Dear R users,
Can anyone help me with mann-kendall trend test? I tried to use the newest
packages 'trend', and the function mk.test, but had problems in applying
the input data.
For example, res <- mk.test(Nile), Nile is a time-series data. But when I
use my dataset, with one column which is a
Hi R users,
I have a data frame, and I generate a date column like this:
df$date = seq(as.Date('2012-01-01'), as.Date('2014-12-31'))
df
A B C
1 2 1
2 2 3
3 2 4
So the data frame has 4 columns now. But when I want to change the values
of column A for specific dates, such as 2012-01-01
helpful.
with(df, approx(x=time, y=C, xout=seq(min(time), max(time), by="days")))
On Thu, Jul 21, 2016 at 5:14 PM, Ismail SEZEN <sezenism...@gmail.com> wrote:
>
> > On 22 Jul 2016, at 01:34, lily li <chocol...@gmail.com> wrote:
> >
> > I have a
Hi all,
I have a problem in opening netcdf files. If one netcdf file contains
longitude, latitude, and daily precipitation. How to relate each
precipitation record to its associated location, and export them as csv
files? Thanks.
I just use nc_open(), ncvar_get(), but it is not very helpful.
u haven't worked much with netcdf files. I will try to
> find a tutorial also to help you along.
>
> Thanks,
>
> -Roy
>
> > On Jul 26, 2016, at 12:07 PM, lily li <chocol...@gmail.com> wrote:
> >
> > Thanks for your reply. But it says "Error in (func
.. ..$ hasAddOffset : logi FALSE
.. ..$ hasScaleFact : logi FALSE
.. ..- attr(*, "class")= chr "ncvar4"
- attr(*, "class")= chr "ncdf4"
On Tue, Jul 26, 2016 at 2:52 PM, Roy Mendelssohn - NOAA Federal <
roy.mendelss...@noaa.gov>
day:
>
> p1 = rasterToPoints(bvar[[1]])
> and write p1 to csv.
>
> Best,
> Jon
>
>
>
> On 7/26/2016 6:54 AM, lily li wrote:
>
>> Hi all,
>>
>> I have a problem in opening netcdf files. If one netcdf file contains
>> longitude, latitude, and
Hi all,
I want to ask that how to create column names for a matrix. For example,
the matrix below, the column names should be: 1-A, 1-B, 1-C, 1-D, 2-A, 2-B,
2-C, 2-D, 3-A, etc. Thanks for your help.
chars = c('A','B','C','D')
matrix1 = matrix(nrow = length(1:100), ncol =
to read the
> crs-variable was not wrapped in a try-call in earlier versions. Upgrading
> might help.
>
> Best,
> Jon
>
>
>
> On 7/27/2016 5:13 PM, lily li wrote:
>
> Hi Jon,
>
> I still have problems. The brick function does not work well and I don't
> kn
:
>
>> Hi,
>>
>> On 07/27/2016 11:17 AM, lily li wrote:
>>
>>> Hi all,
>>>
>>> I want to ask that how to create column names for a matrix. For example,
>>> the matrix below, the column names should be: 1-A, 1-B, 1-C, 1-D, 2-A,
>>> 2-
[2]], tmp[[1]], sep = "-")
> rm(tmp)
> colnames(matrix1) <- nms
>
> head(matrix1)
>
>
> Hope this helps,
>
> Rui Barradas
>
>
> Citando lily li <chocol...@gmail.com>:
>
> Hi all,
>
> I want to ask that how to create column names for a matrix
If replace 1:5 to char2 = c('east','west','south','north','central'), how
to put on column names with the original structure? Thanks again.
On Wed, Jul 27, 2016 at 12:40 PM, Hervé Pagès <hpa...@fredhutch.org> wrote:
> Hi,
>
>
> On 07/27/2016 11:17 AM, lily li wrote:
>
&g
I have a question about interpolating missing values in a dataframe. The
dataframe is in the following, Column C has no data before 2009-01-05 and
after 2009-12-31, how to interpolate data for the blanks? That is to say,
interpolate linearly between these two gaps using 5.4 and 6.1? Thanks.
df
otice how one can copy and paste that example out of the
> mail an into R to see how it works? It would help if your questions
> had that same property - show how the example data could be created.
