Re: [R] Integrating R and Textmate
On 25.07.2008, at 17:06, Rob Goedman wrote: Art, Could it be the case TextMate is activating the wrong version of R (2.6 vs. 2.7.1). I do not believe this. TextMate is using the normal R Terminal. I invoked the following command in a Rdaemon environment: install.packages(ade4, repos=http://cran.r-project.org;, contriburl = contrib.url( http://streaming.stat.iastate.edu/CRAN/;, type=mac.binary), dependencies=TRUE, installWithVers=TRUE) with Mac OSX 10.4.11, R 2.7.0 and I got this Package: ade4 Version: 1.4-9 Date: 2008/5/23 ... URL: http://pbil.univ-lyon1.fr/ADE-4, Mailing list: http://listes.univ-lyon1.fr/wws/info/adelist Packaged: Fri May 23 16:28:17 2008; penel Built: R 2.7.0; universal-apple-darwin8.10.1; 2008-05-26 03:43:26; unix What version of TextMate do you are using and esp. which R bundle?? --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] variable as part of file name
On 02.07.2008, at 15:31, Laura Poggio wrote: Dear all, sorry for this very basic question, but I did not find any good example yet. I would like to set up a variable that can be recall later to substitute a part of a file name. As example: var_filename = as.name(aaa) jpeg(var_filename.jpg) plot() dev.off() try: var_filename - 'foo' jpeg( paste( var_filename, '.jpg', sep='' ) ) See ?paste --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Convert character string to number
On 21.06.2008, at 01:36, Ken Liu wrote: I would like to convert a character vector xxx - c(1/2, 1/4) to yyy - c(0.5, 0.25) , but as.numeric didn't work for me. Could anyone give me a hint please? There are many many ways, and they're depending on the structure of xxx. If you only have such fractions you can use this naïve approach: as.numeric( gsub((\\d+)/(\\d+), \\1, xxx, perl=T) ) / as.numeric ( gsub((\\d+)/(\\d+), \\2, xxx, perl=T) ) --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] cutting out numbers from vectors
On 20.06.2008, at 19:27, calundergrad wrote:
i have a vector with a string of number
e.g
[1] 0113001 001130011000 001130012000 001130013000 001130016000
[6] 001130018000
i want a vector with the same numbers except with the last three
digits of
every factor cut off.
e.g
[1] 01130010 001130011 001130012 001130013 001130016
[6] 001130018
how do i accomplish this?
One way:
gsub((.*)(.{3}), \\1, YOUR_VECTOR)
--Hans
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Re: [R] Convert character string to number
On 21.06.2008, at 17:25, Marc Schwartz wrote: on 06/21/2008 09:18 AM Gabor Grothendieck wrote: On Sat, Jun 21, 2008 at 8:31 AM, Wacek Kusnierczyk [EMAIL PROTECTED] wrote: Hans-Jörg Bibiko wrote: On 21.06.2008, at 01:36, Ken Liu wrote: I would like to convert a character vector xxx - c(1/2, 1/4) to yyy - c(0.5, 0.25) as.numeric( gsub((\\d+)/(\\d+), \\1, xxx, perl=T) ) / as.numeric( gsub((\\d+)/(\\d+), \\2, xxx, perl=T) ) or: library(gsubfn) as.numeric( gsubfn(([0-9]+)/([0-9]+), numerator+denominator~as.numeric(numerator)/as.numeric (denominator), xxx, backref=-2) ) strapply, also in the gsubfn package, could be used here in a similar way too: library(gsubfn) strapply(xxx, ([0-9]+)/([0-9]+), ~ as.numeric(x) / as.numeric (y), backref = -2, simplify = c) [1] 0.50 0.25 or fn$sapply(strapply(xxx, [0-9]+, as.numeric), ~ x[1]/x[2]) [1] 0.50 0.25 I may have missed this one in the thread someplace, but I did not note any solutions based upon using strsplit(). So: sapply(strsplit(xxx, split = /), function(x) as.numeric(x[1]) / as.numeric(x[2])) [1] 0.50 0.25 or apply(sapply(strsplit(xxx, split = /), as.numeric), 2, function(x) x[1] / x[2]) [1] 0.50 0.25 OK. Here is an other one: * for UNIX/Mac and it's meant funnily [to rest R ;) ] sapply(as.list(xxx), function(x) as.numeric(system(paste(echo 'scale=10;,x,'| bc,sep=''), intern=T))) --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] (no subject)
