(rbind, l2)
l2
# Create a new variable
l3 - lapply(sl, function(x) cbind(x, NEW_VARIABLE=seq_len(nrow(x)))**)
l3 - do.call(rbind, l3)
l3
Hope this helps,
Rui Barradas
Em 25-07-2012 01:59, AC Del Re escreveu:
Hi,
I am trying to reshape data from a long to wide format but have a specific
Hi,
I am trying to reshape data from a long to wide format but have a specific
task that I cannot get to output properly.
# SAMPLE DATA;
id - c(1,2,2,3,3,3)
time -c(0,0,5, 0, 2, 10)
x - rnorm(length(id))
long - data.frame(id,time,x)
# To reshape, I would like to exclude 'id' values that have NO
Hi,
Is there an easy way to remove dataframe rows without duplicated values of
a specified column ('id')? e.g.,
dat - data.frame(id = c(1,1,1,2,3,3), value = c(5,6,7,4,5,4), value2 =
c(1,4,3,3,4,3))
dat
id value value2
1 1 5 1
2 1 6 4
3 1 7 3
4 2 4 3
5
Hi,
I have this sample data below and would like to create a list of matricies.
setseed(1254)
id - c(1,1,1,1 ,2,2,2)
o - as.factor(c(1:4, 1, 3, 4))
r - rep(.5, 7)
v - rnorm(7)
s - rnorm(7)
dat -data.frame(id, o, r, v, s)
dat
# dat
# id o r v s
# 1 1 0.5 0.7024631
Thats a good start but I am looking for more. Specifically (from previous
post):
4x4 matrix (based on the maximum number of factor levels in 'o') for each
'id' as a list.
Each matrix would have v in the diagonal and r*s*s in the off-diagonal
(e.g.,
.5*2.0814*.1095 = 0.1139), where
r is constant
Hi,
I am trying to select the first row of a variable with data in long-format,
e.g.,
# sample data
id - c(1,1,1,2,2)
value - c(5,6,7,4,5)
dat - data.frame(id, value)
dat
How can I select/subset the first 'value' for each unique 'id'?
Thanks,
AC
[[alternative HTML version deleted]]
The formula version of aggregate() requires R-2.11.0 +
Dennis
On Sun, Sep 25, 2011 at 1:22 PM, AC Del Re de...@wisc.edu wrote:
Hi,
I am trying to select the first row of a variable with data in
long-format,
e.g.,
# sample data
id - c(1,1,1,2,2)
value - c(5,6,7,4,5)
dat - data.frame(id
Hi,
I am wanting to simulate data where a percentage of the data has
multiple duplicated id variables (with unique values of another factor
variable for the dupicated id variables). Im having trouble figuring
out an efficent way to do so.
For example, consider this mock output [Note: Although
Wonderful, David! Thank you much for your help on this.
AC
On Fri, Jul 9, 2010 at 6:49 PM, David Winsemius dwinsem...@comcast.netwrote:
On Jul 9, 2010, at 7:19 PM, Erik Iverson wrote:
AC Del Re wrote:
Hi David,
I don't have the function in order yet but the names will be going
Hi All,
I am interested in printing column names without quotes and am struggling to
do it properly. The tough part is that I am interested in using these column
names for a function within a function (e.g., lm() within a wrapper
function). Therefore, cat() doesnt seem appropriate and print() is
...@comcast.netwrote:
On Jul 9, 2010, at 3:51 PM, AC Del Re wrote:
Hi All,
I am interested in printing column names without quotes and am struggling
to
do it properly. The tough part is that I am interested in using these
column
names for a function within a function (e.g., lm() within
Hi All,
Attempt #2. any help is much appreciated!:
I am reading through section 2.6 (Mathematics) of the Writing R
Extensions manuscript and am wondering where I can find more
examples/documentation on the \deqn{ } function. I would like to learn how
to display equations using this
Hi All,
I am reading through section 2.6 (Mathematics) of the Writing R
Extensions manuscript and am wondering where I can find more
examples/documentation on the \deqn{ } function. I would like to learn how
to display equations using this function but am not sure how to go about
doing it. The
Hi All,
Im interested in creating a function that will convert a variable within a
data.frame to a factor while retaining the original name (yes, I know that I
can just: var -factor(var) but I need it as a function for other
purposes). e.g.:
# this was an attempt but fails.
facts -
Dallazuanna www...@gmail.comwrote:
Try this:
transform(DF, newA = factor(a), a = NULL)
On Wed, Mar 17, 2010 at 4:06 PM, AC Del Re de...@wisc.edu wrote:
Hi All,
Im interested in creating a function that will convert a variable within
a
data.frame to a factor while retaining the original
Hi All,
I am using a specialized aggregation function to reduce a dataset with
multiple rows per id down to 1 row per id. My function work perfect when
there are 1 id but alters the 'var.g' in undesirable ways when this
condition is not met, Therefore, I have been trying ifthen() statements to
Hi All,
Is there an easy way to reduce a data.frame to 1 'id' per row while keeping
information from the other rows of that same variable, if applicable? e.g.:
# data
multi[1:15,]
id r n wi wi.tau z k alliance a.rater eml
treatment outcome o.rater german
1 100
10 1 0.180
11 11 2 0.600
12 12 3 0.210
On Sat, Feb 20, 2010 at 9:50 PM, AC Del Re acde...@gmail.com wrote:
OK, this is great, Jim. Last question: How about if I want the 1 copy
of each id to be selected randomly versus taking the first one?