>
>
> Bill Dunlap
> TIBCO Software
> wdunlap tibco.com
>
> On Thu, Jul 21, 2016
Hi R users,
I'm trying to download lubricate from this website, and then install it on
my mac.
https://github.com/hadley/lubridate
but it says windows version does not apply to mac. How to install the
package for mac? Thanks.
[[alternative HTML version deleted]]
I use this code, and it works. So has to set 'all=TRUE'.
merge(df, data.frame(time=seq(as.Date("1990-01-01"),
to=as.Date("1990-12-31"), by="days")), all=TRUE)
On Thu, Jul 21, 2016 at 9:22 AM, Daniel Nordlund <djnordl...@gmail.com>
wrote:
> On 7/20/2016 8:
; > a.new <- sub("^.", '', a)
> > a.new
> [1] "35.84375_.100.71875"
> >
>
>
> Jim Holtman
> Data Munger Guru
>
> What is the problem that you are trying to solve?
> Tell me what you want to do, not how you want to do it.
>
> On Thu,
Another question is, if I want to shade the range between the maximum and
minimum values for daily or annual values, how to do it? Thanks again.
On Tue, Aug 2, 2016 at 12:50 PM, lily li <chocol...@gmail.com> wrote:
> Hi all,
>
> I have another question. There are several dataf
('sample_precip_daily.nc')
pre.3d = ncvar_get(pre1, 'precipitation')
require(raster)
rplot = t(pre.3d[, , 1])
r = raster(rplot[nrow(rplot):1, ]
plot(r)
On Tue, Jul 26, 2016 at 1:07 PM, lily li <chocol...@gmail.com> wrote:
> Thanks for your reply. But it says "Error in (function (classes, fdef,
> m
dd it to your plot, but I am not sure if it is
> enough direct.
>
> Cheers
> Petr
>
> > -Original Message-
> > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of lily li
> > Sent: Tuesday, August 2, 2016 8:10 PM
> > To: R mailing list <r-he
l data
> frames.
>
> Something like
>
> df1$fr <- 1
> df2$fr <- 2
>
> dfkompl <- rbind(df1, df2)
>
> ggplot(dfkompl, aes(x=time, y=varA, colour=factor(fr))
>
> Cheers
> Petr
>
>
> > -Original Message-----
> > From: R-help [mailto:r-hel
all:
>
> df.lst <- list(df1, df2, df3, df1, df2, df3)
> do.call(rbind, df.lst)
>
> You might take a look at the facet functionality in ggplot once you are
> ready to build your plots.
>
> Best,
> Ulrik
>
> On Wed, 3 Aug 2016 at 17:42 lily li <chocol...@gmail.
Hi R users,
I have a dataframe, where there is a column 'time' represents time series
but is not complete. How to expand the dataframe so this column will become
complete, where other columns with the newly added rows have NA values?
Thanks.
df
A B C time
105 3.3 1990-01-01
20, 2016, at 1:31 PM, lily li <chocol...@gmail.com> wrote:
> >
> > Hi R users,
> >
> > I have a dataframe, where there is a column 'time' represents time series
> > but is not complete. How to expand the dataframe so this column will
> become
> > com
I still haven't heard back from anyone. Please let me know as I think it is
better to discuss here.
On Sun, Jul 10, 2016 at 1:25 PM, lily li <chocol...@gmail.com> wrote:
> Has anyone used smwrGraphs package? I have some problems and think it may
> be better to discuss if you hav
Has anyone used smwrGraphs package? I have some problems and think it may
be better to discuss if you have been using it. Thanks very much.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more,
Hi all,
I have another question. There are several dataframes, each has the same
columns: time, varA, varB, varC, etc. If I want to plot time ~ varA of each
dataframe, where different dataframe names use different colors. How to do
this in ggplot? Thanks for your help.