On 19.06.2008, at 07:24, Paul Adams wrote: Hello everyone, I am wanting to replace an element in a matrix with NA. I have used the following code dat-read.table(file=C:\\Documents and Settings\ \txt,header=T,row.names=1) file.show(file=C:\\Documents and Settings\\txt) Z.matrix-as.matrix(dat) Y-dat[,46:63] X-dat[1,51] dat[1,51]-NA Whenever I use this code I get the original value when I type show (X).I run the script and type show(X) and the original value is still there.What am I doing wrong? Well, actually nothing. R works line by line. You set X-dat[1,51] with let's say '4711'. Fine X is now '4711'. Then you change the cell dat[1,51]-NA. Fine. If you type show(dat) you'll see that the cell 1,51 is now NA. But X is still the same, because X is NOT bound to the content of the cell dat[1,51]. --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Pattern Matching Replacement
On 19.06.2008, at 20:17, ppatel3026 wrote: I would like to replace \r\n with in a character string, where \r\n exists only between and , how could I do that? Initial: characterString = XMLtag1 id=\F\r\n2\/t\r\nag1\r\ntag\r\n2/tag2/XML Result: characterString = XMLtag1 id=\F2\/tag1\r\ntag2/tag2/ XML Tried with sub(below) but it only replaces the first instance and I am not sure how to pattern match so that it only replaces \r\n that exist within tags( and ). sub(\r\n, , charStream) It's only a very first idea: gsub((?=)([^]*?)\\r\\n([^]*?)(?=), \\1\\2, characterString, perl=T) --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Editor for Mac OSX
On 18.06.2008, at 18:09, Graham Smith wrote:
Have a look at TextMate http://macromates.com/
There are three extensions (bundles) available dealing with R for
TextMate [up to now in the Review repository]:
[in very short terms]
1) R
- writing R scripts and executing it (plots are inside as pdfs
available)
- one can execute more than one R script
- fast syntax highlighting, snippets (macros) for fast writing etc.
- command completion
- GUI for inserting function parameters
- displaying the command signature
- tidy function
- drag'n'drop facilities (drag a csv to the window it inserts read.csv
('filename'))
2) R Console (R.app)
- to remote R.app via AppleScript but with all goodies of TextMate
3) R Console (Rdaemon) - an ESS-like extension
- R runs hidden inside of TextMate
- it combines a text editor and the R console in a sophisticated way
- easy to expandably
- many GUI-like elements (Graphics/Package Manager ...)
- only written in scripting languages
- crash safer - if R/TextMate/Mac crashes one has at least the entire
last session as text file to reconstruct
and many many many more
If you want to know more let it me know.
--Hans
2008/6/18 Sebastian Leuzinger [EMAIL PROTECTED]:
Dear R-list
I am (forced) to change from Linux to Mac and am now looking for a
new
editor for R. I would like one that features a split window
(console +
editor) as well as syntax highlighting. Can anyone help?
Especially the
split-window feature does not seem to be easily available in the
editors
desribed on the R-help site, except Emacs, which I am reluctant to
start
using.
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Re: [R] gsub and multiple replacements
On 02.06.2008, at 17:27, Ng Stanley wrote:
I would like to replace A B by A-B and AA
(DD) by
AA using a single gsub. Is that possible besides using two
gsub ?
Could you be a bit more precisely?
If you are dealing with two fix strings then you can write
ifelse(theString == A B, A-B, AA)
if not, one could find a regexp to solve that problem, but one could
also use gsub in a cascade:
gsub('regexp1', 'replace1', gsub('regexp2', 'replace2', theString) )
etc.
