I am new to R. Have a naive question about the boa package.
I loaded the package as instructed, and after entering
R boa.menu()
I could never got the ready prompt (R hung).
Can someone help? Thanks.
__
R-help@r-project.org mailing list
is there a way to do element-by-element multiplication as in Gauss
and MATLAB, as shown below? Thanks.
---
a
1.000
2.000
3.000
x
1.0002.0003.000
2.0004.0006.000
3.000
difficult to see R's internal logic, which, while quirky, is useful
at the end of the day.
Michael
PS - It's good form to cc the list at each step so others can follow
along and contribute when I say something wrong. It also helps you
get quicker answers.
On Nov 6, 2011, at 1:06 AM, Steven Yen
statistics for a dozen variables from a file that
appeared to reside in z:/R.
Am I not supposed to set the working directory by the line above
(which brings me to my preferred working directory each time I run R)?
At 06:05 PM 11/15/2011, Steven Yen wrote:
Can someone help me with this variable/data
Can someone help me with this variable/data reading issue?
I read a csv file and transform/create an additional variable (called y).
The first set of commands below produced different sample statistics
for hw11$y and y
In the second set of command I renameuse the variable name yy, and
sample
/2011, Sarah Goslee wrote:
Hi,
The obvious answer is don't use attach() and you'll never have
that problem. And see further comments inline.
On Tue, Nov 15, 2011 at 6:05 PM, Steven Yen s...@utk.edu wrote:
Can someone help me with this variable/data reading issue?
I read a csv file and transform
Is there a way to over-write a procedure (subroutine)?
I include a default procedure fixx in a list of procedures which are
compiled into a package. By default, the procedure deliver the data matrix x.
fixx - function(x){
result - list(x=x)
return(result)
}
In some applications, I have
then look at the assignInNamespace function in the utils
package (but note the warning in the description on the help page).
On Tue, Sep 2, 2014 at 12:45 PM, Steven Yen sye...@gmail.com wrote:
Is there a way to over-write a procedure (subroutine)?
I include a default procedure fixx in a list
I use the following command to write data to a .csv file:
write.csv(yxz,file=foo.csv)
And I get the following in the file, with one column appended to the file:
,fsp,fsec,cincome,
1,0,3,2.25,...
2,0,1,2.75,...
3,1,1,0.625,...
Question: is there a way to avoid the first column? Thanks.
Wonderful. It worked like charms and I love it! Thank you Don.
Steven
At 05:06 PM 9/24/2014, Don McKenzie wrote:
I believe you need to specify row.names = FALSE
See the help for write.table()
On Sep 24, 2014, at 2:00 PM, Steven Yen sye...@gmail.com wrote:
I use the following command
Hello
I read data with fortran format:
mydata-read.fortran('foo.txt',
c(4F10.4,F8.3,3F3.0,20F2.0))
colnames(mydata)-c(q1,q2,q3,q4,income,hhsize,
weekend,dietk,quart1,quart2,quart3,male,age35,
age50,age65,midwest,south,west,nonmetro,
Thanks to all.
Steven Yen
At 06:18 PM 9/30/2014, Nordlund, Dan (DSHS/RDA) wrote:
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Steven Yen
Sent: Tuesday, September 30, 2014 2:04 PM
To: r-help
Subject: [R] Reading text file
Hello
Any idea how to read a text file with fortran format, WITH MULTIPLE
RECORDS? My fortran format is as follows, and I do know I need to
change F7.4 to F7.0, and 2F2.0 to 2I2, etc.
I just have no idea how to handle the slash (/) which dictates a
jump to the next record in fortran. Thank you
Hello
Can someone help me with the following, specifically in judging
whether a matrix exists. I have trouble with the first line below. In
this case, matrix obj$hessian exists and is 74 x 74. I receive the
error message:
Warning message:
In all(w$hessian) : coercing argument of type 'double'
. Heiberger wrote:
all() takes a logical argument, not numeric. See ?all
I think you are looking for
is.null(obj$hessian)
If this isn't what you are looking for, please send a reproducible example
to the entire list.