Right now, I tried to use
Hi R users,
I have a dataframe, with daily precipitation data, is it possible to plot
annual mean or annual sum values directly? Thanks for your help.
df
year month day precip time
2010 1 10.5 2010-01-01
2010 1 20.8 2010-01-02
2010
ckage (
> http://coastwatch.pfeg.noaa.gov/xtracto/index.html) there are any number
> of examples using ggplot2 to make maps from netcdf data,
>
> HTH,
>
> -Roy
>
> > On Aug 1, 2016, at 10:35 AM, lily li <chocol...@gmail.com> wrote:
> >
> > Hi all,
Hi R users,
I have a string for example 'X35.84375_.100.71875', and I have another
dataframe df that I want to export with the transformed string name
'35.84375_-100.71875' with no extension. How to do this in R? Thanks for
your help.
a = 'X35.84375_.100.71875'
write.table(df, file='',
Hi R users,
I'd like to ask that how to merge several datasets into one in R? I put
these csv files in one folder, and use the lapply function, but it says
that cannot open file 'xx.csv'. These files have different names, but end
with .csv extension, and the files have the same header. Thanks for
I have a problem in changing row names in a dataframe in R. The first
column is ID, such as aClim_st02, aClim_st03, aClim_st 05, bClim_st01,
bClim_st02, etc. How to rename the names, so that aClim_ all grouped to
aClim, while bClim_ all grouped to bClim? Thanks for your help.
df
ID
", "", df$ID)
>
> HTH
> Ulrik
>
> On Sun, 3 Jul 2016 at 20:16 lily li <chocol...@gmail.com> wrote:
>
>> I have a problem in changing row names in a dataframe in R. The first
>> column is ID, such as aClim_st02, aClim_st03, aClim_st 05, bClim_st01,
>
s.Date(paste(df.count.mon$year, df.count.mon$mon,1),
> '%Y %m %d')
> df.count.mon
>count year mon time
> 1 22 2014 1 2014-01-01
> 2 12 2014 2 2014-02-01
> ...
> You will get values, but I don't think they are the ones you want.
>
> Jim
>
> On Th
Hi R users,
I have a dataframe, with year, month, day, and other variables. I wanted to
calculated monthly values of the variables. For example, there is one
variable called 'count'. I use the code below to convert daily data to
monthly data.
df.count.mon = aggregate(count ~ year+month, data=
Hi R users,
I'm trying to open netcdf files in R. Each nc file has daily climate
measurements for a whole year, covering the whole US. How to limit the file
to a specific rectangle? Thanks.
[[alternative HTML version deleted]]
__
sAsFactors = F" when you read the data, and then
> convert them to numeric.
>
> On 20 September 2016 at 16:00, lily li <chocol...@gmail.com> wrote:
> > Yes, it is stored as factor. I can't check out any problem in the
> original
> > data. Reread data doesn't help eit
Hi R users,
I have a problem in reading data.
For example, part of my dataframe is like this:
df
month day year Discharge
31 20106.4
32 2010 7.58
33 2010 6.82
34 2010 8.63
3
na.strings argument documented under read.table)... so you probably DO have
> unexpected garbage still in your data which could be obscuring valuable
> information that could affect your conclusions.
> --
> Sent from my phone. Please excuse my brevity.
>
> On September 20, 2016 3:1
ric using the colClasses argument to read.table or other
> function.
>
>
>
> On Tue, Sep 20, 2016 at 3:46 PM, lily li <chocol...@gmail.com> wrote:
> > Hi R users,
> >
> > I have a problem in reading data.
> > For example, part of my dataframe is like t
Is there a function in read.csv that I can use to avoid converting numeric
to factor? Thanks a lot.
On Tue, Sep 20, 2016 at 4:42 PM, lily li <chocol...@gmail.com> wrote:
> Thanks. Then what should I do to solve the problem?
>
> On Tue, Sep 20, 2016 at 4:30 PM, Jeff N
=FALSE)
> (I'm just reiterating Jianling said...)
>
> Joe
>
> On Tue, Sep 20, 2016 at 4:56 PM, lily li <chocol...@gmail.com> wrote:
>
>> Is there a function in read.csv that I can use to avoid converting numeric
>> to factor? Thanks a lot.
>>
>>
>>
e. Please excuse my brevity.
>
> On September 20, 2016 4:09:02 PM PDT, lily li <chocol...@gmail.com> wrote:
> >Yes, I tried to add this statement when reading the dataset.
