On Mon, Oct 18, 2010 at 4:38 AM, John Haart anothe...@me.com wrote:
Dear List,
I have a table i have read into R:
Name Yes/No
John 0
Frank 1
Ann 0
James 1
Alex 1
etc - 800 different times.
What i want to do is shuffle yes/no and randomly re-assign them to
On Thu, Oct 21, 2010 at 3:50 PM, HAKAN DEMIRTAS demir...@uic.edu wrote:
Hi,
If a matrix is not positive definite, make.positive.definite() function in
corpcor library finds the nearest positive definite matrix by the method
proposed by Higham (1988).
However, when I deal with correlation
On Tue, Oct 26, 2010 at 3:13 PM, Daisy Englert Duursma
daisy.duur...@gmail.com wrote:
There are several ways to do this but the package ggplot2
library(ggplot2)
qplot(displ,hwy,data=mpg,colour=factor(cyl))
That can of course be done also using the standard plot command
(substitute variable
Sorry, this isn't really an R solution, but here it goes anyway. You
can isolate the block from Source to the first following blank line by
the following unix/linux/cygwin command, assuming inFile is your input
file and outFile is the output file:
cat inFile | grep -A 100 Source | grep -m 1 -B
Before plotting a heatmap we usually standardize all genes to mean
zero and variance 1. That way the green/red represent under/over
expression with respect to the mean expression, which is roughly what
the original 2-color arrays (that literally produced such heatmaps)
were measuring. Of course,
You have (almost) exhausted the 10GB you limited R to (that's what the
memory.size() tells you). Increase memory.limit (if you have more RAM,
use memory.limit(15000) for 15GB etc), or remove large data objects
from you session. Use rm(object), the issue garbage collection gc().
Sometimes garbage
for data to be swapped to and from the disk.
Peter
On Tue, Nov 2, 2010 at 7:36 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
You have (almost) exhausted the 10GB you limited R to (that's what the
memory.size() tells you). Increase memory.limit (if you have more RAM,
use memory.limit
Just a shot in the dark... Do you properly close the input/output
files at the end of your function? If not and the file remains open,
it may throw an error upon new attempt to read it. It is possible that
dyn.unload, among other things, closes all open connections and hence
upon re-load
Weighted mean of x and y coordinates (sorry for the pun :)), that is
something like
n = 21
y = matrix( c(1:n), n, n)
x = matrix( c(1:n), n, n, byrow = TRUE)
# These are the Center of mass coordinates:
xCenter = sum(x * Z)/sum(Z);
yCenter = sum(y * Z)/sum(Z);
If you also need the z coordinate,
On Mon, Nov 8, 2010 at 11:31 PM, Ab Hu master.rs...@yahoo.com wrote:
Thanks! Works great.
I have more questions on this, so I'll continue here:
Now that I have the weighted mean, is it possible to reduce the size of
mountain based on this weighted mean such the original matrix remains 21x21
On Tue, Nov 9, 2010 at 3:40 PM, Barry Rowlingson
b.rowling...@lancaster.ac.uk wrote:
On Mon, Nov 8, 2010 at 5:15 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
If you also need the z coordinate, it simply the mean of the matrix Z.
zCenter = mean(Z)
How can that be right? Suppose
zCenter = mean(Z)
How can that be right? Suppose your mountain is very flat, so that
your mountain is effectively a cube. The Z values are all the same,
and so their mean is the same. However the centre of mass is, by
symmetry, clearly at height/2.
Similarly suppose your mountain
the exponent of asymmetric matrix makes me very curious.
can anyone please explain to me what will happen if we apply exponent to
the asymmetric matrix?
The gates of Hell will open, the world will come to an end, and we
will all perish in a firestorm :)
Sorry, couldn't resist. Exponentiating
On Tue, Nov 9, 2010 at 9:09 PM, sachinthaka.abeyward...@allianz.com.au wrote:
Hi All,
Suppose I want to concatenate a zero to all the values to a column called
period in data frame A. I want to do the following but the following
command actually deletes the entire column altogether.
On Wed, Nov 10, 2010 at 1:38 PM, kurt_h...@nps.gov wrote:
Greetings
I'm attempting to insert missing data on the smallest size class of
cave cricket instars into a data frame. The data involve censusing
photoplots (plots) of roosting cave crickets in which we discern in four
instars or
On Thu, Nov 11, 2010 at 11:33 AM, Noah Silverman
n...@smartmediacorp.com wrote:
Still doesn't work.
