here is the solution if anyone is interrested
barchart(V5 ~ V3 | V1 * V2 , data = t,groups = V4, layout = c(1,6),
auto.key = list(space = right), ylab = Makespan)
Regards
2014/1/14 Adel ESSAFI adeless...@gmail.com
Hello list
I have the following data in file in attachment.
in want to draw
Hello list
I have the following data in file in attachment.
in want to draw bars for every value of V5 in finction of V3
grouped by V2*V1. however, each unique value
of V4, V2 and V1 I want to draw a bar.
This example is very close to want I want to do. but
here, for each value of V3, barchart
, 115.58, 163.48, 108.85, 172.21)), row.names = c(NA, -80L
), .Names = c(V1, V2, V3, V4, V5, V6, V7, V8), class =
data.frame)
2014/1/14 Adel ESSAFI adeless...@gmail.com
Hello list
I have the following data in file in attachment.
in want to draw bars for every value of V5 in finction of V3
grouped
Hello list
I have this data frame which represent values grouped by algorithm.
remark that for each algorithm, we have the same value in V3 but differnt
values in V4.
I want to make a plot with algorithms in axes, and for each algorithm I
draw a bar (for V3) and a bwplot for V4.
is thart
Hello list
I have this data frame which represent values grouped by algorithm.
remark that for each algorithm, we have the same value in V3 but differnt
values in V4.
I want to make a plot with algorithms in axes, and for each algorithm I
draw a bar (for V3) and a bwplot for V4.
is thart
Hello list
I generated pdf files with R that I integrated
in .tex file and compiled with pdflatex.
however, all the fonts of my R figure not embadded. so the file is rejected
from EDAS web site.
Could you help please.
[adel@localhost hcw]$ pdffonts hcw.pdf
name
Hello list,
I have the following data on dm table
dm
Group.1 V1 V2 V3V4 V5 V6 V7 V8
1 C/L NA 15.5 732179 875270.6 -143091.46 1107270 1088300 18964.40
2 C/S NA 15.5 803926 850352.1 -46426.03 1395710 1312310 83403.30
3 D/D NA 15.5
Hello;
I have the following table
m
V2 V1 V3
1 C/L 0 732179
3 C/S 0 803926
19 D/F 0 724924
17 D/I 0 755841
13 D/L 0 731904
15 D/S 0 798289
11 I/F 0 871670
9 I/I 0 897718
5 I/L 0 2628113
7 I/S 0 2628113
2 C/L 1 1107269
4 C/S 1 1395714
20 D/F 1 1181282
18 D/I 1
Hello;
I have the following table
m
V2 V1 V3
1 C/L 0 732179
3 C/S 0 803926
19 D/F 0 724924
17 D/I 0 755841
13 D/L 0 731904
15 D/S 0 798289
11 I/F 0 871670
9 I/I 0 897718
5 I/L 0 2628113
7 I/S 0 2628113
2 C/L 1 1107269
4 C/S 1 1395714
20 D/F 1 1181282
18 D/I 1
ESSAFI
Sent: Wednesday, May 08, 2013 12:48 PM
To: r-help
Subject: Re: [R] R prints empty group on my figure!!
hello,
I attach the figure generated by R:
2013/5/8 Adel ESSAFI adeless...@gmail.com
Hello list
I am trying to solve a problem when drawing a figure related
Hello list
I am trying to solve a problem when drawing a figure related to the
dataframe below.
I draw V6 in Y axes and V3 as X axes. The data are grouped by V1 AND V2.
I use this commande to make it:
xyplot(cm[,6]~cm[,3],type=b,group=interaction(cm[,1],cm[,2],sep=/),
auto.key =list(
hello,
I attach the figure generated by R:
2013/5/8 Adel ESSAFI adeless...@gmail.com
Hello list
I am trying to solve a problem when drawing a figure related to the
dataframe below.
I draw V6 in Y axes and V3 as X axes. The data are grouped by V1 AND V2.
I use this commande to make
thank you
2013/5/6 Gerrit Eichner gerrit.eich...@math.uni-giessen.de
Hello, Adel,
maybe the argument sep of interaction() helps you. Try
interaction( g[,1], g[,2], sep = /)
Regards -- Gerrit
I am using this command to draw the figure attached to this mail.
Thank you
maybe the argument sep of interaction() helps you. Try
interaction( g[,1], g[,2], sep = /)
Regards -- Gerrit
I am using this command to draw the figure attached to this mail.
xyplot(g[,4]~g[,3],type=b,**group=interaction(g[,1],g[,2])**, auto.key
=list( title=Evolution de
Hello,
I have a problem with ggplot and colors
I used this function to draw somes lines and I want them to be all black
(just to test)
however, I dont get any black line in the figure.