> >But when I use summary(df), it shows:
> >Discharge
> >Length:
> >Class :character
Hi R users,
Do any of you have any experience about converting binary files to ascii or
txt files in R? Thanks a lot for your help.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
My apologize, it has been solved. Just include w inside of select, such as:
select = c(w, x, y)
On Fri, Oct 28, 2016 at 12:06 PM, lily li <chocol...@gmail.com> wrote:
> Hi R users,
>
> I have the dataframe as below:
>
> w=c(5,6,7,8)
> x=c(1,2,3,4)
> y=c(1,2,3)
> le
Hi R users,
I have the dataframe as below:
w=c(5,6,7,8)
x=c(1,2,3,4)
y=c(1,2,3)
length(y)=4
z=data.frame(w,x,y)
z$mean1 <- rowMeans(subset(z, select = c(x, y)), na.rm = T)
z$mean2 <- rowMeans(subset(z, select = c(x, y)), na.rm=F)
w x y mean1 mean2
1 5 1 1 1 1
2 6 2 2 2 2
3
Hi R users,
In the current directory, there are several folders (such as fold1, fold2,
fold3, etc.), while each folder includes the same named files, such as
file1.txt, file2.txt, file3.txt, etc. The structures of each folder and
each file are the same, but with different values. I want to read
Hi R users,
I'm wondering why the values changed when I try to transform factors into
numerics.
For example, for a data frame DF, there is one column called precipitation,
which is usually lower than 100mm. But this column is factor when I read in
the data. When transform to numeric values, some
The code I'm using is:
require(reshape)
DF2 = melt(DF, id.vars = c('year', 'month', 'day'), measure.vars =
c('site1_elev', 'site2_elev', 'site1_temp', 'site2_temp'))
But it didn't work.
On Sat, Oct 22, 2016 at 11:50 AM, lily li <chocol...@gmail.com> wrote:
> Hi R users,
>
>
Hi R users,
I want to melt a dataframe, but it mixed up the variables.
DF is the original dataset:
year month day site1_elev site2_elev site1_temp site2_temp
2000 561300 150020 21
2000 571300 1500
Hi R users,
I'm trying to manipulate a dataframe and have some difficulties.
The original dataset is like this:
DF
year month total id note
2000 1 98GA 1
2001 1100 GA 1
2002 2 99GA 1
2002 2 80GB 1
...
2012 1
do, not how you want to do it.
>
> On Sat, Nov 26, 2016 at 11:11 AM, lily li <chocol...@gmail.com> wrote:
>
>> Hi R users,
>>
>> I'm trying to manipulate a dataframe and have some difficulties.
>>
>> The original dataset is like this:
>>
>>
Hi R users,
I'm trying to manipulate dataset, but met some difficulties.
df
year month flow
2006 33.5
2006 43.8
2006 521
2006 632
2007 34.1
2007 44.4
...
I want to calculate total flow for each year, and use the code
Hi R users,
I have a question about filling a dataframe in R using a for loop.
I created an empty dataframe first and then filled it, using the code:
pre.mat = data.frame()
for(i in 1:10){
mat.temp = data.frame(some values filled in)
pre.mat = rbind(pre.mat, mat.temp)
}
However, the
gt; }
>
> nrow(pre.mat) # should be 50
>
>
> Can you give us an example that doesn't work?
>
> Rui Barradas
>
>
> Em 06-01-2017 18:00, lily li escreveu:
>
>> Hi R users,
>>
>> I have a question about filling a dataframe in R using a for loo
Hi R users,
I'm trying to read in data, and then plot time series data. However, I have
some problems. In my dataset, the first column represents time, and in the
format:
mm/dd/-hr:min:sec; For example, 10/01/1995-00:00:00,
10/01/1995-06:00:00, etc.
df:
date
t 11:23 AM, Rui Barradas <ruipbarra...@sapo.pt> wrote:
> Hello,
>
> Have you tried
>
> df$date <- as.POSIXct(dat$date, format = "%m/%d/%Y-%H:%M:%S")
>
> ?
