Dear R-family,
I made a distance matrix of about 2000 stations. its extremely hard to
visualize the details of that matrix. I heard that there is a way in R to
represent the details of distance matrix graphically. more precisely, different
sections of our distance matrix can be presented in
365 419 420 346 472 489
A.K.
From: eliza botto eliza_bo...@hotmail.com
To: smartpink...@yahoo.com smartpink...@yahoo.com
Sent: Thursday, January 10, 2013 9:13 AM
Subject: merging command
Dear Arun,
i need you expertise to merge
Dear useRs,
I have a very basic question. I have a distance matrix and i skipped the upper
part of it deliberately. The distance matrix is 1000*1000. Then i used min
command to extract the lowest value from that matrix. Now i want to know what
is the location of that lowest element? More
Associate Professor of Anthropology
Texas AM University
College Station, TX 77843-4352
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Friday, January 11, 2013 4:21 PM
To: dcarl...@tamu.edu
Cc: 'eliza botto'; r-help@r-project.org
Subject
Dear useRs,
Sorry for such a stupid question. But i cant live without asking it. Actually,
I was going through copula package in R. I needed to know that if there is a
way in R to calculate the emipirical copula density between two random
variables and plot it like the way we do in
Dear R family,
I want to calculate the joint probability (distribution) of two random
continuous variables X and Y.
Could to please tell me how to do it?Thanks in advance..
elisa
[[alternative HTML version deleted]]
Dear R-user,
I have two separate independent events. More precisely, i have data of
discharged patients from two separate hospitals on each day of a certain year.
For each hospital i calculated the non-exceedance probability by using weibull
plot position which should be marginal probability
Dear useRs,
With the following set of command i managed to create the copula density
library(MASS) library(evd) X-matrix(sample(1:3000), ncol=2)
U=cbind(rank(X[,1])/(nrow(X)+1),rank(X[,2])/(nrow(X)+1))
mat1=kde2d(U[,1],U[,2],n=150)
Dear UseRs,
How can i connect my FTN95 fortran compiler with R in window 7?Thanks in
Advance,
Elisa
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Dear R users,[IF THE FORMAT OF MY EMAIL IS NOT CLEAR, I HAVE ATTACHED A TEXT
FILE FOR A CLEAR VIEW]
I would like to use the R output file in Fortran. my file Is exactly in the
following format.
ELISA/BOTTO wATER INN
FROM 1900 11 1 TO 1996 12 31
1901.11. 1 447.000
1901.11. 2
a single character.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 2/11/13 8:41 AM, eliza botto eliza_bo...@hotmail.com wrote:
Dear R users,[IF THE FORMAT OF MY EMAIL IS NOT CLEAR, I HAVE ATTACHED
Dear useRs,
I have a matrix in the following form
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11]
1 1 3 2 3 1 1 2 3 3 2
and following is my desired output (combining the column headers, having same
Dear XpeRts,
I prepared a no qoute Character string by the following command
s-noquote(paste (b1, collapse=,))
where, b1 is the vector of 24 intergers.
dput(b1)
c(1L, 2L, 6L, 7L, 12L, 16L, 17L, 20L, 21L, 23L, 25L, 34L, 46L, 48L, 58L, 64L,
65L, 68L, 82L, 97L, 98L, 101L, 113L, 115L)
@r-project.org
On Thu, Mar 7, 2013 at 11:02 AM, eliza botto eliza_bo...@hotmail.com wrote:
Dear XpeRts,
I prepared a no qoute Character string by the following command
s-noquote(paste (b1, collapse=,))
where, b1 is the vector of 24 intergers.
dput(b1)
c(1L, 2L, 6L, 7L, 12L
, eliza botto eliza_bo...@hotmail.com wrote:
Thankyou very much M. Weylandt. i was actually more interested in knowing
about the error.
Let's talk you through it then:
As you said before you have
b1 - c(1L, 2L, 6L, 7L, 12L, 16L, 17L, 20L, 21L, 23L, 25L, 34L, 46L,
48L, 58L, 64L, 65L, 68L
Dear R users,
You can literally safe my
life my telling me the solution of my problem. I have created matrix of a data
frame with 3 columns, with each column representing data of different year.