AC
On Sat, Feb 20, 2010 at 8:37
Hi All,
I am interested in aggregating a data frame based on 2
categories--mean effect size (r) for each 'id's' 'mod1'. The
'with' function works well when aggregating on one category (e.g.,
based on 'id' below) but doesnt work if I try 2 categories. How can
this be accomplished?
# sample data
0.640
3 7 1 0.490
4 10 1 0.180
5 1 2 0.295
6 5 2 0.490
7 8 2 0.330
8 11 2 0.600
9 6 3 -0.040
10 9 3 0.580
11 12 3 0.210
On Sat, Feb 20, 2010 at 6:54 PM, AC Del Re de...@wisc.edu wrote:
Hi All,
I am interested in aggregating a data frame
11 12 3 0.21
On Sat, Feb 20, 2010 at 8:07 PM, AC Del Re de...@wisc.edu wrote:
Perfect! Thanks Jim.
Do you know how I could then reduce the data even further?
Specifically, reducing it to 1 id per row? In this dataset, id 1 would
have one row eliminated.
Assume the data is much larger
Hi All,
I have a function that is used with data frames having multiple id's
per row and it aggregates the data down to 1 id per row. It also
randomly selects one of the within-id values of a variable (mod),
which often differ within-id. Assume this data frame (below) is much
larger and I want
Hi All,
I have recently created an Rcmdr plugin package and it passed all the
checks and was uploaded to CRAN. I then downloaded it from CRAN and
tried running it from my local R program and received this error:
...
Error in f(libname, pkgname) : could not find function getRcmdr
Error in
Hi All,
I am interested in creating a function that will take x number of lm
objects and automate the comparison of each model (using anova). Here
is a simple example (the actual function will involve more than what
Im presenting but is irrelevant for the example):
# sample data:
id-rep(1:20)
Perfect!
Thank you, Dimitris.
AC
On Mon, Feb 15, 2010 at 1:45 PM, Dimitris Rizopoulos
d.rizopou...@erasmusmc.nl wrote:
try this:
MRfit - function (...) {
models - list(...)
do.call(anova, models)
}
I hope it helps.
Best,
Dimitris
AC Del Re wrote:
Hi All,
I am
1 wai
Any help is much appreciated!
AC Del Re
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
don't:
with(x, aggregate(es, list(id, mod1), mean))
Group.1 Group.2x
1 3 1 0.20
2 1 2 0.30
3 2 4 0.15
ddply() is a little less painless and sorts the output for you
automatically.
HTH,
Dennis
On Wed, Jan 27, 2010 at 7:34 PM, AC Del Re acde
wai
2 0.1 4 other
2 0.2 4calpas
3 0.1 1 itas
3 0.251 wai
Any help is much appreciated!
AC Del Re
[[alternative HTML version deleted]]
__
R-help@r
# If possible, I would also like the option of this (collapsing on id and
mod2):
id es mod1 mod2
1 .30 2wai
2 0.1 4 other
2 0.2 4calpas
3 0.1 1 itas
3 0.251 wai
Any help is much appreciated!
AC Del Re
the option of this (collapsing on id and
mod2):
id es mod1 mod2
1 .30 2wai
2 0.1 4 other
2 0.2 4calpas
3 0.1 1 itas
3 0.251 wai
Any help is much appreciated!
AC Del Re
[[alternative HTML version deleted
Thanks for your help on this Hadley and David!
Dennis Murphy also had a good solution (changing list(data.out2[-1])...etc
to names(data.out2[-1]}...):
data.out3 - reshape(data.out2, direction = 'long', varying =
names(data.out2[-1]),
+ idvar = 'id')
data.out4 - split(data.out3,
Hi All,
I am wanting to convert a data.frame from a wide format to a long format
(with 1 variable) and am having difficulties. Any help is appreciated!
#current wide format
head(data.out2)
id rater.1 n.1 rater.2 n.2 rater.3 n.3 rater.4 n.4
11 11 0.118 79NA NA
Dear R Community,
I am attempting to transpose a dataset from rows to columns but am stuck. I
have tried using reshape() with little luck, possibly due to the categorical
nature of the data. For example:
id-c(1,2,2,3,3,3)
author-c(j,k,k,l,l,l)
tmt-c(cbt,act,dbt,act,act,cbt)
Wonderful, Phil! Your suggestion produced the exact format I desired.
Thank you kindly,
AC Del Re
On Sun, Oct 4, 2009 at 2:03 PM, Phil Spector spec...@stat.berkeley.eduwrote:
AC -
The easiest way I can think of is to create a time variable,
so reshape will know which observation
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