>
> Hope this helps,
>
> Rui Barradas
>
>
>
> Em 30-12-2016 17:40, lily li escre
ds
>
> Duncan
>
> Duncan Mackay
> Department of Agronomy and Soil Science
> University of New England
> Armidale NSW 2351
> Email: home: mac...@northnet.com.au
>
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of lily li
>
I tried it, but it doesn't work. The time column is blank then.
DF$time = substring(DF$time, first=as.Date('1999-01-01),
last=as.Date('2005-12-30'))
On Sat, Dec 31, 2016 at 10:52 AM, David Winsemius <dwinsem...@comcast.net>
wrote:
>
> > On Dec 31, 2016, at 9:26 AM, lily li <c
Sorry, the problem has been solved. I found that strptime is a good
function for this.
DF$time2 = strptime(DF$time, format='%Y-%m-%d)
On Sat, Dec 31, 2016 at 11:02 AM, lily li <chocol...@gmail.com> wrote:
> I tried it, but it doesn't work. The time column is blank then.
> DF$time =
unty" comic strip )
>
>
> On Sat, Dec 31, 2016 at 9:26 AM, lily li <chocol...@gmail.com> wrote:
> > Hi all,
> >
> > Thanks for your help. Now I can convert data to the format "-mm-dd
> > hh:mm:ss", but how to convert it to "-mm-dd&q
01, 5); for (i in 1:1001) tmp[i,] <-
> 1:5})
>user system elapsed
> 0.001 0.000 0.001
> > dim(tmp)
> [1] 10015
>
> On Fri, Jan 6, 2017 at 11:46 PM, lily li <chocol...@gmail.com> wrote:
> > Hi Rui,
> >
> > Thanks for your reply. Ye
Hi R users,
I'm trying to concatenate two strings, while each string has numbers.
For example, strings1 = c(1.2, 1.31, 1.4, 1.51, etc), strings2= c(2.1,
2.22, 2.3, 2.44, etc). I want to have all decimals for the two strings,
such as: strings1= c(1.20, 1.31, 1.40, 1.51, etc), string2 = c(2.10,
Sorry for the emails. I just checked and the problem is still there. Is
there a proper way to reformat the decimal places, such as three or four
decimal places? Thanks.
If maintain four decimal places, the numbers are: 1.2000, 1.3100, 1.4000,
etc.
On Thu, Jan 5, 2017 at 10:46 PM, lily li <cho
I found that the last column is the digits 2.00, so the problem is solved.
On Thu, Jan 5, 2017 at 10:42 PM, lily li <chocol...@gmail.com> wrote:
> Hi R users,
>
> I'm trying to concatenate two strings, while each string has numbers.
> For example, strings1 = c(1.2, 1.
gt;
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Sat, Mar 11, 2017 at 10:50 AM, lily li <cho
(0))
1: `$<-`(`*tmp*`, "Z", value = numeric(0))
I don't know what is the problem, as it works in the Console panel but not
in the top left panel. Thanks for your help.
On Sat, Mar 11, 2017 at 11:50 AM, lily li <chocol...@gmail.com> wrote:
> Hi R users,
>
> I have a pr
Hi R users,
I have a problem about using R studio. For example, there is a dataframe
that has many columns. I want to aggregated column X and column Y into
column Z. Column Z does not exist before the aggregation. I use the code
below:
df$Z = df$X + df$Y
However, it does not work in the top left
- Bert
>
>
> Bert Gunter
>
> "The trouble with having an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Sat, Mar 11, 2017 at 11:14 AM, lily li
ng an open mind is that people keep coming along
> and sticking things into it."
> -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
>
>
> On Tue, Mar 7, 2017 at 10:45 AM, lily li <chocol...@gmail.com> wrote:
> > Hi R users,
> >
Or if there is another way to get '', 'mm', and 'dd' from time variable
'dd-mm-'? Thanks very much.
On Tue, Mar 7, 2017 at 11:45 AM, lily li <chocol...@gmail.com> wrote:
> Hi R users,
>
> I'd like to ask that where to find the 'lubridate' package for Mac Sierra?
>
Hi R users,
I'd like to ask that where to find the 'lubridate' package for Mac Sierra?