2
1
5
3
4
4
4
3
Dear R users,
is there a way in R to calculate normal reduced variate??
eliza
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: r-help@r-project.org
To: eliza_bo...@hotmail.com
On Jun 3, 2012, at 17:57 , eliza botto wrote:
Dear R users,
is there a way in R to calculate normal reduced variate??
Yes. It depends on what you mean, though. AFAICT reduced is just what
others call standard normal (mean 0
for each station, on same coordinate
axis.
Kindly
help us on that. We are all very new to R.
Eliza
botto
Waters
Inn
CC: r-help@r-project.org
From: dwinsem...@comcast.net
To: eliza_bo...@hotmail.com
Subject: Re: [R] Log-normal probability plot
Date: Sun, 3 Jun 2012 13:11:35 -0400
stricktly want normal reduced variant on
x-axis.
i hope you will cooperate.
eliza botto
waters inn
Date: Mon, 4 Jun 2012 11:54:11 +1000
To: r-help@r-project.org
From: mac...@northnet.com.au
Subject: Re: [R] Variate
Hi Eliza
You will not want 1 panel with 96 lines - too confusing after about
365 readings and some have 366(due to leap
year). Now I want to split lists into two different matrices, one containing
leap years and other with normal years.
I
hope you will be kind enough to help me as you did before.
Eliza
Botto
Waters
Inn
Date: Mon, 4 Jun 2012 10:51:49 +0100
From
-06-2012 21:41, eliza botto escreveu:
Dear Rui Barradas, Mackay and all R Users,
Thankyou
very much for your reply. You helped me a lot. I got what I wanted. I just
want
one more favor from you, if you could.
Suppose
I have certain number of lists of data frame, say 50. Each
, length)
i1 - which(xlen == 365)
i2 - which(xlen == 366)
mat365 - matrix(unlist(x[i1]), nrow=365)
mat366 - matrix(unlist(x[i2]), nrow=366)
Hope this helps,
Rui Barradas
Em 04-06-2012 22:46, eliza botto escreveu:
i realy appreciate your concern..
here is a small piece of my data
Dear R users,
we generally apply approx() command to a list data. how can we apply this
command to a matrix, so that we can approximate 366 readings from certain
number of each column over 365 intervals??
hope i am clear in my statement.
eliza botto
From: eliza_bo...@hotmail.com
of a matrix, over 365
days.
hope i am clear in my statement.
eliza botto
From: eliza_bo...@hotmail.com
To: ruipbarra...@sapo.pt
Date: Mon, 4 Jun 2012 22:13:10 +
CC: r-help@r-project.org
Subject: Re: [R] Spliting Lists into matrices
dear rui,
lots of hugs for you
of a matrix, over 365
days.
hope i am clear in my statement.
eliza botto
From: eliza_bo...@hotmail.com
To: ruipbarra...@sapo.pt
Date: Mon, 4 Jun 2012 22:13:10 +
CC: r-help@r-project.org
Subject: Re: [R] Spliting Lists into matrices
dear rui,
lots
Dear Gunter Berton and all,
As
you can see, my data has three lists each containing 366 entries. I converted
them into the matrix. I now want to approx./interpolate 366 entries over 365
intervals, Which means I want to have a matrix with 365 entries.
I
used
approx(matrix,
Dear Rui,
i am greatful for everything you did. bret advised me to use dput(), which i
did. yes! i forgot to complement him. i literally feel sorry for that. i hope
you wont mind and continue extending your help.
regards and love for every one
eliza botto
waters inn
Date: Tue, 5 Jun 2012 12
Dear R Users,
Could you please help me on the following issue?
I have a real large yearly data set. For each year I have
365 flow values. Some of the flow values are not known and thats why you will
see NA written in those slots. I wanted to know, is there a way that I can
estimate those
Dear R users,
is there a package in R, where one can use modified ward's method for
distance measurement??
thnx in advance
regards
eliza
[[alternative HTML version deleted]]
__
R-help@r-project.org
: maitra.mbox.igno...@inbox.com
To: r-help@r-project.org
Subject: Re: [R] modified ward's method
Sorry but what is modified Ward's method? I am guessing this has to do
with hierarchical clustering.