Rich
On Sun, Oct 19, 2014 at 12:17 AM, Steven Yen sye...@gmail.com wrote:
Hello
Dear
I am interested in selecting rows and columns of a matrix with a
criterion defined by a binary indicator vector. Let matrix a be
a-matrix(1:16, 4,4,byrow=T)
a
[,1] [,2] [,3] [,4]
[1,]1234
[2,]5678
[3,]9 10 11 12
[4,] 13 14 15 16
23 29 35
[6,]6 12 18 24 30 36
(j-matrix(c(0,1,0,1,0,1)))
[,1]
[1,]0
[2,]1
[3,]0
[4,]1
[5,]0
[6,]1
((a[as.logical(j), as.logical(j)]))
[,1] [,2] [,3]
[1,]8 20 32
[2,] 10 22 34
[3,] 12 24 36
Steven Yen
At 02:49 PM 10/26
before and after. Thanks.
Steven Yen
---
out-round(cbind(me,se,t,p),digits)
colnames(out)-c(estimates,s.e.,|t-value|,p-value)
rownames(out)-rownames(me)
out
estimates s.e. |t-value| p-value
(Intercept) 0.223263 0.146167 1.527459 0.127173
sex 0.049830 0.039612 1.257973
Wonderful. Works great!
Steven Yen
At 11:52 AM 10/29/2014, Kevin E. Thorpe wrote:
On 10/29/2014 11:41 AM, Steven Yen wrote:
Hello
I am designing a regression printout, which works out nicely. Then, I
try to inject a column of characters to indicate a discrete regressor
with a dot
I like to remove from a data frame rows with labels containing
certain string, e.g., sex and rating. Below is a list of the data
frame and my failed attempt to the rows. Any clues? Thanks.
out
est se t p disc
p.(Intercept) 26.430 13.605 1.943 0.053
p.sex
or rating.
Bill Dunlap
TIBCO Software
wdunlap http://tibco.comtibco.com
On Sun, Nov 16, 2014 at 6:31 PM, Steven Yen
mailto:sye...@gmail.comsye...@gmail.com wrote:
I like to remove from a data frame rows with
labels containing certain string, e.g., sex
and rating. Below is a list of the data
My obj does not always come with a logical variable defined. So I do
my.foo - function(obj,df,digits=5){
if (!is.na(obj$spec$Fisher)) Fisher-obj$spec$Fisher
...
}
This works when Fisher is defined in/passed from obj. When it is
not, I get error:
Error in (!is.na(obj$spec$Fisher)) Fisher :
- ifelse(!(Fisher %in% names(obj$spec)), FALSE, obj$spec$Fisher)
Cheers,
Ben
On Dec 14, 2014, at 8:07 AM, Steven Yen sye...@gmail.com wrote:
My obj does not always come with a logical variable defined. So I do
my.foo - function(obj,df,digits=5){
if (!is.na(obj$spec$Fisher)) Fisher-obj$spec
How do I specify the type of regression in calling a procedure/
In the following I call the procedure to do a probit regression. Of
course, I can change probit into lm in procedure myreg to do a
linear regression.
My question is, how do I automate this (choice of lm or probit) in
calling
Dear
I use sm2vec from package corpcor to puts the lower triagonal entries
of a symmetric matrix (matrix A) into a vector. However, sm2vec goes
downward (columnwise, vector B), but I would like it to go across
(rowwise). So I define a vector to re-map the vector (vector C). This
works. But is
-1.6214086
No need to play with potentially error-prone index vectors; upper.tri
does that for you.
Hope this helps,
Peter
On Fri, Jan 30, 2015 at 3:03 PM, Steven Yen sye...@gmail.com wrote:
Dear
I use sm2vec from package corpcor to puts the lower triagonal entries of a
symmetric matrix (matrix
I like to multiple the first and second column of a 10 x 3 matrix by
100. The following did not work. I need this in an operation with a
much larger scale. Any help?
aa-matrix(1:30,nrow=10,ncol=3); aa
bb-matrix(c(100,100,1),nrow=1,ncol=3); bb
dim(aa)
dim(bb)
aa*bb
Results:
Thank you both. Both John and Peter's suggestions work great!!
At 06:17 PM 1/7/2015, John McKown wrote:
On Wed, Jan 7, 2015 at 5:05 PM, Steven Yen
mailto:sye...@gmail.comsye...@gmail.com wrote:
I like to multiple the first and second column
of a 10 x 3 matrix by 100. The following did not
work
to fix the wmean
routine some how so that I can call with
wmean(mydata,wt=weight)
Good to know there is a better way to initialize the vector Mean and and
a better list command. Thank you!