I downloaded one version for OS X Mavericks binaries, but it does not work.
The error message is as below:
> install.packages("~/Downloads/lubridate_1.6.0.tar.gz", repos = NULL, type
= "source")
ERROR:
Hi R users,
I got warning messages when installing the package, and I pasted the
messages below. I checked updates that my R-studio is already the newest
version. I don't know how to solve the problem. Thanks for your help.
> library(igraph)
Error in dyn.load(file, DLLpath = DLLpath, ...) :
color<-factor(dfm$A)
> plot(dfm$B,dfm$C,pch=ifelse(dfm$DF==1,1,19),
> col=rainbow_colors[as.numeric(dfm$Acolor)])
> legend("bottom",legend=sort(unique(dfm$A)),
> fill=rainbow_colors)
> legend(25,35,c("DF=1","DF=2"),pch=c(1,19))
>
> Jim
>
>
, 2017 at 9:28 AM, lily li <chocol...@gmail.com> wrote:
> Hi Jim,
>
> For true color, I meant that the points in the figure do not correspond to
> the values from the dataframe. Also, why to use rainbow(9) here? And the
> legend is straight in the middle, is it possible to re
Hi R users,
I have a question about plotting. There is the dataframe below, while each
row represents a record. If I want to plot on a A-B plot, i.e., x-axis
represents A, while y-axis represents B values. However, I want to plot the
mean value from records 1-10 as one point, while the 10th and
ls=FALSE,col="red")
>
> The same code will work for a second data frame, except that you would
> use "points" instead of "plot" and change the color. You may also have
> to specify xlim and ylim in the first call to "plot" so that all
> values are
Hi R users,
I still have the problem about plotting. I wanted to put the datasets on
one figure, x-axis represents values B, y-axis represents values C, while
different colors label column A. Each record uses a circle on the figure,
while hollow circles represent DF=1 and solid circles represent
Hi R users,
I'm trying to install the package, but got the error and don't know how to
fix it. Can anyone help me? Thanks very much.
install.packages("smwrGraphs", repos=c("http://owi.usgs.gov/R",;
http://cran.us.r-project.org;), dependencies = TRUE)
Error in install.packages : Line starting '
It is working now. I don't know where's the problem. thanks for your help.
On Sun, Jul 23, 2017 at 12:33 PM, peter dalgaard <pda...@gmail.com> wrote:
>
> > On 23 Jul 2017, at 18:31 , Uwe Ligges <lig...@statistik.tu-dortmund.de>
> wrote:
> >
> >
> >
>
Hi R users,
I have a question about opening the txt files and putting them into a
matrix. The txt files are in the folder01, while they have the name
file.1.txt, file.2.txt, file.3.txt, etc. There are about 200 such text
files. Each txt file contains one value inside. When I tried to use the
code
01", full.names = TRUE),
>> you get the full paths rather name just the file names, i.e. you don't
>> have to use file.path().
>>
>> /Henrik
>>
>> On Thu, Jun 29, 2017 at 12:04 PM, lily li <chocol...@gmail.com> wrote:
>> > Hi R users,
; pathetic excuses of nothings that should eat a bullet for their next meal
> instead of bull SHIT ( although I know they like the taste of shit) (its a
> favorite of ]r[ist subscribers )
>
> Show quoted text
>
> 15:04, "lily li" <chocol...@gmail.com> wrote:
> >
&
of a C like
> for() loop should be avoided when possible, as it could be here.
>
> If I have made an error in understanding what you are doing, please do
> let us all know. I get it wrong from time to time.
>
> Cheers,
> Bert
>
> Bert Gunter
>
> "The trouble wi
Hi R users,
I have a question about adding a column for water year. The dataframe has
the structure below. But the wyear column just shows one year. Could anyone
help me with this problem? Thanks.
DF
year month day timeflow
1972 1 11972-01-01 5
1972
Hi R users,
I am using the plot() function, but have a problem. When saving as pdf
format, the ‰ sign in the x-axis label becomes (...) sign. I prefer to save
in pdf, as this format has a higher resolution than jpeg or other picture
formats. Could anyone tell me how to do then? Thanks.