Ranjan
On Fri, 14 Sep 2012 16:09:00 + eliza botto
eliza_bo...@hotmail.com wrote:
Dear R
fustrating.
kind regards
eliza botto
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PLEASE do read the posting guide http://www.R-project.org
Dear R users,
i have a matrix with 31 rows and 444 columns and i want to extract every 37th
column of that matrix starting from 1. more precisely i want to select columns
1, 38,75, 112 and so on. then doing the same by starting from column number
2(2,39,76,113...).
i know that there is a
work its magic!
To concretize:
x - 1:100
x[c(TRUE, rep(FALSE, 4))]
Cheers,
Michael
On Tue, Sep 18, 2012 at 3:55 PM, eliza botto eliza_bo...@hotmail.com wrote:
Dear R users,
i have a matrix with 31 rows and 444 columns and i want to extract every
37th column of that matrix
thankyou Berend.
regards
eliza
Subject: Re: [R] extracting column and regular interval in R
From: b...@xs4all.nl
Date: Tue, 18 Sep 2012 17:43:15 +0200
CC: r-help@r-project.org
To: eliza_bo...@hotmail.com
On 18-09-2012, at 16:55, eliza botto wrote:
Dear R users,
i have
, Sep 18, 2012 at 3:55 PM, eliza botto eliza_bo...@hotmail.com
wrote:
Dear R users,
i have a matrix with 31 rows and 444 columns and i want to extract every
37th column of that matrix starting from 1. more precisely i want to
select columns 1, 38,75, 112 and so on. then doing
Dear UseRs,
i have a matrix of 365 rows and 444 columns. i drew each column of this matrix
against the number of days in a year, which are obviously 365. now i have 444
curves and i want to Use Fourier analysis for the approximation of the average
values.
does anyone know how to do it?
any
in no overlapped the original
curves.
can any1 advise me what to do?
thanks in advance for you time.
eliza botto
[[alternative HTML version deleted]]
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https
Dear Arun, Rui and David,
thankyou very much. i learnt alot from your replies.
eliza botto
Date: Fri, 21 Sep 2012 18:58:18 -0700
From: smartpink...@yahoo.com
To: ruipbarra...@sapo.pt
CC: r-help@r-project.org
Subject: Re: [R] efficient overlapping average curve on original curves
HI
Dear useRs,
does anyonw now how to avoid [ reached getOption(max.print) -- omitted 138
rows]. i read from the R forum that it can be avoided by increasing the
'max.print' option as much as i like, but i dnt know, how??
need your help on it.
regards
eliza
to access and set the max.print option, and
all the other options that R has.
Sarah
On Mon, Sep 24, 2012 at 1:08 PM, eliza botto eliza_bo...@hotmail.com wrote:
Dear useRs,
does anyonw now how to avoid [ reached getOption(max.print) -- omitted
138 rows]. i read from the R forum that it can
Dear useRs,Is there a command or package in R to do heirarchical clustering by
modified ward method??regardseliza
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Dear useRs,
I have a matrix with 38 columns and 365 rows. what i want to do is the
following.
1. subtracting from each column, first itself and then all the remaining
columns. More precisely, from column number 1, i will first subtract
itself(column 1) and then the remaining 37 columns.
,sum
#or
res1-sapply(1:ncol(mat1), function(i) mat1[,i]-apply(mat1,1,sum))
#or
res1-mapply(FUN=function(i) mat1[,i]-rowSums(mat1), 1:ncol(mat1))
A.K
- Original Message -
From: eliza botto eliza_bo...@hotmail.com
To: r-help@r-project.org r-help@r-project.org
Cc:
Sent
Dear useRs,
i have a matrix X and i generated a distance matrix of X, let us call it Y. I
did hierarchical clustering of Y and got some results. I just wanted to know
that can i use the same distance matrix Y in Kmeans clustering? If not, then
how can i use my own distance matrix for kmeans
Dear useRs,
i am using NbClust to determine appropriate number of cluster for hclustering.
i am consistently getting the following error
Error in if (is.na(n) || n 65536L) stop(size cannot be NA nor exceed 65536)
:
missing value where TRUE/FALSE needed
Does any one know where i am
, 2012 at 4:37 PM, eliza botto eliza_bo...@hotmail.com wrote:
Dear useRs,
i am using NbClust to determine appropriate number of cluster for
hclustering. i am consistently getting the following error
Error in if (is.na(n) || n 65536L) stop(size cannot be NA nor exceed
65536
Dear useRs,
1.how to calculate single median value for two columns of a matrix?
