GUI 1.68 Mavericks build (7202) installed on my Macbook
Pro running Mac OS X 10.11.5 (15F34).
Is this something to worry about? Can anyone help me out?
I downloaded R from the official servers.
Kind regards and thank you in advance !
Fabian
__
R
on any aspects of the package, as well as possible
improvements or extensions, would be highly appreciated.
Thank you and best wishes,
Fabian Krüger
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This is because your vector is recycled:
data.frame(1)*1:4 = data.frame(1)*c(1,2,3,4)
only the first element is needed since the data frame has nothing else
to multiply with c(2,3,4)
(x<-data.frame(1:2, 3:4))
X1.2 X3.4
113
224
(y<-x*5:7)
y[1,1] = x[1,1] * 5
y[2,1] = x[2,1
;- mcreg(as.matrix(creatinine), method.bootstrap.ci = "quantile", na.rm =
TRUE)
mean.slope.est<- mean(m@B1)
sd.slope.est<- sd(m@B1)
mean.intercept.est <- mean(m@B0)
sd.intercept.est <- sd(m@B1)
However, note that these estimates have no direct relationship to the BCa
confidence i
Hello
The function does exactly what you tell it to do; first you substitute
all NA with the mean; then you subtract the mean; for the NA this
meand: mean-mean=0; and this is what you get.
the problem is not the function but the z-score of means.
lg fabian
On 07-03-2014 12:17, David Croll
I m overwhelmed by the different packages dealing with
neg. binomial distribution regression. Can someone please point me which
package is most useful for the above described purpose?
Thank you very much in advance
Regards
Fabian
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esult.
But in nature, chemicals that are only weakly represented may not have very
much influence on the other individuals. For the moment, I won't question
that decision, because it's quite a convention in chemical ecology, as I
heard.
Regards,
Fabian
--
View this message in context:
x27;trymax'.
What could be going wrong? I really have no clue …
Thanks for your help!
Regards,
Fabian
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View this message in context:
http://r.789695.n4.nabble.com/Problem-with-metaMDS-in-vegan-tp4685022p4685043.html
Sent from the R help mailing list archive at Nabble.com.
with maxit, but had to go down to 10 to reach a suitable
result. And I don't think, I may limit the number of iterations that much.
What could possibly be the problem?
It would be great if somebody could help me.
Thaks!
Fabian
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View this message in context:
http://r.789695.n4.nabble.com/
ble to say something
about how high the probability is that my samples come from two different
populations (in the logic of a t-test).
Would this be possible or reasonable at all?
Thank again, I really appreciate your help!
best
Fabian
Would it be possible, too to
On 26 Apr 2012, at 10:56, Pe
x,yy,dmat2,lwd=2,add=T)
##
Is their an easy way to do this (maybe with dmvnorm()?) and could I interpret
the intersect ("shared volume") in the sense of a t-statistic?
Thanks a lot for your help!
_____
Fabian Ro
mat2,lwd=2,add=T)
##
Is their an easy way to do this (maybe with dmvnorm()?) and could I interpret
the intersect ("shared volume") in the sense of a t-statistic?
Thanks a lot for your help!
sincerely,
_________
Fabian
Fabian Ro
2 12.0 6.000 11.368 0.000642 ***
Residuals 18 9.5 0.528
#Is type 3 the Type I should use and why do the results differ if the
design is balanced? I am really confused, it would #be great if someone
could help me out!
#Thanks a lot for your help!
#/Fabian
#University of Goth
package uses standard formula syntax so that complex models can be
specified very concisely. It features powerful and user friendly
visualizations using ggplot2.
--
Fabian Scheipl
Department of Statistics
Ludwig-Maximilians
Dear helpers,
I tried these models to run in the package nlme, but allways got the same
error message...