When using rbind to build the data.frame, it get a structure mostly full of
NA.
The data is correct, so something about pushing into the data.frame is
breaking.
Example code:
results -
On Thu, Nov 11, 2010 at 1:19 PM, William Dunlap wdun...@tibco.com wrote:
Peter,
Your example doesn't work for me unless I
set options(stringsAsFactors=TRUE) first.
(If I do set that, then all columns of 'results'
have class character, which I doubt the user
wants.)
You probably mean
On Thu, Nov 11, 2010 at 1:19 PM, William Dunlap wdun...@tibco.com wrote:
Peter,
Your example doesn't work for me unless I
set options(stringsAsFactors=TRUE) first.
Yes, you need to set options(stringsAsFactors=FALSE) (note the FALSE).
I do it always so I forgot about that, sorry.
I see 4 ways to write the code:
1. make the frame very long at the start and use my code - this is
practical if you know that your data frame will not be longer than a
certain number of rows, be it a million;
2a. use something like
result1 = data.frame(a=a, b=b, c=c, d=d)
within the loop to
You change x from a single value to a vector of size 2, for example here:
if (j==2) {x=x+c(-1,1)*0.5}
That makes
c( qchisq(1-alpha/2,df=2*x)/2,
qchisq(alpha/2,df=2*x+2)/2)
a vector of 4 numbers that you are trying to assign to a row of a
matrix with two columns.
Not sure if there's a pre-defined function for it, but use your basic
math skills: the normal distribution is
dnorm(x) = 1/(sqrt(2*pi)) * exp(-x^2/2),
so the inverse function (on the interval [0, infinity] is
f = function(x) {sqrt( -2*log(sqrt(2*pi) * x)) }
Since the dnorm function is not
On Sat, Nov 13, 2010 at 10:33 PM, Stephen Liu sati...@yahoo.com wrote:
Win 7 64 bit
R version 2.11.1 (2010-05-31)
How to permanently remove;
[Previously saved workspace restored]
rm (list = ls( ))
On next start it still displays;
.
[Previously saved workspace restored]
There is
On Mon, Nov 15, 2010 at 2:07 PM, rchowdhury rchowdh...@alumni.upenn.edu wrote:
Hello,
I am using the hclust function to cluster some data. I have two separate
files with the same data. The only difference is the order of the data in
the file. For some reason, when I run the two files
On Mon, Nov 15, 2010 at 2:19 PM, Reshmi Chowdhury
rchowdh...@alumni.upenn.edu wrote:
Here is the code I am using:
m - read.csv(data_unsorted.csv,header=TRUE)
m - na.omit(m)
cs - hclust(dist(t(m),method=euclidean),method=complete)
ds - as.dendrogram(cs)
As Christian said, you may want to
On Tue, Nov 16, 2010 at 9:40 AM, Jeff Bassett jbass...@cs.gmu.edu wrote:
Giovanni,
Both matrices describing the points (A and B in my example) are the
same size, so the resulting matrix will always be square. Also, the
equation I'm using is essentially the following identity:
Var(A + B) =
Peter,
I see your point. As it turns out though, what I'm trying to
calculate is heritability using a slightly modified version of an
equation from multivariate quantitative genetics. Theoretically I
suppose a heritability matrix could be non-positive definite, but in
practice it almost
On Fri, Nov 26, 2010 at 6:55 AM, Derik Burgert derik2...@yahoo.de wrote:
Dear list,
running a hierachical cluster analysis I want to define a number of objects
that build a cluster already. In other words: I want to force some of the
cases to be in the same cluster from the start of the
Hi all,
I have a package that contains a function foo that calls a function
.fooInternal via match.fun('.fooInternal'). This step is necessary
because I want to give the user an option to override .fooInternal
with a custom function. The .fooInternal function name is not
exported. The function
2010/9/14 Uwe Ligges lig...@statistik.tu-dortmund.de:
I do not see any problem, we'd need to look at the package in order to help,
I think.
I re-checked again and somehow the package now passes all checks, so I
must have mistyped something somewhere. Sorry for that.