On 6/26/2015 2:39 AM, David Winsemius wrote:
On Jun 25, 2015, at 7:48 PM, Steven Yen wrote:
Thanks
places; though it may work fine in your test cases,
it is wrong to be used in generality e.g. inside a function you
provide for more general use,
and is best replaced with the use of inherits() / is()
everywhere out of principle.
Martin Maechler
ETH Zurich
--
Steven Yen
My e-mail alert:
https
Thanks! From this I learn the much needed class statement
if (class(wt)==character) wt - x[, wt]
which serves my need in a bigger project.
Steven Yen
On 6/23/2015 6:20 PM, boB Rudis wrote:
You can do something like:
aaa - function(data, w=w) {
if (class(w) %in% c(integer, numeric
Dear Members
I have a data frame as generated below. I like to be able to call a
function both with a vector and a vector (mydata$v1) in that data frame
(v1). The first call works, but the second does not. Can someone help me
with the second call? Thanks!!
---
How do I read a block of space-delimited numbers into a column vector
using the read.table command? Thank you.
--
Steven Yen
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
I have a line containing summation of four components.
# This works OK:
p-pbivnorm(bb,dd,tau)+pbivnorm(aa,cc,tau)-
-pbivnorm(aa,dd,tau)-pbivnorm(bb,cc,tau)
# This produces unpredicted results without warning:
p-pbivnorm(bb,dd,tau)+pbivnorm(aa,cc,tau)
I had trouble with matrix multiplication when a matrix reduces to a
vector. In the following, lines 1 and 2 work when matrices u and a are
both of order 2.
Lines 3 and 5 do not work (message is matrix not conformable) when u is (T
x 1) and a is (1 x 2) and This causes a problem for users of other
I need help with element-by-element division. Below, matrices a and c are
both 5 x 2 and element-by-element division works as (I) expected. What if
matrix is 1 by 2: to divide first column of a by b[1] and second column of
a by b[2]. I had to go around (two ways) to make it work. In Gauss, these
How do I judge if a matrix contain any NA or otherwise non-missing,
non-numerical?
In the following, I would like to deliver ONE logical of TRUE or FALSE,
rather than a 4 x 4 matrix containing TRUE or FALSE. Thank you.
a-matrix(1:16,nrow=4)
diag(a)-NA
a
[,1] [,2] [,3] [,4]
[1,] NA
Dear
How do you construct a lower triangular matrix from a vector.
I want to make vector
a <- 1:10
into a triangular matrix
1 0 0 0
2 3 0 0
4 5 6 0
7 8 9 10
Thank you!
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
'
command. This does not work; it complains about a function (fn below) not
defined.
Compiling the function into a library file does not work either (with all
sorts of error messages saying this and that not defined).
Steven Yen
fn <- function(beta){
f<-... (define f in this routine)
re
in to MaxLike
> 3 - fix the errors I got from making it a package. It does not lie when it
> tells you things are undefined and, who knows, they may need to be defined.
>
>
> On 03/10/2015 09:47, Steven Yen wrote:
>
>> Hi
>> I collect a list of calls to a package in a fu
or source it from inside probit.R. Thanks.
On Sat, Oct 3, 2015 at 4:47 AM, Steven Yen <sye...@gmail.com> wrote:
> Hi
> I collect a list of calls to a package in a function (routine) so that I
> do not need to repeat the same sets of codes from program to program. In
> the follo
ot;)), digits=10)
> V1 V2 V3 V4 V5 V6 V7
> 1 1950 0.61435 0.026834 0.087227 0.006821 0.180001 0.0456
>
>
> If I recall correctly, a dot in the format pushes the decimal point:
>
> > print(read.fortran(textConnection(txt), c("f5",
Dear fellow R users:
I am reading a data (ascii) file with fortran fixed format, containing
multiple records. R does not recognize fortran's record break (a slash).
I tried to do the following but it does not work. Help appreciated.