2.i have a matrix of 16 columns and 365 rows, how to calculate median
between columns 1 and 16, 2 and 16, 3 and 16, 4 and 16, 5 and 16 till 15th
column. is there a loop command to do the said operation?
,] 212.0
#[7,] 228.5
#[8,] 233.0
#[9,] 182.5
#[10,] 239.5
#[11,] 233.5
#[12,] 220.0
#[13,] 235.0
#[14,] 259.0
#[15,] 227.0
A.K.
- Original Message -
From: eliza botto eliza_bo...@hotmail.com
To: r-help@r-project.org r-help@r-project.org
Cc:
Sent: Monday, October 15
Dear useRs,
i have vectors of about 27 descriptors, each having 703 elements. what i want
to do is the following 1. i want to do regression analysis of these 27 vectors
individually, against a dependent vector, say B, having same number of
elements.2. i would like to know best 10 regression
now. reply like yours, simply wont help. anyway, thanks for
your advice.
eliza
Date: Fri, 26 Oct 2012 16:36:27 -0700
From: ehl...@ucalgary.ca
To: eliza_bo...@hotmail.com
CC: r-help@r-project.org
Subject: Re: [R] regression analysis in R
On 2012-10-26 13:00, eliza botto wrote:
Dear useRs
Dear useRs,i am applying mantel test to find the correlation between distance
matrices, by ade4 package. some of the correlations, although given me
r-values, have shown following warning message..
In is.euclid(m2) : Zero distance(s)
i wanted to know that why has this message prompted? although
Dear useRs,i have two distance matrices A and B. The distances in A are linked
with distances in B. What i want to do is the following...There are some points
in A where distances are zero(those points are apart from usual diagonal of
zero values).Whereas, in B the distances at those points are
= 4)
B - matrix(1:16, ncol = 4)
zeros - which(A == 0, arr.ind = TRUE)
B[zeros] - 0
Hope this helps,
Rui Barradas
Em 19-05-2013 22:05, eliza botto escreveu:
Dear useRs,i have two distance matrices A and B. The distances in A are
linked with distances in B. What i want to do
...@yahoo.com
To: eliza botto eliza_bo...@hotmail.com
Cc: R help r-help@r-project.org
Sent: Sunday, May 19, 2013 5:48 PM
Subject: Re: [R] coping zeros from matrix to another
May be this helps:
set.seed(28)
mat1- matrix(sample(0:50,20,replace=TRUE),nrow=5)
A- dist(mat1)
A[2:4]- 0
Dear useRs,
i have the following data arranged in three columns
structure(c(0.492096635764151, 0.42688044914, 0.521585941816778,
1.66472272302545, 2.61878329527404, 2.19154489521664, 0.493876245329722,
0.4915787202584, 0.889477365620806, 0.609135860199222, 0.739201878930367,
Dear useRs,If i have a matrix, say, 12 rows and 6 columns. The columns are
continuous. I want to find the index of maximum values and the actual maximum
values. The maximum values in each column are the highest values and the values
greater than or equal to 80% of the maximum value. Moreover,
...@xs4all.nl
Date: Fri, 24 May 2013 12:36:47 +0200
CC: r-help@r-project.org
To: eliza_bo...@hotmail.com
On 24-05-2013, at 12:24, eliza botto eliza_bo...@hotmail.com wrote:
Dear useRs,If i have a matrix, say, 12 rows and 6 columns. The columns are
continuous. I want to find the index
that the result comes with the maximum first and the others follow.