Peter
Hello,
I encountered a weird problem. Consider the following code that takes
a list lst and shifts all elements one index up (for example, to
make space for a new first element):
lst = list(1,2)
ll = length(lst);
for (i in ll:1)
lst[[i+1]] = lst[[i]];
lst
If you run it, you get the expected
Hi Joshua,
thanks, I came up with that solution myself after a bit of thinking.
Normally I wouldn't worry about NULL components of lists, but dimnames
is a list and often some components are null and is therefore a bit
tricky to manipulate...
Peter
On Mon, Sep 20, 2010 at 7:39 PM, Joshua Wiley
On Tue, Sep 21, 2010 at 9:50 AM, qcshare qcsh...@gmail.com wrote:
Hello, everyone,
When I run R, I met:
error:cannot allocate vector of size 400Mb, My data is large.
What should I do?
Thanks, everyone.
How big is the RAM in your computer?
There are a few things you can try:
1. Before
this following code:
x-c(1,2,NA)
length(x)
returns 3, correctly counting numbers as well as NA's. How can I
exclude NA's from this count?
sum(!is.na(x))
Peter
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
On Mon, Sep 27, 2010 at 8:22 AM, Kennedy henrik.aldb...@gmail.com wrote:
Hi,
I want to perform a hierarchical clustering using the median as linkage
metric. As I understand it the function hcluster in package amap have this
option but it does not produce the results that I expect.
In the
On Mon, Sep 27, 2010 at 8:22 AM, Kennedy henrik.aldb...@gmail.com wrote:
Hi,
I want to perform a hierarchical clustering using the median as linkage
metric. As I understand it the function hcluster in package amap have this
option but it does not produce the results that I expect.
Also, if
On Mon, Sep 27, 2010 at 8:48 AM, Justin Fincher finc...@cs.fsu.edu wrote:
Howdy,
I have created a set of plots, but I wish to increase the dpi to 300
(instead of the default 72). From the documentation, I thought that
the res parameter to png should accomplish this, but it appears to
On Mon, Sep 27, 2010 at 9:34 AM, Jonas Josefsson
jo...@runtimerecords.net wrote:
I have a two-column table as follows where age is in the 1st column and the
number of individuals is in the 2nd.
age;no
1;21
2;31
3;9
4;12
5;6
You can use the following trick:
x = rep(age, no)
This repeats
On Tue, Sep 28, 2010 at 12:18 PM, Greg Snow greg.s...@imail.org wrote:
Ctrl-C works on some platforms, it would help us to help you if we knew which
OS you are using, which version of R you are using, and in some cases whether
you are using the GUI or Terminal version of R.
Hi,
I have an
On Tue, Sep 28, 2010 at 6:22 PM, Michael Larkin mlar...@rsmas.miami.edu wrote:
I am trying to get R to randomly select values from my dataset (i.e.
bootstrapping) with replacement. However, my attempts at this have been
unsuccessful. Here is a basic example of what I am doing:
I have a data
for (j in 1:n)
{
if (j%%2==0)
{
iRange = c(n:1)
} else
iRange = c(1:n)
for (i in iRange)
{
your code
}
}
Peter
On Wed, Sep 29, 2010 at 10:40 AM, cassie jones cassiejone...@gmail.com wrote:
Dear All,
I am trying to define a loop for a m*n matrix, where
On Wed, Sep 29, 2010 at 6:43 PM, Gundala Viswanath gunda...@gmail.com wrote:
I have a vector that looks like this:
foo
[1] o o o x o o o o o x x o x
How can we find the percentage of o and x in
that vector in R?
table(foo)/length(foo)
Peter
__
On Wed, Sep 29, 2010 at 1:27 PM, Jyotasana Gulati jgul...@ice.mpg.de wrote:
Hi,
I am have a data set of around 43000 probes(rows), and have to calculate
correlation matrix. When I run cor function in R, its throwing an error
message of RAM shortage which was obvious for such huge number of
On Wed, Sep 29, 2010 at 7:18 PM, Christian Schoder
schoc...@newschool.edu wrote:
hi R-users!
does anyone know how I can access/print only the first two digits of a
number? if i have the number 23732, i would like to get 23. if i have
355 i would like to get 35. if i have 4 i would like to get
.
Has any one ever used this package--coXpress??
Regards
..