60
7/2016 2:21 PM, John McKown wrote:
> On Fri, May 27, 2016 at 12:56 PM, Steven Yen <sye...@gmail.com
> <mailto:sye...@gmail.com>>wrote:
>
> Dear fellow R users:
> I am reading a data (ascii) file with fortran fixed format, containing
> multiple re
I read a csv file (with read.csv) containing missing values (as shown
below). Is there a convenient way to set these NA into zeros?
Better yet, is there an option to assign zeros to these blank cells in
reading the csv file? Thank you!
NA -1 NA NA NA 1 NA
NA NA NA NA NA NA NA
NA
Hello
I am constructing a symmetric matrix with library "corpcor". In the
codes below, I am able to construct a symmetric matrix of order 3 and
4. However, the 5 x 5 matrix does not seem right? Help?
Thanks.
> library(corpcor)> r <- 1:3> rr <- vec2sm(r, diag = F)> rr <-
> rr[upper.tri(rr)]>
I like to compose a symmetric matrix in the pattern as shown below (for 3 x
3 and 4 x 4). For a symmetric matrix of order 5, the result does not seem
right. Help? It is possible to write a two-level do loop for the task, but
I suppose that is less efficient.
> library(corpcor)> r <- 1:3; r[1] 1
What is a good way to grep multiple strings (say in a vector)? In the
following, I grep ants, cats, and fox separately and concatenate them,
is there a way to grep the trio in one action? Thanks.
all<-c("ants","birds","cats","dogs","elks","fox"); all
[1] "ants" "birds" "cats" "dogs" "elks"
Dear R users:
> # p is a vector if length 10
> # a is a vector if length 3
> # I like to create a matrix with
> # the first column being p multiplied by a[1]
> # the second column being p multiplied by a[2]
> # the third column being p multiplied by a[3]
> # The following would do that:
Hi all, need help below. Thank you.
> # Matrix v is 5 x 3
> # Vector b is of length 3
> # I like to add b[1] to all element in v[,1]
> # I like to add b[2] to all element in v[,2]
> # I like to add b[3] to all element in v[,3]
> # as follows
> v<-matrix(0,nrow=5,ncol=3); v
[,1] [,2]
Dear all
In the grep command below, is there a way to identify only "age" and
not "age2"? Thanks.
> x<-c("abc","def","rst","xyz","age","age2")
> x
[1] "abc" "def" "rst" "xyz" "age" "age2"
> grep("age2",x)
[1] 6
> grep("age",x) # I need to grab "age" only, not "age2"
[1] 5 6
Also, I post
Can anyone tell me how to retrieve the response (dependent) variable
from a probit regression object (as much as model.matrix(obj)
retrieves the data matrix). Below is a self-runnable set of codes.
Thank you!
library(sampleSelection)
Dear all
In the grep command below, is there a way to identify only "age" and
not "age2"? In other words, I like to greb "age" and "age2"
separately, one at a time. Thanks.
x<-c("abc","def","rst","xyz","age","age2")
x
[1] "abc" "def" "rst" "xyz" "age" "age2"
grep("age2",x)
[1] 6
x)
[1] 6
> grep("age\\b",x)
[1] 5
> grep("age2$",x)
[1] 6
> grep("age$",x)
[1]
From: Jim Lemon <drjimle...@gmail.com>
Date: Wed, May 4, 2016 at 2:19 AM
Subject: Re: [R] Grep command
To: Steven Yen <sye...@gmail.com>
Does not:
abcplus<-c(&
like this.
Any help/insight would be appreciated.
On 7/20/2016 10:08 AM, Steven Yen wrote:
> On 7/19/2016 4:38 PM, John McKown wrote:
>> On Tue, Jul 19, 2016 at 3:15 PM, Steven Yen <sye...@gmail.com
>> <mailto:sye...@gmail.com>>wrote:
>>
>> I recentl
Thanks. I found the reason was Rtools does not run under the new version
of R. I had to go back to as early as R 3.0.2 (September 2013) to make
Rtools work.
Any idea for a go-around? Thanks.
On 7/19/2016 4:38 PM, John McKown wrote:
> On Tue, Jul 19, 2016 at 3:15 PM, Steven Yen <sye...@gma
I recently updated my R and RStudio to the latest version and now the
binary option in the "build" command in devtools stops working.