Hope this helps,
Rui Barradas
Em 24-05-2013 11:41, eliza botto escreveu:
There you go!!!
structure(c(0.706461987893674, 0.998391468394261, 0.72402995269242,
1.70874688194537, 1.93906363083693, 0.89540353128442
:40, eliza botto escreveu:
Dear Rui,Thankyou very much for your help. just for my own knowledge what
if want the values and index, which are less than or equal to 80% of the
maximum value other than those in the neighbors?? like if maximum is in row
number 5 of any column then the second
*x[imx])
values - x[index]
list(index = index, values = values)
}
apply(mat, 2, fun2)
Rui Barradas
Em 24-05-2013 16:23, eliza botto escreveu:
Dear Rui,
I infact wanted to have something like the following..
suppose the columns are
structure(c(0.706461987893674
.
- Original Message -
From: eliza botto eliza_bo...@hotmail.com
To: Berend Hasselman b...@xs4all.nl
Cc: r-help@r-project.org r-help@r-project.org
Sent: Friday, May 24, 2013 6:41 AM
Subject: Re: [R] Continuous columns of matrix
There you go!!!
structure(c(0.706461987893674
- which(x = 0.8*x[imx])
values - x[index]
list(index = index, values = values)
}
apply(mat, 2, fun2)
Rui Barradas
Em 24-05-2013 16:23, eliza botto escreveu:
Dear Rui,
I infact wanted to have something like the following..
suppose the columns are
structure(c
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
Of eliza botto
Sent: Friday, May 24, 2013 2:10 PM
To: ruipbarra...@sapo.pt; r-help@r-project.org
Subject: Re: [R] Continuous columns of matrix
Dear Rui,
Regarding
Value
1 5 1.463772
211 1.494151
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf
Of eliza botto
Sent: Friday, May 24, 2013 2:10 PM
To: ruipbarra
IndexValue
1 5 1.463772
211 1.494151
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf
Of eliza botto
Sent: Friday, May 24, 2013 2:10 PM
1.939064
212 1.791503
$`2`
IndexValue
1 5 1.508740
211 1.670409
$`3`
IndexValue
1 5 1.463772
211 1.494151
$`4`
IndexValue
112 2.245474
$`5`
IndexValue
1 6 1.592817
A.K.
From: eliza botto
)
ret
}
}
It does require a test for all of x being above the threshold, which f didn't
need. You could put the test in f and take it out of fCyclic.
Again, use apply() if you to want to run it over each column.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
From: eliza botto
.
From: eliza botto eliza_bo...@hotmail.com
To: smartpink...@yahoo.com smartpink...@yahoo.com
Sent: Saturday, May 25, 2013 9:17 PM
Subject: RE: QA
thanks arun,
i dont think thANKyou is enough for wat u did. anyway, there is slight
modification that i want to ask to understand the codes
Dear UseRs,I need to know that is there a way in R for a 3D regression
analysis?i actually have a data in 3 dimensional space showing differences
between regimes in 3D space and i want to do its regression analysis with
another data which is also in 3D space.
thanks in advance for your help,
Dear R Users,i am very new to R. I want your help on an issue regarding
distance matrix and cluster analysis
i had discharge data of 4 rivers(a,b,c,d) in 4 vectors each having 364 values
dput(qmu)structure(list(a = c(0.26, 0.25, 0.25, 0.25, 0.24, 0.23, 0.22, 0.21,
0.21, 0.21, 0.2, 0.19, 0.19,
in
advance
Regards
Eliza botto
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PLEASE do read the posting guide http://www.R-project.org
in advance
Eliza Botto
dput(Eliza)structure(list(All.index = structure(c(2, 3, 4, 5, 6, 7, 8, 9, 10,
11, 12, 13, 14, 15, 1.57420409872312, 18.4369535290079, 0.575306409776012,
0.154801385171855, 47.0366288760456, 0.445872832260952, 0.455568929239984,
12.5788269491759, 0.0386469849302515
Dear R-Family,
I have just downloaded a massive data file from internet
(AphroJP_62STN_V1005.1900.gz). Apparently, the file is compressed with .gz.