Jyotasana
- Original Message -
From: Peter Langfelder peter.langfel...@gmail.com
To: Jyotasana Gulati jgul...@ice.mpg.de
Cc: r-help@r-project.org
Sent: Thursday, September 30, 2010 4:05:44 AM
Subject: Re: [R] cor
On Fri, Oct 1, 2010 at 10:51 AM, mlar...@rsmas.miami.edu wrote:
I calculated a large vector. Unfortunately, I have some measurement error
in my data and some of the values in the vector are erroneous. I ended up
wih some Infs and NaNs in the vector. I would like to filter out the Inf
and
Hi Mete,
I think you should look at the help for memory.limit. Try to set a
higher one, for example
memory.limit(16000)
(I think 16GB is what xenon will take).
Peter
On Fri, Oct 1, 2010 at 6:02 PM, Mete Civelek mcive...@mednet.ucla.edu wrote:
Hi Everyone,
I am getting the following error
If no-one replies with a better way, here's a way: under
POSIX-compliant systems, you can write a small C function and wrap it
in an R function.
The C program would be something like
#include unistd.h
void nProcessors(int n)
{
#ifdef _SC_NPROCESSORS_ONLN
long nProcessorsOnline =
On Wed, Oct 6, 2010 at 9:32 AM, Ralf B ralf.bie...@gmail.com wrote:
Can one create a variable through a function by name
createVariable - function(name) {
outputVariable = name
name - NULL
}
after calling
createVariable(myVar)
I would like to have a variable myVar
On Wed, Oct 6, 2010 at 9:32 AM, Ralf B ralf.bie...@gmail.com wrote:
Can one create a variable through a function by name
createVariable - function(name) {
outputVariable = name
name - NULL
}
after calling
createVariable(myVar)
I would like to have a variable myVar
#another simple function to update the value in a vector
update-function(index){
test[index]- 20
}
update(2)
test
#The update() function silently fails to accomplish the update
Replace the '-' by '-' and you'll be good to go if you call the
function from a global environment. More
you should close files that you do not use anymore. the maximum number
of open files is likely 4000 or so. Use close(file) before you open
the next one.
Peter
On Wed, Oct 6, 2010 at 4:55 PM, Yong Wang wangyo...@gmail.com wrote:
Dear List
I am running a loop downloading web pages and save the
I think you want something like this:
optimal.nSplit = rep(NA, 50) # This will hold the result
for (run in 1:50)
{
fit1 = rpart(...)
cpTable = fit1$cptable
bestRow = which.min(cpTable[, xerror]);
optimal.nSplit[run] = cpTable[bestRow, nsplit]
}
In any case, look at
?rpart
?printcp
From what I read, you want something like this:
myfunction-function(dataset,arg1,arg2)
{
func = match.fun(arg2)
argument = dataset[, match(paste(arg1,_test, sep=), names(dataset))]
result=func(argument)
return(result)
}
On Wed, Oct 13, 2010 at 9:28 AM, Manta mantin...@libero.it wrote:
On Wed, Oct 13, 2010 at 10:13 AM, Schwab,Wilhelm K
bsch...@anest.ufl.edu wrote:
Hello all,
I had a very strange looking problem that turned out to be due to unexpected
(by me at least) format changes to one of my data files. We have a small lab
study in which each run is represented by a
On Thu, Oct 14, 2010 at 5:21 PM, Paul Rigor (ucla) pr...@ucla.edu wrote:
Hi all,
I would like to use the fpc and cluster packages for clustering. However, I
would like to create a custom dissimilarity object using a library in
python. Has anyone attempted or know of a work-around for
I assume you mean regression of x on y...
here's the code:
missing = is.na(x)
predicted = predict(lm(x~y))
x[missing] = predicted[missing];
Should work but please check.
Peter
On Thu, Oct 14, 2010 at 10:14 PM, Jumlong Vongprasert
jumlong.u...@gmail.com wrote:
Dear all
I have data (x,y)
Hi all,
apologies if this has been answered before, I didn't find the answer
in the archives. I am putting together a package that I would like to
have optional functionality if another package is installed. In
normal, non-package code, I would simply write something like
if (require(qvalue))
{
If you didn't specify an external BLAS when you ran R configure
script, you are not using ATLAS. If you're not sure and you still have
the output of the configure script, at the end it'll say whether it
uses an external BLAS.