In the lower right panel of R-studio interface, there is the "Export"
button. I saved as PDF from there directly, rather than using functions
On Sat, Aug 5, 2017 at 6:18 PM, Ismail SEZEN <sezenism...@gmail.com> wrote:
>
> > On 6 Aug 2017, at 03:01, lily li <chocol...
un...@r-project.org] On Behalf Of lily li
> Sent: Tuesday, May 09, 2017 10:39 AM
> To: R mailing list <r-help@r-project.org>
> Subject: [R] About calculating average values from several matrices
>
> Hi R users,
>
> I have a question about manipulating the data.
> For ex
s,
> Charles
>
> On Tue, May 9, 2017 at 9:52 AM, lily li <chocol...@gmail.com> wrote:
>
>> I meant for each cell, it takes the average from other dataframes at the
>> same cell. I don't know how to deal with row names and col names though,
>> so
>> it has the
Hi R users,
I have a question about manipulating the data.
For example, there are several such data frames or matrices, and I want to
calculate the average value from all the data frames or matrices. How to do
it? Also, should I convert them to data frame or matrix first? Right now,
when I use
orm(100), 10, 10)
>
> }
>
>
>
> ### mean over all cells
>
> sapply(myData, function(x) mean(x))
>
>
>
> ### mean over all columns
>
> sapply(myData, function(x) colMeans(x))
>
>
>
>
>
>
>
>
>
>
>
> *From:*
Yes, that means to control decimal numbers. For example, use round(2.3122,
digits=1), it gets 2.3
On Tue, May 9, 2017 at 9:11 AM, Doran, Harold <hdo...@air.org> wrote:
> ?round
>
>
>
>
>
> *From:* lily li [mailto:chocol...@gmail.com]
> *Sent:* Tuesday, May 09,
as expected
>
>
>
> *From:* lily li [mailto:chocol...@gmail.com]
> *Sent:* Tuesday, May 09, 2017 11:13 AM
> *To:* Doran, Harold <hdo...@air.org>
> *Cc:* Charles Determan <cdeterma...@gmail.com>; R mailing list <
> r-help@r-project.org>
>
> *Subject:* Re
:
>
> plot(y)
> lines(supsmu(1:20,y))
> lines(0.6*cos((1:20)/3+0.6*pi)+17.2)
>
> Jim
>
>
> On Wed, Jun 21, 2017 at 9:17 AM, lily li <chocol...@gmail.com> wrote:
> > Hi R users,
> >
> > I have a question about fitting a cosine curve. I don't know
Hi R users,
I have a question about fitting a cosine curve. I don't know how to set the
approximate starting values. Besides, does the method work for sine curve
as well? Thanks.
Part of the dataset is in the following:
y=c(16.82, 16.72, 16.63, 16.47, 16.84, 16.25, 16.15, 16.83, 17.41, 17.67,
Thanks. I will do a trial first. Also, is it okay to have the datasets that
have only part of the cycle, or better to have equal or more than one
cycle? That is to say, I cannot have the complete datasets sometimes.
On Tue, Jun 20, 2017 at 7:37 PM, Don Cohen
wrote:
I'm trying the different parameters, but don't know what the error is:
Error in nlsModel(formula, mf, start, wts) :
singular gradient matrix at initial parameter estimates
Thanks for any suggestions.
On Tue, Jun 20, 2017 at 7:37 PM, Don Cohen
wrote:
>
> If you
Hi R users,
I have a question about manipulating the dataframe. I want to create a new
dataframe, and to multiply rows with different seasons for different
constants.
DF
year month day product1 product2 product3
1981 1 1 18 5620
1981 1
t; >> (filled with NA values), then specify the precise rows and columns on
> >> both the left and right hand sides of the assignment operator that
> >> will be altered. Luckily, this is pretty easy...just remember to use
> >> which() on the right hand side of the a
ve the
> same number of rows.
>
> HTH
> Ulrik
>
>
>
> On Wed, 24 May 2017 at 19:30 lily li <chocol...@gmail.com> wrote:
>
>> Hi all,
>>
>> I have a question about combining two data frames. For example, there are
>> the two dataframes below,
1 - 100 of 142 matches
Mail list logo