budget. This sounds like a homework problem
and I don't see any student effort yet. Search terms include: decision
analysis , cost-benefit analysis, or utility theory.
Hopefully, my
(slightly off-topic)
Hello
On Sat, Jan 1, 2011 at 12:20 AM, Yihui Xie x...@yihui.name wrote:
I still recommend the pgfSweave package (as usual) -- you can cache
both data objects (using cacheSweave) and graphics (using pgf).
Do these packages re-implement Sweave, or just use it as a
On Thu, Dec 30, 2010 at 9:48 PM, Marius Hofert m_hof...@web.de wrote:
Thanks, John, I did.
Here is an update [not all problems are solved; can they be?]:
Consider:
library(xtable)
mat - matrix(c(1,NA,3,100,10012.23423,4), ncol = 3, byrow = TRUE)
print(xtable(mat, digits = 1), floating =
On Sun, Dec 26, 2010 at 8:49 AM, Christian Schoder
schoc...@newschool.edu wrote:
Dear R-users,
I've been using R for a while and I am very satisfied! Unfortunately, I
still have not figured out an efficient and general way to construct and
use lags of time series, especially when I need to
On Wed, Dec 22, 2010 at 2:57 AM, Phil Spector spec...@stat.berkeley.edu wrote:
To make your loop work, you need to learn about the get function.
I'm not going to give you the details because there are better
approaches available.
First, let's make some data that will give values which can be
On Wed, Dec 22, 2010 at 6:39 PM, govin...@msu.edu wrote:
Thank you both for your suggestions. I have another question - is there a
specific way to access the individual elements of a 'list' variable? i.e.
dmi = matrix(rnorm(20),4,5)
soi = matrix(rnorm(20),4,5)
pe = matrix(rnorm(20),4,5)
y
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