Alternatively, you may also want to generate two random 5000x5000
c concatenates all arguments. For example, c(c(0,1,2), c(3,4,5)) gives
a vector 0,1,2,3,4,5.
Another example:
c(list(a=c(0,1), b = c(2,3)), list(c = c(4,5), d = c(5,6)))
$a
[1] 0 1
$b
[1] 2 3
$c
[1] 4 5
$d
[1] 5 6
So instead of a list of two lists, you get a single list with 4 components.
)
# still works, from original list construction
x[3]
# but this doesn't work
x[4]
Cheers!
Nick
Peter Langfelder wrote:
c concatenates all arguments. For example, c(c(0,1,2), c(3,4,5)) gives
a vector 0,1,2,3,4,5.
Another example:
c(list(a=c(0,1), b = c(2,3)), list(c = c(4,5), d = c
Should illicit a multi-CPU response with R/ATLAS? If so, any
suggestions on how to tweak my install to get it working? Thanks!
--j
On Wed, May 26, 2010 at 3:17 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
If you didn't specify an external BLAS when you ran R configure
script
On Thu, May 27, 2010 at 9:43 AM, William Dunlap wdun...@tibco.com wrote:
-Original Message-
Unlike with vectors, with lists you don't have to specify
length and can add
as many list components as you want later The length of the list will
automatically adjust.
'Nonrecursive'
temp2 = tempr
temp2[temp20] = 0
HTH
On Fri, May 28, 2010 at 8:37 AM, ecvet...@uwaterloo.ca wrote:
I have a data frame with both positive and negative values, and I want to
make all the negative values equal zero, so i can eventually take an
average.
I've tried
temp2 - ifelse(tempr0, 0,
Well, your example matrix is symmetric, so row and column operations
naturally return the same values.
You may want to note though that if you apply your function to a matrix
along rows, the results will be stored in the __columns__ of the resulting
matrix. Thus, if you want to simply divide the
On Fri, Jun 4, 2010 at 1:44 PM, Ben Bolker bol...@ufl.edu wrote:
Eduardo J. Chica ejchica at gmail.com writes:
Hi I am having problems with the rendering of scientific symbols (mu and
degree) in my plots. Whenever I use these symbols they are rendered
changed (mu is changed to the
This issue is already in the Notes section of ?pdf. It remains to be seen
if the OP's problem was this exact one, since they didn't specify an
example.
aahhh, thank you for pointing this out. I never noticed this note.
Peter
__
c(as.matrix(data)) will not do it?
Peter
On Fri, Jun 4, 2010 at 5:47 PM, Nick Matzke mat...@berkeley.edu wrote:
Hi,
This can't be hard, but I can't find the solution. I have a 380x380 data
frame of numbers. I would like to turn it into a single column so I can do
e.g. hist and mean on it
On Mon, Jun 7, 2010 at 9:05 AM, sidahmed BENABDERRAHMANE
sidahmed.benabderrahm...@loria.fr wrote:
Dear all,
I have a problem when using some classification functions (Kmeans, PAM,
FANNY...) with a distance matrix, and i would to understand how it proceeds
for the positioning of centroids
To get the counts, assuming your data frame is called factors and it only
contains the 17 factors, you can do
n = nrow(factors)
aux = rep(1, n);
tab = tapply(aux, as.list(factors), sum);
example:
factors = matrix(sample(c(1:3), 3000, replace = TRUE), 1000, 3)
lfactors = as.list(data.fran =
apply(iris[, -5], 2, tapply, iris$Species, mean)
On Wed, Jun 9, 2010 at 3:43 PM, SH.Chou cls3...@gmail.com wrote:
Hi there:
I have a question about generating mean value of a data.frame. Take
iris data for example, if I have a data.frame looking like the following:
-
apply(test, 1, paste, collapse = ,)
On Tue, Jun 15, 2010 at 11:27 AM, Jonathan Greenberg
greenb...@ucdavis.edu wrote:
Folks:
Say I have a matrix:
test=matrix(c(1,2,3),nrow=10,ncol=3)
I would like to have an output character vector where each line is
row's values delimited by commas,
eval(parse(text=print(9**2)))
On Thu, Jun 17, 2010 at 12:32 PM, Johannes Huesing
johan...@huesing.name wrote:
Dear expRts,
I have a character string, say a - print(9**2). How do I execute
the contents of the string, parsed as R code? Do I have to open a
connection and use cat(a), and parse it
package::function
On Mon, Jun 21, 2010 at 6:29 AM, Filoche pmassico...@hotmail.com wrote:
Hi everyone.
