stderr_int - summary(lm(y ~ x))$coefficients[1,2]
stderr_slope - summary(lm(y ~ x))$coefficients[2,2]
Jeff.
On Oct 3, 2007, at 3:01 AM, Alexander Moreno wrote:
Hi,
If I have two vectors x and y and I do lm(y~x) and now I want to
define
variables that are the standard errors of the slope
Hi Edna,
Can you send a small subset of the data as an example and the
function call you used to read the data in originally? It might be
helpful in understanding why you're losing the time element.
Jeff.
On Oct 1, 2007, at 12:27 AM, Edna Bell wrote:
Dear R gurus
I would like to take a
Not sure how you want to handle the NAs, but you could try the
following:
#start
MalVar29_37 - read.table(textConnection(V1 V2 V3 V4 V5 V6 V7 V8 V9
0 0 0 0 0 1 0 0 0
0 0 0 0 0 1 0 0 0
0 0 0 0 0 1 0 0 0
NA NA NA NA NA NA NA NA NA
0 1 0 0 0 1 0 0 0), header=TRUE)
How about this:
a - matrix(cbind(rep(2, 500), rep(3, 500)), 500, 2)
b - matrix(cbind(rep(5, 500), rep(6, 500), rep(7, 500)), 500, 3)
matrix(apply(a, c(2), *, b), nrow=500, ncol=6)
We apply the multiplier (quoted as specified in the apply help) with
argument b to every column of a as specified
test - c(060907_17_3_5_1_1_2909.tif, 060907_17_3_5_2_1_2910.tif,
060907_17_3_5_3_1_2911.tif)
sub('[[:digit:]][[:digit:]][[:digit:]][[:digit:]]\.tif', '', test)
or
test - c(060907_17_3_5_1_1_2909.tif, 060907_17_3_5_2_1_2910.tif,
060907_17_3_5_3_1_2911.tif)
sub('[[:digit:]]{4}\.tif', '', test)
I believe you're looking for:
dim(a)
dim(a)[1] # Number of observations, in your example, 12
dim(a)[2] # Number of variables per observation, in your example, 9
--Jeff.
On Sep 17, 2007, at 12:05 PM, Alfredo Alessandrini wrote:
Hi everybody,
If I've a data frame like this:
dataframe a
For the sake of absolute correctness:
sub('[[:digit:]]{4}\.tif', '', test)
should be
sub('[[:digit:]]{4}\\.tif', '', test)
-- Jeff.
On Sep 17, 2007, at 11:59 AM, Jeffrey Robert Spies wrote:
test - c(060907_17_3_5_1_1_2909.tif, 060907_17_3_5_2_1_2910.tif,
060907_17_3_5_3_1_2911.tif)
sub
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