I went around and used the binary=F option which worked by I get the
.tar.gz file instead of the .zip file which I prefer.
Does anyone understand the following
test option for linearHypothesis in library(car) include "Chisq" and
"F". I prefer a simple t-test so that I can retrieve the standard error.
Any options other than linearHypothesis to test the linear hypothesis
(with 1 restriction/degree of freedom)?
> summary(ols1)
Coefficients:
,
> John
>
> -
> John Fox, Professor
> McMaster University
> Hamilton, Ontario
> Canada L8S 4M4
> Web: socserv.mcmaster.ca/jfox
>
>
>> -----Original Message-
>> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of
A is a 5 x 3 matrix and a is a 3-vector. I like to exponentiate A[,1] to
a[1], A[,2] to a[2], and A[,3] to a[3], and obtain the product of the
resulting columns, as in line 3.
I also accomplish this with lines 4 and 5. I like to have rowProducts(B)
but there is not so I came up with something
elopment version of the car package on R-Forge, which you should be able
> to install via install.packages("car", repos="http://R-Forge.R-project.org;).
> Then see ?linearHypothesis for more information.
>
> Best,
> John
>
>> -Original Message-
>
Also,
Is there a way to get the second command (hypothesis defined with
externally scalars) below to work? Thanks.
linearHypothesis(U,"0.5*eq1_DQ+0.3*eq2_DQ",verbose=T)
w1<-0.5; w2<-0.3
linearHypothesis(U,"w1*eq1_DQ+w2*eq2_DQ",verbose=T) # does not work
On 6/29/2016
I need help with what may be a simple option in R (or Rstudio)--to
receive an echo of a comment line.
Running the following two-line script in plain R,
# adding
1+2
I did get the echo:
> # adding
> 1+2
[1] 3
>
However, running the same lines in RStudio, the comment line does not
appear
I need help with gls{nlme}.
Specifically, I am estimating an equation with AR(1) using
maximum-likelihood. I am not understanding the correlationoption below.
Help appreciated.
===
library(nlme)
eq1<-log(chnimp)~log(chempi)+log(gas)+log(rtwex)+befile6+
affile6+afdec6
eed(76543211)
a<-matrix(rpois(20,2),nrow=10); a
a<-sqrt(w)*a; a
t(a)%*%a
On 1/4/2017 5:41 PM, Steven Yen wrote:
> I need help with gls{nlme}.
> Specifically, I am estimating an equation with AR(1) using
> maximum-likelihood. I am not understanding the correlationoption
lemented two of them (?) and it is unclear (to me) what you think
> the right answer for any of them is supposed to be.
> -- Sent from my phone. Please excuse my brevity. On June 7, 2017
> 8:50:55 PM PDT, Steven Yen <sye...@gmail.com> wrote:
>> I need to have all elements o
t not html, otherwise they can
> be mangled.
>
> Cheers
> Petr
>
>> -Original Message-
>> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Steven Yen
>> Sent: Tuesday, January 16, 2018 9:44 AM
>> To: r-help@r-project.org
>> Su
I ran two separate hours-long projects. Results of each were saved to
two separate .RData files.
Content of each includes, among others, the following:
me se t p sig
pc21.age 0.640 0.219 2.918 0.004 ***
pc21.agesq 0.000 0.000 NaN NaN
pc21.inc
Understood. In my case, a.RData and b.RData contain identical
variables/data, plus simulation outputs from separate runs. The codes
deliver what I need. Good to know the three lines work. Thank you.
On 1/16/2018 8:06 PM, Duncan Murdoch wrote:
> On 16/01/2018 6:33 AM, Steven Yen wrote:
>&g
I am running R-3.0.3 on RStudio 1.1.183. I have recently gotten the following
error message while saving an .RData file with the save.image command. I have
not had this problem until recently. Help appreciated.
===
Error in save.image("bope1a.RData") :
image could not be renamed and is left
I am trying to build an R package with Rtools version 3.5.0.4 along with
R-3.5.1
using the following sequence of commands:
File -> Open Project -> Build -> Build Binary Package
I received the following error message:
zip I/O error: No such file or directory
zip error: Temporary file failure
I have had trouble installing packages (e.g., car, aod) in some
computers (such as computers in the student lab) but no problem in my
own laptop.
