Hi Doran
I'm also trying to scrape the leaderboard data. Did you happen to figure
out how to extract the athlete's team/affiliate? Trying to do a bit of code
to figure out which teams will qualify when individuals are removed.
On Sunday, March 2, 2014 2:34:21 PM UTC-5, Doran, Harold wrote:
Hello
Could someone please direct me to the correct commands for adding accents
(grave and aigu) to a letter in a plot title, label, or in added text? I'm
sure there's a handy list somewhere, but I've failed in coming up with the
correct search words to find it.
Thank you muchly!
Jen
way to do the above than
what I
proposed?
Cheers,
Bert Gunter
Genentech Nonclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
Behalf Of Gabor Grothendieck
Sent: Friday, January 29, 2010 11:01 AM
To: Jennifer Young
Hallo
I'm having trouble figuring out how to evaluate an expression when one of
the variables in the expression is defined separately as a sub expression.
Here's a simplified example
mat - expression(0, f1*s1*g1) # vector of formulae
g1 - expression(1/Tm) # expansion of the definition
)))
vals - data.frame(f1=1, s1=.5, Tm=2)
sapply(mat, eval, vals)
HTH,
baptiste
On 29 January 2010 17:51, Jennifer Young
jennifer.yo...@math.mcmaster.ca wrote:
Hallo
I'm having trouble figuring out how to evaluate an expression when one
of
the variables in the expression is defined
= screens , layout = c(2, 2), col = black, lty =
2, scales = list(y = list(relation = same)), panel = pnl)
On Fri, Dec 11, 2009 at 10:02 AM, Jennifer Young
jennifer.yo...@math.mcmaster.ca wrote:
Hello
I've created a function to make a plot with multiple pannels from
columns
of data
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Fri, 11 Dec 2009, Jennifer Young wrote:
Good evening
I often have as output from simulations a list of various values,
vectors
On Mon, Dec 14, 2009 at 11:30 AM, Jennifer Young
jennifer.yo...@math.mcmaster.ca wrote:
splendid!
This worked well, but there are two oddities that I can't resolve.
1. In the real data, the baseline is a cumulative probability plot
(from
simulations) rather than the straight line
PM, Jennifer Young
jennifer.yo...@math.mcmaster.ca wrote:
On Mon, Dec 14, 2009 at 11:30 AM, Jennifer Young
jennifer.yo...@math.mcmaster.ca wrote:
splendid!
This worked well, but there are two oddities that I can't resolve.
1. In the real data, the baseline is a cumulative probability plot
(dat[,i+1], type=l, lty=2)
}
Thank you muchly
Jennifer Young
PS: I am a subscriber, but can't for the life of me figure out how to send
an email while logged in so that the moderators don't have to take the
time to read it over. I always get the please wait while we check it
over email. Likely
then put it into a matrix tidily.
many thanks
Jennifer Young
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self
This is my first post so hopefully I haven't mucked up the rules.
I'm trying to change the default borders in either boxplot or barplot so
that, at the request of a journal, all of my figures have the same type of
border.
I've successfully used par(bty=o) using plot(1:10, bty=o), but it
seems
I'm translating some MATLAB code into R and have not found a simple
equivalent of the function R = subs(S,old,new).
I have, for example, a matrix such as this
mx- function(){
matrix( c(0, f1, f2,
s1, 0, 0,
0, s2, 0), 3,3, byrow=T)
}
and a matrix of data
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