--Hans
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Re: [R] Unicode characters (R 2.7.0 on Windows XP SP3 and Hardy Heron)
On 31.05.2008, at 00:11, Prof Brian Ripley wrote: On Fri, 30 May 2008, Duncan Murdoch wrote: But I think with Brian Ripley's work over the last while, R for Windows actually handles utf-8 pretty well. (It might not guess at that encoding, but if you tell it that's what you're using...) Yes. I already mentioned that there was a big step from R 2.6 to R 2.7 for Windows regarding the support of UTF-8. R passes around, prints and plots UTF-8 character data pretty well, but it translates to the native encoding for almost all character- level manipulations (and not just on Windows). ?Encoding spells out the exceptions (and I think the original poster had not read it). As time goes on we may add more, but it is really tedious (and somewhat error-prone) to have multiple paths through the code for different encodings (and different OSes do handle these differently -- Windows' use of UTF-16 means that one character may not be one wchar_t). R is becoming more and more popular amongst philologists, linguistics etc. It is very nice to have one software environment to gather, analyze, and visualize data based on texts. But, e.g. linguists are dealing very often with more than one language at the same time. That's why they have to use an Unicode encoding. In R they have to use any functions dealing with characters, like nchar, strsplit, grep/gsub, to lower/upper case etc. These functions are, more or less, based on the underlying locale settings. But why? It is a very very painful task to write functions for different encodings on different platforms. Thus I wonder whether it would be possible to switch internally to one Unicode encoding. If one considers e.g. the memory usage UTF-8 would be an option. Of course, such a change will be REALLY a BIG challenge in terms of effort, speed, compatibility, etc. This would also mean to avoid the usage of system libraries. Maybe this would be a task for R 4.0 or it will be my eternal private dream :) OK. Let me be a bit more realistic. An other issue is the used regular expression engine. On a Mac or UNIX machine one can set a UTF-8 locale. Fine. But these locales aren't available under Windows (yet?). Maybe it's worth to have a look at other regexp engines like Oniguruma ( http://www.geocities.jp/ kosako3/oniguruma/ ). It supports, among others, all Unicode encodings. It is used in many applications. I do not know how difficult it will be to implement such a library in R. But this would solve, I guess, 80% of the problems of R users who are interested in text analyzing. nchar, strsplit, grep etc. could make usage of it. Maybe one could write such a package for Windows (maybe also for Mac/ UNIX, because Oniguruma has some very nice additional features). Of course, a string should be piped as an UTF-8 byte stream to the Oniguruma lib, and I do not know whether this is easily possible in R for Windows. Once again, thanks for all the effort done to set up such a wonderful piece of software. --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Unicode characters (R 2.7.0 on Windows XP SP3 and Hardy Heron)
Hi, to put it simply. Windows cannot handle utf-8 data. There is no utf-8 locale available. If your corpus only contains Russian data, maybe English glosses etc. you can try to set lang of Rgui.exe to Russian. Then at least you can use grep, strsplit because they are depending on the locales chosen. On 30.05.2008, at 17:14, Stefan Th. Gries wrote: # I can do that all on Linux, but this arises in a context where # many other character processing issues are explained for Mac, # Linux, *and* Windows, and I'd hate to have to say this one # thing, you can't do on Windows Unfortunately I have to say this quite often :) Cheers, --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] data.frame indexing
On 28.04.2008, at 16:40, Georg Ehret wrote: E.g.: a-as.data.frame(matrix(rnorm(100),nrow=10,ncol=10)) b-which(a$V10.8) b [1] 1 4 6 10 a_indexb-a[b,] a_notIndexB-a[!b,] nrow(a_notIndexB) [1] 0 Indexing a on b is not a problem (a_indexb), but how can do get only the elements left if I take out the elements indexed with b? The ! operator only works on BOOLEAN. ONE possible way to set a_notIndexB is: a_notIndexB -a [-1*b, ] --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] Regular Expressions Help
On 19.04.2008, at 06:46, maud wrote: I am having some trouble learning regular expressions. Let me describe the general problem I am dealing with. Consider the following setup: Joe- c(1,2,3) Bob- c(2,4,6) Alice - c(9,8,7) Matrix - cbind(Joe, Bob, Alice) St - c(Bob, Alice, Alice:Bob) [...] I have been reading over various post on regular expressions, but really haven't made any progress. As far as I can tell there aren't standard string functions in R. (Also, as an aside, is there a wildcard character in R? I'd want something so if x=Bob a statment of the form x== B*b would evaluate true where * is the wildcard.) I'm not really sure if I understood you correctly. If you're looking for a way to match St against something like B*b you can make usage of normal regular expressions (like grep()). For details begin with ?regexp and ?grep Then you can try for instance: grep(B.b, St) to get [1] 1 3 (the indices of the vector St) or directly St[grep(B.b, St)] Cheers, --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to replace German umlauts in strings?