Installation typically goes through, but after I got out and back in R
(and RStudios), the error message says "packages xxx not available".
That is,
I have trouble documenting an R package. In my .Rd file (sixth line below), I
have
uhat<-m%*%y
but when the package is built (successfully), the matrix multiplication part
does not show up in the documentation. The line become (missing %*% y)
uhat<-m
===
\examples{
x<-c(1,2,3,4,5)
I build binary data files into a library by placing the .rda files at the
proper \data sub-folder before building the library with the following
procedure:
1. File -> Open project
2. Build -> Build binary packages.
This has worked up to 3 .rda files.
Now, I add another .rda file to the folder.
David, Rui, and All:
Greetings.
1. I need a helping hand with the polygon statement below so that I can
have the area under the curve highlighted, between (z1,z2).
2. Is it possible to label the X-axis with in two scale, in the current
z-scale and another, say x = (z+5)*2?
Thank you.
z1<- -1
I need help with "apply". Below, I have no problem getting the column sums.
1. How do I get the sum of squares?
2. In general, where do I look up these functions?
Thanks.
x<-matrix(1:10,nrow=5); x
sum <- apply(x,2,sum); sum
[[alternative HTML version deleted]]
Is it possible to release the file destination after sending it to a pdf
file?
Below, line 3 send the graph to a pdf file.
I like to release the devise so that I can see result produced by line
for on the console (screen). Thanks.
x<-1:10
pdf("test1.pdf") # pdf {grDevices}
boxplot(x) # This
Can someone help me with polygon. The following codes are self-runnable
and mark a shaded area under the standard normal curve in the x-range
(-3,-1).
Is there a way to also mark the area in (1,3), at the same time.
That is, I want shaded areas in both tails. Thank you...
===
# Create data for
Thanks!!! It did wonders.
Steven
On 10/3/2018 9:39 AM, David Winsemius wrote:
>> On Oct 2, 2018, at 5:50 PM, Steven Yen wrote:
>>
>> Great. Thanks! It did wonders.
>> 1. Is there a way to suppress the obvious tick stops (-3,-2,-1,0,1,2,3)
>> and mark only the tick
Continue with
>
>
> polygon(-rev(cord.x), rev(cord.y), col = 'skyblue')
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 17:25 de 02/10/2018, Steven Yen escreveu:
>> Can someone help me with polygon. The following codes are self-runnable
>> and mark a shaded area un
How do I print a matrix running a procedure? In the code below, I print
with the cat command and get a vector (from A and C).
A<-matrix(rpois(16,lambda=5),nrow=4,byrow=T)
B<-diag(4)
try5<-function(A,B){
C<-A+B
cat("\nA =",A,"\nC = ",C)
structure(list(A=A,B=B,C=C))
}
v<-try5(A,B)
v$C
--
t;\nC = ")
> print(C)
> structure(list(A=A,B=B,C=C))
> }
>
> HTH,
> Eric
>
>
> On Sat, Dec 22, 2018 at 4:32 PM Steven Yen <mailto:st...@ntu.edu.tw>> wrote:
>
> How do I print a matrix running a procedure? In the code below, I
> print
&g
a base function try() so that's not a great
> name for test functions.
>
> Sarah
>
> On Tue, Dec 25, 2018 at 8:47 AM Steven Yen <mailto:st...@ntu.edu.tw>> wrote:
>
> I would like to suppressed printing of retrievable results in a
> procedure and to print only
I have known from the old days to set a random seed of a LARGE ODD
NUMBER. Now I read instructions of set.seed and it requires ANY INTEGER.
Any idea? Or, does it matter. Thanks.
--
st...@ntu.edu.tw (S.T. Yen)
[[alternative HTML version deleted]]
I would like to suppressed printing of retrievable results in a
procedure and to print only when retrieved.
In line 10 below I call procedure "try" and get matrices A,B,C all
printed upon a call to the procedure. I get around this unwanted
printing by calling with v<-try(A,B) as in line 11.
I like to print a vector, wrapped by rows of 10.
Below the first command below works for 20 numbers.
The second command is ugly. How can I print the 25 numbers into 2 rows
of ten plus a helf row of 5? Thanks.
> x<-1:20; matrix(x,nrow=2,byrow=T)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
I install package using either the command line or Tools -> Install
packages... (in RStudio) and get a non-fatal message saying...
