*** Apologies for cross posting ***
Dear Colleagues, Dear R-users,
I would like to announce the release of the new version of package
JMbayes available from CRAN (http://CRAN.R-project.org/package=JMbayes).
This package fits joint models for longitudinal and time-to-event data
under a
try this:
df - c(F, C, F, B, D, A, D, D, A, F, D, F, B,
C)
tab - table(df)
tab
rep(names(tab), 100 * tab)
I hope it helps.
Best,
Dimitris
On 3/26/2013 9:12 AM, Katherine Gobin wrote:
Dear R forum
I have a vector say as given below
df = c(F, C, F, B, D, A, D, D, A, F, D, F, B,
two possibilities are:
lis - list(c(12.1,0.1,12.0,1.1), c(3.44,3.00,33.10,23.00))
# 1st
m - do.call(rbind, lis)
split(m, col(m))
# 2nd
lapply(seq_along(lis[[1]]),
function (i) sapply(lis, [, i))
I hope it helps.
Best,
Dimitris
On 3/8/2013 11:06 AM, ishi soichi wrote:
Thanks. The
try this:
a - c(1,1,1,1,1,1,2,2,2,2,2,2)
b - c(1,1,1,2,3,4,1,1,2,2,3,4)
c - c(400,200,300,100,500,300,200,100,500,400,200,100)
DF - data.frame(a, b, c)
with(DF, tapply(c, list(a, b), sum))
I hope it helps.
Best,
Dimitris
On 2/4/2013 10:29 AM, Benjamin Gillespie wrote:
Hi guys,
I hope you
You didn't say how you want these variables to be distributed, but in
case you want a multivariate normal, then have a look at function
mvrnorm() from package MASS, and especially at the 'empirical' argument,
e.g.,
library(MASS)
# assumed covariance matrix
V - cbind(c(2, 1), c(1, 1.2))
V
x1
Check R FAQ 7.10: How do I convert factors to numeric?
I hope it helps.
Best,
Dimitris
On 1/23/2013 10:33 AM, Francesco Sarracino wrote:
Dear R listers,
I am trying to compute the mean of a dummy variable that is encoded as a
factor. However, even though the levels of my factor are 0 - 1,
to numeric?
as.numeric(as.character(pp))
and
as.numeric(levels(pp))[as.integer(pp)]
However, whatever I do, I get Warning message: NAs introduced by coercion
and the output is a vector of NA.
Any ideas?
f.
On 23 January 2013 10:39, D. Rizopoulos d.rizopou...@erasmusmc.nl
mailto:d.rizopou
you just need:
mapply(c, Part1$dataset, Part2$dataset, SIMPLIFY = FALSE)
I hope it helps.
Best,
Dimitris
On 1/23/2013 11:01 AM, Alaios wrote:
Thanks a lot Petr,
for the answer
unfortunately that would convert everything to a matrix
num [1:32002, 1:3] 0 0 0 0 0 0 0 0 0 0 ...
but if you
...
- attr(*, dim)= int [1:2] 3 2
I am sorry that I can not find reproducible example to show you
Alex
*From:* D. Rizopoulos d.rizopou...@erasmusmc.nl
*To:* Alaios ala...@yahoo.com
*Cc:* PIKAL Petr petr.pi
you could try the following:
DF - read.table(textConnection(
Target Eaten ID
50 TPP 0 1
51 TPP 1 2
52 TPP 3 3
53 TPP 1 4
54 TPP 2 5
50.1GPA 9 1
51.1GPA11 2
52.1GPA 8 3
53.1GPA 8 4
54.1GPA10 5),
Try this:
x - c(10, 20, 30)
head(x, -1) + tail(x, -1)
I hope it helps.
Best,
Dimitris
On 11/16/2012 3:50 PM, e-letter wrote:
Readers,
If a vector consists of:
10
20
30
how to create a new vector based upon the results of calculations to
the elements, e.g. addition of successive
Another alternative is:
aa - array(0, dim = c(3,3,3))
a - matrix(1, 3, )
for (i in 1:3) {
a[i, ] - -a[i, ]
aa[, , i] - a
}
aa
I hope it helps.
Best,
Dimitris
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] on behalf of
One approach is:
BB - rnorm(6*5*27)
dim(BB) - c(6, 5, 27)
lapply(2:27, function (i) BB[, , i])
I hope it helps.
Best,
Dimitris
On 11/12/2012 8:56 AM, Haris Rhrlp wrote:
Dear R users,
I have an array that has matrices that i want BB[16,5,2:27]
i want to put each of the 26 matrices into a
try this:
a - matrix(1:30, ncol= 3 )
t(a)
I hope it helps.
Best,
Dimitris
On 11/7/2012 12:50 PM, Andras Farkas wrote:
Dear All
I would like to convert matrix rows to columns. I am thinking the t()
function should help, but am having a hard time converting the matrix into
the
If you don't have any NAs, then one way is:
n - 3
r - 5
s - 6
raw - lapply(seq_len(n), function(i){
matrix(rnorm(r * s), ncol = r)
})
Reduce(+, raw) / length(raw)
I hope it helps.
Best,
Dimitris
On 11/5/2012 11:32 AM, ONKELINX, Thierry wrote:
Dear all,
I have a list of n matrices
try this:
l - list(c(1,2,3,7), c(3,4,5,6,3), c(4,2,5,7), c(2,4,6,3,2), c(3,5,7,2))
sapply(l, head, 4)
I hope it helps.
Best,
Dimitris
On 11/1/2012 9:11 AM, Al Ehan wrote:
Hi,
I have this lame question. I want to convert a list (each with varies in
length) to matrix with same row length
Dear R-users,
I would like to announce the release of the new package JMbayes
available from CRAN (http://CRAN.R-project.org/package=JMbayes). This
package fits shared parameter models for the joint modeling of normal
longitudinal responses and event times under a Bayesian approach using
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