Dear R users,
I'm working with 2 data sets which look like (for example) dx and dy in the
next code:
# Seed
set.seed(4)
# First data frame
dx=matrix(rnorm(6*5),ncol=6)
colnames(dx)=LETTERS[1:6]
# Second data frame
dy=matrix(rnorm(3*5),ncol=3)
colnames(dy)=c('A','C','E')
As you will notice,
Hi Tania,
I think it could be. I tried a solution based on your data set using a
chi-squared approach. Here is what I got:
#
# Data set
set.seed(123)
d - data.frame(cbind(val=rnorm(1:10)^2,
group=sample(LETTERS[1:5],100,repl=TRUE)))
d[,val]-as.numeric(as.character(d$val))
#
Hi there,
Perhaps
se-function(x)sqrt(var(x,na.rm=T)/sum(!is.na(x)))
object1-as.data.frame.table(tapply(Data[Year==1999],list(Group[Year==1999],Season[Year==1999]),mean))
object2-as.data.frame.table(tapply(Data[Year==1999],list(Group[Year==1999],Season[Year==1999]),se))
Hope this helps,
Jorge
Hi Luciana,
Try this:
yourData[,1] - sapply(yourData[,1], function(x){
x=as.character(x)
x[which(x==Toyota2)]-Scion
x
}
)
# Example
set.seed(123)
x=c(Jeep,Nissan, Toyota1, Toyota2)
y=rnorm(4)
DATA=data.frame(x,y)
DATA
x y
1Jeep -0.56047565
2 Nissan -0.23017749
3
4 matches
Mail list logo