Installing package into ‘C:/Users/xuhaer/Documents/R/win-library/3.5’
(as ‘lib’ is unspecified)
I know it is not a fatal message. But, is there a way to do a cleaner
Great! Thanks.
On 5/15/2019 7:00 PM, Rui Barradas wrote:
> Hello,
>
> What's wrong with
>
> test <- function(x){
> table <- matrix(x, nrow = 4)
> cat("\nTable:\n")
> print(table)
> invisible(list(table = table))
> }
>
>
> Hope this h
Dear all,
I did all this work with older R (R-3.5.3.patched and older)
but now with R3.6 I cannot replicate the results.
Below I sample 60 observations from 1:500 using the sample command with
a random seed of 123. I get different results. Advice appreciated.
Steven Yen
> # Run under R-3.
> j<-sample(1:length(x),size=60); y<-x[j]
> summary(j)
>
>
> Now I get the results you got udner the old R.
>
> Best,
> Uwe Ligges
>
>
>
> On 21.06.2019 18:39, Steven Yen wrote:
>> Thanks. Somewhat of a mystery. The older version I had was
>&
Unhappy but thanks.
Steven
On 6/22/2019 1:13 AM, Uwe Ligges wrote:
>
>
> On 21.06.2019 19:09, Steven Yen wrote:
>> Now I see that results were replicated but running RNGversion
>> I get a warning message. Isn't there a way to do this clean?
>
> Well, the old RNG is kno
Thanks. Somewhat of a mystery. The older version I had was R-3.5.3patched.
I cannot get the RNGversion command to run. Can you help? Thanks.
On 6/22/2019 12:25 AM, Uwe Ligges wrote:
> See the NEWS, the RNG has been changed, use RNGversion
>
> On 21.06.2019 18:10, Steven Yen wrote:
&g
Dear All,
I would like to get a matrix (table) printed in a procedure, as
attempted below. Please help. Thanks.
test<-function(x){
table<-matrix(x,nrow=4)
cat("\nTable:\n",table)
invisible(list(table=table))
}
x<-1:20
test(x)
--
st...@ntu.edu.tw (S.T. Yen)
[[alternative HTML
Since updating to R3.6.1., I have received a WARNING message saying
Rtools is required.
I get the same message installing online from CRAN and from a .zip file.
It looked like installation still went through in both cases, BUT,
Another student installed a .zip file and received the following
Can someone help me understand why Rtools is needed when installing a
package from CRAN, and from a zipped file? What's the point?
On 9/14/2019 10:29 PM, Steven Yen wrote:
> Since updating to R3.6.1., I have received a WARNING message saying
> Rtools is required.
> I get the sam
.
Thank you.
Steven Yen
===
> install.packages("C:/Users/Bonnie/Desktop/yenlib1_1.1.0.zip", repos =
NULL, type = "win.binary")
WARNING: Rtools is required to build R packages but is not currently
installed. Please download and install the appropriate version of Rtools
be
I have a data frame containing two variables: year and rate (shown below).
Which function can I use to plot rate (y-axis) against year (x-axis)?
There will be more columns of rate later on.
Thank you.
year rate 1 1993 0.608 2 1994 0.622 3 1996 0.623 4 1998 0.647 5 2000
0.646 6 2002 0.625 7 2004
I have a data frame containing two variables: year and rate (shown below).
Which function can I use to plot rate (y-axis) against year (x-axis)?
There will be more columns of rate later on.
Thank you.
year rate 1 1993 0.608 2 1994 0.622 3 1996 0.623 4 1998 0.647 5 2000
0.646 6 2002 0.625 7 2004
I had to use an older version of R (as old as R3.0.3) for a reason. I
myself have no problem installing a package built under a newer version,
but my student (who also installed R3.0.3) could not install the package
(newer version). Had an error message saying package x is not
available
Thanks. Updating RStudio to 1.2.5042 did fix the problem. Thank you!
On 2020/4/28 下午 11:30, Duncan Murdoch wrote:
On 28/04/2020 11:16 a.m., Steven Yen wrote:
Thanks. Can you kindly tell me what to read to do it the "standard way"?
Start with ?INSTALL, and find more details in the
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