Do you have any experience with ggplot and manual colors??
ggplot(cmax, aes(cmax[,3],
Hello,
How can I make a monte carlo simulation on R?
Regards
Adel
--
PhD candidate in Computer Science
Address
3 avenue lamine, cité ezzahra, Sousse 4000
Tunisia
tel: +216 97 246 706 (+33640302046 jusqu'au 15/6)
fax: +216 71 391 166
[[alternative HTML version deleted]]
Hello,
I want to create 10 dataframe using a for loop.
I don t know what to do to create 10 different dataframes whose name is
parametrized with variable i.
This syntaxe fails. It create a unique fataframe called dfn.
Any input will help
Thanks
for (i in 1:10){
+ filename=paste(avail4,i,sep =
Hello
orderulcount
Group.1 Group.2 Group.3 xV5
7C L 0.0 30 C / L
19 C L 0.2 27 C / L
31 C L 0.4 15 C / L
43 C L 0.6 7 C / L
54 C L 0.8 2 C / L
10 C S 0.0 27 C / S
22 C S
with simpler expressions:
if I have a dataframe
A B C
is it possible de transform it to a matrix where nrow(A) colomns, nrow(B)
row and for each value of C, we put the corresponding value in the matrix.
Regards
Le 18 février 2012 13:57, Adel ESSAFI adeless...@gmail.com a écrit :
Hello
Le 11 février 2012 02:33, David Winsemius dwinsem...@comcast.net a écrit :
On Feb 10, 2012, at 7:05 PM, Adel ESSAFI wrote:
Hi list
I need some help for drawing some histograms
I have a dataframe , say,
X Y Z T
I want to draw a histogram Z-T for each value of the couple (X-Y).
When
Hi list
I need some help for drawing some histograms
I have a dataframe , say,
X Y Z T
I want to draw a histogram Z-T for each value of the couple (X-Y).
When I use thus syntax
library(lattice)
histogram(law[,3] ~ law[,66] | law[,1] )
it draws multiple histograms but by selecting distinct
dear list
I use runif to generate a ramdom number between min and max
runif(n, min=0, max=1)
however , the syntaxe of rexp does not allow that
rexp(n, rate = 1)
and it generate a number with the corresponding rate.
The question is: how to generate a number between min and max using rexp().
Deal list
I want to generate a random number in an interval using exponential low
I know how to make that simply using uniform low
x1 - runif(1, 5.0, 7.5)
this will generate a number between 5 et 7.5 but with uniform low.
Could you help pease.?
Regards
--
PhD candidate in Computer
Hello,
is there any help please.
Regards
2011/10/21 Adel ESSAFI adeless...@gmail.com
Hello
I am discovering R and I find it is really very powerful.
However, I find some newbie difficulties.
Here, I have a data frame with manu values that I want to calculate the
frequency (the nomber
Hello,
is there any help please.
Regards
2011/10/21 Adel ESSAFI adeless...@gmail.com
Hello
I am discovering R and I find it is really very powerful.
However, I find some newbie difficulties.
Here, I have a data frame with manu values that I want to calculate the
frequency (the nomber
Hi,
It is not what I want, but, thx anyway.
Regards
2011/10/22 Weidong Gu anopheles...@gmail.com
try this
table(sci[,2]=0,sci[,1]=L)
Weidong Gu
On Sat, Oct 22, 2011 at 7:51 AM, Adel ESSAFI adel.s...@imag.fr wrote:
Hello,
is there any help please.
Regards
2011/10/21 Adel
Is this waht you want?
sci[,5][sci[,2]==0 sci[,1]==L]
Weidong
On Sat, Oct 22, 2011 at 8:19 AM, Adel ESSAFI adeless...@gmail.com wrote:
Hi,
It is not what I want, but, thx anyway.
Regards
2011/10/22 Weidong Gu anopheles...@gmail.com
try this
table(sci[,2]=0,sci[,1]=L
2011/10/22 Adel ESSAFI adel.s...@imag.fr
NO
aggregate(si[,7],list(si[,2],si[,1]),mean)
Group.1 Group.2 x
1 0.0 D 212.5015448
2 0.2 D 200.5271137
3 0.4 D 191.5387529
4 0.6 D 131.5856218
5 0.8 D 16.4515798
6 1.0
for providing the example data, try this
aggregate(si[,7],list(si[,2],si[,1]),function(x) sum(table(x)))
Weidong
On Sat, Oct 22, 2011 at 9:28 AM, Adel ESSAFI adel.s...@imag.fr wrote:
NO
aggregate(si[,7],list(si[,2],si[,1]),mean)
Group.1 Group.2 x
1 0.0 D 212.5015448
2
Hi list
I am discovering R, and
--
PhD candidate in Computer Science
Address
3 avenue lamine, cité ezzahra, Sousse 4000
Tunisia
tel: +216 97 246 706 (+33640302046 jusqu'au 15/6)
fax: +216 71 391 166
[[alternative HTML version deleted]]
__
Hello
I am discovering R and I find it is really very powerful.