When I uncompressed
it, the file was saved in the name (AphroJP_62STN_V1005.1900) of unknown
format. How can I open it in R?
thankyou very much
, eliza botto eliza_bo...@hotmail.com wrote:
Dear R-Family,
I have just downloaded a massive data file from internet
(AphroJP_62STN_V1005.1900.gz). Apparently, the file is compressed with .gz.
When I uncompressed
it, the file was saved in the name (AphroJP_62STN_V1005.1900) of unknown
the gridded
format, I used:
readBin(fid, numeric(), n=1e8, size=4, signed=TRUE, endian='little')
where file is the connection created with file()
Hope this helps,
Pascal
On Tue, Mar 18, 2014 at 4:06 AM, eliza botto eliza_bo...@hotmail.com wrote:
Dear R-Family,
I have just downloaded
points you need, with the coordinates.
HTH
Pascal
On Tue, Mar 18, 2014 at 9:21 PM, eliza botto eliza_bo...@hotmail.com wrote:
Hi Pascal,
Your code worked out perfectly but I have one question though. You wrote
that you did not use stations. What if I want to read stations as i am
Dear R-Family,
I have a data-set of the following format. I am only presenting a part of it.
DateA B C
D
1-Jan-61
0.00
1.27
8.128
0.25
2-Jan-61
6.10
9.144
94.742
=TRUE,stringsAsFactors=FALSE)
res -á as.data.frame(apply(dat[,-1],2,FUN=function(x) {x1
-dat[,1][is.na(x)]; x2 - max(colSums(is.na(dat[,-1]))); if(length(x1) x2)
c(x1, rep(,x2-length(x1))) else x1}),stringsAsFactors=FALSE)
A.K.
On Wednesday, March 19, 2014 2:39 PM, eliza botto
Dear R family,
I am trying to read a real large dataset in R (~ 2Gb). Its in binary format.
When i tried to read it by using following command
readBin(DAT.dat.nc, numeric(), n=9e8, size=4, signed=TRUE, endian='little')
I got the following error
Error: cannot allocate vector of size 5.2 Gb
I have
Dear R-family,
I want to draw a map of the world with 0.5 degree*0.5 degree resolution and
then want to extract the geographical coordinates of my beloved country Ireland
in the same resolution.
I hope there is a way of doing it in R.
Thank you very much in advance,
Eliza
Dear useRs,
I have two column vectors of different lengths say x=1,2,3,4,5,6,7,8 and
y=1,2,3,4,5. I wanted to plot them by using points() command over an already
existed image but got an error, Error in xy.coords(x, y) : 'x' and 'y' lengths
differ.What i actually wanted to do was to plot the
To: eliza_bo...@hotmail.com
CC: r-help@r-project.org
Hi Eliza,
Perhaps the following?
matpoints(t(dat), type = 'l')
HTH,Jorge.-
On Sat, Mar 22, 2014 at 10:18 PM, eliza botto eliza_bo...@hotmail.com wrote:
Dear useRs,
I have two column vectors of different lengths say x=1,2,3,4,5,6,7,8 and
y
.
If I understand correctly, the following will do:
x - 1:8y - 1:5
matrix(apply(expand.grid(x = y, y = x), 1, function(r) paste0((, r[1], ,,
r[2], ))), ncol = length(x))
Best,
Jorge.-
On Sat, Mar 22, 2014 at 10:37 PM, eliza botto eliza_bo...@hotmail.com wrote:
Thankyou very much jorge
Dear Bert and Arun,
Thankyou very much for your help. I am really obliged. :D
Eliza
Date: Sat, 22 Mar 2014 08:17:31 -0700
Subject: Re: [R] plotting vectors of different lengths
From: gunter.ber...@gene.com
To: smartpink...@yahoo.com; jorgeivanve...@gmail.com; eliza_bo...@hotmail.com
CC:
[row.names(mat1) %in% df1$Ry,colnames(mat1)
%in% df1$Rx]),nrow=120, dimnames=list(NULL,colnames(res)))
identical(res,res2)
#[1] TRUE
A.K.
