[R] Identifying matched groups based on a rule

2015-05-07 Thread Ala' Jaouni
Hello,

I'm trying to create a table like below for a data set representing one
test and indexed by five categories.

Categories are grouped into a number of buckets (three in this case: A, B,
C) based on the level at which the difference between groups is significant
(0.05).

Category,  Group,  Mean
1,  A,  94.9
2,  A,  94.8
3,  A+B,  93.4
4,  B+C,  91.4
5,  C,  91.1

Is there a way to do this in R?

Thanks.

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[R] Stop on fail using data manipulation

2013-05-27 Thread Ala' Jaouni
Hello,

I have a data set with test results for multiple devices (rows). I also
have an index (column) that stores the first failing test for each device.
I need to remove the results for all the tests that come after the first
failing test.

Example of a data table:

Device,first_failing_test,test1,test2,test3,test4,test5
1,test2,1,2,3,4,5
2,test4,2,3,4,5,6
3,test1,3,4,5,6,7

New table:

Device,first_failing_test,test1,test2,test3,test4,test5
1,test2,1,2,na,na,na
2,test4,2,3,4,5,na
3,test1,3,4,5,na,na

Ideally I need to pass the first table as an argument to a function and get
back the second table.

Any idea how this can be done in R?

Thanks

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[R] generate random numbers subject to constraints

2008-03-26 Thread Ala' Jaouni
I am trying to generate a set of random numbers that fulfill the
following constraints:

X1 + X2 + X3 + X4 = 1

aX1 + bX2 + cX3 + dX4 = n

where a, b, c, d, and n are known.

Any function to do this?

Thanks,
-Ala'

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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Ala' Jaouni
X1,X2,X3,X4 should have independent distributions. They should be
between 0 and 1 and all add up to 1. Is this still possible with
Robert's method?

Thanks

On Wed, Mar 26, 2008 at 12:52 PM, Ted Harding
[EMAIL PROTECTED] wrote:
 On 26-Mar-08 20:13:50, Robert A LaBudde wrote:
   At 01:13 PM 3/26/2008, Ala' Jaouni wrote:
  I am trying to generate a set of random numbers that fulfill
  the following constraints:
  
  X1 + X2 + X3 + X4 = 1
  
  aX1 + bX2 + cX3 + dX4 = n
  
  where a, b, c, d, and n are known.
  
  Any function to do this?
  
   1. Generate random variates for X1, X2, based upon whatever
   unspecified distribution you wish.
  
   2. Solve the two equations for X3 and X4.

  The trouble is that the original problem is not well
  specified. Your suggestion, Robert, gives a solution
  to one version of the problem -- enabling Ala' Jaouni
  to say I have generated 4 random numbers X1,X2,X3,X4
  such that X1 and X2 have specified distributions,
  and X1,X2,X3,X4 satisfy the two equations ... .

  However, suppose the real problem was: let X2,X2,X3,X4
  have independent distributions F1,F2,F3,F4. Now sample
  X1,X2,X3,X4 conditional on the two equations (i.e. from
  the coditional density). That is a different problem.

  As a slightly simpler example, suppose we have just X1,X2,X3
  and they are independently uniform on (0,1). Now sample
  from the conditional distribution, conditional on
  X1 + X2 + X3 = 1.

  The result is a random point uniformly distributed on the
  planar triangle whose vertices are at (1,0,0),(0,1,0),(0,0,1).

  Then none of X1,X2,X3 is uniformly distributed (in fact
  the marginal density of each is 2*(1-x)).

  However, your solution would work from either point of
  view if the distributions were Normal.

  If X1,X2,X3,X4 were neither Normally nor uniformly
  distributed, then finding or simulating the conditional
  distribution would in general be difficult.

  Ala' Jaouni needs to tell us whether what he precisely
  wants is as you stated the problem, Robert, or whether
  he wants a conditional distribution for given distributions
  if X1,X2,X3,X4, or whether he wants something else.

  Best wishes to all,
  Ted.

  
  E-Mail: (Ted Harding) [EMAIL PROTECTED]
  Fax-to-email: +44 (0)870 094 0861
  Date: 26-Mar-08   Time: 19:52:16
  -- XFMail --


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Re: [R] generate random numbers subject to constraints

2008-03-26 Thread Ala' Jaouni
X1,X2,X3,X4 should have independent distributions. They should be
between 0 and 1 and all add up to 1. Is this still possible with
Robert's method?

Thanks

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and provide commented, minimal, self-contained, reproducible code.