However, I find some newbie difficulties.
Here, I have a data frame with manu values that I want to calculate the
frequency (the nomber of line) of the some criteria.
For exemple here, I want it to print the number of occurence
Bonjour
I have this data frame and I am newbie in R.
I want to ask if it is possible to draw 10 lines in a plot such that: a line
for every colomn, the x - axis is the second column and the y-axis is the
third one.
Thank you for any input
1 0 1094442
1 0.2 1163576.2
1 0.4 1238539.6
1
Hello,
is ot possible to draw two ecdf of vectors (say s1 and s2) on the same
figire with R.
plot function draws a new plot and there is no function like points or lines
to draw a second ecdf on the figure.
Regards
--
*PhD candidate in Computer Science
Address
3 avenue lamine, cité ezzahra,
Hello list
I have this file
0 121289479 25
0 212599129 1
0 285254098 21
0 444889848 45
0 469197123 30
0 640007403 82
0 718215617 8
0 758534043 56
0 799706577 4
0 814441385 93
0 843545059 37
0.2 121289479 6
0.2 285254098 3
0.2 444889848 6
0.2
Points)
You might be interested in ?par especially pch and also in ?legend
as well as in the basic help for ?plot and ?points.
Sarah
On Wed, Sep 14, 2011 at 1:57 PM, Adel ESSAFI adeless...@gmail.com wrote:
Hello list
I have this file
0 121289479 25
0 212599129 1
0 285254098 21
Hello,
I have a file with very big values. I want to display the real values with
classic ways (without exposant)
summary(a[,1]);
Min. 1st Qu.Median Mean 3rd Qu. Max.
1.198e+09 1.199e+09 1.200e+09 1.200e+09 1.201e+09 1.202e+09
Can you help please?
Regards
Adel
--
Hi list
I loaded the content of a file dureetasks.txt to variable a. This file
contains an interger per line.
when I print a vector, it displays correctly.
however, when I try to print the histogram, I get this error message
a=read.table(dureetasks.txt)
hist(a)
Error in hist.default(a) : 'x'
Median : 2658
Mean : 25802
3rd Qu.: 42558
Max. :1575814
hist(a);
Error in hist.default(a) : 'x' must be numeric
2010/8/21 Gavin Simpson gavin.simp...@ucl.ac.uk
On Sat, 2010-08-21 at 11:37 +0200, Adel ESSAFI wrote:
Hi list
I loaded the content of a file dureetasks.txt
-- Forwarded message --
From: Adel ESSAFI adeless...@gmail.com
Date: 2010/8/21
Subject: Re: [R] basic hist() question
To: Henrique Dallazuanna www...@gmail.com
It works fine.
Could you explain to me why it did not worked for read.table?
regards
Adel
2010/8/21 Henrique
thanks,
I'am not veru used with R!!
regards
2010/8/21 Henrique Dallazuanna www...@gmail.com
Adel,
read.table return a data.frame, Gavin showed, you need pass which column
will be plotted to hist.
scan return a vector.
On Sat, Aug 21, 2010 at 10:59 AM, Adel ESSAFI adeless
Hi list
I am a new user of R. I ask for some beginner question
I am searching if there is any function that computes the variation of some
discrete values of a vector (mean() and sd() exists, but i have not find
variation).
Thanks in advance
Adel
--
PhD candidate in Computer Science
Address
-- Forwarded message --
From: Adel ESSAFI adel.s...@imag.fr
Date: 2010/6/5
Subject: Re: [R] How to make R automatic?
To: zhangted001 zhen...@gmail.com
Well, I am new but i will give you an example of script that I run
cat exec2.sh
R --no-saveEOF
fl=list.files(pattern=*.dat
mean. But I looked for ready function :)
compute the mean and the std.dev., it is straightforward to calculate
it.
Adel ESSAFI schrieb:
Hi list
I am a new user of R. I ask for some beginner question
I am searching if there is any function that computes the variation of
some
2010/6/5 Adel ESSAFI adel.s...@imag.fr
2010/6/5 Jannis bt_jan...@yahoo.de
What exactly do you mean by variation? As I understand it, this term is a
broad term for all kinds of different spread measures (like quantile range
or standard deviation). Do you mean the Coefficient of Variation
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