On Saturday, March 22, 2014 4:14 PM, eliza botto eliza_bo...@hotmail.com
wrote:
Thankyou very very much arun. Right now i cant have an acess to PC
Dear UseRs,
I have a question regarding reading the coordinates within a country' map. I
drew map of ireland by using the following commands
library(maps)
library(mapproj)
map(world, ireland)
map.axes()
You can clearly see the axis labelled. What is want to do is to draw lines
(both vertically
-project.org
Subject: Re: [R] points with-in boundaries of a map
On 03/23/2014 01:01 PM, eliza botto wrote:
Dear UseRs,
I have a question regarding reading the coordinates within a country' map.
I drew map of ireland by using the following commands
library(maps)
library(mapproj)
map
: [R] points with-in boundaries of a map
On 03/23/2014 10:29 PM, eliza botto wrote:
Thankyou very much jim. it worked! but regarding second part of my
question, isn't there a way to read the coordinates of intersecting
lines with the premises of the map?
Hi Eliza,
I think you want
statement.
Please refer to www.vestas.com/legal/notice
If you have received this e-mail in error please contact the sender.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of eliza botto
Sent: 23. marts 2014 03:02
To: r
Thanks ray, I really appreciate your concern.
Eliza
Date: Tue, 25 Mar 2014 08:35:15 +1300
From: ray.brownr...@ecs.vuw.ac.nz
To: fr...@vestas.com; eliza_bo...@hotmail.com; r-help@r-project.org
Subject: Re: [R] points with-in boundaries of a map
On 24/03/14 20:09, Frede Aakmann Tøgersen
Dear useRs,
A similar question has previously been asked by another user
(https://stat.ethz.ch/pipermail/r-sig-geo/2011-September/012791.html) but i'll
try to discuss it from another angle. Its about data reading. I am trying to
read to read a data-set APHRO_MA_050deg_V1101R2.1961.gz from
:45 AM, eliza botto eliza_bo...@hotmail.com wrote:
Dear useRs,
A similar question has previously been asked by another user
(https://stat.ethz.ch/pipermail/r-sig-geo/2011-September/012791.html) but
i'll try to discuss it from another angle. Its about data reading. I am
trying to read
the sender.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of eliza botto
Sent: 27. marts 2014 13:26
To: Pascal Oettli
Cc: r-help@r-project.org
Subject: Re: [R] reading dataset
Dear Pascal,
Thanks for your reply
Dear useRs,
I have the data of following format. I have only pasted some part of the data.
The data starts from 1961 and ends up in december 1987.
dat - read.table(text=Date A B C D1-Jan-61 0.00 1.27 8.128 0.252-Jan-61 6.10
9.144 94.742 15.493-Jan-61 0.00 0.508 1.27 0.004-Jan-61 0.00 0 NA
Dear useRs,
Sorry for such a ridiculous question but i really need to know that what is the
difference between NA and NA and how to convert NA to NA.
Thankyou very much in advance
Eliza
[[alternative HTML version deleted]]
Em 31-03-2014 18:31, eliza botto escreveu:
Dear useRs,
I have the data of following format. I have only pasted some part of the
data. The data starts from 1961 and ends up in december 1987.
dat - read.table(text=Date A B C D1-Jan-61 0.00 1.27 8.128 0.252-Jan-61
6.10 9.144 94.742
:40, eliza botto escreveu:
Dear Rui,
Thanks for your reply. But the command seems not to be working. I am
getting the following error.
Error in FUN(X[[1L]], ...) : invalid 'type' (character) of argument
Any idea? :(
Thanks,
Eliza
Date: Mon, 31 Mar 2014 18:48:08 +0100
Dear useRs,
I have a number of text file located at a certain location with the following
names.
s1.txt,s2.txt,s3.txt,s4.txt,s5.txt...s120.txt
when i read them, before opening them, by using
filelist = list.files(pattern = .s*.txt)
The are opened in the following order
[1] s1.txt
Dear useRs,
I have a matrix of 120 row and 1000 columns.What I want is to get an average of
a set of 12 rows starting from 1 till 120 for each column. Precisely, for
column 1 the average of 1:10 rows, 11:20 rows 111:120. similarly for column
2, 3, 4 1000. So in the end i should have a
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