On 10.04.2008, at 18:03, Hofert Marius wrote:
I have a file containing names of German students. These names
contain the characters ä, ö or ü (German umlauts). I use
read.table() to read the file and let's assume the table is then
stored in a variable called data. The names are then contained in
the first column, i.e. data[,1]. Now if I simply display the variable
data, I see, that ä is replaced by \x8a, ö is replaced by \x9a
and so forth. Now, I would like to have these characters replaced by
their LaTeX (or TeX) equivalents, meaning \x8a should be replaced by
\a, \x9a should be replaced by \o and so forth. I tried a lot,
especially with gsub(), however, the backslashes cause problems and I
do not know how to get this to work. The data.frame should then be
written to a file without destroying the replaced substrings (so that
indeed \a appears in the file for \x8a). Is this possible?
Here is a minimal example:
data=data.frame(names=c(Bj\x9arn,S\x9aren),points=c
(10,20),stringsAsFactors=F)
data[1,1]=gsub('\\x9a','\\o',data[1,1]) #does not work! (neither do
similar calls)
Try this:
gsub('\\x9a','\\o',m, perl = TRUE, useBytes = TRUE)
Cheers,
--Hans
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Re: [R] for loop help
On 11.04.2008, at 05:38, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
?`break`
?`next`
for(i in 1:13) {
if(i 13) next
print(Hello!\n)
}
[1] Hello!\n
I am trying to find a solution in R for the following C++ code that
allows
one to skip ahead in the loop:
for (x = 0; x = 13; x++){
x=12;
cout Hello World;
}
Note that Hello World was printed only twice using this C++ loop. I
tried to do the same in R:
for(i in 1:13){
i=12
print(Hello World)
}
It doesn't work as I expected, i.e., this R loop prints Hello
World 13
times.
Maybe to understand this try:
for(i in 1:13){i - rnorm(1);print(i)}
You cannot change the seq in a for loop as you can in C, Perl, etc.
The variables i in for() and the i within the statement are not the
same. Thus you only can query i (see Bill's hint).
see also ?Control; last paragraph in 'Details'
--Hans
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Re: [R] Number of words in a string
On 09.04.2008, at 17:46, Shubha Vishwanath Karanth wrote: To put it simple, C=c(My Dog, Its really good, Beautiful) Now, SOMEFUNCTION(C) should give: c(My, Its really, ) SOMEFUNCTION - function(x) gsub( *\\w+$, , x) But be aware that this won't work for instance for combining diacritics. If you have this: C - c(My Dog, Its really good, Beautiful, Tuli faŝda) in fasda above the s is a combining circumfix ^ would give [1] My Its reallyTuli faŝ Then one should use the strsplit approach. Cheers, --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Re: [R] How to create a legend without plot, and to use scientific notation for axes label ?
On 10.04.2008, at 05:18, Ng Stanley wrote: Also, is there any way to specify scientific notation for axes label ? Scientific notation à la 3E-4 is set by default. Or did you mean engineering notation? Maybe this could help: http://wiki.r-project.org/rwiki/doku.php?id=tips:data- strings:formatengineering --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
[R] distance matrix as text file - how to import?
Dear all, I have -hopefully- a tiny problem. I was sent a text file containing a distance matrix à la: 1 2 3 4 5 6 Now I wanted to import these data into a dist object to, let's say, do 'plot(hclust(v))'. My first naïve approach was to scan the text file in order to get a vector v. Then I did: class(v) - dist attr(v, Size) - 4 But, of course, I got this: 1 2 4 3 5 6 I wonder if there's an elegant way to do it. The only way I know of is very very stony one. I'd be very appreciated for any hint. Cheers, --Hans __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