I want to use 2 different functions (in 2 packages) that have same name. for
instance, if I call the function, it will use the one in the last called
package. Is there a way to specify
On Mon, Jun 21, 2010 at 4:18 PM, song song rprojecth...@gmail.com wrote:
May I ask how to initialize a list?
usually I will use result=list(0) to do this. is this right?
It works, but it is cleaner to use
results=list()
The difference is that list(0) will have one component that contains
On Wed, Jun 23, 2010 at 10:01 AM, Lorenzo Isella
lorenzo.ise...@gmail.com wrote:
Dear All,
I am using the plotrix library to plot some matrices.
I have a problem: some of my data are outliers, hence using a linear
color scale does not work very well (you would see too many cells having
a
On Thu, Jun 24, 2010 at 10:16 AM, Mike Williamson this.is@gmail.com wrote:
Hey everyone,
I've been using 'R' long enough that I should have some idea of what the
heck either expression() or eval() are really ever useful for. I come
across another instance where I WISH they would
On Thu, Jun 24, 2010 at 1:26 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
On 24/06/2010 4:08 PM, Lasse Kliemann wrote:
What is the best way in R to compute a sum while avoiding cancellation
effects?
Use sum(). If it's not good enough, then do it in C, accumulating in
extended
On Thu, Jun 24, 2010 at 1:50 PM, Duncan Murdoch
murdoch.dun...@gmail.com wrote:
On 24/06/2010 4:39 PM, Peter Langfelder wrote:
AFAIK the optimal way of summing a large number of positive numbers is
to always add the two smallest numbers
Isn't that what I said?
I understood that you
On Thu, Jun 24, 2010 at 3:16 PM, john polo jp...@mail.usf.edu wrote:
Dear R users,
I have a list of numbers such as
n
[1] 3000 4000 5000 3000 5000 6000 4000 5000 7000 5000 6000 7000
and i'd like to set up a loop that will keep track of the number of
occurences of each of the values that
On Wed, Jul 6, 2011 at 8:27 AM, Raquel Martinez Garcia
rmartin...@cnio.es wrote:
Hi,
I'm running a tutorial (Meta-analyses of data from two (or more) microarray
data sets), which use wgcna package. I have an error in the function
modulePreservation (it is below).
I'm using R2.13
Can you
On Mon, Jul 11, 2011 at 12:28 PM, Thomas S. Dye t...@tsdye.com wrote:
Aloha all,
I have an adjacency matrix for an acyclic digraph that contains
transitive relations, e.g. (u,v), (v,w), (u,w). I want a DAG with only
intransitive relations. Can someone point me to an R function that will
Hi Meeta,
yes, there was a bug in the package. Please install the newest version
and try again.
Best,
Peter
On Tue, Jul 12, 2011 at 1:20 PM, mistrm meeta.mis...@gmail.com wrote:
Hi Peter and Raquel
I am following the same tutorial and seem to have the same error appear and
I am using 30
Hi Paul,
I assume you are using the argument cutoff to specify the p-value
below which nodes are considered connected and above which they are
not connected.
I would use single linkage hierarchical clustering. If you have two
groups of nodes and any two nodes between the groups are connected
will run much faster.
Peter
On Thu, Jul 14, 2011 at 4:58 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
Hi Paul,
I assume you are using the argument cutoff to specify the p-value
below which nodes are considered connected and above which they are
not connected.
I would use single linkage
On Fri, Jul 15, 2011 at 2:05 PM, Data Analytics Corp.
w...@dataanalyticscorp.com wrote:
But then he apparently rescaled this 44x13
matrix so that the rows all sum to zero and the columns all sum to zero.
None of the row and column standard deviations are 1.0. This I can't see
how to do.
Don't know the answer to you first question, but for the \\ see below.