I have a correlation in 5 sessions within a field (n=12) with ten traps in
one field.
res2a <- lme(response~x+y+z+treatment),correlation =
corARMA(form = ~ session|trapfield, p = 1, q = 0), r
Dear posters,
I have a question concerning binary data analysis. I have presence absence
data of 5 sampling sessions within 3 years, of 12 fields. Each field had 12
traps. I would like to analyse the data with a Generalized Estimating
Equations (GEE) Model in R. For the abundance data I used a gls
You can also automate it with this:
do.multirow<-function(df, which=1:ncol(df)){
for(c in which){
runs <- rle(as.character(df[,c]))
if(all(runs$lengths>1)){
tmp <- rep("", nrow(df))
tmp[c(1, 1+head(cumsum(runs$lengths),-
1))] <-
paste
You can also automate it with this:
do.multirow<-function(df, which=1:ncol(df)){
for(c in which){
runs <- rle(as.character(df[,c]))
if(all(runs$lengths>1)){
tmp <- rep("", nrow(df))
tmp[c(1, 1+head(cumsum(runs$lengths),-1))] <-
paste(
Dear List,
I would like to modify the settings for plotting a Vennerable object,
but I don't know how...so if anyone has an idea I would be really
graetfull.
best, Fabian
some R code to illustrate my problem:
library(Vennerable)
ven <- compute.Venn(Venn(SetNames=c("A&q
Hi all,
I am trying to rebuild the results of a study using a different data
set. I'm using about 450 observations. The code I've written seems to
work well, but I have some troubles minimizing the negative of the
LogLikelyhood function using 5 free parameters.
As starting values I am using
Hi
when I call the function below in R, i get the error: Object 'pairlist'
can't be converted to 'double'.
#include
#include
#include
SEXP CSimPoisson(SEXP lambda, SEXP tgrid, SEXP T2M, SEXP Ni, SEXP NT)
{
double sign, EVar;
double *xlambda, *xtgrid, *xT2M, *xNi, *xNT, *xtau;
Ni[j] <- NT
}
}
return(list(NT=NT,Ni=Ni,tau=tau))
}
I read the manual "writing R extensions" over and over again, but i have
no idea, how to solve the problem with tau because i dont no the leng
)?
thank you very much in advance for your help
fabian
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self
Dear R-users,
I'd like to announce the release of the amer-package that adds the
capability to fit generalized additive mixed models to lme4.
It includes a vignette with real data examples and a brief summary of the
theory behind the implementation.
Best,
Fabian
[[alternative
s case and what this
would imply for the error correlation structure. Could you give us a
guidance?
Your help is most appreciated and we thank you very much in advance!
Kind regards
Fabian Mollet
Doran, H. C. and Lockwood, J. R. 2006. Fitting value-added models in R.
- Journal of E
(names(frmls) %in% names(ans)))
return(as.call(c(ans, frmls[add])))
}
On Thu, Jul 30, 2009 at 11:22 AM, Fabian Scheipl <
fabian.sche...@stat.uni-muenchen.de> wrote:
> This does what you want:
>
> expand.call <- function(definition = NULL, call = sys.call(sys.parent()),
> e
se(ans[[1]]))
add <- which(!(names(frmls) %in% names(ans)))
return(as.call(c(ans, frmls[add])))
}
Best,
Fabian
[[alternative HTML version deleted]]
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PL
be applied.
All the best
Fabian Mollet
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
a
regression.
the "survRegData <- survreg(formula=Surv(time,exercise)~itm, data=Data,
dist="weibull")" command doesn't take into account that multiple records are
part of one subject.
Many thanks!
Fabian Hefner
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1 | 8
1999 | 1999 | 3.4257 | 0.15287 |-0.8615 |3| 0 | 4
2000 | 2000 | 1.1457 | 0.07487 |-0.5485 |3| 1 | 5
2001 | 2001 | 2.4418 | 0.09553 |-0.3772 |3| 0 | 2
Thank you,
Fabian Hefner
__
I have a data frame which contains some valuable date information. But for a
few of the dates, the day information missing .
Viz:
> interesting.data$date
[1] "1/22/93" "1/22/93" "1/23/93" "1/00/93" "1/28/93" "1/31/93" "1/12/93"
i.e. for dates where the day info is missing, the "%d" part of the
I have some data whose date column consists of two types of date entries:
(a) year-only entries (eg "1983") and
(b) full date info (eg September 12, 1962).
Here's what the non-standard date info looks like:
> mode(non.standard.dates)
[1] "numeric"
> head(non.standard.dates)
[1] July 15, 1925 F
Hi there,
I have an ixjxk array where I want to store dates in the first column of
all sub-matrices (i.e. j=1 is a column with dates) and real numbers in
the rest of the columns...I have been trying many things, but I am
not getting anywhere.
Thank you very much for your help,
Fabian
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