On Sat, Jul 16, 2011 at 7:19 PM, Sverre Stausland
john...@fas.harvard.edu wrote:
Unrelated to that problem, but related to gsub() is that I can't find
a way for gsub() to interpret the backslash as a character. In regular
On Sun, Jul 17, 2011 at 11:18 AM, christian krahforst
ckrahfo...@gmail.com wrote:
I have a data frame (gom) or a matrix of trace metal data and some other
observations from water column samples taken at sea (e.g., 19 samples
(rows), 19 variables)
I can calc. the rank individually from each
Hi all,
I encountered a problem when trying to read in an Illumina chip
annotation file. The offending file is large, so I zipped it up and
posted it at
http://www.genetics.ucla.edu/labs/horvath/CoexpressionNetwork/tmp/ProbeInfo_Expression.txt.bz2
Executing this:
annot =
On Fri, Jul 29, 2011 at 6:00 PM, Sarah Goslee sarah.gos...@gmail.com wrote:
Hi Peter,
I'm not going to look at your large file on what for me is Friday evening, but
the usual cause of that kind of problem is a single or double quote in the
text.
bingo! Setting quote = solved the problem.
On Tue, Aug 2, 2011 at 5:07 PM, John Sorkin jsor...@grecc.umaryland.edu wrote:
windows 7
R 2.12.1
Is there any easy way to determine if a sting contains nothing but blanks? I
need to check a series of strings of various length.
OneBlank -
TwoBlanks -
ThreeBlanks -
NoBlanks -
Hi all,
in my package I have a function with name plot.cor (this function is
inherited from another legacy package). According to CRAN package
checks reports, the check apparently thinks plot.cor is a method for
the plot generic (I hope I'm using the correct terminology).
checking Rd \usage
Sorry if this is a duplicate... my email is giving me trouble this evening...
On Tue, Aug 9, 2011 at 8:38 PM, Chris Howden
ch...@trickysolutions.com.au wrote:
Hi,
I’m trying to do a hierarchical cluster analysis in R with a Big Data set.
I’m running into problems using the dist() function.
Assuming you need the full distance matrix at one time (which you do not for
hierarchical clustering, itself a highly dubious method for more than a few
hundred points).
Apologies if this hijacks the thread, but why is hierarchical
clustering highly dubious for more than a few
hundred points?
On Wed, Aug 10, 2011 at 11:22 AM, Soyeon Kim yunni0...@gmail.com wrote:
Dear All,
I have vn variable
vn
[1] V300 V376
What I want to get is
300 376
as.numeric(substring(vn, 2))
HTH
Peter
__
R-help@r-project.org mailing list
On Wed, Aug 10, 2011 at 12:07 PM, Ken Hutchison vicvoncas...@gmail.com wrote:
Hello all,
I am using the clustering functions in R in order to work with large
masses of binary time series data, however the clustering functions do not
seem able to fit this size of practical problem. Library
On Mon, Aug 15, 2011 at 10:34 AM, Rebecca Gray atlas...@gmail.com wrote:
Hello all,
I have what I think is a simple question but I've been unable to solve it. I
have the following string:
A[states=1]:[rate=2]425, B[states=3]:[rate=5]500
I would like to combine the two expressions in the
On Fri, Aug 19, 2011 at 9:19 AM, David Winsemius dwinsem...@comcast.net wrote:
Copying list one what was sent in reply. Anybody have a better solution?
No sure my solution is better, but it avoids the integer conversion
and retains the /.
I wrote a function that padds entries of input
On Fri, Aug 19, 2011 at 11:11 AM, Rebecca Gray atlas...@gmail.com wrote:
Dear all,
I have what is a bit of a confusing question, so I hope that I can explain
clearly. Thank you for your help in advance.
I would like to do a replacement procedure on several strings, but the way
that I am
On Fri, Aug 19, 2011 at 11:50 AM, Liviu Andronic landronim...@gmail.com wrote:
Dear all
Is there an easy way to display only one half (top-right or
bottom-left) of a correlation matrix?
require(Hmisc)
rcorr(as.matrix(mtcars[ , 1:4]))
mpg cyl disp hp
mpg 1.00 -0.85 -0.85 -0.78
On Fri, Aug 19, 2011 at 12:32 PM, Liviu Andronic landronim...@gmail.com wrote:
On Fri, Aug 19, 2011 at 9:02 PM, Peter Langfelder
peter.langfel...@gmail.com wrote:
Use as.dist: here's an example.
Seems promising, but for one issue: I would like to keep the diagonal
and thus specify 'diag=T
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